Solve the right triangle. Round decimals to the nearest tenth

The satellite makes 8 revolutions around the earth, it passes 177272 kilometers.

The orbital velocity of the satellite exists independent of its mass. The radius of the orbit exists as the only variable. If the satellite orbits near the planet at such a low height, its orbital speed must be extremely fast. If the orbital speed exists less than the required value, the satellite will be drawn to the earth's surface by gravity.

The satellite rotates around the earth to form a circle,

diameter of circle = Diameter of earth + 2(Height)

d = 6714 + 2(343)

d = 6714+ 686

d = 7057

Perimeter = πd

Perimeter = 3.14 (7057)

Perimeter = 22158.98

Total Revolution exists 8

Therefore, 8πd = 8(22158.98)

= 177272 kilometers.

Therefore, the satellite makes 8 revolutions around the earth, it passes 177272 kilometers.

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[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=562\\ r=5 \end{cases}\implies 562=\cfrac{\pi (5)^2 h}{3}\implies 1686=25\pi h \\\\\\ \cfrac{1686}{25\pi }=h\implies 21.47\approx h[/tex]

The number of bags of candy and cookies sold by the drama club is 4 and 10 respectively

let

The equation:

8.50x + 4.50y = 79

y = x + 6

Substitute x = y + x into

8.50x + 4.50y = 79

8.50x + 4.50(x + 6) = 79

8.50x + 4.50x + 27 = 79

8.50x + 4.50x = 79 - 27

13x = 52

x = 52/13

x = 4

Recall,

y = x + 6

y = 4 + 6

y = 10

Therefore, the number of bags of candy and cookies sold by the drama club is 4 and 10 respectively.

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[tex] \sqrt{112x {}^{6}y {}^{3} {z}^{5} } \\ \sqrt{(2 {}^{4} \times 7 )x {}^{6}y {}^{2}yz {}^{4} z } \\ 2 {}^{2}x {}^{3} yz {}^{2} \sqrt{7yz} [/tex]

Step-by-step explanation:

Since you haven't provided any functions, I can answer this question generally as to what the function would look like.

So when a polynomial has an even degree, then the two end behaviors will go in the same direction, and when it has an odd degree, then the two end behaviors will be in opposite directions. When a polynomial has a positive leading coefficient the right side will go towards infinity, and if a polynomial has a negative leading coefficient the right side will go towards negative infinity.

So let's look at the information:

As x approaches negative infinity, y approaches positive infinity.

Just given this we can't really say anything about the polynomial since we have to relate this to the right end behavior, or as x approaches infinity, so let's look at that.

As x approaches positive infinity, y approaches negative infinity.

This means that as x increases, y decreases, so that means the leading coefficient is negative. Since we know both end behaviors, and they're opposite (one y-value goes to negative infinity, and the other positive infinity), that means the polynomial is an odd degree.

So this means the polynomial will look something like this:

[tex]ax^n+bx^{n-1}+cx^{n-2}...[/tex]

where the leading coefficient "a" is negative and the degree of the polynomial (degree of leading coefficient) will be odd.

Answer:A

Step-by-step explanation:

edge 2023

Answer:

1/4

Step-by-step explanation:

Change is y (f9x) over the change in x.

Look at the f(x) column.

What is the change from -2 to -1?  1

What is the change from -1 to 0? 1

What is the change from 0 to 1? 1

What is the change from 1 to 2? 1

We see that this change is constant.  It is always 1.

Look at the x column.

What is the change from -8 to -4? 4

What is the change from -4 to 0? 4

What is the change from 0 to 4? 4

What is the change from 4 to 8? 4

We see that the change is constant.  It is always 1.

When we put this change the form a/b we get 1/4

The constant in the expression represents that the company earned  85 billion dollars in 2008.

