The divergence theorem in vector calculus, commonly referred to as Gauss' theorem or Ostrogradsky's theorem, establishes a relationship between a vector field's flow through a closed surface and its divergence in the volume it is contained in.
The divergence theorem explains that the flux through the surface, which is the surface integral of a vector field over a closed surface, is equal to the volume integral of the divergence over the area inside the surface. It implies that the net flux out of a region is equal to the total of all the field sources in the region, with sinks being considered negative sources.
In specifically in electrostatics and fluid dynamics, the divergence theorem is a significant finding in the mathematics of physics and engineering. Typically, it is utilized in three dimensions in various fields. It can, however, apply to any number of dimensions. It is analogous to integration by parts in a single dimension. It is analogous to Green's theorem in two dimensions.
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which intervention is most appropriate for a client with an arterial blood gas (abg) of ph 7.5, a partial pressure of arterial carbon dioxide (paco2) of 26 mm hg, oxygen (o2) saturation of 96%, bicarbonate (hco3-) of 24 meq/l, and a pao2 of 94 mm hg?.
In this case, the most appropriate intervention would be to administer oxygen therapy to the client in order to raise the oxygen saturation and improve their oxygenation.
Additionally, you may want to consider making any necessary adjustments to the patient’s medications, diet, and lifestyle in order to improve their overall health.
Finally, it would be beneficial to monitor the patient’s oxygen levels and arterial blood gases in order to ensure that the oxygen therapy is working as intended and that the patient’s condition is not deteriorating.
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what is the ratio of ingredients used to make broth when using water as the main liquid?
The ratio of ingredients used to make broth when using water as the main liquid can vary depending on the recipe, but a common ratio is 1:10, meaning 1 part of solid ingredients to 10 parts of water.
When making broth, the ratio of ingredients is important as it affects the taste, texture, and nutritional value of the final product. The 1:10 ratio of ingredients is a starting point that can be adjusted based on personal preference.
For example, using a 1:10 ratio of ingredients means that for every 1 part of solid ingredients, such as chopped vegetables, meat, or bones, 10 parts of water are added. This can result in a light, flavorful broth. If a stronger flavor is desired, the ratio of solid ingredients can be increased, while a weaker flavor can be achieved by reducing the amount of solid ingredients.
It is also important to consider the type of ingredients used. For example, if a lot of salty ingredients are used, such as ham hocks or cured meats, the amount of water can be increased to balance out the saltiness. On the other hand, if a lot of herbs and spices are used, the water ratio can be adjusted to suit the desired taste.
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you want to prepare 200 ml of a 0.05 m nacl solution which has a molar mass of 56.44 g/mole. indicate the amount of nacl needed and explain the process (what equipment you would use to measure the liquid, etc.) you would take to make the solution
To make 200 ml of 0.05 M NaCl solution, you would need:
0.05 M * 200 ml = 0.01 moles of NaCl
So, the amount of NaCl needed would be 0.01 moles * 56.44 g/mol = 0.56 g
Process:
Take a clean, dry beaker of 200 ml capacity and pour 200 ml of distilled water in it.Use an analytical balance to measure 0.56 g of NaCl and add it to the beaker with water.Stir the solution until the NaCl is fully dissolved.You can use a glass rod or magnetic stirrer to ensure complete dissolution.Label the beaker with the concentration and date to keep track of it.The solution is now ready to use.
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Which of these are defining features of systemic radiation? use of specific radioactive elements, like iodine in the treatment of thyroid cancer
use of targeting molecules (monoclonal antibodies) that interact via specific proteins on the surface of cancer cells
use of radioactive compound bound to a targeting molecule
The defining features of systemic radiation are:
use of specific radioactive elements, like iodine in the treatment of thyroid canceruse of targeting molecules (monoclonal antibodies) that interact via specific proteins on the surface of cancer cellsuse of radioactive compound bound to a targeting moleculeA type of radiation therapy wherein the radioactive material would be ingested as well as inoculated through into body as well as travels through the bloodstream, identifying and destroying tumour cells. Systemic therapy refers to any cancer treatment which thus targets the entire body. Chemotherapy, for example, is a systemic chemotherapeutic agent that circulates all throughout body to eliminate abnormal cells in a variety of locations.
Systemic treatment refers to internal radiotherapy with such a liquid source. The term "systemic" makes reference to how the therapy travels through someone bloodstream to tissues all over your body, looking for and killing cancer cells. Systemic radiation therapy could be administered orally, intravenously (via an IV line), as well as intramuscularly (via injection).
