pls help due today plesh

The profits exist the same (slope) but the y-intercept is more increased than the actual diagram.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the

change in y coordinate with respect to the change in x coordinate as,

m = Δy/Δx where, m is the slope

Given:

The slope-intercept form of a linear equation is where one side includes only "y"

2x+ 3y= 1470

y= -2/3 x + 490

Hence, the y-intercept exists at 490 and the slope is -2/3x.

As, 2x + 3y = 1593

3y = -2x +1593

y = -2/3x +531

The profits exist the same (slope) but the y-intercept is more increased than the actual diagram.

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Answer:

Step-by-step explanation:

I'm assuming you mean is the number 90 a rational number. The answer is that yes, it is a rational number.

Let me explain:

Under all the possible numbers, there is a taxonomy to organize these types of numbers. It goes down a list from:

- all numbers, which is divided into two groups; complex and real

Under real numbers, there's rational and irrational:

Under rational, there's integers and fractions

Under integers, there's whole numbers and negative

Under whole numbers, there's natural numbers and 0 (yes, zero).

90 falls under natural numbers, which means it is also a rational number. Hope this helps!

Answer:

See explanation

Step-by-step explanation:

50 is 5*10, so multiply 3 by 5 also to get 5 and 15/50. First answer is 15

5 and 15/50 is also equal to 4 and 65/50. second answer is 65

carry the numerator on the second line to get 30 for the third answer.

finally, subtract 3 from 4 to get 1, and subtract 30 from 65 to get 35/50.

last two answers are 1, and 35.

The solution to the system of equations is (x, y) = (-2, 8).15)Unfortunately, the question is incomplete, and I cannot provide an answer without knowing the complete question.

The two given equations are as follows:2x + y = 2x = (1/2)y + 6To solve the above system of equations, we will use the substitution method. First, we will substitute the value of x from the second equation to the first equation.2(1/2)y + 6 + y = 22.5y + 6 = 2Subtracting 6 from both sides, we get:2.5y = -4Dividing both sides by 2.5, we get:y = -4/2.5y = -8/5Substituting the value of y in the second equation to get the value of x:x = (1/2)(-8/5) + 6Multiplying and simplifying:x = -4/5 + 30/5x = 26/514)The given system of equations is:x + y = 6-2x + y = -3We will use the elimination method to solve the system of equations. Adding both the equations, we get:2y = 32y = 16y = 8Substituting the value of y in any of the equations to get the value of x:x + 8 = 6x = 6 - 8x = -2Therefore, the solution to the system of equations is (x, y) = (-2, 8).15)Unfortunately, the question is incomplete, and I cannot provide an answer without knowing the complete question.

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Answer:

8 - w

Step-by-step explanation:

In my opinion, an expression for eight minus w would be 8 - w. Thanks.

Hope it helps.

Answer:

4v - 9

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

multiply inside to the parentheses and add all commmon numbers getting you to, 5v -18 = 2 then add 18 5v=20 divided to v=4

Answer:

C) 84 mm squared

Step-by-step explanation:

The formula for finding area of a triangle is 1/2 times base times height, so substitute and solve for the answer

1/2 times 8 times 21

4 times 21

84

15. The student got 18 questions correct.

16. The weight of vitamin C in that tablet is 14%.

17. The secretary's salary has been increased by 60%.

18. The typist's original typing speed was 21 words per minute.

19. The salesperson made $1,022.40 in commission.

20. The salesperson's monthly earnings will be $19,546.

15. On a 45 questions exam, a student gets 40%.

The number of correct questions that the student got is
= 40% × 45 questions

= 18 questions

16. A vitamin tablet, which weighs 250 milligrams, contains 35 milligrams of vitamin C.

The percent of the weight of this tablet is vitamin C is
= 35mg/250mg × 100%

= 14%

17. Five years ago, a secretary made $11,200 annually. The secretary now makes $17,920 annually.

The percentage the secretary's salary has been increased by
= ($17,920/$11,200 × 100%) - 100%

= 160% - 100%

= 60%

18. A typist was able to increase his speed by 120% to 42 words per minute.

Her original typing speed was
= 42/120%  × 100%

= 42/1.2

= 21 words per minute

19. A salesperson makes a commission of 12% on the total amount of each sale. In one month, she makes a total of $8,520 in sales.

