Answer: It simply means that a freely falling object would increase its velocity by 9.8 m/s per second
Answer:
Hello!
"The acceleration due to gravity on the surface of the earth is 9.8 m/s ²." What does it means that
That every second an object is in free fall, gravity will cause the velocity of the object to increase 9.8 m/s. So, after one second, the object is traveling at 9.8 m/s.
Is there any change in mass of substance after it changes its state? Explain with an example
Answer:
No
Explanation:
When a substance changes its state , there will not be any change in the mass of substance . For example , if we change 100 grams of water (liquid) to ice(solid) , the mass of ice will be same i.e., 100 grams . This shows there is no change in the mass even if a substance changes its state.
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Fill in the blanks with agree or disagree
A list of planet-star radius ratios is an example of evidence.
I ____________ with this statement
Explain your answer, using an example from your investigation about habitable worlds.
A list of planet-star radius ratios is an example of evidence. I agree with this statement.
Why do i agree with the statement above?I agree with A list of planet-star radius ratios is an example of evidence because the Sample records that are taken for planet-star radius ratio are known to often gives a kind of an improved approximate of the stellar characteristics in regards to the smallest stars in the Kepler target list.
What does a planets radius mean?The planetary radius is known to be the distance that exist between a what we see as planet's center and its surface.
Therefore, one can say that planetary radius is known to be a measure of a given planet's size.
So, A list of planet-star radius ratios is a sample evidence and I do affirm the above statement.
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A 62.0-kg cheetah accelerates from rest to its top speed of 32.0 m/s. (a) How much net work is required for the cheetah to reach its top speed? (b) One food Calorie equals 4 186 J. How many Calories of net work are required for the cheetah to reach its top speed?
The energy that it needs to reach the maximum speed is 7583.4 Cal
What is the work done?In Physics, we know that the work done is the product of the force and the distance moved. However, work can be converted to energy since the both have the same dimensions. We define energy in physics as the ability or the capacity to do work.
Given these information, we know that the work done in moving the cheetah as it accelerates from the bottom to the top of the mountain is equal to the kinetic energy of the cheetah thus we can write;
W = KE = 1/2 mv^2
W= 0.5 * 62.0-kg * ( 32.0 m/s)^2
W = 31744 J
Given that;
1 calories = 4.186 J
x calories = 31744 J
x = 7583.4 Cal
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A person is losing thermal energy through the skin at a rate of 120 W when his skin temperature is 30°C. He puts on a sweater, and his skin temperature rises to 33°C. The effective thermal conductivity between his core and the environment changes from 0.22 W/m·K to 0.18 W/m·K. At what rate (J/s) is he now losing thermal energy?
The rate at which the person is now losing thermal energy is 99 J/s.
Thickness of the person's skin
The thickness of the person's skin is calculated as follows;
Q = k(ΔT)h
where;
k is thermal conductivityh is thickness of the person's skinΔT difference in temperature across the skin = 30 °C = 303 Kh = Q/k(ΔT)
h = (120) / (0.22 x 303)
h = 1.8 m
Rate at which the person is now losing thermal energyQ = k(ΔT)h
where;
ΔT is new temperature difference across the skin = 33 °C = 306 KQ = (0.18)(306)(1.8)
Q = 99 J/s
Thus, the rate at which the person is now losing thermal energy is 99 J/s.
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what is relative density of a substance
Answer:
Relative density is the ratio of the density of a substance to the density of a standard, usually water for a liquid or solid, and air for a gas.
3 A rocket of mass 1200 kg is travelling at 2000 m/s. It fires its engine for 1 minute. The forward thrust provided by the rocket engines is 10 kN (10 000 N).
(i) Use increase in momentum = F x t to calculate the increase in momentum of the rocket.
(ii) Use your answer to a to calculate the increase in velocity of the rocket and its new velocity after firing the engines.
The impulse shared by the object equals the difference in momentum of the object. In equation form,
F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.
How to calculate thrust provided by the rocket engines is 10 kN (10 000 N).?
a)There is this impulse-momentum change equation.
[tex]where m$ is the mass of a body, $F$ is a force acting to the body, $t$ is time and $D E L A T A N\}=V_{2}-V_{1}$ is the change of velocity.We consider everything is happen along a straight line, and gravitation does not participate.So, the increase of momentum is $\mathrm{F}^{*} \mathrm{t}=10000 \mathrm{~N} * 60$ seconds $=600000 \mathrm{~N}^{*} \mathrm{~s}=600000\left(\mathrm{~kg}^{*} \mathrm{~m}\right)^{*} \mathrm{~s} / \mathrm{s}^{\wedge} 2=600000 \mathrm{~kg}{ }^{*} \mathrm{~m} / \mathrm{s}$.[/tex]
We consider everything exits happen along a straight line, and gravitation does not participate.
