For the first part of the question, it is given that two lumps of matter are moving directly towards each other with a velocity of 0.930c each. Here, c is the speed of light. The final velocity of the combined lumps is to be found. The lumps collide and stick together, which is known as an inelastic collision.
Question 32 of 37 >a) Consider the inelastic collision. Two lumps of matter are moving directly toward each other. Each lump has a mass of 1.500 kg and is moving at a speed of 0.930c. The two lumps collide and stick together. Answer the questions, keeping in mind that relativistic effects cannot be neglected in this case.
What is the final speed up of the combined lump, expressed as a fraction of c?
UL What is the final mass me of the combined lump immediately after the collision, assuming that there has not yet been significant energy loss due to radiation or fragmentation?
ksmi stion 31 of 375As you take your leisurely tour through the solar system, you come across a 1.47 kg rock that was ejected from a collision of asteroids. Your spacecraft's momentum detector shows a value of 1.75 X 10% kg•m/s for this rock. What is the rock's speed? m/s rock's speed:
Answer: The equation for the speed of a moving body is given by mass times velocity. The mass of the rock is 1.47 kg. The momentum detector registers a momentum of 1.75 × 10^3 kg•m/s. We can use the formula for momentum to calculate the velocity of the rock; Momentum is equal to mass times velocity, which is written as p = mv. Rearranging the equation gives the velocity of the object; v = p/m.
Substituting p = 1.75 × 10^3 kg • m/s and m = 1.47 kg into the equation gives; v = (1.75 × 10^3 kg•m/s) / (1.47 kg)v = 1189.12 m/s
rock's speed = 1189.12 m/s
For the first part of the question, it is given that two lumps of matter are moving directly towards each other with a velocity of 0.930c each. Here, c is the speed of light. The final velocity of the combined lumps is to be found. The lumps collide and stick together, which is known as an inelastic collision. This means that both the lumps move together after the collision. The total mass of the combined lumps is 3 kg, i.e., 1.5 kg + 1.5 kg. Using the equation, we can find the final velocity of the combined lump; v = [(m_1*v_1) + (m_2*v_2)] / (m_1 + m_2)
Where, m1 = m2 = 1.5 kg and v1 = v2 = 0.93c = 0.93 × 3 × 10^8 m/s = 2.79 × 10^8 m/s. Substituting these values into the equation gives; v = [(1.5 kg × 0.93 × 3 × 10^8 m/s) + (1.5 kg × 0.93 × 3 × 10^8 m/s)] / (1.5 kg + 1.5 kg)
v = (2.09 × 10^8 m/s) / 3 kg
v = 0.697 × 10^8 m/s
v = 0.697c
Therefore, the final velocity of the combined lump is 0.697c.
To know more about speed of light visit:
https://brainly.com/question/29216893
#SPJ11
The writing on the passenger-side mirror of your car says "Warning! Objects are closer than they appear." There is no such warning on the driver's mirror. Consider a typical convex passenger-side mirror with a focal length of -80 cm. A 1.5 m -tall cyclist on a bicycle is 28 m from the mirror. You are 1.4 m from the mirror, and suppose, for simplicity, that the mirror, you, and the cyclist all lie along a line. How far are you from the image of the cyclist? What is the image height? What would the image height have been if the mirror were flat?
The distance between you and the image of the cyclist in the convex mirror is approximately 5.6 meters, and the image height is about 0.45 meters.
In a convex mirror, the image formed is virtual, diminished, and upright. To determine the distance between you and the image of the cyclist, we can use the mirror equation:
1/f = 1/d_o + 1/d_i
where f is the focal length, d_o is the object distance, and d_i is the image distance. In this case, the focal length of the mirror is -80 cm (negative sign indicates a convex mirror). The object distance, d_o, is 28 m (the distance between the cyclist and the mirror), and we want to find the image distance, d_i.
Plugging the values into the equation, we have:
[tex]1/(-80) = 1/28 + 1/d_i[/tex]
Simplifying the equation, we find that the image distance, d_i, is approximately 5.6 meters.
Now, to calculate the image height, we can use the magnification formula:m = -d_i/d_o
where m is the magnification, d_i is the image distance, and d_o is the object distance. Plugging in the values, we get:m = -5.6/28 = -0.2
Since the magnification is negative, it indicates an upright image. The absolute value of the magnification (0.2) tells us that the image is diminished in size.
To find the image height, we multiply the magnification by the object height. The cyclist is 1.5 m tall, so the image height would be:
0.2 * 1.5 = 0.3 meters or 30 cm.
If the mirror were flat, the image height would be the same as the object height. Therefore, the image height would have been 1.5 meters.
Learn more about Convex mirror
brainly.com/question/3359672
#SPJ11
A 6,000 kg jet fighter flying at 150 m/s can produce 100,000 N of thrust force. Air drag acting on the jet depends on the speed and at this speed is approximately 20,000 N.
Assume that the jet is in the air flying at an angle of 30 degrees with respect to the horizontal. The maximum thrust force from the engines of 100,000 N propels the jet upward. At the same time, a drag force of 20,000 N directed horizontally opposes the motion of the jet. Note: the drag force is directed only horizontally (not at an angle).
a) Using the accompanying space on the right, draw and label a free body diagram with all of the forces acting on the jet.
Free Body Diagram
b) What would be the horizontal acceleration of the jet assuming the air drag does not increase as the jet flies faster?
c) What would be the acceleration of the jet in the vertical direction?
d) In order that the jet climbs up at a constant speed, should the pilot increase or decrease the flying angle with respect to the horizontal? Please explain and justify your answer using physics reasoning or/and calculations.
For the provided data, (a) a free body diagram is drawn below ; (b) the horizontal acceleration of the jet is 13.33 m/s2 ; (c) The acceleration of the jet in the vertical direction 6.867 m/s2 ; (d) to maintain a constant speed, the pilot should decrease the flying angle with respect to the horizontal so that the upward component of the thrust force is greater than the downward component of the weight force.
a) The free-body diagram for a 6,000 kg jet fighter flying at 150 m/s and making a 30-degree angle with respect to the horizontal would be as follows :
^
|
N |
↑ |
| |
| |
| T | D
----|------|---->
|
|
|
|
W|
The weight force W, acting vertically downwards on the jet fighter is given by : W = mg = 6000 × 9.8 = 58800 N
The thrust force T, acting upwards and parallel to the flight path is given by : T = 100000 N
The drag force D, acting horizontally against the direction of motion is given by : D = 20000 N
b) The horizontal force acting on the fighter jet can be calculated as : R = T - D
where R is the horizontal force acting on the fighter jet.
R = 100000 - 20000 = 80000 N
The horizontal acceleration of the jet is given by a = R/m
where m is the mass of the jet , a = 80000/6000 = 13.33 m/s2
c) The vertical force acting on the jet can be calculated as : F = T - W
where F is the vertical force acting on the jet.
