Quick algebra 1 question for 25 points!



Only answer if you know the answer, Tysm!

Answer:

it helps you control your spending, track your expenses, and save more money.

s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom. This can be obtained the same way of finding algebraic equation using variables ad constants.

From the question it is given that:

From the given statements we can say that sonic booms are created ONLY WHEN the speed of object (s) is greater than the speed of the sound.

This clearly means that sonic booms are produced when s is greater that s

There are three possible situations in the given scenario:

Since we are looking for the true equation of creation of sonic waves,

it would be only the last one (s > 1225 km/hr).

Hence s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom.

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s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom. This can be obtained the same way of finding algebraic equation using variables ad constants.

Find the required inequality:

From the question it is given that:

speed of sound is approximately 1225 km/hr

a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom

From the given statements we can say that sonic booms are created ONLY WHEN the speed of object (s) is greater than the speed of the sound.

This clearly means that sonic booms are produced when s is greater that s

There are three possible situations in the given scenario:

Speed of light can be less than 1225 km/hr ⇒  s < 1225 km/hr ⇒ no sonic boom is created (assumption is wrong)

s = 1225 km/hr  ⇒ no sonic boom is created (assumption is wrong)

s > 1225 km/hr  ⇒ sonic boom is created (assumption is correct)

Since we are looking for the true equation of creation of sonic waves,

it would be only the last one (s > 1225 km/hr).

Hence s > 1225 km/hr is the inequality that describes s, the speeds at which a moving object creates a sonic boom given that when an object travels faster than the speed of sound, it creates a sonic boom.

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Answer:

It is the second picture.

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

This question is asking you to solve for the following system of equations, let x be width and y be height of the rectangle.

[tex]\left \{ {{x=y+5} \atop {x*y=24}} \right.[/tex]

Since the former is already equal to x lets set the second equation to x

[tex]x*y=24[/tex]

[tex]x=24/y[/tex]

Now we have the following system of equations:

[tex]\left \{ {{x=y+5} \atop {x=24/y}} \right.[/tex]

Now that the two equations are equal, we can solve for y:

[tex]y+5=24/y[/tex]

Divide both sides by y

[tex]y^2+5y=24[/tex]

Subtract 24 from the right side setting it to 0:

[tex]y^2+5y-24=0[/tex]

Solve for y using quadratic formula:

[tex]y=\frac{-5\pm \sqrt{5^2-4\cdot \:1\cdot \left(-24\right)}}{2\cdot \:1}[/tex]

[tex]y=3,-8[/tex]

Given the y-values lets plug them into our original equations to find the intersections.

[tex]x=3+5\\x=8[/tex]

Giving intersection vector (8,3)

[tex]x=-8+5\\x=-3[/tex]

Giving intersection vector (-3,-8)

Since both the width and length of the rectangle must be positive lets use the first vector (8,3) as our solution.

The x value being 8 means the width must be 8, y value being 3 the height must be 3, these variable correlate to our original definitions of making the x value equal to the width of the carpet and y value the height of the carpet.

Answer:The width is 3mm

Step-by-step explanation:

Length= 5mm + width

Let the width be represented by W

Area=24mm^2

Since area= length x width

24=(5+ W) x W

24=5W +[tex]W^{2}[/tex]

[tex]W^{2}[/tex] +5W-24=0

The factors are 8 and -3

[tex]W^{2}[/tex]+8w-3w-24=0

Factorise

W(w+8)-3(w+8)=0

(w-3)=0 or (w+8)=0

W=3 0r w= -8

The width cannot be negative.

Hence,W=3mm

Answer:

So, having "hold-out" data allows you to have a nonpartisan set of data (so to speak) for you to refer to later, once you have made use of the "train" and "test" sets. That way you can make a fair assessment as to the difference between the new and old ('hold-out") sets.

Or if you need to repeat the experiment or model again - then you can refer to the "hold out data"

Answer:

numbers

Step-by-step explanation:

numbers

Answer: 254,34 mm².

Step-by-step explanation:

[tex]S{circle}=\pi R^2\\S{circle}=3,14*9^2\\S{circle}=3,14*81\\S{circle}=254,34\ mm^2.[/tex]

Hi :)

Let's first find the area of this circle

For finding the area of a circle we use

[tex]\longrightarrow\sf{A_{\circ}=\pi r^2}[/tex], where only r (radius) is squared

[tex]\textit{We know that :}\begin{cases} \sf{Radius = 9 mm} \\ \sf{\pi =3.14} \end{cases}}[/tex]

Thus

[tex]\longrightarrow\sf{A_{\circ}=3.14\cdot9^2}[/tex]

[tex]\longrightarrow\sf{A_{\circ}=3.14\times81}[/tex]

[tex]\longrightarrow\sf{\underline{A_{\circ}=254.34\: mm}}[/tex]

[tex]\tt{Learn\:More;Work\;Harder}[/tex]

:)

Alpha level. the minimum P-value at which we reject the null hypothesis

That two options are identical is the null hypothesis. According to the null hypothesis, the observed difference is solely the result of chance. The probability that the null hypothesis is correct can be determined via statistical testing.

