the function relates the length of a skid mark measured in feet at an accident scene to the speed of the car in miles per hour. that means an accident reconstructionist can measure the length of a skid mark and find the speed the car was traveling. if a skid mark with a length of 82.5 ft was found, find the speed of the car. round your answer to the nearest tenth.

Answers

Answer 1

If a skid mark with a length of 82.5 feet was found, then the speed of the car is 13.59 miles per hour

The function is

l(s) = 0.46s^2 - 0.199s + 0.264

Where l is the length of a skid mark measured in feet at an accident scene

s is the speed of the car in miles per hour

Given that the skid mark length = 82.5 feet

Then the equation will be

0.46s^2 - 0.199s + 0.264 = 82.5

Rearrange the terms

0.46s^2 - 0.199s + 0.264 - 82.5 = 0

0.46s^2 - 0.199s - 82.236 = 0

Use the quadratic equation

= [tex]\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex]

Substitute the values in the equation

= [tex]\frac{0.199+/-\sqrt{(-0.199)^2-4(0.46)(-82.236)} }{2(0.46)}[/tex]

= (0.199 ± 12.30) / 0.92

Then

(0.199 + 12.30) / 0.92 = 13.59

(0.199 - 12.30) / 0.92 = -13.15

Therefore, the speed of the car is 13.59 miles per hour

The complete question is:

The function l(s) = 0.46s^2 - 0.199s + 0.264 relates the length of a skid mark measured in feet at an accident scene to the speed of the car in miles per hour. that means an accident reconstructionist can measure the length of a skid mark and find the speed the car was traveling. if a skid mark with a length of 82.5 ft was found, find the speed of the car. round your answer to the nearest tenth.

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Related Questions

Solve by using substitution. Express your answer as an ordered pair.
{4x+y=1
y=x−4

Answers

Answer:

The correct answer is (1, -3).

Step-by-step explanation:

To solve this question, we should use substitution. This means we can substitute the value given for y (as indicated by the second equation) into the first equation. This is shown below:

4x + y = 1

4x + (x - 4) = 1

We simplify the left side of the equation and then solve for x.

5x - 4 = 1

5x = 5

x = 1

We must also solve for y. To do this, we can plug in x = 1 into either of the given equations.

y = x - 4

y = 1 - 4

y = -3

Therefore, x = 1 and y = -3. The question asks us to express the answer as an ordered pair (x,y), so the answer is (1, -3).

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An element with a mass of 520 grams decays by 25.1% per minute. To the nearest tenth of a minute, how long will it be until there are 60 grams of the element remaining?

Answers

The total time for the mass of the element to be 60 grams is 7.5 minutes

What is exponential growth factor?

The exponential growth or decay formula is given by

x ( t ) = x₀ × ( 1 + r )ⁿ  for growth rate

x ( t ) = x₀ × ( 1 - r )ⁿ   for decay rate

x ( t ) is the value at time t

x₀ is the initial value at time t = 0.

r is the growth rate when r>0 or decay rate when r<0, in percent

t is the time in discrete intervals and selected time units = n

Given data ,

Let the total mass of element be = 520 grams

So , the value of x₀ = 520 grams

Now , the decay rate of element is given by r = 25.1 %

To calculate the time at which the amount of element left is 60 grams = n

where n is the total time = t

So , x ( t ) = 60

The decay rate formula is given by the equation ,

x ( t ) = x₀ × ( 1 - r )ⁿ

Substituting the values in the equation , we get

60 = 520 ( 1 - 25.1/100 )ⁿ

On simplifying the equation , we get

60 = 520 ( 1 - 0.251 )ⁿ

Divide by 520 on both sides of the equation , we get

( 0.749 )ⁿ = 6/52

Taking logarithm on both sides , we get

n × log ( 0.749 ) = log ( 6/52 )

