T/F The reason that atomic numbers are always integer values is because every element has:a particular number of protons

Answers

Answer 1

This statement is True. The atomic number of an element represents the number of protons in its nucleus, which is an integer value. Therefore, the reason that atomic numbers are always integer values is that every element has a particular number of protons.

The reason atomic numbers are always integer values is that every element has a particular number of protons, and the atomic number represents the number of protons in the nucleus of an atom of that element.

Since protons are discrete particles, the atomic number must be an integer value.

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Related Questions

What are the charges on the copper and phosphide ions, respectively, in copper(II) phosphide?
2+, 3-
2-, 3+
2+, 1-
2-, 1+

Answers

The charges on the copper and phosphide ions in copper(II) phosphide are 2+ and 3-, respectively. This means that copper has lost two electrons, giving it a positive charge, while phosphide has gained three electrons, giving it a negative charge.

To understand why this is the case, we need to look at the chemical formula of copper(II) phosphide, which is Cu3P2. This tells us that there are three copper ions (Cu2+) and two phosphide ions (P3-) in each unit of the compound. The Roman numeral II in the name of copper(II) phosphide indicates that copper has a +2 oxidation state, meaning that it has lost two electrons. The phosphide ion (P3-) has a -3 charge because it has three more electrons than protons.

When copper and phosphide ions combine to form copper(II) phosphide, they do so in a way that allows them to achieve a stable electron configuration. Copper loses two electrons to become Cu2+, while phosphide gains three electrons to become P3-. The resulting compound, Cu3P2, has a neutral charge because the total positive charge of the copper ions (3 x 2+) balances out the total negative charge of the phosphide ions (2 x 3-). In summary, the charges on the copper and phosphide ions in copper(II) phosphide are 2+ and 3-, respectively, because of the way in which they combine to form a stable compound.

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what functional group is always found in alkaloids (such as caffeine, nicotine, and digitalis)?

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The functional group that is always found in alkaloids, including caffeine, nicotine, and digitalis, is the nitrogen-containing heterocyclic group. Alkaloids are a diverse group of naturally occurring organic compounds primarily derived from plant and animal sources.

They have a wide range of pharmacological effects on humans and other animals due to their complex chemical structures and biological activity. The nitrogen atom in the heterocyclic group plays a crucial role in the chemical properties and biological activities of alkaloids. This functional group is often responsible for the basicity of alkaloids and can form various types of bonds with other molecules, contributing to their wide range of interactions within biological systems.

In conclusion, the functional group consistently found in alkaloids is the nitrogen-containing heterocyclic group. This group plays a significant role in the chemical properties and biological activities of these compounds, enabling their diverse effects on living organisms.

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Rank the following systems in order of entropy Most х 10 molecules in 10 slots 7 molecules in 10 slots Х 5 molecules in 10 slots Х 2 molecules in 10 slots Least

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Entropy is a measure of the disorder or randomness of a system. The order of entropy, from most to least, would be:
1. Most - 10 molecules in 10 slots
2. 5 molecules in 10 slots
3. 7 molecules in 10 slots
4. 2 molecules in 10 slots
5. Least - 1 molecule in 10 slots


The reason for the following ranking is based on the concept of entropy, which is a measure of the disorder or randomness of a system. The more molecules there are in a given number of slots, the greater the possible number of configurations or arrangements those molecules can take on, increasing the entropy of the system. Conversely, the fewer molecules there are in a given number of slots, the fewer possible arrangements there are, resulting in lower entropy.

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Please help, I have no clue how to solve this lol

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When 15.5 moles of [tex]HNO_3[/tex] are consumed, 72.06 grams of water can be produced.

