The property of water is that It exists in all three states on Earth.
The major residences to be able to be mentioned in this text are its appeal to polar molecules, its high specific warmth, the excessive warmness of vaporization, the decrease density of ice, and its high polarity.
The primary homes of water are its polarity, concord, adhesion, floor anxiety, excessive unique warmth, and evaporative cooling. A water molecule is barely charged on each ends. this is because oxygen is more electronegative than hydrogen.
Water is good sized functionality to dissolve a ramification of molecules has earned it the designation of “standard solvent,” and it's far this capacity that makes water such an invaluable life-sustaining pressure. On a biological level, water's role as a solvent facilitates cells transport and use substances like oxygen or vitamins.
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What if there was an inverse relationship between the temperature and the volume? How do you think the world might be different? How would this change our day-to-day lives?
If there was an inverse relationship between the temperature and the volume, our daily lives change because in high temperature things will contract.
What if there was an inverse relationship between the temperature and the volume?If there was an inverse relationship between the temperature and the volume then with increasing temperature decrease occur in the volume of a substance. If this type of relationship is present in the world, the objects will contract when the temperature is high and expand when the temperature is low which make the solid materials expand at winter and contract at summer season.
So we can conclude that if there was an inverse relationship between the temperature and the volume, our daily lives change because in high temperature things will contract.
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A syringe containing 2.56 mL of He gas at 75.2 degrees Celsius is cooled to 18.2 degrees Celsius. What is the final volume of the gas?
Answer:
v = 2.141 ml
Explanation:
we can use the "ideal gas law" :-
PV=nRTp :- pressure ( pa )
V :- Volume ( m³ )
n :- amount of substance ( mol )
R :- Ideal gas constant ( 8.314 Jmol-¹ K-¹ )
T :- Temperature ( K)
What is the equilibrium constant for the reaction
Answer:
B.) [tex]K_{eq} = \frac{[SO_3][NO]}{[SO_2][NO_2]}[/tex]
Explanation:
The general equilibrium expression looks like this:
[tex]K_{eq} = \frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]
In this expression,
-----> K = equilibrium constant
-----> uppercase letters = formulas
-----> lowercase letters = balanced equation coefficients
The products are in the numerator and the reactants are in the denominator. Since all of the molecules are gases, they should all be included in the expression. Since the coefficients in the balanced equation are all 1, they do not need to be represented in the expression.
The equilibrium constant expression is:
[tex]K_{eq} = \frac{[SO_3][NO]}{[SO_2][NO_2]}[/tex]
How many moles of Hydrogen gas will be produced if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid given the following balanced chemical reaction:
Mg + 2HCl → MgCl2 + H2
Group of answer choices
A. 1.25 moles
B. 5.0 Moles
C. 7.5 moles
D. 2.5 moles
Taking into account the reaction stoichiometry, 1.25 grams of H₂ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.
Reaction stoichiometryIn first place, the balanced reaction is:
Mg + 2 HCl → MgCl₂ + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Mg: 1 mole HCl: 2 molesMgCl₂: 1 moleH₂: 1 moleMass of hydrogen formedThe following rule of three can be applied: if by reaction stoichiometry 2 moles of Mg form 1 mole of H₂, 2.5 moles of Mg form how many moles of H₂?
[tex]moles of H_{2} =\frac{2.5 moles of Mgx1 mole of H_{2} }{2 moles of Mg}[/tex]
moles of H₂= 1.25 moles
Finally, 1.25 grams of H₂ (option A) are formed if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid.
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The following techniques are used to separate mixtures. A simple distillation B fractional distillation D chromatography E filtration From this list, choose the most suitable technique to separate the following. (a) methane from a mixture of the gases, methane and ethane.
Answer: The answer is B fractional distillation.
Explanation:
Individual components of a mixture can be separated out by a number of methods. These are:
gravity separation: If the various components of the mixture have different gravity, they will form different layers (when shaken and allowed to settle). This way they can be separated out.
Filtration: Particles of different
can you help with this please?
