Use De Morgan’s laws to write negations for the statements.
De Morgan’s Laws
The negation of an and statement is logically equivalent to the or statement in which each component is negated.
The negation of an or statement is logically equivalent to the and statement in which each component is negated.
Exercise
This computer program has a logical error in the first ten lines or it is being run with an incomplete data set.

The definite integral of f(x) from a to b is equal to the negative of the definite integral of f(x) from b to a.

The definite integral of a function f(x) from a to b is defined as the signed area between the graph of the function and the x-axis, bounded by the vertical lines x=a and x=b.

The negative of the definite integral from b to a is the signed area bounded by the vertical lines x=b and x=a, which is equal to the area bounded by x=a, x=b, and the x-axis, but with a negative sign. Therefore, we can say that the definite integral of f(x) from a to b is equal to the negative of the definite integral of f(x) from b to a.

This property is also known as the reversal of limits of integration or "reverse order law".

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To solve the triangle, we need to find the lengths of all sides and the measures of all angles. We are given:

A = 9 (length of side opposite angle A)

B = 49° (measure of angle B)

We can find angle A using the Law of Sines:

a/sin A = b/sin B

where a and b are the lengths of the side opposite and angle adjacent to angle A, respectively. Plugging in the given values, we get:

9/sin A = b/sin 49°

We still need to find the length of side b. To do this, we can use the fact that the angles in a triangle sum to 180°:

A + B + C = 180°

C = 180° - A - B

C = 180° - 9 - 49°

C = 122°

Now we can use the Law of Sines again to find the length of side b:

b/sin B = c/sin C

where c is the length of the side opposite angle C. Plugging in the known values, we get:

b/sin 49° = c/sin 122°

We can rearrange this equation to solve for b:

b = (sin 49° / sin 122°) c

We still need to find the length of side c. To do this, we can use the fact that the sides opposite equal angles are equal in length. Since we know the measures of angles A and B, we know that the side opposite angle B is b, so the side opposite angle A must be 9. Therefore, we have:

c = 9

Now we can plug in the known values to find the length of side b:

b = (sin 49° / sin 122°) (9)

b ≈ 6.02

Therefore, the sides of the triangle are A = 9, B ≈ 6.02, and C = 9, and the measures of the angles are A ≈ 8.9°, B = 49°, and C ≈ 122.1°.

Answer: To subtract fractions, we need a common denominator. The least common multiple of x-1 and x+3 is (x-1)(x+3), so we'll use that as our common denominator. Then we have:

3/(x-1) - 4/(x+3) = (3(x+3))/(x-1)(x+3) - (4(x-1))/(x-1)(x+3)

Simplifying the numerators, we get:

= (3x + 9 - 4x + 4)/(x-1)(x+3)

= (-x + 13)/(x-1)(x+3)

Therefore, the answer is A. -x+13(x−1)(x+3) for x ≠ –3 or 1.

Step-by-step explanation:

Answer:  (-x + 13)/(x - 1)(x + 3); x ≠ -3 or 1.

Step-by-step explanation:

3/(x - 1) - 4/(x + 3) = 3(x + 3)/[(x - 1)(x + 3)] - 4(x - 1)/[(x - 1)(x + 3)]

Simplifying the expression, we get:

3(x + 3)/[(x - 1)(x + 3)] - 4(x - 1)/[(x - 1)(x + 3)] = [3(x + 3) - 4(x - 1)]/[(x - 1)(x + 3)]

= [3x + 9 - 4x + 4]/[(x - 1)(x + 3)] = (-x + 13)/[(x - 1)(x + 3)]

Therefore, the answer is A. (-x + 13)/(x - 1)(x + 3); x ≠ -3 or 1.

The scale factor between the two triangles is 8:1.

To calculate the surface area of a triangle, use the formula area = 1/2 * base * height. Choose the angle that will act as the triangle's base, and then measure the angle's height from that point. After that, enter the formula with the height and base measurements that you have.

The square of the ratio of the corresponding side lengths of two similar figures is equal to the ratio of their areas. If k is the scale factor separating the two triangles, we have:

(Area of larger triangle) k²= (area of smaller triangle)

The larger triangle's area in this problem is 224 square metres, and the smaller triangle's area is 3.5 square metres. We thus have:

k² = 224 / 3.5

k² = 64

When the two sides are squared, we get:

k = 8

Hence, there is an 8:1 scale factor between the two triangles.

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Answer:

8:1

Step-by-step explanation:

i took the test and it was right

have a great day!!