The balanced chemical equation for the reaction between copper and nitric acid is:

[tex]3Cu + 8HNO_3\ - > 3Cu(NO_3)_2 + 2NO + 4H_2O[/tex]

Therefore, to calculate the amount of water produced, we first need to determine how many moles of [tex]HNO_3[/tex] are consumed when 15.5 moles are present:

Moles of [tex]HNO_3[/tex] consumed = 8/15.5 x 15.5 moles = 8.00 moles

Stoichiometry  can be used to calculate the amount of water produced:

Moles of [tex]H_2O[/tex] produced = 4/8 x 8.00 moles = 4.00 moles

Calculating mass of water produced using its molar mass:

Mass of [tex]H_2O[/tex] produced = moles of [tex]H_2O[/tex] produced x molar mass of [tex]H_2O[/tex]

Mass of [tex]H_2O[/tex] produced = 4.00 moles x 18.015 g/mol = 72.06 g

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--The complete Question is,3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O

In the above equation how many grams of water can be made when 15.5 moles of HNO3 are consumed? --

a sample of air from a home is found to contain 4.3 × 10-6 of carbon monoxide. this means that if the total pressure is 695 torr, then the partial pressure of co is ________ torr.

Answers

The partial pressure of CO in the sample of air is 3.00 × 10-3 torr.

The first step to finding the partial pressure of CO is to use the mole fraction of CO in the air sample.

The mole fraction of CO can be calculated by dividing the number of moles of CO by the total number of moles of gas in the sample.

Using the ideal gas law, we can then calculate the partial pressure of CO.
To find the mole fraction of CO, we need to convert the concentration of CO to moles.

We can do this by multiplying the concentration (4.3 × 10-6) by the volume of the air sample. Let's assume the air sample has a volume of 1 L. This gives us:
nCO = (4.3 × 10-6 mol/L) × (1 L) = 4.3 × 10-6 mol
Next, we need to find the total number of moles of gas in the air sample.

We can use the ideal gas law for this:
nTotal = PV/RT = (695 torr) × (1 L) / [(0.08206 L·atm/mol·K) × (298 K)] = 27.69 mol
Now we can calculate the mole fraction of CO:
XCO = nCO / nTotal = (4.3 × 10-6 mol) / (27.69 mol) = 1.55 × 10-7
Finally, we can use the ideal gas law again to find the partial pressure of CO:
PCO = XCO × PTotal = (1.55 × 10-7) × (695 torr) = 3.00 × 10-3 torr


Summary: The partial pressure of CO in the air sample is 3.00 × 10-3 torr. This was found by first calculating the mole fraction of CO, then using the ideal gas law to find the partial pressure.

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select the correct name for k2[co(cn)4].

Answers

Answer:diaquabisethylenediaminenickel(II) bromide

Explanation:

The correct name for the compound K₂[Co(CN)₄] is potassium tetracyanocobaltate(II) IUPAC regulations.

There are certain guidelines for the naming of organic compounds known as IUPAC regulations. Depending on the length of the carbon atom chain, a compound's number is determined. The location of any double or triple bonds or any functional groups is specified before the numbering begins.

The name is supplied in the functional group prefix alphabetical order, and the numbering is set up so that the carbons that contain the functional groups have low numbers.

The longest chain of the given chemical has five carbons. The third carbon has an Co group connected to it, while the second and fourth carbons each have two methyl branches. Consequently, the substance is known as potassium tetracyanocobaltate(II).

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Help please!!!!
Describe why it is important to know the conditions under which an aqueous
oxidation‐reduction reaction takes place in order to balance the ionic equation for
the reaction.

Answers

The chemical reactions in which oxidation and reduction reactions occur simultaneously are defined as the redox reactions. An oxidation-reduction reaction is also called a redox reaction.

A reaction which involves loss of electrons is known as oxidation whereas a reaction which involves gain of electrons is called the reduction. Oxidation can occur only if reduction also takes place side by side and vice versa.

An ionic equation is a chemical equation in which the formula of dissolved aqueous solutions are represented as individual ions. So an oxidation‐reduction reaction takes place in order to balance the ionic equation.

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how many total (or composite) atoms are contained in a unit cell of primitive cubic arrangement?

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A unit cell of a primitive cubic arrangement contains only one atom. The number of total or composite atoms contained in a unit cell of a primitive cubic arrangement depends on the type of unit cell being considered.

