Step 1 of 2: Red the rational expression to its lowest terms 2 - 2x^2/2x^2 - 2Step 2 of 2: Find the restricted values of X, if any, for the given rational expression.

Step 1 Of 2: Red The Rational Expression To Its Lowest Terms 2 - 2x^2/2x^2 - 2Step 2 Of 2: Find The Restricted

Answers

Answer 1
[tex]\frac{2-2x^2}{2x^2-2}[/tex]

Step1

we can factor the numerator and denominator because we have a square subtract

[tex]\begin{gathered} \frac{(\sqrt[]{2}+\sqrt[]{2}x)(\sqrt[]{2}-\sqrt[]{2}x)}{(\sqrt[]{2}x-\sqrt[]{2})(\sqrt[]{2}x+\sqrt[]{2})} \\ \\ \frac{(\sqrt[]{2}+\sqrt[]{2}x)}{\sqrt[]{2}x+\sqrt[]{2})}\cdot\frac{(\sqrt[]{2}-\sqrt[]{2}x)}{(\sqrt[]{2}x-\sqrt[]{2})} \\ \\ 1\cdot-1 \\ \\ =-1 \end{gathered}[/tex]

step 2

restricted values of X are when the denominator is 0

then

[tex]2x^2-2=0[/tex]

factor this

[tex](\sqrt[]{2}x-\sqrt[]{2})(\sqrt[]{2}x+\sqrt[]{2})=0[/tex]

and find the value of x what make each parenthesis 0

[tex]\begin{gathered} \sqrt[]{2}x-\sqrt[]{2}=0 \\ \sqrt[]{2}x=\sqrt[]{2} \\ x=1 \end{gathered}[/tex]

first restricted value is x=1

[tex]\begin{gathered} \sqrt[]{2}x+\sqrt[]{2}=0 \\ \sqrt[]{2}x=-\sqrt[]{2} \\ x=-1 \end{gathered}[/tex]

and the other restricted value is x=-1


Related Questions

D
Question 3
If a car is traveling at 85 mph, how fast is the car traveling in feet per second? Round to 2
decimal places. (Reminder: there are 5280 feet in a mile)
1 pts

Answers

Answer:

See below

Step-by-step explanation:

85 mi/hr   *  1 hr / 3600s  *  5280 ft / mi  =

85 * 5280 / 3600 = 124  2/3  ft/s

Similarities and differences between compound event, mutually exclusive event, overlapping event, independent event, dependent event

Answers

Difference between Dependent and Independent event:

[tex]\begin{gathered} Dependent\text{ Event:} \\ The\text{ outcome of one event affects the outcome of the other.} \\ \text{If A and B are dependent events},\text{ then the probability of both occuring is:} \\ P(A\text{ and B)=}P(A)\times P(B|A) \end{gathered}[/tex][tex]\begin{gathered} \text{Independent Event:} \\ The\text{ outcome of one event does not affects the outcome of the other.} \\ \text{If A and B are independent events, then the probability }of\text{ both occuring is:} \\ P(A\text{ and B)=}P(A)\times P(B) \end{gathered}[/tex]

Write an equation and solve. A number y divided by 5.5 is equal to 86

Answers

y is divided by 5.5 and is equal to 86, so:

[tex]\frac{y}{5.5}=86[/tex]

Solve for y:

Multiply both sides by 5.5:

[tex]\begin{gathered} y=86\cdot5.5 \\ y=473 \end{gathered}[/tex]

Write 243 as a power using the number 3 as the base

Answers

Answer:

[tex]3^5[/tex]

Step-by-step explanation:

Hello! Let's help you with your question here!

So, we want to know 243 as a power using the number 3 as the base. Well, there is an easy way in figuring out to what the power would be.

We have the total and we already have the base. In order to figure out what the power number is, we can essentially just divide 243 by our base number 3, until we get to a point where we can't divide the number by 3 without getting a decimal value! So it would look like this!

[tex]243/3=81[/tex]

[tex]81/3=27[/tex]

[tex]27/3=9[/tex]

[tex]9/3=3[/tex]

[tex]3/3=1[/tex]

Now, it's just a matter of counting how many times we divided by 3 and it turns out we divided the number by 3 5 times! Therefore, we can say that:

[tex]3^5=243[/tex]

Find the slope of each line and then determine if the lines are parallel perpendicular or neither.If a value is not an integer type it in as a decimal rounded to the nearest hundredth.