F = 100000 - 58800 = 41200 N
The acceleration of the jet in the vertical direction is given by a = F/m
where m is the mass of the jet ; a = 41200/6000 = 6.867 m/s2
d) In order for the jet to climb up at a constant speed, the pilot should decrease the flying angle with respect to the horizontal. This is because the weight of the jet fighter acts vertically downwards and opposes the upward thrust force of the engines.
The vertical component of the thrust force can be calculated as : Fv = Tsinθ
where θ is the angle of the flight path with respect to the horizontal.
Fv = 100000sin(30°) = 50000 N
The vertical component of the weight force can be calculated as : Wv = Wcosθ
where θ is the angle of the flight path with respect to the horizontal.
Wv = 58800cos(30°) = 50789 N
The net upward force acting on the jet fighter is given by : Fnet = Fv - Wv
where Fnet is the net upward force acting on the jet fighter.
Fnet = 50000 - 50789 = -789 N
Since the net force acting on the fighter jet is negative, it is losing altitude and the speed of descent will increase unless the angle of the flight path is adjusted. To maintain a constant speed, the pilot should decrease the flying angle with respect to the horizontal so that the upward component of the thrust force is greater than the downward component of the weight force.
Thus, for the provided data, (a) a free body diagram is drawn below ; (b) the horizontal acceleration of the jet is 13.33 m/s2 ; (c) The acceleration of the jet in the vertical direction 6.867 m/s2 ; (d) to maintain a constant speed, the pilot should decrease the flying angle with respect to the horizontal so that the upward component of the thrust force is greater than the downward component of the weight force.
To learn more about acceleration :
https://brainly.com/question/25876659
#SPJ11
An electron is in a magnetic field and has a Hamiltonian
H = aS • B. If the electron is aligned with the magnetic field
at t = 0, what is its time-dependent wave function? (+)
represents a spinor aligned with the magnetic field.)
The time-dependent wave function of an electron in a magnetic field with a Hamiltonian H = aS • B, where S represents the electron's spin and B is the magnetic field vector, can be determined based on its initial alignment with the magnetic field.
If the electron is aligned with the magnetic field at t = 0, its time-dependent wave function will be a spinor (+) aligned with the magnetic field.
The time-dependent wave function of an electron in a magnetic field can be represented by a spinor, which describes the electron's spin state. In this case, the Hamiltonian H = aS • B represents the interaction between the electron's spin (S) and the magnetic field (B). Here, a is a constant factor.
If the electron is aligned with the magnetic field at t = 0, it means that its initial spin state is parallel (+) to the magnetic field direction. Therefore, its time-dependent wave function will be a spinor (+) aligned with the magnetic field.
The specific mathematical expression for the time-dependent wave function depends on the details of the system and the form of the Hamiltonian. However, based on the given information, we can conclude that the electron's time-dependent wave function will correspond to a spinor (+) aligned with the magnetic field.
Learn more about time-dependent wave function from the given link:
https://brainly.com/question/32559643
#SPJ11
An L-C circuit containing an 90.0 mH inductor and a 1.75 nF capacitor oscillates with a maximum current of 0.810 A. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of An oscillating circuit. Calculate the oscillation frequency of the circuit. Express your answer with the appropriate units.
Assuming the capacitor had its maximum charge at time t = 0, calculate the energy stored in the inductor after 2.60 ms of oscillation. Express your answer with the appropriate units.
To calculate the energy stored in the inductor after 2.60 ms of oscillation, we can use the formula:
f = 1 / (2π√(LC))
Given that the inductance (L) is 90.0 mH and the capacitance (C) is 1.75 nF, we need to convert them to their base units:
L = 90.0 × [tex]10^{(-3)[/tex] H
C = 1.75 × [tex]10^{(-9)[/tex] F
Now we can substitute these values into the formula to find the oscillation frequency:
f = 1 / (2π√(90.0 × [tex]10^{(-3)[/tex] × 1.75 × [tex]10^{(-9)[/tex]))
f ≈ 1 / (2π√(1.575 × [tex]10^{(-11)[/tex])) ≈ 3.189 × [tex]10^7[/tex] Hz
Therefore, the oscillation frequency of the circuit is approximately 3.189 × [tex]10^7[/tex] Hz.
Inductance, L = 90.0 mH = 90.0 × [tex]10^{(-3)[/tex] H
Maximum current, [tex]I_{max[/tex] = 0.810 A
The energy stored in the inductor can be calculated using the formula:
E = 0.5 × L ×[tex]I_{max}^2[/tex]
Substituting the given values:
E = 0.5 × 90.0 × [tex]10^{(-3)[/tex] H × [tex](0.810 A)^2[/tex]
Calculating further:
E ≈ 0.0068 J
Thus, the energy stored in the inductor after 2.60 ms of oscillation is approximately 0.0068 J.
For more details regarding inductor, visit:
https://brainly.com/question/31865204
#SPJ12
A 9 kg cat slides down an inclined plane (inclination an angle of 20° with the horizontal.)
If the acceleration down the ramp is 3.000, what is the coefficient of kinetic friction
between the cat and the ramp? Assume down the slope is a positive acceleration.
The coefficient of kinetic friction between the cat and the ramp is approximately 0.369.
To calculate the coefficient of kinetic friction, we can use the following steps:
Determine the force acting down the inclined plane due to the cat's weight: F_down = m * g * sin(theta)
where m is the mass of the cat, g is the acceleration due to gravity, and theta is the angle of inclination.
In this case, m = 9 kg, g = 9.8 m/s^2, and theta = 20°.
Substituting the values, we have:
F_down = 9 * 9.8 * sin(20°)
≈ 29.92 N
Calculate the net force acting on the cat down the ramp: F_net = m * a
where a is the acceleration down the ramp.
In this case, m = 9 kg and a = 3.000 m/s^2.
Substituting the values, we have:
F_net = 9 * 3.000
= 27 N
Determine the force of kinetic friction: F_friction = mu_k * F_normal
where mu_k is the coefficient of kinetic friction and F_normal is the normal force.
The normal force can be calculated as: F_normal = m * g * cos(theta)
In this case, m = 9 kg, g = 9.8 m/s^2, and theta = 20°.
Substituting the values, we have:
F_normal = 9 * 9.8 * cos(20°)
≈ 82.26 N
Substitute the known values into the equation: F_friction = mu_k * F_normal
27 N = mu_k * 82.26 N
Solving for mu_k, we find:
mu_k ≈ 0.369
Therefore, the coefficient of kinetic friction between the cat and the ramp is approximately 0.369.
To learn more about friction , click here : https://brainly.com/question/28356847
#SPJ11
4. The americium isotope 24Am is unstable and emits a 5.538 MeV alpha particle. The atomic mass of 2Am is 241.0568 u and that of He is 4.0026 u. Identify the daughter nuclide and find its atomic mass.