Firstly, a unit cell refers to the smallest repeating unit of a crystal lattice. In a primitive cubic arrangement, each corner of the cube contains one atom. Therefore, a unit cell of a primitive cubic arrangement contains only one atom.

However, if we are considering a composite unit cell, which is made up of multiple primitive unit cells stacked together, then the number of atoms contained in a unit cell would depend on the stacking arrangement. For example, a body-centered cubic (BCC) unit cell contains two atoms - one at each of the eight corners and one in the center of the cube. Similarly, a face-centered cubic (FCC) unit cell contains four atoms - one at each of the eight corners and one at the center of each face.

In summary, the number of total or composite atoms contained in a unit cell of a primitive cubic arrangement depends on the type of unit cell being considered.

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some particulates absorb the water vapor around them. they are said to be ________. A) hygroscopic. B) hydrophobic. C) heavy. D) gases. E) precipitation.

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Particulates that absorb water vapor around them are said to be hygroscopic.

Hygroscopic substances have the ability to attract and retain moisture from their surroundings. When exposed to humid air, these particulates can absorb water molecules through adsorption or absorption processes. This can lead to an increase in their size or weight as they become hydrated.

Hygroscopic substances are commonly used in various applications such as desiccants, humidity control agents, and in preserving moisture-sensitive materials. Examples of hygroscopic substances include certain salts, sugar, wood, and many organic compounds.

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Using MO theory, predict which of the following species is diamagnetic: 1. CN 2. CN 3. CN+ a. 1 and 3 only b.1 only c. 2 and 3 only d. 1, 2, and 3

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Using MO theory, we predict that 1 and 3 (CN and CN2) are diamagnetic, while 2 (CN+) is paramagnetic. Therefore, the correct answer is a. 1 and 3 only.

Using MO theory, we can predict the magnetic properties of molecules based on the electron configuration of their molecular orbitals. Diamagnetic species have all of their electrons paired, while paramagnetic species have unpaired electrons.
For CN, we can draw the MO diagram by combining the atomic orbitals of carbon and nitrogen. The diagram shows that CN has 10 electrons in its molecular orbitals, with all of them paired. Therefore, CN is diamagnetic.
For CN+, we can remove one electron from CN and recalculate the MO diagram. The resulting diagram shows that CN+ has 9 electrons, with one unpaired electron in the highest energy molecular orbital. Therefore, CN+ is paramagnetic.
For CN2, we can combine two CN molecules and draw the MO diagram. The diagram shows that CN2 has 20 electrons in its molecular orbitals, with all of them paired. Therefore, CN2 is also diamagnetic.

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According to Equation 1, the concentration of the polymer with respect to [HPO42–] is:
A) n[HPO42–].
B) n2[HPO42–].
C) (1/n)[HPO42–].
D) (1/n2)[HPO42–].

Answers

Equation 1 is a mathematical representation of the relationship between the concentration of a polymer and the concentration of a specific ion, HPO42–. The equation states that the concentration of the polymer with respect to HPO42– is (1/n2)[HPO42–]. The value of n in the equation refers to the degree of polymerization, which is the number of repeating units in the polymer chain.

The equation suggests that the concentration of the polymer is proportional to the concentration of HPO42–, but the relationship is not a simple one-to-one correspondence. Instead, the concentration of the polymer is related to the concentration of HPO42– by a factor of (1/n2), which reflects the complex interactions between the two species.

In practical terms, the equation can be used to predict the behavior of a polymer solution under different conditions, such as changes in pH or the presence of other ions. By understanding the relationship between the polymer and HPO42–, researchers can design new materials with specific properties and applications. Overall, Equation 1 provides a valuable tool for studying the behavior of polymers in solution and advancing our understanding of these complex materials.

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what is the wavelength range of photons that produce 40-kev electrons in compton scattering?

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The wavelength range of photons that produce 40-keV electrons in Compton scattering is essentially the same as the initial wavelength of the photons.

