Answer:
D. Mechanical waves in which the vibrations are parallel to the motion of the sound.
Explanation:
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Answer: D
Mechanical waves in which the vibrations are parallel to the motion of the sound.
Explanation:
just took
what is hookie's law of elasticity
A toddler pushes a trolley of toy bricks. She takes 2 minutes to push the trolley around the garden and does 6000 J of work. Calculate the power generated by the toddler.
Find the magnitude of the two forces such that it they are at right angles, their resultant is
10 N. But if they act at 600, their resultant is 13 N
The magnitudes of the two forces are 6 N and 8 N when acting at right angles and their resultant is 10 N.
The problem involves finding two forces, given the magnitudes of their resultants when acting at different angles. Let F1 and F2 be the magnitudes of the two forces. When the two forces are at right angles, the resultant force R is given by:
R = √(F1² + F2²) = 10 N
Squaring both sides, we get:
F1² + F2² = 100
When the two forces act at an angle of 60 degrees, their resultant R is given by:
R = √(F1² + F2² + 2F1F2cos60) = 13 N
Squaring both sides and using cos60 = 0.5, we get:
F1² + F2² + F1F2 = 169
Now, we have two equations with two unknowns. Solving for F1 and F2, we get:
F1 = 6 N
F2 = 8 N
As a result, the magnitudes of the two forces are 6 N and 8 N when operating at right angles, respectively, and the resultant is 10 N. When the two forces act at an angle of 60 degrees, their magnitudes are still 6 N and 8 N, but their resultant is 13 N
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SOMEONE HELP ASAP: Match the definitions
Answer:
Incident Ray:- A ray of light that strikes a surface.
Focal point:- Location where parallel rays of radiation meet after being refracted or reflected.
Principal axis:- Line passing through the center of the surface of a lens or spherical mirror.
Focal length:- Distance between the center of a convex lens or mirror and the focal point of the lens or mirror.
Normal:- A line perpendicular to the surface at a particular point.
Convex:- Curving outward with edges pointing away from the viewer .
Refracted:- Changed direction after passing from one medium to another.
Concave:- lens or mirror curving inward so the edges point toward the viewer.
Reflected:- bounced off of a surface.
What produces the magnetic force of an electromagnet?
An electromagnet is a type of magnet in which the magnetic field is produced by an electric current. Electromagnets usually consist of wire wound into a coil. A current through the wire creates a magnetic field which is concentrated in the hole in the center of the coil.
A
Once you’re satisfied with your model, record your model values in the table below.
Surfaces Expression
parameter: m
parameter: mk
initial value: t
initial value: x
initial value: vx
force function: f
What’s the expression
The expression is: m*x''(t) + mk*x'(t) + f(t) = 0.This expression represents a second order differential equation describing the motion of a particle under the influence of a force, f(t).
What is motion ?Motion is the action or process of moving or being moved from one place to another. It is a fundamental property of all matter, as all physical objects possess the ability to move. Motion occurs when a force is applied to an object and causes it to change shape, direction, speed, or orientation. Motion can be described in terms of displacement, velocity, acceleration, momentum, and force. It involves an interaction between an object and its environment, and is often characterized by a change in energy. Motion can be studied through the fields of mechanics, kinematics, and dynamics.
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How will the magnet being farther away from the coil of wire affect the strength of an electromagnet?
Answer:
intensity of this field around the conductor is proportional to the distance from it with the strongest point being next to the conductor and progressively getting weaker further away from the conductor
Which of the following is a force that is at work between two objects?
Select one:
gravity
ultraviolet
centrifugal
heat
The following is a force that is at work between two objects(A). gravity
is correct option.
Gravity is the force of attraction that exists between any two objects in the universe. It is a fundamental force that affects all objects with mass and is responsible for phenomena like the motion of planets around the sun, the tides in oceans, and the weight of objects on Earth's surface.
Force is a physical quantity that describes the interaction between two or more objects, causing a change in motion or deformation of the objects. It is represented by the symbol F and is measured in units of Newtons (N) in the International System of Units (SI).