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you begin with a 3.5l gas sample at 120ºc and 1.4atm. you increase the pressure to 4.7 atm and then cool the sample to 50ºc. what is the final volume of the sample?
The 3.5 L of gas sample at the temperature 120ºC and 1.4atm. If increase the pressure to 4.7 atm and then cool the it to 50ºC. The final volume of the sample is 0.85 L.
The initial volume , V1 = 3.5 L
The initial temperature, T1 = 120ºC = 393 K
The initial pressure,P1 = 1.4 atm
The final pressure , P2 = 4.7 atm
The final temperature, T2 = 50ºC = 323 K
The final volume , V2 = ?
The gas law is expressed as :
P1 V1 / T1 = P2 V2 / T2
(1.4 × 3.5 ) / 393 = ( 4.7 × V2 ) /323
0.0124 = ( 4.7 × V2 ) /323
4 = ( 4.7 × V2 )
V2 = 0.85 L
Thus, the final volume is 0.85 L.
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what type of compound is most consistent with the ir spectrum shown below? the compound responsible for this spectrum is the principle ingredient in oil of cloves. this compound is used not only in perfumes and mouthwashes, but also as an insect attractant and a dental analgesic.
The terminal alkyne type of compound is most consistent with the IR spectrum.
Normally alcohol/phenol group's O-H stretching peak arises around 3550-3200 cm-1 and the carboxylic acid O-H stretching peak arises around 3000-2500 cm-1. O-H peak will appear as a broad peak due to hydrogen bonding. So the given spectra are not applicable for alcohol and carboxylic acid.
In the given spectra a strong sharp peak around 3300 cm-1 indicates terminal alkyne C-H stretch. Usually, the C-H stretch of terminal alkyne appears as a strong sharp peak around 3250-3330 cm-1
The carbonyl stretching peak is a strong peak at 1780-1630. This region peak is not present in the given spectra. Therefore, the given spectra do not match a ketone, ester, carboxylic acid, or aldehyde.
The structured peak at 2950 and 2870 cm-1 is due to-C-H stretch
The medium peak at 2150 cm-1 is due to carbon triple bond carbon
The peak around 610-700 cm-1 is because of -C-H bonding
Therefore the given IR spectra are for a terminal alkyne.
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What type of compound is most consistent with the IR spectrum shown below?
Diagram attached at end of solution
alcohol
carboxylic acid
terminal alkyne
ketone
ester
None of the choices are correct.
aldehyde
what is the molecular geometry of the oxygen atoms in epinephrine?
Answer:
tetrahedral is the molecular geometry of the oxygen atoms in epinephrine.
For this question, choose TWO answers. Which of the following conversions are needed to calculate
the number of atoms in a 8.5 gram sample of sodium?
A 8.5 g/mol = 22.99 g/mol
B
8.5 g/mol = 6.022 x 1023 atoms
B
8.5 g/mol = 6.022 x 1023 atoms
To find the number of atoms in a 8.5 gram sample of sodium, you would need to use Avogadro's number (6.022 x 10^23 atoms/mol) and convert the mass of the sample to moles by dividing it by the molar mass of sodium (22.99 g/mol).
8.5 g / 22.99 g/mol = 0.37 mol
Then you would multiply the number of moles by Avogadro's number to get the number of atoms:
0.37 mol x 6.022 x 10^23 atoms/mol = 2.2 x 10^23 atoms
So, there are approximately 2.2 x 10^23 atoms in a 8.5 gram sample of sodium.
Calculate the van't Hoff factor of a 0.0500 m formic acid solution (HCO2H) which begins to freeze at -0.0984°C. *ΔTf = KfCmi, Kf = -1.86 °C/m
The Van' Hoff factor I is the ratio of the number of particles generated by solute dissociation to the total number of solute molecules in solution. To get the Van' Hoff factor of formic acid.
and Cm is the molality of the solution. The Van' Hoff factor I is the ratio of the number of particles generated by solute dissociation to the total number of solute molecules in solution. To get the Van' Hoff factor of formic acid. constant (-1.86°C/m for water), I is the Van' Hoff factor, and Cm is the molality of the solution. The Van' Hoff factor I is the ratio of the number of particles generated by solute dissociation to the total number of solute molecules in solution. To get the Van' Hoff factor of formic acid.
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1 mole of a hydrocarbon of formula CnH2n was burned completely in oxygen producing carbon dioxide and water vapour only. It required 192g of oxygen.