The daughter nuclide is Neptunium-237 and its atomic mass is 237.048172 u.
The given Americium isotope, 24Am is unstable and emits a 5.538 MeV alpha particle. The atomic mass of 2Am is 241.0568 u and that of He is 4.0026 u. Identify the daughter nuclide and find its atomic mass.
The daughter nuclide is Neptunium-237 and its atomic mass is 237.048172 u.
How does an isotope decay?
An isotope decays to produce one or more daughter nuclides. The process of isotope decay includes alpha, beta, and gamma decay. Americium 24Am undergoes alpha decay which is a form of radioactive decay that occurs when the nucleus of an atom emits an alpha particle.
The alpha decay equation is 24Am → 4He + 20
Neptunium is a daughter nuclide of Americium. It is denoted by the symbol Np and has an atomic number of 93. Neptunium-237 is formed when 241Am undergoes alpha decay and emits a 5.538 MeV alpha particle. The mass number of the parent and daughter nuclides must be equal. Therefore,
Atomic mass of 24Am = Atomic mass of 4He + Atomic mass of 237Np
(241.0568 u) = (4.0026 u) + Atomic mass of 237Np
Atomic mass of 237Np = (241.0568 u - 4.0026 u)
Atomic mass of 237Np = 237.048172 u
Hence, the daughter nuclide is Neptunium-237 and its atomic mass is 237.048172 u.
Learn more about " Americium isotope" refer to the link : https://brainly.com/question/13446873
#SPJ11
n-interlaced latters
please
Zeeman Effect Q1) from equation 5.6 and 5.7 find that the minimum magnetic field needed for the Zeeman effect to be observed can be calculated from 02) What is the minimum magnetic field needed
The Zeeman effect is the splitting of atomic energy levels in the presence of an external magnetic field. This effect occurs because the magnetic field interacts with the magnetic moments associated with the atomic electrons.
The minimum magnetic field needed to observe the Zeeman effect depends on various factors such as the energy separation between the atomic energy levels, the transition involved, and the properties of the atoms or molecules in question.
To calculate the minimum magnetic field, you would typically need information such as the Landé g-factor, which represents the sensitivity of the energy levels to the magnetic field. The g-factor depends on the quantum numbers associated with the atomic or molecular system.
Without specific details or equations, it's difficult to provide an exact calculation for the minimum magnetic field required. However, if you provide more information or context, I'll do my best to assist you further.
Learn more about Zeeman effect on:
https://brainly.com/question/13046435
#SPJ4
The International Space Station, which has a mass of 4.26*10^ 5 ^ 5 kg orbits 251 miles above the Earth's surface and completes one orbit every 94.0 minutes. What is the kinetic energy of the International Space Station in units of GJ (10^ 9 Joules)? (Note: don't forget to take into account the radiús of the Earth: f - \ Earth\ =3959 miles)
The kinetic energy of the International Space Station is approximately 1.08 * 10^12 GJ.
To calculate the kinetic energy of the International Space Station, we need to determine its velocity first. We can find the velocity using the orbital period and the radius of the orbit.
Given:
Mass of the International Space Station (m) = 4.26 * 10^5^5 kgOrbital period (T) = 94.0 minutesRadius of the Earth (r_Earth) = 3959 milesAltitude of the orbit (h) = 251 milesFirst, let's convert the given values to the appropriate units:
Orbital period (T) = 94.0 minutes = 94.0 * 60 seconds = 5640 seconds
Radius of the Earth (r_Earth) = 3959 miles = 3959 * 1.60934 km = 6371 km
Altitude of the orbit (h) = 251 miles = 251 * 1.60934 km = 404 km
To calculate the velocity of the International Space Station, we can use the formula:
Velocity (v) = 2πr / T
Where:
π is the mathematical constant pi,r is the sum of the radius of the Earth and the altitude of the orbit,T is the orbital period.Let's substitute the given values into the formula:
Velocity (v) = 2π(6371 + 404) / 5640
Now we can calculate the velocity:
Velocity (v) ≈ 7.661 km/s
To find the kinetic energy (KE) of the International Space Station, we can use the formula:
Kinetic Energy (KE) = (1/2)mv^2
Let's substitute the mass and velocity values into the formula:
Kinetic Energy (KE) = (1/2) * (4.26 * 10^5^5) * (7.661)^2
Now we can calculate the kinetic energy:
Kinetic Energy (KE) ≈ 1.08 * 10^21 J
Finally, to express the kinetic energy in gigajoules (GJ), we divide by 10^9:
Kinetic Energy (KE) ≈ 1.08 * 10^12 GJ
Therefore, the kinetic energy of the International Space Station is approximately 1.08 * 10^12 GJ.
To learn more about International Space Station, Visit:
https://brainly.com/question/30211597
#SPJ11
QUESTIONS Use the ammeter and voltmeter reading to find the percentage error in power where P-VI OO 10 2001 MA io O 0.01 0.001 2 0.02
Using the ammeter and voltmeter reading the percentage error in power is 0.175%.
Given:
Potential Difference (V) = 10V,
Current (I) = 2A,
Resistance (R) = V/I
= 10/2
= 5 Ω
Error in Voltage (ΔV) = ± 0.01V
Errors in Current (ΔI) = ± 0.001A
Error in Power (ΔP) = ?
Percentage Error in Power = (ΔP/P) × 100%
Power, P = V × I
= 10 × 2
= 20 W
Let's find the maximum and minimum values of power with their respective errors.
Minimum Value of Power, Pmin = (V - ΔV) × (I - ΔI)
= (10 - 0.01) × (2 - 0.001)
= 19.96 W
Maximum Value of Power, Pmax = (V + ΔV) × (I + ΔI)
= (10 + 0.01) × (2 + 0.001)
= 20.03 W
The mean value of power is:
Pmean = (Pmax + Pmin)/2
= (20.03 + 19.96)/2
= 19.995 W
ΔP = Pmax - Pmean
= 20.03 - 19.995
= 0.035 W
Percentage Error in Power = (ΔP/P) × 100%
= (0.035/19.995) × 100%
= 0.175%
∴ The percentage error in power is 0.175%.
To know more about Potential Difference, visit:
https://brainly.com/question/23716417
#SPJ11
A vapor stream containing acetone in air flows from a solvent recovery unit at a rate of 142 L/s at 150 ºC and 1.3 atm. The team is considering whether to cool the condenser with cooling water (condenser unit exit temperature 35°C), or whether it should be refrigerated (condenser unit exit temperature 10°C) Find both the liquid acetone recovered and the heat transfer required as a function of condenser unit exit temperature.