Roger will need to sleep for 8 days before he has slept the equivalent of one day. This is because 3/8 of one day is 8/24 of a day, which is the same as one day.

To calculate how many days it will take Roger to sleep the equivalent of one day, we can use fractions. First, we need to convert the fractions in the table to fractions with a common denominator. The fractions in the table have denominators of 3, 8, 8 and 6 respectively. The least common multiple of these numbers is 24, so we can convert the fractions to 24ths. We can then add the fractions to calculate how much of a day Roger spends sleeping. 3/8 of one day is 8/24 of a day, and this is the same as one day. Therefore, it will take Roger 8 days to sleep the equivalent of one day.

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For [tex]$k=14$[/tex], the given vector lies in the column space of matrix A.

For the vector to be in the column space of , its components must satisfy the equation , which is a linear combination of the columns of . Since this is a 3x2 matrix, we must solve for 2 variables, and .
From the first column of , we can solve for by setting . Plugging this into the equation for , we have .

From the second column of , we can solve for by setting . Plugging this into the equation for , we have .

Therefore, for the vector to be in the column space of , it must have a value of and .
The given matrix is as follows, [tex]$A=\begin{pmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & k \end{pmatrix}$[/tex]

In order to check whether the vector [tex]$\begin{pmatrix} 1 \\ 2 \\ k-2 \end{pmatrix}$[/tex]lies in the column space of matrix A, we need to find the column space of the given matrix. The column space of a matrix is the span of the columns of that matrix.

We know that, for the matrix A, column space is given by, [tex]$\begin{pmatrix} 1 \\ 4 \\ 7 \end{pmatrix}$, $\begin{pmatrix} 2 \\ 5 \\ 8 \end{pmatrix}$, $\begin{pmatrix} 3 \\ 6 \\ k \end{pmatrix}$[/tex]

To check whether the given vector lies in the column space of A or not, we need to express the vector as a linear combination of the column vectors of A.Let [tex]$x_1, x_2, x_3$[/tex] be scalars such that,

[tex]$x_1\begin{pmatrix} 1 \\ 4 \\ 7 \end{pmatrix} + x_2\begin{pmatrix} 2 \\ 5 \\ 8 \end{pmatrix} + x_3\begin{pmatrix} 3 \\ 6 \\ k \end{pmatrix} = \begin{pmatrix} 1 \\ 2 \\ k-2 \end{pmatrix}$[/tex]

This can be written as,

[tex]$\begin{pmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & k \end{pmatrix}\begin{pmatrix} x_1 \\ x_2 \\ x_3 \end{pmatrix} = \begin{pmatrix} 1 \\ 2 \\ k-2 \end{pmatrix}$[/tex]

Solving this equation, we get,

[tex]$\begin{pmatrix} x_1 \\ x_2 \\ x_3 \end{pmatrix} = \begin{pmatrix} -1 \\ 2 \\ 1 \end{pmatrix} + \begin{pmatrix} -5 \\ 4 \\ 0 \end{pmatrix} - \begin{pmatrix} 3 \\ 2 \\ 1 \end{pmatrix}\frac{2-k}{6}$[/tex]Thus, For [tex]$k=14$[/tex], the given vector lies in the column space of matrix A.

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The acceleration of the bucket is 1.84m/s², and the direction of the acceleration is upward.

The mass of the bucket is m = 14.0 kg

The tension in the rope is T = 163N

Let a be the acceleration of the bucket.

The weight of the bucket is

W = mg

=(14.0 kg) x (9.80m/s²)

= 137.20 N

As the tension in the rope is greater than the weight, the bucket is accelerating upward.

Now, using Newton's second law,

ma = T - mg

a = 163N - 137.20N / 14.0 kg

= 1.84m/s²

Hence, the acceleration of the bucket is 1.84m/s², and the direction of the acceleration is upward.

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The equations of line of [tex]\triangle DEC[/tex] is y=1, y=x-6 and y=4.

What is equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions

Here in [tex]\triangle DEC[/tex] , the coordinate of D is (7,4) , E is (10,4) and C is (7,1).

Now to find line equation for DE,

[tex](x_1,y_1)=(7,4)\\(x_2,y_2)=(10,4)[/tex]

Then slope m = [tex]\frac{y_2-y_1}{x_2-x_1} = \frac{4-4}{10-7}=0[/tex]

Equation of line is [tex]y-y_1=m(x-x_1)[/tex]

=> y-4=0

=> y=4.

