Show how to synthesize each of the following using allylic bromination by NBS.

Your answer is partially correct. Try again.
Using the reagents below, list in order (by letter, no period) those necessary to prepare compound A from 2-methylpropene. Note: Not all spaces provided may be needed. Type "na" in any space where you have no reagent.
a. Br₂
b. HBr
c. NaOH
d. NBS, light
e. H₂O, H₂504
f. EtOH
g. Na Me, MeOH

It is helpful to paddle a boat downstream with the flow of water.

The downstream motion means that the boat and the river are going in the same direction. So, the speed of the boat will always be greater than the speed of the river as the speed of river will add up to that of the boat. The velocity of the boat as seen from the banks or the formula of downstream boating = ( u + v ) km/hr. and this is what we call as the relative velocity of the boat with respect to the river bank.

Motion of a boat a waterbody towards the direction of waterflow is called downstream motion.

Velocity of a body with respect to another body or reference is called relative velocity.

When speed of a body is defined along with direction, it is velocity.

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The smallest component of a chemical that can't be chemically broken down to produce static electricity has 18.06 10–23 atoms in each of its elements, which is 4Al2O3.

Protons, electrons, and neutrons are the three fundamental type of particles found in atoms. In contrast, the mass of the electron is extremely little compared to that of neutrons and protons. A neutrons has no charge, a proton has a positive charge, and an electron has a negative charge.

After the Big Big 13.7 billion years ago, atoms began to form. Conditions for the formation of quarks and electrons improved when the scorching, dense new universe cooled. Protons and neutrons were created when quarks joined to form nuclei from these particles.

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Stagnation pressure upstream  is [tex]{Po_{1}=17.085\: atm[/tex],Mach number downstream is [tex]Ma_{2}=0.5[/tex] ,Static pressure downstream is  [tex]P_{2} =7.31\:atm[/tex]Static pressure downstream  is [tex]Po_{2} =8.67\:atm[/tex] Stagnation temperature downstream is  [tex]{To_{2} } =673.29K[/tex]

Stagnation pressure in fluid dynamics is the static pressure at a point where a fluid flow has stopped. A stagnation point has zero fluid velocity. Stalling pressure in an incompressible flow is the same as the total of free-stream static pressure and free-stream dynamic pressure. The fluid density is higher at the stagnation point than at the static point in compressible flow, though. The stagnation enthalpy or stagnation temperature in compressible flow serves many of the same functions as the stagnation pressure in incompressible flow.

The relation for normal shock will be used to find the [tex]M_{2} ,Po_{1} ,P_{2} ,Po_{2}, and\:\: To_{2}[/tex]

[tex]Ma_{2} =\frac{Ma_{1} ^{2}+\frac{2}{r} -1 }{2Ma_{1} ^{2}+\frac{r}{r-1} -1 }[/tex]

Working gas is air and helium

for air , r=1.4 for we r=[tex]\frac{5}{3}[/tex]

[tex]\frac{Po_{1}}{P_{1}} =[1+\frac{r}{r-1} Ma_{1} ^2]^\frac{r}{r-1}[/tex]

[tex]P_{1}=1 atm[/tex]

[tex]\frac{Po_{1}}{P_{1}} =[1+\frac{0.4}{2} (2.5)^2]^\frac{1.4}{0.4}[/tex]

[tex]{Po_{1}=17.085\: atm[/tex]

[tex]Ma_{2}^2 =\frac{Ma_{1} ^{2}+\frac{2}{r} -1 }{2Ma_{1} ^{2}+\frac{r}{r-1} -1 }[/tex]

[tex]Ma_{2}^2 =\frac{2.5 ^{2}+\frac{2}{1.4} -1 }{2\times2.5 ^{2}+\frac{1.4}{1.4-1} -1 }[/tex]

[tex]Ma_{2}^2=\frac{2.5^2+0.2}{21.857-1}[/tex]

[tex]Ma_{2}=0.5[/tex]

[tex]\frac{P_{2} }{P_{1} } =\frac{Ma_{1} \sqrt{1+Ma_1^2\frac{(r+1)}{2} }}{Ma_{2}\sqrt{1+Ma_2^2\frac{(r+1)}{2} }}[/tex]

