Answer: Your answers are
A. 1, 287 ways
B. 154,440 ways
Hope this helped :D
Please mark me brainliest
Which of the following expressions is equivalent to ab2 + 6ab + 7a3 – 14a?
(b + 7)(b + 6)(a2 – 2)
b(b + 6) + 7(a2 – 2)
a[b(b + 6) + 7(a2 – 2)]
a[(b + 7)(b + 6)(a2 – 2)]
Answer:
3rd answer is correct
Step-by-step explanation:
Take the common factor out.
[tex]a {b}^{2} + 6ab + 7a ^{3} - 14a \\ a[ {b}^{2} + 6b + 7 {a}^{2} - 14] \\ \blue{ a[b(b + 6) + 7( {a}^{2} - 2)]}[/tex]
The correct option is: a(b² + 7a² + 6b - 14), which matches the factorized form of the given expression.
The expression ab² + 6ab + 7a³ - 14a can be factored as follows:
ab² + 6ab + 7a³ - 14a
a(b² + 6b + 7a² - 14)
a(b² + 7a² + 6b - 14)
The expression b(b + 6) + 7(a² - 2) does not appear to be directly related to the given expression.
The expression a[(b + 7)(b + 6)(a² - 2)] is not equivalent to the given expression either.
The correct option is: a(b² + 7a² + 6b - 14), which matches the factorized form of the given expression.
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I cant figure this out
24 is the answer! Its all about isolation, i tried to show it a little better in the image attached. Hope this helps!!
The table shows the first five terms for two number sequences with different rules. Select the coordinate plane that has the ordered pairs properly plotted. (4 points)
A table with three columns, with the first column titled Sequence One, the second column titled Sequence Two, and the third column titled Ordered Pair. There are five rows below the heading row. Under Sequence One is the numbers six, eight, ten, twelve, fourteen. Under Sequence Two is the numbers sixteen, thirteen, ten, seven, and four. Under Ordered Pairs is the ordered pairs six and sixteen, eight and thirteen, ten and ten, twelve and seven, and fourteen and four.
The linear function of the table of values is y = -1.5x + 25
How to plot the ordered pairs?The table of values is given as:
Sequence One Sequence Two Ordered Pair
6 16 (6, 16)
8 13 (8, 13)
10 10 (10, 10)
12 7 (12, 7)
14 4 (14, 4)
From the above table of values, we can see that:
As x constantly increases by 2 i.e. +1y constantly decreases by 3 i.e. -3This means that the table represents a linear function, and the slope of the function is
m = -3/+2
This gives
m = -1.5
A linear function is represented as:
y = mx + c
This gives
y = -1.5x + c
Using the table of values, we have
16 = -1.5 * 6 + c
Evaluate the product
16 = -9 + c
Add 9 to both sides
c = 25
Substitute c = 25 in y = -1.5x + c
y = -1.5x + 25
Hence, the linear function of the table of values is y = -1.5x + 25
See attachment for the graph of the table
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Question 10 of 28
Which of the following expressions are equivalent to
2. ? Choose all that apply.
ھر - 20
A.
B.
c.
2
(3)2 - (13 )2
1
1
(x3 - 3 ) ( + 13 )
2
1
(3 - 13) (3 - 13)
مردم زمرے
2
1
D. (x3 - 3 ) ( + 13 )
Answer: A, D
Step-by-step explanation:
A) Correct. [tex](x^3)^2=x^{(3)(2)}=x^6[/tex]. Similar logic for y.
B) Incorrect. The numerators are different.
C. Incorrect. The denominators are not the same.
D. Correct. The denominators are the same by difference of squares.
30 POINTS TO WHO EVER ANSWER THIS QUESTION!!!!
If f(3x)=f(3) + f(x) then show that f(1)-f(3)-f(9) -f(27) = f (81).
The claim is wrong, or your question is incorrectly entered.