Divide by log ( 0.749 ) on both sides , we get

n = log ( 6/52 ) / log ( 0.749 )

n = -0.9378 / -0.1255

n = 7.47 minutes

Therefore , the value of n time t = 7.5 minutes

Hence ,

The total time for the mass of the element to be 60 grams is 7.5 minutes

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A library is holding a special five-day event honoring successful local writers. One writer will be invited to be a guest speaker for each night from Monday through Friday, and no writer will be asked to participate twice. The writers have each written books in only one of four different genres—science fiction, mystery, historical fiction, and non-fiction. A, J, and X are all science fiction writers. B and Y are both mystery writers. C and Z are both historical fiction writers. L is a non-fiction writer. The following conditions apply without exception:
At least one writer from each genre will be invited to speak on at least one night.
No two authors from the same genre will be invited to speak on the following night.
If C is invited to speak, then X is invited to speak on the following night.
If Y is invited to speak, then neither C nor A are invited to speak.
If X and J are both invited to speak, then neither will speak on either the first or last night.
If L and B are both invited to speak, then neither will speak on either the first or last night.
If L is invited to speak on Friday, then on what days MUST a science fiction writer be invited? Possible Answers:Monday and Wednesday
Monday and Tuesday
Tuesday and Thursday
Only Wednesday
Monday and Thursday

Answers

As per the concept of probability, If L is invited to speak on Friday, then the science fiction writer be invited on Monday and Wednesday

Probability:

In statistics, probability refers the possible and favorable outcome of the particular event.

Given,

Here we need to find if L is invited to speak on Friday, then on what days MUST a science fiction writer be invited.

Here we know that the writers of the same genre may not speak on consecutive nights.

And here we have the only five slots to fill, two of the three science fiction writers must speak on Monday and Friday

So, If both X and J are invited, then at least one will be forced to speak on Monday or Friday, which is not allowed.

Then, modification of the rules is actually just a bit of a red herring, since all of the answer choices except for the one regarding science fiction writers is true regardless.

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write the following python function: asquare(k) takes k as a parameter and returns a list containing squares of first k integers. asquare(5) will return the list [1, 4, 9, 16, 25] print that list

Answers

The python function is, [1, 4, 9, 16, 25] [1, 4].

What is square of a number?

It is easy to determine a number's square. To determine the given number's square, we must multiply it by itself. A number raised to the power of 2 is always used to represent the square term.

For instance, the square of 6 is equal to 6 times 6, or 6 x 6 = 6^2 = 36.

A "Square Number" is the product of multiplying an integer or number (not a fraction) by itself.

For instance, 3 x 3 = 3^2, or 3 multiplied by 3 equals 3 squared. In essence, a square number is the result of multiplying an integer or number by itself exponentially.

Hence, the python function is, [1, 4, 9, 16, 25] [1, 4].

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Victoria has 1.90 worth of nickels and dimes. She has two more nickels than dimes. Write a system of equation that could be used to determine the number of nickels and the number of dimes that victoria has.

Answers

The system of equations is  0.05n+0.10d=1.90  and n=d+2

What is an equation?

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated.

The calculation is as follows:

We know that

One nickel = $0.05,

So n nickels are worth 0.05n.

One dime = $0.10,

so dd dimes are worth 0.10d.

Now

The total 0.05n+0.10d =  $1.90

i.e.  

0.05n+0.10d=1.90

And,  

n=d+2

Therefore we can conclude that The system of equations is  0.05n+0.10d=1.90  and n=d+2

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a 10-cmcm-long spring is attached to the ceiling. when a 2.0 kgkg mass is hung from it, the spring stretches to a length of 15 cmcm.

Answers

When a mass of 3 kg is hanged to it, the string will stretch 7.5 cm.

Given,

The length of the spring attached to the ceiling = 10 cm

The quantity of the mass hanged in the spring = 2 kg

The amount of stretching happened in the spring = 15 cm

We have to find the stretching of string when a mass of 3 kg is hanged to it;

Here,

Given that the force applied to the spring by the 2.0 kg is equal to the mass's weight:

F = mg = 2 kg × 9.8 m/s² = 19.6 N

Additionally, the stretching of:

Δx = 15 cm - 10 cm = 5 cm

So, applying Hooke's law:

F = kΔx

To determine the spring constant, k;

k = F/Δx = 19.6/5 = 3.92  N/ cm

The spring is now coupled to a new mass of m = 3.0 kg; the force this mass exerts on the spring equals

F = mg = 3 kg × 9.8 m/s² = 29.4 N

Thus, we may apply Hooke's law once more to determine the new stretching:

Δx = F/k = 29.4/3.92 = 7.5 cm

Therefore,

The string will be stretched 7.5 cm when a mass of 3 kg is hanged to it.

