The graph below represents the following system of inequalities.

Answer:

t>-10

31>k

-4>h

f≥6.8

this is the answer

The measure of angle ∠AOB is 180°. The correct option from the following is (A).

A turn's angle is quantified using degrees or °. A full turn encompasses 360°. A protractor can be used to determine the size of an angle. The term "acute" refers to an angle smaller than 90°. Obtuse refers to an angle between 90° and 180°. Reflex is an angle larger than 180 degrees. Right angles have an angle of exactly 90 degrees.

A quadrilateral is an enclosed form created by uniting four points, any three of which cannot be collinear. A quadrilateral is a polygon that has four sides, four angles, and four vertices. Let us study more about quadrilaterals' shapes, their characteristics, and the various kinds of quadrilaterals, as well as some examples of quadrilaterals.

For the given quadrilateral, the sum of angles is:

∠A + ∠O + ∠B = ∠AOB

60° + 60° + 60° = 180°

Hence, the correct option is (A).

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9514 1404 393

Answer:

  372 m²

Step-by-step explanation:

A vertical line down the center of the figure will divide it into two congruent trapezoids, each with bases 13 and 18, and height 12.

The area of one of them is ...

  A = 1/2(b1 +b2)h

So, the area of the two of them together is ...

  A = (2)(1/2)(b1 +b2)h = (b1 +b2)h

  A = (13 m + 18 m)(12 m) = 372 m²

Answer:

[tex]\frac{23x-37}{x-4}[/tex]

Step-by-step explanation:

Answer:

[tex]P(x>1)=0.9927[/tex]

Step-by-step explanation:

From the question we are told that:

Mean [tex]\=x =7[/tex]

Generally the Poisson equation for \=x is mathematically given by

[tex]P(x>1)=1-P(x \leq 1)[/tex]

Therefor

[tex]P(x>1)=1-(\frac{e^{-7}*7^0}{0!}+{\frac{e^{-7}*7^1}{1!})[/tex]

[tex]P(x>1)=1-(9.1*10^{-4}+6.3*10^{-3})[/tex]

[tex]P(x>1)=1-(7.3*10^{-3}[/tex]

[tex]P(x>1)=0.9927[/tex]

Answer:

I THINK IT IS 74 NOT 4

I HOPE THIS HELPS!!!!!

Answer:

3x3x13 and 2 x 2 x 2 x 2 x 2 x 5 x 5

Step-by-step explanation:

Answer:

3000 is the answer this question.

9514 1404 393

Answer:

  60

Step-by-step explanation:

The minimum number required is the least common multiple (LCM) of 15 and 4. The numbers 15 and 4 have no common factors, so their LCM is their product.

  15×4 = 60 strands are required

Answer:

pixxer

Step-by-step explanation:

please pick inside please

Answer:

I dont now

Step-by-step explanation:

plz conprendation

Answer:

The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is 68%.

The probability that a randomly selected infant has a birth weight between 110 and 130 is 38%.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 120 ounces and a standard deviation of 20 ounces.

This means that [tex]\mu = 120, \sigma = 20[/tex]

The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is

p-value of Z when X = 140 subtracted by the p-value of Z when X = 100.

X = 140

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{140 - 120}{20}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a p-value of 0.84

X = 100

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 120}{20}[/tex]

[tex]Z = -1[/tex]

[tex]Z = -1[/tex] has a p-value of 0.16

0.84 - 0.16 = 0.68

The probability that a randomly selected infant has a birth weight between 100 ounces and 140 ounces is 68%.

The probability that a randomly selected infant has a birth weight between 110 and 130

This is the p-value of Z when X = 130 subtracted by the p-value of Z when X = 110.

X = 130

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{130 - 120}{20}[/tex]

[tex]Z = 0.5[/tex]

[tex]Z = 0.5[/tex] has a p-value of 0.69

X = 110

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{110 - 120}{20}[/tex]

[tex]Z = -0.5[/tex]

[tex]Z = -0.5[/tex] has a p-value of 0.31

0.69 - 0.31 = 0.38 = 38%.

The probability that a randomly selected infant has a birth weight between 110 and 130 is 38%.

9514 1404 393

Answer:

  b:  -1.7, -1.5

Step-by-step explanation:

The graph is shown below. We have annotated the x-intercepts for the equivalent equation ...

  6x^2 +19x +15 = 0

Answer:

6.

Step-by-step explanation:

.