So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.
[tex]$$\Delta(\mathrm{V})=\frac{\mathrm{F.t}}{\mathrm{m}}=\frac{600000}{1200}=500 \mathrm{~m} / \mathrm{s} .$$[/tex]
New velocity after engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.
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In a truck-loading station at a post office, a small 0.200 kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m (Figure 1). The size of the package is much less than 1.60 m, so the package can be treated as a particle. It slides down the track and reaches point B with a speed of 4.80 m/s. From point B, it slides on a level surface a distance of 3.00 m to point C, where it comes to rest.
A). What is the coefficient of kinetic friction on the horizontal surface?
b How much work is done on the package by friction as it slides down the circular arc from A to B ?
The coefficient of kinetic friction on the horizontal surface, μ = 0.39.
The work done on the package by friction as it slides down the circular arc from A to B, W = -4.176.
What is the frictional force acting on the package moving on the track?
Frictional force is the force which opposes the motion of an object over another.
Frictional force acts at the surface of contact of the objects.
The frictional force, F is related to the coefficient of kinetic friction on the horizontal surface, μ, and the normal reaction or weight, mg, of the package as follows:
F = μmg
Work done against friction, W = F * d
W = μmgd
The Kinetic energy of the package is equal to the work done against friction.
Kinetic energy of the package = mv²/2
μmgd = mv²/2
μ = v²/2gd
μ = 4.8²/(2 * 9.81 * 3)
μ = 0.39
b. Work done on the package by friction as it slides down the circular arc from A to B is given as follows:
W = mv²/2 - mgh
W = v²/2 - gh
W = 4.8²/2 - 9.81 * 1.6
W = -4.176
In conclusion, the work done by friction is lost in the form of heat.
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(a) Convert 46.0° to radians.
_______ rad
(b) Convert 17.0 rad to revolutions.
________ rev
(c) Convert 79.5 rpm to rad/s.
__________ rad/s
The answers are :
(a) 23π/90 radians ≈ 0.803 radians
(b) 17/2π revolutions ≈ 2.706 revolutions
(c) 79.5/60 rad/s = 13.25 rad/s
*The important formulas to remember*
Degrees to Radians[tex]\boxed {Radian = Degree \times \frac{\pi}{180^{o}}}[/tex]
2. Radians to Revolutions
[tex]\boxed {Revolution = \frac{Radian}{2\pi}}[/tex]
3. rpm to rad/s
[tex]\boxed {rad/s = \frac{rpm}{60}}[/tex]
A sine bar is used to determine the angle of a part feature. The length of the sine
bar=8.000in. The rolls have a diameter of 1.000 in. All inspection is performed on a surface plate. In
order for the sine bar to match the angle of the part, the following gage blocks must be stacked: 2.0000,
0.5000, 0.2500, and 0.0050. Determine the angle of the part feature.
A sine bar is used to get the angular measurement of a part feature. The angle of the part feature is 18.24°
From the question
Given that,
Length of the sine bar, L = 8.000 in
Diameter of the rolls = 1.000 in
Height under the roll, H = 2.0000 + 0.5000 + 0.0050
= 2.505 in
From sine bar formula,
we know that,
H = sin A x L
sin A = H ÷ L
where,
A ⇒ angle of part feature
H ⇒ height under the roll
L ⇒ length of the sine bar
Substituting values in the above equation,
sin A = H / L
A = sin⁻¹ ( 2.505 ÷ 8 )
A = sin⁻¹ (0.3131)
A = 18.24⁰
Hence the angle of the part feature = 18.24°
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Quark gluon plasma (qgp) is what kind of state of matter I.e. it’s equation of state is what?
a 10 kg block reaches a point with a velocity of 15 m per second and slides down a rough track my the coefficient of the kinetic energy between the two surface ab and the block iis0.52
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It is critical for scientists to be able to describe components of a system quantitatively. Explain why it is important to be able to describe a system quantitatively, using an example from your investigation about habitable worlds
A quantitative description of a system is important as it provides information about the carrying capacity of habitable worlds.