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What is the circumcenter of a triangle formed by (4,2), (3,-3) and (2,2)?

Answers

The circumcenter of a triangle formed by (4,2), (3,-3) and (2,2) is located at (3, -0.4).

The circumcenter of a triangle is the point of intersection of the three perpendicular bisectors of the sides of a triangle.

Let A = vertex at (4,2)

B = vertex at (3,-3)

C = vertex at (2,2)

Get the midpoint of each side.

midpoint = [(x₂ + x₁)/2 , (y₂ + y₁)/2]

side AB : midpoint = [(3 + 4)/2 , (-3 + 2)/2] = (3.5, -0.5)

side AC : midpoint = [(4 + 2)/2 , (2 + 2)/2] = (3, 2)

side BC : midpoint = [(3 + 2)/2 , (-3 + 2)/2] = (2.5, -0.5)

Get the slope of each side.

slope = (y₂ - y₁) / (x₂ - x₁)

side AB : slope = (-3 - 2) / (3 - 4) = 5

side AC : slope = (2 - 2) / (2 - 4) = 0/-2 = 0

side BC : slope = (2 - -3) / (2 - 3) = -5

Determine the equation of the line of each of the three perpendicular bisectors of the sides of a triangle, that passes through the midpoint and with a slope equal to the negative reciprocal of the slope of the side.

y = mx + b

perpendicular bisector of AB :

-0.5 = -1/5(3.5) + b   ;   b = 0.2   ;   y = -1/5x + 0.2

perpendicular bisector of AC :

since AC is a horizontal line, x = 3

perpendicular bisector of BC :

-0.5 = 1/5(2.5) + b   ;   b = -1   ;   y = 1/5x - 1

Since x is already equal to 3, substitute the value of x in the two other equation and solve for y.

y = -1/5x + 0.2

y = -1/5(3) + 0.2

y = -0.4

y = 1/5x - 1

y = 1/5(3) - 1

y = -0.4

Hence, the circumcenter of the triangle is located at (3, -0.4).

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Albert has a credit card with an APR of 20.7% and the following daily balances for this billing period: Days 1-3: $50 Days 4-10: $100 Days 11-25: $175 Days 26-30: $225 1. What is Albert’s daily rate? Round to the nearest ten thousandth.

Answers

Albert daily rate is 3.79%

How to determine Albert daily rate?

We know that rate is the quantity  or amount or the degree of a quantity measured with another quantity.

Albert's credit card APT = 20.7%

Daily balances are

Days 1-3 = (20.7*50)/100   = 10.35

Days 4-10 = (20.7*100)/100 =20.70

Days 11-25 = (20.7*175)/100 = 36.225

Days 26-30 = (20.7*225)/100 =46.575

Number of days in the month = 30 days

Total  balance = $113.80

Daily rate = [tex]\frac{Total amount }{number of days}[/tex]

daily rate = [tex]\frac{113.80}{30}[/tex]

Dividing the figures we have 3.79

Therefore the daily rate is 3.79%

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For the following, find the length of AB:

(Use \large \pi=3.14 when necessary and round your final answer to the hundredths.)



Arc AB =

Answers

In the given diagram, the length of arc AB is 10.05.

Calculating the length of an arc AB

From the question, we are to determine the length of arc AB.

From the formula for calculating the length of an arc, we have that

Length of an arc = θ/360° × 2πr

Where θ is the angle subtended by arc at the center of the circle

and r is the radius of the circle

In the given diagram,

Angle subtended by the arc = 48°

Radius, r = 12

Therefore,

The length of the arc = 48/360 × 2×3.14×12

Length of the arc = 2/15 × 1884/25

Length of the arc = 10.05

Hence, the length of AB is 10.05

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In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time college students who earn a​ bachelor's degree in four years or less. Find the sample size needed to estimate that percentage. Use a .03 margin of error and use a confidence level of 90​%. Complete parts​ (a) through​ (c) below.
a. Assume that nothing is known about the percentage to be estimated.
n=
b. Assume prior studies have shown that about 60​% of​ full-time students earn​ bachelor's degrees in four years or less.
n=
c. Does the added knowledge in part​ (b) have much of an effect on the sample​ size?

