Prepare a grid with magic number 30. You can choose any set of numbers in sequence but the numbers should not be repeated.

If for the first 150 miles of a trip, an car drives at v mph, for the next 200 miles, the car drives at (v+25) mph and the average speed of the whole trip is 35 mph, then the value of v will be 20mph (A).

Given Information:

Average speed = 35 mph

Total distance = 150 + 200 = 350 miles

For the first 150 miles of a trip, an car drives at v mph speed

⇒ Time, t1 = 150/v hrs

For the next 200 miles, the car drives at (v+25) mph speed

⇒ Time, t1 = 200 / (v+25) hrs

Now, the formula for average speed is given as,

Total distance / Total time

= [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex]

⇒ [tex]\frac{350}{\frac{150}{v}+\frac{200}{(v+25)} }[/tex] = 35 mph

[tex]\frac{350 v (v+25)}{150(v+25) + 200v}[/tex] = 35

[tex]\frac{350v^{2} + 8750v}{150v +3750 + 200v}[/tex] = 35

350v² + 8750v = 35 (350v + 3750)

v² + 25v = 35v + 375

v² - 10v = 375

v² - 10v - 375 = 0

Now, the above equation for speed can be written as,

v² - 20v + 15v - 375 = 0

v(v-20) + 15(v-20) = 0

(v-20) (v+15) = 0

v = 20

or v = -15

Since, speed is a scalar quantity, it can't be negative. Thus, v = 20 mph

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By the ratio test, the series converges for

[tex]\displaystyle \lim_{k\to\infty} \left|\frac{(x+2)^{k+1}}{\sqrt{k+1}} \cdots \frac{\sqrt k}{(x+2)^k}\right| = |x+2| \lim_{k\to\infty} \sqrt{\frac k{k+1}} = |x+2| < 1[/tex]

so that the radius of convergence is 1, and the interval of convergence is

|x + 2| < 1   ⇒   -1 < x + 2 < 1   ⇒   -3 < x < -1

The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.  

Ratio test is the test that is used to find the convergence of the given power series.  

First aₙ is noted and then aₙ₊₁ is noted.

For  ∑ aₙ,  aₙ and aₙ₊₁ is noted.

[tex]\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|[/tex] = β

Here [tex]a_{k}[/tex] = [tex]\frac{(x+2)^{k}}{\sqrt{k} }[/tex]  and  [tex]a_{k+1}[/tex] = [tex]\frac{(x+2)^{k+1}}{\sqrt{k+1} }[/tex]

Now limit is taken,

[tex]\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|[/tex] = [tex]\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|[/tex]

= [tex]\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|[/tex]

= [tex]\lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|[/tex]

= [tex]|{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}[/tex]

= [tex]|{x+2 }|[/tex] < 1

- 1 < [tex]{x+2 }[/tex] < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

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Answer:

B

Step-by-step explanation:

By using algebra properties and trigonometric formulas we find that the trigonometric expression [tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex] is equivalent to the trigonometric expression [tex]\frac{2\cdot \tan x}{\cos x}[/tex].

In this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

[tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex]       Given.

[tex]\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}[/tex]      Subtraction between fractions with different denominator / (- 1) · a = - a.

[tex]\frac{2\cdot \sin x}{\cos^{2}x}[/tex]      Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

[tex]\frac{2\cdot \tan x}{\cos x}[/tex]      Definition of tangent / Result

By using algebra properties and trigonometric formulas we conclude that the trigonometric expression [tex]\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}[/tex] is equal to the trigonometric expression [tex]\frac{2\cdot \tan x}{\cos x}[/tex]. Hence, the former expression is equivalent to the latter one.

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Answer:$225,000 each

Step-by-step explanation: Assuming that they each get an equal share of the inheritance, there are 8 shares of the inheritance so we divided the $1.8m by 8 which equals $225,000 each.

Using a quadratic regression equation, it is found that the prediction of volunteers in year 10 is of:

A. 47.

To find the equation, we need to insert the points (x,y) in the calculator.

In this problem, we have that the function initially increases, then it decreases, which means that it is a quadratic function. The points (x,y) to  be inserted into the calculator are given as follows:

(1, 20), (2,17), (3, 16), (4,16), (5,18), (6,21), (7,25), (8,31)

Inserting these points into the calculator, the prediction of y for a value of x is given as follows:

y = 0.702x^2 - 4.726x + 23.857

Hence, when x = 10, the prediction is:

y = 0.702 x 10² - 4.726 x 10 + 23.857

y = 47.

Hence option A is correct.

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Answer:

y is equal to -16

Answer:

y = 8

Step-by-step explanation:

We can use proportions for this question since y varies directly with x. This means that if x changes, y changes along with the x, and vice versa.

When y = -8, x = 4, so the proportion will be -8 : 4.

