Scalar: Temperature, mass, distance, time, speed, volume, area, voltage, current, resistance, work, density, energy, amount of substance, luminous intensity, area density, chemical potential, electric current density, capacitance, inductance.
Vector: Displacement, velocity, acceleration, force, position, eletric field, magnetic field, linear momentum, angular momentum, torque, angular velocity, angular acceleration, electric field density, magnetic field density, roll, pitch, yaw, surge, sway, heave.
projectile motion lab work i need report
The Projectile Motion Lab is focused on a different type of projectile motion - that of a non-horizontally launched projectile.
What is Projectile Motion LabThe goal of this experiment is to accurately estimate and measure the range and time-of-flight of an angled projectile. Finding the ball's initial speed (muzzle velocity) is necessary before estimating the projectile's range when it is fired off a table at an angle other than horizontal. The projectile motion highlights the important fact that even constant acceleration, which is essentially unidirectional, can produce two-dimensional motion. The primary cause is that the object's initial velocity and force are not in the same direction.To learn more about Projectile Motion Lab refer :
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The deflection of a 160-cm-long beam in bending will be _____ times the deflection of an equivalent 120-cm-long beam.1.330.560.751.782.370.42
Given data
*The deflection of the length of the beam in bending is 160 cm
*The equivalent length of the beam is 120 cm
The deflection of a 160-cm-long beam in bending is calculated as
[tex]\begin{gathered} l=\frac{160}{120} \\ =1.33 \end{gathered}[/tex]Hence, the deflection of a 160-cm-long beam in bending will be 1.33 times the deflection of an equivalent 120-cm-long beam
a car is speeding down your street at a constant rate of 45 meters per second what is the net force acting on the car?
There is no acceleration if the velocity remains constant. In other words, the acceleration value is 0.
Why does a car accelerate while moving at constant velocity but not when moving at constant speed?The rate at which an object's velocity (speed and direction) varies is known as acceleration. Therefore, even though an object's speed is constant, it can accelerate if its direction does.
The automobile presses on your back as it accelerates you as it speeds up. Your body has a forward inertia (tendency to continue travelling at the same speed) that causes you to continue moving until the force of your seat belt causes you to slow down at the same pace as the vehicle.
In both the horizontal and vertical axes, the net force acting on the car must be zero. However, a constant force is required to keep it travelling at a constant speed, hence the net force vertically must be zero.
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Converting the number0.700 to Scientific Notation7.00 x 10-17.00 x 101O 7x 1010 7x10-1
Explanation
Step 1
Place a decimal by counting the steps to the left until the coefficient of the number is between 1 and 9.
so
[tex]0.700\rightarrow move\text{ the decimal place 1 position 7.000}[/tex]Step 2
Count the number of steps moved. This will be the power of the base 10.
Moving the decimal point to the right gives a negative exponent, whereas moving the decimal point to the left makes a positive exponent.
1 place to the rigth so the exponent is -1
Step 3
In this case, the coefficient is 7 and the 1 steps are moved
so, Multiply the coeeffcient by 10 exp(1), the (1) we got from the previous step
so, the number is scientific notation is
[tex]\begin{gathered} 0.700\rightarrow7\cdot10^{-1} \\ 7\cdot10^{-1} \end{gathered}[/tex]I hope this helps you
A 75W outdoor lamp is connected to 240V source and left to turn on continuously for an average 14 hours per day. Determine:i) the current through the lamp when it is in operation.ii) the cost of operating the light for one year (365 days) if electricity costs in Malaysia is RM0.22 per kWh
We are given that a 75W lamp is connected to a 24V source. To determine the current passing through the lamp we will use the following formula:
[tex]P=VI[/tex]Where:
[tex]\begin{gathered} P=\text{ electric power} \\ V=\text{ voltage} \\ I=\text{ current} \end{gathered}[/tex]Now we plug in the given values:
[tex]75W=(240V)I[/tex]Now we divide both sides by 240 to solve for "I":
[tex]\frac{75W}{240V}=I[/tex]Solving the operation we get:
[tex]0.31A=I[/tex]Therefore, the current passing is 0.31 Ampere.