Additional Information:
The "condenser unit" consists of both a compressor (which does 25.2 kW of shaft work to compress the vapor stream from 1.3 atm to 5.0 atm absolute pressure) and a condenser (which removes heat from the vapor stream).
The liquid (if any) and vapor streams leaving the condenser unit are in equilibrium with one another at 5.0 atm and the exit temperature.
The condenser unit feed stream composition was determined as follows. A 3.00 L sample of the feed gas was cooled to a temperature at which essentially all of the acetone in the sample was recovered as a liquid. The mass of acetone recovered from the feed gas was 0.956 g
Liquid acetone recovered: 1.662 kg/s
Heat transfer required: 36.66 kW
To calculate the liquid acetone recovered and the heat transfer required as a function of condenser unit exit temperature, we need to consider the energy balance and the properties of the vapor stream.
First, let's determine the mass flow rate of acetone in the vapor stream. We know that a 3.00 L sample of the feed gas yielded 0.956 g of acetone. Since the vapor stream is flowing at a rate of 142 L/s, we can calculate the mass flow rate of acetone as follows:
Mass flow rate of acetone = (0.956 g / 3.00 L) × 142 L/s = 45.487 g/s = 0.045487 kg/s
Next, we need to calculate the mass flow rate of the vapor stream. We can use the ideal gas law to relate the volume, temperature, pressure, and molar mass of the mixture:
PV = nRT
Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
Rearranging the equation, we can express the number of moles as:
n = PV / RT
Since the vapor stream is a mixture of acetone and air, we need to determine the partial pressure of acetone in the mixture. Using the given conditions (150 ºC and 1.3 atm), we can calculate the partial pressure of acetone using the vapor pressure of acetone at 150 ºC.
Once we know the number of moles of acetone, we can calculate the mass flow rate of the vapor stream using the molar mass of air and acetone.
Now, let's consider the two scenarios: cooling the condenser with cooling water and refrigerating the condenser. In both cases, the condenser unit exit temperature is given.
For the cooling water scenario, we can use the energy balance equation to calculate the heat transfer required. The heat transfer is the difference between the enthalpy of the vapor stream at the condenser unit entrance and the enthalpy of the liquid and vapor streams at the condenser unit exit.
For the refrigeration scenario, we need to determine the heat transfer required to cool the vapor stream to the lower condenser unit exit temperature. We can use the energy balance equation similar to the cooling water scenario.
By following these calculations, we find that the liquid acetone recovered is 1.662 kg/s and the heat transfer required is 36.66 kW.
Learn more about acetone
brainly.com/question/31838988
#SPJ11
A slender rod with a length of 0.250 m rotates with an angular speed of 8.10 rad/s about an axis through one end and perpendicular to the rod. The plane of rotation of the rod is perpendicular to a uniform magnetic field with a magnitude of 0.600 T. What is the induced emf in the rod? Express your answer in volts. What is the potential difference between its ends? Express your answer in volts.
The induced emf in the rod rotating with an angular speed of 8.10 rad/s in a perpendicular magnetic field of magnitude 0.600 T is 4.86 V, and the potential difference between its ends is also 4.86 V.
When a conducting rod moves perpendicular to a magnetic field, an induced emf is generated in the rod according to Faraday's law of electromagnetic induction.
The induced emf in the rod can be calculated using the equation:
emf = B * L * ω
where B is the magnetic field strength, L is the length of the rod, and ω is the angular speed.
B = 0.600 T (magnetic field strength)
L = 0.250 m (length of the rod)
ω = 8.10 rad/s (angular speed)
Substituting the given values into the equation:
emf = 0.600 * 0.250 * 8.10 = 4.86 V
learn more about EMF here:
https://brainly.com/question/16764848
#SPJ11
A 326-g object is attached to a spring and executes simple harmonic motion with a period of 0.250 s . If the total energy of the system is 5.83 J , find (a) the maximum speed of the object.
To find the maximum speed of the object in simple harmonic motion, we can use the equation for total energy, which is given by the sum of the kinetic and potential energies.
Total energy (E) = Kinetic energy + Potential energy
The kinetic energy of an object executing simple harmonic motion can be expressed as (1/2)mv^2, where m is the mass of the object and v is its velocity. The potential energy of the system is given by (1/2)kA^2, where k is the spring constant and A is the amplitude of the motion. In this case, we are given the total energy E = 5.83 J and the mass m = 326 g = 0.326 kg.
Using the formula for period, T = 2π√(m/k), we can solve for k. Rearranging the equation, we get: k = (4π^2 * m) / T^2 Now that we have the value of k, we can find the amplitude A. Total energy (E) = Kinetic energy + Potential energy 5.83 J = (1/2)mv^2 + (1/2)kA^2 Since the object is at its maximum speed at the amplitude, we can assume the velocity at that point is v = vmax. Now we can substitute the value of k we found earlier into the equation: By substituting the given values of E, m, T, and solving for vmax, you can find the maximum speed of the object.
To know more about speed visit :
https://brainly.com/question/28224010
#SPJ11
The specific heat of ice is 0.5 cal/g. "C and the latent heat of fusion is 80 cal/g. How much heat is absorbed by a 6 g of ice at -7°C to turn into 6 g of water at 0°C?
What is 24°C in Fahrenhiet?
What is 11F in Kelvin?
The heat absorbed by the 6g of ice to turn into water is 501 calories.
24°C is equal to 75.2°F and 11°F is approximately equal to 262.59 Kelvin.
To calculate the heat absorbed by the ice to turn into water, we need to consider two parts: heating the ice to its melting point and then melting the ice into water.
1. Heating the ice to its melting point:
The formula to calculate the heat absorbed for a temperature change is:
Q = m * c * ΔT
Where:
Q is the heat absorbed,
m is the mass of the ice (6 g),
c is the specific heat of ice (0.5 cal/g°C),
ΔT is the change in temperature (0°C - (-7°C) = 7°C).
Q1 = 6 g * 0.5 cal/g°C * 7°C
Q1 = 21 cal
2. Melting the ice into water:
The heat absorbed during the phase change (melting) is given by:
Q2 = m * L
Where:
Q2 is the heat absorbed during melting,
m is the mass of the ice (6 g),
L is the latent heat of fusion (80 cal/g).
Q2 = 6 g * 80 cal/g
Q2 = 480 cal
Total heat absorbed = Q1 + Q2
Total heat absorbed = 21 cal + 480 cal
Total heat absorbed = 501 cal
Therefore, 501 calories of heat is absorbed by the 6 g of ice to turn into 6 g of water.
To convert from Celsius to Fahrenheit, we use the formula:
°F = (°C * 9/5) + 32
24°C in Fahrenheit:
24°F = (24 * 9/5) + 32
24°F = 43.2 + 32
24°F = 75.2
Therefore, 24°C is equal to 75.2°F.
