URGENT please help _​

There is a 25% chance that a flight between New York City and Chicago will take between 97 and 98 minutes.

Since the time to fly between New York City and Chicago is uniformly distributed between 96 and 100 minutes, the probability of a flight being between any two times is proportional to the length of the time interval between those two times.

To find the probability that a flight is between 97 and 98 minutes, we need to calculate the length of the time interval between those two times, which is 1 minute.

Then, we divide the length of the interval by the length of the entire time range (100-96 = 4 minutes) to obtain the probability of a flight being between 97 and 98 minutes: Probability = 1 minute / 4 minutes = 0.25 or 25%.

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Answer:

Step-by-step explanation:

To find the mean, we need to calculate the sum of all the values and divide by the number of data values. Using the stem and leaf plot and the key, we can determine the following data values:

12, 15, 17, 22, 25, 26, 28, 32, 33, 34, 36, 37, 39, 42, 44, 45, 46, 47, 48, 49, 52, 53, 55, 57, 57, 59, 62, 65, 68, 72, 73, 75, 75, 77, 79, 82, 85, 88, 92, 95

There are 37 data values in total. To find the sum of the data, we can add up all the individual values:

12 + 15 + 17 + 22 + 25 + 26 + 28 + 32 + 33 + 34 + 36 + 37 + 39 + 42 + 44 + 45 + 46 + 47 + 48 + 49 + 52 + 53 + 55 + 57 + 57 + 59 + 62 + 65 + 68 + 72 + 73 + 75 + 75 + 77 + 79 + 82 + 85 + 88 + 92 + 95 = 2098

So the sum of the data is 2098. To find the mean, we divide the sum by the number of data values:

MEAN = sum of data / number of data values

MEAN = 2098 / 37

MEAN = 56.7568

Rounded to the nearest hundredth, the mean of the data is 56.76. Therefore, the answer is closest to option A) 57.

To find the point P on the line y=3x that is closest to the point (50,0), we need to use the formula for the distance between a point and a line. This formula is:

distance = |Ax + By + C| / sqrt(A^2 + B^2)

Where A, B, and C are the coefficients of the equation of the line in the form Ax + By + C = 0.

In this case, the equation of the line y=3x can be written as -3x + y = 0. So we have:

A = -3, B = 1, C = 0

Now we can plug in the values of (50,0) and solve for x and y to find the point P that is closest to it:

distance = |-3x + y| / sqrt((-3)^2 + 1^2)
distance = |-3x| / sqrt(10)

To minimize the distance, we need to minimize |-3x|. This occurs when x = 0. So the point P that is closest to (50,0) is the point (0,0).
To find the point P on the line y = 3x that is closest to the point (50, 0), we need to minimize the distance between P and (50, 0).

Let P(x, y) be a point on the line y = 3x. The distance between P and (50, 0) is given by the distance formula:

D = sqrt((x - 50)^2 + (y - 0)^2)

Since y = 3x, we can rewrite the distance formula as:

D = sqrt((x - 50)^2 + (3x)^2)

To minimize the distance, we can minimize the square of the distance (D^2), as it avoids dealing with the square root:

D^2 = (x - 50)^2 + (3x)^2

Now, we can find the derivative of D^2 with respect to x and set it to 0 to find the critical points:

d(D^2)/dx = 2(x - 50) + 2(3x)^2 * 6x = 0

Solve this equation to find the x-coordinate of the point P. Then, use y = 3x to find the corresponding y-coordinate. Finally, you'll have the coordinates of the point P that is closest to (50, 0).

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The claim that the population mean is less than 125 (Option E) would

the interval tends to refute.

The 90% confidence interval for the population mean is 135 to 160. This means that if we were to repeat the process of taking samples from the same population and constructing a 90% confidence interval, we would expect 90% of the intervals to contain the true population mean.

With this in mind, let's consider each claim:

A. The interval does not rule out the possibility that the population mean is more than 110, as 110 is less than the lower bound of the interval.

B. The interval does not rule out the possibility that the population mean is less than 150, as 150 is greater than the upper bound of the interval.

C. The interval does not rule out the possibility that the population mean is between 140 and 150, as both of these values fall within the interval.

D. The interval does not rule out the possibility that the population mean is more than 140, as 140 is less than the upper bound of the interval.