Now we will calculate the cost of operating the lamp for one year. To do that we will calculate first the number of hours the lamp will be connected for the year. Since the lamp is connected 14 hours a day, this means that in 365 days the number of hours is:
[tex]14\frac{hours}{day}\times365day=5110hours[/tex]Now we determine the kWh. To do that we will multiply the number of hours by the electrical power and we will divide the result by 1000 to convert the W into kW. We get:
[tex]75W\times\frac{1kW}{1000W}\times5110h=383.25kWh[/tex]Now we determine the cost by multiplying the kWh of the lamp by the cost per kWh:
[tex]0.22\frac{RM}{kWh}\times383.25kWh=84.32RM[/tex]Therefore, the cost of operating the lamp for a year is 84.32 RM:
Why can your contact with both very hot and very cold objects cause skin burns?
Contact with very cold objects cause skin burns because skin cells freeze, forming sharp ice crystals that can damage the skin cell structure.
contact with very hot objects cause skin burns because there are tissue damage that results from heat exposure to the skin.
What is the skin?The h skin is the outer covering of the body and is the largest organ of the integumentary system.
The skin also serves as a protective shield against heat, light, injury, and infection.
There are symptoms associated with damage or burn to the skin, which includes;
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A particle’s position along the x-axis is described byx(t) = A t + B t2,where t is in seconds, x is in meters, and the constants A and B are given below.Randomized VariablesA = -3.15 m/sB = 2.4 m/s21 what is the position of the particle when the velocity is zero.
Given data:
Position of the particle along the x-axis;
[tex]x(t)=At+Bt^2[/tex]Here, A and B are constants with A=-3.15 m/s and B=2.4 m/s².
Therefore,
[tex]x(t)=-3.15t+2.4t^2[/tex]The velocity of the particle is given as,
[tex]v(t)=\frac{dx(t)}{dt}[/tex]Substituting x(t),
[tex]\begin{gathered} v(t)=\frac{d}{dt}(-3.15t+2.4t^2) \\ =\frac{d}{dt}(-3.15t)+\frac{d}{dt}(2.4t^2) \\ =-3.15+2\times2.4t \\ =-3.15+4.8t \end{gathered}[/tex]The time when the velocity will be zero is calculated by substituting v(t)=0 in the above expresion,
[tex]\begin{gathered} 0=-3.15+4.8t \\ 4.8t=3.15 \\ t=\frac{3.15}{4.8} \\ \approx0.66\text{ s} \end{gathered}[/tex]Therefore, the position of the particle when the velocity is zero is calculated by substituting t=0.66 s in the equation for the position of the particle,
[tex]\begin{gathered} x(0.66\text{ s})=-3.15\times0.66+2.4\times(0.66)^2 \\ \approx-1.03\text{ m} \end{gathered}[/tex]Therefore, the position of the particle when the velocity is zero is -1.03 m (1.03 m to the left of its initial position).
The dust in a molecular cloud emits at maximum intensity at a wavelength of 101 µm. What is the temperature of the cloud (in K)?
The temperature of the cloud is mathematically given as
T = 28.683k
This is further explained below.
. What is the temperature of the cloud in K?Generally, using wiens law to calculate the temperature the equation is mathematically given as
T = b/landa* m
where b = 2.897 x 10^-3
T = 2.897*10^-3/101 x 10^-6
T = 28.683k
In conclusion, The interstellar medium often consists of dust as its typical minor component. It is usually considered that its dynamic involvement in the contraction of the diffuse gas into molecular clouds plays no significant role at all because of the tiny mass fraction, which is f less than 0.01.
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5. The graphs above show the magnitude F of a force exerted on an object as a function of the object's position xfor two trials in an experiment. W, and W, are the work done on the object by force 1 and force 2, respectively.How do w, and W2 compare, and why?(A) W, > W2, because the maximum value of force 1 is greater than the maximum value of force 2.(B) W, > Wą, because the slope of force 1's graph increases, while the slope of force 2's graph decreases.(C) W,
We are given the graphs of two forces F1 and F2.
