(refer to photos attached. Example of previous question with wrong/correct answers example, and current question needing to be solved)

Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the magnitude of the electric field only.) _____N/C

If a charge of −3.94 µC is placed at this point, what are the magnitude and direction of the force on it?

Magnitude _______N

Direction?

- toward the left
- upward
-downward
- toward the right

Since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

For an electron moving in a uniform magnetic field, the force on the electron is given by

F = Bev where

Also, this magnetic force equals the centripetal force on the electron, F'

F' = mv²/r where

Since both forces are equal,

F = F'

Bev = mv²/r

Be = mv/r

We know that angular speed, ω = v/r. So,

Be = mω

Also, angular speed, ω = 2π/T where T = period of revolution of electron

So, Be = m2π/T

Making T subject of the formula, we have

T = 2πm/Be

so, since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

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As mass increases, the following which is found to be always true is a corresponding increase in the inertia and is therefore denoted as option C.

This is defined as the property of a body to resist changes in velocity or motion. Such feature is characterized by the body having the tendency to remain at rest or in uniform motion unless an external force acts on it.

When mass increase, inertia also increases due to the large amount of force which is needed to change the direction or motion of a body in this scenario. On the other hand, when mass decreases, there is a corresponding decrease in the inertia which is present in a given body over a period of time.

This is therefore the reason why mass of a body is directly proportional to its inertia and makes it the most appropriate choice.

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The two fields were physical quantities are used in motion calculations are length and mass with time.

The physical quantity in a field is referred as every point in a particular space time.

 If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.

Length, mass and time  are the physical quantities used in motion calculations.

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The  electric charge on surface is 2.66×10-⁹NC

The electric charge is the property  of subatomic particle that causes it to experience a force when placed in an electric and magnetic field.

We have given ,

Electric field= 1.5×10⁴N/C

 Radius = 4cm = 0.04m

E = k× q/ r²

 1.5×10⁴×16×10-⁴/9×10⁹=q

 q= 2.66×10-⁹C

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Answer:

Anticlockwise directions

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Answer:

Dynamics is just a nice word used in physics denoting a branch of physics, related to the study of forces. Usually these forces are not in mechanical equilibrium, else the branch would be statics.

Option(d)i.e, Plasma is the Image of particles that are spread out, many are not touching, high energy.

Along with solid, liquid, and gas, plasma is frequently referred to as the "fourth state of matter." Heating a gas will result in the formation of plasma, which is a soup of positively and negatively charged particles (ions), similar to how adding energy causes a liquid to boil and transform into a gas (electrons).

Plasmas are less dense than solids or liquids and, like gases, have no set structure or volume. However, in contrast to regular gases, plasmas are composed of atoms in which part or all of the electrons have been removed and positively charged nuclei, known as ions, are free to move around.

Solids, liquids, gases, ionized plasma, quark-gluon plasma, bose-einstein condensate, and fermionic condensate are the seven states of matter.

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A sine bar is used to get the angular measurement of a part feature. The angle of the part feature is 18.24°

From the question

Given that,

Length of the sine bar, L = 8.000 in

Diameter of the rolls = 1.000 in

Height under the roll, H = 2.0000 + 0.5000 + 0.0050

                                     = 2.505 in

From sine bar formula,

we know that,

H = sin A x L

sin A = H ÷ L  

where,

A ⇒ angle of part feature

H ⇒ height under the roll

L ⇒ length of the sine bar

Substituting values in the above equation,

sin A = H / L

A = sin⁻¹ ( 2.505 ÷ 8 )

A = sin⁻¹ (0.3131)

A = 18.24⁰

Hence the angle of the part feature = 18.24°

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Answer:

Relative density is the ratio of the density of a substance to the density of a standard, usually water for a liquid or solid, and air for a gas.

Answer:

960 N

Explanation:

answer should have two signif digits  

a = change in velocity divided by change in time

   1 m/s / .5 s =   2 m/s^2

F = ma      a = g + 2 m/s^2 = 9.81 + 2 =  11.81 m/s^2

  81 kg * 11.81 m/s^2   = 956.61   N = ~ 960 N  (two sig digits)

(Please let me know if this is incorrect....I am not SURE )

The impulse shared by the object equals the difference in momentum of the object. In equation form,

F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.

a)There is this impulse-momentum change equation.