We need to find the y when x is 4, so our equation will be:

-8 : 4 = y : -4

Since the proportion will be the same.

Next, we multiply the inner two numbers, and the outer two numbers, saying that the values are the same.

4y = 32

y = 8

So y = 8 will be our answer!

Answer:

D.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The measurement used to describe a television is the length of its diagonal. The relation between the width, height, and diagonal is described by the Pythagorean theorem.

The Pythagorean theorem tells us the relation between the sides of a right triangle and its hypotenuse. The diagonal of a rectangle is the hypotenuse of a right triangle whose sides are the width and height of the rectangle. If 'c' is the number of "ratio units" in the diagonal, we have ...

  4² +3² = c²

  c = √(16 +9) = 5

The diagonal of the screen is 5 ratio units, so the width is 4/5 of the length of the diagonal, and the height is 3/5 the length of the diagonal.

The width is ...

  (4/5)(47 in) = 37.6 in . . . width

The height is ...

  (3/5)(47 in) = 28.2 in . . . height

The area is the product of the width and height:

  A = WH = (37.6 in)(28.2 in) = 1060.32 in²

The area of the screen is 1060.32 square inches.

Answer:

9

Step-by-step explanation:

let the number be y

5×y - 7 = 3×y + 11

5y-7 = 3y+11

collect like terms

5y-3y = 11+7

2y = 18

y = 18/2

y = 9

Using the formula for a z-distribution confidence interval of proportions, he also needs to know the confidence level.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

Of these 3 itens, the problem states that he knows the sample size and the sample proportion, hence he needs to know z to determine the confidence interval. z depends on the confidence level, which is the remaining parameter.

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[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 1 :}}}}}}[/tex]

[tex]\star\:{\underline{\underline{\sf{\purple{Solution:}}}}}[/tex]

❍ Arrange the given data in order either in ascending order or descending order.

2, 3, 4, 7, 9, 11

❍ Number of terms in data [n] = 6 which is even.

As we know,

[tex]\star \: \sf Median_{(when \: n \: is \: even)} = {\underline{\boxed{\sf{\purple{ \dfrac{ { \bigg (\dfrac{n}{2} \bigg)}^{th}term +{ \bigg( \dfrac{n}{2} + 1 \bigg)}^{th} term } {2} }}}}}[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ { \bigg (\dfrac{6}{2} \bigg)}^{th}term +{ \bigg( \dfrac{6}{2} + 1 \bigg)}^{th} term } {2} }[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \dfrac{6 + 2}{2} \bigg)}^{th} term } {2} }[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ \bigg( \cancel{ \dfrac{8}{2}} \bigg)}^{th} term } {2} }[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ {3}^{rd} term +{ 4}^{th} term } {2} }[/tex]

• Putting,

3rd term as 4 and the 4th term as 7.

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 4 + 7 } {2} }[/tex]

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} ={ \dfrac{ 11} {2} }[/tex]

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: even)} = \purple{5.5}[/tex]

[tex]\\[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 2 :}}}}}}[/tex]

[tex]\star\:{\underline{\underline{\sf{\red{Solution:}}}}}[/tex]

❍ Arrange the given data in order either in ascending order or descending order.

1, 2, 3, 4, 5, 6, 7

❍ Number of terms in data [n] = 7 which is odd.

As we know,

[tex]\star \: \sf Median_{(when \: n \: is \: odd)} = {\underline{\boxed{\sf{\red{ { \bigg( \frac{n + 1}{2} \bigg)}^{th} term}}}}}[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: odd)} = {{ \bigg(\dfrac{ 7 + 1 } {2} \bigg) }}^{th} term[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: odd)} = { \bigg(\cancel{\dfrac{8}{2}} \bigg)}^{th} term[/tex]

[tex]\\[/tex]

[tex] \sf Median_{(when \: n \: is \: odd)} ={ 4}^{th} term[/tex]

• Putting,

4th term as 4.

[tex]\longrightarrow \: \sf Median_{(when \: n \: is \: odd)} = \red{ 4}[/tex]

[tex]\\[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 3 :}}}}}}[/tex]

[tex]\star\:{\underline{\underline{\sf{\green{Solution:}}}}}[/tex]

The frequency distribution table for calculations of mean :

[tex]\begin{gathered}\begin{array}{|c|c|c|c|c|c|c|} \hline \rm x_{i} &\rm 3&\rm 1&\rm 7&\rm 4&\rm 6&\rm 2 \rm \\ \hline\rm f_{i} &\rm 4&\rm 6&\rm 2&\rm 2 & \rm 1&\rm 1 \\ \hline \rm f_{i}x_{i} &\rm 12&\rm 6&\rm 14&\rm 8&\rm 6&\rm \rm 2 \\ \hline \end{array} \\ \end{gathered} [/tex]

