Suppose you were given the statement "All points on a rigid object have the same angular acceleration and angular speed." a. How could you use the bugs in Ladybug Revolution to test this idea?b. Is the angular displacement also the same or does it differ? Explain your reasoning

The electron's speed after traveling 1.4 cm without knowing its original speed.

The speed of an electron is the speed of light in a vacuum, which is approximately 299,792,458 meters per second. Electrons are fundamental particles, and they travel at the speed of light due to the fact that they possess no mass. They are affected by electromagnetic fields, which can cause them to accelerate or decelerate, but they will always move at the speed of light when in a vacuum.

The electron's speed after traveling 1.4 cm cannot be determined without knowing its original speed. The electron's speed is a measure of its velocity, which is the rate of change of its position. Therefore, it is not possible to calculate the electron's speed after traveling 1.4 cm without knowing its original speed.

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Height above Earth affects the gravitational potential energy of an item. We know the height of the ball lowers since it is rolling down a hill.

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The letter "x" is used to represent the stretch of a spring in physics.

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The ability to keep an object in the center of your field of view when moving from one objective to another is called parfocality.

Parfocality is an important feature of compound microscopes, as it allows you to quickly switch between objective lenses while maintaining the same field of view.

This allows you to maintain the same field of view when changing objectives and quickly switch between different magnification powers. Parfocality also prevents the image from becoming blurred when switching objectives, as the object remains in the center of the field of view.

Additionally, parfocality ensures that the object is always in the same position in the field of view, regardless of the objective used. This makes it easier to observe and compare objects at different magnifications.

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The boulder will land approximately 81.3 meters from the base of the cliff.

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Answer:

This statement is a common misconception and would be classified as misinformation. The term "global warming" is often used to refer to the overall increase in the Earth's average surface temperature, which is primarily caused by human activity, such as the burning of fossil fuels and deforestation. The term "climate change" is used to describe the broader range of changes that are occurring in the Earth's climate, including not only warming but also changes in precipitation, sea level, and other factors. While there have been periods of slower warming, the Earth's average surface temperature has continued to rise overall, and is projected to continue to do so in the future.

The measurement unit we would use to measure the distance of Australia is Kilometer.

There are various units of measurement of length and distance. But they are used on the basis of the scale of measurement or on the basis of the accuracy required to measure anything. Like meter is used to measure the dimension of a field, a ground, cricket pitch, similarly inches, or cm are used to measure the length of the cloths, size of our shoes, etc. Whereas long distance like the distance between two cities, or countries are measure by kilometer or miles. 1 kilometer is equal to 1000 meters and one mile is equal to 1061 meters.

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The vertical speed of the ball will be 0.029 m/s, when it reaches 50 meters above the ground.

The projectile speed of the ball, v = 35 m/s

Angle of projectile motion, θ = 45°

Vertical component of velocity, u = 35sin45 = 24.75 m/s

Height of the ball, h = 50 m

Let the time taken to reach the ball is t sec, then by the second equation of motion,

h = ut - 0.5gt²

50 = 24.75×t - 0.5×9.81×t²

4.905t² - 24.75t + 50 = 0

On solving t = 2.52 & 4.905

Ignoring the t = 4.905 as it is during the freefall motion, so taking t = 2.52 sec.

Now by the first equation of motion,

v = u + at

v = u - gt

v = 24.75 - 9.81 × 2.52

v = 0.029 m/s

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The equations of motion are used to find the motion characteristics of an object with time.The time it takes the motorcycle to reach the car is approximately 5.39 seconds

A) The time it takes the motorcycle to reach the car is approximately 5.39 seconds

B) The distance the motorcycle travel from the moment it starts to accelerate to the moment it catches up with the car is approximately 155 meters

The reason the above values are correct is as follows:

The given parameters are;

The initial speed of the car and the motorcycle, v₁ = 18.0 m/s

The initial distance between the motorcycle following the car = 58.0 m

The time after which the motorcycle starts to accelerate, t₁ = 5.00 secs

The acceleration of the motorcycle = 4.00 m/s²

The time at which the motorcycle catches up with the car = t₂

Required:

A) The time it takes the motorcycle to accelerate before it catches up with the car, which is to find t₂ - t₁

Method:

The distance moved by motorcycle to reach the car = The distance moved by the car in the same time + 58.0 meters