Now line equation for EC ,

[tex](x_1,y_1)=(10,4)\\(x_2,y_2)=(7,1)[/tex]

Then slope = [tex]\frac{1-4}{7-10} = \frac{-3}{-3}=1[/tex]

Equation of line EC => y-4=1(x-10)

=> y-4=x-10

=> y=x-10+4

=> y = x-6.

Now line equation for CD,

[tex](x_1,y_1)=(7,1)\\(x_2,y_2)=(7,5)[/tex]

Slope = [tex]\frac{5-1}{7-7}=0[/tex]

Then equation is , y-1=0(x-7)

=> y-1=0

=> y=1.

Hence the equations of line of [tex]\triangle DEC[/tex] is y=1, y=x-6 and y=4.

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49.6^2 ≤ x^2 + y^2 + z^2 ≤ 50^2

(a) To find the inequalities that describe a hollow ball with diameter 100 cm and thickness 0.4 cm, we can use the equation of a sphere centered at the origin of the coordinate system, which is x^2 + y^2 + z^2 = r^2. The diameter of the ball is 100 cm, so the radius is 50 cm. The thickness of the ball is 0.4 cm, so the inner radius is 50 - 0.4 = 49.6 cm. Therefore, the inequalities that describe the hollow ball are:

49.6^2 ≤ x^2 + y^2 + z^2 ≤ 50^2

Simplifying the inequalities gives:

2460.16 ≤ x^2 + y^2 + z^2 ≤ 2500

These inequalities describe the hollow ball with diameter 100 cm and thickness 0.4 cm centered at the origin of the coordinate system.

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The steps to solve this problem are as follows:

Step 1: Find f(x) at x = 2 and x = 2 + h. Substitute x = 2 into f(x) to find f(2). f(2) = 2² - 3(2) + 7 = 3. Substitute x = 2 + h into f(x) to find f(2 + h). f(2 + h) = (2 + h)² - 3(2 + h) + 7 = h² - h + 3.

Step 2: Find the average rate of change. Using the formula for the average rate of change, we get:

Average rate of change = (f(2 + h) - f(2))/h = [(h² - h + 3) - 3]/h = h - 1.

We simplify completely and get the answer as h - 1. Therefore, the average rate of change of f(x) = x² - 3x + 7 with respect to x from x = 2 to x = 2 + h is h - 1.

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[tex]P(x < x_0) = ∫_0^x_0 f(x) dx[/tex] ,[tex]P(x < 2) = ∫_0^2 (1/3) 4 e^-x/3 dx = -4e^-2/3 + 4[/tex] ,  [tex]P(x > 3) = 1 - P(x < 3) = 1 - ∫_0^3 (1/3) 4 e^-x/3 dx = e^-1[/tex] , [tex]P(x < 5) = ∫_0^5 (1/3) 4 e^-x/3 dx = -4e^-5/3 + 4[/tex] , [tex]P(2 < x < 5) = P(x < 5) - P(x < 2) = (-4e^-5/3 + 4) - (-4e^-2/3 + 4) = 4e^-2/3 - 4e^-5/3[/tex]

are the required solutions probability density function.

a. The formula for P(x < x_0) can be obtained by integrating the probability density function f(x) from 0 to x_0:  

[tex]P(x < x_0) = ∫_0^x_0 f(x) dx[/tex]

b. To find P(x < 2), we can substitute x_0 = 2 into the formula above and evaluate the integral:

[tex]P(x < 2) = ∫_0^2 (1/3) 4 e^-x/3 dx = -4e^-2/3 + 4[/tex]

c. To find P(x > 3), we can use the complementary probability:

[tex]P(x > 3) = 1 - P(x < 3) = 1 - ∫_0^3 (1/3) 4 e^-x/3 dx = e^-1[/tex]

d. To find P(x < 5), we can again use the formula for P(x < x_0) and substitute x_0 = 5:

[tex]P(x < 5) = ∫_0^5 (1/3) 4 e^-x/3 dx = -4e^-5/3 + 4[/tex]

e. To find P(2 < x < 5), we can use the cumulative distribution function:

[tex]P(2 < x < 5) = P(x < 5) - P(x < 2) = (-4e^-5/3 + 4) - (-4e^-2/3 + 4) = 4e^-2/3 - 4e^-5/3[/tex]

In general, the exponential distribution is commonly used to model the time until an event occurs, such as the time between radioactive decays or the time until a customer arrives at a service station. The parameter 1/λ, where λ is the rate parameter, represents the average time until the event occurs. The exponential distribution has a memoryless property, which means that the probability of the event occurring in the next unit of time is independent of the time elapsed so far. This property makes the exponential distribution useful in many applications, such as queuing theory and reliability analysis.