☆ Calculating the [tex]\sum f_{i}[/tex]

[tex] \implies 4 + 6 + 2 + 2 + 1 + 1[/tex]

[tex] \implies 16[/tex]

☆ Calculating the [tex]\sum f_{i}x_{i}[/tex]

[tex] \implies 12 + 6 + 14 + 8 + 6 + 2[/tex]

[tex]\implies 48[/tex]

As we know,

Mean by direct method :

[tex] \: \: \boxed{\green{{ { \overline{x} \: = \sf \dfrac{ \sum \: f_{i}x_{i}}{ \sum \: f_{i}}}}}}[/tex]

here,

• [tex]\sum f_{i}[/tex] = 16

• [tex]\sum f_{i}x_{i}[/tex] = 48

By putting the values we get,

[tex]\sf \longrightarrow \overline{x} \: = \: \dfrac{48}{16}[/tex]

[tex]\sf \longrightarrow \overline{x} \: = \green{3}[/tex]

[tex]{\large{\textsf{\textbf{\underline{\underline{Note\: :}}}}}}[/tex]

• Swipe to see the full answer.

[tex]\begin{gathered} {\underline{\rule{290pt}{3pt}}} \end{gathered}[/tex]

The dollar gains depreciated relative to the pound when the price of pounds in dollars increases, for instance, from $1 = 1 pound to $2 = 1 pound.

Devaluation of a currency can take place in both absolute and relative terms. When the value of one currency declines in relation to the values of other currencies, this is referred to as a relative devaluation. For instance, the British pound sterling may be worth more today than it did yesterday in terms of US dollars.

A currency's value declines when compared to other currencies, which is known as currency depreciation. Political unrest, interest rate differences, weak economic fundamentals, and investor risk aversion are a few examples of the causes of currency devaluation.

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Answer:

[tex]\displaystyle x=\frac{5}{4},\;\;1\frac{1}{4}, \;\; or \;\; 1.25[/tex]

Step-by-step explanation:

    To solve for x, we need to isolate the x variable.

    Given:

[tex]\displaystyle x+\frac{1}{2} =\frac{7}{4}[/tex]

    Subtract [tex]\frac{1}{2}[/tex] from both sides of the equation:

[tex]\displaystyle (x+\frac{1}{2})-\frac{1}{2} =(\frac{7}{4})-\frac{1}{2}[/tex]

[tex]\displaystyle x=\frac{7}{4}-\frac{1}{2}[/tex]

    Now, we will create common denominators to simplify.

[tex]\displaystyle x=\frac{7}{4}-\frac{2}{4}[/tex]

[tex]\displaystyle x=\frac{5}{4}[/tex]

Answer:

130 degrees

Step-by-step explanation:

We know (x-10)+(2x+10) is 180 degrees.

So first we need to find x. (x-10)+(2x+10)=3x

3x=180

x=60

Angle TRV is 2x+10.

If we input 60 in the place of x, it is 2(60)+10=120+10=130.

The answer is 130 degrees.

3x-2y=  7

Slope intercept form y= mx+b

   3x- 2y=  7

-   3x           -3x

-2y/-2=  3x/-2 - 7/2  

y=   3x/-2 -7/2

Answer:

3x/2 and the second 7/-2y

Step-by-step explanation:

thats how is what i got

Answer:

3600

Step-by-step explanation:

Reason is because you put the answer in your question.

Answer:

Rs.10800

Step-by-step explanation:

loss of article(L%)=10%

s.p=?

c.p of an article (c.p)=c.p

Now,

s.p=100-L%×c.p

_____

100

= 100-10 ×c.p

_____

100

=90 ×c.p

___

100

=0.9 × c.p

if article sold with Rs. 540 more

Article profit =5%

s.p =c.p + 540 =100+p%×c.p

______

100

or, c.p +540=105×c.p

______

100

or, c.p +540=1.05×c.p

or,c.p +540=1.05c.p

or, 540=1.05c.p-c.p

or,540=0.05c.p

or, 540=c.p

____

0.05

Therefore, c.p =Rs. 10800

a) The coordinates for T and H such that quadrillateral MATH is a rectangle are T(x, y) = (2, - 2) and H(x, y) = (5, - 4).

b) The quadrilateral MATH is a rectangle.

