Quick algebra 1 question for 50 points!

Only answer if you know the answer, Tysm!

Quick Algebra 1 Question For 50 Points!Only Answer If You Know The Answer, Tysm!

Answers

Answer 1

Answer:

x=1

Step-by-step explanation:

2/3(9x-6) = 1/4(12-4x)

We want to solve for x

Distribute

6x-4=3-x

Add x to each side

6x-4+x = 3-x+x

7x-4 = 3

Add 4 to each side

7x-4+4 = 3+4

7x=7

Divide by 7

7x/7 = 7/7

x=1

Answer 2

Answer:

x = 1

Step-by-step explanation:

[tex]\frac{2}{3}[/tex] (9x - 6) = [tex]\frac{1}{4}[/tex] (12 - 4x) ← distribute parenthesis on both sides

6x - 4 = 3 - x ( add x to both sides )

7x - 4 = 3 ( add 4 to both sides )

7x = 7 ( divide both sides by 7 )

x = 1


Related Questions

what is the digit of 7 in 906point7

Answers

The 7 is in the first position after the decimal point so it is in the tenths column so it is worth 7 tenths or 7/10
Hello there! In the number 906.7, 7 is in the first place to the right of the decimal point. Because of this, we know that it is in the tenths place (not the tens). Anything to the right of the decimal points is less than a whole until it equals up to 1.0. In this number, these are the values of all of the digits:

• 9 has a value of 900 and is in the hundreds place

• 0, despite being in the tens place, has a value of 0

• 6 has a value of 6 and is in the ones place

• 7 has a value of 0.7, 70%, or 7/10 because it is one place to the right of the decimal point and is therefore not a full number

The digit of 7 in 906.7 is 7/10. If you need additional help, let me know and I will gladly assist you.

What is the smallest positive integer having eactly 5 different positive integer divisors?

Answers

The smallest positive integer having exactly 5 different positive integer divisors is 60.

What are positive integers?Positive integers are the numbers that we use to count: 1, 2, 3, 4, and so on. A collection of positive integers excludes numbers with a fractional element that is not equal to zero and negative numbers. Positive integers can be used for addition, subtraction, multiplication, and division operations.

To find the smallest positive integer having exactly 5 different positive integer divisors:

Take out the LCM of 1,2,3,4, and 5.The LCM of 1,2,3,4, and 5 is 60.

Therefore, the smallest positive integer having exactly 5 different positive integer divisors is 60.

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Find the total surface area. A. 78 B. 98 C. 69 D. 92

Answers

The total surface area of the figure is 92 m².

How to find the surface area of a figure?

The surface area of a figure is the sum of the whole sides of the figure.

Therefore,

surface area = 4 × 4 + 4 × 4 + 6 × 4 + 2 × 4 + 1 / 2 (2 + 6)3.5 +  1 / 2 (2 + 6)3.5

Hence,

surface area = 16 + 16 + 24 + 8 + 14 + 14

Therefore,

surface area = 32 + 24 + 8 + 28

surface area = 56 + 8 + 28

surface area = 92 m²

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Pls help I’ll brainlest
Asap

Answers

Answer:

C. slope

Greetings !

The symbol for slope is "m". Slope can be calculated by taking any two locations along a line and calculating the ratio of the RISE to the RUN (the ratio of the difference between vertical positions of the locations to the difference between horizontal positions of the locations).

Answer: slope.

Step-by-step explanation:

Consider the function . find the vertical asymptote(s) of f(x). x = 0, –9 x = –9 x = 0, 9 x = 9

Answers

The vertical asymptote of f(x) is (A) x = 0, –9.

What is a function?A function is an expression, rule, or law in mathematics that describes a relationship between one variable (the independent variable) and another variable (the dependent variable). Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.

To find the vertical asymptote of f(x):

The vertical asymptotes of a function are the zeroes of the denominator of a rational function

The function is given as: [tex]f(x) = \frac{(x-9)}{(x^{3} -81x)}[/tex]

Set the denominator to 0:

[tex]x^{3} -81x=0[/tex]

Factor out x:

[tex]x(x^{2} -81)=0[/tex]

Express 81 as 9^2:

[tex]x(x^{2} -9^{2} )=0[/tex]

Express the difference between the two squares:

[tex]x(x-9)(x+9)[/tex]

Split, [tex]x=0[/tex] or [tex]x=-9[/tex] or [tex]x+9=0[/tex].

