Answers
Answer:
First question: 1/x^-7
Second question:
x^7
Step-by-step explanation:
To divide these problems (same variable base and exponents) subtract the exponents.
To get rid of a negative on the exponent, "push" the term across the fraction bar. Passing over the fraction bar changes the sign of the exponent. There are math reasons for this, its not random. But thats how it works. (Has to do with an exponent of -1 which will give you the reciprocal of your base).
Also, to multiply terms with the same base, add the exponents.
see image.
Related Questions
Solve the triangle: a = 12,c = 2-2, B = 33". If it is not possible, say so.A= 25.1",b = 1.8, C = 121.9"This triangle is not solvable.A = 45*,b= V2.C = 102VEA= 30', b = -, C = 117"
Answers
ANSWER:
A=25.1 degrees
b = 1.8
C = 121.9 degrees
SOLUTION:
We can solve this problem using the cosine law, since we are given the length of 2 sides of triangle and the angle they formed.
[tex]b\text{ =}\sqrt[]{c^2+a^2-2ac\cos B}[/tex]We substitute the given
[tex]\begin{gathered} b\text{ =}\sqrt[]{(2\sqrt[]{2})^2+(\sqrt[]{2})^2-2(\sqrt[]{2})(2\sqrt[]{2})\cos 33} \\ b\text{ = 1.8} \end{gathered}[/tex]Using Sine Law, we can get the angles
[tex]\begin{gathered} \frac{1.8}{\sin 33}=\frac{\sqrt[]{2}}{\sin A} \\ A=25.1 \end{gathered}[/tex]Since the total angle inside a triangle is 180, the angle at C is
[tex]C-33-25.1=121.9[/tex]The probability that an individual is left-handed is 12%, In a randomly selected class of 30students, what is the probability of finding exactly 4 left-handed students?
Answers
Given that:
- The probability that an individual is left-handed is 12%.
- There are 30 students in the class.
You need to use this Binomial Distribution Formula, in order to find the probability of finding exactly 4 left-handed students :
[tex]P(x)=\frac{n!}{(n-x)!x!}p^x(1-p)^{n-x}[/tex]Where "n" is the number being sampled, "x" is the number of successes desired, and "p" is the probability of getting a success in one trial.
In this case:
[tex]\begin{gathered} n=30 \\ x=4 \\ p=\frac{12}{100}=0.12 \end{gathered}[/tex]Therefore, by substituting values into the formula and evaluating, you get:
[tex]P(x=4)=\frac{30!}{(30-4)!4!}(0.12)^4(1-0.12)^{30-4}[/tex][tex]P(x=4)\approx0.2047[/tex]Hence, the answer is:
[tex]P(x=4)\approx0.2047[/tex]-5 ( -10-2(-3)) to the 2nd power . numerical exponents
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The value of -5 ( -10-2(-3)) to the 2nd power is -6480.
What is an exponent?It should be noted that an exponent simply means the number through which another number can be multiplied by itself.
Based on the information given, it should be noted that PEDMAS will be used. This implies:
P = parentheses
E = Exponents
D = division
M = multiplication
A = addition
S = subtraction
-5 ( -10-2(-3)² will be illustrated thus:
It's important to calculate the value in the parentheses first according to PEDMAS.
= -5 [(-12(-3)]²
= -5 (36)²
= -5 × 1296
= -6480
The value is -6480.
In this case, the concept of PEDMAS is used to get the value.
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Round the decimal number to the nearest thousandth.
11.59978
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Answer:
Step-by-step explanation:
Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval.
Answers
We have the following integral in the discrete sum form:
[tex]\lim_{||\Delta||\to0}\sum_{i\mathop{=}1}^{\infty}(6c_i+3)\Delta x_i.[/tex]In the interval [-9, 6].
To convert to the integral form, we convert each element of the discrete sum form:
[tex]\begin{gathered} \lim_{||\Delta||\to0}\sum_{i\mathop{=}1}^{\infty}\rightarrow\int_{-9}^6 \\ 6c_i+3\rightarrow6x+3 \\ \Delta x_i\rightarrow dx \end{gathered}[/tex]Replacing these in the formula above, we get the integral form:
[tex]\int_{-9}^6(6x+3)\cdot dx.[/tex]AnswerTwo people start walking at the same time in the same direction. One person walks at 2 mph and the other person walks at 6 mph. In how many hours will they be 2 mile(s) apart?
Answers
Let's define the following variable:
t = number of hours for them to be 2 miles apart
Distance covered by Person A after "t"hours would be 2t or 2 miles times "t" hours.