[tex]\frac{P_{2} }{P_{1} } =\frac{2.5 \sqrt{1+2.5^2\frac{(0.4)}{2} }}{0.5 \sqrt{1+0.5^2\frac{(0.4)}{2} }}[/tex]

[tex]P_{2} =7.31\:atm[/tex]

[tex]\frac{Po_{2} }{P_{1} } ={(1+ {\frac{(r-1)}{2} Ma_{2}^2 })^\frac{r}{r-1}[/tex]

[tex]\frac{Po_{2} }{7.31 } ={(1+ {\frac{(1.4-1)}{2} 0.5^2 })^\frac{1.4}{0.4}[/tex]

[tex]Po_{2} =8.67\:atm[/tex]

[tex]\frac{To_{2} }{T_{2} } ={(1+ {\frac{(r-1)}{2} Ma_{2}^2 })^\frac{r}{r-1}[/tex]

[tex]\frac{To_{2} }{T_{2} } =(\frac{Po_{2} }{P_{1} })^2(\frac{Ma_{2} }{Ma_{1} })^2[/tex]

[tex]{T_{2} } =300\times(\frac{7.31 }{1 })^2(\frac{0.5}{2.5 })^2[/tex]

[tex]{T_{2} } =641.23K[/tex]

[tex]{To_{2} } =641.23K(1+\frac{0.4}{2}(0.5)^2)[/tex]

[tex]{To_{2} } =673.29K[/tex].

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Question: A stationary normal shock has the following conditions upstream: static pressure P1 = 1 atm, static temperature T1 = 300 K, and Mach number M1 = 2.5. For each of the cases below determine the following variables (in the units indicated):

(i) The stagnation pressure upstream, P01 [atm],

(ii) The Mach number downstream, M2,

(iii) The static pressure downstream, P2 [atm],

(iv) The stagnation pressure downstream, P02 [atm],

(v) The stagnation temperature downstream, T02 [K].

Paul might use the waves  for comparison in order to determine the motion of the other boat.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

The velocity of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's relative location changes in relation to another object over time.

By counting waves between the ships, he can determine the motion of the other boat.

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The function fizzle(n) can be calculated using a recursive approach.

Here's how we can calculate fizzle(8):

fizzle(8) = fizzle((8 + 1)/2) + fizzle(8/2) = fizzle(4.5) + fizzle(4)

Since fizzle is not defined for non-integer values, we will use the floor function to round down 4.5 to 4:

fizzle(8) = fizzle(4) + fizzle(4) = fizzle((4 + 1)/2) + fizzle(4/2) + fizzle((4 + 1)/2) + fizzle(4/2) = fizzle(2.5) + fizzle(2) + fizzle(2.5) + fizzle(2)

Again, we will round down 2.5 to 2:

fizzle(8) = fizzle(2) + fizzle(2) + fizzle(2) + fizzle(2) = fizzle((2 + 1)/2) + fizzle(2/2) + fizzle((2 + 1)/2) + fizzle(2/2) + fizzle((2 + 1)/2) + fizzle(2/2) + fizzle((2 + 1)/2) + fizzle(2/2) = fizzle(1.5) + fizzle(1) + fizzle(1.5) + fizzle(1) + fizzle(1.5) + fizzle(1) + fizzle(1.5) + fizzle(1)

Since fizzle is defined for the value of 1, we can finally calculate fizzle(8):

fizzle(8) = fizzle(1) + fizzle(1) + fizzle(1) + fizzle(1) + fizzle(1) + fizzle(1) + fizzle(1) + fizzle(1) = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 8

Therefore, fizzle(8) = 8.

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(a) The spacing Y of the maxima of the screen for light is  5 x 10^-7 m. (b) Yes, we would expect to observe the interference of light. (c) The slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.

(a) The spacing Y of the maxima on the screen can be calculated using the formula for the interference of light from two slits:

=> Y

= L x λ / d

here L is distance from the slits to the screen,

λ is wavelength of the light,

d is distance between the slits.

Putting the values, we have:

=> Y

= 1 m x 500 nm / 1 cm

= 500 nm/cm

= 5 x 10^-7 m

(b) Yes, we would expect to observe the interference of light on the screen for this situation. This is because when light passes through two narrow slits, it creates an interference pattern on the screen that is a result of the constructive and destructive interference of the light waves. This pattern is characterized by bright and dark bands, with the bright bands representing areas of constructive interference and the dark bands representing areas of destructive interference.