[tex]where m$ is the mass of a body, $F$ is a force acting to the body, $t$ is time and $D E L A T A N\}=V_{2}-V_{1}$ is the change of velocity.We consider everything is happen along a straight line, and gravitation does not participate.So, the increase of momentum is $\mathrm{F}^{*} \mathrm{t}=10000 \mathrm{~N} * 60$ seconds $=600000 \mathrm{~N}^{*} \mathrm{~s}=600000\left(\mathrm{~kg}^{*} \mathrm{~m}\right)^{*} \mathrm{~s} / \mathrm{s}^{\wedge} 2=600000 \mathrm{~kg}{ }^{*} \mathrm{~m} / \mathrm{s}$.[/tex]

We consider everything exits happen along a straight line, and gravitation does not participate.

So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.

[tex]$$\Delta(\mathrm{V})=\frac{\mathrm{F.t}}{\mathrm{m}}=\frac{600000}{1200}=500 \mathrm{~m} / \mathrm{s} .$$[/tex]

New velocity after  engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.

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Let us assume a man travelled from a point A to a point B over a distance 'd'. After a while he travels the same distance back to point A.

Therefore, since his initial and final positions are the same, displacement is equal to zero, and the distance travelled is (d + d) = 2d, which is not zero.

Example:

Imagine a person walks 10 meters forward and then turns around and walks 10 meters back to the starting point. In this case, the displacement is zero (starting point to ending point), but the distance traveled is 20 meters (10 meters forward + 10 meters backward).

Assuming point K is held in equilibrium, by Newton's second law we have

• net horizontal force

[tex]F_C \cos\left(\tan^{-1}\left(\dfrac57\right)\right) - F_A = 0[/tex]

• net vertical force

[tex]F_C \sin\left(\tan^{-1}\left(\dfrac57\right)\right) - F_B = 0[/tex]

where the angle [tex]\theta[/tex] that rope C makes with the horizontal axis satisfies

[tex]\tan(\theta) = \dfrac{9-4}{11-4} = \dfrac57[/tex]

Solve the first equation for [tex]F_C[/tex].

[tex]F_C = F_A \sec\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]

(Recall that [tex]\sec(x)=\frac1{\cos(x)}[/tex].)

Substitute this into the second equation and solve for [tex]F_B[/tex].

[tex]F_B = F_C \sin\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]

[tex]F_B = F_A \sec\left(\tan^{-1}\left(\dfrac57\right)\right) \sin\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]

[tex]F_B = F_A \tan\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]

(Recall that [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}[/tex].)

[tex]F_B = \dfrac57 F_A[/tex]

[tex]\boxed{F_B \approx 36.1\,\rm N}[/tex]

A quantitative description of a system is important as it provides information about the carrying capacity of habitable worlds.

Quantitative description refers to the description of a system which is focused on the numerical value of the properties or components of the system.

For example, a quantitative description of the components of a given habitat will be focused on the number of the individual species in the habitat. It will also be focused on the numerical value of the non-living components of the system and how such values affect the living components of the system numerically.

This information will then be used by scientists to see how modifications of the various quantitative components of the habitat will help to improve the chances of survival of species found in the habitat. This leads to such concepts as the carrying capacity of a habitat which is the maximum number of species that the available resources is a habitat can easily sustain.

In conclusion, a quantitative description is important to in investigations about the habitable world.

