Utilizando la distribución binomial, la probabilidad de resolver un problema de n problemas propuestos, es p^n.
¿Cuál es la fórmula de distribución binomial?La fórmula es:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Los parámetros son:
x es el número de éxitos.n es el número de intentos.p es la probabilidad de éxito en un solo intento.La probabilidad de que todos los problemas sean resolvidos es dada por P(X = n), asi:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = n) = C_{n,n}.p^{n}.(1-p)^{n-n}[/tex]
P(X = n) = p^n
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Donna has a $300 loan through the bank she is charged a simple rate The total interest she paid on the loan was $63 As a percentage what was the annual interest rate on her loan
The annual interest rate is 21%
How to determine the annual interest rate?The given parameters are
Loan Amount, P = $300
Interest, I = $63
Number of years, T = 1
The annual interest rate is calculated as
I = PRT
Substitute the known values in the above equation
63 = 300 * R * 1
Evaluate the product
300R = 63
Divide through by 300
R = 21%
Hence, the annual interest rate is 21%
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Which of the LCM (40,120,150)?
Answer:
2400
Step-by-step explanation:
40 = 2^3 * 5
120 = 2^5 * 5
150 = 2 * 3 * 5^2
LCM = 2^5 * 3 * 5^2
832 x156 show your work
Answer:
129792
Step-by-step explanation:
156
× 832
----------
312
468
+ 1248
---------------
129792
cual es el valor x-3=11
The function f(x) is shown in the graph
f(a)
Which type of function describes ((x)?
© Exponential
O Logarithmic
O Rational
O Polynomial
Answer:
the function is an exponential funtion.
Step-by-step explanation:
learned it
How many workers will be needed to complete a task in 6 days, given that 8 workers can complete the same task in 9 days?
Considering the simple inverse rule of three, 12 workers will be needed to complete a task in 6 days, given that 8 workers can complete the same task in 9 days.
Inversely proportional relationshipTwo variables are related when a change in one of them causes a change in the other.
Two variables have an inversely proportional relationship when an increase in one variable causes the other to decrease or, analogously, a decrease in one causes the other to increase.
In other words, two magnitudes are inversely proportional when as one increases, the other decreases in the same proportion, and as the first decreases, the second increases in the same proportion.
Simple inverse rule of threeThe simple inverse rule of three is used when the problem deals with two inversely proportional magnitudes where the amount of one of a magnitude corresponding to a given amount of the other magnitude must be calculated.
To carry out an inverse rule of three, it must be taken into account that if for a value A of one magnitude, there is a value B of the other magnitude, while for a value of C of the first magnitude, the second magnitude is will correspond a value of X:
A → B
C → X
So: [tex]X=\frac{AxB}{C}[/tex]
Amount of workers neededThe number of people who perform a task is inversely proportional to the time it takes: a greater number of workers corresponds to less time to perform the task. Then:
9 days → 8 workers
6 days → amount of workers
So:[tex]amount of workers=\frac{9 daysx8 workers}{6 days}[/tex]
amount of workers= 12 workers
Finally, 12 workers will be needed to complete a task in 6 days, given that 8 workers can complete the same task in 9 days.
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Twelve different video games showing drugs were observed. The duration times of drugs were recorded, with the times (seconds) listed below. Assume that these sample data are used with a 0.01 significance level in a test of the claim that the population mean is greater than 75 sec. If we want to construct a confidence interval to be used for testing that claim, what confidence level should be used for a confidence interval? If the confidence interval is found to be -34.1 sec < μ < 238.3 sec, what should we conclude about the claim?
88 15 537 53 0 52 197 40 182 0 2 59
1.) The confidence level should be _____%
2.) What should we conclude about the claim?
The given confidence interval __(contains / does not contain)___ the value of 75 sec, so there ___( is / is not )___ sufficient evidence to support the claim that the mean is greater than 75 sec.
_____________________________________________
NOTE: Please explain like I'm five. I'm not understanding why the confidence level should be anything but 90% and I don't know *why* we would conclude what we would conclude about this claim.
The answers to the questions are:
1. The confidence level is 99 percent.
2. We have to conclude that there is no sufficient evidence available to support this claim because the Confidence interval contains 75 sec.
How to solve for the confidence level1. The confidence level here should be
1- 0.01 = 0.99
= 99 percent
Given that, 99% confidence interval for population mean (μ) is (-34.1 sec u< u < 264.1 ) seconds.