If it required 192g of oxygen. The formula for the hydrocarbon can be observed as C₆H₁₂.
How to determine the formula for the hydrocarbon?
It is required to examine the chemical equation that is balanced for the combustion of the hydrocarbon in order to find the value of 'n' in the hydrocarbon formula CₙH₂ₙ.
The equation for the combustion process of a hydrocarbon is:
CₙHₙ + (n + 1/2)O₂ → nCO₂ + nH₂O
In the equation, it is observed that 'n' moles of CₙH₂ₙ react with 'n + 1/2' moles of O₂ to produce 'n' moles of CO₂ and 'n' moles of H₂O.
According to the question, 192g of oxygen is needed, so find the moles of oxygen used:
Moles of O₂ = mass of O₂ / molar mass of O₂
= 192g / 32g/mol
= 6 moles
The stoichiometric ratio between O₂ and CₙH₂ₙ is 1:1, the number of moles of CₙH₂ₙ is also 6 moles.
Now, find the value of 'n' through the relationship between moles of C and moles of H in the hydrocarbon.
Each mole of CₙH₂ₙ contains 'n' moles of carbon and 2n moles of hydrogen.
To consider the balanced equation, it is observed that 6 moles of carbon are produced.
Thus, the number of moles of carbon is equal to 6. Hence, each mole of CₙH₂ₙ contains 'n' moles of carbon, the formula for the hydrocarbon can be observed as C₆H₁₂.
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The given question is incomplete, so the most probable complete question is,
1 mole of a hydrocarbon of formula CnH2n was burned completely in oxygen producing carbon dioxide and water vapour only. It required 192g of oxygen. Work out the formula of the hydrocarbon.
What is the % mass/volume concentration of a solution consisting of 36 grams of K2SO4 with a total solution volume of 0.6 L? a. 6% b. 60% c. 21.6% d. 1.6% e. 0.06%
The correct response is option A) 6 % mass/volume concentration.
Here in the given question we have to find the mass/volume concentration which is equal to mass in kg / volume in L x 100
The rate of the mass of the solute present in a result to the volume of the result as a total is known as the mass/ volume percent. The indicated proportion must be multiplied by 100 because this type of attention is expressed as a chance.
Converting the grams of K2SO4 i.e 36 g into Kg = 0.036 Kg
volume of the solution = 0.6 L
Concentration = 0.036 / 0.6 x 100
= 6 % mass/ volume
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Neon is an inert gas. Why? reason.
Answer:
Neon is one of six elements, found in the rightmost column of the Periodic Table, that is inert.
Explanation:
Neon is one of six elements, found in the rightmost column of the Periodic Table, that is inert. Noble gases react very unwillingly, because the outermost shell of electrons orbiting the nucleus is full, giving these gases no incentive to swap electrons with other elements.
when 100g of gaseous water decomposes 1337 kj of heat are used by the reaction. how much heat would be needed to decompose water and produce 17g of oxygen
255.7 KJ of heat is needed to decompose water and produce 17g of oxygen.
Balance chemical reaction is given by,
H₂O → H₂ + 1/2 O₂ .
Atomic mass of H = 1 u ,
Atomic mass of O = 16 u ,
Molar mass of H₂O = 2 × 1 + 1 × 16 = 18 g/mol ,
Molar mass of O₂ = 2 × 16 = 32 g/mol ,
Moles = mass/molar mass ,
Moles of H₂O = 100/18 = 5.555 mol ,
Moles of O₂ = 17/32 = 0.5312 mol ,
From balanced chemical reaction :
1 mol H₂O --------> 0.5 mol O₂
x --------> 0.5312 mol O₂ .
x = 0.5312/0.5 = 1.0625 mol H₂O
Moles of H₂O = 1.0625 mol ,
Hence ,
5.555 mol H₂O ----------> 1337 KJ
1.0625 mol H₂O ----------> x
x = 1.0625 mol H2O × 1337 KJ/5.555 mol H₂O
x = 255.7 KJ .
Heat = 255.7 KJ .
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rank the compounds in order of increasing rates of their sn2 reactions.
The rate of an S N 2 reaction is dependent on the substrate structure, particularly the size and polarizability of the leaving group and the steric hindrance around the carbon center. The rate of an S N 2 reaction generally increases as the substrate becomes more bulky and the leaving group becomes more polarizable.