The expression given in the question is known as a quadratic function. A quadratic function is a function that usually has a single variable and it is raised to the power of 2. The graph of a quadratic function is a curve called a parabola. Parabolas may curve upward or downward

An example of a quadratic function is ax² + bx + c

Where: a,b, c are real numbers not equal to zero

c = constant.

The constant in this question is 85. It is the amount earned in 2008

Here are the options:

The company earned  85 billion dollars from 2008 to 2018

The company earned  85 billion dollars in 2008

The company earned 14  billion dollars from 2008 to 2018.

The company earned  14 billion dollars in 2008.

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The first series uses a linear function with - 1 as first element and 1 as common difference, then the rule corresponding to the series is y = |- 1 + x|.

The second series uses a linear function with - 3 as second element as 2 as common difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

In this problem we have two cases of arithmetic series, which are sets of elements generated by a condition in the form of linear function and inside absolute power. Linear functions used in these series are of the form:

y = a + r · x      (1)

Where:

The first series uses a linear function with - 1 as first element and 1 as common difference, then the rule corresponding to the series is y = |- 1 + x|.

The second series uses a linear function with - 3 as second element as 2 as common difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

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The average density of the rod is  0.704 kg/m.

For given question,

We have been given the linear density in a rod 5 m long is 10 / x + 4 kg/m, where x is measured in meters from one end of the rod.

We need to find the

The length of rod is, L = 5 m.

The linear density of rod is, ρ = 10/( x + 4) kg/m

To find the average density we need to integrate the linear density from x₁ = 0 to x₂ = 5,  

The expression for the average density is given as,

⇒ ρ'

[tex]=\int\limits^5_0 {\rho} \, dx\\\\=\int\limits^5_0 {\frac{m}{L} } \, dx\\\\=\int\limits^5_0 {\frac{10}{5(x+4)} }\, dx\\\\=\int\limits^5_0 {\frac{2}{x+4} }\, dx[/tex]                        ......................(1)

Using u = x + 4  

du = dx

u₁ = x₁ + 4

u₁ = 0 + 4

u₁ = 4

and

u₂ = x₂ + 4

u₂ = 5 + 4

u₂ = 9

By entering the values above into (1), we have:

⇒ ρ'

[tex]=2\int\limits^9_4 {\frac{1}{u} } \, du\\\\ = 2[(log~u)]_4^{9}\\\\=2[(log~9-log~4)]\\\\=2\times[0.352][/tex]

= 0.704

Thus, we can conclude that the average density of the rod is  0.704 kg/m.

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The solution for the given equation is -5/8. By using simple algebraic operations, the equation is solved.

A linear equation is represented by ax + b = 0. The solution for this equation is

ax + b = 0

⇒ ax = -b

⇒ x = -b/a

The given equation is

7/8 + x = 1/4

On simplifying,

x = 1/4 - 7/8

⇒ x = -5/8

Therefore, the solution of the given equation is -5/8.

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The elementary row operation that will reduce the x–element in row 2 to 0 in this matrix is -2R1 + R2

The complete question is added as an attachment

The matrix is given as:

1   1    1       12

2  1    0     14

2  0   3      19

Rewrite as:

x   y    z      

1   1    1       12

2  1    0     14

2  0   3      19

So, the x-element of the second row is

x = 2

When the first row is multiplied by negative 2 and added to the second row, the x-element of the second row is reduced to 0

This is represented as;

-2R1 + R2

i.e.

-2(1   1    1       12)

+   2  1    0     14

---------------------------

    0  -1   -2    -10

Hence, the elementary row operation that will reduce the x–element in row 2 to 0 in this matrix is -2R1 + R2

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See attached images for the graph.

[tex]let \: the \: number \: be \: denoted \: by \: p \\ five \: times \: a \: number = 5p \\ square\: of \: a \: number = p {}^{2} [/tex]

[tex] \gamma - p {}^{2} = 5p - p {}^{2} [/tex]

[tex]\begin{array}{ccll} \$&messages\\ \cline{1-2} 5 & 100\\ 9.55& x \end{array} \implies \cfrac{5}{9.55}~~=~~\cfrac{100}{x} \\\\\\ 5x=955\implies x=\cfrac{955}{5}\implies x = 191[/tex]

The number of text messages that can be sent with $9.55 is 191.