Notice that the graph of force 1 is increasing whereas the graph of the force 2 is decreasing.
This means that the slope of force 1 is increasing and the slope of force 2 is decreasing.
So, the work done by force 1 is greater than the work done by force 2.
Therefore, the correct answer is option B.
W1 > W2, because the slope of force 1's graph increases, while the slope of force 2's graph decreases.
An airplane flies on a level path. There is a pressure difference of 587 Pa between the lower and upper surfaces of the wings. The area of each wing surface is about 100 m2. The air moves below the wings at a speed of 80.5 m/s. Estimate the weight of the plane.
ANSWER:
117400 N
STEP-BY-STEP EXPLANATION:
Given:
Pressure difference = 587 Pa
Surface area of the wing = 100 m^2
Speed of the sir below the wing = 80.5 m/s
The weight of the plane is the force due to the pressure difference of upper and lower side of both wings. Therefore:
[tex]\begin{gathered} F=\Delta P\cdot2A \\ F=587\cdot2\cdot100 \\ F=117400\text{ N} \end{gathered}[/tex]The weight is a force of 117400 N.
Electric potential differences are measured in amperes.Question 19 options:TrueFalse
The change in potential energy between two positions when work is done on a charge is called the electric potential difference.
Electric potential difference is measured in joules per coulomb or volt.
Whereas ampere is the unit of current.
Therefore, we can conclude that the given statement is false.
calculate the work done by gravity as a 3.9 kg object is movies from point A to point B , in figure along paths 1,2 and 3
Answer:
-76.44 J
Explanation:
The force due to gravity is conservative, it means that no matter the path, the work done from A to B will be always the same and it depends on the vertical distance between A and B which in this case is 2.0 m.
So, the work done by the gravity is
W = Fdcosθ
Where the force is the weight so, F = mg = (3.9 kg)(9.8 m/s²) = 38.22 N
d is the vertical distance, so , d = 2.0 m
And θ is the angle between the displacement and the weight, so, θ = 180
Then,
W = (38.22N)(2.0 m)cos(180)
W = -76.44 J
Therefore, the work done by gravity along paths 1, 2, and 3 was -76.44 J
A 100 watt lamp has a resistance of 120 Ω. Find the current in the lamp.Group of answer choices2.15 A1.20 A0.913 A0.833 A
0.913 A
Explanation
the poweris given by
[tex]P=I^2R[/tex]so
Step 1
Let
[tex]\begin{gathered} I=I \\ P=100\text{ watts} \\ \text{resistance}=120\text{ ohm} \end{gathered}[/tex]b) now replace
[tex]\begin{gathered} P=I^2R \\ 100=I^2\cdot120 \\ \text{divide boths sides by 120} \\ \frac{100}{120}=\frac{I^2\cdot120}{120} \\ 0.8333=I^2 \\ \text{square root in both sides} \\ \sqrt{0.8333}=\sqrt{I^2} \\ 0.91287=I \\ \text{rounded} \\ I=0.913\text{ Amperes} \end{gathered}[/tex]therefore, the answeris
0.913 A
I hope this helps you
In a classroom, who is a receiver of messages?
A mover pushes a 20 kg crate across a level floor with a force of 200 N, but the crate accelerates at a rate of only 7.5 m/s2 because a friction force opposes the crate's motion. What is the magnitude of this force of friction?Force of FrictionA. 50 NB.100 NC. 15 ND. 25 N
ANSWER
[tex]A\text{.}50N[/tex]EXPLANATION
Parameters given:
Mass of crate, m = 20 kg
Force of push, F = 200 N
Acceleration of crate, a = 7.5 m/s²
To find the force of friction, we have to apply the net force acting on a body. The sum of all forces acting on the crate is equal to the product of its mass and its acceleration.
Therefore, we have:
[tex]F_{\text{net}}=F-F_f[/tex]where Ff = force of friction
Therefore, we have that:
[tex]\begin{gathered} m\cdot a=200-F_f \\ 20\cdot7.5=200-F_f \\ 150=200-F_f \\ \Rightarrow F_f=200-150 \\ F_f=50N \end{gathered}[/tex]That is the force of friction. (Option A)
A 1200-kg car accelerates from rest to 20.5 m/s in 4.50 s. What is the average power delivered by the engine? Use the work-energy theorem to calculate for the work (in terms of kilojoules [kJ]). Show your complete solutions.