The appropriate equation of motion to use are s = u \cdot t + \dfrac{1}{2} \cdot a\cdot t^2 and d = u\cdot t

Where;

s = The distance between the motorcycle and the car = 58.0 m

u = The initial velocity of the motorcycle = 18.0 m/s

t = Δt = t₂ - t₁ = The time the motorcycle accelerates

a = The acceleration of the motorcycle = 4.00 m/s²

d = The distance moved by the car

By the method, we have;

s = d + 58.0

u \cdot t + \dfrac{1}{2} \cdot a\cdot t^2 = u \cdot t

Plugging in the values into the equation gives;

(18.0 \times t) + \dfrac{1}{2} \times 4 \times t^2 = (18.0 \times t) + 58.0

Cancelling the like term, (18.0 × t), on both sides of the equation gives;

\dfrac{1}{2} \times 4 \times t^2 = 58.0

2\cdot t^2 = 58.0

t = \Delta t = \sqrt{\dfrac{58.0}{2} } = \sqrt{29} \approx 5.39

The time it takes the motorcycle to reach the car, t ≈ 5.39 second

The time it takes the motorcycle to reach the car is approximately 5.39 seconds

B) Required:

The distance the motorcycle travels from the moment it starts to accelerate, t₁ to the time it catches up with the car, t₂

Method:

The distance travelled during the time interval t₂ - t₁ should be calculated

The distance, s, travelled during the time interval t_2 - t_1 = \Delta t = t is given as follows;

s = u \cdot t + \dfrac{1}{2} \cdot a \cdot t^2

From part (A), u = 18.0 m/s t = \sqrt{29} s, and a = 4.00 m/s², therefore;

s = 18.0 \times \sqrt{29} + \dfrac{1}{2} \times 4.00 \times (\sqrt{29} )^2 \approx 154.933

Rounded to three significant figures, the distance the motorcycle travel, s = 155 meters

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Answer:

it is in the direction of flow of elections

Without gravity, a projectile would climb vertically by a factor equal to time times the vertical component of its starting velocity (viy• t). It will fall 0.5 g t2 distance in the presence of gravity.

h = v 0 y 2 2 g . The maximum height a projectile can reach above its launch site is defined by this equation, which only depends on the vertical component of the starting velocity.

In a vertical launch, an object is sent up or down vertically from a height H without taking into account any air resistance or other obstacles. It is a uniformly accelerated rectilinear motion (u.a.r.m.) where gravity serves as the acceleration.

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The law that governs the conservation of electric charge in a closed system is known as the law of conservation of charge.

According to this law, the total amount of electric charge in a closed system remains constant and cannot be created or destroyed. As for how objects can change their charges in a closed system, it is because the distribution of electric charge can change.

For example, when two objects with different electric charges are brought into contact, electrons can flow from one object to the other until both objects have the same electric potential. This transfer of electrons results in a change in the charge of each object, but the total charge remains the same.

Another way objects can change their charges is through the process of ionization, where an atom loses or gains electrons, resulting in a change in the electric charge of the atom. Again, the total charge remains constant, as the lost or gained electrons must go somewhere.

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A) E = k * Q / R^2, electric field strength is maximum at R. B) Electric field strength at this point is E is k * Q / R^2 = k * Q / R^2,

A quantitative expression of the intensity of electric field at a particular location is called electric field strength.

A) Electric field strength is maximum at a distance of R from the ring, along the z-axis and the expression for the electric field strength can be given as: E = k * Q / R^2

k is Coulomb's constant and R is distance from the center of ring to the point where electric field is being calculated. Hence, the electric field strength is maximum at R.

B) Electric field strength at a distance of R from the center of the ring along the z-axis can be expressed as: E = k * Q / R^2

k is Coulomb's constant and R is radius of  ring. Hence, the expression for the electric field strength at the point where it is maximum is:

E is k * Q / R^2 = k * Q / R^2,

k, Q, and R are variables and value of k is constant, equal to 8.99 * 10^9 N * m^2 / C^2. Variables Q and R are total charge on the ring and the radius of the ring respectively.

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The values for the molar volume obtained from the two reactions are very close, and we can conclude that the molar volume of the gas produced in the reactions is approximately 5.3 × 104 L/mol at 21.5°C.

The molar volume of a gas can be calculated by dividing the volume of the gas by the number of moles of gas produced. To compare the values for the molar volume obtained from the two reactions, we need to determine the number of moles of gas produced in each reaction.