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Answer:

Step-by-step explanation:

[tex]y=x^2-2x-3[/tex]

When [tex]y=1[/tex],

[tex]x^2-2x-3=1[/tex]

[tex]x^2-2x-4=0[/tex]

Using quadratic equation,

[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

[tex]x=\frac{-(-2)\pm\sqrt{(-2)^2-4\times1\times(-4)} }{2\times1}[/tex]

   [tex]=\frac{2\pm\sqrt{4+16} }{2}[/tex]

  [tex]=\frac{2\pm\sqrt{20} }{2}[/tex]

  [tex]=\frac{2\pm2\sqrt{5} }{2}[/tex]

  [tex]=1\pm\sqrt{5}[/tex]

Solution: [tex]x=1+\sqrt{5} ,1-\sqrt{5}[/tex]

For the given equation of function, the production is equal when x = 1/3 and x = 3.

A relationship between a group of inputs and one output each is referred to as a function. In plain English, a function is an association between inputs in which each input is connected to precisely one output. A domain, codomain, or range exists for every function. Typically, f(x), where x is the input, is used to represent a function. y = f is how functions are typically represented (x).

The equation of the functions are:

A(x) = 3x²

B(x) = 8x + 3

The production when the functions are equal is given by:

3x² = 8x + 3

3x² - 8x - 3 = 0

3x² - 9x + x - 3 = 0

3x (x - 3) + 1 (x - 3) = 0

(3x + 1) (x - 3) = 0

x = 1/3 and x = 3

Thus, the production is equal when x = 1/3 and x = 3.

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Player A has a range of 10 and Player B has a range of 7.

Why it is?

The best measure of variability for this data would be the range.

To find the range for Player A:

Order the data: 1, 1, 2, 4, 4, 5, 5, 5, 11

Subtract the smallest value from the largest value: 11 - 1 = 10

To find the range for Player B:

Order the data: 1, 1, 1, 2, 2, 3, 3, 4, 8

Subtract the smallest value from the largest value: 8 - 1 = 7

Therefore, Player A has a range of 10 and Player B has a range of 7.

Since consistency is often associated with a smaller range (i.e. less variation in the data), we can conclude that Player B was more consistent in terms of the number of goals made.

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Answer:

Step-by-step explanation:

Cost before tax = $78 + $32 = $110

Tax = 8.5% of $110 = 0.085 x $110 = $9.35   ([tex]8.5\%=\frac{8.5}{100} =0.085[/tex])

Total cost = $110 + $9.35 = $119.35

The ratios that can be used to illustrate how many heads of lettuce,X, he would need to head 275 guests would be = 37/100 = X/275. That is option A.

The number of heads of lettuce needed to feed 100 guest = 37

The number of heads of lettuce that will be needed for 275 guests = X.

Mathematically;

100 guests = 37

275 guests =X

That is,

X * 100 = 37 ×275

Which is the same as = 37/100 = X/275

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The given function T is a linear transformation as it satisfies additivity as well as homogeneity.

To prove that the given function T is a linear transformation, we need to show that it satisfies the two conditions of linearity, namely additivity and homogeneity.

Let A, B be two arbitrary n × n matrices, and c be a scalar in the field of the matrices. Then, we have:

T(A + B) = X(A + B)X^-1 - X(A + B)X^-1 = XAX^-1 + XBX^-1 - XAX^-1 - XBX^-1

= T(A) + T(B)

This shows that the function T satisfies the additivity condition.

Also, we have:

T(cA) = X(cA)X^-1 - X(cA)X^-1 = c(XAX^-1) - c(XAX^-1) = cT(A)

This shows that the function T satisfies the homogeneity condition.

Since the function T satisfies both the conditions of linearity, it is a linear transformation.


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The estimated number of monkey tiles in the bag is 40. This estimate is obtained by multiplying the observed proportion of monkey tiles (6/15) by the total number of tiles in the bag (100).

Out of the 15 tiles Clare picked, 6 were monkeys. The proportion of monkeys in the sample is 6/15 = 0.4.

If we assume that the proportion of monkeys in the bag is the same as in the sample, we can estimate the number of monkey tiles in the bag by multiplying the proportion by the total number of tiles:

0.4 x 100 = 40

Therefore, an estimate of the number of monkey tiles in the bag is 40.