Answer:
Explanation:
Given:
m = 1200 kg
V₀ = 0 m/c
V = 20.5 m/s
t = 4.50 s
____________
N - ?
1)
Car acceleration:
a = (V - V₀) / t = (20.5 - 0) / 4.50 ≈ 4.56 m/s²
2)
Vehicle traction force:
F = m·a = 1200·4.56 ≈ 5 470 N
3)
Vehicle speed:
V = V₀ + a·t = 0 + 4.56·4.50 ≈ 20.5 m/s
4)
Average vehicle speed:
N = F·V / 2 = 5 470·20.5 / 2 ≈ 56 000 W
What is the energy of a baby who weighs 20 N sitting in a high chair 1.5 m high?
The gravitational potential energy of a baby with a weight of 20N and 1.5m from the ground is 30 Joules.
What is the energy of the baby?The gravitational potential energy is equal to the weight of a body multiply by its height from ground level.
It is expressed as;
U = mgh
Where m and g are the mass and acceleration due to gravity, which is also called weight, h is the height from the ground level.
Given the data in the question;
Weight of the baby mg = 20NHeight h = 1.5mGravitational potential energy U = ?Plug the given values into the formula and solve for U.
U = mg × h
U = 20N × 1.5
U = 30Nm
U = 30 Joules.
Therefore, the gravitational potential energy is 30 Joules.
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What would happen to the orbits of the planets if the amount of gravity produced bythe Sun were reduced to almost zero?A. The planets would abandon their orbit and move out into space.B. The planets would start crashing into each other.C. The planets would orbit as usual.
Given:
The amount of gravity produced by the Sun was reduced to almost zero.
To find:
What would happen to the orbits of the planets
Explanation:
The centripetal force for the rotation of every planet is supplied by the gravitational force between the sun and the planet. If the gravitational force by the sum becomes zero, the planets would begin moving away from their usual path into space.
Hence, the planets would abandon their orbit and move out into space.
What type of evidence do you think would be most difficult to collect? Why?
Answer: I think the evidence that would be most difficult to record and find would be trace evidence.
Explanation: I think trace evidence is the hardest type of evidence to collect. Trace evidence would be most difficult to collect because they are often small evidence like blood or hair.
If a piece of paper is cut in half, it will become two pieces of paper that are each half the size of the original piece. If one of the half-pieces is cut in half again, it will become two pieces of paper that are each one quarter the size of the original piece
If the piece of paper is cut in half over and over again, will there ever be a point at which it is no longer paper? Explain your answer.
No, cutting paper is a physical alternative. which means that it's far nonetheless paper irrespective of how many times you narrow it.
Upon infinite cutting, we reach its atom, which further can not be broken but at this point, it will not be called paper any longer.
An atom is a particle of remember that uniquely defines a chemical element. An atom includes a central nucleus that is surrounded by way of one or greater negatively charged electrons. The nucleus is undoubtedly charged and consists of one or greater pretty heavy debris called protons and neutrons.
Atoms encompass 3 essential types of debris, protons, electrons and neutrons. Neutrons and protons have about equal mass and in the assessment of this, the mass of an electron is negligible. A proton includes a fantastic price, a neutron has no price and an electron is negatively charged.
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calculate the pressure exterted by liquid having a density of 13600 kg/m3 and a depth of 12 meter.
The density of the liquid is,
[tex]d=13600kg/m^3[/tex]The depth is,
[tex]h=12\text{ m}[/tex]The pressure at any depth for a liquid is given by,
[tex]P=\text{hdg}[/tex]Substituting the values we get,
[tex]\begin{gathered} P=12\times13600\times9.8 \\ =1.599\times10^6N/m^2 \end{gathered}[/tex]The required pressure at that depth is,
[tex]1.599\times10^6N/m^2[/tex]A student tries to unscrew a bolt with a spanner with 25 cm long. Thelargest force that he is able to apply is 100 N, while the minimummoment required to unscrew the nut is 30 N m. Can he unscrew the nut?