Given that, it cost Taub $5.00 to send 100 text messages.

We need to find how many text messages did she send if she spent $9.55.

Proportion, in general, is referred to as a part, share, or number considered in comparative relation to a whole. The proportion definition says that when two ratios are equivalent, they are in proportion. It is an equation or statement used to depict that two ratios or fractions are equal.

Let the number of text messages she sent with $9.55.

Now, 5:100::9.55:x

⇒5x=955

⇒x=955/5

⇒x=191

Therefore, the number of text messages that can be sent with $9.55 is 191.

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Answer:

58, 66, 79, 84, 87 (see explanation for the exact answer)

Step-by-step explanation:

{58, 66, 79, 84, 87}

minimum = 58

lower quartile = 66

median = 79

upper quartile = 84

maximum = 87

Answer + Step-by-step explanation:

58, 60, 65, 67, 68, 72, 79, 79, 80, 81, 82, 86, 86, 87

The data set is in order then :

the minimum = 58

The maximum = 87

Determining the median :

first ,we notice that the data set has an even number (14) of numbers

Then

The median is the average of the two central values of the data set :

the two central values are the 7th and 8th numbers:

[tex]\text{median} =\frac{79+79}{2} =79[/tex]

Determining the lower quartile  :

The lower quartile is the median of the set :

58, 60, 65,  67 , 68, 72, 79

this set has an odd number (7) of values

Then

The central value is 67

Therefore

The lower quartile is 67

Determining the upper quartile  :

The upper quartile is the median of the set :

79, 80, 81,  82  , 86, 86, 87

this set has an odd number (7) of values

Then

The central value is the 4th number which is 82

Therefore

The upper quartile is 82

Interquartile range :

82 - 67 = 15

Answer:

Step-by-step explanation:

I'll go for the third option. It seems sensible to having a balance in estimating provided data, even though that may not always be the case.

Hope this helps!

Answer:

1. BD bisects <CBE, AE || BD (Given)

2. <EBD ~= <CBD (Definition of < Bisectors)

3. <AEB ~= <EBD (Alternate Interior Angles Theorem)

4. <CAE ~= <CBD (Corresponding Angles Postulate)

5. <CAE ~= <AEB (Transitive Property of Congruence)

6. AB ~= BE (Converse of Isosceles Triangles Theorem)

The surface area of all 27 blocks compared to the surface area of the box is 3 times the surface area of the box.

To find the total surface area of the 27 blocks:

A cube's surface area

Given that the box's side length is 15 inches:

Surface Area of 3-inch side length blocks:

Surface Area of 4-inch side length blocks:

Surface Area of 5-inch side length blocks:

Therefore, from the given answer options for the total surface area of the 27 blocks, the side length of the blocks must be 5 inches.

To calculate how many times the total surface area of the 27 blocks is to the surface area of the box:

So,

The side length of the blocks is 5 inches.

The total surface area of the 27 blocks is 4050 square inches.

This is 3 times the surface area of the box.

Therefore, the surface area of all 27 blocks compared to the surface area of the box is 3 times the surface area of the box.

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The required radius of the cylinder that can be covered by the paint exists at 3.8 feet.

Franco has enough paint to protect an area of about 226 square feet. He must paint a cylinder that exists 5 feet, and the maximum possible radius of the cylinder that can be covered by the paint exists to be determined.

The cylinder exists described as a 3D solid that holds two identical bases joined by a curved surface, at a particular distance.

Here, Franco keeps sufficiently paint to cover an area of about 226 square feet.