Answers

ANSWERS

• Slope of line 1: ,8

,

• Slope of line 2: ,-6

,

• The lines are ,neither

EXPLANATION

The slope of a line passing through points (x1, y1) and (x2, y2) is,

[tex]m=\frac{y_1-y_2}{x_1-x_2}[/tex]

The points given for line 1 are (-8, -55) and (10, 89). The slope of this line is,

[tex]m_1=\frac{-55-89}{-8-10}=\frac{-144}{-18}=8[/tex]

The points given for line 2 are (9, -44) and (4, -14). The slope of this line is,

[tex]m_2=\frac{-44-(-14)}{9-4}=\frac{-44+14}{5}=\frac{-30}{5}=-6[/tex]

• If two lines are ,parallel, then they have the same slope.

,

• If two lines are ,perpendicular, then their slopes are opposite and reciprocal.

The slopes of these two lines are 8 and -6. These slopes are different and they are neither opposite nor reciprocal. Hence, these lines are neither parallel nor perpendicular.

A teacher received the following answer to a quiz question in which the student was asked to simplify the expression in Step 1:

Step 1: −5(x − 16y) + 7(−2x − 8y)
Step 2: −5x + 80y − 14x − 8y
Step 3: −5x − 14x + 80y − 8y
Step 4: (−14x − 5x) + (80y − 8y)
Step 5: −19x + 72y

Part A: Identify the step where the student made a mistake and explain the specific error that was made. Support your answer using the correct vocabulary. (6 points)

Part B: How would you correct the mistake? Show all your work.

Answers

The student made a mistake and explain the specific error that was made. Support your answer using the correct vocabulary. The mistake has been done in Step 2.

PART A: There is a mistake in Step 2, Distributive Property has been employed incorrectly.

7 has to multiply by both the terms inside the bracket, but it has been multiplied with the first term only.

7(-2 x-8 y)=-14 x-56 y and 7(-2 x-8 y) -14 x-8 y

Hence, -5(x-16 y)+7(-2 x-8 y)=-5 x+80 y-14 x-56 y

PART B :

The given equation is

-5(x-16 y)+7(-2 x-8 y)

Applying distributive property to the above equation that states A(B+C)=AB+AC, we get :

-5 x+80 y-14 x-56 y

Now, Writing the terms with the same variable together, we get

(-5 x-14 x)+(80 y-56 y)

Proceeding with solving terms inside the brackets according to BODMAS, we get,

-19 x+24 y

Hence , −5(x − 16y) + 7(−2x − 8y) = -19x +24y

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Kayden walks 4/5 km to a friends house. Then he and friend walk 1 3/5 km more to go fishing at their favorite pond. How far to Kayden walk all together?


PLEASE HELP THIS IS ON KHAN

Answers

7/5 km walked is how long they walked

Write a function g whose graph represents a vertical shrink by a factor of 1/2 of the graph of f(x) = 2x+6. g(x) =

Answers

Vertical shrink factor = 1/2

So, f(x) = 1/2 g(x)

[tex]\begin{gathered} g(x)=\frac{1}{2}f(x) \\ \text{ where, f(x)=2x+6} \\ g(x)=\frac{1}{2}(2x+6) \\ g(x)=x+3 \end{gathered}[/tex]

Answer : g(x) = x + 3

13. Bethany buys a used car for $9,000. She puts $600 down and finances the rest for 4 1/2 years at 5%annual interest. At the end of years, the $9000 car will have cost her $

Answers

Answer :

$11,062.40

Explanation :

The formula for the future amount in a compounding interest is :

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Where P is the present value

r is the rate of interest

n is the number of compounding in a year

t is time in years

From the given problem,

She puts a downpayment of $600 so the remaining will be :

9000 - 600 = 8400, which she will be financing for 4.5 years

So P = 8400

r = 5% or 0.05

n = 1 (Since it will only be compounding once in 1 year - annually)

t = 4.5 years

Using the formula above :

[tex]\begin{gathered} A=8400(1+\frac{0.05}{1})^{1(4.5)} \\ A=10462.40 \end{gathered}[/tex]

The value of the $9000 car after 4.5 years will be the sum of the downpayment and the future amount.

