The height at which the gun is being held above the ground is 3.969 m.
What is the height above the ground?
In motion of object in physics and mathematics, we know that the formula for time taken is,
Time = Distance/Velocity
We are given;
Velocity; v = 207 m/s
Distance; d = 192 meters
Thus,
Time taken = 192/207
= 0.927 seconds
Due to acceleration due to gravity, the displacement of bullet along vertical direction y is gotten from newtons equation of motion,
y = ut + ¹/₂gt²
where,
u is initial velocity = 0 m/s
Thus,
y = 0 + ¹/₂(9.8)(0.9)²
y = 3.969 m
Thus, the height at which the gun is being held above the ground is 3.969 m.
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A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ
The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)
How do I determine the kinetic energy?We'll begin by obtaining the velocity of the flywheel. This is shown below:
Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?v = at
v = 0.6 × 60
v = 36 m/s
Finally, we shall determine the kinetic energy of the flywheel. Details below:
Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 50 × 36²
KE = 25 × 1296
KE = 32400 J
Divide by 1000 to express in KJ
KE = 32400 / 1000
KE = 32.4 KJ
Thus, the kinetic energy is 32.4 KJ (Option D)
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A single frictionless roller-coaster car of mass m = 55 kg tops the first hill with speed v0 at height h = 22.0 m. How much work does the gravitational force do on the car from that point to (a) point A, (b) point B, and (c) point C? If the gravitational potential energy of the car–Earth system is taken to be zero at C, what is its value when the car is at (d) B and (e) A?
The answer should be with two decimals.
The gravitational potential energy of the roller-coaster at point A and B respectively 11870.10 Joule and 5935.05 Joule.
What is gravitational potential energy?The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
According to the question:
Mass of the rollercoaster: m = 55 kg.
Height of point A: h =22.0 m.
Height of point B: h/2 = 22.0/2 m = 11.0 m.
Height of point C = 0.
Taking, acceleration due to gravity: g = 9.81 m/s² we get:
The gravitational potential energy of the car at point A:
E₁ = mgh = 55 kg × 9.81 m/s² × 22.0 m = 11870.10 Joule.
The gravitational potential energy of the car at point B:
E₂ = mgh/2 = 55 kg × 9.81 m/s² × 11.0 m = 5935.05 Joule.
Hence, gravitational potential energy of the car at point A and B respectively 11870.10 Joule and 5935.05 Joule.
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As part of astronaut training, a prospective astronaut is spun around in a human centrifuge such that the candidate experiences a centripetal acceleration that is 2.8 times the acceleration due to gravity on the surface of the earth. If the candidate is 11.05 m from the center, determine the candidate's speed in meters per second.
The candidate's speed (m/s), given that the candidate experiences a centripetal acceleration that is 2.8 times the acceleration due to gravity is 17.4 m/s
How do I determine the candidate's speed?We understood that the centripetal acceleration is related to speed and radius according to the following formula:
a = v² / r
Cross multiply
v² = ar
Take the square root of both sides
v = √ar
Where
v is the speeda is the centripetal accelerationr is the radiusWithe the above formula, we can determin the speed of the candidate. Details below:
Acceleration due to gravity (g) = 9.8 m/s²Centripetal acceleration = 2.8 × g = 2.8 × 9.8 = 27.44 m/s²Radius (r) = 11.05 mSpeed of candidate (v) =?v = √ar
v = √(27.44 × 11.05)
v = 17.4 m/s
Thus, the speed of the candidate is 17.4 m/s
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A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the distance dfirst traveled by the plane in the first second of its run?
The distance travelled by the plane in the first second of its run is 5m.
What is Velocity?Velocity is defined as the rate of change of a body’s position with respect to time. Velocity is basically speeding in a specific direction. It is a vector quantity, which means we need both magnitude (speed) and direction to define velocity. If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.
From the question;
velocity (acceleration) = 5m/s2
distance = 1800m
so, to find the distance travelled in the first second;
time = 1 second
using the formula; [tex]velocity = \frac{displacement}{time}[/tex]
therefore; displacement = velocity x time
displacement = 5 x 1
displacement = 5m
In conclusion, the plane travelled 5m in the first second of its run.
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As part of astronaut training, a prospective astronaut is spun around in a human centrifuge such that the candidate experiences a centripetal acceleration that is 2.5 times the acceleration due to gravity on the surface of the earth. If the candidate is 9.98 m from the center, determine the candidate's speed in meters per second.
The speed of the astronaut is determined as 15.64 m/s.