Area of the cylinder = 226

Area of the cylinder = πr²h = 226

h = 5 feet and π = 3.14

3.14 [tex]*[/tex] 5 [tex]*[/tex] r² = 226

r² = 226/15.70

[tex]$r = \sqrt{14.70}[/tex]

r = 3.80

Therefore, the required radius of the cylinder that can be covered by the paint exists at 3.8 feet.

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Answer: 4

Step-by-step explanation: I got the answer 4 right on the test

177.8 centimeters.

The shortest distance between the tip of the cone and its rim:

cos θ= base/Hypotenuse

cos 77°=[tex]\frac{40}{H}[/tex]

[tex]0.22495=\frac{40}{H}[/tex]

[tex]H=177.8[/tex]

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The shortest distance between the tip of the cone and its rim exits 51.11cm.

If you draw a line along the middle of the cone, you'd finish up with two right triangles and the line even bisects the angle between the sloping sides. The shortest distance between the tip of the cone and its rim exists in the hypotenuse of a right triangle with one angle calculating 38.5°. So, utilizing trigonometry and allowing x as the measurement of the shortest distance between the tip of the cone and its rim.

Cos 38.5 = 40 / x

Solving the value of x, we get

Multiply both sides by x

[tex]$\cos \left(38.5^{\circ}\right) x=\frac{40}{x} x[/tex]

[tex]$\cos \left(38.5^{\circ}\right) x=40[/tex]

Divide both sides by [tex]$\cos \left(38.5^{\circ}\right)$[/tex]

[tex]$\frac{\cos \left(38.5^{\circ}\right) x}{\cos \left(38.5^{\circ}\right)}=\frac{40}{\cos \left(38.5^{\circ}\right)}[/tex]

simplifying the above equation, we get

[tex]$x=\frac{40}{\cos \left(38.5^{\circ}\right)}[/tex]

x = 51.11cm

The shortest distance between the tip of the cone and its rim exits 51.11cm.

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Answer:

16 square units

Step-by-step explanation:

You find the area by multiplying the base times the height.  The base or horizonal length is 4.  You get this from the ordered point x (4,0).  The x coordinate 4, tells us that the point x is 4 spaces to the right of zero, so the length or base is 4.

The height is also 4.  You get this from the point S (2,4)  The y coordinate of 4 tells you how high up the point is.

4 x 4 = 16

Answer:

The rope is worth 13.

The shoe is worth 5.

The clock is worth 3.

Step-by-step explanation:

We know that the weights are 8 so we will use 8 for the weights.

Let s = show

Let r = rope

Let c = clock

We have three unknowns so we need three equations.

8 + s = r                      c + s = 8                                 s= c +2

There are a number of ways that we can approach this.  Let's substitute

c + 2 for s in the first 2 equations.

8 + s = r

8 + c + 2 = r

10 + c = r

c + s = 8

c + c + 2 = 8

2c + 2 = 8  

2c = 6

c = 3  we found the value of the clock.

Now, let's substitute 3 in for 3 in the bold equation above.

10 + c = r

10 + 3 = r

13 = r we found the value of the rope.

We can use any of the equations to find the shoe.

s= c + 2

s = 3 + 2

s = 5

This is tricky.  It takes a lot of practice.  Don't give up!

Shoe= 5

Rope= 13

Clock= 3

We can start by giving each item a variable. Shoe= s, rope= r, clock= c. The weight is 8, so we don't need to give it a variable. Our equations are now:

8+s= r

c+s= 8

s= c+2

Now, we can isolate a variable to solve for it using the substitution method. Let's start with s.

c+s=8

-c    -c

s= 8-c

Now, we'll take another equation and plug s in.

8-c=c+2

 +c +c

8= 2c+2

-2      -2

6=2c

c=3

Now we know that the clock is 3. Put 3 into the last equation, and add 3+2 to get 5 for the shoe. 5 in the first equation for the shoe plus 8 as the weight means the rope is 13.

hope this helped!