Solve for x:

[tex]x=0\\[/tex] or [tex]x=-9[/tex] or [tex]x+9=0[/tex].

Therefore, the vertical asymptote of f(x) is (A) x = 0, –9.

(See attachment for the graph of f(x))

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The complete question is given below:

Consider the function f(x)=(x-9)/(x^3-81x) . find the vertical asymptote(s) of f(x).

A) x = 0, –9

B) x = –9

C) x = 0, 9

D) x = 9

(2x+1)/(x²-3) simplified

Answers

The simplified expression of (2x+1)/(x²-3) is 2x/(x²-3) + 1/(x²-3)

How to simplify the expression?

The expression is given as:

(2x+1)/(x²-3)

The above expression is a fraction and the numerator has 2 terms

For a fraction

A + B)/x

The fraction can be split as

A/x + B/x

Using the above as a guide, we have:

(2x+1)/(x²-3) = 2x/(x²-3) + 1/(x²-3)

Hence, the simplified expression of (2x+1)/(x²-3) is 2x/(x²-3) + 1/(x²-3)

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guys please help me

Answers

Answer:

-1 and 1

Step-by-step explanation:

Reflecting D over the y-axis maps it onto (1,2).

This is supposed to map onto F(0,3), so this is a shift 1 unit left and 1 unit up.

So, the blanks are -1 and 1, respectively.

Answer: (x + [-1], y + [1])

Step-by-step explanation:

      See attached. We can draw, or picture it in our heads, what the reflection would look like. Then we can pick one (or multiple to test) points and see the translation.

      We can also test with a set of points. B', (2, 4) becomes G in the transformation. G is at (1, 5)

      (1 - 2, 5 - 4) -> (-1, 1)

K
Consider a study conducted in 2018 to estimate the percentage of people from a certain region who do not use the
Internet. Complete parts (a) through (c) below.
a. If a 99% confidence level is used, how many people should be included in the survey if the researchers wanted to
have a margin of error of 7%?
There should be people included in the survey.
(Round up to the nearest person as needed.)
rred

Answers

The number of people who must be included in the survey, that is, the sample size should be 340.

We assume the sample size to be n.

The confidence interval required is 99%.

The Z-score corresponding to the 99% confidence interval is (Z) 2.58.

The true proportion (p) of the sample is not given, so we assume it to be 50% or 0.5.

The margin of error for the sample (E) is given to be 7% or 0.07.

By the formula of margin of error, we know that:

E = Z√[{p(1 - p)}/n].

Putting in the values, we have, we get:

0.07 = 2.58√[{0.5*0.5}/n],

or, (0.07/2.58)² = 0.25/n,

or, n = 0.25/{(0.07/2.58)²} = 339.6122449 ≈ 340.

Thus, the number of people who must be included in the survey, that is, the sample size should be 340.

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Use the given data set to complete parts​ (a) through​ (c) below.​ (Use α=​0.05.)

Answers

1. The value of the linear correlation coefficient r is given as 0.8159. The correct option is a. There is insufficient evidence to support the claim of a nonlinear correlation between the two variables

2. The scatterplot reveals a distinct pattern that is not a straight-line pattern.

What is the linear correlation coefficient?

This is the data that we get when we try to get the existing relationship that is in existence between the variables that are used in a regression equation.

The value of r was calculated using a statistical tool online. The graph showed us it was not a straight line. The value of the r = 0.8159

The results of the test is in the attachment

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Después de 15 meses de haber prestado un capital al 5% de rédito, tengo que pagar de interés Q468.75. ¿Qué capital se ha prestado?

Answers

The capital borrowed, or the principal when the interest was Q468.75 is Q7500.

The principal P, amount borrowed, at a certain rate of interest R%, for  a time of T years, giving an interest of I, can be calculated using the formula:

P = (I * 100)/(R * T).

In the question, we are asked to find the capital borrowed, that is, the principal, when the user pays Q468.75 after 15 months at 5% of income.

Thus, Interest (I) = Q468.75, rate of interest (R) = 5%, and time (T) = 15 months = 15/12 years = 1.25 years.

Thus, the principal P, can be calculated by substituting the values in the formula: P = (I * 100)/(R * T).