[tex]600+10642.40=\$11,062.40[/tex]

The answer is $11,062.40

The parking fee at a carnival is $1.50 for kids and $3.00 for adults. The day of the event 1700 people showed up and $3,750.00 was collected. How many children and how many adults attended??

Answers

There are 900 children and 800 adults in attendance

How to determine the number of children and adults in attendance?

The given parameters are:

Kids fee = $1.50 per kidAdult fee = $3.00 per adultNumber of people = 1700Amount collected = $3,750.00

Let the kids be x and the adults be y

So, we have

x + y = 1700

1.5x + 3y = 1750

Make y the subject in x + y = 1700

y = 1700 - x

Substitute y = 1700 - x in 1.5x + 3y = 1750

1.5x + 3(1700 - x) = 3750

So, we have

1.5x + 5100 - 3x = 3750

Evaluate the like terms

1.5x = 1350

Divide

x = 900

Recall that

y = 1700 - x

So, we have

y = 1700 - 900 = 800

Hence, the number of children and adults in attendance are 900 and 800 respectively

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Jackson and his family are driving to his grandmother's house. They have 5 of the trip left to go. Theyplan to complete the remainder of the trip over the next 3 hours. What fraction of the total trip willJackson's family travel each hour, if they drive at a constant rate?

Answers

Given:

The number of the trip =5 trips.

The number of hours = 3 hours

Jackson's family travel each hour

[tex]=\frac{The\text{ number of the trips}}{\text{The number of hours}}[/tex][tex]=\frac{5}{3}[/tex]

Hence Jackson's family travel 5/3 trip each hour.

A ball is dropped from a height of 6 feet. With each bounce, the ball rebounds to a height that is three-quarters as high as the previous bounce. Represent the height to which the ball rises after it hits the floor for the nth time using a recursive formula and an explicit formula. Recursive Formulas: anar.an-1 or an+1 =rean Explicit Formula: an = Q .m-1 Represent (using sigma notation) the total vertical distance the ball has traveled when it hits the floor for the fifth time. Calculate this distance. ? Σ ? k=? Sn 4,(1-r") 1-r

Answers

We know that each time the ball bounces it travels a distance of 3/4 the original height, that means that for each bounce the ball will rise:

[tex]a_n=\frac{3}{4}a_{n-1}[/tex]

where a_n is the height of the nth bounce and a_(n-1) is the bounce n-1 (the previous one).

Now, from this formula we know that:

[tex]a_1=\frac{3}{4}a_0=\frac{3}{4}\cdot6=\frac{9}{2}[/tex]

Therefore the explicit formula for the height of the nth bounce is:

[tex]\begin{gathered} a_n=\frac{9}{2}(\frac{3}{4})^{n-1} \\ =\frac{9}{2}\cdot\frac{4}{3}(\frac{3}{4})^n \\ =6(\frac{3}{4})^n \end{gathered}[/tex]

Then:

[tex]a_n=6(\frac{3}{4})^n[/tex]

Now, to find the total distance it travels by the fifth bounce we follow:

The first time the ball hits the ground it has traveled a distance of 6 ft.

Now, for the second bounce we have:

[tex]6(\frac{3}{4})+6(\frac{3}{4})=12(\frac{3}{4})[/tex]

(one distance up and one distance down).

For the third bounce we have:

[tex]6(\frac{3}{4})(\frac{3}{4})+6(\frac{3}{4})(\frac{3}{4})=12(\frac{3}{4})^2[/tex]

If we continue this process we notice that the ball will travel a total distance of:

[tex]6+12(\frac{3}{4})+12(\frac{3}{4})^2+12(\frac{3}{4})^4+\ldots\text{..}[/tex]

but this can be written (for an infinity number of bounces) as:

[tex]\begin{gathered} 6+12\sum ^{\infty}_{n\mathop=0}(\frac{3}{4})^{n+1} \\ =6+12(\frac{3}{4})\sum ^{\infty}_{n\mathop=0}(\frac{3}{4})^n \\ =6+9\sum ^{\infty}_{n\mathop=0}(\frac{3}{4})^n \end{gathered}[/tex]

As we said this is for an infinity of bounces if we like only five bounces then we have:

[tex]6+9\sum ^5_{n\mathop=0}(\frac{3}{4})^n[/tex]

Now to find the distance in this case we do the sum and we get appoximately 35.5928 feet.