ANSWER
No, he cannot
EXPLANATION
First, let us draw a sketch of the problem:
For him to be able to unscrew the nut, the moment of the largest force he can apply must be greater than the minimum moment required to unscrew the nut.
To find the moment of the force, we apply the formula:
[tex]M=F\cdot d[/tex]where F = force applied = 100 N;
d = distance between effort and bolt i.e. the length of the spanner = 25 cm = 0.25 m
Therefore, we have that the moment of the force is:
[tex]\begin{gathered} M=100\cdot0.25 \\ M=25Nm \end{gathered}[/tex]Since the largest moment is 25Nm, and the minimum moment required to unscrew the nut is 30Nm, he cannot unscrew the nut.
The answer is NO.
How does the Coulomb force affect charge interactions?A.Like and opposite charges attract.B.Like charges repel, and opposite charges attract.C.Like and opposite charges repel.D.Like charges attract, and opposite charges repel.
B. Like charges repel, and opposite charges attract.
Given Data:
Let us consider two e
As the swings ride hits top speed, what applies centripetal force to keep the riders traveling in a circle?
a the chains holding the seats on the ride
b the people themselves
c nothing
d the seat
As the swings ride hits top speed, the force that applies to the centripetal force to keep the riders traveling in a circle is option A: the chains holding the seats on the ride.
Which provides the centripetal force in a rotating swing carnival ride?The centripetal force is the resultant force because the swings move in a circle. The centripetal force is seen aa the force that keeps the rider in a circle and the horizontal component of the tension force that is said to be produced by the total of the forces acting along the x-axis.
Therefore, Moving objects are continuously forced to shift their path toward the center of rotation by centripetal force, which stops them from escaping a curve.
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Which of the following most directly limits the number of organisms in a community?
A. Amount of available shelter
B. Wind
C. Hours of daylight/day
D. UV radiation
The following most directly limiting the number of organisms in a community is the amount of available shelter. Option A.
Examples of limiting factors are biological in nature such as competition with other organisms for food mates and resources. Others are abiotic such as space temperature altitude and the amount of sunlight available in the environment. Limiting factors are usually expressed as a lack of a particular resource.
Limiting factors are resources or other factors in the environment that can limit population growth. The limiting factors are the lack of food supplies and the lack of space. Competition for resources such as food and space will stop the rate of increase and the population will plateau. Immigration is the permanent immigration of some individuals coming into an existing population from outside.
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Question 2 of 25Which of the following is an SI unit of measurement?OA. LiterOB. YardOC. QuartOD. Gallon
Given:
Some units are given
To find:
The unit of measurement
Explanation:
Liter, Quart, and Gallon are the units of measurement of the volume of a fluid.
The Yard is the unit of the measurement of length.
The SI unit of measurement is Liter.
in which ecosystem would a lion hunt a zebra? freshwater
savanna
desert
Answer:
Savanna
Explanation:
lions are in Africa right? Hot deserty climat so the answer would be Savanna.
Answer:
Savanna
Explanation:
Lions are predators in African savanna. They hunt on large herbivore populations of buffalos, impalas, zebras, and even elephants and giraffes.
How does Newton's second law affect a seat-belted vs. an unseat-belted passenger in an automobile that is involved in a car crash (before the crash, during the crash, and immediately after the crash).
According to Newton's Second Law, acceleration increases as force does. The acceleration decreases with increasing mass.
Newton's Second LawSeat belts are related to Newton's Second Law since it asserts that larger forces result in greater acceleration, whereas bigger masses result in less acceleration. It goes without saying that a seat belt prevents you from accelerating. If you were in a car accident and were hit hard, you would accelerate more quickly, but the seat belt would prevent you from doing so. Have you ever heard the belief that if a tissue box is on a car's back dashboard, it will suddenly stop? The tissue box, which might pierce a person's head, flew from the back dashboard forward and toward the front of the vehicle.To learn more about Newton's Second Law refer :
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The Moon has a mass of 7.35 × 1022 kg and a radius of 1.74 × 106 m. It orbits around the Earth at a distance of 3.84 × 108 m, completing a full rotation every 27.3 days. It also spins on its axis at a speed such that the same side of the moon is always facing the Earth. calculate the angular momentum of the moon in its orbit around the earth, b,calculate the angular momentum of the moon in its rotation around its axis, c,how many times larger is the angular momentum than the rotational angular momentum for the moon?