In that month, she made a commission of
= $8,520 × 12%

= $1,022.40

20. A salesperson receives a salary of $850 per month plus a commission of 82% of her sales. In a particular month, she sells $22,800 worth of merchandise.

Her monthly earnings will be
= $850 salary + 82% × $22,800

= $19,546

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We are given the expression √4x^2+100 and the substitution x/5=tan(θ). Our goal is to use the substitution to write the expression as a trigonometric expression and simplify as much as possible.

First, let's substitute x/5=tan(θ) into the expression:

√4(tan(θ)*5)^2+100

Next, let's simplify the expression:

√4(25tan^2(θ))+100

√100tan^2(θ)+100

Now, let's factor out 100 from the expression:

√100(tan^2(θ)+1)

10√tan^2(θ)+1

Finally, let's use the trigonometric identity 1+tan^2(θ)=sec^2(θ) to simplify the expression further:

10√sec^2(θ)

10sec(θ)

Therefore, the expression √4x^2+100 can be written as 10sec(θ) using the substitution x/5=tan(θ).

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The error that occurred is called a transposition error.

A transposition error is when two digits are reversed or transposed in an accounting transaction. In this case, the debit that was supposed to be made to the Purchaser account was instead debited to the Accounts Payable account.

To correct this error, we need to make a journal entry that reverses the incorrect entry and then make the correct entry. The journal entry to reverse the incorrect entry would be:

Debit: Accounts Payable $5,000
Credit: Purchaser $5,000

This entry reverses the incorrect debit to Accounts Payable and the incorrect credit to Purchaser.

Next, we need to make the correct entry, which is:

Debit: Purchaser $5,000
Credit: Accounts Payable $5,000

This entry correctly debits the Purchaser account and credits the Accounts Payable account.

After these two journal entries are made, the accounts will be correctly balanced and the error will be corrected.

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complete question

A P^(5),000 debit to be made to the Purchaser account was debited to Accounts payabhe instead. which type of error is found here?

1. The value of Z is 1.96 determined from Z-table or a calculator. 2. The confidence interval equation is 161 ± 1.96* (4/√20). 3.The standard error is 0.8944. 4. The margin of error is 1.754. 5. The upper and lower limits are 162.754 and 159.246 respectively. 6. Confidence interval indicate how confident the researchers is that true mean is within the range.

1. For a 95% confidence interval, the value for Z is 1.96. This value is found by looking at a Z-table or using a calculator to find the Z-score that corresponds to a 95% confidence level.

2. The confidence interval equation is:

CI = x ± Z* (σ/√n)

Where x is the sample mean, Z is the Z-score, σ is the sample standard deviation, and n is the sample size.

Plugging in the values from the question, we get:

CI = 161 ± 1.96* (4/√20)

3. The standard error is calculated by dividing the sample standard deviation by the square root of the sample size:

SE = σ/√n = 4/√20 = 0.8944

4. The margin of error is calculated by multiplying the Z-score by the standard error:

ME = Z*SE = 1.96*0.8944 = 1.754

5. The upper and lower limits are calculated by adding and subtracting the margin of error from the sample mean:

Upper limit = x + ME = 161 + 1.754 = 162.754

Lower limit = x - ME = 161 - 1.754 = 159.246

6.  The 95% confidence interval for the mean drug price is between $159.246 and $162.754. This means that we are 95% confident that the true mean price of the drug is within this range.

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To prove that C is a field, we need to show that it satisfies the following 11 axioms of a field:

C is closed under addition: For all a, b ∈ C, a + b ∈ C.