Distance covered by Person B after "t" hours would be 6t or 6 miles times "t" hours.
If the distance of Person A and B is 2 miles apart after "t" hours, we can say that:
[tex]\begin{gathered} \text{Person B}-PersonA=2miles \\ 6t-2t=2miles\text{ } \end{gathered}[/tex]From that equation, we can solve for t.
[tex]\begin{gathered} 6t-2t=2miles\text{ } \\ 4t=2miles\text{ } \\ \text{Divide both sides by 4.} \\ t=0.5hrs \end{gathered}[/tex]Therefore, at t = 0.5 hours or 30 minutes, the two persons 2 miles apart.
At 0.5 hours, Person A will
Simplify 2f+ 6f help me pls
Answers
Answer:
[tex]{ \tt{ = 2f + 6f}}[/tex]
- Factorise out f as the common factor;
[tex]{ \tt{ = f(2 + 6)}} \\ = 8f[/tex]
Write a recursive formula for an, the nthterm of the sequence 8, -2, -12, ....
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We have the sequence: 8, -2, -12...
We can prove that this is an arithmetic sequence as there is a common difference d=-10 between consecutive terms.
Then, the recursive formula (the expression where the value of a term depends on the value of the previous term) can be written as:
[tex]a_n=a_{n-1}-10[/tex]Answer: the recursive formula is a1 = 8, a(n) = a(n-1) - 10
thanks for the help!!!!!
Answers
The required values of given the trigonometric functions are sin(A + B) = -100/2501 and sin(A - B) = -980/2501.
What are Trigonometric functions?Trigonometric functions are defined as the functions which show the relationship between the angle and sides of a right-angled triangle.
We have been given that the trigonometric function
sin (A) = -60/61 and cos(B) = 9/41
So cos (A) = √1 - (-60/61)² = 11/61, and sin(B) = √1 - (9/41)² = 40/41
To compute the trigonometric functions sin(A + B) and sin(A - B)
⇒ sin(A + B) = sinA cosB + cos A sinB
⇒ sin(A + B) = (-60/61)(9/41) + (11/61)(40/41)
⇒ sin(A + B) = -540/2501 + 440/2501
⇒ sin(A + B) = -100/2501
⇒ sin(A - B) = sinA cosB - cos A sinB
⇒ sin(A - B) = (-60/61)(9/41) - (11/61)(40/41)
⇒ sin(A - B) = -540/2501 - 440/2501
⇒ sin(A - B) = -980/2501
Thus, the required values of given the trigonometric functions are sin(A + B) = -100/2501 and sin(A - B) = -980/2501.
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graph the line with slope 1/3 passing through the point (4,2)
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To graph a line we need two points, to find a second one we need the equation of the line. The equation of a line is given by:
[tex]y-y_1=m(x-x_1)[/tex]Plugging the values given we have:
[tex]\begin{gathered} y-2=\frac{1}{3}(x-4) \\ y-2=\frac{1}{3}x-\frac{4}{3} \\ y=\frac{1}{3}x-\frac{4}{3}+2 \\ y=\frac{1}{3}x+\frac{2}{3} \end{gathered}[/tex]Once we know the equation of a line we find a second point on the line, to do this we give a value to x and use the equation to find y. If x=1, then:
[tex]\begin{gathered} y=\frac{1}{3}\cdot1+\frac{2}{3} \\ y=\frac{1}{3}+\frac{2}{3} \\ y=\frac{3}{3} \\ y=1 \end{gathered}[/tex]Then we have the point (1,1).
Now that we have two points of the line we plot them on the plane and join them with a straight line. Therefore the graph of the line is:
Allied Health - A wound was measured to be 0.8 cm in length. Whaat is the greatest possible error of this weight in grams?
Answers
Ok, so
First of all, we got that the wound was measured to be 0.8cm.
This measurement equals to:
[tex]0.8\operatorname{cm}\cdot\frac{10\operatorname{mm}}{1\operatorname{cm}}[/tex]0.8cm is equal to 8 millimeters.
Now, the greatest possible error in a measurement is one half of the precision (smallest measured unit).
8 mm was measured to the nearest 1 mm, so the measuring unit is 1 mm.
So, one half of the precision (1mm) is 0.5
Therefore, the greatest possible error is 0.5 mm
What is the product in simplest form? State any restrictions on the variable9X^2+9X+18)/(X+2) TIMES (x^2-3x-10)/(x^2+2x-24)
Answers
So, here we have the following expression:
[tex]\frac{9x^2+9x+18}{x+2}\cdot\frac{x^2-3x-10}{x^2+2x-24}[/tex]The first thing we need to notice before simplifying, is that the denominator can't be zero.