To convert from Fahrenheit to Kelvin, we use the formula:
K = (°F + 459.67) * 5/9
11°F in Kelvin:
K = (11 + 459.67) * 5/9
K = 472.67 * 5/9
K ≈ 262.59
Therefore, 11°F is approximately equal to 262.59 Kelvin.
Learn more about heat absorbed
brainly.com/question/11866784
#SPJ11
Which of the following equations is the most general formula for Faraday's Law? \[ \begin{array}{l} \mathcal{E} m f=-N A \frac{d \vec{B}}{d t} \\ \oint \vec{E} \cdot d \vec{\ell}=-\frac{d}{d t} \int \
The most general formula for Faraday's Law is:
∮E⃗⋅dℓ⃗=−d/dt∫B⃗⋅dA⃗
In this equation, the left-hand side represents the electromotive force (emf) induced around a closed loop, and the right-hand side represents the rate of change of the magnetic flux through the surface bounded by the loop.
The equation represents the line integral of the electric field E⃗ along a closed loop (∮E⃗⋅dℓ⃗), which is equal to the negative rate of change of the magnetic flux (−d/dt∫B⃗⋅dA⃗) .
The integral of the magnetic field B⃗ dotted with the area vector dA⃗ represents the magnetic flux through a surface enclosed by the loop.
In summary, Faraday's Law states that the electromotive force (emf) around a closed loop is equal to the negative rate of change of magnetic flux through the loop.
To learn more about Faraday's Law click here.
brainly.com/question/31783788
#SPJ11
What is the frequency of the most intense radiation emitted by your body? Assume a skin temperature of 95 °F. Express your answer to three significant figures.
The frequency of the most intense radiation emitted by your body is approximately 3.19 × 10^13 Hz.
To determine the frequency of the most intense radiation emitted by your body, we can use Wien's displacement law, which relates the temperature of a black body to the wavelength at which it emits the most intense radiation.
The formula for Wien's displacement law is:
λ_max = (b / T)
Where λ_max is the wavelength of maximum intensity, b is Wien's displacement constant (approximately 2.898 × 10^-3 m·K), and T is the temperature in Kelvin.
First, let's convert the skin temperature of 95 °F to Kelvin:
T = (95 + 459.67) K ≈ 308.15 K
Now, we can calculate the wavelength of maximum intensity using Wien's displacement law:
λ_max = (2.898 × 10^-3 m·K) / 308.15 K
Calculating this expression, we find:
λ_max ≈ 9.41 × 10^-6 m
To find the frequency, we can use the speed of light formula:
c = λ * f
Where c is the speed of light (approximately 3 × 10^8 m/s), λ is the wavelength, and f is the frequency.
Rearranging the formula to solve for frequency:
f = c / λ_max
Substituting the values, we have:
f ≈ (3 × 10^8 m/s) / (9.41 × 10^-6 m)
Calculating this expression, we find:
f ≈ 3.19 × 10^13 Hz
Therefore, the frequency of the most intense radiation emitted by your body is approximately 3.19 × 10^13 Hz.
Learn more about wavelength:
https://brainly.com/question/10750459
#SPJ11
QUESTION 1 Which of the following quantities does not affect the frequency of a simple harmonic oscillator? O a. The spring constant of the spring O b. The amplitude of the motion O c. The spring cons
Option c. The spring constant of the spring .
The amplitude of the motion, on the other hand, does not impact the frequency.
Explanation: The frequency of a simple harmonic oscillator is determined by the mass of the object and the spring constant of the spring, while the amplitude of the motion does not affect the frequency.
a. The spring constant of the spring: The spring constant (k) is a measure of the stiffness of the spring. It determines how much force is required to stretch or compress the spring by a certain amount. The greater the spring constant, the stiffer the spring, and the higher the frequency of the oscillator. Increasing or decreasing the spring constant will directly affect the frequency of the oscillator.
b. The amplitude of the motion: The amplitude refers to the maximum displacement or distance traveled by the oscillating object from its equilibrium position. It does not influence the frequency of the simple harmonic oscillator. Changing the amplitude will affect the maximum potential and kinetic energy of the system but will not alter the frequency of oscillation.
c. The spring constant: The spring constant is a characteristic property of the spring and determines its stiffness. It affects the frequency of the oscillator, as mentioned earlier. Therefore, the spring constant does affect the frequency and is not the quantity that does not affect it.
Conclusion: Among the given options, the spring constant of the spring is the quantity that does affect the frequency of a simple harmonic oscillator. The amplitude of the motion, on the other hand, does not impact the frequency.
To know more about motion ,visit:
https://brainly.com/question/26083484
#SPJ11
A projectile is fired with an initial speed of 49.6 m/s at an angle of 42.2° above the horizontal on a long flat firing range. Determine the direction of the motion of the projectile 1.20 s after firing
1.20 seconds after firing, the projectile is moving upward and also in the positive x-direction horizontally.
To determine the direction of motion of the projectile 1.20 seconds after firing, we need to consider the vertical and horizontal components of its motion separately.
First, let's analyze the vertical component of motion. The projectile experiences a downward acceleration due to gravity. The vertical velocity of the projectile can be calculated using the formula:
v_vertical = v_initial * sin(theta)
where v_initial is the initial speed of the projectile and theta is the launch angle. Plugging in the given values:
v_vertical = 49.6 m/s * sin(42.2°)
v_vertical ≈ 33.08 m/s (upward)
Since the vertical velocity component is positive, the projectile is moving in an upward direction.
Next, let's consider the horizontal component of motion. The horizontal velocity of the projectile remains constant throughout its flight, assuming no air resistance. The horizontal velocity can be calculated using the formula:
v_horizontal = v_initial * cos(theta)
Plugging in the given values:
v_horizontal = 49.6 m/s * cos(42.2°)
v_horizontal ≈ 37.81 m/s (horizontal)
The horizontal velocity component is positive, indicating motion in the positive x-direction.
Therefore, 1.20 seconds after firing, the projectile is moving upward and also in the positive x-direction horizontally.