In Compton scattering, a photon interacts with an electron, transferring some of its energy and momentum to the electron. The change in energy of the photon is related to the scattering angle through the Compton wavelength shift equation:

Δλ = λ' - λ = h / (mec) * (1 - cos(θ))

where Δλ is the change in wavelength, λ' is the scattered wavelength, λ is the initial wavelength, h is the Planck constant, me is the electron mass, c is the speed of light, and θ is the scattering angle. Given that the energy of the electron is 40 keV, use the equation for the energy of a photon to determine the initial photon energy:

E = hc / λ

40,000 eV = (hc / λ') - (hc / λ)

Simplifying the equation:

hc / λ' = (hc / λ) + 40,000 eV

λ' = (λ * λ') / (λ - λ')

Substituting λ' = λ - Δλ, we get:

λ - Δλ = (λ * (λ - Δλ)) / λ

Simplifying further:

λ - Δλ = λ - Δλ

This equation indicates that the change in wavelength is negligible compared to the initial wavelength.

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how much (grams) methane (ch4) is required to make 42.00 grams of carbon dioxide according to the following equation? do not type units into your answer. ch4(g) 2o2(g) co2(g) 2h2o(l)

Answers

0.95 g of methane is required to make 42.00 grams of carbon dioxide.

On combustion, Methane produces a blue flame as it burns in the atmosphere. Methane burns to produce water (H2O) and carbon dioxide (CO2) when exposed to enough oxygen. It creates a significant quantity of heat during combustion, making it an excellent fuel source. A highly efficient greenhouse gas is methane.

A carbon dioxide molecule is created when one methane molecule reacts with two oxygen molecules and two water molecules, which are typically released as steam or water vapor while the reaction is taking place. The cleanest burning fossil fuel is natural gas.

Given reaction is:

[tex]CH_{4} + O_{2}[/tex] → [tex]CO_{2} + 2H_{2}O[/tex]

Gram molecular mass of [tex]CO_{2}[/tex] = 12 + 2(16) = 44

As 1 mole of methane on complete combustion produces 44g of carbon dioxide,

Therefore, Moles of methane required to produce 42.00 grams of carbon dioxide is:

= 1/44 × 42 = 0.95 grams.

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.At a high altitude water boils at 95∘C instead of 100∘C as at sea level because
A
the atmospheric pressure is greater
B
the atmospheric pressure is less
C
the climate is cooler
D
the vapour pressure of water is greater.

Answers

At a high altitude, water boils at 95°C instead of 100°C as at sea level because the atmospheric pressure is less.

When you move to a higher elevation, the air pressure decreases due to the lower concentration of air molecules. This reduced pressure affects the boiling point of water. At sea level, the atmospheric pressure is higher, which means water molecules need more energy to break free from their liquid state and transition into vapor. This is why water boils at 100°C under these conditions. In contrast, at a high altitude, the lower atmospheric pressure means water molecules require less energy to break free, so the boiling point drops to 95°C.

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.Select the false statement below.
(1) Group 1A and 2A metals are strong reducing agents
(2) Group 3A metals are more reactive than Group 2A metals which are more reactive than Group 1A metals
(3) oxides of Group 1A and 2A metals are basic (exception: BeO is amphoteric)
(4) hydroxides of most Group 2A metals are less soluble than hydroxides of Group 1A metals due to differences in ionic/covalent character of the hydroxides

Answers

The false statement is (2) Group 3A metals are more reactive than Group 2A metals which are more reactive than Group 1A metals.

This statement is incorrect as the reactivity of the groups decreases as we move from Group 1A to Group 3A. Group 1A metals are the most reactive of the three groups, followed by Group 2A metals and then Group 3A metals. This trend can be explained by the increasing ionization energy and electronegativity from left to right across the periodic table.

Group 1A and 2A metals are indeed strong reducing agents. They readily give up their valence electrons to form cations and have a strong tendency to form ionic compounds with nonmetals. The oxides of Group 1A and 2A metals are basic in nature, as they react with water to form metal hydroxides. However, BeO is an exception to this trend as it is amphoteric in nature and can react with both acids and bases.

Hydroxides of most Group 2A metals are indeed less soluble than hydroxides of Group 1A metals due to the differences in the ionic/covalent character of the hydroxides. The hydroxides of Group 1A metals have more ionic character, while the hydroxides of Group 2A metals have more covalent character, which makes them less soluble in water.