For experiment 1, the mass of zinc added was 0.100 g, and the molar mass of zinc is 65.38 g/mol, so the number of moles of zinc added is 0.100 g / 65.38 g/mol = 0.00153 mol. The volume of gas produced in the reaction is given by the volume in the gas syringe, which is 36.81 ml. At 21.5°C and 1 atm, 1 ml of a gas has a volume of 22.4 liters, so the volume of gas produced in the reaction is 36.81 ml * 22.4 L/ml = 817.24 L. Therefore, the molar volume of the gas produced in experiment 1 is 817.24 L / 0.00153 mol = 5.30 × 104 L/mol.

For experiment 2, the mass of zinc added was 0.200 g, and the molar mass of zinc is 65.38 g/mol, so the number of moles of zinc added is 0.200 g / 65.38 g/mol = 0.00306 mol. The volume of gas produced in the reaction is given by the volume in the gas syringe, which is 73.64 ml. At 21.5°C and 1 atm, 1 ml of a gas has a volume of 22.4 liters, so the volume of gas produced in the reaction is 73.64 ml * 22.4 L/ml = 1634.48 L. Therefore, the molar volume of the gas produced in experiment 2 is 1634.48 L / 0.00306 mol = 5.31 × 104 L/mol.

As we can see, the values for the molar volume obtained from the two reactions are very close, and we can conclude that the molar volume of the gas produced in the reactions is approximately 5.3 × 104 L/mol at 21.5°C.

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The complete question is:

Calculate and compare the value for the molar volume at 21.5 °C obtained based on the data for the first reaction with the value for the molar volume at 21.5 °C obtained using the second reaction. The molar mass of Zn is 65.38 g/mol. experiment 1 HCL: 45 ml Zn: 0.100 g pressure before zinc was added to HCL: 1.000 atm pressure after: 1.138 atm temp before: 21.5 C temp after: 22.3 C volume in gas syringe: 36.81 ml experiment 2 HCL: 45 ml Zn: 0.200 g pressure before zinc was added to HCL: 1.000 atm pressure after: 1.277 atm temp before: 21.5 C temp after: 23.0 C volume in gas syringe: 73.64 ml.

If 30 J are added by heat to water at 12 °c, the change in entropy is calculated to be 0.105 J/K.

Entropy is the measure of disorder in a system, it tells about how much energy is not available to do work.

Mathematically, entropy is Δs = Q/T

where,

Q is heat transferred

T is temperature in kelvin

Δs is change in entropy

Heat energy Q is given as  30 J.

Temperature T = 12 + 273 = 285 K

Δs = Q/T = 30/285 = 0.105 J/K

Thus, if 30 J are added by heat to water at 12 °c, the change in entropy is calculated to be 0.105 J/K.

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The value "z = 1.0" is given to a galaxy redshift, which is a measurement of how much the galaxy's light's wavelength has been distorted as it travels through the expanding cosmos.

Redshift is expressed as a fractional value "z", where z = (λ observed - λ emitted) / λ emitted. In this case, "z = 1.0" means that the observed wavelength of light from the galaxy has been stretched by a factor of 1 (i.e., the wavelength has doubled). Redshift is typically measured using spectroscopy, which involves splitting the light from the galaxy into its individual spectral lines and comparing the observed wavelengths to the wavelengths of the same spectral lines in a laboratory or a theoretical reference spectrum. By measuring the redshift of a galaxy, astronomers can determine its distance from us and its motion relative to us. The interpretation of a redshift as a measure of distance is based on the idea that the universe is expanding, and that the farther away a galaxy is from us, the faster it will be moving away from us due to the expansion of the universe. This leads to an increase in the observed wavelength of its light (i.e., redshift), which can be used to estimate the galaxy's distance.

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The capacitance of a parallel-plate capacitor made of two 4.0 cm x 4.0 cm metal plates if the plates are separated by 5.0 mm is 0.073 F (or 73 nF).