Help me plsss I will mark brainliest

Solve for n.

−2(n − 4.5) > 11

n > 1

n < 1

n > −1

n < −1

Answers

Answer:

D. n < −1

Step-by-step explanation:

Hope this helps :))

n < -1 is the correct answer

Use the information to find a linear algebraic equation model to use to answer the question being asked. When typing your answers do not include any spaces between your characters.Meya and Eric are joking that their combined ages equal Sam’s age. If Meya is twice Eric's age and Sam is 69 yr old, what are Meya and Eric's ages?Let m= Meya's ageLet e= Eric's ageWhat equation can we make to represent the relationship between Meya's and Eric's ages? AnswerUse your relationship from the question above to create an equation to find Meya and Eric's ages: AnswerMeya's age is AnswerEric's age is Answer

Answers

Answer

Meya's age is 46 year

Eric's age is 23 years

Step-by-step explanation:

Let Meya age be m

Let Eric's age be e

The combination of Meya and Eric age is equal to Sam age

Sam age = 69 years

Meya is twice Eric's age

This implies that

m = 2e --------------- equation 1

Since the combination of their age will be equal to Sam age

m + e = 69 ------------ equation 2

To find Eric age, substitute the value of Meya age into the above equation

m = 2e

m + e = 69

2e + e = 69

3e = 69

Divide through by 3

3e/3 = 69/3

e = 23 year

Hence, Eric's age is 23 year

Since m = 2e

e = 23

m = 2(23)

m = 46 year

Evan has $580 to spend at a bicycle store for some new gear and biking outfits.
Assume all prices listed include tax.
• He buys a new bicycle for $396.95.
• He buys 4 bicycle reflectors for $7.40 each and a pair of bike gloves for $22.94.
• He plans to spend some or all of the money he has left to buy new biking outfits
for $42.10 each.

Answers

Required inequality is 47.25x ≤ 194.02.

What is inequality?

An inequality is created when two or more algebraic expressions are compared using the symbols <, >, or ≤. They represent mathematical formulas when neither side is equal.

Given Data

Evan has $580 to spend at a bicycle store for some new gear and biking outfits

He buys a new bicycle for $396.95.

• He buys 4 bicycle reflectors for $7.40 each and a pair of bike gloves for $22.94.

• He plans to spend some or all of the money he has left to buy new biking outfits for $42.10 each.

Money spend on reflectors = 4(17.33)

Money spend on reflectors = $69.32

Total money left = (580 -(285.41 + 69.32 + 31.25))

Total money left = $194.02

If she buy x biking outfits:

47.25x ≤ 194.02

Required inequality is 47.25x ≤ 194.02.

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Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=x^2+14x+20.

Answers

Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=x^2+14x+20.

we have that

the quadratic formula is equal to

[tex]x=\frac{-b\pm\sqrt[\square]{b^2-4ac}_{}}{2a}[/tex]

where

a=1

b=14

c=20

substitute the given values in the formula

[tex]\begin{gathered} x=\frac{-14\pm\sqrt[\square]{14^2-4(1)(20)}_{}}{2(1)} \\ \\ x=\frac{-14\pm\sqrt[\square]{116}_{}}{2} \\ \\ x1=\frac{-14+\sqrt[\square]{116}_{}}{2} \\ \\ x2=\frac{-14-\sqrt[\square]{116}_{}}{2} \end{gathered}[/tex]