These factors increase the likelihood of the nucleophile attacking the substrate at the backside and decreasing the rate of recombination. Given the information, I cannot rank the compounds in order of increasing rates of their S N 2 reactions as the compounds are not specified. To determine the order of reactivity, one would need to examine the specific structural and electronic properties of the substrates, including the size and polarizability of the leaving group and the level of steric hindrance around the carbon center. The rate of an S N 2 reaction can also be influenced by other factors such as solvent, temperature, and the nature of the nucleophile.
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Use the electronic structures of the elements to explain why oxides of elements in the same group have the same type of formula.
Oxides of elements in the same group have the same type of formula due to their similar electronic configurations.
How are elements in the same group similar?Elements in the same group have the same number of valence electrons and thus, the same oxidation state in their compounds.
This leads to the same type of bonding and resulting chemical formula for their oxides and as a result of this, their electronic structure shows that elements in the same group would have the same type of formula
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In 20X3 C Co reported net sales revenues of 198 billion and cost of goods sold ... their gross profit percentage for 20X3?31)
A)43.5% B)76.74% C)69.7% D)30.3%
The gross profit percentage for 20X3 was 69.7% (Option C).
Gross profit is the amount by which revenue from sales exceeds the cost of goods sold. It is calculated as follows:
Gross profit = Net sales revenue - Cost of goods sold
To calculate the gross profit percentage, we divide the gross profit by the net sales revenue and multiply by 100 to express the answer as a percentage:
Gross profit percentage = (Gross profit / Net sales revenue) x 100
Using the information given in the question, we can calculate the gross profit and gross profit percentage for 20X3 as follows:
Gross profit = 198 billion - Cost of goods sold
Gross profit = 198 billion - (198 billion - Gross profit)
Gross profit = 198 billion - 198 billion + Gross profit
Gross profit = Gross profit
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A 50 kg girl rode her 12 kg bicycle in a race. She started from rest and then peddled with a velocity of 10 m/s. What is the change in kinetic energy of the girl and her bicycle?
The initial kinetic energy is zero because the girl was at rest. The final kinetic energy is thus, 3100 J. Therefore, the change in kinetic energy is 3100 J
What is kinetic energy ?Kinetic energy of an object is generated by virtue of its motion. It is related to the mass and velocity of the object as follows:
Ke = 1/2 mv²
Given that, mass of girl = 50 kg
mass of bicycle = 12 kg.
total mass = 62 kg.
velocity = 10 m/s.
Then initial kinetic energy = 0 since v = 0.
Then, ΔKe = 1/2 62 kg × (10 m/s)² - 0 = 3100 J
Therefore, the change in kinetic energy of the girl is 3100 J.
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What happened to the Arctic Ocean during the pat 40 year?(1 point)
Repone
It ha gained more ea ice. It ha gained more ea ice. It ha grown maller. It ha grown maller. It ha become war
(Thi i for omething ele not for me)
The Arctic Ocean has experienced significant sea ice loss over the past 40 years due to rising global temperatures caused by human-induced climate change.
This pattern is probably going to go on as normal temperatures in the Cold keep on rising quicker than elsewhere in the world. This deficiency of ocean ice has extensive ramifications for worldwide atmospheric conditions.
As well with respect to the creatures that rely upon the ice, like polar bears, walruses, and other Icy untamed life. It additionally has monetary and international ramifications.
As the contracting ice cap is making it more straightforward to get to beforehand undiscovered oil and gaseous petrol stores, and likewise opening up new transportation paths could abbreviate the movement time among Asia and Europe.
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Compound Formula Major Species Present When Dissolved In Water Methanol CH3OH Magnesium Sulfate MgSO4 Propylene Glycol C3H6OH2compound formula major species present when dissolved in water methanol CH3OH magnesium sulfate MgSO4 propylene glycol C3H6OH2
Compound formula Major species
CH₃OH CH₃OH
MgSO₄ Mg²⁺, SO₄²⁻, H₃O⁺
C₃H₆(OH)₂ C₃H₆(OH)₂
1) CH₃OH , it is called as methanol. It is nonelectrolyte. It is neither a base nor the acid and it can not dissociates into the water.
The major species is CH₃OH .
2) MgSO₄ , magnesium sulfate will dissociates into the ions when dissolve in the water.
MgSO₄ + H₂O --> Mg²⁺ + SO₄²⁻ + H₃O⁺
3) C₃H₆(OH)₂ , propylene gylcol and it will not dissociate but it will remain as the molecule. The molecules is the species that solvated by the water molecule.
