Answer:
SO₂: 0.39atm
O₂: 3.645atm
Explanation:
Based on the reaction:
2 SO₂(g) + O₂(g) → 2 SO₃(g)
2 moles of sulfur dioxide react per mole of oxygen to produce 2 moles of sulfur trioxide.
When the reaction occurs an comes to equilbrium, the partial pressure of each gas is:
SO₂: 1.3atm - 2X
O₂: 4.1atm -X
SO₃: 2X
Where X is the reaction coordinate.
As pressure at equilibrium of SO₃ is 0.91 atm:
0.91atm = 2X
Thus: X = 0.455atm.
Replacing, pressures at equilibrium of the gases are:
SO₂: 1.3atm - 2×0.455atm = 0.39 atm
O₂: 4.1atm -0.455atm = 3.645 atm
An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0 L tank?
Answer:
1.2 atm
Explanation:
Given data
Volume of the gas in the tank (V₁): 200.0 LPressure of ethylene gas in the tank (P₁): ?Volume of the gas in the torch (V₂): 300 LPressure of the gas in the torch (P₂): 0.8 atmIf we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.
[tex]P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm[/tex]
Methanol (CH3OH) is the simplest of the alcohols. It is synthesized by the reaction of hydrogen and carbon monoxide
CO(g)+2H2(g)=CH3OH
If 500 mol of CO and 750 mol of H2 are present, which Is the limiting reactant?
Answer:
By reacting carbon monoxide and hydrogen the formation of methanol takes place, the reaction is,
CO(g)+2H₂(g)⇔CH₃OH (g)
Based on the given reaction, one mole of methanol is obtained by reacting one mole of carbon monoxide (CO) with the two moles of hydrogen (H₂). It is mentioned in the question that for the reaction 500 mol of carbon monoxide and 750 moles of hydrogen are present.
Therefore for 500 moles of carbon monoxide, there is a requirement of 2 × 500 moles of hydrogen, which is equivalent to 1000 moles of hydrogen (H₂). However, only 750 moles of hydrogen is present. Therefore, the limiting reactant in the given case is H₂. The present moles of H₂ will react with 0.5 × 750 moles of CO = 375 mole of CO
The additional or excess concentration of CO, which is the excess reactant will be, 500-375 = 125 moles.
A sample of gas occupies a volume of 120.0mL at a pressure of 0.75atm and a temperature of 295K. What will the volume be at a pressure of 1.25
atm and a temperature of 345K?
A)48mL
B)84mL
C)8mL
D)4mL
Answer:
A) 84 mL
Explanation:
use general gas equation P1×V1 / T1 = P2×V2/T2
rearrange the formula and solve for V2,it should give you V2= 84mL
Answer:
[tex]\large \boxed{\text{B) 84 mL}}[/tex]
Explanation:
We can use the Combined Gas Laws to solve this problem .
[tex]\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}[/tex]
Data
p₁ = 0.75 atm; V₁ = 120.0 mL; T₁ = 295 K
p₂ = 1.25 atm; V₂ = ?; T₂ = 345 K
Calculations
[tex]\begin{array}{rcl}\dfrac{p_{1}V_{1} }{T_{1}} & = & \dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{\text{0.75 atm $\times$ 120.0 mL}}{\text{295 K}} & = & \dfrac{\text{1.25 atm} \times V_{2}}{\text{345 K}}\\\\\text{0.305 mL} & = & \text{0.003 523V}_{2}\\V_{2}& =& \dfrac{\text{0.305 mL}}{0.003523}\\\\& = & \textbf{84 mL}\\\end{array}\\\text{The new volume of the gas is $\large \boxed{\textbf{84 mL}}$}[/tex]
You weighed out 0.020 g of your crude aspirin product in order to determine the amount of salicylic acid impurity. Following the procedure outlined in the manual, you dissolved the solid and diluted the solution to a final volume of 10.0 mL. If the absorbance of your sample solution was 1.07, what was the percent salicylic acid in your product
Answer:
The correct answer is 7.8 percent.