x1 and x2 are the zeros of the quadratic equation

The solutions are real numbers

Fill in the missing angle measures. Given: ab and c d and <1 = 32°

Answers

hello

from the image given,

angle 1 = 32

[tex]\begin{gathered} \angle1=\angle8 \\ \text{reaon: alternate angles are equal} \end{gathered}[/tex][tex]\begin{gathered} \angle1=\angle3 \\ \text{reason:corresponding angles are equal} \\ \angle3=32^0 \end{gathered}[/tex][tex]\begin{gathered} \angle1+\angle5=180^0 \\ \text{reason: angles on a straight line is equal to 180}^0 \\ \angle1=32 \\ 32+\angle5=180 \\ \angle5=180-32 \\ \angle5=148^0 \end{gathered}[/tex][tex]\begin{gathered} \angle5+\angle6=180^0 \\ reason;\text{ angles on a straight line = 180} \\ \angle5=148 \\ 148+\angle6=180 \\ \angle6=180-148 \\ \angle6=32^0 \\ or\text{ we can simply say } \\ \angle1=\angle6 \\ \text{reason: opposite angles are equal} \end{gathered}[/tex][tex]\begin{gathered} \angle5=\angle2 \\ \text{reason: opposite angles are equal} \\ \angle2=148^0 \\ or\text{ we can say }\angle1+\angle2=180\text{ since they are on a straight line} \end{gathered}[/tex][tex]\begin{gathered} \angle3+\angle4=180^0 \\ \text{reason: angles on a straight line = 180} \\ 32+\angle4=180 \\ \angle4=180-32 \\ \angle4=148^0 \end{gathered}[/tex][tex]\begin{gathered} \angle4=\angle7 \\ \text{reason: opposite angles are equal} \\ \angle7=148 \end{gathered}[/tex][tex]\begin{gathered} \angle1=\angle8 \\ \text{reason; alternate angles are equal} \\ \angle8=38^0 \end{gathered}[/tex]

[tex]\begin{gathered} \angle1=\angle14 \\ \text{alternate angles are equal} \\ \angle14=32^0 \end{gathered}[/tex][tex]\begin{gathered} \angle5=\angle13 \\ \text{reason;corresponding angles are equal} \\ \angle13=148^0 \end{gathered}[/tex][tex]\begin{gathered} \angle13=\angle10 \\ \text{reason:opposite angles are equal} \\ \angle10=148^0 \end{gathered}[/tex][tex]\begin{gathered} \angle9=\angle14 \\ \text{reason:opposite angles are equal} \\ \angle9=32^0 \end{gathered}[/tex][tex]\begin{gathered} \angle12=\angle13 \\ \text{reason: alternate angles are equal} \\ \angle12=148^0 \end{gathered}[/tex][tex]\begin{gathered} \angle11+\angle12=180 \\ \text{reason:angles on a straight line equal 180}^0 \\ \angle11+148=180 \\ \angle11=180-148 \\ \angle11=32^0 \end{gathered}[/tex][tex]\begin{gathered} \angle12=\angle15 \\ \text{reason : opposite angles are equal} \\ \angle15=148^0 \end{gathered}[/tex][tex]\begin{gathered} \angle11=\angle16 \\ \text{reason: opposite angles are equal} \\ \angle16=32^0 \end{gathered}[/tex]

from the calculations above, it's evident we can use several ways to find angles in four parallel lines

nt-Facing Task StatementHere is a scatter plot that shows the years when some used cars were madeand their prices in 2016, together with the graph of a linear model for therelationship between year and price.

Answers

The slope is positive

as the line moves from 2006 to 2016, it also goes up showing an incease in car prices.

What’s the correct answer answer asap for brainlist

Answers

Answer:

Iron

Step-by-step explanation:

Just learned about this

Answer:

C. Hydrogen

Step-by-step explanation:

Carbon, Hydrogen, Oxygen, and Nitrogen are most commonly found in lipids.

if this helps you, pls leave a heart. if it dosent, im so sorry. :(

In a survey, 100 people were asked if they smoke and whether or not they exercise regularly ( more than twice a week). The results are summarized in the table below.

Answers

Explanation:

a) The % of people that do not smoke, regardless of whether or not they exercise.

= No. of people that dont smoke/total number of people

= 76/100

Answer: 76% of people do not smoke.

b) % of people that do not exercise regularly, regardless of whether or not they smoke:

= 84/100

Answer = 84% do not exercise regularly

If f (x) = 3x2 + 5x − 4, then the quantity f of the quantity x plus h end quantity minus f of x end quantity all over h is equal to which of the following?

Answers

If a function [f(x) = (3x² + 5x - 4)], then the expression [{f(x + h) - f(x)}/h] will be equal to (3h + 6x + 5).

As per the question statement, a function [f(x) = (3x² + 5x - 4)].

We are required to calculate the value of the expression [{f(x + h) - f(x)}/h].