Answer:

[tex]C)\:8[/tex]

8 units tiles must be added

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Answer:

So 912$ is 58% of 1584 $

Step-by-step explanation:

Answer:

1. 0.1684 = 16.84%.

2. 0.2568 = 25.68%

3. 0.0013 = 0.13%

4. 0.0126 = 1.26%.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have blood that is Group O, or they do not. The probability of a person having blood that is Group O is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

45% of them have blood that is Group O

This means that [tex]p = 0.45[/tex]

Question 1:

This is P(X = 6) when n = 16. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 6) = C_{16,6}.(0.45)^{6}.(0.55)^{10} = 0.1684[/tex]

So 0.1684 = 16.84%.

Question 2:

This is P(X = 3) when n = 8. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{8,3}.(0.45)^{3}.(0.55)^{5} = 0.2568[/tex]

So 0.2568 = 25.68%.

Question 3:

This is P(X = 16) when n = 20. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 16) = C_{20,16}.(0.45)^{16}.(0.55)^{4} = 0.0013[/tex]

So 0.0013 = 0.13%.

Question 4:

This is P(X = 9) when n = 11. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 9) = C_{11,9}.(0.45)^{9}.(0.55)^{2} = 0.0126[/tex]

So 0.0126 = 1.26%.

Answer:

[tex]y = 125.00x + 591.00[/tex]

Step-by-step explanation:

Given

See attachment for table

Required

Equation for Paris

From the table, we have:

[tex]flight = 591.00[/tex]

[tex]hotel = 125.00[/tex]

Let the number of nights be x.

So, the equation for the total amount (y) is:

[tex]y = flight + hotel * x[/tex]

[tex]y = 591.00 + 125.00 * x[/tex]

[tex]y = 125.00x + 591.00[/tex]

Answer:

0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The standard deviation of the lifetime is 15 hours and the mean lifetime of a bulb is 520 hours.

This means that [tex]\sigma = 15, \mu = 520[/tex]

Find the probability of a bulb lasting for at most 528 hours.

This is the p-value of Z when X = 528. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{528 - 520}{15}[/tex]

[tex]Z = 0.533[/tex]

[tex]Z = 0.533[/tex] has a p-value of 0.7031

0.7031 = 70.31% probability of a bulb lasting for at most 528 hours.

Answer:

c) tan

Step-by-step explanation:

tan = Opposite side / close side

When close side = v         and     Opposite side = 2,8m

First simplify all polynomials and rewrite them in descending exponent order.

1. [tex]-x^2+2x[/tex]

2. [tex]x^3-4x^2[/tex]

3. [tex]-2x^2+2x+3[/tex]

Now observe the terms with highest exponents in each expression, in particularly focus on their exponent value,

[tex]-x^2[/tex] with value of 2

[tex]x^3[/tex] with value of 3

[tex]-2x^2[/tex] with value of 2

The value is also known as order of polynomial and it is a way to classify polynomials.

Every order creates a family of polynomials determined by the order (which is always greater than -1)

A polynomial such as (1) and (3) have an orders of 2, which is often called quadratic order and thus the polynomials (1), (3) are classified in the same family of quadratic polynomials, these are polynomials with order of 2.

Polynomial (2) however has an order of 3, which is called cubic order. This polynomial (2) is classified in the family of cubic polynomials.

There are of course many other families, in fact, infinitely many of them because you have order 0, 1, 2, 3, and so on there are precisely [tex]\aleph_0+1[/tex] read as "aleph 0 + 1" (the number of natural numbers + 1 (because 0 is not a natural number)) of polynomial families.

The first few have these fancy names, for example:

order 0 => constant polynomial

order 1 => linear polynomial

order 2 => quadratic polynomial

order 3 => cubic polynomial

order 4 => quartic polynomial

and so on.

Hope this helps!

Answer:

What function?

Step-by-step explanation:

Answer:

[tex]\displaystyle f(x)=\frac{3}{2}x^3-\frac{27}{2}x^2+36x-21[/tex]

Where:

[tex]\displaystyle a=\frac{3}{2}, \, b=-\frac{27}{2}, \, c=36, \text{and } d=-21[/tex]

Step-by-step explanation:

We are given a cubic function:

[tex]f(x)=ax^3+bx^2+cx+d[/tex]

And we want to find a, b, c and d such that the  function has a relative maximum at (2, 9); a relative mininum at (4, 3); and an inflection point at (3, 6).