What is centripetal acceleration?
The centripetal acceleration of an object is the rate of change of tangential velocity of the object around a circular track.
Mathematically, the formula for centripetal acceleration is given as;
a = v²/r
where;
v is the linear speed of the astronautr is the radius of the circular pathMake v the subject of the formula and determine the candidate's speed in meters per second.
v² = ar
v = √ar
where;
a is the centripetal acceleration = 2.5g = 2.5 x 9.8 m/s²v = √(2.5 x 9.8 x 9.98)
v = 15.64 m/s
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FRQ 2
Anthony's firm produces wrestling sweatpants in a perfectly competitive market. The table below shows Anthony's total variable cost. He has a fixed cost of $240, and the price per pair of sweatpants is $60 (seriously tho, $60 ? ? 1 {m} all for spirit wear and stuff, but let's be reasonable) Quantity 6 7 8 9 10 Total variable Cost $120 $145 $165 $220 $290 $390 a. Calculate the average total cost of producing 6 and then 9 sweatpants, respectively. Show your work.
b. Calculate the marginal cost of producing the tenth pair of sweatpants. $70
c. What is Anthony's profit-maximizing quantity? Use marginal analysis to explain your answer.
d. At the profit-maximizing quantity you determined in part (c), calculate Anthony's profit or loss. Show your work.
e. Anthony also produces hoodies at a loss in a perfectly competitive market. Draw a correctly labeled graph for Anthony's firm showing the following at a market price of $200.
i. Anthony's profit-maximizing quantity of hoodies
ii. Anthony's loss, completely shaded
The output at which MC and MR are equal is the maximum profit.
Explain about the Maximum profit?
When the final unit of sales (marginal revenue) equals the final unit of production's cost, the management has maximized profit (marginal cost). The production level at which MC = MR is known as maximum profit.
Profit = Total Revenue - Total Cost is a key component of the profit maximisation formula. In light of the fact that the first order—MR = MC—and subsequent orders are dependent upon one another, a company maximizes profit when MR = MC.
As an illustration, let's say you believe that at a price of $10, you can sell 200 items while racking up $1,000 in fixed expenses and $800 in variable costs. At this pricing point, there is a total revenue of $2,000 ($200 x $10). The profit is $200 due to the $1,800 total in expenses.
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Suppose you drop a book. As the book is falling to the ground, which of the following statements is true?
A. The magnitude of the force that the Earth exerts on the book is larger than the magnitude of the force that the book exerts on the Earth
B. Because the book is in free fall, there is no force between the Earth and book.
C. The magnitude of the force that the Earth exerts on the book is smaller than the magnitude of the force that the book exerts on the Earth
D. The magnitude of the force that the Earth exerts on the book is the same as the magnitude of the force that the book exerts on the Earth
The magnitude of the force that the Earth exerts on the book is the same as the magnitude of the force that the book exerts on the Earth. Thus, the correct option is D.
What is Newton's third law of motion?The Newton's third law of motion states that for each and every action i.e., force in nature there is an equal and opposite reaction. If an object exerts force on another object, the another object will also exert an equal and opposite force on the first object. In other words, forces result from interactions of object.
In this case, as the book falls on the ground, the force will is exerted on the ground by the book is same in magnitude to the force exerted by the book on the ground.
Therefore, the correct option is D.
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2×3.14√(1.0m/(9.8〖ms〗^(-1) )=)
This is the period in a simple harmonic motion which is 2 seconds in this question.
What is Period ?The period of an oscillatory object can be defined as the total time taken by a vibrating body to make one complete revolution about a reference point.
We are given the below question
2×3.14√(1.0m/(9.8〖ms〗^(2) )= T
This question can as well be expressed as
2π√(L/g) which is equal to period T.
In a nut shell, Period T = 2×3.14√(1.0m/9.8)
T = 6.28√0.102
T = 6.28 × 0.32
T = 2.006 s
Therefore, the period T of the oscillation is 2 seconds approximately.
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18. The police estimate that for good road conditions the frictional force, F, on a skidding vehicle of mass m is
given by F = 0.8mg. A car of mass 450 kg skids to a halt narrowly missing a child. The police measure the skid
marks and find they are 12.0m long.
(i)
Calculate the deceleration of the car when it was skidding to a halt.
The child's mother says the car was travelling well over the speed limit of 50 kmh but the driver of the car
says she was travelling at 48 kmh and the child ran out in front of her.
The deceleration will be calculated by dividing the final velocity minus the initial velocity by the time it takes for the velocity to drop.
