The picture is above no one answers my questions can someone please answer this I will be so thankful!

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Explanation:

The term "equidistant" means "equally distant".

We want (x,y) to be the same distance to the x axis, the y axis, and the point (3,6).

Let n represent this unknown equal distance. Negative distance doesn't make sense, so we'll have n > 0.

Start at the origin and move n units to the right to arrive at (n,0). We are n units from the y axis.

Now move n units up to arrive at (n,n). This point is guaranteed to be n units away from each axis.

That is one potential point. Other potential points are:

One point for each quadrant.

Let's assume that the answer is in the 1st quadrant since (3,6) is located here.

We need to find an expression that represents the distance from the point (n,n) to (3,6). We'll set that distance expression equal to n so we can solve.

Part 1 of those steps

[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\n = \sqrt{(n-3)^2+(n-6)^2}\\\\n^2 = (n-3)^2+(n-6)^2\\\\n^2 = (n^2-6n+9)+(n^2-12n+36)\\\\n^2 = 2n^2-18n+45\\\\[/tex]

Part 2 of those steps

[tex]0 = 2n^2-18n+45-n^2\\\\0 = n^2-18n+45\\\\n^2-18n+45 = 0\\\\(n-3)(n-15) = 0\\\\n-3 = 0\ \text{ or } \ n-15 = 0\\\\n = 3\ \text{ or } \ n = 15\\\\[/tex]

The quadratic formula could be used as an alternative pathway.

Therefore, the mystery point could be located at (3,3) or at (15,15)

Use the distance formula to verify each answer. I'll let you do this part.

---------

Extra info:

If you were to perform similar steps with the point (-n,n), then you'll find that no real numbered solutions exist. The two solutions would be complex numbers.

The cases (n,-n) and (-n,-n) have no solutions at all.

Therefore, we have confirmed only case (n,n) would work.

- 125/216 . A rational number can also be expressed as a fraction as long as the denominator is not 0. It can consist of negative, positive numbers too. i hope this helped

The answer is C because they do not repeat.

Answer:

......................

Step-by-step explanation:

you are welcome

Answer:

x=0

Step-by-step explanation:

-14-8x=-2(-3x+7)

-14-8x=6x-14

-8x=6x+0

-2x=0

x=0

Answer:

(-5,4)

Step-by-step explanation:

If you look at A and then at AB midpoint you will see that A is 5 down from M and 4 right from M. So, if you minus 4 from -1 you get -5, and if you add 5 from -1 you get 4. Therefor the answer is (-5,4)

Advanced math : shes correct

Answer: That would be 28q+12

Step-by-step explanation:

4(7q)= 28q

4(3)=12

hope this helps.

Answer:

28q+12

Step-by-step explanation:

hope this helps sorry i get it wrong

4(7q)= 28q

4(3)=12

Answer:

  (0, -26)

Step-by-step explanation:

We can use the 2-point form of the equation for a line to write its equation:

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (1 -(-8))/(36 -24)(x -24) -8

  y = 9/12(x -24) -8

  y = 3/4x -26

Comparing this to slope-intercept form:

  y = mx + b

we see that the y-intercept, b, is -26.

The y-intercept of the line is (0, -26).

Answer:

4n + 16

Step-by-step explanation:

Difference = +4 each time

20 - 4(1) = 16

Therefore nth term = 4n + 16

Proof:

4(2) + 16 = 24

4(3) + 16 = 28

Answer: 16

Step-by-step explanation:

She runs an average of 1 mile per 8 minutes. 2 miles would be 16 minutes

6 ÷ q × 3

Filler so I can post

Answer:

It can divide equally  

Step-by-step explanation:

Answer:

The symmetric property of equality. :)

Answer:

8 hours

Step-by-step explanation:

57 + 9h = 129

9h = 72

h = 8

Heidi needs to babysit for 8 hours to afford the new bike.

The linear equation is the algebraic form of equation whose variable has the exponent of one. It is the combination of two variables and a constant value present in them.

For the given situation,

Heidi's savings = $57

Amount for babysitting per hour = $9

Total cost of the bike = $129

Let us consider 'x' for hours she needs to babysit.

This can be represented as linear equation as

[tex]57 +9h=129[/tex]

⇒ [tex]9h=129-57[/tex]

⇒ [tex]9h=72[/tex]

⇒ [tex]h=8[/tex]

Hence we can conclude that Heidi needs to babysit for 8 hours to afford the new bike.