[tex]x=1 \implies f(3) = f(3) + f(1) \implies f(1) = 0[/tex]
[tex]x=3 \implies f(9) = f(3) + f(3) = 2f(3)[/tex]
[tex]x=9 \implies f(27) = f(3) + f(9) = 3 f(3)[/tex]
[tex]x=27 \implies f(81) = f(3) + f(27) = 4f(3)[/tex]
Then
[tex]f(1) - f(3) - f(9) - f(27) = 0 - f(3) - 2f(3) - 3f(3) = -6f(3) \neq 4f(3) = f(81)[/tex]
at least if [tex]f(3)\neq0[/tex].
Miranda and cyndi start hiking from the same point. miranda hikes at a heading of , or due west, and cyndi hikes at a heading of , or n e. if they both hike 4 miles/hour, approximately how far apart are they after one hour?
They are both 6.9 miles apart after one hour if they both hike 4 miles/hour
The correct option is (B)
What is the triangle?In terms of geometry, the triangle is a three-sided polygon with three edges and three vertices. The triangle's interior angles add up to 180°.
According to the given information:Miranda and Cyndi start hiking from the same point. Miranda hikes at a heading of 270° or due west, and Cyndi hikes at a heading of 30°
From the isosceles triangle:h = 4sin30
h = 4(1/2)
h = 2 miles
From Pythagoras theorem:x² = 4² - h² = 4² - 2²
x = √12
x = 3.46 miles
Total distance = 2×3.46 = 6.9 miles
Thus, they are both 6.9 miles apart after one hour if they both hike 4 miles/hour option (B) 6.9 miles is correct.
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I understand that the question you are looking for :
Miranda and Cyndi start hiking from the same point. Miranda hikes at a heading of , or due west, and Cyndi hikes at a heading of , or n e. if they both hike 4 miles/hour, approximately how far apart are they after one hour?
A) 4.3 miles. .
B) 6.9 miles
C) 8.0 miles
D) 5.7 miles
two trains are moving towards each other on the same railroad track. From this track there's an offshot peice of railroad- the length of whice is shorter than the length of the train but longer than the length of one train car. How can the trains pass eash other?
If the length of whice is shorter than the length of the train but longer than the length of one train car then the train can pass one car at a time.
Given that two trains are moving towards each other on the same railroad track. From this track there's an offshot peice of railroad- the length of whice is shorter than the length of the train but longer than the length of one train car.
We are required to find how the trains pass each other.
Two cases are there:
For each car in the shorter train
Train A leaves one of its cars on the offshot.Both trains move until train B car move the car from the offshoot the portion of track away from train A.Train B moves to allow the cycle to repeat.We assume that cars can be decoupled at any point in the train,so that any required order of cars can be preserved.We further assume that train can move any one of the A's car in addition to all of them.
The total number of cars lengths that must pass the off shoot is the product of the number of cars in both the trains.So,it does not seems to matter which train makes use of the offshoot.
Hence if the length of whice is shorter than the length of the train but longer than the length of one train car then the train can pass one car at a time.
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A quarterback throws an incomplete pass. the height of the football at time t is modeled by the equation h(t) = –16t2 40t 7. rounded to the nearest tenth, the solutions to the equation when h(t) = 0 feet are –0.2 s and 2.7 s. which solution can be eliminated and why? the solution –0.2 s can be eliminated because time cannot be a negative value. the solution –0.2 s can be eliminated because the pass was not thrown backward. the solution 2.7 s can be eliminated because the pass was thrown backward. the solution 2.7 s can be eliminated because a ball cannot be in the air for that long due to gravity.
The solution that can be eliminated is (a) the solution –0.2 s can be eliminated because time cannot be a negative value.
How to determine the solution that can be eliminated?The equation is given as:
h(t)) = -16t^2 + 40t + 7
From the question
When h(t) = 0, the values of t are
t = -0.2 and t = 2.7
The t in the function h(t) represents time
As a general rule, time cannot be negative.