How to Calculate the deceleration of the car ?When we are in a vehicle and feel like we are moving forward relative to the vehicle, we are decelerating. Deceleration is a subset of acceleration that only applies to objects slowing down. It is thus the rate at which an object slows down.
Because acceleration must be reported as a magnitude with a direction, it is a vector. Negative and positive signs are used to indicate direction in one-dimensional motion. Thus, if the signs are negative, the object is slowing down.
It is calculated as follows:
FinalVelocity-InitialVelocityTimetaken = Deceleration
It is denoted by -a, where an is the rate of acceleration.
If the starting velocity, final velocity, and time taken are provided, the Deceleration Formula is as follows:
a = v−ut
If we have the initial velocity, the final velocity, and the distance traveled, we can calculate deceleration as follows:
a = v2–u22s
Where,
-a Deceleration
u Initial velocity
v Final velocity
s Distance
t Time
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The deceleration will be calculated by dividing the final velocity minus the initial velocity by the time it takes for the velocity to drop.
How to Calculate the deceleration of the car ?When we are in a vehicle and feel like we are moving forward relative to the vehicle, we are decelerating. Deceleration is a subset of acceleration that only applies to objects slowing down. It is thus the rate at which an object slows down.Because acceleration must be reported as a magnitude with a direction, it is a vector. Negative and positive signs are used to indicate direction in one-dimensional motion. Thus, if the signs are negative, the object is slowing down.It is calculated as follows:
FinalVelocity-InitialVelocityTimetaken = Deceleration
It is denoted by -a, where an is the rate of acceleration.
If the starting velocity, final velocity, and time taken are provided, the Deceleration Formula is as follows:
a = v−ut
If we have the initial velocity, the final velocity, and the distance traveled, we can calculate deceleration as follows:
a = v2–u22s
Where,
-a Deceleration
u Initial velocity
v Final velocity
s Distance
t Time
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I You are driving down the road at 15.6 m/s (35 mph) when an ambu-
lance passes you with its siren blaring. The ambulance siren produces
a frequency of 700 Hz. As the ambulance approaches you from be-
hind, you hear a frequency of 740 Hz. (a) What is the speed of the am-
bulance? (b) What frequency do you hear after the ambulance passes?
The speed of the ambulance is 33.35 m/s and the frequency heard after the ambulance passes is 667.07 Hz.
Calculation:-
V = f(344 - 15.6/344 - vs)
740 = 700(344 - 15.6/344 - vs)
344 - V s = 70/74 (344 - 15.6)
344 - V s = 310.64
V s = 33.35 m/s
After pass
F = 700 ( 344 + 15.6/344 + 33.35)
= 700 × 359.6/377.35
F = 667.07 Hz
Frequency is the wide variety of occurrences of a repeating event in line with a unit of time. The time period frequency refers to the variety of waves that pass a set factor in unit time. It additionally describes the number of cycles or vibrations undergone for the duration of one unit of time with the aid of a body in periodic motion.
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A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 4.80 m/s in 0.848 s. What are the magnitudes of the linear impulse and the average total force experienced by a 70.0 kg passenger in the car during the time the car accelerates?
linear impulse = ? Kg•m/s
Average force = ? N
The magnitude of the linear impulse are 336.57 N sec
Impulse is the critical of a force, F, over the time c language, t, for which it acts. seeing that pressure is a vector quantity, the impulse is likewise a vector quantity. Impulse implemented to an item produces an equal vector trade in its linear momentum, additionally inside the resultant course.
Calculation:-
mass = 70 kg
acceleration = (4.80 - 0 ) / 0.848
= 5.67 m/s²
Force = mass × acceleration
= 70 × 5.67
= 396.9 N
Impulse = force × time
= 396.9 N × 0.848 s
= 336.57 N sec
An impulse is an unexpected pressure or preference — this will be an electrical impulse or an impulse to get some pizza. in case you act on a sudden feeling or notion, you are following an impulse. it is like a whim: an impulse isn't always something you've given numerous ideas.
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a 2 kg rolling ball has a velocity of 3 5 ms what is its momentum
A 2 kg rolling ball has a velocity of 3.5 m/s, and its momentum is 7 kg m/s.
Momentum =Mass×Velocity
Mass=2kg
Velocity=3.5m/s
Momentum = 2×3.5
Momentum = 7 kg m/s
In Newtonian mechanics, momentum is the result of an object's mass and velocity, more precisely linear momentum or translational momentum. It has a direction and a magnitude, making it a vector quantity.