C is closed under multiplication: For all a, b ∈ C, ab ∈ C.

C is associative under addition: For all a, b, c ∈ C, (a + b) + c = a + (b + c).

C is associative under multiplication: For all a, b, c ∈ C, (ab)c = a(bc).

C has an additive identity: There exists 0 ∈ C such that for all a ∈ C, a + 0 = a.

C has a multiplicative identity: There exists 1 ∈ C such that for all a ∈ C, a1 = a.

C has additive inverses: For all a ∈ C, there exists b ∈ C such that a + b = 0.

C has multiplicative inverses: For all a ≠ 0 ∈ C, there exists b ∈ C such that ab = 1.

C is commutative under addition: For all a, b ∈ C, a + b = b + a.

C is commutative under multiplication: For all a, b ∈ C, ab = ba.

Multiplication distributes over addition: For all a, b, c ∈ C, a(b + c) = ab + ac.

Proofs of the 11 axioms:

To show that C is closed under addition, we can use the fact that the sum of two complex numbers is also a complex number. That is, for any a, b ∈ C, a + b = (a + bi) + (b + di)i, where i is the imaginary unit. This is clearly a complex number, so C is closed under addition.

To show that C is closed under multiplication, we can use the fact that the product of two complex numbers is also a complex number. That is, for any a, b ∈ C, ab = (a + bi)(b + di) = (ab - bd) + (ad + bc)i, which is also clearly a complex number, so C is closed under multiplication.

To show that C is associative under addition, we can use the associative property of addition for real numbers. That is, for any a, b, c ∈ C, (a + b) + c = a + (b + c).

To show that C is associative under multiplication, we can use the associative property of multiplication for real numbers. That is, for any a, b, c ∈ C, (ab)c = a(bc).

To show that C has an additive identity, we can use the fact that the real number 0 is also a complex number, and that for any a ∈ C, a + 0 = a.

To show that C has a multiplicative identity, we can use the fact that the real number 1 is also a complex number, and that for any a ∈ C, a1 = a.

To show that C has additive inverses, we can use the fact that for any a ∈ C, there exists a complex number -a such that a + (-a) = 0. This is because the real numbers have additive inverses, and the imaginary unit i has an additive inverse -i.

To show that C has multiplicative inverses, we can use the fact that for any a ≠ 0 ∈ C, there exists a complex number 1/a such that a(1/a) =

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The solution to 4 is a>-162. This is because the inequality can be rewritten as -162 > -21, meaning that any number greater than -162 will satisfy the inequality.

Inequality is the unequal distribution of opportunities, resources, or rights among people or groups. It can be found in wealth, income, health, education, access to services and resources, and legal rights. Inequality is a social phenomenon that affects people differently depending on race, gender, age, or background. Inequality can be a result of unequal access to resources, differences in power dynamics, or the unequal distribution of resources among people or groups. It can lead to disparities in health, education, and economic outcomes for those who experience it. Inequality can be addressed through policies that promote equity and inclusion, such as targeted education initiatives and access to employment opportunities.

The reason this is happening is because when solving inequalities, we must isolate the variable on one side of the inequality sign. In this case, we can do this by adding 162 to both sides of the inequality. This will move the -21 to the other side and the result is a>-162.

In order to ensure that the solution is correct, it is important to check the answer by substituting a value larger than -162 into the inequality. If the value satisfies the inequality, then the solution is correct.

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The sοlutiοn tο 4 is a>-162. This is because the inequality can be rewritten as -162 > -21, meaning that any number greater than -162 will satisfy the inequality.