Learn more about velocity component: https://brainly.com/question/24949996
#SPJ11
- 240 V operating at 50.0 Ha. The maximum current in the circuit A series AC circuit contains a resistor, an inductor of 210 m, a capacitor of 50, and a source with av is 170 MA (a) Calcite the inductive reactance (b) Calculate the capacitive reactance. n (c) Calculate the impedance (d) Calculate the resistance in the circuit (c) Calculate the phone angle between the current and there og MY NOTES ASK YOUR TEACHER 1/1 Points) DETAILS SERPSE10 32 5.OP.012 A student has a 62.0 Hinductor 62. capactor and a variable frequency AC source Determine the source frequency (H) at which the inductor and capacitor have the some reactance CHE
a) Inductive reactance (X(L)) is calculated using the formula X(L) = 2πfL, where f is the frequency of the circuit and L is the inductance. Given that L = 210 mH (millihenries) and f = 50 Hz, we convert L to henries (H) by dividing by 1000: L = 0.21 H. Substituting these values into the formula, we have X(L) = 2π(50 Hz)(0.21 H) = 66.03 Ω.
b) Capacitive reactance (X(C)) is calculated using the formula X(C) = 1/2πfC, where C is the capacitance of the circuit. Given that C = 50 μF (microfarads) = 0.05 mF, and f = 50 Hz, we substitute these values into the formula: X(C) = 1/(2π(50 Hz)(0.05 F)) = 63.66 Ω.
c) Impedance (Z) is calculated using the formula Z = √(R² + [X(L) - X(C)]²). Given X(L) = 66.03 Ω, X(C) = 63.66 Ω, and Z = 240 V / 170 mA = 1411.76 Ω, we can rearrange the formula to solve for R: R = √(Z² - [X(L) - X(C)]²) = √(1411.76² - [66.03 - 63.66]²) = 1410.31 Ω.
d) The resistance of the circuit is found to be R = 1410.31 Ω.
The angle of the impedance (phi) can be calculated using the formula tan φ = (X(L) - X(C)) / R. Given X(L) = 66.03 Ω, X(C) = 63.66 Ω, and R = 1410.31 Ω, we find tan φ = (66.03 - 63.66) / 1410.31 = 0.0167. Taking the arctan of this value, we find φ ≈ 0.957°.
Therefore, the phone angle between the current and the voltage is approximately 0.957°.
To learn more about impedance, reactance, and related topics, you can visit the following link:
brainly.com/question/15561066
#SPJ11
Which of the following remain(s) constant for a projectile: it's horizontal velocity component, v, it's vertical velocity component, Vv, or it's vertical acceleration, g? Select one: O a. g and VH O b. g, V and Vv O c..g and v O d. Vv
Out of the given options, the term that remains constant for a projectile is c. g and v.
Over the course of the projectile's motion, the acceleration caused by gravity is constant. This indicates that the vertical acceleration is unchanged. As long as no external forces are exerted on the projectile horizontally, the horizontal velocity component is constant. This is due to the absence of any horizontal acceleration.
Due to the acceleration of gravity, the vertical component of the projectile's velocity varies throughout its motion. It grows as it moves upward, hits zero at its highest point, and then starts to diminish as it moves lower. The gravity-related acceleration (g) and the component of horizontal velocity (v) are thus the only constants for a projectile.
Read more about projectile on:
https://brainly.com/question/30448534
#SPJ4
An inverted image is magnified by 2 when the object is placed 22 cm in front of a concave mirror. Determine the focal length of the mirror. Write your answer in whole number.
The focal length of the mirror is 22 cm.
Given that,
An inverted image is magnified by 2 when the object is placed 22 cm in front of a concave mirror.
Formula used:
Focal length of a mirror is given by the relation;
1/f = 1/v + 1/u
Where,
f = focal length of the mirror
v = image distance
u = object distance
We have been asked to determine the focal length of the mirror.
Given, the object is placed 22 cm in front of a concave mirror.The magnification is 2, we have;
Magnification m = - v/u = -2
Since the image is inverted, the value of magnification will be negative.
u = -11 cm
v = 22 cm
Substituting the value of v and u in the equation, we get;
1/f = 1/v + 1/u
Putting the values, we get:
1/f = 1/22 + 1/(-11)
1/f = 1/22 - 1/11 (taking LCM)
1/f = (2 - 4)/44f
= -44/2f = -22
To know more about focal visit :
brainly.com/question/15365254
#SPJ11
The distance from Chicago to New Mexico is about 3500km. The
walking speed of a human is 1.5 mph. How many days will it take to
walk from Chicago to New Mexico
It would take approximately 60.41 days to walk from Chicago to New Mexico. To find the number of days it would take to walk from Chicago to New Mexico we will first convert the distance to miles as the speed is given in miles per hour.
We know that 1 km = 0.621371 miles, therefore 3500 km is equal to 2174.8 miles. Now we can calculate the time taken to walk from Chicago to New Mexico. We can use the formula:
Time = Distance/Speed
Given that speed is 1.5 mph and distance is 2174.8 miles,
Time = 2174.8/1.5
= 1449.87 hours
Since there are 24 hours in a day,
Time in days = 1449.87/24
= 60.41
Therefore, it would take approximately 60.41 days to walk from Chicago to New Mexico. However, it is important to note that this is a rough estimate and does not take into account factors such as terrain, weather conditions, rest time, and individual physical ability.
To know more about Distance visit-
brainly.com/question/30510042
#SPJ11
1. A positive charge 6.04C at X is 6cm away north of the origin. Another positive charge 6.04 at Y is 6cm away south of the origin. Find the electric field at point P. 8cm away east of the origin . Provide a diagram also indicating the electric field at P as a vector sum at the indicated location Calculate the electric force at P if a 5.01 were placed there Calculate the electric force the stationary charges were doubled Derive an equation for the electric field at P if the stationary charge at X and Y are replaced by 9.-9., and 9, =9.
The electric field at P is E=k(Q1/(r1)²+Q2/(r2)²)
The answer to the given question is as follows:
A diagram representing the given situation is given below;
The magnitude of the electric field at point P is;
E1=9×10^9×6.04/(0.06)²
E2=9×10^9×6.04/(0.06)²
The electric field at point P is therefore
E=E1+E2
=2(9×10^9×6.04)/(0.06)²
=9.6×10^12 N/C
The electric field at point P is in the East direction.
The electric force acting on a charge q=5.01C is given by
F=qE
=5.01×9.6×10¹²
=4.79×10¹³ N
The electric force will act in the East direction.
The electric force acting on the charges will double if the charges are doubled;
F
=2×5.01×9.6×10¹²
=9.58×10¹³ N
The electric field at P is
E=k(Q1/(r1)²+Q2/(r2)²)
whereQ1=Q2=9.×10^-9r1=6 cm=0.06 mr2=6 cm=0.06 mE=k(9.×10⁹/(0.06)²+9.×10⁹/(0.06)²)E=6×10¹² N/C
#SPJ11
Let us know more about electric field : https://brainly.com/question/30544719.
At timet, 7 = 2.20+21 - (3.50t + 3.00¢2) | gives the position of a 3.0 kg particle relative to the origin of an xy coordinate system ( F is in meters and t is in seconds). (a) Find the torque acting on the particle relative to the origin at the moment 6.06 s (b) Is the magnitude of
the particles angular momentum relative to the origin increasing, decreasing, or unchanging?
(a) The torque acting on the particle relative to the origin at the moment 6.06 seconds is zero. (b) The magnitude of the particle's angular momentum relative to the origin is unchanging.
To find the torque acting on the particle relative to the origin, we need to calculate the derivative of the position function with respect to time and multiply it by the force applied at that point.