The kilogram meter per second (kg m/s), which is a unit of measurement for momentum in the International System of Units (SI), is a unit of measurement for a newton-second. According to Newton's second law of motion, a body's momentum changes at a rate equal to the net force acting on it.
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write the equation to show how force and acceleration are related
F = ma, or force is equal to mass times acceleration, is the equation used in Newton's second law of motion to demonstrate the relationship between force and acceleration.
What is force and acceleration?A force pushes or pulls an object. The total of all forces acting on an object is known as the net force. An object will change speed in the direction of the net force when there is one applied to it. The object's acceleration reveals how much it accelerates or decelerates.
Newton's second law of motion explains the connection between force and acceleration. They are of the same size. The acceleration of an object rises by the same amount as the force being applied to it. Force is simply defined as mass times acceleration.
What is the acceleration force formula and Can you have acceleration without a force?Mass (kg) times acceleration (m/s2) equals force (N). Therefore, an object with constant mass will accelerate in direct proportion to the applied force.
There won't be any acceleration if there are no external forces operating on the object. The object will move at a constant speed if there is no acceleration. We may examine Newton's second law and the acceleration formula mathematically.
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Base quantity and among following is 1 electric charge 2amount of substance 3 area 4 volume
Area is the base quantity. A base quantity is one of the physical quantities that make up a traditionally selected subset, and it is one that cannot be stated in terms of the other physical quantities in the subset.
Is space a fundamental quantity?Area can therefore be stated using square meters (mm=m2) as a derived number in terms of SI base units. ( m × m = m 2 ) . The same is true for volume, which is a derived quantity that can be expressed in cubic meters (m3).A base quantity is one of the physical quantities that make up a traditionally selected subset, and it is one that cannot be stated in terms of the other physical quantities in the subset.A base quantity is one of the physical quantities that make up a traditionally selected subset, and it is one that cannot be stated in terms of the other physical quantities in the subset. There are seven basic fundamental quantities: length, mass, time, electricity, substance amount, light intensity, and temperature.To learn more about Base quantity refer to:
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What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =[tex]\frac{1}{2}[/tex] * 4.2 * 32²
=2,150.4 kgm²
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4. Two students standing on skateboards with frictionless bearings face the same direction
with student x behind student y, as shown above. If student x pushes on student y's back,
which of the following is true?
(A) Both students roll backward
(B) Student x rolls backward and student Y remains still
(C) Student X rolls backward and student Y rolls forward
(D) Student X remains still and student Y forward
(E) Neither student moves
According to Newton's third law of motion Student X rolls backward and student Y rolls forward.
What are Newton's laws?Unless and until an external force acts on a body, it remains at rest or in uniform motion along a straight line. In simple terms, Newton's first law of motion states that a body will not begin to move unless and until an external force acts on it.His second statement states that a force is defined as the change in momentum (mass times velocity) divided by the change in time. Momentum is defined as an object's mass m multiplied by its velocity V.Newton's third law asserts that there is an equal and opposite reaction to every action (force) in nature. When object A applies a force to object B, object B applies an equal and opposite force to object A.To learn more about Newton's laws refer,
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The student detarmined the deneity of the rock to be 2.55 ± 0.10 g / cm²
What are the maximum and minimum values for the density of the rock?
Maximum density = _____ g/cm²
Minimum denety = ______ g / cm²
Table 1 gives the density of five different types of rock. Type of rock Basalat Chalk Fint Sand stone Slate Density in gm/cm² 2.90 ± 0.10 2.35 ± 0.15 2.60 ±0.10 2.20 ± 0.20 2.90 ± 0.20 Which two types of rock in Table 1 could be the type of rock the student had? Tick (✓) one box.
Basalt or chalk
Chalk or flint
Flint or sandstone
Sandstone or slate
022.) The maximum and minimum values for the density of the rock are:
Maximum density = 2.65 g/cm²
Minimum density = 2.45 g / cm²
023.) The two types of rock in table 1 which could be the type of rock the student had are chalk or flint.
What is density?Density is defined as the quantity that measures the mass of a substance with respect to its volume.
Mathematically, density is represented as d = mass/volume. = D = m/v = kg/m³ or g/cm³.