Answers

The required sample sizes are given as follows:

a) n = 752.

b) n = 722.

c) The added knowledge in item b has an effect, as it decreases the sample size required. The decrease is not huge because the estimate is close to 0.5, but the farther the estimate gets from 0.5, the more the sample size decreases.

What is a confidence interval of proportions?

A confidence interval of proportions has the bounds given by the rule presented as follows:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The margin of error is calculated as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The variables used to calculated these bounds are listed as follows:

[tex]\pi[/tex] is the sample proportion, which is also the estimate of the parameter.z is the critical value.n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

The margin of error in this problem is given as follows:

M = 0.03.

For item a, there is no previous estimate, hence we consider [tex]\pi = 0.5[/tex] and the sample size is obtained as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2[/tex]

n = 752. (rounding up).

For item b, the estimate is [tex]\pi = 0.6[/tex], hence the sample size is obtained as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 1.645\sqrt{\frac{0.6(0.4)}{n}}[/tex]

[tex]0.03\sqrt{n} = 1.645\sqrt{0.6(0.4)}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.6(0.4)}}{0.03}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.6(0.4)}}{0.03}\right)^2[/tex]

n = 722. (rounding up).

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Use the Alternating Series Estimation Theorem to estimate the range of values of x for which the given approximation is accurate to within the stated error.sin x = x − x 36 ( | error | < 0.01)

Answers

The Alternating Series Estimation Theorem to estimate the range of values of x for which the given approximation is ( -0.0654 , 0.0654 ) .

Given :

Use the Alternating Series Estimation Theorem to estimate the range of values of x for which the given approximation is accurate to within the stated error.sin x = x − x^3 / 6 ( | error | < 0.01 )

The next nonzero term in the Taylor series for sine is x^5 / 120 .

x^5 / 120 < .00000001

-0.00000001 < x^5 / 120 < .00000001

-0.0000012 < x^5 < .0000012

( -0.0000012 )^1/5 < x < ( .0000012 )^1/5

we have ( .0000012 )^1/5 ≈ .0654

= ( -0.0654 , 0.0654 )

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There are 1,295 students attending a small university. There are 714 women enrolled. What percentage of student are women?

Answers

Answer:

55.13 I'm sure is the answer

There are 714 women out of the total 1295 students:

    [tex]\dfrac{714}{1295}\approx0.551351351351351[/tex]

About 55.14% of the students are women.

Find m<2
(Please help my test ends 12:50 west coast)

Answers

Answer:

40

Step-by-step explanation:

40

At the time of her​ grandson's birth, a grandmother deposits 14000 in an account that pays 9.5% compounded monthly. What will be the value of the account at the​ child's twenty-first​ birthday, assuming that no other deposits or withdrawals are made during this​ period?

Answers

The value of the account at the​ child's twenty-first​ birthday is 102125.44

How to determine the value of the account at the​ child's twenty-first​ birthday?

We can use the compound interest formula to determine the value of the account (A) on the​ child's twenty-first​ birthday:

A = P (1 + r/n)^(nt)

Where:

P is the initial amount of money deposited in the account

r is the interest rate

n is the number of times the interest is compounded per year

t is the number of years

Given: P = 14000, r = 9.5% = 0.095, t = 21, n = 12 (i.e. 12 months per year)

Substitututing into A = P (1 + r/n)^(nt):

A = 14000 (1 +  0.095/12)^(12×21)

A = 14000 (1 +  0.095/12)^(252)

A = 102125.44

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HELP ME QUICICICKCKC

Answers

Answer:

A.

Step-by-step explanation:

Multiply the x like terms than multiply the other like terms

Need help on this! (Many points!)

Answers

Answer:

[tex]\frac{-8}{9}[/tex]

Step-by-step explanation:

Substitute in 7 for x

[tex]\frac{7^{2}-5(7) -6 }{7^{2}-6(7) - 16 }[/tex]

[tex]\frac{49-35-6}{49-42-16}[/tex]

[tex]\frac{-8}{9}[/tex]

Callie took out a loan for $7000 to purchase a car. The loan must be repaod at the end of six years in one payment with interest of 5%. The total amount Callie has to pay back at the end of the loan is
A.$7350
B.$9100
C.$7900
D.$9700

Answers

The correct value of answer is B. $9100.The interest on the loan is 5% of the principal. So, the interest amount is:= $350

To calculate the total amount Callie has to pay back at the end of the loan, we need to add the principal amount (the original loan amount) and the interest accrued over the six-year period.