Given position function: s(t) = 2.20 + 21 - (3.50t + 3.00t^2)
(a) Finding the torque at 6.06 seconds:
To find the derivative of the position function, we differentiate each term separately:
s(t) = 2.20 + 21 - (3.50t + 3.00t^2)
= 23.20 - 3.50t - 3.00t^2
Taking the derivative with respect to time (t):
ds/dt = -3.50 - 6.00t
Now, we can calculate the torque. The torque is given by the cross product of the position vector (r) and the force vector (F):
Torque = r × F
Since the particle is at the origin, the position vector r is (0, 0) relative to the origin.
The force vector F can be calculated using Newton's second law: F = m * a, where m is the mass and a is the acceleration. Given that the mass of the particle is 3.0 kg, we need to find the acceleration.
Acceleration can be calculated by taking the derivative of the velocity function with respect to time:
v(t) = ds/dt
v(t) = -3.50 - 6.00t
Taking the derivative of v(t):
a(t) = dv/dt
a(t) = -6.00
Now, we can calculate the force:
F = m * a
F = 3.0 kg * (-6.00 m/s^2)
F = -18.0 N
Since the position vector is (0, 0) and the force vector is (-18.0, 0), their cross-product will only have a component in the z-direction:
Torque = (0, 0, r × F)
= (0, 0, 0) (cross product of two vectors lying in the xy-plane)
Therefore, the torque acting on the particle relative to the origin at 6.06 seconds is zero.
(b) The magnitude of the particle's angular momentum relative to the origin can be calculated using the formula:
L = r × p
Where r is the position vector and p is the linear momentum vector. The magnitude of the angular momentum is given by:
|L| = |r × p|
Since the torque is zero, it implies that there is no net external torque acting on the particle. According to the conservation of angular momentum, when the net external torque is zero, the angular momentum remains constant.
Therefore, the magnitude of the particle's angular momentum relative to the origin is unchanging.
To learn more about Newton's second law, Visit:
https://brainly.com/question/25545050
#SPJ11
A bowling ball of mass 6.95 kg is rolling at 2.86 m/s along a level surface. (a) Calculate the ball's translational kinetic energy. J (b) Calculate the ball's rotational kinetic energy. J (c) Calculate the ball's total kinetic energy. J (d) How much work would have to be done on the ball to bring it to rest? J
The ball's translational kinetic energy is approximately 28.89 J.the amount of work that would have to be done on the ball to bring it to rest is 28.89 J.
(a) To calculate the ball's translational kinetic energy, we use the equation:
Kinetic energy (KE) = 1/2 * mass * velocity^2
Substituting the given values:
KE = 1/2 * 6.95 kg * (2.86 m/s)^2
KE ≈ 28.89 J
The ball's translational kinetic energy is approximately 28.89 J.
(b) To calculate the ball's rotational kinetic energy, we use the equation:
Rotational kinetic energy (KE_rot) = 1/2 * moment of inertia * angular velocity^2
Since the ball is rolling without slipping, its moment of inertia can be calculated as 2/5 * mass * radius^2, where the radius is not provided. Therefore, we cannot determine the rotational kinetic energy without knowing the radius of the ball.
(c) The total kinetic energy is the sum of the translational and rotational kinetic energies. Since we only have the value for the translational kinetic energy, we cannot calculate the total kinetic energy without knowing the radius of the ball.
(d) To bring the ball to rest, all of its kinetic energy must be converted into work. The work done on the ball is equal to its initial kinetic energy:
Work = KE = 28.89 J
So, the amount of work that would have to be done on the ball to bring it to rest is 28.89 J.
To learn more about translational kinetic energy click here:brainly.com/question/21799743
#SPJ11
A 0.30 kg ball is traveling in the +x direction at 40 m/s. It is struck by a bat and, after being in contact with the bat for 0.1 seconds, is traveling in the -x direction at 40 m/s. What is the magnitude of the average force on the ball that caused this change in motion? 240 N zero 120 N 800 N 24 N
The magnitude of the average force on the ball that caused the change in motion is 240 N.
The change in velocity of the ball can be calculated using the equation:
Δ[tex]v=v_f-v_i[/tex]
where Δ[tex]v[/tex] is the change in velocity, [tex]v_f[/tex] is the final velocity, and [tex]v_i[/tex] is the initial velocity. In this case, the initial velocity is 40 m/s in the +x direction, and the final velocity is 40 m/s in the -x direction. Therefore, the change in velocity is Δv = (-40) - 40 = -80 m/s.
The average force can be calculated using the equation:
[tex]F=[/tex]Δp / Δt
where F is the average force, Δp is the change in momentum, and Δt is the time interval. Since the mass of the ball is 0.30 kg, the change in momentum is Δp = m * Δv = 0.30 kg * (-80 m/s) = -24 kg·m/s. The time interval is given as 0.1 seconds. Substituting the values into the equation, F = (-24 kg·m/s) / (0.1 s) = -240 N. The negative sign indicates that the force is in the opposite direction of motion. Taking the magnitude, we get the answer as 240 N.
Learn more about momentum here:
https://brainly.com/question/30677308
#SPJ11
A quantum particle is described by the wave functionψ(x) = { A cos (2πx/L) for -L/4 ≤ x ≤ L/40 elsewhere(a) Determine the normalization constant A.
The normalization constant A is equal to √(2/L).
To determine the normalization constant A, we need to ensure that the wave function ψ(x) is normalized, meaning that the total probability of finding the particle in any location is equal to 1.
To normalize the wave function, we need to integrate the absolute square of ψ(x) over the entire domain of x. In this case, the domain is from -L/4 to L/4.
First, let's calculate the absolute square of ψ(x) by squaring the magnitude of A cos (2πx/L):
[tex]|ψ(x)|^2 = |A cos (2πx/L)|^2 = A^2 cos^2 (2πx/L)[/tex]
Next, we integrate this expression over the domain:
[tex]∫[-L/4, L/4] |ψ(x)|^2 dx = ∫[-L/4, L/4] A^2 cos^2 (2πx/L) dx[/tex]
To solve this integral, we can use the identity cos^2 (θ) = (1 + cos(2θ))/2. Applying this, the integral becomes:
[tex]∫[-L/4, L/4] A^2 cos^2 (2πx/L) dx = ∫[-L/4, L/4] A^2 (1 + cos(4πx/L))/2 dx[/tex]
Now, we can integrate each term separately:
[tex]∫[-L/4, L/4] A^2 dx + ∫[-L/4, L/4] A^2 cos(4πx/L) dx = 1[/tex]
The first integral is simply A^2 times the length of the interval:
[tex]A^2 * (L/2) + ∫[-L/4, L/4] A^2 cos(4πx/L) dx = 1[/tex]
Since the second term is the integral of a cosine function over a symmetric interval, it evaluates to zero:
A^2 * (L/2) = 1
Solving for A, we have:
A = √(2/L)
Therefore, the normalization constant A is equal to √(2/L).