Since the function has a relative maximum at (2, 9), this means that:

[tex]f(2)=9=a(2)^3+b(2)^2+c(2)+d[/tex]

Simplify:

[tex]8a+4b+2c+d=9[/tex]

Likewise, since it has a relative minimum at (4, 3):

[tex]f(4)=3=a(4)^3+b(4)^2+c(4)+d[/tex]

Simplify:

[tex]64a+16b+4c+d=3[/tex]

We can subtract the first equation from the second. So:

[tex](64a+16b+4c+d)-(8a+4b+2c+d)=(3)-(9)[/tex]

Simplify:

[tex]56a+12b+2c=-6[/tex]

Divide both sides by two. Hence:

[tex]28a+6b+c=-3[/tex]

Relative minima occurs only at the critical points of a function. That is, it occurs whenever the first derivative equals zero.

Find the first derivative. We can treat a, b, c and d as constant. Hence:

[tex]f'(x)=3ax^2+2bx+c[/tex]

Since it has a minima at (2, 9), it means that:

[tex]f'(2)=3a(2)^2+2b(2)+c=0[/tex]

Thus:

[tex]12a+4b+c=0[/tex]

(We will only need one of the two points to complete the problem.)

Inflection points occurs whenever the second derivative of a function equals zero. Find the second derivative:

[tex]f''(x)=6ax+2b[/tex]

Since there is a inflection point at (3, 6):

[tex]18a+2b=0\Rightarrow 9a+b=0[/tex]

Solve for b:

[tex]b=-9a[/tex]

Substitute this into the above equation:

[tex]12a+4(-9a)+c=0[/tex]

Solve for c:

[tex]c=24a[/tex]

Substitute b and c into the previously acquired equation:

[tex]28a+6(-9a)+(24a)=-3[/tex]

Solve for a:

[tex]\displaystyle -2a=-3\Rightarrow a=\frac{3}{2}[/tex]

Solve for b and c:

[tex]\displaystyle b=-9\left(\frac{3}{2}\right)=-\frac{27}{2}\text{ and } c=24\left(\frac{3}{2}\right)=36[/tex]

Using either the very first or second equation, solve for d:

[tex]\displaystyle 8\left(\frac{3}{2}\right)+4\left(-\frac{27}{2}\right)+2(36)+d=9[/tex]

Hence:

[tex]d=-21[/tex]

Hence, our function is:

[tex]\displaystyle f(x)=\frac{3}{2}x^3-\frac{27}{2}x^2+36x-21[/tex]

Answer:

D)

[tex]an = -6 \times {( \frac{1}{4} )}^{n - 1} [/tex]

Step-by-step explanation:

(See the picture)

The explicit formula is given as [tex]T_n=-6(\frac{1}{4} )^{n-1}[/tex]

The general explicit formula for a geometric sequence is expressed as:

Given the following recursive functions:

[tex]a_1=-6\\ a_n=a_{n-1}\cdot\frac{1}{4} [/tex]

Get the next two terms:

[tex]a_2=a_{1}\cdot\frac{1}{4} \\ a_2=-6\cdot\frac{1}{4} \\ a_2=\frac{-3}{2} [/tex]

For the third term:

[tex]a_3=a_{2}\cdot\frac{1}{4} \\ a_3=\frac{-3}{2} \cdot\frac{1}{4} \\ a_3=\frac{-3}{8} [/tex]

The common ratio for the sequence will be [tex]\frac{1}{4} [/tex]

The explicit formula is given as [tex]T_n=-6(\frac{1}{4} )^{n-1}[/tex]

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Answer:

Price of X is $24.81

Price of Y is $3.66

Price of Z is $11.36

Step-by-step explanation:

for person A, we know that earns $40, then we can write the equation:

-4*z + 3*x + 3*y = $40

For person B, we know that earns $50, then:

1*z + 2*x - 3*y = $50

For person C, we know that earns $130, then:

6*z - 1*x + 4*y = $130

Then we have a system of equations:

-4*z + 3*x + 3*y = $40

1*z + 2*x - 3*y = $50

6*z - 1*x + 4*y = $130

To solve the system, we need to isolate one of the variables in one of the equations.