Explanation:
As mentioned in the given question, the absorbance (A) of the sample solution is 1.07. To find the concentration of aspirin, Beer's law is used, that is, A = ebc
Here, e is the extinction coefficient, which is equal to 139.322 M^-1cm^-1 as per the standard value for salicylic acid, b is the pathlength, which is equivalent to 1 cm. Now putting the values we get,
A = ebc
c = A / (eb)
c = 1.07 / (139.322 × 1)
c = 0.00768 M
Now to determine the percent salicylic acid in the sample, there is a need to compare the value of concentration determined with the concentration of aspirin given initially.
0.02 grams is the initial concentration of aspirin mentioned in the question. The molar mass of aspirin is 240 g/mol.
Therefore, the moles of aspirin will be,
0.02 / 240 = 8.33 × 10^-5 moles
The final volume of the diluted solution given is 10 ml or 0.01 liters.
The molarity of aspirin in the diluted solution will be,
c1 = 8.33 × 10^-5 / 0.01 = 8.33 × 10^-3 M or 0.00833 M
Now, the percent of salicylic acid in the product will be,
c1 - c / c1 × 100
(0.00833 - 0.00768) / 0.00833 × 100 = 7.8 %
Absorbance is directly proportional to the concentration of the solution. The absorbance can be calculated if the molar absorptivity, path length, and concentration of the absorbing species are known.
The percent of salicylic acid in the solution is 7.8%
Given that:
Absorbance of the solution is = 1.07
Path length = 1 cm.
Applying Beer's Law,
A = ε b c
where,
c = concentration, A = absorbance, ε = constant, and b = path length
Now, putting the values in above equation
c = [tex]\dfrac{\text{A}}{\text {(e b)}}[/tex]
c = [tex]\dfrac{1.07}{139.32 \times 1}[/tex] ( ε = 139.32)
c = 0.00768 M
Now, to calculate the percent of the salicylic acid in the solution, we will compare the given concentration of the aspirin.
As we know:
Given mass of aspirin = 0.02 g
Molar mass of aspririn = 240
Number of moles of aspirin = 0.02 / 240 = 8.33 x 10⁻⁵
Now, the molarity of aspirin is:
[tex]\text{Molarity}&= \dfrac{8.33 \times 10^{-5}}{0.01}\\\\\text{Molarity}&= 8.33 \times 10^{-5}[/tex]
Now, the percent of the salicylic acid is:
[tex]\dfrac{\text {C}_1 - \text C}{\text {C}_1 \times 100}[/tex]
[tex]\dfrac{(0.00833 - 0.00768)}{0.00833 \times 100}[/tex]
Percent of Salicyclic acid = 7.8%.
Thus, the percentage of the salicylic acid in the given solution is 7.8%.
To know more about Absorbance, refer to the following link:
https://brainly.com/question/17062521
Consider the following intermediate chemical equations.
2 equations. First: upper P subscript 4 (s) plus 6 upper C l subscript 2 (g) right arrow 4 upper P upper C l subscript 3 (g) delta H 1 equals negative 4,439 kilojoules. Second: 4 upper P upper C l subscript 3 (g) right arrow upper P subscript 4 (s) plus 10 upper C l subscript 2 (g) Delta H 2 equals 3,438 kilojoules.
What is the enthalpy of the overall chemical reaction Upper P upper C l subscript 5 (g) right arrow upper P upper C l subscript 3 (g) plus Uper C l subscript 2 (g).?
-999 kJ
-250. kJ
250. kJ
999 kJ
Answer:
PCl3 or option C
Explanation:
For everyone taking edge, trust me. Most of the answers are half-fasted, and offer no explanation. My explanation is that this is the right answer and you can trust me. Im taking the courses just like all of you, so i have no reason to misslead. Hope this helps! if you require more information, i cannot offer it. I gain knowledge by my failures.
Answer:
The correct answer is 250. kJ
Also referred to as C or Option 3
Explanation:
I got the answer correct because of the help from the other answer. Therefore, please mark the other person brainliest, they deserve it!
3. Which can happen when energy is transferred from one system to
another? Choose the correct answer. *
O
New energy is created.