The capacitance of a parallel-plate capacitor can be calculated using the formula:

C = ε_0 × A / d

where:

C is the capacitance in Farads

ε_0 is the vacuum permittivity constant (8.854 x 10⁻¹² F/m)

A is the area of each plate in square meters

d is the distance between the plates in meters

So, for the given parallel-plate capacitor:

A = 4.0 cm x 4.0 cm = 0.04 m x 0.04 m = 0.0016 m²

d = 5.0 mm = 5.0 x 10⁻³ m

C = ε_0 × A / d

C = 8.854 x 10⁻¹² F/m * 0.0016 m² / 5.0 x 10⁻³ m

C = 0.073 F (or 73 nF)

Therefore, the capacitance is 0.073 F (or 73 nF)

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A 42-year-old lady is prescribed a diagnostic mammography by a doctor. On a routine screening mammography, abnormal tissue was discovered. Values for the CBC, blood markers, or blood chemistry were abnormal.

An x-ray of a breast for diagnostic purposes is called mammogram.

As cancer cells are less specialised than healthy cells, they create abnormal proteins.

If cancer has been indicated by a suspicious lump or abnormal blood tests, then the type of body imaging which is next step is called diagnostic mammogram.

Chemotherapy functions to combat cancer because it targets characteristics of fast growing cancer cells. This means they target specific points of the cell cycle to stop cell division.

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For seals and diaphragms in water lubricated bearings, rubber is an excellent material to use.

For seals and diaphragms in water lubricated bearings, rubber is an excellent material to use due to its properties of elasticity, flexibility, and durability. Rubber is able to withstand the pressure and wear caused by water movement, and its elasticity allows it to maintain a tight seal against the bearing surfaces.

Titanium alloys are known for their strength and corrosion resistance, but they may not have the necessary elasticity and flexibility for use as seals and diaphragms in water lubricated bearings. Silicon is commonly used in the electronics industry, but it may not have the necessary properties for use in these types of bearings. Uranium is a highly radioactive material and is not appropriate for use in seals or diaphragms in any type of machinery. Therefore, the answer is (a) rubber.

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Other information needed to determine the final momentum of the dumpster is : the initial velocity of the cart.

In physics, collision is any event in which two or more bodies exert force on each other in relatively short time. Although, most common use of the word collision refers to incidents in which two or more objects collide with great force, scientific use of the term implies nothing about the magnitude of force.

Collision is a short-duration interaction between two bodies or more than two bodies simultaneously causing change in the motion of bodies involved due to the internal forces acted between them during this.

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The age of the Earth and the moon are nearly identical, as believed, unlike the Earth, however most of the rock found on the moon are older than that found on the Earth. This is because, unlike the moon has no atmosphere to weather rocks or plate tectonic activity to destroy rocks.

The movement of tectonic plates in the Earth's lithosphere and the eruption of volcanoes effectively recycles the rock on the surface, by consuming or burying the older rocks while creating the new ones. Over a period of time, some of the Earth's oldest rocks have been eroded through the action of air and water, both.

In contrast to bodies like the Moon and Mercury have remained essentially static for the time of billions of years. So, on them we see old surfaces which are heavily populated by craters that are formed from the massive meteoric impacts early in the history of the Solar System. These bodies are valuable as an enduring record of the history.

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The velocity of the object is A√(k/3m), when its potential energy is 2/3E.

For simple harmonic motion,

kinetic energy + potential energy = total mechanical energy

When the displacement is maximum, = A, then kinetic energy will be zero, so total mechanical energy will be only potential energy = E

E = 0.5kA²

The spring constant is k, and the maximum displacement is A.

When potential energy is 2E/3, so kinetic energy would be K = E - 2E/3

K = E/3 = kA²/6

Let the velocity of the object is v.

0.5 mv² = kA²/6

v² = kA²/3m

v = A√(k/3m)

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--The given question is incomplete, the complete question is:

"An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement from equilibrium is A and the total mechanical energy of the system is E.

What is the object's velocity when its potential energy is 2/3E?"--

No, because motion is relative.

Without a frame of reference, it is impossible to characterise the motion of the body. Motion is always described in relation to a chosen frame of reference since it is relative.

The frames of reference on this page are all classical (i.e., Special Relativity's effects are disregarded), and inertial (meaning the frames are not accelerating relative to one another). In all inertial frames, the laws of physics are the same (this is known as Galilean invariance). To put it another way, you cannot conduct an experiment to establish which reference frame you are in (Einstein used this hypothesis to devise the theory of Special Relativity). This implies that we can approach problems and provide a comparable answer in any reference frame.

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Option (A) and (B) -Duration of magnetic polarity event -rate at which the plates are moving away from mid-ocean ridge.

What determines the polarity of a magnet?