Answer:
A.) 2,4,5-trimethylhexan-2-ol
B.) 6-bromo-3-ethylhexan-2-one
C.) 3-isoproyl-4-propyloctan-1-al
Explanation:
A.) Since there is an alcohol (-OH) group in the molecule, the name should have the ending -ol. Since the alcohol is on the 2nd carbon, there should be a 2 in front of the -ol. The longest carbon chain contains 6 single-bonded carbons, making this a hexane. There are 3 methyl (-CH₃) groups on the 2nd, 4th, and 5th carbons.
Therefore, the IUPAC name is: 2,4,5-trimethylhexan-2-ol
B.) Since there is a ketone (C=O) group in the molecule, the name should have the ending -one. Since the ketone takes priority, it is on the 2nd carbon. As such, there should be a 2 in front of the -one. The longest carbon chain contains 6 single-bonded carbons, making this a hexane. There is an ethyl (-CH₂CH₃) group on the 3rd carbon and a bromo (-Br) group on the 6th carbon.
Therefore, the IUPAC name is: 6-bromo-3-ethylhexan-2-one
C.) Since there is an aldehyde (HC=O) group in the molecule, the name should have the ending -al. Since the aldehyde is on the 1st carbon, you can add a 1 before the -al (technically not necessary). The longest carbon chain contains 8 single-bonded carbons, making this an octane. There is an isopropyl (-CHCH₃CH₃) group on the 3rd carbon and a propyl (-CH₂CH₂CH₃) on the 4th carbon.
Therefore, the IUPAC name is: 3-isoproyl-4-propyloctan-1-al (or 3-isoproyl-4-propyloctanal)
If a 66.5 g sample of ammonium nitrate (NH4NO3) is dissolved in enough water to make 315 mL of solution, what will be the molarity (M)?
Answer:
2.64 M
Explanation:
To find the molarity, you need to (1) convert grams to moles (via molar mass), then (2) convert mL to L, and then (3) calculate the molarity (via molarity ratio). The final answer should have 3 sig figs to match the sigs figs of the given values.
(Step 1)
Molar Mass (NH₄NO₃): 2(14.007 g/mol) + 4(1.008 g/mol) + 3(15.998 g/mol)
Molar Mass (NH₄NO₃): 80.04 g/mol
66.5 grams NH₄NO₃ 1 mole
--------------------------------- x ---------------------- = 0.831 moles NH₄NO₃
80.04 grams
(Step 2)
1,000 mL = 1 L
315 mL 1 L
-------------- x ------------------ = 0.315 L
1,000 mL
(Step 3)
Molarity = moles / volume
Molarity = 0.831 moles / 0.315 L
Molarity = 2.64 M
Using standard heats of formation, calculate the standard enthalpy change for the following reaction.
2BrF3(g) -----> Br2(g) + 3F2(g)
Using standard heats of formation, the standard enthalpy change for the reaction is mathematically given as
= 542.11 kJ
What is the standard enthalpy change for the following reaction?Generally, the equation for standard enthalpy change is mathematically given as
[tex]\Delta H rxn = \Delta H product - \Delta H reactant[/tex]
therefore,
[tex]\Delta H rxn = (\Delta H Br_2 + \Delta H 3F_2) - (\Delta H 2BrF_3)[/tex]
= (30.91 kJ + 3*0 kJ) - (2*(-255.6) kJ)
= 542.11 kJ
In conclusion, the standard enthalpy change for the following reaction is
= 542.11 kJ
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Please help me with this reaction
The major product from the above organic reaction is I
In this reaction, methoxy ethane undergoes addition reaction with hydrogen bromide, Markownikoff's rule being involved in the reaction.
What are organic compounds?Organic compounds are the compounds which contains carbon and hydrogen.
Generally, organic compounds are characterized by the following:
All organic compounds contains carbon Organic compounds are also combustible in nature They are mostly covalent bonded molecules They are all soluble in non-polar solvents.They can be isolatedThey can also be prepared in the laboratoryBelow are some classes of organic compounds:
AlkanesAlkenesAlkynesAlkanolsAlkanoic acidAlkanalsEstersKetonesAminesSo therefore, the major product from the the above organic reaction is IV
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What would the hydroxide ion concentration be if the hydrogen ion concentration was 1.5 x 10-10 M?
