Answer:
A). The complementary shapes of an enzyme and a substrate.
Explanation:
The Lock-and-key mechanism was proposed by Emil Fischer for the first time and characterized as the metaphor which helps in elucidating the specificity of the enzymatic reactions. In this metaphor, the lock is described as the enzyme while 'key' is characterized as the substrate which the enzyme acts upon. If the key is not appropriately sized, it will not fit into the active site i.e. the keyhole of the lock or enzyme and reaction will not take place. Thus, option A is the correct answer.
9 different lab rules Explain how students will do a safe lab
Answer:
Report all accidents, injuries and breakage of class or equipment to instructor immediately.Keep pathways clear by placing extra items on the shelves or under the work tables. If under the tables make sure that these items can no be stepped on.Long hair (chin-length or longer) must be tied back to avoid catching fire.Wear sensible clothing including footwear. Loose clothing should be secure so they do not get caught in a flame or chemicals.Work quietly - know what you are doing by reading the assigned experiment before you start to work. Pay close attention to any cautions described in the laboratory exercises.Do not taste or smell chemicals.Wear safety goggles to protect your eyes when heating substances, dissecting, etcDo not attempt to change the position of glass tubing in a stopper.Never point a test tube being heated at another student or yourself. Never look into a test tube while you are heating it.Hope this helps:))
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A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X
[tex] \LARGE{ \boxed{ \rm{ \red{Required \: answer}}}}[/tex]
☃️ Chemical formulae ➝ [tex]\sf{CaCO_3}[/tex]
How to find?For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
[tex] \boxed{ \sf{No. \: of \: moles = \frac{given \: weight}{molecular \: weight} }}[/tex]
Solution:Atomic weight of elements:
Ca = 40
C = 12
O = 16
❍ Molecular weight of [tex]\sf{CaCO_3}[/tex]
= 40 + 12 + 3 × 16
= 52 + 48
= 100 g/mol
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 g / 100 g mol‐¹
⇛ No. of moles = 0.1 moles
☄ No. of moles of Calcium carbonate in that substance = 0.1 moles
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Which ionic equation for reaction of Magnesium with dilute hydrochloric acid is correct? Mg (s) + 2H+ (aq) â Mg2+ (aq) + H2 (g) Mg (s) + 2HCl (aq) â MgCl2+ (aq) + H2 (g) Mg (s) + 2H+ (aq) â Mg2+ (s) + H2 (g) Mg (s) + H+ (aq) â Mg+ (aq) + H2 (g)
Answer:
Mg(s) + 2H⁺(aq) ⟶ Mg²⁺(aq) + H₂(g)
Explanation:
A net ionic equation shows all the ionic substances as ions and shows the correct state of each substance.
B. is wrong. HCl ionizes in aqueous solution into H⁺ and Cl⁻.
C. is wrong. Mg²⁺ is not a solid. It is an aqueous ion.
D. is wrong. The equation needs 2H⁺(aq) to be balanced.