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Answer:

Step-by-step explanation:

Try using g(x)

Let g(x) = y

y = 2x + 4

Interchange x and y

x = 2y + 4

Subtract 4 from both sides

x - 4 = 2y

Divide by 2

x/2 - 4/2 = 2y/2

y = x/2 - 2

This is exactly what f(x) is

So g(x) and f(x) are inverses.

Answer:

2x=4

Step-by-step explanation:

3(2x-5)-4x+8=-2x+1

6x-15-4x+8=-2x+1

2x-15+8=-2x+1

2x-7=-2x+1

4x=8

2x=4

a)  Yes, the result is significant at the 5% level.

b)  No, the result is not significant at the 5% level.

c)The difference in significance between the two results can be explained by the slight increase in the sample mean from 541.4 to 541.5.

(a)To test the hypotheses, we will use a one-sample t-test since we have the sample mean (xbar = 541.4) and the population standard deviation (σ = 100) is known. The sample size is 100.

The test statistic (t-score) is calculated using the formula:

t = (xbar - μ) / (σ / √n)

where xbar is the sample mean, μ is the population mean under the null hypothesis, σ is the population standard deviation, and n is the sample size.

In this case:

xbar = 541.4, μ = 525, σ = 100, and n = 100.

t = (541.4 - 525) / (100 / √100)

t = 16.4 / 10

t = 1.64

Using a significance level of 0.05 (5%), we compare the t-score to the critical value from the t-distribution table. For a one-tailed test, the critical value at the 5% level with degrees of freedom (df) = n - 1 = 99 is approximately 1.66.

Since the calculated t-score (1.64) is smaller than the critical value (1.66), we fail to reject the null hypothesis. The result is not statistically significant at the 5% level.

(b)Using the same calculations as in part a), the t-score is calculated as follows:

t = (541.5 - 525) / (100 / √100)

t = 16.5 / 10

t = 1.65

The critical value at the 5% level with df = 99 is still approximately 1.66.

Since the calculated t-score (1.65) is still smaller than the critical value (1.66), we still fail to reject the null hypothesis. The result is not statistically significant at the 5% level.

c)While the increase is minimal, it leads to a slightly higher t-score (1.65) in part b) compared to part a) (1.64).

Considering that any increase greater than 15 points is considered a success, it's important to note that neither result (541.4 or 541.5) meets this criterion. Therefore, the training program does not appear to have a statistically significant impact on GMAT scores based on the given data and significance level.

It's worth considering a larger sample size or conducting further studies to gather more data and assess the training program's effectiveness with a higher degree of certainty.

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X(t) = Pexp(Dt)P⁻¹X(0),where X(0) is the initial Condition.

9.1 To find the eigenvalues of a matrix A is equivalent to finding the solutions to the equation det(A- λI) = 0. λ is an eigenvalue of A if and only if λ is a solution of the characteristic equation det(A- λI) = 0.

We have A = [2 9; 1 2]

The characteristic equation is given by|2- λ 9| = (2- λ)(2- λ) - 9 = λ² - 4λ - 5 = 0Therefore, the eigenvalues are given byλ₁ = -1 and λ₂ = 5.9.2

The eigenspace of a matrix A associated with an eigenvalue λ is the set E of all eigenvectors of λ, together with the zero vector E = ker(A - λI).

Thus we must solve the equations(A - λ₁I)x = 0 and (A - λ₂I)x = 0.For λ₁ = -1, we have A + I = [3 9; 1 3],

giving(A + I)x = 0 ⇒ x₁ + 3x₂ = 0 ⇒ x₁ = - 3x₂.So the eigenspace E₁ = Span{(-3, 1)}.For λ₂ = 5, we have A - 5I = [-3 9; 1 -3], giving(A - 5I)x = 0 ⇒ - 3x₁ + 9x₂ = 0 ⇒ x₁ = 3x₂.So the eigenspace E₂ = Span{(3, 1)}.9.3

If there exists a basis of eigenvectors for A, then A is diagonalizable. A is diagonalizable if and only if the eigenspaces Ei are such that dim(Ei) = multiplicity of λi, where λi is the ith eigenvalue of A. If so, then A is similar to a diagonal matrix .