The interest can be calculated using the formula: Interest = Principal * Rate * TimeHere, the principal amount is $7000, the interest rate is 5% (or 0.05 as a decimal), and the time is 6 years.

Interest = $7000 * 0.05 * 6 = $2100

Adding the interest to the principal, the total amount Callie has to pay back is:

Total amount = Principal + Interest = $7000 + $2100 = $9100

Therefore, the correct answer is B. $9100.

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What is the solution set of the quadratic inequality x^2-5<0?

Answers

The solution set of the quadratic inequality x² - 5 < 0 is - √5 < x < √5

How to determine the solution set?

From the question, we have the following parameters that can be used in our computation:

The quadratic inequality is:

x^2-5<0

Express properly

x² - 5 < 0

Add 5 to both sides of the inequality

x² < 5

Take the square root of both sides

x < ±√5

Expand the inequality expression

- √5 < x < √5

Hence, the solution is - √5 < x < √5

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Can someone help me with this, please?

Answers

π√π÷√π  is an irrational number. So option (a) is required answer.

What is irrational number?

A real number that cannot be stated as a ratio of integers is said to be irrational; an example of this is the number 2. Any irrational number, such as p/q, where p and q are integers, q, cannot be expressed as a ratio. Once more, an irrational number's decimal expansion is neither ending nor recurrent.

Examples of irrational number: √3, ∛2, π

π is an irrational because it is neither ending nor recurrent.

Solving each part of options, we get

π√π÷√π = π

√25 = 5

√π÷π = 1

2√2 ÷ √2 = 2

As most of the option give rational number only one option gives irrational number which is π

We get π from option (a)

So, option (a) is correct option.

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solve 2y=3x+12 for y

Answers

Answer: y=[tex]\frac{3x}{2}[/tex]+6

Step-by-step explanation:

isolate y by dividing both sides by 2

y=3x+12/2

y=[tex]\frac{3x+12}{2}[/tex]

y=[tex]\frac{3x}{2}[/tex]+6

Find the derivative using the Fundamental Theorem of Calculus, part 1, which states that if f(x) is continuous over an interval [a, b], and the function F(X) is defined by F(X) - F'(x) = f(x) over [a, b]. [*re) or, then del tot Additional Materials eBook 4.
then Find the derivative using the Fundamental Theorem of Calculus, part 1, which states that if f(x) is continuous over an interval (a, b), and the function F(x) is defined by F(X) - F'(x) = f(x) over [a, b]. de la intu In(u) du 6.
Evaluate the definite integral using the Fundamental Theorem of Calculus, part 2, which states that iffis continuous over the interval [a, b] and F(x) is any antiderivative of f(x), then Giºrno dx = F(b) – Fla). [x?- ») 3x) dx Х

Answers

On solving the question, by the help of, Fundamental Theorem of Calculus, we got answer  [tex]3xe^x[/tex]

What is fundamental Theorem of Calculus?

A theorem that connects the ideas of differentiating a function from integrating a function is known as the fundamental theorem of calculus. The two processes are inverses of one another, with the exception of a constant number that is dependent on the starting point for computing area.

When asked to compute the derivative of an integral, utilize the calculus fundamental theorem rather than evaluating the integral.

FTOC informs us that:

[tex]\frac{d}{dx} [\int\limits^{3x}_t {3lnt} \, dxt] = 3xe^x[/tex]

(That is, the integral's derivative returns the original function to us.)