Inequality is the unequal distributiοn οf οppοrtunities, resοurces, οr rights amοng peοple οr grοups. It can be fοund in wealth, incοme, health, educatiοn, access tο services and resοurces, and legal rights. Inequality is a sοcial phenοmenοn that affects peοple differently depending οn race, gender, age, οr backgrοund. Inequality can be a result οf unequal access tο resοurces, differences in pοwer dynamics, οr the unequal distributiοn οf resοurces amοng peοple οr grοups. It can lead tο disparities in health, educatiοn, and ecοnοmic οutcοmes fοr thοse whο experience it. Inequality can be addressed thrοugh pοlicies that prοmοte equity and inclusiοn, such as targeted educatiοn initiatives and access tο emplοyment οppοrtunities.

The reasοn this is happening is because when sοlving inequalities, we must isοlate the variable οn οne side οf the inequality sign. In this case, we can dο this by adding 162 tο bοth sides οf the inequality. This will mοve the -21 tο the οther side and the result is a>-162.

In οrder tο ensure that the sοlutiοn is cοrrect, it is impοrtant tο check the answer by substituting a value larger than -162 intο the inequality. If the value satisfies the inequality, then the sοlutiοn is cοrrect.

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Complete question:

What is the solution to 3/4a>-16?

a>-21 1/3

a<-21 1/3

a>21 1/3

a<21 1/3

Answer:

The answer is B

Step-by-step explanation:

To solve this, we need to combine like terms.
(9c-8d) + (2c-6) + (-d+3)
9c + 2c - 8d - d - 6 + 3
11c - 8d - d - 6 + 3
11c - 9d - 6 + 3
11c - 9d - 3

The simplified trigonometric expression is sin(a).

The functions of an angle in a triangle are known as trigonometric functions, commonly referred to as circular functions. In other words, these trig functions provide the relationship between a triangle's angles and sides. There are five fundamental trigonometric functions: sine, cosine, tangent, cotangent, secant, and cosecant.

Here the given trigonometric expression is,

=> [tex]\frac{sec(a)}{cot(a)+tan(a)}[/tex]

We know that [tex]cot(a)=\frac{cos(a)}{sin(a)}[/tex] and [tex]tan(a)=\frac{sin(a)}{cos(a)}[/tex] and [tex]sec(a)=\frac{1}{cos(a)}[/tex]

Then,

=> [tex]\frac{\frac{1}{cos(a)} }{\frac{cos(a)}{sin(a)}+\frac{sin(a)}{cos(a)} }[/tex]

=> [tex]\frac{\frac{1}{cos(a)} }{\frac{cos^2a+sin^2a}{cos(a)sin(a)} }[/tex]

=> [tex]\frac{\frac{1}{cos(a)} }{\frac{1}{cos(a)sin(a)} }[/tex]

=> [tex]\frac{1}{cos(a)}\times\frac{sin(a)cos(a)}{1}[/tex]

=> sin a

Hence the simplified trigonometric expression is sin(a).

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Answer:

See below for proof.

Step-by-step explanation:

Given equations for x and y:

  [tex]x=v_0 \cdot t \cdot \cos \theta[/tex]

  [tex]y=-16 \cdot t^2 + v_0 \cdot t \cdot \sin \theta[/tex]

Rearrange the equation for x to isolate t by dividing both sides of the equation by v₀ · cos θ:

[tex]\implies t=\dfrac{x}{v_0 \cdot \cos \theta}[/tex]

Square the equation for x:

[tex]\implies x^2=(v_0 \cdot t \cdot \cos \theta)^2[/tex]

[tex]\implies x^2={v_0}^2 \cdot t^2 \cdot \cos^2 \theta[/tex]

Rearrange to isolate t² by dividing both sides of the equation by v₀² · cos²θ:

[tex]\implies t^2= \dfrac{x^2}{{v_0}^2 \cdot \cos^2 \theta}[/tex]

Now we have created expressions for t and t² in terms of x.