O
Some energy is destroyed.
O
The energy changes form.
O
The energy changes into mass
Answer:
The energy changes form
Explanation:
As the Law of Conservation of energy states, energy can neither be crated nor destroyed. But, it can change form, whether that change is potential to kinetic or energy into heat or entropy, which is to us unusable as it is the energy of disorder.
ellus
What is the pH of a 3.5 x 10-11 M
H+ solution?
pH = [?]
Answer:
[tex]pH=10.5[/tex]
Explanation:
Hello,
In this case, since we define the pH as:
[tex]pH=-log([H^+])[/tex]
We can directly compute it by using the given concentration of H⁺:
[tex]pH=-log(3.5x10^{-11})\\\\pH=10.5[/tex]
For which we conclude it is a basic solution as the pH is greater than 7.
Best regards.
Sometimes in the lab we collect the O2gas formed by a chemical reaction over water (see sketch at right). This makes it easy to isolate and measure the amount of gas produced. Suppose the gas evolved by a certain chemical reaction taking place at 55.0C is collected over water, using an apparatus something like that in the sketch, and the final volume of gas in the collection tube is measured to be 117mL. Calculate the mass of that is in the collection tube. Round your answer to significant digits. You can make any normal and reasonable assumptions about the reaction conditions and the nature of the gases.
Answer:
mass CO = 0.12166 g
Explanation:
Mass of CO = 0.12 grams
Explanation
Volume of CO gas = 117 mL = 0.117 L
Temperature of CO = 55.0 oC = 328 K
Assumption : Pressure of CO = atmospheric pressure = 1.0 atm
According to ideal gas law,
moles of CO = [(Pressure of CO) * (Volume of CO gas)] / [(R) * (Temperature of CO)]
where R = gas constant = 0.0821 L-atm/mol-K
moles of CO = [(1.0 atm) * (0.117 L)] / [(0.0821 L-atm/mol-K) * (328 K)]
moles of CO = 0.004345 mol
mass CO = (moles of CO) * (molar mass CO)
mass CO = (0.004345 mol) * (28.0 g/mol)
mass CO = 0.12166 g
You have 0.00891 g of platinum. What is this in micrograms?
Which of the following describes the change in atomic mass and atomic number during this reaction?
Please answers only , 100 pts and brainliest, wrong answers will be reported.
What is the molarity of 9.8 gram Sulfuric Acid in 500 mL of water?
Answer:
.2mol/L
Explanation:
Answer:
2mol/l
Explanation:
If a solution has a pOH=12, what is its pH?
Answer:
2
Explanation:
pH+pOH=14
- Hope that helps! Please let me know if you need further explanation.
Answer:
2
Explanation:
Ph+PoH=14
What is the molarity of a solution in
which 3.8 moles of sodium chloride
(NaCl) is dissolved in water to a final
volume of 2.5 L?
Answer:
1.52M in NaCl
Explanation:
Molarity = moles solute / volume solution in Liters
=> molarity (M) = 3.8 moles / 2.5 Liters solution = 1.52 molar solution in NaCl
Answer: 1.52
Explanation:
The radioactivity due to carbon-14 measured in a piece of a wooden casket from an ancient burial site was found to produce 20 counts per minute from a given sample, whereas the same amount of carbon from a piece of living wood produced 160 counts per minute. The half-life of carbon-14, a beta emitter, is 5730 years. Thus we would estimate the age of the artifact to be about?
Answer:
17202.6 years
Explanation:
Activity of the living sample (Ao) = 160 counts per minute
Activity of the wood sample (A) = 20 counts per minute
Half life of carbon-14 = 5730 years
t= age of the artifact
From;
0.693/t1/2= 2.303/t log Ao/A
Then;
0.693/ 5730= 2.303/t log Ao/A
Substituting values;
0.693/5730= 2.303/t log (160/20)
Then we obtain;
1.209×10^-4 = 2.0798/t
t= 2.0798/1.209×10^-4
Thus;
t= 17202.6 years
Therefore the artifact is 17202.6 years old.