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.How many unshared electrons and bonding
electrons exist around the central atom in
ozone (O3)?
1. none; two
2. zero; eight
3. one; three
4. one; six
5. two; two
6. four; four
7. four; three
8. three; six
9. two; six

Answers

The answer is option 4: one unshared electron and six bonding electrons exist around the central atom in ozone (O3).


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A Freon leak in the air-conditioning system of a large building releases 20kg of CHF2CL per month.
If the leak were allowed to continue, how many kilograms of Cl would be emitted into the atmosphere each year?

Answers

Approximately 8,199.30 grams or 8.1993 kg of Cl would be emitted into the atmosphere each year if the Freon leak were allowed to continue.

To determine the amount of Cl (chlorine) emitted into the atmosphere each year due to the Freon leak, we need to consider the molar mass and molecular structure of CHF2Cl (Freon-22).

The molar mass of CHF2Cl is approximately 86.47 g/mol. Given that 20 kg of CHF2Cl is released per month, we can convert it to grams: 20 kg * 1000 g/kg = 20,000 g.

Next, we calculate the number of moles of CHF2Cl: 20,000 g / 86.47 g/mol = 231.31 mol.

Each molecule of CHF2Cl contains one chlorine atom, so the number of moles of Cl is the same as the number of moles of CHF2Cl, which is 231.31 mol.

To convert moles to grams, we multiply by the molar mass of chlorine (35.45 g/mol): 231.31 mol * 35.45 g/mol = 8,199.30 g.

Therefore, approximately 8,199.30 grams or 8.1993 kg of Cl would be emitted into the atmosphere each year if the Freon leak were allowed to continue.

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.1. Look up the structure for chlorophyll b. Do you expect it to be more or less polar than chlorophyll a? why?
2. Xanthophylls are yellow cartenoid pigments that are commonly found in vegetables, and include compounds like lutein and neoxanthin. Look up structures of these molecules. Do you expect them to be more or less polar than B-carotene? why?

Answers

The more polar nature of chlorophyll b makes it easier to dissolve in water and participate in the photosynthesis process. Xanthophylls like lutein and neoxanthin are more polar than B-carotene.

1. The structure of chlorophyll b includes a carbonyl group, which makes it more polar than chlorophyll a. The carbonyl group is a functional group that contains a double bond between a carbon and oxygen atom, making it more electronegative and able to interact with water molecules. Chlorophyll a, on the other hand, does not have a carbonyl group, making it less polar than chlorophyll b.
2. Xanthophylls like lutein and neoxanthin are more polar than B-carotene due to the presence of hydroxyl groups. Hydroxyl groups contain a hydrogen and oxygen atom, making them polar and capable of hydrogen bonding. B-carotene, on the other hand, lacks these hydroxyl groups, making it less polar than xanthophylls. The polar nature of xanthophylls allows them to dissolve in water and participate in various biological processes such as photoprotection and light harvesting in photosynthesis.

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) how would you determine the volume of a 125 ml erlenmeyer flask that you will use for the experiment? (a 125 ml flask does not have a total volume of 125 ml.) [1 pt]

Answers

To determine the actual volume of a 125 mL Erlenmeyer flask that you will use for the experiment, you can perform a volumetric calibration.


Use the following procedure to perform the task:

1. Clean and dry the flask thoroughly.
2. Use a graduated cylinder or a pipette to accurately measure 125 mL of distilled water (or another liquid with a known density) at room temperature.
3. Carefully pour the measured liquid into the Erlenmeyer flask.
4. Observe the liquid level in the flask. If the liquid reaches the 125 mL mark, then the flask has an accurate volume. If not, record the difference between the liquid level and the 125 mL mark.
5. Calculate the actual volume of the flask using the difference recorded in step 4, and adjust your experimental measurements accordingly.

Remember that a 125 mL Erlenmeyer flask may not have a total volume of exactly 125 mL, so conducting a volumetric calibration is essential to ensure accurate measurements during your experiment.