We are required to locate:

h'(x) where h(x)= [tex]\int\limits^{3x}_t {3lnt} \, dxt= 3xe^x[/tex]

what we want

[tex]h'(x) = \frac{d}{dx} [\int\limits^{ex}_t {3lnt} \, dxt] = 3xe^x.............................A[/tex]

(Note that the first integral's upper limits are not in the proper format for the FTOC to be applied immediately.) The chain rule and a replacement can be used to alter the definite integral. Let:

[tex]u = e^x = \frac{du}{dx} = e^x[/tex]

Using the chain rule and substituting into the integral [A], we obtain:

[tex]\frac{d}{dx} [\int\limits^{ex}_t {3lnt} \, dxt] =[/tex][tex]\frac{d}{dx} [\int\limits^{u}_t {3lnt} \, dxt] = 3xe^x[/tex]

= [tex]e^x \frac{d}{du} [\int\limits^{ex}_t {3lnt} \, dxt] = 3xe^x[/tex]

now we got answer - [tex]3xe^x[/tex]

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Match the equation with its graph

Y=2/5x-1

Answers

Answer:

the second one

Step-by-step explanation:

f(x) = 3x² + 4x - 6
g(x) = 6x³5x² - 2

Find (f - g)(x).

O A. (f-g)(x) = 6x³ - 2x² + 4x - 8
O B. (f-g)(x) = -6x³ - 2x² + 4x - 8
O c. (f - g)(x) = 6x³ - 8x² - 4x + 4
O D. (f - g)(x) = -6x³ + 8x² + 4x - 4

Answers

The difference of the functions, f(x) = 3x² + 4x - 6 and g(x) = 6x³ - 5x² - 2, is: D. (f - g)(x) = -6x³ + 8x² + 4x - 4.

How to Find the Difference of Two Functions?

Finding the difference of two functions involves combining like terms together and then simplify.

Given the functions:

f(x) = 3x² + 4x - 6

g(x) = 6x³ - 5x² - 2

To find (f - g)(x), it implies that we find the difference between f(x) and g(x).

(f - g)(x) = f(x) - g(x)

Substitute

f(x) - g(x) = (3x² + 4x - 6) - (6x³ - 5x² - 2)

Open the parentheses:

f(x) - g(x) = 3x² + 4x - 6 - 6x³ + 5x² + 2

Combine like terms

f(x) - g(x) = - 6x³ + 8x² + 4x - 4

Therefore, the answer is: D. (f - g)(x) = -6x³ + 8x² + 4x - 4

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simplify 1+1

[tex] \frac{1}{(1 - { \sqrt{ 5} )}^{2 } } + \frac{1}{(1 + \sqrt{ {5)}^{2} } } [/tex]
simplify ​

Answers

The value of the surd when simplified is 1/6

How to simplify the surd?

We should recall that surd is the square root of all irrational numbers, simplification involves making it more simpler.

The given question is [tex]\frac{1}{(1-\sqrt{5 })^{2} } + \frac{1}{(1+\sqrt{5} )^{2} }[/tex]

We shall be simplifying the expression in parts

From difference of two squares

(1)/[(1-√5)(1+√5) = 1+5 = 1/6

The second part is 1/[(1+√5)(1+√5) = 1/(1+√10+5)

= 1/(6+√10)

Joining the two parts to get

1/6 + 1/(6+√10

Simplifying the fractions

(√10+1)/(6+√10)

= 1/6

Therefore the value of the expression is 1/6

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Find the measure of the arc or central angle indicated.

Answers

The central angle of the given arc LKJ is;  211°

How to find the length of an arc of a circle?

We want to find the length of the arc LKJ. The central angle for this arc length is; 115° + 96° = 211°

The formula for length of arc is;

L = θ/360 * 2πr

where;

θ is central angle

r is radius

We are not given the radius and as such, we can only find the central angle which is 211°

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Change the circle equation into standard form then answer the following questions:
of the center?
of the vertices?
Coordinates
Coordinates
How long is the radius?
Domain?
Range?
X²+ y²-14X + 8Y+ 40 = 0

Answers

We must transform the current polynomial to circle standard form: (x-h)^2+(y-k)^2=r^2. We will do so by completing the square, which produces a perfect square trinomial that can be factored into a square binomial in the form of the circle standard form.