If 120.4 grams of reactant completely breaks down (decomposes) to produce 106.4 grams of chlorine. What mass of nitrogen gas could be expected? *
Answer:
[tex]m_{nitrogen}=14g[/tex]
Explanation:
Hello,
In this case, since we are talking about a chemical reaction in which a compound having nitrogen and chlorine is decomposed into chlorine and nitrogen, we must remember that the law of conservation of mass must be obeyed, for that reason, we notice that the mass of the whole reactants must equal the mass of the whole products, as shown below:
[tex]m_{reactants}=m_{products}[/tex]
Next, we know there is only one single reactant and products are constituted by both chlorine and nitrogen:
[tex]m_{reactant}=m_{chlorine}+m_{nitrogen}[/tex]
In such a way, we can compute the mass of nitrogen as shown below:
[tex]m_{nitrogen}=m_{reactant}-m_{chlorine}=120.4g-106.4g\\\\m_{nitrogen}=14g[/tex]
Best regards.
The pressure of a gas is 100.0 kPa and its volume is 500.0 mL. If the volume increases to 1,000.0 mL, what is the new pressure of the gas?
Answer:
[tex]P_2=50kPa[/tex]
Explanation:
Hello,
In this case, we can apply the Boyle's law in order to understand the pressure-volume relationship as an inversely proportional relationship relating the initial and the final volume:
[tex]P_1V_1=P_2V_2[/tex]
Next, we compute the final pressure P2:
[tex]P_2=\frac{P_1V_1}{V_2}=\frac{100.00kPa*500.0mL}{1000.0mL} \\\\P_2=50kPa[/tex]
Thus we validate, the higher the volume the lower the pressure.
Best regards.
H2O(g) + Cl2O(g) ↔ 2 HOCl(g) (a) Initially, 0.0555 mol H2O and 0.0230 mol Cl2O are mixed in a 1.00 L flask. At equilibrium, there is found to be 0.0200 mol of HOCl(g). Calculate the concentrations of H2O(g) and Cl2O(g) at equilibrium. (b) Using your results from part (a), calculate the equilibrium constant, Kc. (c) 1.0 mol pure HOCl is placed in a 2.0 L flask. Use your Kc from part (b) to calculate the equilibrium concentrations of H2O(g) and Cl2O(g).
Answer:
a)
[H₂O] = 0.0455M
[Cl₂O] = 0.0130M
[HOCl] = 0.0200M
b) Kc = 0.676
c) [H₂O] = [Cl₂O] = 0.177M
Explanation:
Based on the reaction:
H₂O(g) + Cl₂O(g) ⇄ 2HOCl(g)
Kc is defined as:
Kc = [HOCl]² / [H₂O][Cl₂O] For molar concentrations in equilibrium
As volume of the flask is 1.00L, the initial molar concentrations of H₂O and Cl₂O is 0.0555M and 0.0230M, respectively.
In equilibrium, the concentrations are:
[H₂O] = 0.0555M - X
[Cl₂O] = 0.0230M - X
[HOCl] = 2x = 0.0200M → X = 0.0100M
Where X is reaction coordinate
a) Concentrations in equilibrium are:
[H₂O] = 0.0455M
[Cl₂O] = 0.0130M
[HOCl] = 0.0200M
b) Replacing in Kc:
Kc = [0.0200]² / [0.0455][0.0130] = 0.676
c) Initial concentration of HOCl is 1.0mol / 2.0L = 0.50M. In equilibrium concentrations are:
[H₂O] = X
[Cl₂O] = X
[HOCl] = 0.50M - 2X
Replacing in Kc formula:
0.676 = [0.50-2X]² / [X][X]
0.676X² = 4X² - 2X + 0.25
0 = 3.324X² - 2X + 0.25
Solving for X:
X = 0.177M
X = 0.425M → False answer, produce negative concentrations.
As X = [H₂O] = [Cl₂O]; equilibrium concentrations of both compounds is 0.177M
State whether the following is an example of a physical or chemical change:! 21. Burning a log: ________________________________! 22. Folding a piece of paper: _________________________! 23. Freezing water: _________________________! 24. Bending a copper wire. _________________________!