The "significance level," often known as the alpha level, must be established before performing any statistical test. The likelihood of rejecting the null hypothesis when it is true is what is meant by the term "alpha level" in statistics. The likelihood of making a poor decision is what this phrase means.

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The number of different integers there are for the condition described in which case, the square of the square of the integer is a two-digit integer as in the task content is 4 possible integers which includes; -2, -3, 2, 3.

According to the task content, the square of the square of such integers must be a two-digit number, that is, less than or equal to 99.

The numbers in discuss, x must satisfy;

x⁴ < 99.

The numbers in this regard are therefore, -2, -3, 2, 3.

Ultimately, the integers which satisfy the condition described in which case, the square of the square of the integer is a two-digit integer as in the task content is 4 possible integers which includes; -2, -3, 2, 3.

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Answer is Healthclub A costs $33 less in monthly fees than Healthclub B

The number next to the “x” is your rate.

So Healthclub A charges $33 less than B

A charges 27 monthly fee

B charges 60 monthly fee

60-27=33

Using Chebyshev's Theorem, we are guaranteed to find at least 75% of the people earning hourly wages between $4.15 and $23.23.

When the distribution is not normal, Chebyshev's Theorem is used. It states that:

In this problem, we want the values within 2 standard deviations of the mean, hence the values are:

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Answer:

11/6 + -2/5 +-13/10?

11/6 + (-2/5) + (-13/10)

43/30 - 13/10

2/15

The estimated value of y when x=30. The answer rounded to three decimal places is 5.

Envisioned cost method, as of any date of willpower, with respect to any paintings of art, the most latest estimate of fee of such paintings of artwork, as determined every so often through the relevant Borrower in accordance with phase 5.12.

To discover the estimated value E(X), or imply μ of a discrete random variable X, in reality,y multiply every value of the random variable by way of its chance and upload the products. The method is given as E ( X ) = μ = ∑ x P ( x ) .

In opportunity theory, the estimated value is a generalization of the weighted common. Informally, the anticipated price is the mathematics suggestion of a big variety of independently decided effects of a random variable.

estimated Y when

b₁x + b

X = 30.

=( 0·302) (30) + (-3-772)

5.288

= 5

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Answer:

The mean absolute deviation (MAD) is 0

Step-by-step explanation:

20 + 16 + 21 + 16 + 22 + 16 + 15

= 126 ÷ 7 = 18

(20 - 18) + (16 - 18) + (21 - 18) + (16 - 18) + (22 - 18) + (16 - 18) + (15 - 18) =

2 +(-2) + 3 + (-2) + 4 + (-2) + (-3) = 0 ÷ 7= 0

The mean absolute deviation (MAD) is 0

Answer:

blank = inheritance

Step-by-step explanation:

Hope that helps

Answer:

3

Step-by-step explanation:

[tex]6=2 \times 3 \\ \\ 12=3 \times 2^2 \\ \\ 21=3 \times 7[/tex]

Step-by-step explanation:

f(a):

   So for this you simply plug in "a" as x, and this doesn't really do anything beside replace all values with x, so you just have the equation:

  [tex]f(a) = 5a+4[/tex]

2 f(a):

   So for this one, you want to represent f(a) using the equation it's equal to (5a + 4), and substitute it in for f(a). In doing so, you get the expression:

   2*f(a) -> 2(5a + 4) -> 10a + 8

f(2a):

   So this is very similar to the first question, although you will have to do some multiplication. So just plug in 2a as "x" to get the equation:

   [tex]f(2a) = 5(2a) + 4 = 10a+4[/tex]

f(a+2):

   Basically the same process, you plug in (a+2) as "x" and simplify:

   [tex]f(a+2) = 5(a+2) + 4\\f(a+2) = 10a+10+4\\f(a+2) = 10a+14[/tex]

f(a) + f(2):

  This is similar to the second question, and you simply want to replace the f(a) with the equation that represents it (5a + 4) and same thing for f(2) = 5(2) + 4

   [tex]f(a) + f(2) = (5a+4)+(5(2)+4) \\f(a) + f(2) = (5a+4)+(10+4)\\f(a)+f(2) = (5a+4) + (14)\\f(a) + f(2) = 5a+18[/tex]

This statement is true that the In c 11 you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

According to the statement

we have given that the one statement and we have to tell that the those statement is true or false after analyzing it.

So,

In C++ 11 is  a programming language which is used to write the coding. And in this language you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

Because in the coding it is not possible that the you can make loop without declare the random variable in the loop.

Due to this reasons without declare the variable it is not possible.

So, This statement is true that the In c 11 you cannot use a range-based for loop to modify the contents of an array unless you declare the range variable as a reference variable.

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=======================================================

Explanation:

Replace x with 4 and y with 5.

Then use the order of operations (PEMDAS) to simplify until you get a single number.

Something like 9x means "9 times x", and a similar situation happens with the 8y term as well.