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Of the general types of hair relaxers, which one does not require pre-shampooing?Sodium HydroxideScalp AbrasionBase CreamChemical Hair Relaxer

Answers

Of the general types of hair relaxers, the chemical hair relaxer that does not require pre-shampooing is the sodium hydroxide relaxer.

This is because sodium hydroxide relaxers are highly alkaline and can cause scalp irritation if they come into contact with oils or dirt on the scalp. Pre-shampooing is typically recommended with other types of relaxers, such as those containing guanidine hydroxide or ammonium thioglycolate, to remove any buildup on the scalp and prepare it for the relaxing process. However, with sodium hydroxide relaxers, a base cream is usually applied to the scalp and hairline before application to protect them from the harsh chemical and avoid any scalp abrasion.

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does it make sense to say that a textbook is about 99.9 percent empty space?

Answers

Yes, it does make sense to say that a textbook is about 99.9 percent empty space. This is because the vast majority of the book is made up of pages, which are mostly composed of air.

The actual content of the book, such as text and images, only takes up a very small fraction of the overall space. However, it is important to note that this statement is referring to the physical space of the book, rather than its informational content.
Yes, it does make sense to say that a textbook is about 99.9 percent empty space, as this statement refers to the atomic structure of the materials that make up the textbook. Atoms, which are the building blocks of matter, are composed of a nucleus containing protons and neutrons, surrounded by electrons. The distance between the nucleus and the electrons is relatively vast compared to the size of the particles themselves, making most of the atom's volume empty space.

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in the drawings on the right-hand side, what does the solid wedge connecting atoms represent?

Answers

In the drawings on the right-hand side, the solid wedge connecting atoms represents the covalent bond between the atoms.

A covalent bond is a chemical bond that forms when two atoms share electrons in order to achieve a stable electron configuration. The solid wedge connecting the atoms in the drawing represents the sharing of electrons between the two atoms, which results in a strong and stable bond.

In the drawings, the atoms are represented by circles or spheres, and the solid wedge connecting them is used to indicate the covalent bond between the atoms. The size and shape of the solid wedge can vary depending on the strength of the bond and the number of atoms involved.  

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what is the mass percent of a solution prepared from 17.5 g mgcl2 in 85.0 g h2o?

Answers

The mass percent of the solution prepared from 17.5 g [tex]MgCl_2[/tex] in 85.0 g [tex]H_2O[/tex] is 17.07%.

To calculate the mass percent of a solution, we need to divide the mass of the solute by the mass of the solution (which is the sum of the masses of the solute and solvent, water).

Mass percent = (mass of solute ÷ mass of solution) × 100%

First, we need to calculate the mass of the solution:

Mass of solution = mass of solute + mass of solvent

Mass of solution = 17.5 g [tex]MgCl_2[/tex] + 85.0 g [tex]H_2O[/tex]

Mass of solution = 102.5 g

Now we can calculate the mass percent:

Mass percent = (mass of [tex]MgCl_2[/tex] ÷ mass of solution) × 100%

Mass percent = (17.5 g ÷ 102.5 g) × 100%

Mass percent = 17.07%

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three hydroxide ions are needed to form a neutral ionic compound with an aluminum ion. (True or False)

Answers

False.Aluminum ion has a charge of +3 and hydroxide ion has a charge of -1. To form a neutral ionic compound, three hydroxide ions will combine with one aluminum ion.

A compound is a substance made up of two or more different elements that are chemically bonded together in a fixed ratio. The elements in a compound cannot be separated by physical means, such as filtration or evaporation, but can be separated by chemical means, such as a chemical reaction. Examples of compounds include water (H2O), sodium chloride (NaCl), and carbon dioxide (CO2)

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Combustion of 28.78 g of a compound containing only carbon, hydrogen, and oxygen produces 33.31 gCO2 and 13.64 gH2O.
What is the empirical formula of the compound?
C2H2O3
C4H8O6
C6HO12
C2H4O3

Answers

The Combustion of the 28.78 g of the compound that is containing the carbon, the hydrogen, and the oxygen produces the 33.31 g CO₂ and 13.64 g H₂O. The empirical formula is C₂H₄O₃.