The dimensions of E₁ and E₂ are both 1, and so dim(E₁) + dim(E₂) = 2 = n, where n is the order of the matrix.

So A is diagonalizable.9.4 Let P = [x y] be a matrix whose columns are the eigenvectors of A.

Then P-¹AP is a diagonal matrix whose diagonal entries are the eigenvalues of A.

So, we have P = [-3 3; 1 1], with P⁻¹ = [-⅓ ⅓; ⅓ ⅓] andP⁻¹AP = [-1 0; 0 5].Therefore, A = P[P⁻¹AP]P⁻¹ = [-3 3; 1 1][1 0; 0 5][-⅓ ⅓; ⅓ ⅓] = [-2 -9; 1 2].9.5 We have already found that A = PDP⁻¹ whereD = diag(-1, 5) andP = [-3 3; 1 1].

Therefore,A² = PDP⁻¹PDP⁻¹ = PD²P⁻¹= [-3 3; 1 1][1 0; 0 25][-⅓ ⅓; ⅓ ⅓] = [7 -27; 5 -19].A³ = A²A = [7 -27; 5 -19][-2 -9; 1 2] = [-187 297; -131 207].9.6

The differential equations are 3/₁ = ₁ + 2x₂ and 3/₂ = 21₁ + 1₂. We can write these asa vector equationX' = AX,where X = [x₁ x₂]ᵀ, X' = [3/₁ 3/₂]ᵀand A = [1 2; 21 1].We have already diagonalised A as A = PDP⁻¹, whereD = diag(-1, 5) andP = [-3 3; 1 1].Therefore,X' = AX ⇒ P⁻¹X' = P⁻¹AX ⇒ Y' = DY,where Y = P⁻¹X = [-1/3 2/3; 1/3 1/3]X and Y' = P⁻¹X'.SoY' = DY = [-1 -5; 2 10]Y.

The solution is given byY(t) = exp(Dt)Y(0),where exp(Dt) is the matrix exponential exp(Dt) = [e⁻ᵗ e⁻5ᵗ; -2e⁻ᵗ + 2e⁻5ᵗ 2e⁻ᵗ - e⁻5ᵗ].

Therefore,X(t) = Pexp(Dt)P⁻¹X(0),where X(0) is the initial condition.

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Answer:

9997.46

Step by step Explanation

The product of the complex numbers (3 + 4i) and (6 + i) is 14 + 27i, where i² = -1.

To find the product of the given complex numbers: (3 + 4i)(6 + i)There are different methods to solve this multiplication problem, but one common way is to use the FOIL method:

First, Outer, Inner, Last. This method involves multiplying each term in the first complex number by each term in the second complex number.

FOIL method: First: (3)(6) = 18Outer: (3)(i) = 3iInner: (4i)(6) = 24iLast: (4i)(i) = -4

Using this method, we can write the product as: (3 + 4i)(6 + i) = 18 + 3i + 24i - 4i²

The term i² equals -1, so we can substitute -1 for i² and simplify: (3 + 4i)(6 + i) = 18 + 27i - 4= 14 + 27i

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In question C1, we are asked to prove that the span of the standard basis B = {e₁, e₂, ..., eₙ} for Rⁿ is equal to Rⁿ, and also that B is linearly independent.

To prove that the span of B is equal to Rⁿ, we need to show that every vector in Rⁿ can be expressed as a linear combination of the vectors in B. Since the vectors in B are the standard basis vectors, they have a value of 1 in only one component and 0 in all other components. Any vector in Rⁿ can be written as a linear combination of these standard basis vectors by assigning appropriate coefficients. Therefore, the span of B includes all possible linear combinations, covering all vectors in Rⁿ.

To prove that B is linearly independent, we need to show that the only solution to the equation a₁e₁ + a₂e₂ + ... + aₙeₙ = 0 (where a₁, a₂, ..., aₙ are scalars) is when a₁ = a₂ = ... = aₙ = 0. Since the vectors in B are distinct and have a value of 1 in only one component, the only way the equation can hold true is when all the coefficients are zero. Thus, B is linearly independent.

Overall, the proof establishes that the span of the standard basis B is equal to Rⁿ, indicating that B can represent any vector in Rⁿ, and also verifies that B is linearly independent, implying that the vectors in B are not redundant or dependent on each other.

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False.