As you can see,
[tex]\begin{gathered} x+2\ne0\to x\ne-2 \\ x^2+2x-24\ne0\to(x+6)(x-4)\ne0\to\begin{cases}x\ne-6 \\ x\ne4\end{cases} \end{gathered}[/tex]These are the restrictions on the given variable.
Now, we could start simplyfing factoring each term:
[tex]\begin{gathered} \frac{9x^2+9x+18}{x+2}\cdot\frac{x^2-3x-10}{x^2+2x-24},x\ne\mleft\lbrace2,4,-6\mright\rbrace \\ \\ \frac{9(x^2+x+2)}{x+2}\cdot\frac{(x-5)(x+2)}{(x+6)(x-4)},x\ne\lbrace2,4,-6\rbrace \end{gathered}[/tex]This is,
[tex]9(x^2+x+2)\cdot\frac{(x-5)}{(x+6)(x-4)},x\ne\lbrace4,-6\rbrace[/tex]So, the answer is:
[tex]\frac{9(x^2+x+2)(x-5)}{(x+6)(x-4)},x\ne\lbrace4,-6\rbrace[/tex]It could be also written as:
[tex]\frac{(9x^2+9x+18)(x-5)}{(x+6)(x-4)},x\ne\lbrace4,-6\rbrace[/tex]Work out the following sums and write the answers correctly.
a) £1.76 + £2.04
b) £5.62 + £2.38
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Answer of a is €3.8
Answer of b is €8
Solution :
To get the answer add two decimal number
ie. the sum of first question is €1.76 + €2.04 = €3.8
the sum of second question is €5.62 + €2.38 = €8
Addition is one of the four basic operations of arithmetic, the other three being subtraction, multiplication and division.The addition of two whole numbers results in the total amount or sum of those values combined.Addends are the numbers added, and the result or the final answer we get after the process is called the sum.To learn more about Addition refer :
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please help this is for my study guide thanks! (simplify)
Answers
One way of simplifying the given expression is by using the following definition:
[tex]k^{-1}=\frac{1}{k}[/tex]So, for the given expression, we have:
[tex]-3k^{-1}=-3\cdot\frac{1}{k}=-\frac{3}{k}[/tex]Therefore, a possible answer is:
[tex]-\frac{3}{k}[/tex]Finding the vertex focus directrix and axis of symmetry of a parabola
Answers
Equation:
[tex](y+1)^2=6(x-5)[/tex]The vertex is given by the following formula:
[tex](y-k)^2=4p(x-h)[/tex]where the vertex is (h, k). Thus, in our equation k = -1 and h = 5, and the vertex
is (5, -1).
Additionally, the focus is given by (h+p, k). In our case:
[tex]p=\frac{6}{4}=\frac{3}{2}[/tex]Then, the focus is:
[tex](5+\frac{3}{2},-1)[/tex]Simplifying:
[tex](\frac{13}{2},-1)[/tex]The directrix is x = h - p:
[tex]x=5-\frac{3}{2}=\frac{7}{2}[/tex]Finally, the axis of symmetry is y = -1.
Alpha Industries is considering a project with an initial cost of $7.9 million. The project will produce cash inflows of $1.63 million per year for 7 years. The project has the same risk as the firm. The firm has a pretax cost of debt of 5.58 percent and a cost of equity of 11.25 percent. The debt-equity ratio is .59 and the tax rate is 21 percent. What is the net present value of the project?
Answers
The net present value of the project of the company Alpha Industries is $494,918.
Given,
The initial cost of the project = $7.9 million
Cost of debt = 5.58 percent
Cost of equity = 11.25 percent
The debt-equity ratio= .59
Tax rate = 40 percent.
Let us assume
Equity be $x, then
Total = $1.59x
Respective weights = Pretax cost of debt × (1 - tax rate)
=5.58% × (1 - 0.4)
Respective weights = 3.348%
WACC = Respective costs × Respective weights
WACC = (x ÷ 1.59x × 11.25%) + (0.59x ÷ 1.59x × 3.348)
WACC = 8.318%
The present value of annuity = Annuity × (1 - (1 + interest rate)^ - time period] ÷ Rate
=1.63 × [1 - (1.08317811321)^-7]÷ 0.08317811321
= $1.63 × 5.150256501
The present value of annuity = $8,394,918.10
The net present value = The present value of cash inflows - The present value of cash outflows
= $8,394,918.10 - $7,900,000
The net present value of the the project = $494,918
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The length of a rectangle is 5yd less than twice the width, and the area of the rectangle is 33yd^. Find the dimensions of the rectangle.