Taking into account the definition of pH and pOH, the hydroxide ion concentration will be 6.61×10⁻⁵ M.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
Hydroxide ion concentrationIn this case you know that the hydrogen ion concentration is 1.5×10⁻¹⁰ M, this is, [H⁺]= 1.5×10⁻¹⁰ M.
Replacing in the definition of pH:
pH= - log (1.5×10⁻¹⁰ M)
Solving:
pH= 9.82
Replacing in the relationship established between pH and pOH, the pOH can be calculated as:
pOH + 9.82= 14
Solving:
pOH= 14 - 9.82
pOH= 4.18
Replacing in the definition of pOH, the concentration of hydroxide ion is obtained:
- log [OH⁻]= 4.18
Solving:
[OH⁻]= 10⁻⁴ ¹⁸
[OH⁻]= 6.61×10⁻⁵ M
In summary, the hydroxide ion concentration will be 6.61×10⁻⁵ M.
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You perform an electrolysis of NaCl and collect one of the products in a test tube. You realize later you did not label the test tube. You dip a strip of damp pH paper into the test tube and get no reaction. You dip a dry strip of pH paper into the tube and there is no reaction. You hold a lit match near the mouth of the test tube and hear a loud 'pop'. Which product is in the test tube?
A. Chlorine gas
B. Sodium hydroxide (NaOH)
C. Hydrogen gas
D. Oxygen gas
The correct alternative is (b). NaOH will be present in the test tube, after performing electrolysis.
Aqueous electrolysis of salt solutions finds the salt ions in competition with electrolysis of water at the respective electrodes. That is, water can undergo reduction at the cathode as can the cation of the salt; while at the anode water can undergo oxidation as can the anion of the salt. The reactions are as follows:
Cathode:
H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g)
Anode:
2H₂O(l) ⇄ O₂(g) + 4H⁺(aq) + 4e⁻
The distinction can be determined by comparing the 'Standard Reduction Potentials' of the half-reactions.
For NaCl(s) => Na⁺(aq) + Cl⁻(aq) :
At the Cathode:
Na⁺ + e⁻ => Na⁰(s); εo = -2.71v
2H₂O(l) + 2e⁻ ⇄ 2OH⁻(aq) + H₂(g); εo = -0.83v (Dominant Rxn at cathode – more positive value)
At the Anode:
Cl⁻(aq) => Cl₂(g) + 2e⁻; εo = 1.36v
2H₂O(l) => O₂(g) + 4H⁺ + 4e⁻; εo = 1.23v (Dominant Rxn at anode – more positive value)
Since the more dominant reaction at the cathode(reduction) produces hydroxide ions, the solution would become alkaline with Na⁺ ions already present.
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If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.
If the mass of the sun is 2x, at least one planet will fall into the habitable zone. if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully.
Mass of the sun and motion of planetsThe size of the sun and motion of planets around it is illustrated below;
When the mass of the sun is 1xIf the mass of the sun is 1x, at least one planet will fall into the habitable zone. if I place a planet in orbits 2, 6, and 75, and all planets will orbit the sun successfully.
When the mass of the sun is 2xIf the mass of the sun is 2x, at least one planet will fall into the habitable zone. if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully.
When the mass of the sun is 3xIf the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits 672, and 7 and all planets will orbit the sun successfully.
Thus, If the mass of the sun is 2x, at least one planet will fall into the habitable zone. if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully.
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Which of the following will increase entropy in a reaction?
Group of answer choices
A. Using a larger particle
B. heating up the reaction
C. cooling down the reaction
D. Making less moles of products than there were reactants.
The condition that will increase the entropy in a reaction is heating up the reaction (option B).
What is entropy?Entropy in chemistry is the measure or degree of the disorder or randomness present in a chemical system.
In a chemical reaction, reacting substances called reactants collide with one another to form products.
However, the degree at which the reactants collide with one another is referred to as the entropy of the reaction.
Therefore, the condition that will increase the entropy in a reaction is heating up the reaction i.e. increase in temperature.