This means that the solution t = -0.2 can be eliminated
Hence, the solution that can be eliminated is (a) the solution –0.2 s can be eliminated because time cannot be a negative value.
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HELPP!!!!! PLSSSS!!!!
Consider functions f and g. Select the correct answer.
f(x)=(x^4)+9x²-3
g(x)=(1/2)^(x-2)
Using a table of values, what are the approximate solutions to the equation f(x)=g(x) to the nearest quarter of a unit?
A.) x congruent to -0.25 and x congruent to 2.5
B.) x congruent to -1 and x congruent to 0.75
C.) x congruent to -0.5 and x congruent to 0.5
D.) x congruent to -0.25 and x congruent to 1.5
The following table represents a relation. X Y -3 0 0-2 5 -3 11-2 Does the table represent y as a function of c? Why or why not? No, because a number in the input is the same as a number in the output. Yes, because there are no x-values with more than one y-value. Yes, because every x-value has at least one y-value. No, because there are two inputs that have the same output.
The table represent y as a function of c, Yes because every x-value has at least one y-value.
According to the question,
X -3 0 5 11
Y 0 2 -3 -2
In order to find the table represent y as a function of c, When x = -3; y=0; x= 0 ;y=2; x= 0 y=2; x= 5 y=-3; x= 11 y=-2.
No, because a number in the input is the same as a number in the output.⇒ Above option is wrong, because a number in the input is not same as a number in the output.
Yes, because there are no x-values with more than one y-value.⇒ Above option is wrong, because there are many x-values with more than one y-value.
Yes, because every x-value has at least one y-value.⇒ Above option is correct, because every x-value has at least one y-value.
No, because there are two inputs that have the same output.⇒ Above option is wrong, because there are not two inputs that have the same output
Hence, the table represent y as a function of c, Yes, because every x-value has at least one y-value. Above option is correct, because every x-value has at least one y-value.
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which expression is simplified form of 24/27
Answer:
8/9
Step-by-step explanation:
I'm pretty sure it's that
The answer is 8/9.
First, find the HCF of 24 and 27.
24 = 8 x 327 = 9 x 3Hence, the HCF of the numbers is 3.
Then, divide both sides of the fraction by 3.
(24/3)/(27/3)8/9What is next year's expected cash flow if there is a 50/50 probability that it will be either $10 million or $60 million?
The next year's expected cash flow if there is a 50/50 probability that it will be either $10 million or $60 million is $35 million.
What is probability?Probability refers to possibilities. This branch of mathematics deals with the occurrence of a random event. The value's range is 0 to 1. The probability formula states that the ratio of positive outcomes to all other outcomes determines how likely an event is to occur.
Sum of outcomes= 410+$60=$70 million
Number of outcomes=2
As the probability is 50/50, the next year’s expected cash flow will be
10+60/(2)
=70/2
=35 million dollars.
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Angles 1 and 2 form a right angle. 2 lines form a right angle. another line extends between the 2 lines to form 2 angles. the top angle is labeled 1, and the bottom angle is labeled 2. which word describes their measures?
The word complementary describes the their measures of ∠1 and ∠2.
According to the statement
we have given that the some conditions like
Angles 1 and 2 form a right angle. 2 lines form a right angle. another line extends between the 2 lines to form 2 angles. the top angle is labeled 1, and the bottom angle is labeled 2.
And we have to find the word that describes all about the given angles.
So, For this purpose,
According the given conditions, we recall that:
Angles that are complementary angles whose sum equals 90 degrees.
A right angle equals 90 degrees.
From the information given, we know that:
m∠1 and m∠2 forms a right angle.
Since a right angle = 90 degrees, therefore:
m∠1 + m∠2 = 90° (complementary)
So, The word complementary describes the their measures of ∠1 and ∠2.
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Answer: complementary
Step-by-step explanation: took the test on edge!