Substitute these into the equation for y:

[tex]\implies y=-16 \cdot t^2 + v_0 \cdot t \cdot \sin \theta[/tex]

[tex]\implies y =-16 \cdot \left(\dfrac{x^2}{{v_0}^2 \cdot \cos^2 \theta}\right)+ v_0 \cdot \left(\dfrac{x}{v_0 \cdot \cos \theta}\right) \cdot \sin \theta[/tex]

Simplify:

[tex]\implies y =-\dfrac{16}{{v_0}^2} \cdot \left(\dfrac{x^2}{\cos^2 \theta}\right)+\left(\dfrac{x}{\cos \theta}\right) \cdot \sin \theta[/tex]

[tex]\implies y =-\dfrac{16}{{v_0}^2} \cdot \left(\dfrac{1}{\cos^2 \theta}\right) \cdot x^2+x \cdot \left(\dfrac{\sin \theta}{\cos \theta}\right)[/tex]

[tex]\textsf{Use\;the\;identities\;\;$\sec^2\theta=\dfrac{1}{\cos^2\theta}$\;\;and\;\;$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$}:[/tex]

[tex]\implies y=-\dfrac{16}{{v_0}^2} \cdot \sec^2 \theta \cdot x^2+x \cdot \tan \theta[/tex]

[tex]\textsf{Hence\;proving\;that\;\;$y=-\dfrac{16}{{v_0}^2} \cdot \sec^2 \theta \cdot x^2+x \cdot \tan \theta$}.[/tex]

The equation can be written as,

[tex]y = \dfrac{-15x^2} { (v_o^2) + (\dfrac{1} { v_o^2})tan^{-1}(\dfrac{y} { x})}[/tex].

An object or particle that is projected in a gravitational field, such as from the surface of the Earth, and moves along a curved path while only being affected by gravity is said to be in projectile motion.

To begin with, we know that the horizontal displacement of the projectile is given by [tex]x = v_ot cos(\theta)[/tex], where vo is the initial velocity of the projectile and θ is the angle it makes with the positive x-axis. Therefore, we can rearrange this equation to solve for time t:

[tex]t = \dfrac{x} { (v_o cos(\theta))}[/tex]

Next, we can use the equation for vertical displacement under constant acceleration due to gravity: [tex]y = -16t^2+ v_ot sin(\theta)[/tex]. Substituting the expression for t derived above, we obtain:

[tex]y = -16[\dfrac{x} { (vo cos(\theta)}]^2 + v_o([\dfrac{x} { (v_o cos(\theta)}] sin(\theta)[/tex]

Simplifying this expression, we get:

[tex]y = \dfrac{-16x^2} { (v_o^2 cos^2(\theta)) + x tan(\theta)}[/tex]

Now, we need to eliminate the angle θ in terms of x and y. We can do this by using the fact that tan(θ) = y / x, which gives:

[tex]\theta= tan^{-1}(\dfrac{y} { x})[/tex]

Substituting this expression for θ into our previous equation, we obtain:

[tex]y =\dfrac{ -16x^2 }{(v_o^2 cos^2(tan^{-1}(\dfrac{y} { x}))} + x\ tan(tan^{-1}(\dfrac{y} { x})[/tex]

Since tan(tan⁻¹(z)) = z, we can simplify this expression further:

[tex]y = \dfrac{-16x^2} { (v_o^2 (1 + (\dfrac{y} { x})^2))} + y[/tex]

Finally, by rearranging terms, we get the desired equation:

[tex]y = \dfrac{-15x^2} { (v_o^2) + (\dfrac{1} { v_o^2})tan^{-1}(\dfrac{y} { x})}[/tex]

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Check the picture below.

Answer:

The answer is 145°

Step-by-step explanation:

Angle 3 and 4 make a right angle (90°) Subtract 55 from 90.

90-55=35

Angle 3 and Angle 1 are vertical angles, hence they have the same measurement.

Angle 1 is 35°

Angle 1 and 2 make a 180° angle. Subtract 35 from 180.