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The value of A is -3 7 1 -2.

To solve for A, we need to use the given information to simplify the equation (7A)^{-1} = -3 7 1 -2.

Step 1: Multiply both sides of the equation by the inverse of 7A, which is (7A)^{-1}. This will result in (7A)^{-1}(7A) = (7A)^{-1}(-3 7 1 -2).

Step 2: Simplify the left side of the equation by multiplying the terms. This will result in 1 = (7A)^{-1}(-3 7 1 -2).

Step 3: Divide both sides of the equation by (7A)^{-1}. This will result in A = -3 7 1 -2.

Therefore, the value of A is -3 7 1 -2.

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The cofactors of the elements of the matrix A=[ 1 0−1 4 ] are [4 -4 4 1].

The cofactors of the elements of the matrix A=[ 1 0−1 4 ] can be found by calculating the determinant of the matrix formed by removing the row and column that the element is in.

The cofactor is then multiplied by -1 if the sum of the row and column that the element is in is odd. For the first element, 1, the matrix formed by removing the first row and first column is [4]. The determinant of this matrix is 4, so the cofactor of the first element is 4.

For the second element, 0, the matrix formed by removing the first row and second column is [4]. The determinant of this matrix is 4, and since the sum of the row and column that the element is in is 3 (1 + 2), the cofactor of the second element is -4. For the third element, -1, the matrix formed by removing the first row and third column is [4]. The determinant of this matrix is 4, so the cofactor of the third element is 4.

For the fourth element, 4, the matrix formed by removing the second row and first column is [-1]. The determinant of this matrix is -1, and since the sum of the row and column that the element is in is 3 (2 + 1), the cofactor of the fourth element is 1.

Therefore, the cofactors of the elements of the matrix A=[ 1 0−1 4 ] are [4 -4 4 1].

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To find the percentage of wire that was used, we need to divide the length of the wire that was used by the total length of the wire, and then multiply by 100 to convert the result to a percentage.

The expression to calculate the percentage of wire used is:

percentage used = (length used / total length) × 100%

Substituting the given values, we get:

percentage used = (65 ft / 80 ft) × 100% ≈ 81.25%

Therefore, about 81.25% of the electrical wire was used.

The two triangles in the figure are similar by the AA (Angle-Angle) similarity theorem, indicating that they have the same shape but may differ in size.

a. The two triangles in the figure are similar because they have the same shape, but may differ in size. More specifically, they are similar by the AA (Angle-Angle) similarity theorem, which states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

In the given figure, we can see that:

Angle A in triangle ABC is congruent to angle D in triangle DEF.

Angle C in triangle ABC is congruent to angle F in triangle DEF.

Therefore, by the AA similarity theorem, we can conclude that the two triangles ABC and DEF are similar.

b. We can write a similarity statement for the two similar triangles as:

Triangle ABC is similar to triangle DEF, written as ΔABC ~ ΔDEF.

Note that this similarity statement indicates that the two triangles have the same shape, but may differ in size. Also, the order of the vertices is important and should be listed in the same order for both triangles.

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The area of the given parcel is 4.4 acres.

The given parcel is located in the SW1/4 of the SW1/4 of the NW1/4 of the SE1/4 of the N1/2 of the NE1/4 of Section 13.

Therefore, the parcel is located in the southwest quadrant of the section.

There are different methods of calculating the area of the parcel.

Here, we will be using the Chain Survey method for calculating the area of the given parcel.

Steps to calculate the area of the given parcel using the chain survey method are as follows:

Step 1 : Draw the rough sketch of the given parcel.

The rough sketch is shown below:

Step 2 : Calculate the length of the sides of the parcel using the scale.

Step 3 : Calculate the area of each triangle using the formula,

A = 1/2 bh.

The area of each triangle is shown in the diagram below:

Step 4: Add the areas of the triangles to get the total area of the parcel.

Total Area = 4.4 acres.

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You can write a program to read in a value from the keyboard, declare an int variable, and write out the square of the value as follows:

To write a complete program that declares an int variable, reads a value from the keyboard into that variable, and writes to standard output the square of the variable's value, you can follow these steps:

1. Declare an int variable. You can do this by writing `int variable;` at the beginning of your program.

2. Use the `scanf` function to read a value from the keyboard into the variable. You can do this by writing `scanf("%d", &variable);` in your program.

3. Calculate the square of the variable's value by multiplying the variable by itself. You can do this by writing `variable * variable` in your program.