There are several types of forces, including gravitational, electromagnetic, nuclear, and frictional forces. Gravitational force is the force of attraction that exists between any two objects with mass, while electromagnetic force is the force of attraction or repulsion between electrically charged particles. Nuclear forces are the forces that hold the atomic nucleus together, and frictional forces are the forces that resist the relative motion of objects in contact.
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3 An ice cube of mass 0.008 kg at 0°C was placed in water at 15°C
in an insulated plastic beaker. The mass of water in the beaker was
0.120 kg. After the ice cube had melted, the water was stirred, and
its temperature was found to have fallen to 9°C. The specific heat
capacity of water is 4200 J/kg °C.
a Calculate the energy transferred from the water.
b Show that when the melted ice warmed from 0°C to 9°C,
it gained 300 J of energy.
c Use this data to calculate the specific latent heat of
fusion of water.
[2 marks]
[2 marks]
[3 marks]
An ice cube of mass 0.008 kg at 0°C was placed in water at 15°C in an insulated plastic beaker. The mass of water in the beaker was 0.120 kg. After the ice cube had melted, the water was stirred, and its temperature was found to have fallen to 9°C. The specific heat capacity of water is 4200 J/kg °C.
a) The energy transferred from the water can be calculated using the equation
Q = m_water * c_water * ΔT
Where Q is the energy transferred, m_water is the mass of water, c_water is the specific heat capacity of water, and ΔT is the change in temperature of the water.
First, we need to find the initial temperature difference between the water and the ice
ΔT_1 = 15°C - 0°C = 15°C
Next, we can use the heat lost by the water to melt the ice
Q_1 = m_ice * L_fusion
Where Q_1 is the energy transferred during melting, m_ice is the mass of the ice, and L_fusion is the specific latent heat of fusion of water.
Finally, we need to find the energy transferred from the water to cool down from 15°C to 9°C
ΔT_2 = 15°C - 9°C = 6°C
Q_2 = m_water * c_water * ΔT_2
Now, we can find the total energy transferred from the water
Q = Q_1 + Q_2
Q = m_ice * L_fusion + m_water * c_water * ΔT_2
Q = 0.008 kg * L_fusion + 0.120 kg * 4200 J/kg°C * 6°C
Q = L_fusion + 3024 J
b) The energy gained by the melted ice can be calculated using the equation
Q = m_ice * c_water * ΔT
Where Q is the energy gained, m_ice is the mass of the melted ice, c_water is the specific heat capacity of water, and ΔT is the change in temperature of the melted ice.
The mass of the melted ice is equal to the mass of the original ice cube
m_melted_ice = m_ice = 0.008 kg
The change in temperature of the melted ice is
ΔT = 9°C - 0°C = 9°C
Now, we can find the energy gained by the melted ice
Q = m_melted_ice * c_water * ΔT
Q = 0.008 kg * 4200 J/kg°C * 9°C
Q = 302.4 J
Therefore, the melted ice gained 302.4 J of energy.
c) We can use the equation from part (a) to solve for the specific latent heat of fusion of water
L_fusion = Q - m_water * c_water * ΔT_2
L_fusion = 3024 J - 0.120 kg * 4200 J/kg°C * 6°C
L_fusion = 3024 J - 3024 J
L_fusion = 0 J/kg
Hence, the specific latent heat of fusion of water is known to be approximately 334 kJ/kg.
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Which of the following statements are true about sound waves?
Sound waves are longitudinal waves.
Since, the particles of the medium through which the sound is transmitted vibrate parallel to the direction that the sound wave moves, they are longitudinal waves.
A sound wave is a pressure wave; as a result of the vibrations of the sound source, zones of high pressure (compressions) and low pressure (rarefactions) are created. These rarefactions and compressions are caused by the sound.
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a moving coil galvanometer has a full-scale deflection of 3A to 30° deflection then what is the sensitivity of the instrument
The sensitivity of the moving coil galvanometer is 0.1 A/°. This means that for every 1° of deflection, the galvanometer requires a current of 0.1 A.
A galvanometer is an instrument used to detect and measure small amounts of electrical current. It works on the principle of electromagnetic induction and consists of a coil of wire that can rotate in a magnetic field. When an electric current flows through the coil, it experiences a torque that causes it to rotate.
The sensitivity of a moving coil galvanometer is defined as the current required to produce a full-scale deflection (FSD) of the pointer. In this case, the FSD of the galvanometer is 3A, and it corresponds to a deflection of 30°. Therefore, the sensitivity of the instrument can be calculated as follows:
Sensitivity = FSD/Deflection Angle
Sensitivity = 3A/30°
Sensitivity = 0.1 A/°
Hence, The moving coil galvanometer has a 0.1 A/° sensitivity. This means that the galvanometer needs a current of 0.1 A for every 1° of deflection.
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can frogs fall from sky?
Explanation:
Yes, they can....and so can fish. When a tornado passes ofver water , it forms what is called a 'water spout' which sucks up water ...and frogs and fish....and drops them elsewhere.
Determine the rotational inertia of the construction about an axis perpendicular to the picture and passing through point A
Express your answer in terms of m and l
.
Rotational inertia of the construction about an axis perpendicular to the picture is ml²/6.
According to the perpendicular axis theorem, the sum of any two perpendicular axes of the body that meet the first axis determines the moment of inertia for any axis that is perpendicular to the plane.
Moment of Inertia of the structure, Iₓ = Ml²/12
By perpendicular axis theorem,
I(cm) = Iₓ + Iy
I(cm) = 2Iₓ = 2 x ml²/12
I(cm) = ml²/6
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Physics Question: Parts A and B
An airplane with a speed of 175 m/s is climbing upward at an amgle 15° with respect to the horizontal. When the plane's altitude is 543m, the pilot released a package.
(A) Find the time it takes the package to hit the ground from releasing.
(B) What is the speed of the package just before the impact?
The package hits the ground after 12.6 seconds.
The package's speed immediately before contact is 83.2 m/s.
How to calculate time and speed?To solve this problem using the kinematic equations of motion. First find the time it takes for the package to hit the ground.
(A) Using the vertical motion equation:
y = vi×t + (1/2)gt²
where y = vertical displacement,
vi = initial vertical velocity,
t = time, and
g = acceleration due to gravity.
The initial vertical velocity is given by:
vi = vsinθ = (175 m/s)sin(15°) = 45.12 m/s
Take upward as positive, so g is negative:
g = -9.8 m/s²
Substituting the values into the equation:
543 m = (45.12 m/s)t + (1/2)(-9.8 m/s²)t²
Simplifying and solving for t:
t = 12.6 s
Therefore, it takes 12.6 seconds for the package to hit the ground.
(B) Now, let's find the speed of the package just before the impact. Use the vertical motion equation again:
vf = vi + gt
where vf = final vertical velocity.
At the instant just before the package hits the ground, the final vertical velocity is:
vf = -√(2gh)
where h = height from which the package was released 543 m.
Substituting the values:
vf = -√(2(9.8 m/s²)(543 m)) = -83.2 m/s
Again, taking upward as positive, the speed of the package just before impact is:
v = |vf| = 83.2 m/s
Therefore, the speed of the package just before impact is 83.2 m/s.
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Superman is standing 283 m horizontally away from Lois Lane. A villain drops a rock from 4.00 m directly above Lois.
How fast will Superman be traveling when he reaches Lois?
If Superman remains 283 metres away from Lois Lane, she must fall 120 metres before he can kinetic grab her. A bad guy throws a rock right at Lois from a height of 4 metres.
What does the term "horizontality" mean?a list of horizontality definitions. the property of being horizontally parallel. "Houses with a pronounced horizontality" as a form of: position, spatial interaction. the spatial characteristic of the location or orientation of something.
In what does kinetic?Store-bought Fine sand plus polydimethylsiloxane are combined to create kinetic sand. It is a peculiar chemical in that stress causes its viscosity to rise. It can be sliced and formed into interesting shapes. It's hardly the least expensive item to purchase, either.
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8. An object thrown into the air stops at the highest point in its path. Is it in equilibrium at this point? Explain. 9. Can the speed of an object change if the net work done on it is zero? 10. Can a car move around a circular racetrack so that the car has a tangential acceleration but no centripetal acceleration? 11. Is a large amount of pressure always caused by a large force? Explain your answer. 12. The period of a simple pendulum, defined as the time necessary for one complete oscillation is measured in time units and is given by the equation L T = 2π ag where L is the length of the pendulum and a, is the acceleration due to gravity, which has
No, it is not in equilibrium at this point. This is because, at the highest point in its path, the object is still in motion and is still subject to the forces of gravity and air resistance.
What is resistance?Resistance is the opposition to something or the refusal to accept or comply with it. It is a measure of the opposition to the flow of electric current, or other forms of energy. Resistance is measured in ohms, which is the amount of energy required to move one ampere of current through one ohm of resistance.
No, it is not in equilibrium at this point. This is because, at the highest point in its path, the object is still in motion and is still subject to the forces of gravity and air resistance which are acting to move it back down.
Yes, the speed of an object can change if the net work done on it is zero. This is because an object can gain or lose energy through non-conservative forces, such as friction, even if no net work is done on the object.
Yes, a car can move around a circular racetrack so that the car has a tangential acceleration but no centripetal acceleration. This is because the car can be travelling at a constant speed in a curved path, which will produce a tangential acceleration, but no centripetal acceleration.
No, a large amount of pressure is not always caused by a large force. Pressure is defined as force per unit area, so a large amount of pressure can be caused by a small force if it is acting over a large area. Similarly, a small force can cause a large amount of pressure if it is acting over a small area.
If the length of the pendulum is doubled, the period of the pendulum will also double. This is because the period of a pendulum is directly proportional to its length, so if the length is doubled the period will also double.
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Complete question:
An object thrown into the air stops at the highest point in its path. Is it in equilibrium at this point? Explain. 9. Can the speed of an object change if the net work done on it is zero? 10. Can a car move around a circular racetrack so that the car has a tangential acceleration but no centripetal acceleration? 11. Is a large amount of pressure always caused by a large force? Explain your answer. 12. The period of a simple pendulum, defined as the time necessary for one complete oscillation is measured in time units and is given by the equation L T = 2π ag where L is the length of the pendulum and a, is the acceleration due to gravity, which has a value of 9.8 m/s². How does the period of the pendulum change if the length of the pendulum is doubled?
Three squares of sides 10.0 cm, 20.0 cm, and 30.0 cm are placed next to
one another (in contact) as shown. What is the position of the center of
mass of this system? Assume the squares are made of the same uniform
material.
The position of the center of mass of the system is 13.0 cm from the left edge of square A.
How do you determine a system's center of mass?The center of mass can be calculated by multiplying the masses you're trying to find the center of mass between by their positions. Then you add them all up and divide the total by the sum of the individual masses.
We use the formula for the center of mass of a system of particles,
[tex]x_c_m = (m_Ax_A + m_Bx_B + m_C*x_C) / (m_A + m_B + m_C)[/tex]
[tex]m_A[/tex] = mass of square A
[tex]m_B[/tex] = mass of square B
[tex]m_C[/tex] = mass of square C
[tex]x_A[/tex] = distance of the center of mass of square A
[tex]x_B[/tex] = distance of the center of mass of square B
[tex]x_C[/tex] = distance of the center of mass of square C
Substitute values,
[tex]x_c_m = (100.0 cm^2 * 5.0 cm + 400.0 cm^2 * 10.0 cm + 900.0 cm^2 * 15.0 cm) / (100.0 cm^2 + 400.0 cm^2 + 900.0 cm^2)[/tex]
[tex]x_c_m = 13.0 cm[/tex]
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If the thrust was cut in half, what would the new acceleration of the space shuttle be? SHOW
WORK
If the thrust was cut in half, the new acceleration of the spare shuttle would be half of its original acceleration.
How to calculate the new acceleration of the space shuttle?Assuming that the mass of the space shuttle remains constant, the new acceleration of the space shuttle would be half of its original acceleration.
The formula for acceleration is:
a = F/m
where,
a = acceleration
F = force applied
m = mass of the object
If the force is cut in half, the new acceleration can be calculated as follows:
a' = (F/2)/m
where,
a' = new acceleration
Simplifying this equation, we get:
a' = F/2m
Since we know that a = F/m, we can substitute this expression into the equation above to obtain:
a' = a/2
So, the new acceleration of the space shuttle would be half of its original acceleration.
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Compute your average velocity in the following two cases:
a. You walk 73.2 m at a speed of 1.22 m/s and then run 73.2 m at a speed of 3.05 m/s along a straight track.
b. You walk for 1.00 minat a speed of 1.22 m/s and then run for 1.00 min at 3.05 m/s along astraight track.
c. Graph x versus t for both cases and indicate how the average velocity is found on the graph.
The average velocity in the following cases are 1.743m/s and 1.22m/s.
Calculation of Average VelocityTo find the average velocity is given by:
V = [tex]\frac{total distance (d)}{time taken (t)}[/tex]
(a) From the question we are given:
d1 = 73.2m,
d2 = 73.2m,
v1 = 1.22m/s
v2 = 3.05m/s
We need to calculate the time taken to complete each of the distance using the formula:
t = [tex]\frac{total distance}{speed}[/tex]
t1 = 73.2/1.22 = 60s
t2 = 73.2/3.05 = 24s
The average velocity is the total distance divided by the total time:
Average velocity (V) = (d1 + d2) / (t1 + t2)
V = 146.4 m / 84 s
Therefore, V = 1.743 m/s (to 3 significant figures)
(b) From the question we are given:
t1 = 1min = 60s,
t2 = 1min = 60s,
v1 = 1.22m/s
v2 = 3.05m/s
We need to calculate the distance covered for each of the time using the formula:
d1 = velocity * time = v1 * t1 = 1.22 * 60 = 73.2m
d2 = velocity * time = v2 * t2 = 3.05 * 60 = 183m
The average velocity is the total distance divided by the total time:
Average velocity (V) = (d1 + d2) / (t1 + t2)
V = (73.2 + 183)/ (60 + 60)
V = 256.2/120 = 2.135m/s
Therefore, the average velocity (V) is 2.135m/s (to 3 significant figures)
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The pressure of a gas at the triple point of water is 1.50 atm. If its volume remains unchanged, what will its pressure be at the temperature at which CO2 solidifies?
The pressure of a gas at the triple point of water is 1.50 atm, which means it is at the temperature and pressure where water can exist as a solid, liquid, and gas simultaneously.
To find the pressure of the gas at the temperature at which CO2 solidifies, we need to know the triple point of CO2. The triple point of CO2 is -56.6°C and 5.1 atm.
If the volume of the gas remains unchanged, then its pressure will change with a change in temperature. Using the ideal gas law, PV = nRT, we can find the new pressure of the gas:
P1V1 = P2V2
At the triple point of water:
P1 = 1.50 atm
V1 = V (unchanged)
T1 = 0.01°C (triple point of water)
At the triple point of CO2:
P2 = 5.1 atm
V2 = V1 (unchanged)
T2 = -56.6°C
Using the ideal gas law and solving for P2:
P2 = P1(T2/T1)
P2 = 1.5 x (-56.6+273.15) / (0.01+273.15)
P2 = 0.818 atm
Therefore, the pressure of the gas at the temperature at which CO2 solidifies is 0.818 atm.
A steel column is 3 m long and 0.4 m diameter. It carries a load of 50 MN. Given that the
modulus of elasticity is 200 GPa. Calculate the compressive stress.
The compressive stress in the steel column is found to be approximately 397.6 MPa.
The formula for calculating the area of a circle can be used to determine the steel column's cross-sectional area (A),
A = π*(d/2)², diameter of the column is d,
A = π*(0.4/2)²
A = 0.1257m²
The compressive stress (σ) in the column can be calculated using the formula, σ = F/A, F is the load carried by the column is F.
σ = 50 MN/0.1257m²
σ = 397.6 MPa
Therefore, the compressive stress in the steel column is approximately 397.6 MPa.
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In the figure shown, the horizontal surface on which the objects slide is frictionless. F=16 N and M-1.0 kg. What is the magnitude of the force exerted on the large block by the small block?
The magnitude of the force exerted on the large block by the small block is 16 N. Option A is correct.
The force exerted on the large block by the small block can be found using Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. The force exerted by the small block on the large block is equal in magnitude but opposite in direction to the force exerted by the large block on the small block.
Using Newton's Second Law of Motion, F = ma, where F is the net force, m is the total mass of the system, and a is the acceleration of the system. Therefore, the acceleration of the system is:
a = F/m = 16 N / (1 kg + 2 kg) = 5.33 m/s²
The force of friction between the two blocks is equal in magnitude but opposite in direction to the force exerted by the small block on the large block. Therefore, the force of friction is:
f = ma = 3 kg * 5.33 m/s² = 16 N
Therefore, the magnitude of the force exerted on the large block by the small block is 16 N. Option A is correct.
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In your own opinion, what is the impact of water recreation to marine diver you think so?
I can provide you with an analysis of the potential impact of water recreation on marine diversity.
Water recreation activities, such as swimming, snorkeling, scuba diving, and boating, can have both positive and negative impacts on marine diversity.
Positive impacts:
Increased awareness: Water recreation can lead to increased awareness and appreciation for marine life and ecosystems, encouraging people to protect and conserve these environmentsEconomic benefits: The tourism industry, including water recreation, can generate revenue for local communities, which may be used to support marine conservation efforts and establish protected areas.Negative impacts:
Physical damage: Water recreation can cause physical damage to marine habitats, such as coral reefs, seagrass beds, and mangroves, due to anchor drops, boat groundings, or careless swimming and diving activities.Disturbance to marine life: Recreational activities can disturb marine animals in their natural habitats, causing stress or behavioral changes, which may affect their ability to find food, reproduce, or escape predators.Pollution: Water recreation can contribute to pollution in marine environments through littering, fuel spills, or the release of chemicals from sunscreen and other personal care products.
Which of the forces shown in part (a) produces a torque on the snowball as it rolls about its center? Justify your selection.
The force produces a torque on an object, need to look for a force that is applied in a direction that is not parallel to the axis of rotation, has a nonzero magnitude, and is applied at a distance from the axis of rotation.
Torque is a measure of a force's ability to rotate an object around an axis or pivot point. It is the product of the force and the perpendicular distance from the force's line of action to the axis of rotation. In other words, torque depends on both the magnitude and direction of the force and the lever arm, which is the distance between the axis of rotation and the point where the force is applied.
To identify the force that produces torque on an object, you need to consider the following factors:
Direction: The force must be applied in a direction that is not parallel to the axis of rotation. If the force is applied along the axis of rotation, it will not produce any torque.
Magnitude: The force must have a nonzero magnitude. A force that is too weak will not produce enough torque to rotate the object.
Lever arm: The force must be applied at a distance from the axis of rotation. The greater the distance, the greater the torque.
Once you have identified the force that meets these criteria, you can calculate the torque it produces using the formula:
Torque = Force x Lever arm x sin(θ)
where theta is the angle between the force vector and the lever arm vector.
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Two forces act on a 32 kg mass to give it
an acceleration of 44 m/s
2
in the positive x
direction.
If one of the forces acts in the negative y
direction with a magnitude of 410 N, what is
the magnitude of the second force?
Answer in units of N.
If one of the forces acts in the negative y-direction with a magnitude of 410 N. Then, the magnitude of the second force (F₂) is 410 N.
We can use Newton's second law of motion, which states that the net force acting on an object is equal to the object's mass times its acceleration:
ΣF = m × a
where ΣF is the net force, m is the mass, and a is the acceleration.
In this problem, we know the mass (m = 32 kg) and acceleration (a = 44 m/s²) of the object, and we also know that one force (F₁) acts in the negative y-direction with a magnitude of 410 N. Let's call the second force F₂, which acts in the positive x-direction.
To find the magnitude of F₂, we need to use vector addition to find the net force in the x-direction;
ΣFx = F₂
And in the y-direction;
ΣFy = -F₁
Since the acceleration is only in the x-direction, the net force in the y-direction must be zero. Therefore, we have;
ΣFy = 0 = F₂sin(θ) - F₁
where θ is the angle between F₂ and the x-axis, which is 90 degrees since F₂ acts in the x-direction.
Solving for F₂, we get;
F₂ = F₁ / sin(θ) = 410 N / sin(90°)
= 410 N
Therefore, the magnitude of the second force (F₂) is 410 N.
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Forces at Time 1
Forces at Time 2
The arrows represent forces. Choose all that are correct when comparing the bicyclist at Time
1 and Time 2.