E. The interval refutes the claim that the population mean is less than 125, as 125 is less than the lower bound of the interval.

Therefore, the answer is (E) The population mean is less than than 125.

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By using completing the square method, the solution to this quadratic equation is x = √13 ± 2.

In Mathematics, the standard form of a quadratic equation is represented by the following equation;

ax² + bx + c = 0

Next, we would solve the given quadratic equation by using the completing the square method;

x² - 4x - 9 = 0

x² - 4x = 9

In order to complete the square, we would have to add (half the coefficient of the x-term)² to both sides of the quadratic equation as follows:

x² - 4x + (4/2)² = 9 + (4/2)²

x² - 4x + 4 = 9 + 4

x² - 4x + 4 = 13

By simplifying, we have;

(x - 2)² = 13

x = √13 ± 2

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Answer:

84.5 square units.

Step-by-step explanation:

The formula to calculate the area of a trapezoid is:

Area = (base 1 + base 2) * height / 2

Using the measurements you provided, we can calculate the area of the trapezoid as follows:

Area = (12 + 14) * 6.5 / 2

Area = 26 * 6.5 / 2

Area = 169/2

Area = 84.5

Therefore, the area of the trapezoid is 84.5 square units.

Answer:Mode = 33, Mean = 35.5

Step-by-step explanation:

The mode is whatever number appears the most.

To find the mode, first put the numbers in order from least to greatest.

29, 31, 33, 33, 37, 38, 40, 43

In this case, 33 appears the most, so the mode is 33.

The mean is the average of all of the numbers.

Firstly, add up all of the numbers:

29 + 31 + 33 + 33 + 37 + 38 + 40 + 43 = 284

Now that you have all of them added up, divide the final sum by the number of numbers you have in the list. In this case, you have 8 numbers.

284/8 = 35.5

Your mean is 35.5

If the area of a square of side (4x-1) is equal to 49, the perimeter of the square is 12 units.

We can start by using the formula for the area of a square, which is side squared, to solve for the side of the square. In this case, we know that the area of the square is 49, so we can set up the equation as follows:

(4x-1)² = 49

Expanding the left side of the equation, we get:

16x² - 8x + 1 = 49

Subtracting 49 from both sides, we get:

16x² - 8x - 48 = 0

Dividing both sides by 8, we get:

2x² - x - 3 = 0

We can solve for x using the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

Plugging in the values of a, b, and c from our equation, we get:

x = (-(-1) ± √((-1)² - 4(2)(-3))) / 2(2)

x = (1 ± √(25)) / 4

x = (1 ± 5) / 4

x = 1 or x = -3/2

Since the side of a square cannot be negative, we can only use the solution x = 1.

Therefore, the side of the square is 4x-1 = 4(1)-1 = 3.

To determine the perimeter of the square, we can use the formula for the perimeter of a square, which is 4 times the length of one side. In this case, the length of one side is 3, so the perimeter of the square is:

4 x 3 = 12

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The alternative hypothesis μ ≠ 0 would indicate a two-tailed test.

Option  C is the correct answer.

We have,

A two-tailed test is a statistical test where the alternative hypothesis is that the population parameter is not equal to a specific value.

In this case,

The alternative hypothesis of μ ≠ 0 indicates that the population mean can be either greater than or less than zero, leading to two possible outcomes

in the test. It means that the test will check if the population mean is significantly different from zero in either direction.

This is in contrast to a one-tailed test, where the alternative hypothesis is directional and indicates that the population parameter is either greater than or less than a specific value.

Thus,

The alternative hypothesis μ ≠ 0 would indicate a two-tailed test.

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The complete question.

Which of the following alternative hypotheses would indicate a two-tailed test?

μ  > 0

μ < 0

μ ≠ 0

μ = 0

The student's parents will pay half of the first-year cost, which is $12,000.

The academic scholarship will pay an additional $500, leaving the student with a remaining cost of $24,000 - $12,000 - $500 = $11,500 for the first year.

If the student wants to pay off the remaining $11,500 by the end of 12 months, they will need to save an average of $958.33 per month.

Therefore, the minimum amount that the student will need to save every month is approximately $958.33.

Answer:jessica

Step-by-step explanation:

do distance divided by time for all of them except noah and find the greatest

Answer:

C

D

Step-by-step explanation:

A reason not to use a chi-square test of homogeneity to analyze a set of data is if the assumptions of the test are not met. These assumptions include:

1. The data must be categorical, meaning it consists of counts or frequencies in different categories.

2. The sample size must be large enough, with an expected frequency of at least 5 in each cell of the contingency table.

3. The observations must be independent, meaning each data point should not influence the others.

If any of these assumptions are not met, it may not be appropriate to use a chi-square test of homogeneity to analyze the data. Instead, you may need to consider alternative statistical methods that better suit your data and research question.

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To find the limit, we can begin by multiplying the numerator and denominator by the conjugate of the numerator, which is (√1 + 8x + √1 - 10x):

lim (√1 + 8x - √1 - 10x)/x

= lim [(√1 + 8x - √1 - 10x)/(√1 + 8x + √1 - 10x)] * [(√1 + 8x + √1 - 10x)/x]

= lim [(8x - 10x)/ (x(√1 + 8x + √1 - 10x))] * [(√1 + 8x + √1 - 10x)/x]

= lim [(8 - 10)/ (√1 + 8x + √1 - 10x)]

= lim [-2/ (2√1)]

= -1/√1

= -1

Therefore, the limit of the given expression as x approaches 0 is -1. We didn't need to use l'Hospital's Rule for this problem, as it was possible to simplify the expression before applying the limit.

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Answer:

3

Step-by-step explanation:

1/2x3x2

1.5x2

3

Hope this helps :)

4√5+2√5

4+2(√5)

6√5

option C

From the given scatter plot we can conclude that No, Fabricio should draw the line with all of the data points above it.

Hence the correct option is (A).

The given graph is a scatter plot of a data set.

The line should fit the scatter points that is the line must passes through most of the points which shows a common trends or which depicts the characteristics of the data set.

Here in the given scatter plot we can see that the points chronically goes in downward direction.

So the fit line should be a straight line in downward direction that is a decreasing straight line.

But Fabricio drew a increasing line.

So the correct choice is (A).

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The question us incomplete. The complete question will be -

The scenario that represents the expression is Making three payments of $20 each to total paying. Option A

3(-20) denotes three times negative twenty, which is simplified to -60.

This can illustrate the scenario of making three $20 payments to total $60, as each payment of $20 leads in a $60 drop in total. The proper scenario is Option A.

Option B entails paying 20 $3 payments for a total payment of $60, but the phrase 3(-20) does not describe this circumstance.

Option C entails getting money from three pals, which has nothing to do with the payment phrase 3(-20).

Option D entails paying $3 for each of 20 arcade games, for a total payment of $60, although this situation is unrelated to the payment phrase 3(-20).

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Answer:

Recall that the equation we created was:

y = 2x + 10

where y represents the number of leaves and x represents the number of weeks since spring has started.

To find the expected average number of leaves on a tree 8 weeks after spring has started, we need to evaluate the equation for x = 8:

y = 2(8) + 10

y = 16 + 10

y = 26

Therefore, the expected average number of leaves on a tree 8 weeks after spring has started is 26.

Answer:

Step-by-step explanation:

(a) In the equation T = 0.02t + 15.0, the slope (0.02) represents the rate of change in temperature per year, which is the amount by which the temperature is expected to increase each year. The T-intercept (15.0) represents the temperature in °C at the beginning of the time period being considered, which in this case is the year 1950.

(b) To predict the average global surface temperature in 2050, we need to find the value of T when t = 2050 - 1950 = 100 (since t is measured in years since 1950).

Substituting t = 100 into the equation, we get:

T = 0.02(100) + 15.0 = 17.0

Therefore, the predicted average global surface temperature in 2050 is 17.0 °C.

The measure of the angle ∠6 as 57 degrees.

Same-side interior angles are pairs of angles that are on the same side of the transversal and between the two parallel lines. When two parallel lines are intersected by a transversal, the same-side interior angles are supplementary, which means that they add up to 180 degrees. This is known as the Same-Side Interior Angles Theorem.

Now, let's apply this theorem to the given problem. We are given that ∠4 is 123 degrees and we need to find the measure of ∠6. Since ∠4 and ∠6 are same-side interior angles, we know that they add up to 180 degrees. We can use this information to set up an equation:

∠4 + ∠6 = 180

Substituting the value of ∠4 as 123 degrees, we get:

123 + ∠6 = 180

To solve for ∠6, we can subtract 123 from both sides of the equation:

∠6 = 180 - 123

Simplifying the right-hand side of the equation, we get:

∠6 = 57

Therefore, the measure of ∠6 is 57 degrees.

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Complete Question:

Same-side interior angles always add up to 180°. If ∠4 and ∠6 are same-side interior angles, what is the measure of ∠6 where the value of ∠4 is 123 degrees?

The volume of sphere A is 256π/3 cm³.

The volume of sphere B is  288π cm³.

The volume of sphere C is   2048π/3 cm³.

The volume of each sphere is calculated as follows;

V = ⁴/₃ πr³

where;

Volume of sphere A;

V = ⁴/₃ πr³

V = ⁴/₃ π(4³) = 256π/3 cm³

Volume of sphere B;

V = ⁴/₃ πr³

V = ⁴/₃ π(6³) = 288π cm³

Volume of sphere C;

V = ⁴/₃ πr³

V = ⁴/₃ π(8³) = 2048π/3 cm³

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Answer:

Okay, let's break this down step-by-step:

* Kiran drove 250 mi from Tortula to Cactus.

* So we need to find her speed on that portion of the trip.

* The total trip time was 11 hours.

* From Cactus to Dry Junction (360 mi trip) her speed increased by 10 mi/h.

* So if her speed increased by 10 mi/h, we can call her original speed from Tortula to Cactus = x mi/h

* Then her speed from Cactus to Dry Junction = x + 10 mi/h

* In 11 hours she drove:

** 250 mi from Tortula to Cactus (at speed x mi/h)

** 360 mi from Cactus to Dry Junction (at speed (x + 10) mi/h)

* So:

** 250 / x = time from Tortula to Cactus (in hours)

** 360 / (x + 10) = time from Cactus to Dry Junction (in hours)

* And:

** time from Tortula to Cactus + time from Cactus to Dry Junction = 11

* Solving this:

250 / x + 360 / (x + 10) = 11

610 / x + 36 = 11

x = 24

So Kiran's speed from Tortula to Cactus was 24 mi/h.

Let me know if you have any other questions!

Answer:

Yes, you need to find the GCF (greatest common factor) to solve this word problem.

The greatest common factor of 35 and 42 is 7. So you can create 7 teams with equal number of boys and girls on each team without leaving anyone out

Step-by-step explanation:

The function f(x) is a logarithmic function with a vertical asymptote at x = -8. The range of the function is from negative infinite to positive infinity, and it is increasing on it's entire domain. The end behavior of the function on the left side is that as x -> -8^+, y -> -∞, and to the right side, is that as x -> +∞, y -> +∞.

The function starts being defined at x = -8, hence the vertical asymptote of the function is given as follows:

x = -8.

The range of the function is the set containing all values assumed by y on the graph, hence it is in fact from negative infinity to positive infinity, and the function is increasing on it's entire domain.

The end behavior is the values on the extreme left and extreme right of the graph.

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The metric prefixes for [tex]10^1^2, 10^9, 10^6[/tex] and [tex]10^3[/tex] are tera (T), giga (G), mega (M), and kilo (k) respectively. The metric prefix for 2.1 is deca (da). The negative metric prefixes for [tex]10^1^2, 10^9, 10^6[/tex], and [tex]10^3[/tex] are pico (p), nano (n), micro (μ), and milli (m) respectively. The negative metric prefix for 2.1 is deci (d). So the symbols for these are: T (tera), G (giga), M (mega), k (kilo), da (deca), p (pico), n (nano), μ (micro), m (milli), d (deci)

1. [tex]10^1^2[/tex]: The metric prefix for [tex]10^1^2[/tex] is tera, and its symbol is T.
2. [tex]10^9[/tex]: The metric prefix for [tex]10^9[/tex] is giga, and its symbol is G.
3.[tex]10^6[/tex]: The metric prefix for [tex]10^6[/tex] is mega, and its symbol is M.
4. [tex]10^3[/tex]: The metric prefix for [tex]10^3[/tex] is kilo, and its symbol is k.
5. 2: There is no specific metric prefix for 2.
6. 1: There is no specific metric prefix for 1.

Now for the negative powers of these numbers:

1. [tex]10^-^1^2[/tex]: The metric prefix for[tex]10^-^1^2[/tex] is pico, and its symbol is p.
2. [tex]10^-^9[/tex]: The metric prefix for [tex]10^-^9[/tex] is nano, and its symbol is n.
3. [tex]10^-^6[/tex]: The metric prefix for[tex]10^-^6[/tex] is micro, and its symbol is µ.
4. [tex]10^-^3[/tex]: The metric prefix for[tex]10^-^3[/tex] is milli, and its symbol is m.

Please note that there are no metric prefixes for the negative powers of 2 and 1.

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The total number of arrangements, we can simply add up the results from each case:

C(21,8) + C(5,1) C(21,7) 8 + C(5,2) C(21,6) 2

Now, We can solve this problem, we can break it down into three cases, based on the number of vowels included in the arrangement.

Hence, Here are the three cases:

Case 1: No vowels included: In this case, we need to select 8 letters from the 21 consonants in the alphabet.

This can be done with C(21,8) ways.

Case 2: One vowel included:

Here, we need to select one of the five vowels and then select 7 letters from the 21 consonants.

The vowel can be placed in any of the 8 positions, but once it is placed, the other vowels must be placed in alphabetical order.

Therefore, the number of arrangements in this case is, C(5,1) C(21,7) 8.

Case 3: Two vowels included: In this case, we need to select two of the five vowels, and then select 6 letters from the 21 consonants.

Again, the vowels must be placed in alphabetical order once they are selected.

However, we have two possible orders to place the vowels - either at the start or in the middle of the 8-letter arrangement.

Therefore, the number of arrangements in this case is C(5,2) C(21,6) 2.

So, The total number of arrangements, we can simply add up the results from each case:

C(21,8) + C(5,1) C(21,7) 8 + C(5,2) C(21,6) 2

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On solving the query we can say that In conclusion, while option D does not meet the condition, alternatives A, B, and C are equivalent to equations that represent y as a function of x.

Mathematics is concerned with numbers and their variations, equations and related structures, shapes and their places, and possible placements for them. The relationship between a collection of inputs, each of which has an associated output, is referred to as a "function". An relationship between inputs and outputs, where each input yields a single, distinct output, is called a function. Each function has a domain and a codomain, often known as a scope. The letter f is frequently used to represent functions (x). X is the input. The four main types of functions that are offered are on functions, one-to-one functions, many-to-one functions, within functions, and on functions.

Let's investigate each choice:

A: 3x - 4y = -2

We must put y on one side of the equation in order to describe y as a function of x. We may do this by dividing by -4 after removing 3x from both sides:

-4y = -3x - 2 y = (3/4)x + 1/2

C: x² - 3y = 0

We must isolate y in order to express y as a function of x. This may be done by dividing by -3 after removing x2 from both sides of the equation: y = (1/3)x2.

The condition is met by option C since this equation expresses y as a function of x.

In conclusion, while option D does not meet the condition, alternatives A, B, and C are equivalent to equations that represent y as a function of x.

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The equations that are equivalent to an equation that expresses y as a function of x are A, B, and C.

What is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas. It involves the study of variables, expressions, equations, and functions.

The equation that expresses y as a function of x is y = f(x). To be equivalent to this equation, an equation must also express y as a function of x. Let's examine each equation:

A: 3x-4y=-2 can be rewritten as y = (3/4)x + 1/2, which expresses y as a function of x. Therefore, A is equivalent to an equation that expresses y as a function of x.

B: x-y⁴=0 can be rewritten as y = ±√x, which expresses y as a function of x. Therefore, B is equivalent to an equation that expresses y as a function of x.

C: x²-3y=0 can be rewritten as y = (1/3)x², which expresses y as a function of x. Therefore, C is equivalent to an equation that expresses y as a function of x.

D: lxl + lyl = 2 does not express y as a function of x because for every x value, there are two possible y values that satisfy the equation. Therefore, D is not equivalent to an equation that expresses y as a function of x.

Therefore, the equations that are equivalent to an equation that expresses y as a function of x are A, B, and C.

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