(c) To calculate the distance the slits should be placed to observe the maxima separated by 1 mm, we need to rearrange the formula for Y and solve for d:

=> d

= L x λ / Y

= 1 m x 500 nm / 1 mm

= 500 x 10^-9 m

So, the slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.

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To find the deflection of a pointer in a centrifugal force experiment, you need to perform the following steps:

Calculate the force: The magnitude of the centrifugal force can be calculated using the equation F = m * r * w^2, where m is the mass of the pointer, r is the distance from the axis of rotation, and w is the angular velocity. The deflection of the pointer is proportional to the centrifugal force, so you can use the measurement of the deflection to estimate the force.

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For the given charge the magnitude of electric field at 1 m is  4 times the electric field at 2 m.

Electric charge can create magnetic field as well electric fields.

According to the given question a charge is given and we need to find electric field at 2 different positions that is at 1 m and 2 m.

Electric field at 1 m is E1   E1 = Kq/r₁²

E1 = Kq / 1²

E1 = Kq -------- 1

Electric field at 2 m is E2 , E2 = Kq/ r₂²

E2 = Kq / 2²

E2 = Kq / 4 ---------- 2

After comparing E1 and E2 from the above equation 1 and 2

E1 = 4 E2

Thus electric field at 1 m is  4 times the electric field at 2 m.

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The above question is incomplete. Check complete question below:

The magnitude of the electric field 1 m away from the positive charge is _________ the magnitude of the electric field 2 m away .

1. equal to

2. one-quarter

3. four times

4. two times

5. one-half

The output of this linear time-invariant system is a weighted sum of the inputs from the past and present. The weights applied to each input sample are determined by the impulse response coefficients.

thus modifying the filter's frequency response.

For n = -1, 0, and 1,

the indicated impulse response represents a discrete-time linear filter with an impulse response of

h(n) = 0.5(-1)n.

The filter has a symmetric response with alternating positive and negative coefficients, 0.5 and -0.5, and is finite in length. When a certain input signal is used to drive the filter, the impulse response can be used to determine the filter's output

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a) The ratio of the sailing speed v s to the non-sailing speed v ns is calculated to be 3.712.

b) In terms of 1/v s, the difference in the times the insects take to travel the first 2.0 m along the path with and without sailing is 5.41/v s.

a) We know that, v ∝ 1/t

where, v is velocity

t is time

v s is the sailing speed

v ns is non sailing speed

So, v s /v ns = 24.5/6.6 = 3.712

v ns = 1/3.712 v s = 0.27 v s ---(1)

Given, d = 2 m

We know, t = d/v

t s = 2/v s

t ns = 2/ v ns ----(2)

where, t s time taken for sailing

t ns is the non sailing time

Putting v ns = 0.27 v s in (2),

t ns = 2/(0.27 v s) ---(3)

The difference between t ns and t s is,

t d = t ns - t s

t d = 2/(0.27 v s) - 2/v s

t d = 2/v s (1/0.27 - 1)

t d = 2/v s (3.703 - 1)

t d = (2× 2.703)/v s

t d =  5.41/v s

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A platinum coil turns becomes a superconductor when immersed in liquid helium at a temperature of 4 kelvin.

Energy from the outside is captured by the circulating fluid running through the coils, which then releases it through the interior coils into the building's interior. Superconductors have no electrical resistance as well as perfect diamagnetism. Cooper pairs of electrons are what cause superconductivity. The BCS theory, so named in honour of its three discoverers, describes how materials transform into "superb conductors" when their internal electrons cooperate to form Cooper pairs (or BCS pairs). When cooled to extremely low temperatures (near absolute zero, or roughly -273° Celsius), conductors completely lose all of their electrical resistance.

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Answer:

4.0 x 10^-4 N.

Explanation:

The net force on particle q3 can be calculated by determining the force of each of the other particles on it, and then summing them. The force between two particles is given by Coulomb's Law, which states that the force between two charges is equal to the product of the charges divided by the square of the distance between them.

First, we need to find the force between q1 and q3:

F12 = k*(q1*q3)/(0.447^2)

Next, we need to find the force between q2 and q3:

F23 = k*(q2*q3)/(0.447^2)

The net force on particle q3 can be found by summing the two forces:

F_net = F12 + F23

where k is the Coulomb's constant = 910^9 Nm^2/C^2

Note that the force between q1 and q3 and between q2 and q3 will be in opposite direction as the charges are opposite in nature.

So, the net force on particle q3 = F12 + F23 = (kq1q3)/(0.447^2) + (kq2q3)/(0.447^2)

Now you can substitute the values of q1,q2,q3 and distance to calculate the net force on particle q3.

To calculate the net force on particle q3, we first need to calculate the force between each pair of particles using Coulomb's law:

F = k * |q1 * q2| / r^2

where F is the force, k is the Coulomb constant (8.99 x 10^9 N*m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between the particles.

Between q1 and q2:

F12 = k * |-1.21 uC * -55.0 uC| / (0.447 m)^2 = -1.6 x 10^-4 N

Between q2 and q3:

F23 = k * |-55.0 uC * 148 uC| / (0.447 m)^2 = 5.6 x 10^-4 N

The net force on particle q3 is the vector sum of the forces acting on it. Since the forces acting on q3 are in the same direction, we can simply add them to find the net force:

Fnet = F23 + F12 = 5.6 x 10^-4 N - 1.6 x 10^-4 N = 4.0 x 10^-4 N

So the net force on particle q3 is 4.0 x 10^-4 N.

When we arrange the objects in increasing strength of gravitational attraction, the following results:

To arrange the objects in increasing strength of gravitational attraction, we shall determine the gravitational force between each pair oif the objects. Details below:

For electron-dog:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 9.11×10⁻³¹ × 20) / 1²

F = 1.22×10⁻³⁹ N

For butterfly-rock:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.0×10⁻⁴ × 8) / 1²

F = 2.67×10⁻¹³ N

For electron-butterfly:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 9.11×10⁻³¹ × 5.0×10⁻⁴) / 1²

F = 3.04×10⁻⁴⁴ N

For rock-dog:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 8 × 20) / 1²

F = 1.07×10⁻⁸ N

From the above calculations, we have the gravitational attraction as:

Thus, arranging in increasing order, we have:

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Evaporation and sublimation are the mechanisms through which moisture is introduced to unsaturated air.

Unsaturated air has a relative humidity substantially lower than 100%, while saturated air is thought to have a relative humidity of 100%. The opposite of saturated air is unsaturated air, which contains less water vapour but has a greater capacity to hold it. By changing the temperature, you may switch between the two types of air. Just bring the unsaturated air's temperature down till it becomes saturated. Any air with a moisture content greater than zero is capable of doing that. Liquid water is converted into vapor by evaporation and transpiration, and this vapor rises into the atmosphere as a result of rising air currents.

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Answer: 2

Explanation:

The temperature of the mixture is 23.04°C, if the temperature of ice is 0°C and that of the water is 50°C.

The temperature of the mixture can be calculated using the equation of Heat Transfer:

Q = mcΔT

Where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

c₁ is the heat transfer capacity of water = 4.18 J/°C

c₂ is the heat transfer capacity of ice = 2.09 J/°C

First, calculate the heat transferred from the water to the ice:

Q₁ = mc₁ΔT₁

Q₁ = 300×4.18× (50-T)

Second, calculate the heat absorbed by the ice:

Q₂ = mc₂ΔT₂

Q₂ = 150×2.09×(T - 0)

The total heat transferred is the sum of the heat absorbed by the ice and the heat transferred from the water to the ice:

Q₁ + Q₂ = 0

Solving for T, we find:

T = (Q₁ + Q₂) / (mc₁ + mc₂)

T = [300×4.18× (50-T) + 150×2.09×(T - 0)] / (300 × 4.18 + 150× 2.09)

T = (15037.5 J) / (654.3 J/°C)

T = 23.04°C

Therefore, the temperature of the mixture is approximately 23.04°C.

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This situation is impossible because capacitors are linear components, meaning that the capacitance of a combination of two or more capacitors is not the sum of the individual capacitances.

The capacitance of the combination can be calculated using the equation C = C1 + C2 / (1 + (C1*C2) / C), where C1 and C2 are the individual capacitances.

The capacitance of a combination of capacitors is determined by their individual capacitances and the geometrical arrangement of the capacitors in the circuit. In a capacitive circuit, capacitors are connected in series and/or parallel.

When capacitors are connected in series, the total capacitance is the inverse of the sum of the reciprocals of the individual capacitances. When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances.

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The net charge to be placed on a piece of sulphur is calculated to be -966.4 C.

For us to find out how much charge is being put, we need first to find out how many atoms of sulphur there are. This can be achieved knowing that sulphur has 32.1 u of mass, and each u is 1.66 × 10⁻²⁷. So, there will be,

Atoms = (326 × 10⁻³)/(32.1 × 1.66× 10⁻²⁷) = (326 × 10²⁴)/(53.29) = 6.12 × 10²⁴

We have a total of 6.12 × 10²⁴ atoms. We know that an electron will be added on 1/1012 of these atoms. That is,

⇒ 6.12 × 10²⁴ × 1/1012 = 0.00604 × 10²⁴ = 6.04 × 10²¹ electrons

Multiplying this by the charge of each electron,

Net charge Q = 6.04 × 10²¹ ×(-1.6 × 10⁻¹⁹) = -9.664 × 10² C = -966.4 C

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These clouds typically form between 1,000 and 5,000 feet in the air, while temperature increases frequently follow cloud formation and result in an increase in cloud base height.

These clouds may cause small showers and are relatively created by air rising as a result of surface heating. There are three broad categories for cloud heights: low, moderate, and high. The distance from the ground to the base of a cloud determines its classification. Low clouds typically have bases below 6,500 feet above the ground; intermediate clouds have bases between 6,500 and 20,000 feet; and high clouds have bases at 20,000 feet and above. Depending on the location and temperature, we may state that the distance between the ground and the cloud is approximately 2 to 18 kilometers.

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The roller coaster's highest point is 6.12 metres above the ground.

Kinetic energy is the power a thing possesses as a result of motion. It is equal to the object's mass divided by the square of its velocity, or one-half of the object's mass. At its maximum speed of 50 m/s, the roller coaster car contains 3000j of kinetic energy.

The roller coaster's potential energy is equal to the height above the ground when it is at its highest point. Potential energy is equal to an object's mass times its gravitational acceleration times its height.

As a result, the roller coaster's highest point's separation from the ground is determined by 3000j divided by (50 m/s multiplied by 9.8 m/s2), or 6.12 metres.

Therefore, the roller coaster's highest point is 6.12 metres above the ground.

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A magnetic field is generated by the magnet and flows through any attracting item or substance, such as ferrofluid.

A magnet is a substance or item that generates a magnetic field. This magnetic field is invisible, but it is responsible for a magnet's most remarkable property: a force that attracts or repels other ferromagnetic elements such as iron, steel, nickel, cobalt, and so on. Any substance capable of attracting iron and forming a magnetic field around itself is referred to as a magnet. By the end of the nineteenth century, all known elements and numerous compounds had been investigated for magnetism, and all had been discovered to have some magnetic property. A magnet is a metallic item that attracts ferrous or magnetic objects. Magnetite is an iron ore with magnetic characteristics. North pole: When a magnet is hanging freely, one of its poles always points north.

Here,

The magnet generates a magnetic field, which flows through any attracting object or material, such as ferrofluid.

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The magnitude of the second charge was changed by a factor of √(1/3), or approximately 0.577.

Coulomb's law states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them, and the equation is:

F = k × q1 × q2 / r²

where k is the Coulomb constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

Initially, q1 = q, and q2 = q. The magnitude of the force is 10 N:

10 = k × q² / r²

After the magnitude of the first charge is tripled, the magnitude of the force becomes 5 N:

5 = k × 3q² / r²

Solving for q2, we get:

q2 = √(q² / 3)

q2 = √(1/3)

q2 = 0.577

So the magnitude of the second charge was changed by a factor of √(1/3), or approximately 0.577.

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The time required for the car to accelerate from rest to 70.9 mil/h is: 0.46 s

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

The formula for uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

vf = vi + (a * t)

Where:

Given info:

By converting the final velocity units from (mil/h) to (m/s) we have:

vf= 70.9 mil/h * 1609.34 m/1  * 1 h/3600 s

vf= 31.69 m/s

Applying the final velocity formula, clearing the time, and assuming the cyclist starts from rest we get:

vf = vi + (a * t)

t = (vf – vi) /a

t = (31.69 m/s – 0 m/s) /7 *9.8 m/s²

t = 31.69 m/s/ 68.6 m/s²

t = 0.46 s

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The number of electrons transferred by rubbing the balloon on the head is 34.38 x 10¹⁰

The charge gained by the balloon = 55  x 10⁻⁹C

The number of electrons transferred can be found using the formula,

                 Q = ne

where Q is the charge transferred

           n is the number of electrons

           e is the charge of an electron

Let us rearrange the above equation in order to get the number of electrons,

              n = Q/e

Let us substitute the known values in the above equation, we get

              n = 55 x 10⁻⁹/ 1.6 x 10⁻¹⁹

                  = 34.38 x 10¹⁰

Therefore, the number of electrons is 34.38 x 10¹⁰

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Yes, ice has a higher specific heat than copper.

The specific heat of ice is 2.09 J/g°C, while the specific heat of copper is 0.385 J/g°C. This means that the amount of energy required to raise the temperature of 1 gram of ice by 1 degree Celsius is more than twice the amount of energy required to raise the temperature of 1 gram of copper by 1 degree Celsius.

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The box will have the greatest velocity just before striking the ground when it is dropped without initial velocity (i.e. dropped from rest).

This is because the velocity of a freely falling object under the influence of gravity increases with time, following the equation v = gt, where v is velocity, g is the acceleration due to gravity (9.8 m/s^2 on the Earth's surface), and t is time.

The velocity of the box continues to increase as it falls, reaching its maximum just before it strikes the ground.

If the box is given an initial velocity, for example by being thrown, it will still increase in velocity as it falls, but the maximum velocity will be less than if it was dropped from rest.

The final velocity of the box just before striking the ground will depend on the height from which it was dropped and the time taken to fall.

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Answer: 20

Explanation:

Answer:

3V

Explanation:

We take variable resistance as 4000 ohms as voltages are different as resistors are connected in series. Also, as voltage (V) ∝ resistance (R), higher the voltage, higher the resistance used. When most of the voltage out the provided 12V from the cell is used, we can get the least voltage for the 2000 ohm resistor where the voltmeter is connected.

Adding all the resistors:

R(eq) = R₁ + R₂ + R₃ = 4000 + 2000 + 2000 => 8000Ω

By ohm's law:

I = V/R(eq) = 12/8000 => 0.0015A

Again, by ohm's law:

V = IR₂ = 0.0015A * 2000Ω

∴ V = 3V

Hope this helps!

The average person has a heartbeat are:

a. 11224416 beats.

b.11224416 beats.

c. 11224416 beats.

(a) In a year, the person has 60 minutes * 24 hours/minute * 365 days/year = 525600 minutes.

So in 3.0 years, the person has 3.0 years * 525600 minutes/year = 1576800 minutes.

And the number of beats in that time is 1576800 minutes * 71.2 beats/minute = 11224416 beats.

(b) In 3.00 years, the person has 1576800 minutes, just as in 3.0 years.

And the number of beats in that time is 1576800 minutes * 71.2 beats/minute = 11224416 beats.

(c) In 3.000 years, the person has 1576800 minutes, just as in 3.0 and 3.00 years.

And the number of beats in that time is 1576800 minutes * 71.2 beats/minute = 11224416 beats.

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The electromagnetic force and gravitational force are two of the four fundamental forces of nature. While the electromagnetic force is much stronger than the gravitational force on a small scale, it appears that gravity dominates on larger scales.

The electromagnetic force is strongest between electrically charged particles, while the gravitational force is proportional to the mass of objects. The electromagnetic force is approximately 10^36 times stronger than the gravitational force on the scale of single atoms and molecules. However, on larger scales, the gravitational force begins to dominate.

This is because the electromagnetic force is a long-range force that decreases rapidly with distance, while the gravitational force is a long-range force that decreases more slowly with distance. As a result, the total amount of gravitational force between two large objects like stars or planets is much greater than the total amount of electromagnetic force.

In summary, the electromagnetic force is much stronger than the gravitational force on a small scale, but it is overpowered by gravity on large scales due to the long-range nature of the gravitational force and its relatively slower decrease with distance.

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Answer: Waxing crescent moon

Explanation: The moon phase that comes after the new moon is waxing crescent and before the first quarter.