We are to test the claim that the population mean is greater than 75 sec.
2.
The given confidence interval contains the value of 75 sec, so there is not sufficient evidence to support the claim that the mean is greater than 75 sec.
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What is the equation of the circle that has its center at -26,120 and passed through the origin
well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius
[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill[/tex]
[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill[/tex]
kerri said that the quotient of 4.2/5 is about 8 tenths because 4.2/5 is close to 40 tenths /5 do you agree with Kerris reasoning?
Kerris reasoning that 4.2/5 is about 8 tenths because 4.2/5 is close to 40 tenths/5 is correct
How to interpret Kerris reasoning?The quotient is given as:
4.2/5
Kerris reasoning is that
4.2/5 is approximately 0.8
We start by calculating the actual value of the quotient 4.2/5
Using a calculator, we have:
4.2/5 = 0.84
Approximate to the nearest tenth
4.2/5 = 0.8
This means that Kerris reasoning that 4.2/5 is about 8 tenths because 4.2/5 is close to 40 tenths/5 is correct
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Name a line that does not appear to intersect plane L.
Answer:
BE
Step-by-step explanation:
A line and a plane will not intersect if they are parallel. A line is named by naming any two points on it, in any order.
LineThe line containing points B, E, F appears to be parallel to plane L. As such, it will remain at the same distance from plane L throughout its infinite length. The line can be named by 2 points in any of 6 different ways.
Line BE is parallel to plane L.
__
Additional comment
Other names for the same line include ...
BF, EF, EB, FB, FE.
if im taking a 32 hour course and ive completed 73% of it how much time do i have left
Answer:
8.64 hours, so
8 hours, 38 mins, 24 seconds
Just find that 27% you have left, then find how much that 27% is in terms of time.
It might be wrong so double check it please.
Answer:
8.64 hours
which is 8hrs 38mins and 24secs
Step-by-step explanation:
If you've completed 73% then you have 27% left to go still. (100-73 = 27)
27% of 32
= .27×32
= 8.64 hours left
That is 8hrs and .64 of an hour .64×60=38.4 mins
which is 38 mins and .4 of a minute.
.4×60 = 24secs
Probably you will just round this answer.
A. What are the coordinates of R’ if R (-2, 7) is dilated around the origin with k=3?
B. What are the coordinates of T’ if T (4,-1) is dilated by a scale factor of ½ with R as the center of the dilation?
A: The coordinates of the point R' are (- 6, 21).
B: The coordinates of the point T' are (1, 3).
How to generate new points by definition of dilation
In this question we must make use of rigid transformations to find the location of new points, rigid transformations are transformations used in geometric loci such that Euclidean distance is conserved. In this case, we need to use a kind of rigid transformation known as dilation, which is defined below:
P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)] (1)
Where:
O(x, y) - Center of dilationk - Dilation factorP(x, y) - Original pointP'(x, y) - Resulting pointPart A - If we know that O(x, y) = (0, 0), R(x, y) = (- 2, 7) and k = 3, then the coordinates of point R' are:
R'(x, y) = (0, 0) + 3 · [(- 2, 7) - (0, 0)]
R'(x, y) = (- 6, 21)
Part B - If we know that O(x, y) = (- 2, 7), T(x, y) = (4, - 1) and k = 1/2, then the coordinates of point T' are:
T'(x, y) = (- 2, 7) + (1 / 2) · [(4, - 1) - (- 2, 7)]
T'(x, y) = (- 2, 7) + (1 / 2) · (6, - 8)
T'(x, y) = (- 2, 7) + (3, - 4)
T'(x, y) = (1, 3)
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mary is making a batch of chocolate chip cookies the recipe calls for 9 cups of flour and 2 4/7 cups of sugar she isshort on flour cuts the recipe down to 7 cups if flour how much sugar should she add
Mary added [tex]$24 \frac{1}{2}[/tex] cups of sugar.