Since, [f(x) = (3x² + 5x - 4)] given,

Then, [f(x + h) = {3(x + h)² + 5(x + h) -4}]...[substituting (x + h) in place of "x" in the equation {f(x) = (3x² + 5x - 4)}]

Or, [f(x + h) = {3(x² + 2xh + h²) + 5x + 5h - 4}]

Or, [f(x + h) = (3x² + 3h² + 6xh + 5x + 5h - 4)]

Or, [f(x + h) = (3x² + 5x + 3h² + 5h + 6xh - 4)]

Therefore, [{f(x + h) - f(x)}/h]

= [{(3x² + 5x + 3h² + 5h + 6xh - 4) - (3x² + 5x - 4)}/h]

= [{(3x² - 3x²) + (5x - 5x) - (4 - 4) + 3h² + 5h + 6xh}/h]

= [(3h² + 5h + 6xh)/h]

= [h(3h + 6x + 5)/h]

= (3h + 6x + 5)

That is, [{f(x + h) - f(x)}/h] will be equal to (3h + 6x + 5).

Function: In Mathematics, a function is an operator, which when fed with particular inputs, will perform a fixed set and sequence of operations on the input, and produce particular outputs.Expression: Expressions are mathematical statements that consist of a minimum of two terms containing numbers or variables, or both, connected by operator(s) in between, and formed as per arithmetic rules.

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Subtract the two polynomials 3x^2+7x-1 - x^2+6x-1

Answers

The polynomial (3x²+7x-1)-(x²+6x-1). The polynomial after subtraction is 2x²+x.

Given that,

The polynomial (3x²+7x-1)-(x²+6x-1)

We have to subtract the polynomial and find the polynomial.

The polynomial is nothing but algebraic expressions called polynomials include coefficients and variables. Indeterminates are another name for variables. Mathematical operations like addition, subtraction, multiplication, and positive integer exponents can be performed on polynomial equations, however division by variables cannot.

Take the polynomial,

=(3x²+7x-1)-(x²+6x-1)

We have to subtract the each terms like x² terms and x terms  and constant.

=3x²-x²+7x-6x-1+1

=2x²+x

Therefore, the polynomial after subtraction is 2x²+x.

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Give one example of how a learner on level 1 will define a rectangle.

Answers

Step-by-step explanation:

Level 1 Analysis: Describe shapes on the basis of their properties. Students learn what properties each shape has. Example: “All rectangles have 4 sides with opposite sides equal and parallel, and 4 right angles.” or “Perpendicular lines form a right angle.”

A learner on basic level one will define a rectangle by four straight lines at right angles.

A rectangle has four straight lines in which any two opposite sides are parallel and equal in length to each other and any two adjacent sides are perpendicular to each other making a right angle in between the sides.

It is a four-sided polygon having four angles in which all the internal angles are of 90 degree each. One can make a rectangle by taking 2 sets of two sticks different in length and arrange the equal sides opposite to each other making an angle of 90 degree between every adjacent side.

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one pump can empty a pool in 2 days, whereas a second pump can empty the pool in 11 days. How long will it take the two pumps, working together, to empty the pool?It will take the two pumps ___ days to empty the pool together.

Answers

Let x be the number of days it will take the two pump to empty the pool together

[tex](\frac{1}{2}+\frac{1}{11})\times x=1[/tex][tex](\frac{11+2}{22})\times x=1[/tex][tex]\frac{13}{22}x=1[/tex]

Multiply both-side by 22/13

[tex]x=\frac{22}{13}[/tex][tex]=1.6923[/tex]

write equation In standard form

15( y - 1/3 ) =x

Answers

The standard form of the linear equation 15( y - 1/3 ) = x is 3x - 45y = -15.

What is the given equation in standard form?

The standard form of a linear equation is expressed as;

Ax + By = C

Where A and B are the coefficient of x and y respectively, C is the constant term.

Given the equation in the question;

15( y - 1/3 ) = x

Multiply both sides by 3

3(15( y - 1/3 )) = 3x

First, apply distributive property to remove the parenthesis.

15( 3y - 1 ) = 3x

45y - 15 = 3x

3x = 45y - 15

Now, move all terms containing variables to the left and side of the equation and reorder the equation in form of Ax + By = C

3x - 45y = -15

Therefore, the standard form of the equation is 3x - 45y = -15.