---------

Here's what the steps look like:

9x + 8y

9*4 + 8*5

36 + 40

76

Therefore, 9x+8y = 76 when x = 4 and y = 5.

The point (4,5) is located on the line 9x+8y = 76

[tex](x-1) ^ { 3 } -(x-2) ^ { 2 } =1[/tex]

[tex]x^{3}-3x^{2}+3x-1-\left(x-2\right)^{2}=1 [/tex]

[tex]x^{3}-3x^{2}+3x-1-\left(x^{2}-4x+4\right)=1 [/tex]

[tex]x^{3}-3x^{2}+3x-1-x^{2}+4x-4=1 [/tex]

[tex]x^{3}-4x^{2}+7x-1-4=1 [/tex]

[tex]x^{3}-4x^{2}+7x-5=1 [/tex]

[tex]x^{3}-4x^{2}+7x-5-1=0 [/tex]

[tex]x^{3}-4x^{2}+7x-6=0 [/tex]

[tex]±6,±3,±2,±1 [/tex]

Answer:

6/25.

Step-by-step explanation:

They are 19, 29, 59, 79, 89 and 97.

A total of 6.

So the required fraction is 6/25.

Using the z-distribution, the estimate for how much the drug will lower a typical patient's systolic blood pressure is:

[tex]46.6 \leq \mu \leq 48[/tex]

The confidence interval is:

[tex]\overline{x} \pm z\frac{\sigma}{\sqrt{n}}[/tex]

In which:

In this problem, we have a 80% confidence level, hence[tex]\alpha = 0.8[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.8}{2} = 0.9[/tex], so the critical value is z = 1.28.

The other parameters are given by:

[tex]\overline{x} = 47.3, \sigma = 15.9, n = 878[/tex]

Then the bounds of the interval are:

[tex]\overline{x} - z\frac{\sigma}{\sqrt{n}} = 47.3 - 1.28\frac{15.9}{\sqrt{878}} = 46.6[/tex]

[tex]\overline{x} + z\frac{\sigma}{\sqrt{n}} = 47.3 + 1.28\frac{15.9}{\sqrt{878}} = 48[/tex]

Hence the interval is:

[tex]46.6 \leq \mu \leq 48[/tex]

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Answer:

I = (PTR)/100

1450=(5000*1*R)/100

1450*100=5000R

145000/50000=R

29=R

Step-by-step explanation:

We know,

[tex] S.I. = \rm\cfrac{P*R*T}{100}[/tex]

Given,

Principal P = 5000

Rate R = R(Assume)

Time T = 1

Interest = 1450

Plug:

[tex]1450 = \frac{5000 \times r \times 1}{100} [/tex]

Solve:

[tex]1450 \times 100 = 5000 \times r[/tex]

[tex]145000 \div 5000 = r[/tex]

[tex]r \: = \: 29 \%[/tex]

Rate = 29

Therefore,the rate of Interest is 29%.

Answer:

No,

Step-by-step explanation:

X^-2 is equal to 1/X^2. so any number or letter to negative power, is the same as 1 divided by that number or letter to the positive power..(power remains with denominator

Answer:  the average rate of change of the function is 23.

Step-by-step explanation:

[tex]h(x)=x^2-10x+21\ \ \ \ \ -1\leq x\leq 10 \ \ \ \ A(x)=?\\\displaystyle\\A(x)=\frac{\Delta y}{\Delta x}=\frac{h(x-g)-h(x)}{g} \\g=x_{max}-x_{min}\\g=10-(-1)\\g=10+1\\g=11.\ \ \ \ \ \Rightarrow\\A(x)=\frac{(x-11)^2-10*(x-11)+21-(x^2-10x+21)}{11} \\A(x)=\frac{x^2-22x+121-10x+110+21-x^2+10x-21}{11} \\A(x)=\frac{231-22x}{11}\\ A(x)=\frac{11*(21-2x)}{11}\\ A(x)=21-2x.\\x=x_{min}\ \ \ \ \ \Rightarrow\\A(x)=21-2*(-1)\\A(x)=21+2\\A(x)=23.[/tex]

Using linear functions, it is found that both people are paid the same.

A linear function is modeled by:

y = mx + b

In which:

For Bob, we have that that the intercept is of 30000, with a slope of $600, hence his salary after x years is given by:

B(x) = 30,000 + 600x.

For Sue, we have that that the intercept is of 2 x 15000 = 30000, which is the fixed yearly salary with a slope of 2 x 300 = $600, hence her salary after x years is given by:

S(x) = 30,000 + 600x.

The salaries are equal, that is, both people are paid the same.

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Slope can be found from two points using the equation [tex]\frac{y_{2}- y_{1}}{x_{2}- x_{1}}[/tex].

Take any two points to substitute in. In this example, I'll use the first two points, (-4, 15), and (-2, 9). Put these into the equation and you'll get

[tex]\frac{(9-15)}{(-2-(-4))}[/tex]. Simplify further to get [tex]\frac{-6}{2}[/tex]. Divide this and you'll get the slope, -3!

hope this helps!