P = (468.75*100)/(5*1.25),

or, P = 46875/6.25,

or, P = 7500.

Thus, the capital borrowed, or the principal when the interest was Q468.75 is Q7500.

The provided question is in Spanish. The question in English is:

"After 15 months of having borrowed capital at 5% of income, I have to pay Q468.75 in interest. What capital has been borrowed?"

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1. Find the length of a.

Answers

Answer:

Step-by-step explanation:

[tex]\dfrac{ 1 }{ 2 } \times 12\times 15\times \sin ( 110 )[/tex]

==> 84.57

I need help here’s a picture can somone explain what I need to do??

Answers

Answer:

176 square feet

Step-by-step explanation:

add the areas of the rectangle and triangle

rectangle area is

16 times 8 which is

128

rectangle area is

1/2 times 12 times 8 which is

48

then add them

128 plus 48 is

176 square feet

please help 14 points ASAP




Here are yesterday's high temperatures (in Fahrenheit) in 12 U.S. cities. 48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80 Notice that the temperatures are ordered from least to greatest. Give the five-number summary and the interquartile range for the data set. Five-number summary
Minimum:
Lower quartile:
Median: Upper quartile:
Maximum:
Interquartile range:

Answers

The desired measures for the data-set is given by:

Minimum: 48Lower quartile: 54.Median: 63.5.Upper quartile: 74.Maximum: 80.IQR: 20

How to find the five number summary and interquartile range of the data-set?

The five number summary is composed by the measures explained below, except the IQR.

The minimum value is the smallest value from the data-set, as the maximum value is the greatest value of the data-set.The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.The first quartile is the median of the first half of the data-set.The third quartile is the median of the second half of the data-set.The interquartile range is the difference of the third quartile and the first quartile.

In this problem, we have that:

The minimum value is the smallest value, of 48.The maximum value is the smallest value, of 80.The data-set has even cardinality, hence the median is the mean of the middle elements, which are 63 and 64, hence the median is of 63.5.The first quartile is the median of the five elements of the first half, hence it is of 54.The third quartile is the median of the five elements of the second half, hence it is of 74.The IQR is the difference between the quartiles, hence 74 - 54 = 20.

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Select the correct answer from the drop-down menu. consider the equations y = |x − 1| and y = 3x 2. the approximate solution of this system of equations is .

Answers

The approximate solution of this system of equations is

(x,y)=(-0.25,1.25)

What is an equation?

Equation is defined as the state of being equal and is often shown as a math expression with equal values on either side, or refers to a problem where many things need to be taken into account.

Given that,

y = |x − 1| and y = 3x+2

 y = |x − 1|

    = (x-1) ,    for  (x-1)>0 or x>1

and

y = -(x-1)  ,    for(x-1)<0  or x<1

y  = -x+1      

Now,   For x>1

y = x-1    ......(1)

y = 3x+2   ......(2)

Solving for x by equaliting's method:

 3x+2 = x-1

→ 3x-x = -1-2

→ 2x = -3

→ x = -3/2

→ x = -1.5 which is <1.

For x<1

y = -x+1    ......(1)

y = 3x+2   ......(2)

Solving for x by equaliting's method:

 3x+2 = -x+1

→ 3x+x = 1-2

→ 4x = -1

→ x = -1/4

→ x= -0.25 which is <1.

substitute the value of x = -0.25 in equation 1 for x<1.

y = -x+1

  = -(-0.25)+1

y  = 1.25

Hence, The approximate solution of this system of equations is

(x,y)=(-1/4,5/4)=(-0.25,1.25).

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Find the length of the function over the given interval. y = 3x from x = 0 to x = 2

Answers

The length of the function y = 3x over the given interval [0, 2] is 3.2 units

For given question,

We have been given a function  y = 3x

We need to find the length of the function on the interval x = 0 to x = 2.

Let f(x) = 3x where f(x) = y

We have  f'(x) = 3,  so  [f'(x)]² = 9.  

Then the arc length is given by,

[tex]\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2[/tex]

This means, the arc length is 3.2 units.

Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units

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Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centered at a=1. Write the Taylor series in summation notation

Answers

Answer:

[tex]e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...[/tex]

[tex]\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n[/tex]

Step-by-step explanation:

Taylor series expansions of f(x) at the point x = a

[tex]\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...[/tex]

This expansion is valid only if [tex]\text{f}\:^{(n)}(a)[/tex] exists and is finite for all [tex]n \in \mathbb{N}[/tex], and for values of x for which the infinite series converges.