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Answer:

See below

Explanation:

A) bearing y reaches the FLOOR in the same amount of time   .5 seconds  since there is no initial vertical velocity component

B.  in .5 seconds y will travel     5 m/s * .5 s = 2.5 meters horizontally

C.  d = 1/2 a t^2

         = 1/2 (9.81)(.5^2) = 1.23 m table height

(a) Bearing y takes 0.2 seconds to reach the table. (b) Bearing y travels 1 meter horizontally before hitting the floor. (c)  The height of the table top above the floor level is 1.225 meters.

a) Time is taken for bearing y to reach the table:

For a horizontal motion, the equation to calculate time is:

Time (t) = Distance (d) ÷ Velocity (v)

Time (t) = Width of the table / Velocity of y

t = 1  / 5

t = 0.2 sec

So, bearing y takes 0.2 seconds to reach the table.

b) Horizontal distance traveled by bearing y before hitting the floor:

Distance (d) = Velocity (v) × Time (t)

d = 5 × 0.2

d = 1 m

So, Bearing y travels 1 meter horizontally before hitting the floor.

c) The height of the table top above the floor level:

h = (1/2) × g × t²

h = (1/2) × 9.8 × (0.5)²

h = (1/2) × 9.8 × 0.25

h = 1.225 m

So, the height of the table top above the floor level is 1.225 meters.

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Answer:

work done = ( force × displacement)

(a)The force acting on the block is it's self weight and displacement is equal to height of the tower.

work done by gravity = (250 × 10) = 2500 joule

(b) The work done by gravity 2500 joule is transferred to the object in the form of it's kinetic energy.

Answer:

No

Explanation:

When a substance changes its state , there will not be any change in the mass of substance . For example , if we change 100 grams of water (liquid) to ice(solid) , the mass of ice will be same i.e., 100 grams . This shows there is no change in the mass even if a substance changes its state.

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The coefficient of kinetic friction on the horizontal surface, μ = 0.39.

The work done on the package by friction as it slides down the circular arc from A to B, W = -4.176.

Frictional force is the force which opposes the motion of an object over another.

Frictional force acts at the surface of contact of the objects.

The frictional force, F is related to the coefficient of kinetic friction on the horizontal surface, μ, and the normal reaction or weight, mg,  of the package as follows:

F = μmg

Work done against friction, W = F * d

W = μmgd

The Kinetic energy of the package is equal to the work done against friction.

Kinetic energy of the package = mv²/2

μmgd = mv²/2

μ = v²/2gd

μ = 4.8²/(2 * 9.81 * 3)

μ = 0.39

b. Work done on the package by friction as it slides down the circular arc from A to B is given as follows:

W = mv²/2 - mgh

W = v²/2 - gh

W = 4.8²/2 - 9.81 * 1.6

W = -4.176

In conclusion, the work done by friction is lost in the form of heat.

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43.DB(decibels)

⇉ Unit conversion

4.3(bels)

4.951NP

4.3(decades)

14.28(octaves)

Interpretations

⇉ Power quantity level

Basic unit dimensions

⇉ ( logarithmic quantity ).

They provided the intensity in decibels for the problem, but they are unsure by what factor to increase it (I) to make the sound loud enough for the elderly person to hear.

Neglect f entirely.

The following equation must be used to convert decibels (dB) to I:

I=(10^(dB/10))*10^-12

Divide the elder person's dB by the younger person's dB after doing this for each dB.

1.8372093023.

Decibels are used to measure sound (dB). A motorcycle engine operating is roughly 95 dB louder than regular conversation, which is around 60 dB louder than a whisper. Your hearing may begin to be harmed if exposed to noise over 70 dB for an extended period of time. Your ears can suffer instant damage from loud noise above 120 dB.

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The rate at which the person is now losing thermal energy is 99 J/s.

The thickness of the person's skin is calculated as follows;

Q = k(ΔT)h

where;

h = Q/k(ΔT)

h = (120) / (0.22 x 303)

h = 1.8 m

Q = k(ΔT)h

where;

Q = (0.18)(306)(1.8)

Q = 99 J/s

Thus, the rate at which the person is now losing thermal energy is 99 J/s.

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The answers are :

(a) 23π/90 radians ≈ 0.803 radians

(b) 17/2π revolutions ≈ 2.706 revolutions

(c) 79.5/60 rad/s = 13.25 rad/s

*The important formulas to remember*

     [tex]\boxed {Radian = Degree \times \frac{\pi}{180^{o}}}[/tex]

    2. Radians to Revolutions

     [tex]\boxed {Revolution = \frac{Radian}{2\pi}}[/tex]

    3. rpm to rad/s

     [tex]\boxed {rad/s = \frac{rpm}{60}}[/tex]

The information is missing here but data that may support the existence of life in an exoplanet may include the discovery of atmospheric biological gases.