Let's isolate z in the second equation:

z = $50 - 2*x + 3*y

now we can replace this in the other two equations:

-4*z + 3*x + 3*y = $40

6*z - 1*x + 4*y = $130

So we get:

-4*($50 - 2*x + 3*y) + 3*x + 3*y = $40

6*($50 - 2*x + 3*y) - 1*x + 4*y = $130

Now we need to simplify both of these, so we get:

-$200 + 11x - 9y = $40

$350 - 13*x + 28*y = $130

Now again, we need to isolate one of the variables in one of the equations.

Let's isolate x in the first one:

-$200 + 11x - 9y = $40

11x - 9y = $40 + $200 = $240

11x = $240 + 9y

x = ($240 + 9y)/11

Now we can replace this in the other equation:

$350 - 13*x + 28*y = $130

$350 - 13*($240 + 9y)/11 + 28*y = $130

Now we can solve this for y.

- 13*($240 + 9y)/11 + 28*y  = $130 - $350 = -$220

-13*$240  - (13/11)*9y + 28y = - $220

y*(28 - (9*13/1) ) = -$220 + (13/11)*$240

y = ( (13/11)*$240 - $220)/(28 - (9*13/1) ) = $3.66

We know that:

x = ($240 + 9y)/11

Replacing the value of y, we get:

x = ($240 + 9*$3.66)/11  = $24.81

And the equation of z is:

z = $50 - 2*x + 3*y = $50 - 2* $24.81 + 3*$3.66 = $11.36

Then:

Price of X is $24.81

Price of Y is $3.66

Price of Z is $11.36

Answer:

[tex]P(x < 3) = 25\%[/tex]

[tex]E(x) = 3[/tex]

Step-by-step explanation:

The given parameters can be represented as:

[tex]\begin{array}{ccccccc}x & {5} & {4} & {3} & {2} & {1}& {0} & P(x) & {25\%} & {30\%} & {20\%} & {15\%} & {5\%} & {5\%} \ \end{array}[/tex]

Solving (a): P(x < 3)

This is calculated as:

[tex]P(x < 3) = P(x = 0) + P(x = 1) + P(x =2)[/tex] ----- i.e. all probabilities less than 3

So, we have:

[tex]P(x < 3) = 5\% + 5\% + 15\%[/tex]

[tex]P(x < 3) = 25\%[/tex]

Solving (b): Expected number of events

This is calculated as:

[tex]E(x) = \sum x * P(x)[/tex]

So, we have:

[tex]E(x) = 5 * 25\% + 4 * 30\% + 3 * 20\% + 2 * 15\% + 1 * 5\% + 0 * 5\%[/tex]

[tex]E(x) = 125\% + 120\% + 60\% + 30\% + 5\% + 0\%[/tex]

[tex]E(x) = 340\%[/tex]

Express as decimal

[tex]E(x) = 3.40[/tex]

Approximate to the nearest integer

[tex]E(x) = 3[/tex]

Answer:

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

Step-by-step explanation:

We are given the following function:

[tex]f(x) = \frac{x+1}{x^2-6x+8}[/tex]

It's a fraction, so the domain is all the real values except those in which the denominator is 0.

Denominator:

Quadratic equation with [tex]a = 1, b = -6, c = 8[/tex]

Using bhaskara, the denominator is 0 for these following values of x:

[tex]\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4[/tex]

[tex]x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]

[tex]x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

Answer:

41 feet

Step-by-step explanation:

12 +12 + [tex]\sqrt{144+144}[/tex]

Answer:

Perfilar. Comienza por delimitar la forma y dimensión del macizo. ...

Cavar y abonar. ...

Enmarcar y rastrillar. ...

Distribuir y plantar.

Step-by-step explanation:

500 kwh

$105 - $30 = $75

$75 / $0.15 = 500

Answer:

$105-$30 service fee, this leaves only the electricity used. $75. now to find how many kilowatt hours used you divide $75/.15=500 answer 500 kilowatt hours.

Step-by-step explanation:

see above

Answer:

n=-9,-8,-7

Step-by-step explanation:

n<100

but that is the positive square root

\(-10 n is between the negative and positive square root of 100

thus, n=-9,-8,-7

The solution of the inequality n² < 100 will be less than 10.

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.

The inequality is given below.

n² < 100

Simplify the equation, then we have

n² < 100

n² < 10²

n < 10

The solution of the inequality n² < 100 will be less than 10.

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Answer:

$49.5

Step-by-step explanation:

* means multiply

at $1.98 per loaf

25 * 1.98 =

49.5

Answer:

48.75

Step-by-step explanation:

It would be the cheapest option