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What answer should be reported, with the correct number of significant figures, for the following calculation? (433.621 - 333.9) × 11.900
Answer:
1187 ( four S.D. )
Explanation:
(433.621 - 333.9) × 11.900 333.9 has only 4 S.D. answer should only have 4 S.D
= 1186.6799 = ~ 1187 with 4 Significant Digits
Need the answer pretttty pleaseeeeee
Answer:
B.) their electrons are assigned to the s and p orbitals only
Explanation:
Once you get to the fourth row on the periodic table, the transition metals are introduced. The transition metals are located in the d-block and their electrons fill up d orbitals. When an element in the p-block (the right side of the table) is in one of these rows, the d-block has to fill up first.
How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? cacl2(aq) k2co3(aq) → 2 kcl(aq) caco3(aq)
Answer:
1.12 g CaCl₂
Explanation:
To find the mass of calcium chloride, you need to (1) convert grams KCl to moles KCl (via molar mass), then (2) convert moles KCl to moles CaCl₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CaCl₂ to grams CaCl₂ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Molar Mass (KCl): 39.098 g/mol + 35.453 g/mol
Molar Mass (KCl): 74.551 g/mol
Molar Mass (CaCl₂): 40.078 g/mol + 2(35.453 g/mol)
Molar Mass (CaCl₂): 110.984 g/mol
1 CaCl₂(aq) + K₂CO₃(aq) -----> 2 KCl(aq) + CaCO₃(aq)
1.50 g KCl 1 mole 1 mole CaCl₂ 110.984 g
----------------- x ----------------- x ----------------------- x ------------------ =
74.551 g 2 moles KCl 1 mole
= 1.12 g CaCl₂
State which substance is undergoing oxidation and which substance is undergoing reduction in the following reaction:
Fe 3+ (aq) + SO3 2- (aq) ---> Fe 2+ (aq) + SO4 2- (aq)
Fe is undergoing oxidation while S is undergoing reduction
What is oxidation-reduction reaction?Oxidation-reduction reaction can simply be defined as a special type of chemical reaction in which the oxidation states of substrate change. Oxidation is the
So therefore, Fe is undergoing oxidation while S is undergoing reduction
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The combustion of 296 g of propane (C₃H₈) produces 713 g of carbon dioxide. [C₃H₈ + 5O₂ --> 3CO₂ + 4H₂O; C = 12.01 g/mol, H = 1.01 g/mol, O = 16.0 g/mol]
What is the percent yield?
80.5%
124%
0.805%
41.50%
Answer:
80.5%
Explanation:
The percent yield is made up of the theoretical yield and actual yield. The theoretical yield is the amount of product produced from the balanced chemical equation and molar masses. The actual yield is the amount of product produced in an experiment.
To find the percent yield, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio from equation coefficients), then (3) convert moles CO₂ to grams CO₂ (via molar mass), and then (4) calculate the percent yield. It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
(Steps 1 - 3)
Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.01 g/mol)
Molar Mass (C₃H₈): 44.11 g/mol
Molar Mass (CO₂): 12.01 g/mol + 2(16.0 g/mol)
Molar Mass (CO₂): 44.01 g/mol
1 C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
296 g C₃H₈ 1 mole 3 moles CO₂ 44.01 g
------------------- x ---------------- x ---------------------- x ---------------- = 886 g CO₂
44.11 g 1 mole C₃H₈ 1 mole
(Step 4)
Actual Yield
Percent Yield = ------------------------------ x 100%
Theoretical Yield
713 g CO₂
Percent Yield = ---------------------- x 100%
886 g CO₂
Percent Yield = 80.5%
Write a balanced equation for the following redox reaction using the oxidation number method:
Cl2 (g) + KI (aq) ---> I2 (s) + KCl (aq)
The balanced equation for the following redox reaction using the oxidation number method is as follows:
2K + 2I− + Cl 2 → I2 +2Cl− +2K+
What is a redox reaction?A redox reaction in chemistry is a chemical reaction in which some of the atoms have their oxidation number changed.
According to this question, the following balanced chemical equation is given:
Cl2 (g) + KI (aq) → I2 (s) + KCl (aq)
The oxidation number of the ions in a redox reaction changes, and in this case, the ionic reaction is as follows:
2K + 2I− + Cl 2 → I2 + 2Cl− +2K+
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How many moles of solute particles are present in 1 mL (exact) of aqueous 0.0040 M Ba(OH)2?