Answer:
Physical change
Explanation:
Because it doesn't require any chemical to change
Answer:
Physical change
Physical change
Physical change
Physical change
Explanation:
HELP ASAP!!!! PLEASE AND THANK YOU!!!! Aluminum, which has a specific heat capacity of 0.902 J/g◦C and a mass of 20.9 g absorbs 348.0 J of energy. The final temperature (T2) is 100.0◦C. Calculate the initial temperature (T1).
Answer:
81.54 °C
Explanation:
Use the equation
q = mcΔT
348 = 20.9(0.902)(100-t)
t = 81.54 °C
*note, you don't have to convert these to kelvin since the difference will be the same
Which sulfur is a gas that reacts with liquid water to produce aqueous sulfuric acid, or acid rain. What is the equation for this reaction
Answer:
Sulfur Trioxide
Explanation:
Sulfur trioxide is a gas that reacts with liquid water to produce aqueous sulfuric acid,or acid rain.
A solution of KOH has a [OH-] concentration of 0.045 M. What is the pOH of the solution? *
1 point
-1.3
1.3
1.1
0.90
what is the answer?
Answer:
[tex]pOH=1.3[/tex]
Explanation:
Hello,
In this case, since pH is computed by knowing the concentration of hydrogen ions, one could compute the pOH by knowing the concentration of the hydroxyl ions as in this case which is 0.045M as shown below:
[tex]pOH=-log([OH^-])=-log([0.045])\\\\pOH=1.3[/tex]
Best regards.
Answer:
The pOH of the 0.045 M solution is 1.3
The second option (1.3) is correct
Explanation:
Step 1: Data given
Concentration [OH-] of KOH is 0.045 M
Step 2: Calculate pOH
pOH = -log[OH-]
pOH = -log (0.045)
pOH = 1.3
The answer:
The pOH of the 0.045 M solution is 1.3
The second option (1.3) is correct
What is the concentration of a solution in which 0.99 g of KOH are dissolved in 500 mL?
Answer:
.00352mol/L
Explanation:
molarity (concentration) = number of moles / volume of solvent (in L)
M = .99g / 56.108g/mol / .5L
M = .0176mol / .5L
M = .00352mol/L
is the normal resting position of an object.
Answer:
being stationary relative to a particular frame of reference or another object; when the position of a body with respect to its surroundings does not change with time it is said to be at rest
Explanation:
Been stationary is the normal resting position of an object
When an object is at rest ( normal resting position ) it is stationary ( i.e. the position of the object does not change with time in relation to its environment or another object/reference )
When an object is at rest it posses its' highest potential energy and its least kinetic energy. therefore been stationary is the normal resting position of an object.
Hence we can conclude that Been stationary is the normal resting position of an object.
Learn more : https://brainly.com/question/22533065
A crystal of table salt (NaCl) is dissolved in water. Which of the following statements explains why the dissolved salt does not recrystallize as long as the temperature and the amount of water stay constant?
A crystal of table salt (NaCl) is dissolved in water. Which of the following statements explains why the dissolved salt does not recrystallize as long as the temperature and the amount of water stay constant?
Na+ and Cl- ions lose their charges in the water.
Water molecules surround the Na+ and Cl- ions.
Na+ and Cl- ions leave the water through vaporization.
Water molecules chemically react with the Na+ and Cl- ions.
Your answer: -
Answer: B - Water molecules surround the Na+ and Cl- ions.
a hot liquid located under earth's surface?
Answer:
Magma
Explanation:
Magma is the hot liquid under earths surface
The tribute states of the ancient Aztec empire
were governed directly by the emperor.
made regular payments to the emperor.
acted as powerful independent city-states.
O surrounded the main Aztec city-state.
Answer:
made regular payments to the emperor.
Explanation:
The Aztec Empire was an alliance of three states: Mexico-Tenochtitlan, Texcoco, and Tlacopan. The area in and around the Valley of Mexico was ruled by these three city-states from 1428 to 1521. The state religion of the empire was polytheistic. The tribute states of the ancient Aztec empire made regular payments to the emperor.