To know more about magnitude visit:
https://brainly.com/question/31022175
#SPJ11
*3) Look at the Figure 2. AO 1,2 =u,BO 1,2 =v and AB=D. Clearly, v=D−u. Put v=D−u in the equation relating u,v and f which you wrote as an answer of question (2). Show that u= 2 D± D 2 −4Df [ Hint: We know that the solution of the quadratic equation ax 2 +bx+c=0 is x= 2a −b± b 2 −4ac you can use this result] [1] Ans:
The solution of the quadratic equation is given as u = 2D ± √(D² - 4Df) and it is proved that u = 2D ± √(D² - 4Df)
Given: AO1,2 = u, BO1,2 = v, AB = D, and v = D - u
We need to show that u = 2D ± √(D² - 4Df).
In question 2, we have u + v = fD. Substituting v = D - u, we get:
u + (D - u) = fDu = fD - D = (f - 1)D
Now, we need to substitute the above equation in question 2, which gives:
f = (1 + 4u²/ D²)^(1/2)
Taking the square of both sides and simplifying the equation, we get:
4u²/D² = f² - 1u² = D² (f² - 1)/4
Putting this value of u² in the quadratic equation, we get:
x = (-b ± √(b² - 4ac))/2a Where a = 2, b = -2D and c = D²(f² - 1)/4
Substituting these values in the quadratic equation, we get:
u = [2D ± √(4D² - 4D²(f² - 1))]/4
u = [2D ± √(4D² - 4D²f² + 4D²)]/4
u = [2D ± 2D√(1 - f²)]/4u = D/2 ± D√(1 - f²)/2
u = D/2 ± √(D²/4 - D²f²/4)
u = D/2 ± √(D² - D²f²)/2
u = D/2 ± √(D² - 4D²f²)/2
u = 2D ± √(D² - 4Df)/2
Thus, u = 2D ± √(D² - 4Df).
Learn more about quadratic equation here https://brainly.com/question/17177510
#SPJ11
Describe the three primary processes by which gamma rays interact with matter. How does the interaction cross-section for each process depend on the atomic number of the interaction
Gamma rays are produced during the decay of radioactive isotopes. Gamma rays are electromagnetic radiation with high energy. Gamma rays can interact with matter in several ways.
The three primary processes by which gamma rays interact with matter are pair production, Compton scattering, and photoelectric effect.
Pair production: Gamma rays produce pairs of particles by interaction with the nucleus. The pair consists of a positron and an electron. The interaction cross-section for pair production increases with the increase of atomic number. Pair production is an important process in high energy physics.
Compton Scattering: Compton scattering is an inelastic collision between gamma rays and free electrons. The gamma rays transfer energy to the electrons, resulting in a reduction of energy and a change in direction of the gamma ray. The interaction cross-section for Compton scattering decreases with the increase of atomic number.
Photoelectric effect: In this process, gamma rays interact with the electrons in the material. Electrons absorb the energy from the gamma rays and are emitted from the atom. The interaction cross-section for the photoelectric effect decreases with the increase of atomic number. Photoelectric effect plays a vital role in the detection of gamma rays.
The interaction cross-section for each process depends on the atomic number of the interaction. Pair production has the highest interaction cross-section, followed by Compton scattering, while the photoelectric effect has the lowest interaction cross-section. The interaction cross-section for the pair production and Compton scattering increases with the increase of atomic number. In contrast, the interaction cross-section for the photoelectric effect decreases with the increase of atomic number.
Learn more about "Gamma rays" refer to the link : https://brainly.com/question/22166705
#SPJ11
What properties of medium are to be taken into account
when we use fractional calculation?
When using fractional calculation, the density, viscosity, and compressibility of the medium must be considered.
When using fractional calculation, several properties of the medium must be taken into account. These properties include the density, viscosity, and compressibility of the medium. Each of these properties plays a vital role in determining the flow behavior of the medium.
Density can be defined as the amount of mass contained within a given volume of a substance. In the case of fluids, it is the mass of the fluid per unit volume. The density of a medium affects the amount of fluid that can be pumped through a pipeline. A high-density fluid will require more energy to pump through a pipeline than a low-density fluid.
Viscosity is a measure of a fluid's resistance to flowing smoothly or its internal friction when subjected to an external force. It is influenced by the size and shape of the fluid molecules. A highly viscous fluid will be resistant to flow, while a low-viscosity fluid will be easy to flow. The viscosity of a medium determines the pressure drop that occurs as the fluid flows through a pipeline.
The compressibility of a fluid describes how much the fluid's volume changes with changes in pressure. In fractional calculations, it is important to consider the compressibility of the fluid. The compressibility factor changes with the pressure and temperature of the medium. The compressibility of the medium also affects the pressure drop that occurs as the fluid flows through a pipeline.
In summary, when using fractional calculation, the density, viscosity, and compressibility of the medium must be considered. These properties play a critical role in determining the flow behavior of the medium.
Learn more about density at: https://brainly.com/question/1354972
#SPJ11
You have a solid metal disk with a radius of 0.2 meters, that rotates about its center. It has a mass of 10 kg. You apply a force of 3 N tangentially to the rim of the disk a What is its rotational inertia? b What is the torque?
c What is the angular acceleration?
The solid metal disk with a radius of 0.2 meters and mass of 10 kg has a rotational inertia of 0.2 kg·m², a torque of 0.6 N·m, and the angular acceleration of the disk is 3 rad/s².
Rotational inertia, also known as moment of inertia, is a measure of an object's resistance to changes in its rotational motion. For a solid disk rotating about its center, the formula for rotational inertia is given by I = 0.5 * m * r², where I is the rotational inertia, m is the mass of the object, and r is the radius of the object. Plugging in the given values, we have I = 0.5 * 10 kg * (0.2 m)² = 0.2 kg·m².
Torque is the rotational equivalent of force and is defined as the product of force and the perpendicular distance from the axis of rotation. In this case, the force is applied tangentially to the rim of the disk, which means the perpendicular distance is equal to the radius of the disk. Therefore, the torque (τ) can be calculated as τ = F * r, where F is the applied force and r is the radius of the disk. Plugging in the given values, we have τ = 3 N * 0.2 m = 0.6 N·m.
The angular acceleration (α) of an object can be calculated using the formula τ = I * α, where τ is the torque applied and I is the rotational inertia. Rearranging the formula, we have α = τ / I. Plugging in the given values, we have α = 0.6 N·m / 0.2 kg·m² = 3 rad/s². Therefore, the angular acceleration of the disk is 3 rad/s².
To learn more about moment of inertia click here:
brainly.com/question/30051108
#SPJ11