180-35=145

The measurement of angle 2 is 145°

Answer:

Step-by-step explanation:

∠5 + ∠4 = 90 + 55 = 145

∠2 = ∠5 + ∠4 (vertically opposite angles)

∴ ∠2 = 145

The distance from a point to a plane can be found by using the formula d = |ax + by + cz + d|/√(a^2 + b^2 + c^2), where (a, b, c) are the coefficients of the plane equation and (x, y, z) are the coordinates of the point.

For the first part of the question, the distance from the point (-1, 3, -5) to the plane 4x – 4y + 3z = -2 can be found by plugging in the values into the formula:
d = |(4)(-1) + (-4)(3) + (3)(-5) + (-2)|/√(4^2 + (-4)^2 + 3^2)
d = |-4 - 12 - 15 - 2|/√(16 + 16 + 9)
d = |-33|/√41
d = 33/√41

For the second part of the question, an equation of the plane through the point (-1, -2, 2) and perpendicular to the vector (5, -1, -2) can be found by using the formula ax + by + cz = d, where (a, b, c) are the components of the vector and (x, y, z) are the coordinates of the point. Plugging in the values gives:
(5)(x - (-1)) + (-1)(y - (-2)) + (-2)(z - 2) = 0
5x + 5 - y - 2 - 2z + 4 = 0
5x - y - 2z = -7

Therefore, the equation of the plane is 5x - y - 2z = -7.

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The value of the machine after 4 years can be calculated using the formula:
V = P * (1 - r) ^ n
Where:
V = value after n years
P = initial purchase price
r = annual depreciation rate
n = number of years

In this case, P = 3,000.00, r = 0.10 (10%), and n = 4.
Plugging these values into the formula, we get:
V = 3,000.00 * (1 - 0.10) ^ 4
V = 3,000.00 * 0.90 ^ 4
V = 3,000.00 * 0.6561
V = 1,968.30

Therefore, the value of the machine after 4 years is $1,968.30.

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104 consumers bought at least one of the three labels, 12 consumers bought labels A and B but not C 44 consumers bought label A and 91 consumers bought none of these labels because of the equations.

To find the number of consumers who buy the product sold under at least one of the three labels, we need to add up the number of consumers who buy the product under each label individually and those who buy the product under multiple labels.

However, we need to be careful not to double count those who buy the product under all three labels. Therefore, the formula for this calculation is:

At least one of the three labels = (A only) + (B only) + (C only) + (A and B only) + (A and C only) + (B and C only) + (A, B, and C)

Plugging in the given values, we get:

At least one of the three labels = 15 + 20 + 28 + 12 + 9 + 12 + 8 = 104 consumers

To find the number of consumers who buy the product sold under labels A and B but not C, we simply use the value given for those who buy only those sold under labels A and B:

Labels A and B but not C = 12 consumers

To find the number of consumers who buy the product sold under label A, we need to add up the number of consumers who buy the product under label A individually and those who buy the product under label A and one or both of the other labels. Therefore, the formula for this calculation is:

Label A = (A only) + (A and B only) + (A and C only) + (A, B, and C)

Plugging in the given values, we get:

Label A = 15 + 12 + 9 + 8 = 44 consumers

Finally, to find the number of consumers who buy the product sold under none of these labels, we subtract the number of consumers who buy the product under at least one of the three labels from the total number of consumers surveyed:

None of these labels = Total consumers - At least one of the three labels = 195 - 104 = 91 consumers

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Yes, Tanner has enough spray paint for his arrow.

What is an Area?

The amount of space occupied by a flat (2-D) surface or an object's shape is known as its area. A planar figure's area is the area that its perimeter encloses. The quantity of unit squares that completely encircle the surface of a closed figure is its area. Square measurements for area include cm2 and m2.

Given : paint available in can = 12 ft²

We know that the arrow is comprised of a triangle and a rectangle.