What is a quantitative description of the components of a system?Quantitative description refers to the description of a system which is focused on the numerical value of the properties or components of the system.
For example, a quantitative description of the components of a given habitat will be focused on the number of the individual species in the habitat. It will also be focused on the numerical value of the non-living components of the system and how such values affect the living components of the system numerically.
This information will then be used by scientists to see how modifications of the various quantitative components of the habitat will help to improve the chances of survival of species found in the habitat. This leads to such concepts as the carrying capacity of a habitat which is the maximum number of species that the available resources is a habitat can easily sustain.
In conclusion, a quantitative description is important to in investigations about the habitable world.
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a man carries a hand bag by hanging on his hand and moves horizontally where the bag does not move up or down. What is the work done on the bag? The man gets tired after sometime of the movement. Why
The work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.
What is the work done?In Physics, we define the work done as the product of the of force and distance. Hence, we generally define the work done as that which occurs when the force applied moves a distance in the direction of the force. This implies that the work done is not a vector but a scalar quantity.
In relation to the man and the bag, the work done is the product of the force that the man applies and the displacement of the bag. As such, the reason for the tiredness of the man is that the internal energy that he possesses is transferred to moving the bag.
Thus, the work that the man does is the scalar product of the force applied by the man and the horizontal displacement of the bag.
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progress of science has not caused any ill effect true or false?
density of a substance ratio
Answer:
Density of a substance is the ratio of mass of the substance to its volume.
Answer:
Density of a substance is the ratio of mass of the substance to its volume.
What is the mass of the sun plus all the planets in solar system?
A thin-walled hollow sphere has a radius 4cm from the center
of the sphere, the eletric field points radially inward and
has a magnitude of 1.5 × 10^4 NC". How much charge is on the surface
The electric charge on surface is 2.66×10-⁹NC
What is an electric charge?The electric charge is the property of subatomic particle that causes it to experience a force when placed in an electric and magnetic field.
We have given ,
Electric field= 1.5×10⁴N/C
Radius = 4cm = 0.04m
E = k× q/ r²
1.5×10⁴×16×10-⁴/9×10⁹=q
q= 2.66×10-⁹C
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Have my equation written out but struggling to solve. Can someone help me solve!
The solution of this system is (i₁, i₂, i₃) = (- 10.852 A, 8.479 A, - 2.374 A). The negative signs indicate that real direction of the current is opposite than supposed.
How to find the missing current in a circuit
In this question we must make use of Kirchhoff's laws to find the values of the missing currents in the circuit presented in the picture. There are two rules according to Kirchhoff's laws:
The sum of currents found at nodes of circuits is always equal to zero.The net sum of voltages in a closed loop of a circuit is always equal to zero.Based on the information given by the picture, we have the following system of linear equations that describes the entire circuit:
i₃ = i₁ + i₂
- i₁ · R₁ + ε₁ - i₁ · r₁ - i₁ · R₅ + ε₂ - i₂ · (r₂ + R₂) = 0
ε₂ - i₂ · (r₂ + R₂) - i₃ · r₄ - ε₄ - i₃ · r₃ + ε₃ - i₃ · R₃ = 0
- i₁ - i₂ + i₃ = 0 (1)
(R₁ + r₁ + R₅) · i₁ + (r₂ + R₂) · i₂ = ε₁ + ε₂ (2)
(r₂ + R₂) · i₂ + (r₄ + r₃ + R₃) · i₃ = ε₂ + ε₃ - ε₄ (3)
If we know that R₁ = 5 Ω, r₁ = 0.10 Ω, R₅ = 20 Ω, r₂ = 0.50 Ω, R₂ = 40 Ω, r₄ = 0.20 Ω, r₃ = 0.05 Ω, R₃ = 78 Ω, ε₁ = 22 V, ε₂ = 49 V, ε₃ = 10.5 V and ε₄ = 33 V, then the currents flowing in the circuit are:
- i₁ - i₂ + i₃ = 0
25.1 · i₁ + 40.5 · i₂ = 71
25.1 · i₂ + 78.25 · i₃ = 26.5
The solution of this system is (i₁, i₂, i₃) = (- 10.852 A, 8.479 A, - 2.374 A). The negative signs indicate that real direction of the current is opposite than supposed.
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What is an example of total internal reflection at work?
A.
A ray of light has the same intensity both entering and exiting a fiber optic cable.
B.
A ray of light entering a glass cube gets refracted.
C.
A ray of light in air hits a shiny surface and bounces off.
D.
A ray of light entering a ruby gets refracted.
[tex]\huge\underline{\underline{\boxed{{ \mathbb{SOLUTION:}}}}}[/tex]
[tex]\leadsto[/tex] Total internal reflection occurs when a ray of light is traveling through a medium and, when that medium changes, it does not refract into the second medium but instead it reflects back into the first medium.
By Snell's law, we know that
[tex]\longrightarrow \sf{n_1 sin \emptyset_1 = n_2 sin \emptyset_2}[/tex]
If this happens, then [tex]\sf{n_2 \angle n_1}[/tex], and the ray does not lose intensity due to refraction.
[tex]\huge\underline{\underline{\boxed{\mathbb{ANSWER:}}}}[/tex]
[tex]\large \bm{ A.}[/tex] A ray of light has the same intensity both entering and exiting a fiber optic cable.
Show that time period of revolution an electron beam in uniform magnetic field is independent of velocity and radius of path
Since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path
How to show that time period of revolution an electron beam in uniform magnetic field is independent of velocity and radius of path?For an electron moving in a uniform magnetic field, the force on the electron is given by
F = Bev where
B = magnetic field, e = electron charge and v = speed of electronAlso, this magnetic force equals the centripetal force on the electron, F'
F' = mv²/r where
m = mass of electron, v = speed of electron and r = radius of pathSince both forces are equal,
F = F'
Bev = mv²/r
Be = mv/r
We know that angular speed, ω = v/r. So,
Be = mω
Also, angular speed, ω = 2π/T where T = period of revolution of electron
So, Be = m2π/T
Making T subject of the formula, we have
T = 2πm/Be
so, since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path
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A solid, homogeneous sphere with a mass of m0, a radius of r0 and a density of ρ0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'f or s' are possible answers in some of the cases.
The new sphere has a density of ρ > ρ0 and a mass of m = m0.
The new sphere has a mass of m > m0 and a radius of r = r0.
The new sphere has a radius of r = r0 and a density of ρ > ρ0.
Based on the given data about, volume, mass, and density of the spheres;
the water level will fall; fthe water level may rise or fall; r or fthe water level will rise; rWhat determines whether an object floats are sinks in water?The density, mass, volume, and shape of an object determines whether it will float or sink in water.
Density = mass/volumeFor an object to float, it will displace its own weight of the fluid in which it floats. This is according to Archimedes' principle which states that the upward force acting on a body immersed fully or partially in a fluid, is equal to the weight of the fluid displaced.
Considering the given scenarios:
1. The new sphere has a density of ρ > ρ0 and a mass of m = m0.
This means that the volume of new sphere is smaller than the volume of the original sphere, therefore, the water level will fall,
2. The new sphere has a mass of m > m0 and a radius of r = r0.
This means that the new sphere will have a greater volume and mass. However, the density may be greater or less.. Therefore, the water level may rise or fall.
3. The new sphere has a radius of r = r0 and a density of ρ > ρ0.
The new sphere has equal volume, greater density and mass than the original sphere. Therefore, the water level will rise.
In conclusion, the level of the water in the container depends on the volume, mass and density of the object placed in it.
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A 2.0-kg projectile is fired with initial velocity components v0x = 30 m/s and v0y = 40 m/s from a point on the Earth's surface. Neglect any effects due to air resistance.
a) What is the kinetic energy of the projectile when it reaches the highest point in its trajectory?
b) How much work was done in firing the projectile?
(a) The kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.
(b) The work done in firing the projectile is 2,500 J.
Kinetic energy of the projectile at maximum height
The kinetic energy of the projectile when it reaches the highest point in its trajectory is calculated as follows;
K.E = ¹/₂mv₀ₓ²
where;
m is mass of the projectilev₀ₓ is the initial horizontal component of the velocity at maximum heightNote: At maximum height the final vertical velocity is zero and the final horizontal velocity is equal to the initial horizontal velocity.
K.E = (0.5)(2)(30²)
K.E = 900 J
Work done in firing the projectileBased on the principle of conservation of energy, the work done in firing the projectile is equal to the initial kinetic energy of the projectile.
W = K.E(i) = ¹/₂mv²
where;
v is the resultant velocityv = √(30² + 40²)
v = 50 m/s
W = (0.5)(2)(50²)
W = 2,500 J
Thus, the kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.
The work done in firing the projectile is 2,500 J.