The maximum and minimum values of the density of a rock can be determined as follows:
Maximum density= 2.55+ 0.10 = 2.65g/cm³
Minimum density= 2.55 - 0.10 = 2.45g/cm³
There are five different rocks given which has the following density values:
Basalat = 2.90+/- 0.10 = 3.00 or 2.80g/cm³
Chalk = 2.35+/-0.15 = 2.50 or 2.20g/cm³
Fint = 2.60+/- 0.10 = 2.70 or 2.50g/cm³
Sandstone = 2.20 +/-0.20 = 2.00 or 2.40 g/cm³
Slate = 2.90+/- 0.20 = 3.10 or 2.70g/³
Therefore, the two types of rock in table 1 which could be the type of rock the student had are chalk or flint.
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When considering gravity acceleration and the force of acceleration, what must be true? Question 4 options: A) The mass of the body must be the same as the acceleration of the body. B) The direction of the force and the direction of acceleration must be opposite of each other. C) The direction of acceleration must be perpendicular to the direction of the force. D) The direction of the force and the direction of acceleration must be the same as each other.
Answer:
The answer is D) The direction of the force and the direction of acceleration must be the same as each other.
Answer:
The direction of the force and the direction of acceleration must be the same as each other
Explanation:
Phobos, one of the moons of Mars, orbits at a distance of 9378 km from the center of the red planet.
Part A What is the orbital period of Phobos?
The orbital period of Phobos is 7.66 hours.
What is orbital period?The orbital period also known as the revolution period is the amount of time it takes an astronomical object to complete one orbit around another. It usually refers to planets or asteroids orbiting the Sun, moons orbiting planets, exoplanets orbiting other stars, or binary stars in astronomy.
It will be calculated thus:
T^2 = (4π)^2( d^3) / ((G)(Mm))
where d is the distance in meters, 9.378 x 10^6 meters
(4π)^2 = 39.5
G = 6.67 x 10^-11 m^3 kg^-2 s^-2
Mm = the mass of Mars in kg which is 6.42 x 10^23 kg.
T^2 = 7.61 x 10^8 sec^2
Find the square root.
T = 2.76 x 10^4 sec
T = 7.66 hours
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a vector x when added to two vectors = 5i - 7j + 7k and b 2i + 4j - 3k give a unit vector along y axis as their resultant find the acceleration of body of 5kg When x act an the body
please help !!!!!!!!!!!!!!
Randi has become very proficient at using Photoshop, but as a photojournalist cannot ethically alter photos except to do what?
fix people’s skin if they have blemishes
get rid of clutter in the background
change people’s hair color
adjust brightness
Answer:
the answer will be adjust brightness
Explanation:
thank you
The content of a photograph must not be altered in Photoshop or by any other means. No element should be digitally added to or subtracted from any photograph.
Do not manipulate images or add or alter sound in any way that can mislead viewers or misrepresent subjects. Do not pay sources or subjects or reward them materially for information or participation. Do not accept gifts, favors, or compensation from those who might seek to influence coverage.
In addition, it is unethical for individuals and institutions to alter images in order to fool their audience.
By what fraction would the diameter of the moon appear shortened to an observer in a rocketship travelling at a speed of 300km/sec with respect to the moon
The diameter of the Moon is around one-fourth (27.2%) of the diameter of the Earth.
what is diameter ?
A diameter of a circle would be any straight line segment that goes through the Centre of the circle and has ends that are on the circle. It can alternatively be described as the circle's longest chord. Both definitions are true for the diameter of a sphere.
In current parlance, the length d of a diameter is also referred to as the diameter. In this context, the diameter is used rather than the diameter (which corresponds to the line segment itself), since all diameters of a circle or sphere share the same length, which is twice the radius.
3476 km is the diameter of the moon (equator) 3472 kilometres
The diameter of the Earth is 12756 km at the equator and 12742 km at the poles.
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How can you tell how objects differ in density?
Answer:
You have to compare the densities,
Explanation:
To find density:
1. Measure the object's weight
2. Divide the mass by the volume
a heater has a power of 2500W. The heater is turned on for 180 seconds. Calculate the energy transferred by the heater
The energy transferred by the heater that has a power of 2500W and is turned on for 180s is 450,000J.
How to calculate energy?Electrical energy is the energy made available for consumption or consumed in the form of electricity or electric power.
Electrical energy can be calculated as follows:
Electrical energy = Power x Time.
The total amount of electrical energy used depends on the total power used by all electrical devices and the total time they are used in the home.
According to this question, a heater has a power of 2500W and is turned on for 180 seconds. The energy can be calculated as follows;
E = 2500W × 180s
E = 450,000J
Therefore, 450,000J is the energy transferred to the heater.
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An object of mass 2kg moves in circles at radius 8m at uniform speed of 30m/s calculate. A_angular velocity B_ceritripetal force
The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.