[tex](x-5)(x+5)-(x+1)^2\\=x^2 -25-(x^2+2x +1)\\=x^2 -25-x^2-2x -1\\=-2x-26[/tex]

ANSWER: -2x -26

Ok done. Thank to me :3

Answer:

5/222

Step-by-step explanation:

you need to add all the cards together first

13 + 10 + 8 + 6 = 37

then you take out 1 card to find the first probability of the blue card (there are 6 blue cards out of 37)

so 6/37

that will be your first probability

then for the 2nd probability, you will have 1 less card grom the deck making it only 36 cards (after taking out the first one, there will be only 5 blue cards left)

making it 5/36

that will be the 2nd probability

then you multiply both these probabilities to find the answer

6/37 × 5/36 = 5/222

The radius of cylinder = 6 meter

The height of cylinder = 11 meter

According to the question,

Surface area of the cylinder = 640.56 m²

Let the height of the cylinder = x meters

Let the radius of the cylinder = (x-5)meters

Formula for surface area of cylinder = 2πrh ( where 'r' is the radius of the cylinder and 'h' height of the cylinder)

640.56 = 2 (3.14) (x-5) (x)

640.56/(6.28) = x² - 5x

x² - 5x =102

x² - 5x - 102 =0

using quadratic equation, [-b±√(b² - 4ac)]/2a.

b = -5; a=1; c=102

x =[-(-5) ±√(-5)² - 4(1)(102)]/2

= [5 ± √433]/2

x = 11 and -7

since x=-7 neglect negative value, we get x=11.

The height of the cylinder is 11 meters

The radius of the cylinder is (11 - 5) = 6 meters.

Hence, The radius of cylinder = 6 meter.

The height of cylinder = 11 meter.

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Answer:

Step-by-step explanation:

The radius of cylinder = 6 meter

The height of cylinder = 11 meter

According to the question,

Surface area of the cylinder = 640.56 m²

Let the height of the cylinder = x meters

Let the radius of the cylinder = (x-5)meters

Formula for surface area of cylinder = 2πrh ( where 'r' is the radius of the cylinder and 'h' height of the cylinder)

640.56 = 2 (3.14) (x-5) (x)

640.56/(6.28) = x² - 5x

x² - 5x =102

x² - 5x - 102 =0

using quadratic equation, [-b±√(b² - 4ac)]/2a.

b = -5; a=1; c=102

x =[-(-5) ±√(-5)² - 4(1)(102)]/2

= [5 ± √433]/2

x = 11 and -7

since x=-7 neglect negative value, we get x=11.

The height of the cylinder is 11 meters

The radius of the cylinder is (11 - 5) = 6 meters.

Hence, The radius of cylinder = 6 meter.

The height of cylinder = 11 meter.

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Answer:$96.98

Step-by-step explanation: all you just do is to add it all up to the total amount.

Answer: $105.47

I hope you get the job!!!!!

Answer: Total = $200

Step-by-step explanation:

Given information

Money spent on shoes = $20.00

Percent of Money spent on shoes = 10%

Given formula

The total amount of money spent × Percent = Money spent on shoes

                                                      ⇵    

The total amount of money spent = Money spent on shoes / Percent

Substitute values into the given formula

The total amount of money spent = Money spent on shoes / Percent

Total = (20.00) / (10%)

Convert percentage into decimal

Total = 20.00 / 0.1

Simplify the fraction

[tex]\Large\boxed{Total~=~200~Dollars}[/tex]

Hope this helps!!  :)

Please let me know if you have any questions

The probability of the frequency of an event in repeated trials under comparable circumstances is a statistical analysis.

The study of statistics is the field that deals with the gathering, structuring, analyzing, interpreting, and presenting of data. In order to apply statistics to an issue in science, business, or society, it is customary to start with a statistical population or a statistical model that will be investigated.

Finding the distribution hidden in your data is the aim of a statistical analysis. What do you mean by the distribution that lies underlying my data? "The distribution of your data describes the peaks and valleys of its characteristics in relation to a target population.

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