[tex]\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1[/tex]

[tex]\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...[/tex]

[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}[/tex]

[tex]\text{f}(x)=e^{4x} \implies \text{f}(1)=e^4[/tex]

[tex]\text{f}\:'(x)=4e^{4x} \implies \text{f}\:'(1)=4e^4[/tex]

[tex]\text{f}\:''(x)=16e^{4x} \implies \text{f}\:''(1)=16e^4[/tex]

Substituting the values in the series expansion gives:

[tex]e^{4x}=e^4+4e^4(x-1)+\dfrac{16e^4}{2}(x-1)^2+...[/tex]

Factoring out e⁴:

[tex]e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right][/tex]

Taylor Series summation notation:

[tex]\displaystyle \text{f}(x)=\sum^{\infty}_{n=0} \dfrac{\text{f}\:^{(n)}(a)}{n!}(x-a)^n[/tex]

Therefore:

[tex]\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n[/tex]

1
2. Rotate Rectangle ABCD 90° counterclockwise.
Then, translate it along the vector (3,4).
A
D
B
C
-4 -2
4
2
АУ
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-4
2
4
X
A'(
B'(
C'(
D'(
A"(
B"(
C"(
D"(
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HELP ME PLS

Answers

Rotating 90 degrees counterclockwise: [tex](x,y) \longrightarrow (-y,x)[/tex]

[tex]A(-4,4) \longrightarrow A'(-4, -4)\\\\B(-3, 4) \longrightarrow B'(-4, -3)\\\\C(-3, 1) \longrightarrow C'(-1, -3)\\\\D(-4, 1) \longrightarrow D'(-1, -4)[/tex]

Translate along [tex]\langle 3, 4 \rangle[/tex]: [tex](x,y) \longrightarrow (x+3, y+4)[/tex]

[tex]A'(-4, -4) \longrightarrow A''(-1, 0)\\\\B'(-4, -3) \longrightarrow B''(-1, 1)\\\\C'(-1, -3) \longrightarrow C''(2, 1)\\\\D'(-1, -4) \longrightarrow D''(2, 0)[/tex]

What is the solution for x in the equation?

10x − 4.5 + 3x = 12x − 1.1

x =

Answers

Answer: x= 3.4

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

Answer:

x = 3.4

Step-by-step explanation:

[tex]10x - 4.5 + 3x = 12x -1.1 \\ 13x - 4.5 = 12x - 1.1 \\ 13x - 12x - 4.5 = 12x - 12x - 1.1 \\ x - 4.5 = - 1.1 \\ x - 4.5 + 4.5 = - 1.1 + 4.5 \\ x = 3.4[/tex]


Rewrite 2x = 128 as a logarithmic equation.
Ologx128=2
O log2x = 128
O log₂128 = x
Olog128x = 2

Answers

The logarithmic equation is:

log₂128 = x

So the correct option is the third one

How to rewrite this as a logarithmic equation?

Here we have the expression.

2ˣ = 128

Now, if we apply the natural logarithm to both sides, we can get:

ln(2ˣ) = ln(128)

Because of the property of natural logarithms, we can write the left side as:

ln(2ˣ) = x*ln(2) = ln(128)

Now, if we isolate x, we get:

x = ln(128)/ln(2)

And remember that:

ln(k)/ln(n) = logₙ(k)

Then we can rewrite the logarithmic equation as:

x = log₂(128)

Which is the third option.

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In quadrilateral qrst, angle r s t measures (5x 15)°. angle tqr measures (4x 3)°. circle p is inscribed with quadrilateral q r s t. what is the measure of angle rst?

Answers

The measure of the angle rst is [tex]105^{o}[/tex].

What is the inscribed quadrilateral theorem?

According to the theorem, a quadrilateral can be inscribed by a circle if and only if its opposing angles are supplementary. A quadrilateral that may be encircled by a circle is known as a cyclic quadrilateral.

The sum opposite angles of a quadrilateral is 180 degrees.

We can see that the angles rst and angle tqr are opposite angles of quadrilateral qrst, hence supplementary angles.