First, use the commutative property to rearrange and group x and y:

x^2+(-14x)+y^2+8y+40=0

Now, we will subtract 40 from both sides:

x^2+(-14x)+y^2+8y=-40

We can now complete the square for both x and y:

(x^2-14x+(-14/2)^2)+(y^2+8y+(8/2)^2)=-40+(-14/2)^2+(8/2)^2

Simplify:

x^2-14x+49+y^2+8y+16=-40+49+16

Factor and simplify:

(x-7)^2+(y+4)^2=25

Now, factor the 25 to a squared factor:

(x-7)^2+(y+4)^2=5^2

The circle is now in standard form, so let’s identify its features:

Center: (h,k) = (7, -4)

Radius: 5

Vertices: (7, 1), (7, -9), (2, -4), (12, -4)

Domain: [2, 12]

Range: [-9, 1]

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When finding f(g(x)) what do you need to know about the domains and ranges
of f(x) and g(x)? Explain

Answers

All x-values that are within the scope of both f and g make up the domain of the (f g)(x).

How can the domain of f/g)(x be determined?All x-values that are within the scope of both f and g make up the domain of the (f g)(x). In this case, f has a domain of "x | x 0" and g has a domain of "all real numbers," thus (f g)(x) also has a domain of "x | x 0" since these values of x fall within both f and g's domains.Utilizing graphs is another method for determining the domain and range of functions. The collection of possible input values is referred to as the domain, and the domain of a graph is made up of all the input values displayed on the x-axis. The collection of potential output values that make up the range is represented by the y-axis.      

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A mining company owns two mines. These mines produce an ore that can be graded into two classes: regular grade and low grade. The company must produce at least 350 tons of regular-grade and 610 tons of low-grade ore per week. The first mine produces 5 tons of regular-grade and 17 tons of low-grade ore per hour. The second mine produces 20 tons of regular-grade and 10 tons of low-grade ore per hour. The operating cost of the first mine is $7000 per hour, and the operating cost of the second mine is $29,000 per hour. The first mine can be operated no more than 54 hours a week, and the second mine can be operated no more than 27 hours a week. How many hours per week should each mine be operated to minimize the cost?

Answers

The number of hours to operate the mines to minimize cost are Mine 1 hour = 30 hours and Mine 2 hour = 10 hours

How to determine the number of hours?

The given parameters can be represented using the following table of values

                             Mine 1 (x)              Mine 2 (y)   Available

Regular grade          5                            20             350

Low grade               17                             10              610

Operating cost      7000                     29000

Time                        54                              27

From the table, we understand that we are to minimize cost

This means that:

Objective function: C = 7000x + 29000y

Subject to:

5x + 20y ≥ 350

17x + 10y ≥ 610

Next, we plot the constraints on a graph (see attachment)

From the graph, we have

(x, y) = (30, 10)

This means that

Mine 1 hour = 30 hours

Mine 2 hour = 10 hours

Hence, the number of hours are 30 and 10 hours

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Your sorority is preselling tickets for an end of year formal. You will save 22% off the door price by prepaying
$56.40 per ticket now.

How much will you pay if you wait to purchase tickets at the door?

Answers

You will save 12.408

Answer:

$68.81

Step-by-step explanation:

22% of 56.40 can be found by multiplying

.22 and 56.4, which equals 12.408

therefore, if you add 12.408, or 12.41, to 56.40 you will get 68.81

The Fitzhugh-Nagumo model for the electrical impulse in a neuron states that, in the absence of relaxation effects, the electrical potential in a neuron v(t) obeys the differential equation dv dt = −v[v2 − (1 + a)v + a] where a is a positive constant such that 0 < a < 1. (a) For what values of v is v unchanging (that is, dv/dt = 0)? (Enter your answers as a comma-separated list.) v = (b) For what values of v is v increasing? (Enter your answer using interval notation.) (c) For what values of v is v decreasing? (Enter your answer using interval notation.)

Answers

The values of v for the electric impulse model in the Fitzhugh-Nagumo model are 0, 1, and a.

What is electric impulse?

The strength of the field is shown by the distance between the lines; the closer they are to one another, the stronger the field.

In this scenario, the field weakens as we travel away from the charge because the distance between the lines widens (it actually obeys an inverse square law,

The electric field, which is pointed away from the core charge, is indicated by the direction of the lines.

This is due to the fact that a positive test charge would be repelled away from the electric field if it were placed there because the direction of the electric field corresponds to the direction of the force that a positive test charge would experience when immersed in the electric field.

Hence, The values of v for the electric impulse model in the Fitzhugh-Nagumo model are 0, 1, and a.

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