Subtract the given fraction:-
[tex] \frac{3}{5} - \frac{5}{3} = [/tex]
In △MDK, m=16.4, d=22, and k=19. Identify m∠D rounded to the nearest degree. The figure shows triangle M D K. The length of side M D is k units. The length of side D K is m units. The length of side K M is d units.
Answers;
a) 46°
b) 58°
c) 76°
d) 14°
The length of the sides,MD, DK, and KM gives the measure of the angle m<D as c) 76°
Which method can be used to find the measure of angle m<D?In triangle ∆MDK, we have;
m = 16.4
d = 22
k = 19
Using cosine rule, we get;
d² = m² + k² - 2•m•k•cos(D)
Therefore;
2•m•k•cos(D) = m² + k² - d²
[tex]D = arccos \left( \frac{ {m}^{2} + {k}^{2} - {d}^{2} }{2 \cdot m \cdot k} \right)[/tex]
Which gives;
[tex]D = arccos \left( \frac{ {16.4}^{2} + {19}^{2} - {22}^{2} }{2 \times 16.4 \times 19} \right) \approx {76}^{ \circ} [/tex]
m<D = 76°The correct option is therefore;
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Answer:
76
Step-by-step explanation:
Use the Law of Cosines to find m∠D
.The figure shows the same triangle as in the beginning of the task. Angle M D K is highlighted in red.
Set up the equation for the Law of Cosines.
d2=k2+m2−2kmcosD
Substitute the given values and solve for m∠D
.222=192+16.42−2(19)(16.4)cosD
Simplify.
484=629.96−623.2cosD
Subtract 629.96
.−145.96=−623.2cosD
Divide by −623.2
0.234=cosD
Use the inverse cosine function to find m∠D
and round to the nearest degree.
The figure shows a screen of a graphical calculator. The inverse cosine of 0 point 2 3 4 is calculated. The result is 76 point 4 6 7 3 1 6 4 6.
m∠D=cos−1(0.234)≈76∘
Therefore, m∠D≈76∘
hope it helps you!
.
What is the minimum number of cards that must be drawn from an ordinary deck of cards to guarantee that you have been dealt at least three aces?
The minimum number of cards which must be drawn to get atleast 3 cards of aces is 4.
According to the given question.
We have a deck of cards.
As, we know that
The total numbers of cards in a deck = 52
Since, we have to find the minimum number of cards to be drawn so that we will get atleast 3 cards of aces.
As they have used atleast in the question so the cards can be more also so we have to reach at minimum number of cards to be drawn to guarantee atleast 3 cards of aces.
Number of suits in a standard deck= 4 (Clubs, Hearts, Diamond, Spades)
Number of aces in a suit = 1
We need atleast three cards of aces. Which means that we have 4*1 =4 cards from each suit.
Thereofre, the minimum number of cards which must be drawn to get atleast 3 cards of aces is 4.
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If f (x) = x² - 7, evaluate the following: f(12) f(-7)
Answer: f(12) = 137, f(-7) = 42
Step-by-step explanation: In a function, what you want to do is plug in the value they give you for x. This means you substitute x with the value they are looking for.
In this case, they are looking at 12 and -7. Let's do 12 first.
The equation becomes (12^2) - 7. 12^2 is 144, and 144-7 is 137.
Now we do -7. The equation becomes (-7)^2 - 7. -7^2 is 49, and 49 - 7 is 42.
Hope this helped!
Confused about this question
Answer:
17.1
Step-by-step explanation:
Plug in -1 for x, this gets you -4.
Solve 2^-4 and get .0625.
Add .0625 to 17 and get 17.0625.