Answers
Let l be the length of the rectangle and w its width.
From this, we have:
I) w - l = 5
II) l*w = 33
From I, we have w = 5 + l
Applying this to equation II, we have: l(5+l) = 33
l^2 + 5l - 33 = 0
The positive root of this equation is l = [sqrt(157) - 5]/2 = 3.8 yd (rounded to the nearest tenth)
Applying this to equation I, we have: w - 3.8 = 5, which implies w = 5 + 3.8 = 8.8 yd
Circle O shown below has an are of length 47 inches subtended by an angle of 102°.Find the length of the radius, x, to the nearest tenth of an inch.
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We will have the following:
[tex]\begin{gathered} 47=\frac{102}{360}\ast2\pi(x)\Rightarrow\pi(x)=\frac{1410}{17} \\ \\ \Rightarrow x=\frac{1410}{17\pi}\Rightarrow x\approx26.4 \end{gathered}[/tex]So, the radius is approximately 26.4 inches.
The sum of a number and 4 times it’s reciprocal is 13/3. Find the number(s).
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Let the unknown number be "x"
We will write an algebraic equation from the word problem given. Then we will solve for "x".
Given,
Sum of number (x) and 4 times the reciprocal is 13/3
We can convert it into an algebraic equation:
[tex]x+(4\times\frac{1}{x})=\frac{13}{3}[/tex]Now, let's solve for the unknow, x,
[tex]\begin{gathered} x+(4\times\frac{1}{x})=\frac{13}{3} \\ x+\frac{4}{x}=\frac{13}{3} \\ \frac{x^2+4}{x}=\frac{13}{3} \\ 3(x^2+4)=13\times x \\ 3x^2+12=13x \\ 3x^2-13x+12=0 \\ (x-3)(x-\frac{4}{3})=0 \\ x=3 \\ x=\frac{4}{3} \end{gathered}[/tex]The numbers are
[tex]\begin{gathered} 3 \\ \text{and} \\ \frac{4}{3} \end{gathered}[/tex]How many solutions does the system have? 2x + 3y = -6 3a - 4y = -12 no solutions O exactly one solution O infinitely many solutions
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Therefore, it has exactly one solution.
In the answer section, give the question letter and the word TRUE or FALSE for each of the following:
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a) We rewrite the right side of the expression as:
[tex](-2)^4=((-1)\cdot2)^4=(-1)^4\cdot2^4=1\cdot2^4=2^4\ne-2^4.[/tex]So we see that the expression of point a is FALSE.
b) We consider the expression:
[tex]b^x.[/tex]We take the logarithm in base b, we get:
[tex]\log_b(b^x)=x\cdot\log_b(b)=x\cdot1=x.[/tex]We see that the logarithm of a number x to a base b is just the exponent you put onto b to make the result equal x. We conclude that this expression is TRUE.
c) We know that in any base a, we have:
[tex]\log_a(0)\rightarrow-\infty.[/tex]We conclude that the expression of this item is FALSE.
d) Logarithms are defined only for numbers greater than 0. So we conclude that this expression is FALSE.
e) We consider the expression:
[tex]\log_b(b^{10})-\log_b(1)=10.[/tex]Applying the properties of logarithms, we get:
[tex]\begin{gathered} 10\cdot\log_bb-0=10, \\ 10\cdot1=10, \\ 10=10\text{ \checkmark} \end{gathered}[/tex]We see that this expression is TRUE.
Answera) FALSE
b) TRUE
c) FALSE
d) FALSE
e) TRUE
A money market account offers 1.25% interest compounded monthly. If you want to save $500 in two years, how much money would you need to save per month?
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If you want to save $500 in two years, you need to save $20.58 per month with a 1.25% interest compounded monthly.
How is the periodic saving determined?The monthly savings can be determined using an online finance calculator as follows:
N (# of periods) = 24 months (2 x 12)
I/Y (Interest per year) = 1.25%
PV (Present Value) = $0
FV (Future Value) = $500
Results:
Monthly Savings = $20.58
Sum of all periodic savings = $494.04
Total Interest = $5.96
Thus, the investor needs to save $500 in two years to save $20.58 monthly.