For a square matrix A, the vectors in the column space of A (col(A)) are not necessarily orthogonal to the vectors in the null space of A (nul(A)). The column space consists of all possible linear combinations of the columns of A, while the null space consists of all vectors that satisfy the equation Ax = 0.

Orthogonality between col(A) and nul(A) would imply that any vector in col(A) is perpendicular to any vector in nul(A), which is generally not the case. There may exist some specific scenarios where col(A) and nul(A) have orthogonal vectors, but it is not a general property.

Therefore, the statement that vectors in the column space of a square matrix A are orthogonal to vectors in the null space of A is false.

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Answer:

The answer to what?

Step-by-step explanation:

Answer:

x² + 2hx + h² - 4

Step-by-step explanation:

To evaluate f(x + h), substitute x = x + h into f(x), that is

fx + h)

= (x + h)² - 4 ← expand (x + h)² using FOIL

= x² + 2hx + h² - 4

Answer:

x = 3.8

Step-by-step explanation:

Perimeter is all the side lengths added up.

Step 1: Set up equation

x + 2(8.3) + 3.8 = 24.2

Step 2: Solve for x

Answer:

[tex]\Large \boxed{\sf 3.8}[/tex]

Step-by-step explanation:

Perimeter of a shape is the sum of all sides.

Opposite sides in a parallelogram are of equal length.

Answer:

x=28/3

Step-by-step explanation:

Answer:

x=9 and 1/3

Step-by-step explanation:

x/8+5/6=2

Common denominator will be 48. So:

6x/48+40/48=2

That means that (6x+40)/48=2

(since they both have the same denominator)

Now, multiply 2 by 48. You get 96.

6x+40=96

Subtract 40

6x=56

x=9 and 1/3

Answer:

1) x=67, y=83, z=80 2) x=5

Step-by-step explanation:

1) 28+85=113 a triangle is 180 degrees so 180-113=67 so x=67

x and y are supplementary meaning both sides equal 150 so 150-67=83

83+17=100 now going back how much did i say a triangle should equal? 180 so z is 80

2)a triangle = 180 since the triangle is a right angle it includes the angle 90 so make the equation to solve for x

180=90+8x+2+9x+3

take 90 to other side so you are subtracting 180-90

90=8x+2+9x+3

combine like terms

90=17x+5

subtrcat 5 from 90

85=17x

now divide 85 by 17 and you get x=5

The probability that a randomly selected day in December will have an average temperature of at least 60°F is approximately 0.1935 (or 19.35%).

To calculate the probability of randomly selecting a day with an average temperature of at least 60°F, you need additional information. Specifically, you need to know the total number of days in December in Orange County, CA.

Since you mentioned that there are 31 days in the month of December, we'll assume that this is accurate. In that case, the probability can be calculated based on the 31-day period.

Given that the dataset consists of 20 days and only 6 of them have an average temperature of at least 60°F, you can calculate the probability as follows:

Probability = (Number of days with average temperature ≥ 60°F) / (Total number of days in December)

Probability = 6 / 31

So, the probability that a randomly selected day in December will have an average temperature of at least 60°F is approximately 0.1935 (or 19.35%).

Please note that if the actual number of days in December differs from 31 or if you have access to a larger dataset, the probability calculation would change accordingly.

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Our goal is to find values of X, Y₁, and Y₂ that make both equations equal to zero.The unknown Variables: X, Y₁, Y₂,The equations: Equation (1) and Equation (2)

In the given equations, we have three unknown variables: X, Y₁, and Y₂. These variables represent the values we are trying to find.

We also have two equations, labeled as Equation (1) and Equation (2). These equations provide the relationships between the variables.

To solve for the unknown variables, we need to find values of X, Y₁, and Y₂ that satisfy both equations simultaneously.

Let's restate the equations for clarity:

Equation (1): X - a + bY₁ = 0

Equation (2): X - e - dY₂ = 0

Our goal is to find values of X, Y₁, and Y₂ that make both equations equal to zero.

So, in summary:

- The unknown variables: X, Y₁, Y₂

- The equations: Equation (1) and Equation (2)

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Answer:

15

Step-by-step explanation:

Prime factorization of the numbers:

330 = 2 × 3 × 5 × 11

75 = 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

225 = 3 × 3 × 5 × 5

LCM(330, 75, 450, 225)

= 2 × 3 × 3 × 5 × 5 × 11

= 4950

GCD(330, 75, 450, 225) = 15