The question says answer to the nearest tenth so you round the 6 up to a 1 giving you 17.1
PLEASE I NEED HELP PLEASE
Answer:
i'll give you answer.Dont worry. Since i came back from school
Volume=
Help me please thanks so much asap
Answer:
600
Step-by-step explanation:
since it is a right triangle based pyramid, 2 of them will make a cube. so, it is bwh / 2.
base = 24
width = 10
height = 5
volume = 1200
volume of pyramid = 600
20 POINTS TO SOLVE THIS ANSWER!!!
Answer:
V₁ = 104 in.³ , S₂ = 650 in. ²
Step-by-step explanation:
⇒ Ratio = 4/10 = 2/5
⇒ V₁ : V₂ = (ratio)³ = 8/125 {geometric scale}
⇒ S₁ : S₂ = (ratio)² = 4/25
∴ V₁ = 8/125 × V₂ = 1,625 in³ × 8/125 = 104 in.³
⇒ S₂ = 25/4 × S₁ = 104 in² × 25/4 = 650 in.²
PLS HELP ASAP! THX
Let g(x)= 2x^2+3x-9 and h(x)=x^2+2x-6
Find (h-g)(2.1)
The value of the polynomial difference when the value of x is 2.1 is -3.51
Difference of polynomialsPolynomials are functions that has a leading degree of 3 and above. Given the following polynomial expression below;
g(x)= 2x^2+3x-9 and;
h(x)=x^2+2x-6
Take the difference
(h-g)(x) = h(x) - g(x)
Substitute
(h-g)(x) = x^2+2x-6 - (2x^2+3x-9)
(h-g)(x) = x^2+2x-6-2x^2-3x+9
(h-g)(x) = -x^2-x+3
Substitute the value of x to have;
(h-g)(2.1) = -(2.1)^2 - 2.1 + 3
(h-g)(2.1) = -4.41 + 0.9
(h-g)(2.1) = -3.51
Hence the value of the polynomial difference when the value of x is 2.1 is -3.51
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Use the slope formula to find the slope of the line in the graph shown above.
Question 19 options:
A)
–2
B)
2
C)
–1∕2
D)
1∕2
According to the slope formula, the slope of the line shown in the picture is equal to - 1 / 2. (Correct choice: C)
How to find the slope of a line shown in a graph
In this problem we should determine the slope associated to a line described on a Cartesian plane. This information can be found by knowing the coordinates of two points and substituting on the secant line formula:
m = Δy / Δx (1)
Where:
m - SlopeΔx - Change in the independent variable.Δy - Change in the dependent variable.After a quick inspection, we find that the points (0, 3) and (6, 0) lie on the line and the slope according to the secant line formula is:
m = (0 - 3) / (6 - 0)
m = - 3 / 6
m = - 1 / 2
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How many 5-letter words can be made using exactly 5 of the letters from
TEXAS and MEXICO? Letters may only be used as many times as they appear. (For
example, XETEX is allowed. However, MATEA is not allowed, since the A appears twice
in MATEA but only once in the given words.)
The total number of ways by words are formed is 35 ways.
According to the statement
We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.
And we have to find the possible ways.
So, The given words are:
TEXAS and MEXICO
Here X = 2 and E = 2 and all other words are one time used words.
We can find possible ways by use of combination and permutation.
So,
Total number of ways = [tex]3C_{1} ^{5} + 2C_{2} ^{5}[/tex]
here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.
So,
Total number of ways = [tex]3C_{1} ^{5} + 2C_{2} ^{5}[/tex]
Total number of ways = [tex]3(\frac{5!}{1!} ) + 2(\frac{5!}{2!*3!} )[/tex]
Total number of ways = [tex]3(5) + 2(10)[/tex]
Total number of ways = 15 + 20
Total number of ways = 35.
So, The total number of ways by letters are formed is 35 ways.
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Translate each sentence into an equation.
1. One fourth of m minus six is equal to two times the sum of m and 9.
4. MARBLES Drew has 50 red, green, and blue marbles. He has six more red marbles than blue marbles
and four fewer green marbles than blue marbles. Write and solve an equation to determine how many blue
marbles Drew has.
One fourth of m minus six is equal to two times the sum of m and 9:
[tex]\dfrac{1}{4}m -6=2(m+9)[/tex]This is self-explanatory, please comment if something is unclear.
Question 2Drew has 50 marbles; red, green and blue.