So, the area of given arrow = area of rectangle + area of triangle

Now, area of triangle = 1/2 ×base × height

                                    = 1/2 × 3 × (6 - 5 1/3)

                                    = 3/2 × ( 6 - 16/3)

                                    = 3/2 × ( 18-16)/3

                                    = 3/2 × 2/3

                                    = 1 ft²

Similarly, area of rectangle =  length × breadth

                                             = 5 1/3 × 2

                                             = 16/3 × 2

                                             = 32/3 ft²

Hence, area of arrow = area of triangle +area of rectangle

                                    = 1 + 32/3

                                    = 35/3 ft²

                                    = 11.67 ft²

So, he has sufficient paint to cover the arrow.

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As we proved that there exists a δ > 0 such that the function f(x) > 0 for all x ∈ (p − δ, p + δ).

To prove this, we will use the definition of continuity of a function. According to this definition, for a function to be continuous at a point p, the limit of the function as x approaches p must be equal to the value of the function at p.

In this case, we know that f(p) is greater than 0. So, if we can find a δ such that for all x within δ units of p, f(x) is also greater than 0, then we can show that f is continuous at p.

Let's begin by assuming that there is no such δ, i.e., for any δ > 0, there exists an x within δ units of p such that f(x) is less than or equal to 0. This means that we can find a sequence of points xn that approach p such that f(xn) is less than or equal to 0 for all n.

Since f is continuous, we know that lim xn → p f(xn) = f(p) (by the definition of continuity). But we also know that f(p) is greater than 0, so lim xn → p f(xn) cannot be less than or equal to 0. This is a contradiction, which means our assumption that there is no δ such that f(x) is greater than 0 for all x within δ units of p must be false.

Therefore, there must exist a δ > 0 such that f(x) is greater than 0 for all x within δ units of p, which proves our original statement.

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Complete Question:

Let f : (a, b) → R be continuous such that for some p ∈ (a, b), f(p) > 0. Show that there exists a δ > 0 such that f(x) > 0 for all x ∈ (p − δ, p + δ).

The requried rate of change of the function f[x] on the interval -5 ≤ x ≤ 0 is F(x)' = -11/5.

Rate of change is defined as the change in value with rest to the time is called rate of change.

Here,
From the graph we have,
F(-5) = 1 and F(0) = -10

So the rate of change is given as,
F(x)' = F(0) - F(-5) / 0 + 5
F(x)' = -10 - 1 / 5
F(x)' = -11/5

Thus, the requried rate of change of the function f[x] on the interval -5 ≤ x ≤ 0 is F(x)' = -11/5.

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The expected lifetime reproductive value for an individual in a population with an intrinsic rate of increase (r) of 0 is 1, the correct option is A.

The calculation for the expected lifetime reproductive value can be expressed as:

R₀ = ∑ lxmx

In a stable population with an intrinsic rate of increase of 0, the survival probability (lx) is constant across all age classes, and the average number of offspring produced by an individual (mx) is also constant.

R₀ = lxm

where l is the survival probability and m is the average number of offspring per individual.

Since the population is stable, each individual replaces itself with one offspring, so m = 1.

Therefore, the calculation for the expected lifetime reproductive value in a population with an intrinsic rate of increase of 0 is:

R₀ = lxm = 1 x 1 = 1, the correct option is A.

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Answer:

8x^2-4x-15

Step-by-step explanation:

To find the sum of the functions, we add them together:

f(x) + g(x) = (5x + 4) + (3x² - 9)

Simplifying, we get:

f(x) + g(x) = 3x² + 9x - 5

Therefore, the sum of the functions is 3x² + 9x - 5, which is option D.

Answer:120

Step-by-step explanation:

$120,000

The formula for an exponential function passing through the points (-2,--) and (2, 75) is: y = 75 * 2x + 2. To answer the question about the house valued at $120,000, the value of the house is not related to an exponential function. Therefore, the answer is that the value of the house is $120,000.

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Answer:

1278in^3

Step-by-step explanation:

21×8=168

168×6=1008in^3

5×9=45

45×6=270in^3

1008+270=1278in^3