Therefore,

<RST + <TQR = 180

5x+15 + 4x+ 3 = 180

9x + 18 = 180

9x = 180 - 18

9x = 162

x = 162/9

x = 18

Since <RST = 5x+15

<RST = 5(18) + 15

<RST = 90 + 15

<RST = 105degrees

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Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Answers

According to the developed scale, a radiant day is 16 times brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is 16 times brighter than a dim day.

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The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

Evaluate the expression w2 - v+ 1 for W = -2 and v = -8.

A. -11
B. 5
C. 13
D. -3

Answers

Answer:

13

Step-by-step explanation:

w^2 = -2^2 = 4

-v = -1*-8 = 8

Put it together: w^2-v+1 --> 4+8+1 = 13

Add 77 -10 with its additive inverse.​

Answers

Answer: 77 - 10 = 67, and the additive inverse of 77 - 10 is 77 + 10. 77 + 10 = 87.

Hope this helps! This question was kind of confusing for me, because I didn’t understand why you said to add 77 - 10… is this is the incorrect answer sorry your question was worded weird

A rectangle on a coordinate plane is translated 5 units up and 3 units to the left. Which rule describes the
translation?
(x + 5, y-3)
(x + 5, y + 3)
(x, y)(x-3, y + 5)
(x, y) (x + 3, y + 5)
(x, y)
O(x, y)
Mark this and return
Save and Exit
lext
Submit

Answers

Answer:

(x+5, y-3)

Step-by-step explanation:

I would say this because when a plane is translated up it would be positive and when it's translated to the left it would be negative,

Using the following table determine the probability a person tests positive who does not actually have Tuberculosis.

Answers

Using it's concept, the probability a person tests positive who does not actually have Tuberculosis is:

c. 49/148.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there are 198 + 98 = 296 people who test positive, which is the number of total outcomes, and of those, 98 do not have the disease, which is the number of desired outcomes. Hence the probability is given by:

p = 98/296 = 49/148.

Which means that option c is correct.

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The probability a person tests positive who does not actually have Tuberculosis is 1/100

How to determine the probability a person tests positive who does not actually have Tuberculosis?

The probability is given as:

The probability a person tests positive who does not actually have Tuberculosis.

This is a conditional probability, and it can be calculated using

P = n(Tests positive | Does not have Tuberculosis)/n(Does not have Tuberculosis)

Using the given table of values, we have:

P = 98/9800

Evaluate the quotient

P = 1/100

Hence, the probability a person tests positive who does not actually have Tuberculosis is 1/100

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You start at (-4, 0). You move left 1 unit and down 5 units. Where do you end?

Answers

Answer: (-5, -5)

Step-by-step explanation:

(-4, 0)

Here, -4 is our x value and 0 is our y value

The x value moves horizontal (left and right) while the y value moves vertical (up and down)

If we move 1 unit left, we change x by -1 so, -4 -1 = -5

If we move 5 units down, we change y by -5 so, 0 -5 = -5

Therefore,

our new endpoint is: (-5, -5)

A sampling method is​ _________ when the individuals selected for one sample are used to determine the individuals in the second sample.

Answers

Answer:

someone please help me check my page

someone please help me check my pageStep-by-step explanation:

What is the difference between the smallest 7-digit number and the largest 6-digit number?

Answers

Answer:

the greatest 7 digit no.is = 999,99,99 the smallest 6 digit no.is= 1,00,000

Step-by-step explanation:

Sorry if I'm wrong I tried.

Do the data in the table represent a direct variation or inverse variation? Write an equation to model the data in the table?
x 2 4 8 12
y 4 2 1 2/3

Answers

Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x

Variation

Direct variation

y = k × x

4 = k × 2

4 = 2k

k = 4/2

k = 2

when y = 2 and x = 4

y = k × x

= 2 × 4

y = 8

Indirect variation

y = k/x

4 = k / 2

8 = k

when y = 2 and x = 4

y = k/x

2 = k/4

2 × 4 = k

k = 8

So,

y = k/x

y = 8/x

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Graph f(x) = 2x - 3 on a coordinate plane.
Can you explain what you are going to do in order to graph this equation?
What do you expect the graph to look like?

Answers

Answer:

Create a table.

Plug values into the equation to complete the table.

Use the table to plot points on the graph.

Draw lines through the points on your graph.

The graph should look linear because there is an x that doesn't have a power greater than or less than 1.

Other Questions
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