Electrons flow in the opposite direction through the wire, from negative to positive. However, the direction of the current determines the polarity of the electromagnetic field. The charge moves to the negative pole, which is the north pole of the magnet.

What is the definition of magnetic polarity?

All magnets have north pole and a south pole. The magnetic pole is strongest part of magnet. The north and south poles of a magnet attract each other. The two south poles and the two north poles repel each other. A magnetic field is area around a magnet that attracts or repels objects.

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The speed of the ball having mass 1.15 kg and this 2.15 kg is 3.48m/s and 1.06m/s respectively after collision.

The ball having a mass of 1.15 kg is moving at a speed of 5m/s to the right and it hits A ball of mass 2.15 kg head on travelling with a speed of 3.5m/s to the left if the collision is elastic collision, then the speed of the balls after collision will be given by the formula,

v = 2mu/(M+m)

V = (M-m)U/(M+m)

Here,

m = 1.15 kg,

M = 2.15 kg,

u = 5m/s,

U = 3.5m/s.

v is speed of ball moving to right after collision and V is the speed of ball having mass 2.15 kg moving left after collision.

Putting values,

v = 3.48m/s and,

V = 1.06m/s.

So, the speed of the ball having a mass 1.15 kg after collision is 3.48m/s and the speed of the ball having mass 2.15 kg of the collision is 1.06m/s.

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Both copper and silver are good conductor of electricity but only copper is used for making electrics wire and not silver because silver is expensive material when compared to copper.

Despite the fact that silver is an excellent heat conductor, it is not used in the production of electrical wire because of its high cost. Silver is a valuable metal that is used to make jewelry, high-value coins, and electroplating. Because of this, silver is not used to make electric wires. When it is exposed to air, silver quickly oxidizes and becomes tarnished.

Copper is nearly always utilized because of its low cost and the fact that it is an adequate conductor for the majority of uses. In comparison to copper, silver has a resistivity that is just marginally lower; yet, due to its higher density, the two elements are almost comparable in terms of their ratio of resistivity to mass.

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The peak radiation of a star with a temperature of 10,000 K will occur at a wavelength of approximately 0.3 micrometers.

Generally, The peak wavelength of a blackbody's radiation is inversely proportional to its temperature.

This means that as the temperature of the blackbody increases, the wavelength of its peak radiation decreases.

In this case, the temperature of the star is higher than our sun, so its peak radiation will occur at a shorter wavelength.

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Answer:

It takes the object 2.581 seconds to reach the bottom of the plane.

Explanation:

We will need to use Newton's Second Law to answer this question.

According to Newton's Second Law, acceleration is directly proportional to the net force and inversely proportional to the object's mass. Therefore the acceleration of an object depends on the mass of the object and the amount of force applied.

[tex]F_{net}=ma[/tex]

Lets identify all the forces affecting the motion of the object.

The force due to gravity has two components; the horizontal (parallel) and vertical (perpendicular).

The force parallel to the plane trying to accelerate the block down the plane is

[tex]mg\sin \theta[/tex]

The perpendicular force balances out with the normal force. The normal force is equal to the force of the object perpendicular to the plane.

[tex]mg\cos\theta[/tex]

We also have a force opposing the motion of the object; the force due to friction. The formula for the force due to friction is

[tex]F_F=F_N\mu[/tex]

[tex]F_F=\mu mg\cos \theta[/tex]

We can say the net force of the object is

[tex]ma=mg\sin \theta -\mu mg\cos \theta[/tex]

We can simplify this by cancelling the common factor of [tex]m[/tex].

[tex]a=g\sin \theta - \mu g\cos \theta[/tex]

We are given

[tex]\theta=30 \textdegree\\\mu=0.3\\h=4\\g=10[/tex]

Substituting our values into the equation gives us

[tex]a=10*\sin 30- 0.3* 10*\cos 30[/tex]

Acceleration

Lets simplify.

[tex]a=10*\frac{1}{2} - 0.3* 10*\cos 30[/tex]

[tex]a=10*\frac{1}{2} - 0.3* 10*\frac{\sqrt{3} }{2}[/tex]

[tex]a=5- 0.3* 10*\frac{\sqrt{3} }{2}[/tex]

[tex]a=5-3*\frac{\sqrt{3} }{2}[/tex]

[tex]a=5-\frac{3\sqrt{3} }{2}[/tex]

[tex]a=2.402[/tex]

Plane Length

We are given the angle and the side opposite to the angle.