The mass of the compound = 28.78 g

The Mass of Carbon, C = 33.31 g CO₂ × (12.01 g C/44.01 g CO₂)

The Mass of Carbon, C = 9.09 g of C

The Mass of Hydrogen, H = 13.64 g H₂O × (2.016 H/18.02 g H₂O)

The Mass of Hydrogen, H = 1.52 g H

The Mass of Oxygen, O = Mass of compound - Mass of C - Mass of H

The Mass of Oxygen, O = (28.30 – 9.09 – 1.52) g

The Mass of Oxygen, O  = 17.85 g

The moles of C = 9.09 / 12 = 0.75 mol

The moles of H = 1.52 / 1 = 1.52 mol

The moles of O = 17.85 / 16 = 1.11 mol

Moles of C = 1 = 2

Moles of H = 2 = 4

Moles of O = 1.48  = 3

The empirical formula is C₂H₄O₃.

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the ansi z87.1 standard ensures that eyewear protects against group of answer choices splashes of corrosive chemicals the impact of shrapnel splashes of organic solvents fogging

Answers

Standard ensures that eyewear protects against  impact of shrapnel splashes of organic solvents .

What is the importance of eyewear in the laboratory?

Protective eyewear can be sen as one of the protective tools that is been required in the labortory especially when carry out a chemic reaction.

It shoud be noed that this is eeded to be worn in all laboratory spaces where physical, biological, as well as the chemical hazards are present  so as ro reduce the act and  chance of an eye injury, it should be noted tha the Eye injuries in laboratory spaces  is very common due toserious eye damage.

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During the electrolysis of molten Nal, what reaction occurs at the anode? A) I^-(I) + e → 12^-() B) 2 I^-(I) → I2(g) + 2e C) Nal(l) → Nal2(I) D) 2 I^-(I) + e → I2(g) E) Na (I) + e^- — Na(l)

Answers

During the electrolysis of molten NaI, the reaction that occurs at the anode is: B) 2 I^-(l) → I2(g) + 2e.


During the electrolysis of molten Nal (sodium iodide), the process involves the passage of an electric current through the molten Nal. This process is carried out in an electrolytic cell with two electrodes, the anode (positive) and the cathode (negative). When an electric current is passed through the molten Nal, it undergoes electrolysis, which involves the splitting of the ionic compound into its constituent ions.
At the anode, which is the positive electrode, the negative ions (I^-) are attracted and oxidized. The oxidation of I^- results in the formation of I2(g) and the release of two electrons (2e^-). Therefore, the reaction that occurs at the anode during the electrolysis of molten Nal is:
2 I^- (I) → I2 (g) + 2e^-
This reaction shows that the negative ions (I^-) are oxidized to form I2(g) and release two electrons at the anode.
In summary, during the electrolysis of molten Nal, the reaction that occurs at the anode is the oxidation of I^- to form I2(g) and release two electrons (2e^-).

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Write a balanced equation using the correct formulas and include conditions (s, l, g or aq) for each of the following reactions. Express your answer as a chemical equation. Identify all of the phases in your answer. A.) Sodium metal reacts with liquid water to form hydrogen gas and aqueous sodium hydroxide. B.) Solid phosphorus reacts with chlorine gas to form solid phosphorus pentachloride. C.) Solid copper (II) oxide reacts with carbon monoxide gas to form solid copper and carbon dioxide gas. D.) Liquid pentene (C5H10) burns in oxygen gas to form carbon dioxide gas and water vapor. E.) Solid iron(III) sulfide is oxidized by oxygen gas to solid iron(III) oxide and sulfur dioxide gas.

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A.) Sodium metal reacts with liquid water to form hydrogen gas and aqueous sodium hydroxide.

2Na(s) + 2H2O(l) → H2(g) + 2NaOH(aq)

B.) Solid phosphorus reacts with chlorine gas to form solid phosphorus pentachloride.

P4(s) + 10Cl2(g) → 4PCl5(s)

C.) Solid copper (II) oxide reacts with carbon monoxide gas to form solid copper and carbon dioxide gas.

CuO(s) + CO(g) → Cu(s) + CO2(g)

D.) Liquid pentene (C5H10) burns in oxygen gas to form carbon dioxide gas and water vapor.

C5H10(l) + 8O2(g) → 5CO2(g) + 5H2O(g)

E.) Solid iron(III) sulfide is oxidized by oxygen gas to solid iron(III) oxide and sulfur dioxide gas.

4FeS(s) + 7O2(g) → 2Fe2O3(s) + 4SO2(g)

In each equation, the reactants are on the left side of the arrow, and the products are on the right. The phases of each substance are included in parentheses after the formula, with (s) representing a solid, (l) representing a liquid, (g) representing a gas, and (aq) representing an aqueous solution. Conditions such as temperature and pressure are not included in the equations.

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Arrange the following compounds in order of decreasing dispersion interactions: CCl4, CH4, C3H8. Explain please!

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The order of decreasing dispersion interactions for the given compounds is CCl4 > C3H8 > CH4.

Dispersion interactions, also known as London dispersion forces or van der Waals forces, are weak intermolecular forces that arise due to temporary fluctuations in electron distribution around molecules. These forces are influenced by factors such as molecular size and shape, as well as the number of electrons in the molecule.

1. CCl4 (Carbon tetrachloride) has a molecular formula of CCl4 and consists of a central carbon atom surrounded by four chlorine atoms. It is a relatively large molecule with a high electron count, which contributes to stronger dispersion forces.

2. C3H8 (Propane) has a molecular formula of C3H8 and consists of three carbon atoms and eight hydrogen atoms in a chain configuration. Although it has a smaller electron count than CCl4, its size and shape still contribute to significant dispersion forces.

3. CH4 (Methane) has a molecular formula of CH4 and consists of a central carbon atom surrounded by four hydrogen atoms. It is the smallest molecule among the three, with the lowest electron count, resulting in the weakest dispersion forces.

In summary, the dispersion interactions decrease in the order CCl4 > C3H8 > CH4 due to differences in molecular size, shape, and electron count.

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The order of decreasing dispersion interactions is: CCl4 > C3H8 > CH4. Dispersion interactions, also known as London dispersion forces, occur between nonpolar molecules due to temporary fluctuations in electron density.



The strength of these interactions depends on the size of the molecule, with larger molecules experiencing stronger dispersion forces. In the case of the compounds CCl4, CH4, and C3H8, all three are nonpolar molecules, meaning they experience dispersion interactions as their primary intermolecular force. To arrange these compounds in order of decreasing dispersion interactions, we need to consider their molecular sizes. CCl4 is the largest molecule of the three, followed by C3H8 and then CH4. Therefore, CCl4 would experience the strongest dispersion forces, followed by C3H8 and then CH4. This can be explained by looking at the electron cloud of each molecule. CCl4 has four chlorine atoms bonded to a central carbon atom, making it a large molecule with a high electron density.

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describe the step by step method one should use to measure out 5.00 grams of calcium chloride

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The main answer to measuring out 5.00 grams of calcium chloride involves using a digital scale and a measuring spoon or scoop. Here are the steps:



1. Turn on the digital scale and place the measuring spoon or scoop on top of it.

2. Press the tare button to reset the scale to zero with the spoon or scoop on it.

3. Carefully add small amounts of calcium chloride to the spoon or scoop until the scale reads 5.00 grams.

4. Use a spatula or small scoop to transfer the measured calcium chloride to a container for use.

5. Repeat the process as needed until you have measured out the desired amount of calcium chloride.

To accurately measure out a specific amount of calcium chloride, a digital scale is required. Using a measuring spoon or scoop can help to ensure consistent measurements. It's important to tare the scale with the spoon or scoop on it to ensure that only the calcium chloride is being weighed. Careful additions of the calcium chloride can then be made until the desired weight is achieved. Transferring the measured calcium chloride to a container helps to avoid any loss or spillage. The process can be repeated as many times as needed until the desired amount of calcium chloride is measured.

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