The major species is C₃H₆(OH)₂ .
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Find a real-world example of chemistry where nucleophilic substitution is involved.
A real-world example of chemistry where nucleophilic substitution is involved is the industrial reaction between sodium cyanide and acetic acid to produce sodium acetate and hydrogen cyanide.
This reaction is a nucleophilic substitution reaction because the cyanide ion acts as a nucleophile and attacks the carbonyl carbon of the acetic acid molecule, replacing the leaving group (hydrogen).
In the reaction between sodium cyanide and acetic acid, the cyanide ion acts as a nucleophile and attacks the carbonyl carbon of the acetic acid molecule. This leads to the formation of a new bond between the cyanide ion and the carbonyl carbon, and the displacement of the hydrogen ion. The resulting product is sodium acetate and hydrogen cyanide.
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from a full-strength hydrogen peroxide solution, how would you prepare 240 ml of two-thirds strength hydrogen peroxide solution for a wound irrigation using normal saline as the diluent?
To prepare 240 mL of two-thirds strength hydrogen peroxide solution for a wound irrigation using normal saline as the diluent, you need to mix 160 mL of full-strength hydrogen peroxide with 80 mL of normal saline.
This creates a total volume of 240 mL, with two-thirds of it being hydrogen peroxide and one-third being normal saline.
When using a hydrogen peroxide solution for wound irrigation, it is important to ensure that the concentration of the solution is appropriate for the type of wound being treated. Generally, hydrogen peroxide solutions of 2-3% concentration are used for wound irrigation. Higher concentrations can cause tissue damage and skin irritation.
Additionally, it is important to ensure that the diluent used is appropriate for the type of wound being treated. For example, normal saline is most commonly used for wound irrigation, but other diluents such as sterile water may be used for different types of wounds.
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2. which one of the reactions involving metal ions (equations 1-6 on the exp 12 part a pre-lab page) represents a redox reaction? which species is oxidized (write the element and the oxidation number before and after oxidation)? which species is reduced (write the element and the oxidation number before and after reduction)?
In a redox reaction, the species that is oxidized (loses electrons) is assigned a higher oxidation number after the reaction, while the species that is reduced (gains electrons) is assigned a lower oxidation number after the reaction.
The element and its oxidation number before and after oxidation or reduction can be determined by examining the reaction equation and noting changes in oxidation numbers for each species.
Example: In the reaction, Fe + Cu^2+ -> Fe^2+ + Cu, the Fe goes from an oxidation number of 0 to +2, which indicates that it has been oxidized. The Cu^2+ goes from an oxidation number of +2 to 0, indicating that it has been reduced.
So, the species oxidized is Fe (0 to +2) and the species reduced is Cu^2+ (+2 to 0).
About ElectronsElectrons are subatomic particles that have a negative charge and are commonly written as e-. The electron has no known basic components or substructures, so it is believed to be an elementary particle. Electrons have a mass of about 1/1836 the mass of a proton.
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consider two solutions, one of kcl(s) dissolved in water; a second of o2(g) dissolved in water. what would be the effect of increasing the pressure on each solution?
At greater pressures, the concentration of one kcl(s) in the gas phase increases, as does the concentration of dissolved gas molecules, o2(g) in the solution at equilibrium.
Henry's law is useful in many situations. CO2 bubbles develop when a carbonated beverage is opened, for example, because the drink was bottled under CO2 at a pressure greater than 1 atm. When the container is opened, the pressure of CO2 above the solution rapidly lowers, allowing some of the dissolved gas to escape as bubbles.
At some cases, if scuba divers are breathing compressed air, Henry's law explains why they must carefully rise to the surface after a dive. More N2 from the air dissolves in the diver's internal fluids when pressures rise beneath water.
Meanwhile, if a diver ascends too rapidly, the abrupt pressure shift causes tiny bubbles of N2 to develop throughout the body, resulting in "the bends." These bubbles can obstruct blood flow through small blood arteries, causing severe discomfort and, in rare cases, death.
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How many moles are present in 32.3 grams of carbon dioxide (CO2)?
answer choices
O 44.01 moles
O 1421.52 moles
O 32.3 moles
O 0.73 moles
Answer:
0.73 moles
Explanation:
consider the atom with the chemical symbol ir with a mass number of 193. how many protons are in an atom of ir?
The element Iridium (Ir) has an atomic number of 77, meaning that there are 77 protons in an atom of Iridium.