Givens.
• Mass of the Moon = 7.35x10^22 kg.
,• The radius of the orbit = 3.84x10^8 m.
First, find the tangential velocity.
[tex]v=\frac{2\pi r}{T}=\frac{2\pi\cdot3.84\times10^8m}{2.36\times10^6s}=1022.35\cdot\frac{m}{s}[/tex]Observe that we use the period in seconds, not in days. The transformation we performed is
[tex]T=27.3\text{days}\cdot\frac{86400\sec}{1day}=2.36\times10^6\sec [/tex]Once we have the tangential velocity, we can find the angular momentum of the Moon around the Earth.
[tex]\begin{gathered} L=mvr=7.35\times10^{22}\operatorname{kg}\cdot1022.35\cdot\frac{m}{s}\cdot3.84\times10^8m \\ L=2.9\times10^{34}\operatorname{kg}\cdot\frac{m^2}{s} \end{gathered}[/tex]Therefore, the angular momentum around the Earth is 2.9x10^34.
The angular momentum of the moon can be found using the following formula.
[tex]L=I\cdot w[/tex]Where I is the moment of inertia of the moon and w is the angular velocity.
The moment of inertia of a spherical solid is
[tex]I=\frac{2}{5}mr^2[/tex]The mass of the moon is 7.35 × 10^22 kg and its radius is 1.74 × 10^6 m. So, the inertia is
[tex]\begin{gathered} I=\frac{2}{5}\cdot7.35\times10^{22}\operatorname{kg}\cdot(1.74\times10^6m)^2 \\ I=8.9\times10^{34}\operatorname{kg}\cdot m^2 \end{gathered}[/tex]Using its angular velocity of 2.7x10^-6 rad/s, we find its angular momentum.
[tex]\begin{gathered} L=2.7\times10^{-6}rad/s\cdot8.9\times10^{34}\operatorname{kg}\cdot m^2 \\ L=2.4\times10^{29}\operatorname{kg}\cdot\frac{m^2}{s^{}} \end{gathered}[/tex]The angular momentum of the moon onto itself is 2.4x10^29.
At last, divide both momentums to compare them.
[tex]\frac{L_{\text{earth}}}{L_{\text{moon}}}=\frac{2.9\times10^{34}\operatorname{kg}\cdot\frac{m^2}{s}}{2.4\times10^{29}\operatorname{kg}\cdot\frac{m^2}{s^{}}}=1.2\times10^5[/tex]Therefore, the angular momentum around the Earth is 1.2x10^5 times greater than the angular momentum of the Moon onto itself.
Q5. Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), will it ever swing higher than it's starting point? Explain your answer in terms of kinetic and potential energy.
Unless you push a pendulum at the start of it's swing (doing work to give it extra energy), it will never swing higher than it's starting point.
In a pendulum, the total energy of the system always remains constant.
Total energy = Potential Energy + Kinetic Energy
When a bob of a pendulum is raised to hang in the string it gains potential energy because work is done to raise the bob. In a pendulum motion, at the starting point potential energy is at its maximum, meaning kinetic energy is zero.
As it starts to swing the potential energy is converted into kinetic energy. So potential energy decreases and kinetic energy increases. At the lowest point of the swing the kinetic energy is maximum and potential energy is zero. As the motion continues when it reaches the top most point potential energy will be maximum and Kinetic energy will be zero again. Throughout the entire motion total energy remains constant. Only when you push it initially, it will gain extra energy to go higher than the starting point.
Therefore, unless you push a pendulum at the start of it's swing (doing work to give it extra energy), it will never swing higher than it's starting point.
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