Quadrilaterals are figures with four sides and whose internal angles sums a total of 360 degrees. A quadrilateral is a rectangle when each pair of opposite sides are parallel and have the same length to each others, each of the four angles are right angles and each pair of perpendicular sides.

a) Vectorially speaking, we can construct a rectangle by using the following definitions:

M(x, y) = (a, b), A(x, y) = (c, d), T(x, y) = (a, d), H(x, y) = (c, b)

If we know that a = 2, b = - 4, c = 5, d = - 2, then the points T and H are described below:

T(x, y) = (2, - 2), H(x, y) = (5, - 4)

The coordinates for T and H such that quadrillateral MATH is a rectangle are T(x, y) = (2, - 2) and H(x, y) = (5, - 4).

b) To prove that quadrilateral MATH, we need to prove that:

MT = HA      

(2, - 2) - (2, - 4) = (5, - 2) - (5, - 4)

(0, 2) = (0, 2)

TA = MH

(5, - 2) - (2, - 2) = (5, - 4) - (2, - 4)

(3, 0) = (3, 0)

MT • TA = 0

(0, 2) • (3, 0) = 0 · 3 + 2 · 0 = 0

MH • HA = 0

(3, 0) • (0, 2) = 3 · 0 + 0 · 2 = 0

Therefore, the quadrilateral MATH is a rectangle.

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The probability that the first interview occurs on the fifth resume that you sent is 0.2592.

According to the given question.

The probability of being called for an interview, p = 0.40.

So, the probability of not being called for an interview, q = 1 - 0.40 = 0.60

As we know that binomial distribution summarizes the number of trials, or observations when each trial has the same probability of attaining one particular value. The binomial distribution determines the probability of observing a specified number of successful outcomes in a specified number of trials.

Therefore, the probability that the first interview occurs on the fifth resume that you send out

= [tex]^{5} C_{1} (0.40)^{1} (0.60)^{4}[/tex]

= 5(0.40)(0.1296)

= 0.2592

Hence, the probability that the first interview occurs on the fifth resume that you sent is 0.2592.

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Using the chord theorem, option C is the best solution since x = 5.

The four line segments that are created by two intersecting chords inside of a circle are explained by the chord theorem, sometimes referred to as the intersecting chords theorem, a statement in fundamental geometry. The products of the line segment lengths on each chord are equal, according to this assertion.

The value of x must be determined in order to answer the question.

We may determine the following using the chord property:

8*x = 4*10,

or, 8x = 40,

or, x = 40/8,

or x = 5.

Given that x = 5, option C is the best option according to the chord theorem.

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The equation of a circle exists:

[tex]$(x-h)^2 + (y-k)^2 = r^2[/tex], where (h, k) be the center.

The center of the circle exists at (16, 30).

Let, the equation of a circle exists:

[tex]$(x-h)^2 + (y-k)^2 = r^2[/tex], where (h, k) be the center.

We rewrite the equation and set them equal :

[tex]$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0[/tex]

[tex]$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0[/tex]

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

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I assume the given series is

[tex]\displaystyle 2 + \frac4{2^2} + \frac8{3^2} + \frac{16}{4^2} + \cdots = \frac{2^1}{1^2} + \frac{2^2}{2^2} + \frac{2^3}{3^2} + \frac{2^4}{4^2} + \cdots = \sum_{n=1}^\infty \frac{2^n}{n^2}[/tex]

By the ratio test, the series diverges, since

[tex]\displaystyle \lim_{n\to\infty} \left|\frac{2^{n+1}}{(n+1)^2} \cdot \frac{n^2}{2^n}\right| = 2 \lim_{n\to\infty} \frac{n^2}{(n+1)^2} = 2 > 1[/tex]

The number of pieces of card stock which would result upon the process repetition is; 256 pieces.

According to the task content, it follows that since, there are 8 pieces of the 8 inches per side cards initially, the resulting number of cards after carrying out the process of cutting cards into half five, 5 times is;

No of cards = 8 (2)⁵

No. of cards = 256 pieces.

The size of each of the cards in discuss provided that all cuts will be made along and not across the longer edge is; 8 by 1/4 inches.

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For direct variation, variation constant = 2.

For inverse square variation, variation constant = 4.

For inverse variation, variation constant =80.

For inverse variation, variation constant = 9.

For direct square variation, variation constant = 0.6

For direct variation, variation constant = -0.84

(a) Direct variation: y = Kx where x = 3 and y = 6

Variation constant(k) = y/x = 6/3 =2

(b) Inverse square variation: y = K/[tex]x^{2}[/tex] where x = -2 and y = 1

Variation constant(k) = y[tex]x^{2}[/tex] = 1(-2)(-2) =4

(c) Inverse variation: y = K/x where x = 8 and y = 10

Variation constant(k) = y*x = 8*10 =80

(d) Inverse variation: y = K/x where x = 3 and y = 3

Variation constant(k) = y*x = 3*3 =9

(e) Direct square variation: y = K[tex]x^{2}[/tex] where x = 5 and y = 15

Variation constant(k) = y/[tex]x^{2}[/tex] = 15/25 =0.6

(f) Direct variation: y = Kx where x = -7.5 and y = 6.3

Variation constant(k) = y/x = -6.3/7.5 = -0.84

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