An exoplanet is any planet that surrounds another star beyond the sun, and therefore they are discovered by analyzing other galaxies in the Universe.

The existence of life in these exoplanets can be indirectly supported by the presence of gases that are only produced by organisms, which are detected by suitable telescopes that analyze emission spectra.

In conclusion, the information is missing here but data that may support the existence of life in an exoplanet include biological gases.

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The object that ends up with less electrons has a positive charge; option A.

Electrons are negatively charged particles which form a part of the three fundamental particles in an atom.

Electrons can easily be removed from the vicinity of atoms making the atom to become positively charged. On the other hand, when atoms gain extra electrons, they become negatively-charged.

On way of charging objects is by rubbing them against other objects in order to gain extra electrons or to lose electrons.

When two objects are rubbed together, the object that ends up with less electrons has a positive charge, whereas the object that ends up with more electrons has a negative charge.

In conclusion, objects can become charged when they are rubbed against each other, and they can either become negatively or positively-charged by gain or loss of electrons.

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The object indicated here that ends up with fewer electrons has an unknown charge (not enough info, Option B).

The atomic charge makes reference to the overall charge of an atom, which can be evidenced by knowing its net charge (positive or negative charge).

The net charge of a molecule and/or atom is obtained by calculating the amount of electrically negative electrons (e-) and the number of positive protons.

Neutrons are another type of subatomic particle that have not net charge (neither positive nor negative).

In conclusion, the object indicated here that ends up with fewer electrons has an unknown charge (not enough info, Option B).

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Answer:

Density of a substance is the ratio of mass of the substance to its volume.

Answer:

Density of a substance is the ratio of mass of the substance to its volume.

Explanation:

first rule of parallel circuits : the voltage is the same in the whole circuit, no matter where we measure.

so, we have 1.5V at every bulb.

second rule of parallel circuits : the total current is the sum of the individual branch currents.

so, if the battery really allows it, then we have 3 times 0.4 A = 3×0.4 = 1.2 A as current in the circuit.

(a) The position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

(b) The size of the image is 1.8.

The position of the coin placed next to the convex side of a thin spherical glass shell is calculated as follows;

1/d = 1/f - 1/d'

where;

Focal length = r/2 = 17 cm / 2 = 8.5 cm

1/d = 1/8.5 - (-1/6.5)

1/d = 1/8.5 + 1/6.5

1/d = 0.1176 + 0.1538

1/d = 0.2714

d = 1/0.2714

d = 3.68 cm

Magnification, M = d'/d

M = (6.5)/(3.68)

M = 1.8

Thus, the position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

The size of the image is 1.8.

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The energy that it needs to reach the maximum speed is 7583.4 Cal

In Physics, we know that the work done is the product of the force and the distance moved. However, work can be converted to energy since the both have the same dimensions. We define energy in physics as the ability or the capacity to do work.

Given these information, we know that the work done in moving the cheetah as it accelerates from the bottom to the top of the mountain is equal to the kinetic energy of the cheetah thus we can write;

W = KE = 1/2 mv^2

W= 0.5 * 62.0-kg * ( 32.0 m/s)^2

W = 31744 J

Given that;

1 calories = 4.186 J

x calories = 31744 J

x = 7583.4 Cal

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The energy needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3 will be 1.93 *10^-18J and 12.09 eV.

The following can be deduced:

Energy of electron in hydrogen atom is

En = -13.6 /n2 eV

where n is principal quantum number of orbit.

Energy of electron in first orbit = E1 = -13.6 / 12 = - 13.6eV

Energy of electron in third orbit = E3 = -13.6 /32 = -1.51 eV

Energy required to move an electron fromfirst to thirdorbit ΔE = E3- E1

ΔE = -1.51 - ( 13.6) = 12.09 eV

Energy in Joule = 12.09 *l/× 1.6 × 10^-19 = 1.93 × 10^-18 J.

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Complete question:

How much energy is needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3? Give theanswer (a) in joules and (b) in eV.