Answer:
4.0 x 10^-6 moles
Explanation:
0.0040 M Ba(OH)2 means there is .0040 moles per liter
you want 1 ml which is 1/1000 liter so you get 1/1000 of the moles
= .0000040 moles
What volume did a helium-filled balloon have at 22.5 c and 1.95 atm if it’s new volume was 56.4 mL at 3.69 atm and 11.9c
This is an exercise in the general or combined gas law.
To start solving this exercise, we obtain the following data:
Data:T₁ = 22.5 °C + 273 = 295.5 KP₁ = 1.95 atmV₁ = ¿?P₂ = 3.69 atmT₂ = 11.9 °C + 273 = 284.9 kV₂= 56.4 mlWe use the following formula:
P₁V₁T₂ = P₂V₂T₁ ⇒ General formula
Where
P₁ = Initial pressureV₁ = Initial volumeT₂ = Initial temperatureP₂ = Final pressureV₂ = final volumeT₁ = Initial temperatureWe clear the formula for the initial volume:
[tex]\boldsymbol{\sf{V_{1}=\dfrac{P_{2}V_{2}T_{1}}{P_{1}T_{2}} } }[/tex]
We substitute our data into the formula to solve:
[tex]\boldsymbol{\sf{V_{1}=\dfrac{(3.69 \not{atm})(56.4 \ ml)(295.5 \not{k})}{(1.95 \not{atm})(284.9\not{k})} }}[/tex]
[tex]\boldsymbol{\sf{V_{1}=\dfrac{61498.278}{555.555} \ lm }}[/tex]
[tex]\boxed{\boldsymbol{\sf{V_{1}=110.697 \ lm }}}[/tex]
The helium-filled balloon has a volume of 110.697 ml.
Answer:
111 ml
Explanation:
Use the general rule for gases:
P1 V1 / T1 = P2 V2 / T2 Looking for V1 T must be in Kelvin
re-arrange to :
V1 = P2 V 2 * T1 / (T2 * P1) <==== now sub in the values
V1 = 3.69 * 56.4 * (22.5 + 273.15) / [(11.9 + 273.15) * 1.95]
V1 = 110.6949 ml
for correctness, the answer should only have THREE significant digits as all of the factors have three SD
V1 = 111 ml
The symbol X in the following equation, 23/11 Na + 1/1H → 23/12 Mg + X, is a/an
Answer:
X = ¹₀n
Explanation:
The mass number is the total amount of neutrons and protons in the element. The atomic number is the total protons in the element. The mass number is the superscript and the atomic number is the subscript. The mass and atomic numbers must be balanced on both sides of the equation. The element can be identified by the atomic number.
In the event that we have an atomic number of zero, there is no element this represents, so the letter "n" should be used.
²³₁₁Na + ¹₁H → ²³₁₂Mg + X
Mass Number:
Reactants = Products
23 + 1 = 23 + ?
24 = 23 + ?
1 = ?
Atomic Number:
Reactants = Products
11 + 1 = 12 + ?
12 = 12 + ?
0 = ?
The complete equation is:
²³₁₁Na + ¹₁H → ²³₁₂Mg + ¹₀n
If the pressure is doubles and the temperature is held constant what will happen to the volume of a gas?
Group of answer choices
A. Quadrupled
B. Doubled
C. Reduced by Half
D. Reduced by a Fourth
Answer:
C
Explanation:
Of course increasing the pressure will reduce the volume
P1V1 = P2V2
P1V1/P2 = V2 WHEN P2 = 2 P1----multiply both sides by 1/2
P1 V1 / 2P1 = 1/2 V2 <===== 1/2 the original
Predict the products and write a word equation and a balanced chemical reaction
equation for when aqueous lithium sulfate reacts with aqueous calcium iodide.
Answer:
1.) aqueous lithium sulfate + aqueous calcium iodide ---> aqueous lithium iodide + solid calcium sulfate
2.) Li₂SO₄ (aq) + CaI₂ (aq) ------> 2 LiI (aq) + CaSO₄ (s)
Explanation:
This appears to be a double-displacement reaction. In these reactions, the cation of one compound swaps with the cation of another.