Equation for this:
r + g + b = 50He has six more red marbles than blue marbles:
Equation for this:
r = b + 6He has four fewer green marbles than blue marbles:
Equation for this:
g = b - 4Substitute r and g into first equation and solve for b:
r + g + b = 50b + 6 + b - 4 + b = 503b + 2 = 503b = 48b = 48/3b = 16Drew has 16 blue marbles.
о
О A. y< x
у>4
О B. y< x
y<4
( C. y> x
у>4
о D. y> x
y<4
-5
5
5
Answer:
b
Step-by-step explanation:
B
O Yes
O No
2. (02.01 LC)
Is the following relation a function? (1 point)
{(3,-2), (1, 2), (-1,-4), (-1, 2)}
Answer:
No
Step-by-step explanation:
Each x can have only ONE y as its partner. In this relation, -1 has TWO different partners: in one point (-1,-4) the y is -4 and in another point (-1,2) the y is 2. Not a function.
Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answer:
○ 1 hour 41 minutes or more
Step-by-step explanation:
We can make two equations that represent the total amount each plumber charges.
If [tex]x[/tex] represents the number of hours they work, then:
•Total charged by Plumber A = [tex]35 + 15x[/tex]
• Total charged by Plumber B = [tex]40+12x[/tex]
Now, if Plumber A is more expensive than Plumber B, then:
Total charged by Plumber A > Total charged by Plumber B
∴ [tex]35 + 15x[/tex] > [tex]40+12x[/tex]
Now all we have to do is solve for [tex]x[/tex]:
[tex]35 + 15x[/tex] > [tex]40+12x[/tex]
⇒ [tex]35 + 15x -12x > 40[/tex]
⇒ [tex]35 + 3x > 40[/tex]
⇒ [tex]3x > 5[/tex]
⇒ [tex]x > \bf \frac{5}{3} \space\ \mathrm{h}[/tex]
[tex]\frac{5}{3} \space\ \mathrm h[/tex] is equivalent to [tex]\frac{5}{3} \times 60 \space\ \mathrm {min}[/tex] = 100 minutes, which is the same as 1h 40min.
This means if Plumber A works more than 1h 40min, they become more expensive than Plumber B.
More than 1h 40min is equivalent to '1 hour 41 minutes or more', therefore the first option is correct.
For the transformation t, what is t-1? t : (x, y) (x 4, y 3) t-1: (x, y) (x - 4, y - 3) (-4x, -3y) (x 3, y 2)
The transformation [tex]$\mathrm{T}^{-1}$[/tex] exists described as
[tex]$T^{-1}:(x, y) \rightarrow(x-4, y-3)$$[/tex]
The value of a exists -4 and value of b exists -3.
How to determine the value of [tex]$\mathrm{T}^{-1}$[/tex]?
The transformation T exists given as
[tex]$T:(x, y) \rightarrow(x+4, y+3)[/tex]
Let the transformation [tex]$\mathrm{T}^{-1}$[/tex] exists described as
[tex]$T^{-1}:(x, y) \rightarrow(x+a, y+b)$$[/tex]
If T and [tex]$T^{-1}$[/tex] exists inverses each other, then
[tex]$&T\left(T^{-1}(x)\right)=x \\[/tex]
[tex]$&T(x+a)=x \\[/tex]
[tex]$&x+a+4=x \\[/tex]
[tex]$&a=-4[/tex]
The value of a exists -4.
If T and [tex]$\mathrm{T}^{-1}$[/tex] exists inverses each other, then
[tex]$&T\left(T^{-1}(y)\right)=y \\[/tex]
[tex]$&T(y+b)=y \\[/tex]
[tex]$&y+b+3=y \\[/tex]
b = -3
The value of b exists -3.
The transformation [tex]$\mathrm{T}^{-1}$[/tex] exists described as
[tex]$T^{-1}:(x, y) \rightarrow(x-4, y-3)$$[/tex].
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