Answer:
B
Explanation:
Porosities can have merits and demerits during manufacturing procedures of dental materials. Clarify this statement.
Answer:
The porosities in dental materials can be of merit and not merit since some dental materials need to be porous in order to reduce their weight and improve their properties and functions, whereas in those (which are the majority) porosities are not Merit, see the properties of the material, the function and can even influence dental rehabilitation.
An example of this is the use of vitreous ionomers, which is a dental material, where when it is spatulated it remains porous, it can give recurrence of infectious caries, since its permeability increases, the best cariogenic microorganisms are filtered and porosity works as a retentive site for these microorganisms that make up the dental biofilm.
In summary, the world of dental materials is very wide, some are resins, other cements, others have metallic claims, etc. To say that the presence of porosity is merit or demerit would be ideal because for some materials this is favorable and for others unfavorable since they are very versatile, with different qualities, different degrees of porosity, different molecules, different coefficients of thermal expansion, some do not set, others do not, some are light-cured, others do not, some withstand more mechanical forces and have more elastic modulus and less porosity, while others do not, and thus with many more variables.
Explanation:
In the manufacture of dental materials, much attention is always paid to what the manufacturer indicates in these indications that come on the reverse side of the material or on a paper inside the material container.
This is important to know, because the manufacturer is the one that indicates the mode of use and working time according to the trademark and the chemical composition of the dental material.
That a dental material in its manufacture is more or less porous, makes its density, weight and volume possibly be affected, there are materials that seek to increase porosity for a certain purpose, while others seek the opposite, depending on the function that is applied, will have more or less pores.
The example we gave above about the vitreous ionomer is an example that indicates that in the case of restorative dental materials where the function is to SEAL the porosity is almost nil, since otherwise it will not seal the cavity that was formed with caries and not the infectious problem would be solved.
On the other hand, in the surgical field of dentistry there are bone grafts or porous macroparticles that are for the purpose of bone replacement, which in order to be integrated need blood vessels that run over these pores, irrigating the area of bone neoformation well, in this case the merit of porosity if necessary and it is essential that they be very porous.
PLEASE help! BRAINLIEST to right answer!
Answer:
The answer is e - Negative, Exothermic
Explanation:
Kono Dio Da!!
How many kilograms of solvent (water) must 0.71 moles of KI be dissolved in to produce a 1.93 m solution?
Answer: kg= 0.37
Explanation:
Use the molality formula.
M= m/kg
An empty weighing dish has a mass of 1.0041 ± 0.0002 g. After you add dried sodium chloride to the dish, the mass is 3.2933 ± 0.0002 g. You quantitatively transfer the sodium chloride into a 500.00 ± 0.05 mL volumetric flask and dilute to the mark with deionized water. The molar mass of sodium chloride is 58.440 g/mol. What is the absolute error in the concentration of the resulting solution? Report your answer normally to the correct number of significant figures with the correct unit.
Answer:
The correct answer to the following question will be "0.0013%".
Explanation:
The given values are:
Weight of an empty dish = 1.0041 ± 0.0002 g
Weight of dish + sodium chloride (NaCl) = 3.2933 ± 0.0002 g
Weight of NaCl = 2.2892 ± 0.0002 g
Now,
Volume of the solution = 500.00 ± 0.05 ± 0.0002
= 500.00 ± 0.0502 ml
So,
Molarity = [tex]\frac{W \ NaCl}{M \ NaCl} \times \frac{1000}{Volumes \ of \ solution}[/tex]
On putting the values in the above formula, we get
= [tex]\frac{(2.2892\addeq +0.0002)}{58.440}\times \frac{1050}{(500.00+0.0502)}[/tex]
= ([tex]3.917[/tex] ± [tex]0.0002[/tex]) × ([tex]2[/tex] ± [tex]0.0502[/tex])
= ([tex]0.7834[/tex] ± [tex].00001004[/tex])
Now,
Absolute error = [tex]\frac{0.00001004}{0.7834}\times 100[/tex]
= [tex]0.0013[/tex]%