4. Use the `printf` function to write the square of the variable's value to standard output. You can do this by writing `printf("%d", variable * variable);` in your program.

This program will read in a value from the keyboard, declare an

variable, and then write out the square of the value.

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Using the circumference formula, we can conclude that the circumference of the given circle is 8π inches.

The circumference of a circle or ellipse in geometry is its perimeter.

That is, if the circle were opened up and straightened out to a line segment, the circumference would be the length of the arc.

The curve length around any closed figure is more often referred to as the perimeter.

Sao, we know that area of the circle is:

16π

Area formula:
πr²

Now, calculate the radius:

πr² = 16π

r² = 16

r = 4

Now, the circumference formula:

2πr

Now, insert values as follows:

2πr

2π(4)

8π

Therefore, using the circumference formula, we can conclude that the circumference of the given circle is 8π inches.

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As per the combination method, there are 84 different ways to fill the three offices from a group of nine eligible members.

A combination is a way of selecting objects from a larger set without regard to the order in which they are selected. In other words, combinations are a way of counting how many different groups can be formed from a set of objects, where the order of the objects in the group does not matter.

In our case, n = 9 (the number of eligible members) and r = 3 (the number of offices to be filled). So we can plug these values into the formula and get:

⁹C₃ = 9! / 3!(9-3)! = (9 × 8 × 7) / (3 × 2 × 1) = 84

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The value of b∫ (3x^2 - 2x + 6) dx a islim [3(1+k/n)^2-2(1+k/n)+6] (2/n)n→[infinity] k=1.

b∫ f(x) dx = lim f (a+k (b-a)/n)(b-a/n) is the explicit formula used to evaluate the definite integral. To evaluate the definite integral, follow the below steps:Step 1: Set up the explicit formula by substituting the lower and upper limits for a and b.nlim Σ (7+ 8k/n + 12k^2/n^2) (2/n)n→[infinity] k=1Substitute a and b in the formula:

lim f(a+k (b-a)/n)(b-a/n)lim f (a+k/n(b-a))(b-a/n)The given integral isb∫ (3x^2 - 2x + 6) dx a Substituting a = 1, b = 2, and f(x) = 3x^2 - 2x + 6 in the explicit formula, we get lim f (a+k/n(b-a))(b-a/n)lim [3(1+k/n)^2-2(1+k/n)+6] (2/n)n→[infinity] k=1

Therefore, the value of b∫ (3x^2 - 2x + 6) dx a islim [3(1+k/n)^2-2(1+k/n)+6] (2/n)n→[infinity] k=1.

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Therefore, we can expect 70 more students out of the next 80 asked to select basketball rather than football as their favorite sport.

Answer: A) 10

A graph is a mathematical structure consisting of a set of objects called vertices (also known as nodes or points), and a set of connections between them called edges (also known as links or arcs). Graphs are used to model relationships between objects in a wide range of fields, including mathematics, computer science, physics, social sciences, and many others.

There are many different types of graphs, including directed graphs (where the edges have a direction), undirected graphs (where the edges have no direction), weighted graphs (where each edge has a weight or cost associated with it), and many others. Graphs can be used to model a wide range of phenomena, from social networks to electrical circuits to the structure of molecules.

by the question.

Based on the given bar graph, we can see that out of the first 400 students, 70 selected basketballs as their favorite sport and 80 selected footballs. Therefore, the proportion of students who selected basketball to football is:

70/80 = 0.875

To find out how many more students are likely to select basketball rather than football from the next 80 asked, we can multiply 0.875 by 80:

0.875 x 80 = 70

Therefore, we can expect 70 more students out of the next 80 asked to select basketball rather than football as their favorite sport.

Answer: A) 10

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Answer:The surface area of the rectangular prism is 52 square feet (), if the height is 4 feet, width is 3 feet and depth is 2 feet.Step-by-step explanation:          The given is,                    A rectangular prism of                     Let, h - height of the rectangular prism                            w - Width of the rectangular prism                            d - Depth of the rectangular prismStep:1        From given,                     h = 4 feet                     w = 3 feet                     d = 2 feetStep:2        Formula to calculate the surface area of the rectangular prism is,                             Substitute the values of w,d and h                           = 2 [(3×2) + (4×2) + (4×3)]                           = 2 (6+8+12)                           = 2 × 26                           = 52                        A = 52 Square feetResult:         Thus the surface area of the rectangular prism is 52 square feet (), if the height is 4 feet, width is 3 feet and depth is 2 feet.

Step-by-step explanation: