A 32.0 kg crate is initially moving with a velocity that has magnitude 3.58 m/s in a direction 37.0 ∘ west of north. How much work must be done on the crate to change its velocity to 5.10 m/s in a direction 63.0 ∘ south of east?
The amount of work done on the crate to change its velocity is 211.1 J.
What is the work done on the crate to change its velocity?
The work done on the crate to change its velocity is calculated by applying the principle of conservation of energy as shown below.
Applying work-energy theorem, the work done in changing the velocity of the crate is equal to the change in kinetic energy of the crate as shown below;
W = ΔK.E
W = ¹/₂m(v₂² - v₁²)
where;
m is mass of the cratev₁ is the initial velocity of the cratev₂ is the final velocity of the crateW = ¹/₂m(v₂² - v₁²)
W = ¹/₂(32)(5.1² - 3.58²)
W = 211.1 J
Thus, the amount of work done on the crate to change its velocity from 3.58 m/s at 37.0 ∘ west of north to 5.10 m/s in a direction 63.0 ∘ south of east, is based on the principle of conservation of energy.
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A space station in the form of a large wheel,
356 m in diameter, rotates to provide an “artificial gravity” of 5.1 m/s2 for people
located at the outer rim.
What is the frequency of the rotational mo-
tion for the wheel to produce this effect? Answer in units of rev/min.
The frequency of the rotational motion for the wheel to produce this effect 1.62 rev/min.
What is the angular speed of the wheel?
The angular speed of the wheel is calculated by applying the formula for centripetal acceleration of the wheel.
a = v²/r = ω²r
where;
ω is the angular speed of the wheel in radian per secondsr is the radius of the wheelThe radius of the wheel = 356 m / 2 = 178 m
ω = √a/r
ω = √(5.1/178)
ω = 0.17 rad/s
The angular speed in revolution per minute is calculated as follows;
ω = 0.17 rad/s x 1 rev/2π rad x 60 s/1min
ω = 1.62 rev/min
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A turtle with a mass of 28.59 kg starts from rest and is pushed to the right on an ice rink upside down on its shell (he loves it I promise). He reaches the opposite end and ends up travelling at 5.18 m/s which takes 37.80 s. What would be the net force acting on the turtle?
The net force acting on the turtle would be 3.92N.
What is net force?
This is referred to as the total forces acting on an object.
Formula for calculating force on a body:
F= mv/t...........(i)
Formula for calculating net force:
Fnet= F₁ +F₂ +F₃ +F......FN ............(ii)
where,
F₁ +F₂ +F₃ +F......FN= force acting on the body.
From the Question:
Mass, M=28.59 kg
Velocity, V= 5.18 m/s
time, T =37.80 s.
Using equation (i)
F= mv/t
=28.59 kg*5.18 m/s
37.80 s.
=3.92N
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The number density of gas atoms at a certain location in the space above our planet is about 1.18 x 10^11 m^-3, and the pressure is 2.50 x 10^-10 N/m² in this space. What is the
temperature there in degrees celsius?
There is a temperature of 153.56K in that area.
In plain English, what is the Boltzmann constant?The Boltzmann constant, often known as Boltzmann's constant and denoted by the letters k or k B, establishes the relationship between absolute temperature and the amount of kinetic energy held within each molecule of an ideal gas.
A gas's temperature is what?A gas's temperature is a representation of its molecules' typical average translational kinetic energy. The molecules in a hot gas move more quickly than those in a cold gas; the mass remains constant, but the kinetic energy—and consequently the temperature—is higher due to the higher velocity of the molecules.
PV=nKT
where,
K=1.380649 × 10-23 m2 kg s-2 K-1
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A cap 6.000 cm in diameter plugs an opening in a spherical container 1.000 m in diameter at atmospheric pressure. The container is submerged to a depth of 10.00 ft in water. Assume the plug is planar and the pressure over the container is equalized. The force needed to remove the plug is closest to?
The force needed to remove the plug that is 6.000 cm in diameter which plugs an opening in a spherical container 1.000 m in diameter at atmospheric pressure is 85 N
P = F / A
P = ρ g h
P = Pressure
F = Force
A = Area
ρ = Density
g = Acceleration due to gravity
h = Height
ρ = 1000 kg / m³
g = 9.8 m / s²
h = 10 ft = 3.048 m
A = π r²
d = 6 cm = 0.06 m
r = d / 2 = 0.06 / 2
r = 0.03 m
A = 3.14 * 0.03 * 0.03
A = 0.002826 m²
Equating both formulae of P,
F / A = ρ g h
F = 1000 * 9.8 * 3.048 * 0.002826
F = 85 N
Therefore, the force needed to remove the plug is closest to 85 N
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what sources of motion does a shake flashlight harness
Answer:
The power for the LED stems from the movement of a magnet through a coil of wire on a tube. Each time the magnet moves through the coil of wires, the magnet generates a pulse of electricity. This is what happens when you shake the flashlight. A capacitor allows you to use the flashlight without continuously shaking it.
Carbon -14 forms nitrogen -14 by? A.alpha decay B.gamma decay C.positron decay D.beta decay.
Nitrogen-14 is created through the beta decay of carbon-14. Beta particle emission occurs along with this kind of disintegration.
How does alpha decay work?The unstable nucleus emits alpha particles during this disintegration. A helium nucleus with two protons and two neutrons makes up an alpha particle. Additionally, it bears a +2 charge.
Beta decayThis kind of radioactive decay results in the emission of gamma rays. The process produces a lot of energy, yet the number of protons doesn't change.
How can carbon become nitrogen?Carbon has an atomic number of 6, while nitrogen has a number of 7. Since the only way that carbon-14 and nitrogen-14 differ from one another is in their atomic number. Nitrogen-14 is created through the beta decay of carbon-14. Only beta decay allows for the conversion of carbon-14 into nitrogen-14, and the number of protons remains constant.
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A moving object is moving with a speed of 20m/s on the line y=√3x +1. How many meters does it move in the x direction in 3 seconds?
how can i solve it?
2077 m distance it move in the x direction in 3 seconds
speed=distance/time
distance=speed × time
distance= 20×3
√3x +1=60
x=119
put x's value in equation
distance= 2077 m
Distance, which is independent of direction, is the length between two points or things. Distance solely considers the overall magnitude and disregards the start and finish places because it is a scalar attribute. Distance can only have a positive or zero value because it is a scalar attribute; it cannot be negative.
The meter (m) is the most widely used unit of measurement for distance, however kilometers (km) can also be used to describe longer distances and centimeters (cm) or millimeters can be used to express shorter distances (mm). The distance traveled is frequently represented by the letter D when computing distance.
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1. An object is dropped to the ground and its momentum increases. Explain how the law of
conservation of momentum and Newton's third law of motion can be applied to this
situation.
An object is dropped to the ground and its momentum increases. Due to this influence of the earth's gravitational pull, the total momentum of the free-falling body is conserved and earth and object is exerting equal and opposite forces on each other , hence newton's third law of motion is also applied
When a body is freely falling , both the body and earth will exert an equal and opposite force on each other due to newton's third law of motion which says every action has a reaction .
The Earth itself accelerates (ever so slightly) toward the object at the same time. The opposite-direction velocity of the Earth will be exactly proportional to the ratio of the object's mass to Earth's mass, thus exactly balancing momentum , hence momentum is conserved .
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Part F
Imagine you were a sportscaster at the Olympics. You'd created a mathematical model similar to the one you just did. Imagine that you had a
computer program that could do an instantaneous analysis of video motion using that model. How could you use it in your sportscast?
A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.
Why will a program be needed?A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.
Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience
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Which of the following are projectiles (using the definition of a projectile)? (KEEP IN MIND, these are under normal circumstances unless otherwise stated) human walking meteor in Earth's atmosphere car driving airplane landing asteroid basketball being shot by Steph Curry ball on a rope , swinging around a pole (tetherball football thrown bird flying tennis ball served at 140 mph
The example of projectile is a basketball being shot by Steph Curry.
What is projectile?Projectile is any object propelled through space by the application of a force.
Projectile is used to describe any object that is cast, fired, flung, heaved, hurled, tossed, or thrown. For example, when a ball is thrown straight upward, or kicked.
In projectile motion, gravity is the only force acting on the object. This doesn’t necessarily mean that other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory.
Other examples of projectile is as follows:
Firing a canonJavelin throwArcheryGun fireGolf ballTherefore, it can be said that a basketball being shot by a renowned basket baller into the air is an example of projectile.
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Consider a wooden cylinder of density 0.75g/cm³ floating in water with its axis perpendicular to the surface and the height is 15cm. How much of the cylinder will be under water?. If the radius were 10cm, how much would be under water? Suppose the cylinder is completely submerged and anchor in the water by a string, for the cylinder nof 10cm radius, what will be the force on the string?. Where g=9.8m/s, density of water=1g/cm³.
6923 N is the force on the string, Where g=9.8m/s, density of water=1g/cm³.
volume=2πrh
volume= 942 cm³
density= mass/volume
mass=density× volume
mass=0.75g/cm³× 942 cm³
mass=706 kg
F= mg
F=706×9.8
F= 6923 N
Every action that attempts to maintain, modify, or change the motion of a body is referred to as a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).
According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight route in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changing velocity) in the direction of the force.
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A projectile is fired horizontally at 180 m/sec from an altitude of 734.7 m. What is the final vertical velocity of the projectile as it hits the ground?
Answer:
216 m/s
Explanation:
Final velocity will be resultant of the initial horizontal velocity ( 180 m/s) and the vertical velocity from falling 734.7 m
Verital vf = at need to find time
df = 734.7 = 1/2 a t^2
t= 12.2 sec
vf = at
= 9.81 (12.2) = 120 m/s
Just before hotting the ground,
resultant velocity = sqrt(180^2 + 120^2) = 216 m/s
Motor oil, axle grease, and other lubricants are slippery. Why do you
think people spend the money to put these lubricants in their cars? Answer ASAP
Because there is less resistance, it is simpler to maneuver their vehicle and requires less effort.
How should we define force?The definition of force is physics states that when a mass-containing object is pushed or pulled, it alters its velocity. The ability to change a body's resting and moving state is actually possessed by force, an external agent. It moves and has a certain size.
What role does force play?Things move and, more precisely, change their motion as a result of force. The forces of magnetic forces and gravity are two examples of natural forces that humans have encountered. These two forces don't need to be in close proximity to each other to work because they act at a distance.
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Three miles of an ideal gas kept at constant temperature 300K are compressed from volume of 4L to 1L. Calculate work done in the process where R = 8.31 J/mol/K
[tex]{ \boxed{ \red{ \sf{W = 10370.652 \: J}}}}[/tex]
Explanation:
Given,
[tex]{ \blue{ \sf{μ = 3}}}[/tex]
[tex]{ \blue{ \sf{ T= 300K}}}[/tex]
[tex]{ \blue{ \sf{ V_{1} = 4L}}}[/tex]
[tex]{ \blue{ \sf{ V_{2} = 1L}}} [/tex]
[tex]{ \blue{ \sf{W = \: ?}}}[/tex]
[tex]{ \blue{ \sf{R = 8.31 \: J/mol/K}}}[/tex]
[tex]{ \purple{ \sf{W = μRT \: l_{n}[ \frac{ V_{2}}{ V_{1} }}]}} [/tex]
[tex]{ \purple{ \sf{W = μRT[ l_{n} V_{2} - l_{n}V _{1}}]}}[/tex]
[tex]{ \purple{ \sf{W = 2.303μRT[ log_{1} - log_{4}]}}}[/tex]
[tex]{ \purple{ \sf{W = 2.303 \times 3 \times 8.31 \times 300(0 - 0.6021)}}}[/tex]
[tex]{ \purple{ \boxed{ \green{ \sf{W = 10370.652 \: J}}}}}[/tex]
Two forces, F1=(1.65i−0.90j+1.15k) N F2=(−1.00i+1.20j) N are applied on a moving object of mass 0.20 kg. The displacement vector produced by the two forces is d=(10.0i+8.8j+5.1k)m. What is the work done by the two forces?
I need help with this question. please
Answer:
I don't Know espero que le entiendas
A car accelerated uniformly from rest and attained a velocity of 8m/s. it then travels with the uniform velocity of for the next 22 seconds and later brought to rest in 5 seconds
(a )draw the velocity time graph
(b.) calculate the total distance covered (c.) calculate the distance covered after 25 seconds.
Answer:
See below
Explanation:
See diagram below
8 seconds to 60 m/s then 60 m/s for 22 seconds then to 0 m/s in 5 seconds
What happens to Fg if both masses double
A. Reduced by 1/2
B. increases by 2
C. Reduces by 1/4
D. Increases by 4
If both masses double, FG increases by 4.
What is Gravitational Force?
Gravity is a fundamental interaction that all objects with mass or energy experience due to its Latin root, gravitas, meaning "weight". Approximately 1038 times weaker than that of the strong interaction, 1036 times weaker than that of the electromagnetic force, and 10^29 times weaker than the weak interaction, gravity is by far the weakest of the four fundamental interactions. The level of subatomic particles is therefore unaffected by it significantly. The motion of planets, stars, galaxies, or even light is controlled by gravity, which is the most important interaction between objects just at macroscopic level.
What happens to Fg if both masses double?
The gravitational force increases by 4, when both the masses double.
F = Gm1m2/r2
If both masses double, then
m1 = 2m1 , m2 = 2m2
F = G(2m12m2)/r2 ⟹
F = 4F
Thus gravitational force becomes 4 times.
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two vehicle are moving in same direction the first one has velocity of 24m/s another has 18m/s find their relative velocity & also their relative velocity when they are moving in opposite direction
The relative velocity of two vehicles moving in the same direction will be 42 m/s, whereas the relative velocity of two vehicles moving in different directions will be 8 m/s.
Let the velocities of the two vehicles be, v1 and v2, respectively.
Given,
The velocity of the first vehicle (v1) = 24 m/s
The velocity of the second vehicle (v2) = 18 m/s
Case-1
When they are moving in a same direction,
The relative velocity (V) of the two vehicles will be the sum of their velocities, i.e.,
V = v1 + v2
=> V = 24 + 18
=> V = 42 m/s.
Case-2
When the vehicles are moving in different directions,
The relative velocity (V) of the two vehicles will be the difference between the velocities, i.e.,
V = v1 - v2
=> V = 24 - 18
=> V = 6 m/s.
Therefore, The relative velocity of two vehicles moving in the same direction will be 42 m/s, whereas the relative velocity of two vehicles moving in different directions will be 8 m/s.
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A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).
The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².
How to calculate acceleration?Acceleration is change of velocity with respect to time (can include deceleration or changing direction).
The acceleration of a body can be calculated by using the following expression;
a = F/m
Where;
a = acceleration (m/s²)F = force (N)m = mass (kg)According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:
a = 4N ÷ 2.55kg
a = 1.57m/s²
Therefore, 1.57m/s² is the acceleration of the object.
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A 10Kg cannon shoots a cannon ball of mass 1kg that accelerates 20m/s2.
1) What is the force on the ball
2) What is the acceleration of the cannon?
1) The force on the ball is 20 N
2) The acceleration of the cannon is 2m/s2.
State Newton's 2nd law of motion
Newton's second law of motion, which is what we utilize, asserts that,
F= m x a
where:
F is the total force in newton.
m is the object's mass in kilograms.
In meters per second squared, a represents the object's acceleration.
1) Using this we find the force on the ball,
F = m x a
= 1 x 20
= 20 N
2) Newton's law states that every actoin has an equal and opposie reaction. Thus the force on the cannon, Fc will be equal to the force acting on the ball, Fb while it was shooted.
As such we can find the acceleration of the cannon using the equation:
Fc = Fb
m1 x a1 = m2 x a2
10 x a = 1 x 20
a = 20/10
a = 2 m/s2
Hence,
1) The force on the ball is 20 N
2) The acceleration of the cannon is 2m/s2.
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You are given 13.0 m of thin wire. You form the wire into a circular coil with 70 turns.
If this coil is placed with its axis parallel to a 0.19 T magnetic field, what is the flux through the coil?
The magnetic flux through the coil is determined as 25.2 Tm².
What is the magnetic flux through the coil?
Magnetic flux is defined as the number of magnetic field lines passing through a given closed surface.
The magnetic flux through the coil is calculated using the following formula.
Ф = BA cosθ
where;
B is the magnetic field strengthA is the area of the coilθ is the inclination of the coilA = πd²/4
where;
d is the diameter of the wireA = π(13)²/4
A = 132.73 m²
Since the coil is parallel to the magnetic field, θ = 0
Ф = BA cosθ
Ф = 0.19 T x 132.73 m² x cos(0)
Ф = 25.2 Tm²
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The toy car in Figure 20 runs off the edge of a table that is 1.225m high. The car lands 0.4000m from the base of the table. Show all work.
How long did it take the car to fall?
The time taken for the toy car to fall from the given height is 0.5 second.
What is the time of motion of the toy car?
The time of motion of the toy car is calculated by applying the following equation as shown below.
h = vt + ¹/₂gt²
where;
h is the vertical height of fall of the toy carv is the initial vertical velocity of the toy cart is the time of motion of the toy carg is acceleration due to gravity = 9.8 m/s²The initial vertical velocity of the toy car = 0
h = 0 + ¹/₂gt²
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
t = √(2 x 1.225 / 9.8)
t = 0.5 second
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An unknown radioactive element decays into non-radioactive substances. It's 520the radioactivity of a sample decreases by 60 percent.
a) What is the half-life of the element?
b) How long will it take a 100 mg sample to break down to 92 mg?
The half life of the sample is 393.4 days while it would take 47.3 days for 100 mg sample to break down to 92 mg.
What is the half-life of the element?We know that the half life has to do with the time that it takes for only half of the number of the radioactive atoms in the sample to remain. We have in this case that;
N/No = (1/2)t/[tex]t_{\frac{1}{2} }[/tex]
No = Number of radioactive atoms originally present
N = Number of atoms at time t
t = time taken
[tex]t_{\frac{1}{2} }[/tex] = half life
Then we are told that the sample decreases by 60 percent thus 40 percent is left.
We have;
0.4No/No = (1/2)^520/[tex]t_{\frac{1}{2} }[/tex]
0.4 = (1/2)^520/[tex]t_{\frac{1}{2} }[/tex]
ln0.4 = 520/[tex]t_{\frac{1}{2} }[/tex] ln 0.5
520/[tex]t_{\frac{1}{2} }[/tex] = ln0.4 /ln 0.5
[tex]t_{\frac{1}{2} }[/tex] =520/ ln0.4 /ln 0.5
= 393.4 days
Then
Using;
92/100 = (1/2)^t/ 393.4
0.92 = (1/2)^t/ 393.4
ln 0.92 = t/ 393.4 ln 0.5
t = ln 0.92/ ln 0.5 * 393.4
t = 47 days
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A rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 x 10¹
meters per second². After 30 seconds of flight, how high has it reached?
It take 3.03 sec long to the rocket to reach an altitude of 9.0* 10^3.
What is altitude?
Altitude is the height of an object or point in relation to sea level or ground level.It is the apparent height of celestial object above the horizon, measured in angular distance.
Sol-A sign simply indicates multiplication operation.
As per the question we have given- a=accelaration =-2*101=-202m/s^2
(We use negative sign here because it opposes the gravitational force)
d= distance/altitude =9*103= 927 meters
V= initial velocity= 0 m/s
T = Time substituting,927=3.03 second.
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4. In a physics lab, Kate and Rob use a hanging mass and pulley system to exert a 2.45 N
rightward force on a 0.500-kg cart to accelerate it across a low-friction track. If the total
resistance force to the motion of the cart is 0.72 N, then what is the cart's acceleration?
Fgrav = 4.90 N; Fnorm = 4.90 N; Fnet = 1.73 N, then the acceleration of the cart is (a) = 3.46 m/s/s,
What is acceleration and its types?Acceleration is defined as a vector quantity, the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. It can be either positive, negative, or zero depending upon the velocity and its direction. Three types of acceleration are Uniform acceleration, non-uniform acceleration, and average acceleration.
Formula
{a} = v - v0/t =Δv/Δ t
{a} = average acceleration
v = final velocity
v_0 = starting velocity
t = elapsed time
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If I wanted to increase the current, but maintain the voltage in a USB 3.1 port that provides a current of 0.9 A and a voltage of 5 V, to which I have connected a device with 4 ohms of resistance, how would I have to associate several USB ports to achieve this?
To achieve an increase in the current delivered in the USB 3.1 port, at a constant voltage, the several USB ports must be connect in parallel to each other. This will ensure an increase in current and constant voltage.
What is the relationship between current and resistance?According to ohms Law the current flowing through an ohmic conductor is directly proportional to the voltage across the conductor.
V = IR
where;
I is the current in the circuitR is the resistance across the circuitV is the voltage across the circuitI = V/R
To increase the current at a constant voltage, the resistance must decrease.
In a parallel circuit, the current flowing in each circuit component is different while the voltage drop in each circuit component is the same.
Thus, to increase the current delivered in the USB port, and maintain the initial voltage, the several USB ports must be connect in parallel to each other.
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1. The mass of oil in a reservoir is 825kg. If the reservoir has a volume of 0.197m³.
Determine:
i.
ii.
The density of the oil
The specific weight of the oil
The specific gravity of the oil
Density, Specific Weight & Gravity of oil is 899.7 kg/m³, 8826.057 kg/m²s² and 0.8997 respectively.
Given: Mass =825kg, Volume =0.197m³
Density =Mass/Volume
=825/0.197
=899.7 kg/m³
specific weight= Density x Gravity
= 899.7 x 9.81 = 8826.057 kg/m²s²
Specific Gravity= Density/Density of water
=899.7/1000
=0.8997
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what form of energy can you produce by rubbing an eraser against a piece of paper?
Answer:
it gets hot
Explanation:
because you are rubbing it hard
ASTRONOMY QUESTION
Over what range of distances from the Sun would you expect to find solid, rocky material collecting together to form a terrestrial planet?
Group of answer choices
A) 5 - 50 AU
B) beyond 50 AU
C) 0.2 - 5 AU
D) 0 - 0.2 AU
The range of distances from the Sun that you would expect to find solid, rocky material collecting together to form a terrestrial planet is option (C) 0.2 - 5 AU.
What is formation of a terrestrial planet about?Jovian planets can be found at distances of 2 AU to 50 AU or more. This is the area where the early Solar System's temperature was below 273 K, water's freezing point.
Therefore, While rocky and metallic materials (Terrestrial planets) might have condensed over the whole range of distances from the Sun, only the rocky material could have accumulated over the range from 2 AU and inwards. H and He may have also been captured by the planet if it had been further from the Sun than 2 AU, which would have made it a Jovian or gas giant planet.
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