The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.
Calculation:-
A. angular velocity ω = v/r
= 30 /8
= 3.75 m/s
B. Centripetal force = mv²/r
= 2×30²/8
= 225 N
There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.
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Response
Sheet-Investigation 2
A friend at another school sends you an email. In that
email your friend tells you that they are studying the
solar system in science class. Your friend is confused
about gravity.
They read in a science book that gravity is a force that
keeps planets in orbit around the Sun. But your friend
thought that gravity is the force that pulls things toward
the center of Earth. For example, when you drop a bail,
it falls down to the ground.
Your friend asked this question. Is it possible that both
these things could be true about gravity?
Write a reply to your friend. What would you tell your
friend to help him or her answer this question?
Of course, the majority of gravitational forces are too small to be felt. Only as an object's mass increases can gravitational forces be observed.
What is the Universality of Gravity?There are other objects besides the earth and the sun and other planets that interact gravitationally as well.All objects are subject to gravitational interactions, the strength of which is directly inversely proportional to the product of their masses.You are therefore gravitationally drawn to your lab partner, the desk you are working at, and even your physics book when you sit in your seat in the physics classroom.Gravity is a universal force that all things are attracted to in proportion to the product of their masses, according to Newton's ground-breaking theory.Everywhere there is gravity.Of course, the majority of gravitational forces are too small to be felt. Only as an object's mass increases can gravitational forces be observed.To learn more about gravity, refer to
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What is the momentum of a 2000 kg truck traveling at 35 m s?
Momentum of the truck will be 70000 kg-m/s
Momentum can be defined as the impulse gained by a moving object.
Also it can be defined as the product of mass of the object with the velocity by which it is moving.Momentum can only be calculated when the body is in motion.The SI unit for momentum is kg-m/sIt is a vector quantity and has the direction same as that of the velocity of the object.It is represented by M and mathematically, M = Mass * VelocityMass of the truck = m = 2000 kg
Velocity of the truck = v = 35 m/s
Momentum = M = m * v
M = 2000 * 35
M = 70000 kg-m/s
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A 11.1 kg block of steel is pushed at a constant speed across
a Teflon surface. What is the normal force on the block?
(Answer to one decimal place with no units.)
The normal force on the block of steel of mass 11.1Kg at constant speed is 108.8 N.
Mass of steel block = 11.1 Kg
Normal force on the block = Force exerted by the surface on the block
= mass × acceleration due to gravity
= m × g
Taking the value of g as 9.8 m/s
= 11.1 × 9.8
= 108.78 N
By converting the answer to one decimal place, round the value to
= 108.8 N
Thus, the normal force on the block of steel by the Teflon surface round to one decimal place is 108.8 N.
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You wish to place a spacecraft in a circular orbit around the earth so that its orbital speed will be 4.00×10^3m/s. What is this orbit's altitude above the earth's surface?
The orbit's altitude above the earth's surface is 2.29 x 10^7 meters.
What is altitude?Altitude or height is a distance measurement, usually in the vertical or "up" direction, between a reference datum and a point or object.
We are given that
Orbital speed= 4.00×10^3 m/s
We have to find the radius of orbit of spacecraft.
We know that
Gravitational constant = 6.67x 10^-11 m³ kgs²
mass of earth = 5.972 x 10^24 kg
orbital speed = [tex]\sqrt{ \frac{GM}{r}[/tex]
Where G= Gravitational constant
M=Mass of earth
r=Radius of orbit
Substituting the values in the formula and evaluating, we have
r = 2.29 x 10^7 meters
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a solid shape is made from centimetre cubes here are the plan front elevation and the side elevation of the shape centimetre cubes are added to make this cuboid
The number of cubes that are added to make it a cuboid s 30.
What is a cube?The shape of a cube is sometimes referred to as "cubic." Another way to put it is that a cube is a block with uniform length, width, and height. It also has 12 edges and 8 vertices, with three of the edges meeting at a single vertex point. Examine the diagram below, noting the faces, edges, and vertices. It is also known as a square parallelepiped, a right rhombohedron, and an equilateral cuboid.
The cube, one of the platonic solids, is a convex polyhedron with all of its faces square. The cube can have either cubical or octahedral symmetry. A square prism is a specific type of cube.
The number of blocks needed to make the cuboid
= 4 * 4 * 3 = 48 cm cubes.
Therefore the number of cubes to be added
= 48 cubes - 18 cubes
= 30 cubes.
30 cubes are added.
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