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Which of these are equivalent to 11/4 choose all that apply

Answers

Answer: -11 ÷ 4; 11 ÷ (-4); [tex]\frac{-11}{4}[/tex]; [tex]\frac{11}{-4}[/tex]

Step-by-step explanation:

A negative divided by a negative is a positive.

A positive divided by a negative or a negative divided by a positive is a negative.

Find the value of X in the triangle below use the value to determine the value of the angles and labels up accordingly 6x+4x+2x

Answers

Answer: 15

Step-by-step explanation:

Triangle = 180 degrees

So, 6x + 4x + 2x = 180

Next, you combine like terms: 6x + 4x + 2x = 12x

Now, your equation should be 12x = 180

Then, you divided 180 by 12 and you get 15

Answer: x = 15

6. The water level of a stream has been
rising at a constant rate all day. When
the water depth was measured at noon,
it was 3 inches deep. By 4 P.M., it was 4
inches. If x represents the number of
hours since noon and y represents the
water level in inches, sketch the
relationship between x and y.

Answers

The sketch for the equation, y = 1/4x + 3, which represents the relationship between x and y is given in the diagram below.

How to Write the Equation of a Relationship?

If x and y represents two variables of a relationship, and the starting value is represented as "b", the unit rate/constant rate as "m", the equation of the relationship between x and y, in slope-intercept form, is: y = mx + b.

From the information, the two points we can derive for the relationship between x and y are:

(0, 3) which is the water level at noon.(4, 4) which is the water level at 4 pm.

Thus, we would have the following:

Constant rate/unit rate (m) = change in y / change in x = (4 - 3)/(4 - 0) = 1/4

y-intercept of the equation is the initial depth of water (b) = 3

To write the equation, substitute m = 1/4 and b = 3 into y = mx + b:

y = 1/4x + 3

The sketch for the relationship between x and y is shown in the diagram below.

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The relationship between the depth of water and time can be represented

as y = (1/4)x + 3.

What are lines and their slopes?

We know lines have various types of equations, the general type is

Ax + By + c = 0, and the equation of a line in slope-intercept form is

y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.

Given, The water level of a stream has been rising at a constant rate all day.

When the water depth was measured at noon, it was 3 inches deep.

By 4:00 pm, it was 4 inches.

From this, we can conclude the two points are (0, 3) and (4, 4).

Slope(m) = (y₂ - y₁)/(x₂ - x₁).

slope(m) = (4 - 3)/(4 - 0).

Slope(m) = 1/4.

∴ 3 = (1/4)×0 + b.

b = 3.

So, y = (1/4)x + 3.

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If f (x) = x² − 1 and g (x) = 4x − 3, find [f o g] (3) .

Answers

Answer:

(f ○ g)(3) = 80

Step-by-step explanation:

evaluate g(3) then substitute the value obtained into f(x)

g(3) = 4(3) - 3 = 12 - 3 = 9 , then

f(9) = 9² - 1 = 81 - 1 = 80

What’s the range of grades on the fifth exam that results in earning a B is _. If the highest grade is 100 then _ .

Answers

Let x be the grade of the last exam, then the average is:

[tex]\frac{71+76+88+92+x}{5}=\frac{x+327}{5}[/tex]

now, to get a B we need this to be greater or equal than 80 and less than 90, that is:

[tex]80\leq\frac{x+327}{5}<90[/tex]

Solving for x we have:

[tex]\begin{gathered} 80\leq\frac{x+327}{5}<90 \\ 5\cdot80\leq x+327<5\cdot90 \\ 400\leq x+327<450 \\ 400-327\leq x<450-327 \\ 73\leq x<123 \end{gathered}[/tex]

Therefore the range of grades on the fifth exam that results in earnings a B is

[tex]73\leq x<123[/tex]

If the highest grade is 100, then

[tex]73\leq x\leq100[/tex]

Answer:

73-100

Step-by-step explanation:

Steve has a pretty lenient grading system!  (Usually 85-93 is a B.)

He needs at LEAST an 80 , so the average of his five scores must meet this

(71+76+88+92+x)  / 5  = 80

    solve for x = 73

If he scores less than a 90 average , he will still get a B

(71+ 76 + 88+92 +x) / 5 < 90      shows x < 123  ( which he cannot score)

   so the range of scores on fifth test  to get a final grade B is   73 - 100 .

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