We can use the SIN function to evaluate the length of the plane.

[tex]O[/tex] is the opposite side (height)

[tex]H[/tex] is the hypotenuse (plane length)

[tex]\sin \theta=\frac{O}{H}[/tex]

Solving for [tex]H[/tex] gives us

[tex]H=\frac{O}{\sin \theta}[/tex]

Given

[tex]O=4\\\theta=30[/tex]

[tex]H=\frac{4}{\sin 30}[/tex]

[tex]H=\frac{4}{\frac{1}{2} }[/tex]

[tex]H=4*2[/tex]

[tex]H=8[/tex]

The length of the plane is 8 meters.

Time

We can evaluate the time using this motion equation.

[tex]\Delta x=v_ot+\frac{1}{2} at^2[/tex]

We are given

[tex]\Delta x=8\\v_o=0\\a=2.402[/tex]

Substituting our values into the equation gives us

[tex]8=0*t+\frac{1}{2} *2.402*t^2[/tex]

Lets simplify and evaluate [tex]t[/tex].

[tex]8=\frac{1}{2} *2.402*t^2[/tex]

[tex]8=1.201*t^2[/tex]

[tex]\frac{8}{1.201}=t^2[/tex]

[tex]6.66=t^2[/tex]

[tex]\sqrt{6.66}=t[/tex]

[tex]2.581=t[/tex]

The altitude of the satellite is 883.89 km

Generally, The Rayleigh criterion for resolution states that the minimum angle, θ, between two point sources that can be resolved is given by:

θ = 1.22 * λ / D

where

λ is the wavelength of light and

D is the diameter of the lens.

The minimum distance, d, between two point sources that can be resolved is given by:

d = θ * L

where

L is the distance from the lens to the image.

Given the green lights have a wavelength of 508 nm, we can convert it to meters:

λ = 508 * 10^-9 m

Given the diameter of the lens is 49.8 cm, we can convert it to meters:

D = 49.8 cm * (1 m / 100 cm)

= 0.498 m

Using the Rayleigh criterion, we can find the minimum resolvable angle:

θ = 1.22 * λ / D

= 1.22 * 508 * 10^-9 / 0.498

= 1.24449799*10^{-6} radians

We know the lights on the satellite are spaced 1.1 m apart, so:

d = 1.1 m

Solving for the distance from the lens to the image, L:

L = d / θ

= 1.1 m / 1.24449799*10^{-6} radians

=883890.53 m

Finally, converting the distance to kilometers:

L = 883890.53 m * (1 km / 1000 m)

= 883.89 km

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(1) The time of the second occurrence is 2.92 s (2) displacement is 29.24 m (3) velocity of the particle is 4.86 m/s (4) the time of second occurence is 2.94 s.

Given z = c1t^2 - c2t^3 and c1 = 2.12 m/s^2 and c2 = 3.29 m/s^3.

1) The particle is at z = 0 twice. To find the second occurrence, we set z = 0 and solve for t:

0 = 2.12t^2 - 3.29t^3

This is a cubic equation and can be solved using numerical methods or by using a computer algebra system.

The second solution is approximately t = 2.92 s.

2) The displacement of the particle between 2 s and 5 s can be found by finding the final position minus the initial position:

Δz = z(5s) - z(2s) = (2.12 × 5^2 - 3.29 × 5^3) - (2.12 × 2^2 - 3.29 × 2^3)

Δz = 29.24 m

3) The velocity of the particle is given by the derivative of the position function, so we can find the velocity at t = 0.657 s as:

v = dz/dt = 2c1t - 3c2t^2 = 2 × 2.12 × 0.657 - 3 × 3.29 × 0.657^2

v = 4.86 m/s

4) The velocity is at 0 twice. To find the second occurrence, we set v = 0 and solve for t:

0 = 2 × 2.12t - 3 × 3.29t^2

This is a quadratic equation and can be solved using the quadratic formula or by using a computer algebra system.

The second solution is approximately t = 2.94 s.

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Question - A particle moves in such a way that its position z, in meters, is given as a function of t, in seconds, by the equations z=c1t^2-c2t^3

1) The particle is at 0 twice. What is the time of the second occurrence of z=0 in seconds?

2) What is the displacement(m) of the particle between 2sec and 5 sec?

3) What is the velocity of the particle at t=0.657s? The velocity is also at 0 twice.

4) What is the time of the second occurence?