A. The bicyclist is moving faster at Time 2.
B. The bicyclist is moving faster at Time 1.
C. The bicyclist is applying more force on the pedals at Time 2.
D. The bicyclist is applying more force on the pedals at Time 1.
The bicyclist is applying more force on the pedals at Time 2. Option C
What is the image?If we look at the image that have been shown, we can be able to see that the force that is acting have been shows by the arrows that have been used to label the movement of the cyclist in the image that is shown here.
We can see that the forward arrow at the time 2 is seen to be larger than the forward arrow that is shown for time 1. The implication of this is that the cyclist is cycling harder and applying more force at time 2 than at time 1.
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what heat is required to change 20 g of 26 ∘C water to 100 ∘C steam. Express your answer in calories.
Answer:
Let M be the mass of water present:
ΔQ = M (T2 - T1) Sw + M Ss using specific heat of water and latent heat of vaporization
ΔQ = 20 g * 74 deg C * 1 cal / (g & deg C) + 20 g * 540 cal / g)
ΔQ = 12,300 cal
A particle is Projected with a velocity of 196m/s at an elevation of 30⁰ find?
The Velocity and Direction of motion at a height of 130m
According to the question the velocity and direction of motion of the particle at a height of 130m is 173.20 m/s, 30°.
What is velocity?Velocity is a vector physical quantity that measures the rate of change of an object's position. It is a combination of speed and direction and is measured in units such as meters per second (m/s). Velocity is the rate of change of an object’s position with respect to time. It is the amount of distance covered in a period of time. It is a vector quantity as it has both magnitude as well as direction. It can be calculated by dividing the distance covered by the time taken. Velocity is the rate at which an object is changing its position. It is a measure of how fast an object is traveling in a specific direction.
The velocity components of the particle at a height of 130m will be the same as it was at the time of projection since there is no acceleration, only gravity acting on it.
The velocity of the particle at a height of 130m will be:
Vx = 196 m/s * cos 30° = 173.20 m/s
Vy = 196 m/s * sin 30° = 98 m/s
The direction of motion of the particle at a height of 130m will be the same as the angle of projection i.e. 30°.
Therefore, the velocity and direction of motion of the particle at a height of 130m is 173.20 m/s, 30°.
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Suppose we wish to test whether or not the vectors a and b are perpendicular, where a = 3i+2j-k and b=i-2j-k Given the vectors: A = 3i + 2j - k and B = 5i +5j, find: a. The dot product A.B. b. The projection of A onto B. c. The angle between A and B. d. A vector of magnitude 2 in the XY plane perpendicular to B.
A ball punted vertically has a hang time of 3.8 seconds.
A. Construct position-time, velocity-time, and acceleration-time graphs and a motion map for this situation.
B. What was its initial velocity?
Answer:
A.
Position-time graph:
The position-time graph for the ball punted vertically will be a parabolic curve, with the vertex at the highest point of the ball's trajectory. Since the initial position is zero, the curve will go through the origin.
Velocity-time graph:
The velocity-time graph will be a straight line that starts at the initial velocity and decreases linearly until it reaches zero at the highest point of the ball's trajectory. After that, the velocity increases linearly in the negative direction until the ball hits the ground.
Acceleration-time graph:
The acceleration-time graph will be a constant negative value, representing the acceleration due to gravity.
Motion map:
A motion map is a diagram that shows the position of an object at several specific times during its motion. For the ball punted vertically, the motion map would look like this:
|O|------|-------|------|-------|------|H|
O represents the initial position, and H represents the highest point of the ball's trajectory. The "|" symbols represent the position of the ball at regular intervals of time.
B.
To find the initial velocity of the ball, we can use the hang time and the acceleration due to gravity.
Hang time = 3.8 seconds
Acceleration due to gravity = -9.8 m/s^2
At the highest point of the ball's trajectory, the velocity is zero. Therefore, we can use the following kinematic equation to find the initial velocity:
hang time = (final velocity - initial velocity) / acceleration
Solving for initial velocity:
initial velocity = final velocity - (hang time x acceleration)
final velocity = 0 m/s
hang time = 3.8 s
acceleration = -9.8 m/s^2
initial velocity = 0 - (3.8 x -9.8)
initial velocity = 37.64 m/s
Therefore, the initial velocity of the ball was 37.64 m/s.