How to estimate how much sugar should Mary add?The ratio of flour to sugar exists at 9 cups: 2 4/7 cups
Utilizing equivalent ratios, given that 7 cups of sugar was utilized,
Let cups of flour needed = x such that our equation becomes
flour/sugar[tex]$ =\frac{9}{2\frac{4}{7} }=\frac{x}{7}[/tex]
[tex]$ \frac{9}{2\frac{4}{7} }=\frac{x}{7}[/tex]
Convert mixed numbers into improper fractions
[tex]$2 \frac{4}{7}= \frac{18}{7}[/tex]
simplifying the above equation, we get
[tex]$\frac{9}{\frac{18}{7} } = \frac{x}{7}[/tex]
= [tex]$24 \frac{1}{2}[/tex]
x = 24.5
The value of x = 24.5.
Therefore, [tex]$24 \frac{1}{2}[/tex] cups of sugar exist required.
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The dialogue of a square is X units what is the area of the square in terms of X
The area of the square in terms of x unit is x²/ 2
Diagonal of a square
The expression for the diagonal of a square is written as'
d^2=s^2+s^2
Where
s² is the area of the squared² is the diagonal of the same squareBut from the given question we have that the diagonal of the said square is 'x'
Now, let's substitute the values into the expression of the diagonal given above,
d^2=s^2+s^2
d² = s² + s²
We have,
x² = s² + s²
Collect and add like terms
x² = 2s²
But we know that s² represents the area of the square
So,
x² = 2 × area
Make 'area' subject of formula
Area = x²/ 2
Now, we can say that the area of the square in terms of x units is x²/2
Therefore, the area of the square in terms of x unit is x²/ 2
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The percentage of each transaction contributed to the total transactions in the same Account. Use BASE_EQUIV_AMT as the unit.
The percentage that each transaction contributed to the total transactions in the same account (Cash Account and Service Revenue) is computed as follows:
Cash Account:1. Service Revenue $900 = 8%
2. Owner's Equity, Barbara Hanson $2,200 = 19.8%
3. Accounts Receivable $750 = 6.8%
5. Note Payable $6,000 = 54.1%
6. Unearned Revenue $1,250 = 11.3%
Total cash receipts = $11,100
Service Revenue:1. Cash $900 = 70.6%
4. Accounts Receivable $375 = 29.4%
Total $1,275
How is the percentage computed?The percentage that each transaction contributed to the total transactions in the same account can be computed by taking the dollar value of the transaction over the total value of transactions in the same account and then multiplying by 100.
Percentage values show the degrees of relationship among variables.
The formula for computing percentage in this scenario is transaction value/total transactions value × 100%.
Transaction Analysis:1. Cash $900 Service Revenue $900
2. Cash $2,200 Owner's Equity, Barbara Hanson $2,200
3. Cash $750 Accounts Receivable $750
4. Accounts Receivable $375 Service Revenue $375
5. Cash $6,000 Note Payable $6,000
6. Cash $1,250 Unearned Revenue $1,250
Question Completion:The following transactions occurred during July:
1. Received $900 cash for services provided to a customer during July.
2. Received $2,200 cash investment from Barbara Hanson, the owner of the business.
3. Received $750 from a customer in partial payment of his account receivable, which arose from sales in June.
4. Provided services to a customer on credit, $375.
5. Borrowed $6,000 from the bank by signing a promissory note.
6. Received $1,250 cash from a customer for services to be rendered next year.
Use the transactions to compute the percentage of each transaction relative to the total transactions in the same account.
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A farmer finds there is a linear relationship between the number of bean stalks, n , she plants and the yield, y , each plant produces. When she plants 30 stalks, each plant yields 25 oz of beans. When she plants 32 stalks, each plant produces 24 oz of beans. Find a linear relationship in the form y=mn+b that gives the yield when n stalks are planted.
Answer:
y = -1/2n +40
Step-by-step explanation:
We are given two ordered pairs (stalks, ounces) and asked for the slope-intercept form equation of the line through them.
SlopeThe slope of the desired line can be found from the formula ...
m = (y2 -y1)/(x2 -x1)
For the given points (30, 25) and (32, 24), the slope is ...
m = (24 -25)/(32 -30) = -1/2
Y-interceptThe y-intercept of the desired line can be found from the formula ...
b = y -mn
b = 25 -(-1/2)(30) = 25 +15 = 40
Slope-intercept equationThe slope-intercept equation of a line is ...
y = mn +b . . . . . line with slope m and y-intercept b
y = -1/2n +40 . . . . . . line with slope -1/2 and y-intercept 40
The linear relationship between stalks (n) and yield (y) is ...
y = -1/2n +40
Use the graphing tool to find the local minimum and the local maximum for the given function.
Over the interval [-3, -1], the local minimum is
A) -3
B) -2
C) -1
D) 0
Over the interval [-1, 0], the local maximum is
A) -1
B) 0
C) 1.5
D) 4.39
Over the interval [0, 3], the local minimum is
A) -40
B) -32
C) -18
D) 0
The local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.
Given a graph of a function.
We are required to find:
A)Local minimum over the interval [-3,-1],
B) Local maximum over the interval [-1,0],
C) Local minimum over the interval [0,3].
We know that local maximum is a point after which the value of function starts decreasing and the local minimum is a point after which the value of function starts increasing.
When we see the graph from x=-3 to x=-1 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at x=-2 and y=0, so the value of local minimum will be 0.
When we see the graph from x=-1 to x=0 we can find that the highest point is where the value of f(x) is maximum and after which the graph is decreasing is at y=4.39, so the value of local maximum will be 4.39.
When we see the graph from x=0 to x=3 we can find that the highest point is where the value of f(x) is minimum and after which the graph is increasing is at y=-32, so the value of local minimum will be -32.
Hence the local minimum over the interval [-3,-1] is 0, the local maximum over the interval [-1,0] is 4.39, local minimum over the interval[0,3]is -32.
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Try it
How many true, real number solutions does the equation n + 2 = √-16-5n have?
solution(s)
Answer:
none
Step-by-step explanation:
The domain of the equation can be found by looking at the requirements ...
the square root is non-negativethe argument of the square root is non-negative.DomainFor n+2 ≥ 0, we find ...
n ≥ -2 . . . . . . . . subtract 2 from both sides
For -16-5n ≥ 0, we find ...
-16 ≥ 5n . . . . . add 5n
-3.2 ≥ n . . . . . divide by 5
Together, these domain restrictions require that ...
n ≥ -2
n ≤ -3.2
These intervals do not overlap, so there are no values of n that can satisfy this equation.
__
Additional comment
The solutions would appear on the attached graph as points where the curves intersect above the x-axis. They do not intersect, hence the equation has zero solutions.
__
If we were to solve this without regard to domain restrictions, we would square both sides to get ...
(n +2)² = -16 -5n
n² +9n +20 = 0 . . . . . put in standard form
(n +4)(n +5) = 0 . . . . . factor
n = {-5, -4} . . . . . . . . . both are extraneous solutions.
These "solutions" do not satisfy the requirement that the square root be positive.
Find the value of x.
Answer:
x = 106 degrees
Step-by-step explanation:
x + 104 + 40 + 110 = 360
x + 254 (No more 254)
- 254 (Again no more 254)
x = 106
25(0.3x-4)-5(1.5x-6)+100·13/4
Answer:
255 (assuming x is the variable x)
340 (assuming x is the multiplication sign)
See explanation below.
Step-by-step explanation:
I assume that x is the variable x.
25(0.3x-4)-5(1.5x-6)+100·13/4 =
= 7.5x - 100 - 7.5x + 30 + 25 × 13
= -70 + 325
= 255
If my assumption above is incorrect, and x really means the multiplication sign, then we have this:
25(0.3×-4)-5(1.5×-6)+100·13/4 =
= 25(-1.2) - 5(-9) + 100(3.25)
= -30 + 45 + 325
= 340
After descending 8.25 feet, a bird is now
at a height of 16.5 feet. What was the initial
height of the bird?
Pls need help 100 points and crown if right!!!
Marlene only has enough ingredients to make a 1/3
batch of cookies. For the smaller batch, she only needs 3/4
cup of sugar. How much sugar does the recipe for a full batch of cookies call for? Include all your work in your answer.
Answer:
[tex]\sf 2\dfrac{1}{4}\ cups \ of \ sugar[/tex]
Explanation:
Let the full batch be x
Here given:
3/4 cup of sugar required to make 1/3 batch of cookies
Build equation:
[tex]\sf \rightarrow \dfrac{1}{3}x = \dfrac{3}{4} \ cup \ of \ sugar[/tex]
Solve:
[tex]\sf \rightarrow x = \dfrac{3(3)}{1(4)}[/tex]
[tex]\sf \rightarrow x = \dfrac{9}{4}[/tex]
[tex]\rightarrow \sf x = 2\dfrac{1}{4}[/tex]
Answer:
2 2\3 cups of sugar.
Step-by-step explanation:
2.) A shop sells oranges at 6 for N100. A trader sells the same kind of oranges at 8 for N120.
Which price is cheaper, by how much per orange?
The cheaper price among this set of orange sales is the one done by trader B, who sells 8 for N120.
How is the cheaper price determined?The cheaper price can be computed by finding out the price per unit.
Data and Calculations:Price of Set Unit Price
Sale of 6 oranges N100 N16.67 (N100/6)
Sale of 8 oranges N120 N15.00 (N120/8)
Thus, selling 8 oranges for N120 is cheaper than selling 6 oranges for N100, and N1.67.
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Which of the following demonstrates the correct calculation for simple interest?
The statement that demonstrates the correct calculation for simple interest is " A principal balance of $10,000 at 5% interest earns $500 each year as interest.
What is a simple interest?Simple interest is based on the principal amount of a loan or the first deposit in a savings account.
Simple interest does not compound interest on an interval basis. For instance quarterly, semi annually, annually etc. This are carried out in the case of compound interest.
Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on principal plus interest.
Hence base don the explanation above, the statement that demonstrates the correct calculation for simple interest is " A principal balance of $10,000 at 5% interest earns $500 each year as interest.
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A car traveled at an average speed of 80 km/h for 5 hours. What was
the distance traveled?
Answer:
400 km
Step-by-step explanation:
Distance = rate times time
Distance = 80(5)
Distance = 400
Please help, need for math hw and cant figure it out
The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
How to represent the quadratic function in standard form?The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Which of the following represents a quadratic function?
a. y = 3x - 2
b. y=6+5x + x²
c. x³10x = 21
d. y= 2² +4
Answer:
○ [tex]y = 6 + 5x + x^2[/tex]
Explanation:
What is a quadratic equation?A quadratic equation is an algebraic equation where the highest power of [tex]x[/tex] is 2. The general form of a quadratic equation is as follows:
[tex]\boxed{ax^2 + bx + c = 0}[/tex],
where a, b, and c represent known constants, and [tex]x[/tex] is the unknown.
In this question, if you take a look at the second option, you will see that it is possible to rearrange the equation to make it look the general form:
[tex]y = 6 + 5x + x^2[/tex]
⇒ [tex]y = x^2 + 5x + 6[/tex]
Therefore, this equation is quadratic.
The other three options are not quadratic equations because none of them have an [tex]x^2[/tex] term in them.
[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]
[tex]\leadsto[/tex] A quadratic equation is an algebraic equation of the second degree. The formula is:
▪ [tex]\longrightarrow \sf{y = ax^2 + bx + c}[/tex]
This can also be written as:
▪ [tex]\longrightarrow \sf{y = c + bx+ax^2}[/tex]
Comparing the equation above with each of the options, the equation that represents a quadratic function is:
[tex]\longrightarrow \sf{y=6+5 + x^2}[/tex]
[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]
◉ [tex] \large\bm{b. \: y=6+5x + x^2}[/tex]
At the beach, Nardia collected triple the number of seashells that Pierre did. Together, they collected 52 seashells. Which equations represents p, the number of seashells that Pierre collected.
3 p + p = 52
3 + p = 52
52 + p = 3 p
52 + p = 3
Answer:
A
Step-by-step explanation:
p = Pierre shells
Nardia shells = 3p
3p + p = 52
Answer:
a
Step-by-step explanation:
Write a polynomial that has a GCF of 7m and another with a GCF of 2ab squared.
The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²
The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³
Writing PolynomialsFrom the question, we are to write a polynomial that has a GCF of 7m
That is,
We are to write a polynomial that has a greatest common factor of 7m
Writing the polynomial
14mn - 21m + 49m²n + 7mn²
The polynomial above has a greatest common factor of 7m. That is, 7m is the greatest factor that can divide each of the terms
We are to write a polynomial with a GCF of 2ab²
Writing the polynomial
6a²b² - 8ab³ + 4a³b² + 2a³b³
The polynomial above has a greatest common factor of 2ab². That is, 2ab² is the greatest factor that can divide each of the terms
Hence,
The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²
The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³
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1+1-1(2)+1=?
A,0
B,1
C,2
D,3
Answer:
B. 1
Step-by-step explanation:
-1*2 = -2
-2+1 = -1
-1+1 = 0
0+1 = 1