Iridium is a chemical element with the symbol Ir and atomic number 77. It is a dense, malleable, ductile, highly unreactive, precious, silverish-white transition metal. Iridium is the second-densest element (after osmium) and is the most corrosion-resistant metal, even at temperatures as high as 2000 °C.
It has a very low electrical conductivity and is the only metal to maintain good electrical conductivity in air at temperatures of up to 1600 °C. Iridium is the most stable of the noble metals and its monatomic form is the most common state of the element in nature.
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The balmer series of lines for the hydrogen atom are found only in the visible region of the spectrum..a. Trueb. False
The statement is true, because, The Balmer series of lines for the hydrogen atom are found only in the visible region of the spectrum.
This is because the energy of the photons emitted during the transitions from the higher energy levels to the lower energy levels of the hydrogen atom is in the visible range of the electromagnetic spectrum.
The Balmer series of lines is a set of spectral lines in the visible region of the electromagnetic spectrum emitted by hydrogen atoms. The Balmer series is named after Johann Balmer, who first identified the spectral lines in 1885.
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ki/i2 is mixed with na2s2o3. the na2s203 immediately dissolves. was this a chemical change or physical change? support your answer with evidence.
This is a chemical change. When sodium thiosulfate (Na₂S₂O₃) is mixed with potassium iodide (KI), a chemical reaction will occurs, which producing iodine (I₂) as well as other products.
Evidence of a chemical change which includes the formation of a new substances with different properties, such as different color, odor, as well as chemical behavior. The dissolving of the sodium thiosulfate into the solution is also an indication of a chemical change, as the properties of the solid have changed into a new substance in solution form, with different properties than to the solid.
2Na₂S₂O₃ + I₂ → 2NaI + Na₂S₄O₆
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what is the magnitude of the weight of the sodium ion, which has a mass of 23 u (atomic mass units)? 1u
Explanation:
The weight of an object is the force exerted on it due to gravity, and its magnitude is measured in newtons (N).
We can calculate the weight of the sodium ion using the formula:
weight = mass x acceleration due to gravity
The mass of the sodium ion is given as 23 u (atomic mass units). One atomic mass unit is defined as one twelfth of the mass of a carbon-12 atom, which is approximately 1.66 x 10^-27 kg.
The acceleration due to gravity on the Earth's surface is approximately 9.8 m/s^2.
So, we can calculate the weight of the sodium ion as:
(23 x 1.66 x 10^-27 kg) x 9.8 m/s^2 = 3.6 x 10^-25 N
Therefore, the magnitude of the weight of the sodium ion is 3.6 x 10^-25 N. Keep in mind that this is a very small value, and the weight of the sodium ion is difficult to measure or detect.
2 03(g) → 3 0₂(8) AH=-285 kJ/mol,
The bond enthalpy of the oxygen-oxygen bond in O, is 498 kJ/mol. Based on the enthalpy of the reaction represented above, what is the average bond enthalpy, in kJ/mol, of an oxygen-oxygen bond in 03?
Please help meee
Explanation:
=> The simplest form of
56
:
98
56:98 is
4
:
7.
4:7.
Step-by-step explanation:
Given ratio -
56
:
98
56:98
We have to reduce it to its simplest form,
For that, we have to find the GCD of the numerator as well as the denominator:
So, the GCD for
56
56 and
98
98 is
14.
14.
Now, divide both the numerator and denominator by the GCD:
=
>
56
÷
14
98
÷
14
=>
98÷14
56÷14
=
>
4
7
=>
7
4
Hence, the simplest form is
4
:
7.
4:7.
Please help and right down each step!!
The mass of [tex]Ag_2CrO_4[/tex] that would be formed will be 2.69 grams.
Stoichiometric problemMole of 2.5 grams silver nitrate = 2.5/143.32 = 0.017 mol
Mole of 18.0 mL, 0.450 M sodium chromate = 18/1000 x 0.450 = 0.0081
From the balanced equation of the reaction, the mole ratio of silver nitrate to sodium chromate is 2:1. In other words, the sodium chromate is a bit limiting.
The mole ratio of sodium chromate and [tex]Ag_2CrO_4[/tex] is 1:1. Hence, the equivalent mole of [tex]Ag_2CrO_4[/tex] formed would also be 0.0081 mol.
Mass of 0.0081 mol [tex]Ag_2CrO_4[/tex] = 0.0081 x 331.73
= 2.69 grams
In other words, the mass of [tex]Ag_2CrO_4[/tex] formed from the reaction would be 2.68 grams.
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