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the meaninn of dynamics
Answer:
Dynamics is just a nice word used in physics denoting a branch of physics, related to the study of forces. Usually these forces are not in mechanical equilibrium, else the branch would be statics.
What is 2 chemical properties of acids and bases
⇒ Acids taste sour, react with metals, react with carbonates, and turn blue litmus paper red. Bases taste bitter, feel slippery, do not react with carbonates and turn red litmus paper blue.
The study of acids and bases is crucial to chemistry. The Lewis acid/base motif, which broadens the concept of an acid and base beyond H+ and OH- ions, is one of the most relevant theories.
Acids are ionic compounds, which means they have a positive or negative charge. In water, these ionic compounds separate to create hydrogen ions, or H+.
The quantity of H+ ions in the solution determines how strong an acid is. Acid is stronger the more H+ there is. Bases are ionic substances that separate in water to produce the negatively charged hydroxide ion (OH-). The quantity of Hydroxide ions in a base determines its strength (OH-). The strength of the base increases with OH- ion concentration.
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Three ropes A, B and C are tied together in one single knot K. (See figure.)
If the tension in rope A is 50.5 N, then what is the tension in rope B?
Assuming point K is held in equilibrium, by Newton's second law we have
• net horizontal force
[tex]F_C \cos\left(\tan^{-1}\left(\dfrac57\right)\right) - F_A = 0[/tex]
• net vertical force
[tex]F_C \sin\left(\tan^{-1}\left(\dfrac57\right)\right) - F_B = 0[/tex]
where the angle [tex]\theta[/tex] that rope C makes with the horizontal axis satisfies
[tex]\tan(\theta) = \dfrac{9-4}{11-4} = \dfrac57[/tex]
Solve the first equation for [tex]F_C[/tex].
[tex]F_C = F_A \sec\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
(Recall that [tex]\sec(x)=\frac1{\cos(x)}[/tex].)
Substitute this into the second equation and solve for [tex]F_B[/tex].
[tex]F_B = F_C \sin\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
[tex]F_B = F_A \sec\left(\tan^{-1}\left(\dfrac57\right)\right) \sin\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
[tex]F_B = F_A \tan\left(\tan^{-1}\left(\dfrac57\right)\right)[/tex]
(Recall that [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}[/tex].)
[tex]F_B = \dfrac57 F_A[/tex]
[tex]\boxed{F_B \approx 36.1\,\rm N}[/tex]
The Kennedy Space Center was in charge of the Apollo 13 mission.
True
False.
Identify two fields where physical quantities are used in motion calculations
The two fields were physical quantities are used in motion calculations are length and mass with time.
The physical quantity in a field is referred as every point in a particular space time.
How physical quantities are used in motion calculations?
If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.
Length, mass and time are the physical quantities used in motion calculations.
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Based on the information provided, how confident can you be that this exoplanet is able to support life as we know it?
The information is missing here but data that may support the existence of life in an exoplanet may include the discovery of atmospheric biological gases.
What is an exoplanet?An exoplanet is any planet that surrounds another star beyond the sun, and therefore they are discovered by analyzing other galaxies in the Universe.
The existence of life in these exoplanets can be indirectly supported by the presence of gases that are only produced by organisms, which are detected by suitable telescopes that analyze emission spectra.
In conclusion, the information is missing here but data that may support the existence of life in an exoplanet include biological gases.
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The revolution of the earth around the sun demonstrate what motion?
Answer:
Anticlockwise directions
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How far would you push a car if you did 28,000J of work, exerting a force of 825N?
We push a car to the distance of 33.939m if we do 28000J work , exerting a force of 825N.
What is work done and force ?work done: The amount of energy transferred to a body .Force : force is an influence that can change the velocity of an object .How to calculate distance moved from work done and force ?we know ; work done =Force ×distance moved in the direction of force Mathematically, W=F.Swhere W= work doneF = applied force
S = distance moved
So S=W/F=28000J/825N
=33.939meter
Thus, we can conclude that the distance moved by the car is 33.939m.
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A stone of weight 10N falls from the top of a 250m high cliff. a) Calculate how much work is done by the force of gravity in pulling the stone to the foot of the cliff. b) How much energy is transferred to the stone?
Answer:
work done = ( force × displacement)
(a)The force acting on the block is it's self weight and displacement is equal to height of the tower.
work done by gravity = (250 × 10) = 2500 joule
(b) The work done by gravity 2500 joule is transferred to the object in the form of it's kinetic energy.