Therefore, lithium swaps with calcium. The new products are lithium iodide (LiI) and calcium sulfate (CaSO₄). Lithium iodide is soluble in water, whereas calcium sulfate is generally not.
The word equation (including the states of matter):
aqueous lithium sulfate + aqueous calcium iodide ---> aqueous lithium iodide + solid calcium sulfate
An equation is balanced when there is an equal amount of each element on both sides of a reaction. If these amounts are unequal, you can add coefficients to modify the quantities of particular molecules.
The unbalanced equation:
Li₂SO₄ (aq) + CaI₂ (aq) ------> LiI (aq) + CaSO₄ (s)
Reactants: 2 lithium, 1 sulfur, 4 oxygen, 1 calcium, 2 iodine
Products: 1 lithium, 1 sulfur, 4 oxygen, 1 calcium, 1 iodine
The balanced equation:
Li₂SO₄ (aq) + CaI₂ (aq) ------> 2 LiI (aq) + CaSO₄ (s)
Reactants: 2 lithium, 1 sulfur, 4 oxygen, 1 calcium, 2 iodine
Products: 2 lithium, 1 sulfur, 4 oxygen, 1 calcium, 2 iodine
Difference between jaanto and panighatta..
Answer:
they're both completely different games
Explanation:
Answer: uh.. tricky
Explanation:
If a thermometer reads 17° C, what is the temperature in Fahrenheit?
Answer:
62.6
Explanation:
formula = (°C x 9/5) + 32
(17°C x 9/5) + 32
30.6 + 32
62.6
us
Let's say that you were asked to find the
molecular formula for a compound given its
empirical formula, CH₂O, and the compound's
molar mass.
The first step in solving such a problem is to
calculate the molar mass for the empirical
formula. What is the molar mass of CH₂O?
(C=12.01 amu, H=1.008 amu, O=16.00 amu)
[?] g/mol CH₂0
1
Answer:
Molar mass = 30.026 g/mol
Explanation:
Let Molar mass be mm
mm of CH2O = 12.01 + 2(1.008) + 16.00
= 12.01 + 2.016 + 16.00 = 30.026 g/mol
A chemistry student needs 45.0mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is ·0.626gcm−3. Calculate the mass of pentane the student should weigh out. Round your answer to 3 significant digits.
The mass of pentane the student should weigh out is
The density of pentane is 0.626 gcm-3
To calculate the mass of pentane following expression is used,
(Density is defined as the mass divide by volume)
Density = mass / volume
mass of pentane = Density of pentane * Volume of pentane
mass of pentane = 0.626 gcm-3 * 45.0 mL
= 28.17 g
Here the unit of mass of pentane is g,
However the unit of density is gcm-3 and unit of volume is mL i.e. cm3
Hence, Mass = gcm-3 * cm3
Mass = g
The mass of pentane the student should weigh out is 28.17g
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An enzyme (MW 24 kDa, pI 5.5) is contaminated with two other proteins, one with a similar molecular mass and a pI of 7.0 while the other has a molecular mass of 100 kDa and a pI of 5.4. Suggest a procedure to purify the contaminated enzyme.
The procedure to purify/separate these enzymes might be associated with the ion exchange chromatography methodology.
What is ion exchange chromatography methodology?The ion exchange chromatography methodology is a technique to separate molecules such as proteins (in this case enzymes) based on their charge.
The ion exchange chromatography methodology is based on the use of different types of resins that allow the separation of molecules based on their charges and mass.
In conclusion, the procedure to purify/separate these enzymes might be associated with the ion exchange chromatography methodology.
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which three directions in the drawing below are most likely to result in a warmer earth?
The directions that are likely to result in a warmer earth are the directions 3, 5 and 6.
What is global warming?The term global warming has to do with the gradual rise in the temperature of the earth as a result of the re-radiation of infrared rays back to the earth. We know that greenhouse gases are able to trap the infrared rays from the sun and reradiate same to the surface of the earth and this ultimately leads to a warmer earth.
As such, if we look at the image closely, we can see that there is a reradiation of the rays to the earth in the directions 3, 5 and 6. It then follows that the directions that are likely to result in a warmer earth are the directions 3, 5 and 6.
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