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find slope -1,4 3,15
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Answer:11/4
Step-by-step explanation: First you put the points in m=x1-x2/y1-y2
m=15-4/3+1=15
Let x equals negative 16 times pi over 3 periodPart A: Determine the reference angle of x. (4 points)Part B: Find the exact values of sin x, tan x, and sec x in simplest form. (6 points)
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The reference angle of x is -60 degree. The exact values of sin x, tan x, and sec x is [tex]$\sin \left(-60^{\circ}\right)=-\frac{\sqrt{3}}{2}$[/tex], [tex]$\tan \left(-60^{\circ}\right)=-\sqrt{3}$[/tex], [tex]$\sec \left(-60^{\circ}\right)=2$[/tex]
[tex]x=-\frac{16 \times 180}{3}$$[/tex]
Multiply the numbers: [tex]$16 \times 180=2880$[/tex]
[tex]$x=-\frac{2880}{3}$[/tex]
Divide the numbers: [tex]$\frac{2880}{3}=960$[/tex]
x=-960
Or, x = 2 [tex]\times[/tex] 360 - 960
Follow the PEMDAS order of operations
Multiply and divide (left to right) 2 [tex]\times[/tex]360 : 720 =720-960
Add and subtract (left to right) 720-960: -240
x= -240
Reference angle =180-240
Reference angle= -60
Sin (-60 degree)= [tex]$\sin \left(-60^{\circ}\right)=-\frac{\sqrt{3}}{2}$[/tex]
[tex]$\tan \left(-60^{\circ}\right)=-\sqrt{3}$[/tex]
[tex]$\sec \left(-60^{\circ}\right)=2$[/tex]
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use this figure for questions 1 through 4 1. are angles 1 and 2 a linear pair?2. are angles 4 and 5 a linear pair ?3.are angles 1 and 4 vertical angles?4. are angles 3 and 5 vertical angles ?
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Linear pair angles form a straight line, so, both angles add up to 180°.
1 and 2 are not a linear pair.
4 and 5 are a linear pair.
Vertical angles are opposite angles, that are equal.
1 and 4 are vertical angles
3 and 5 are NOT vertical angles-
whats an inequality to compare the numbers
11 and -9
Answers
The inequality comparison
What is Inequality?
Inequality of wealth in major cities Economic inequality comes in many forms, most notably wealth inequality measured by the distribution of wealth and income inequality measured by the distribution of income.
Given, numbers are
11 and -9
an inequality to show all numbers: from (11) to (–9) inclusive
-9 ≤ x ≤ 11
Hence, inequality to compare the numbers
11 and -9 is -9 ≤ x ≤ 11
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6. Takao scores a 90, an 84, and an 89 on three out of four math tests. Whatmust Takao score on the fourth test to have an 87 average (mean)?a. 87b. 88c. 85d. 84e. 86
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Consider x as Takao's fourth score.
Then, to achieve an 87 average, we have:
[tex]\begin{gathered} 87=\frac{90+84+89+x}{4} \\ x+263=4\cdot87 \\ x=348-263 \\ x=85 \end{gathered}[/tex]Answer:
c. 85
Solve for x. (x-8a)/ 6 = 3a-2x
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Given the equation:
[tex]\frac{x-8a}{6}=3a-2x[/tex]To solve for x, first we move the 6 to the other side of the equation:
[tex]\begin{gathered} \frac{x-8a}{6}=3a-2x \\ \Rightarrow x-8a=(3a-2x)\cdot6 \end{gathered}[/tex]Since the 6 was dividing, we pass it to the other side multiplying. Now we apply the distributive property and move the term -8a to the other side:
[tex]\begin{gathered} x-8a=(3a-2x)\cdot6 \\ \Rightarrow x-8a=18a-12x \\ \Rightarrow x=18a-12x+8a \\ \end{gathered}[/tex]Finally, we move the -12 to the other side with its sign changed:
[tex]\begin{gathered} x+12x=18a+8a=26a \\ \Rightarrow13x=26a \\ \Rightarrow x=\frac{26}{13}a=2a \\ x=2a \end{gathered}[/tex]therefore, x=2a
How can I solve this equation if x = -2 and y = -3? 3y (x + x² - y) I've also included a picture of the equation.
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In order to calculate the value of the equation, let's first use the values of x = -2 and y = -3 in the equation and then calculate every operation:
[tex]\begin{gathered} 3y(x+x^2-y) \\ =3\cdot(-3)\cdot(-2+(-2)^2-(-3)) \\ =-9(-2+4+3) \\ =-9\cdot5 \\ =-45 \end{gathered}[/tex]Therefore the final result is -45.
Tow "N" Go Towing Company charges a flat fee of $75 plus an additional $5 for every mile the car is towed. Which function models the cost, T(), of towing a car for miles?
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Answer:
5N + 75 I believe
