The hi density of water is 1g/cubic cm.if object with a mass of 100g has a weight of 1n on earth.calculate the volume of water displaced by the object.

Answers

Answer 1

The volume of water displaced by an object with a mass of 100 g and a weight of 1 N on Earth is 0.102 m³.

The formula used to calculate the volume of a fluid displaced by an object is V = m/ρ, where m is the mass of the object, and ρ is the density of the liquid it is Immersed in.

Therefore, in order to calculate the volume of water displaced by the object with a mass of 100g, we must first determine the relationship between mass and weight.

In this situation, the object has a weight of 1N on Earth. For objects, the weight can be calculated using the formula W = mg (where W is weight, m is mass, and g is the gravitational acceleration).

Given that the gravitational acceleration of Earth is 9.8 m/s², the mass of the object can be calculated as m = W/g. Therefore in this case, m = 1N/9.8 m/s² = 0.102 kg.

Now that we know the mass of the object, we can calculate the volume of water displaced.

Using the formula V = m/ρ, where m is 0.102 kg, and ρ is the density of water (1 g/cubic cm), the volume of water displaced by the object can be calculated to be V = 0.102 kg/1 g/cubic cm = 0.102 m³.

Therefore, the volume of water displaced by an object with a mass of 100 g and a weight of 1 N on Earth is 0.102 m³.

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Related Questions

Discuss whether any work is being done by each of the following agents and, if so, whether the work is positive or negative. (c) a crane lifting a bucket of concrete

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The crane lifting the bucket of concrete is doing positive work as it applies a force in the direction of the displacement.

In the case of a crane lifting a bucket of concrete, work is indeed being done. The work done by the crane can be determined by the equation:

Work = Force x Distance x cos(θ)

Here, the force is the upward force exerted by the crane on the bucket, the distance is the vertical displacement of the bucket, and θ is the angle between the force and the displacement.

Since the crane is lifting the bucket upward, the force exerted by the crane and the displacement of the bucket are in the same direction. Therefore, the angle θ between them is 0 degrees, and the cosine of 0 degrees is 1. As a result, the work done by the crane is positive.

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