Use the conversion factor 1 gallon=3.785 to convert 4 liters into gallons

Answers

Answer 1

Using the conversion factor, we can convert the liters into the number of gallons of 1. 057 gallons.

How to convert the liters ?

A conversion factor is a mathematical ratio that is used to convert one unit of measurement to another. It is a multiplier or divisor that relates two different units of measurement for the same quantity.

To convert 4 liters into gallons using the conversion factor 1 gallon = 3.785 liters, you divide the given value (in liters) by the conversion factor.

This means that the number of gallons in 4 liters would be:

= 4 liters ÷ 3. 785 liters/gallon

= 1. 057 gallons

Therefore, 4 liters is approximately equal to 1. 057 gallons.

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Related Questions

What are the solutions to the system of equations graphed?

Answers

Answer:

(- 2, 0 ) , (1, - 3 )

Step-by-step explanation:

the solutions to the system of equations are at the points of intersection with the curve and the straight line.

points of intersection are at (- 2, 0 ) and (1, - 3 ) , then

solutions are (- 2, 0 ) , (1, - 3 )

A hemisphere is on top of a cylinder the radius of the hemisphere is 5 and the height of the cylinder is 8 what is the volume somehelp?

Answers

Answer:

V = π(5^2)(8) + (4/3)π(5^3)

= 200π + (500/3)π = (1,100/3)π

= about 1,151.92 cm^3

Students were asked their favorite ice cream flavor. The results showed that 196 students selected vanilla as their favorite ice cream flavor. This represents 49% of the total number of students surveyed. What was the total number of students surveyed?

I need the answer and explanation!!!

Answers

Answer:

The total number of students surveyed is 400.

Step-by-step explanation:

We want to know that 49% of what number is 196

Let x = the total number of students

.49x = 196        (49% as a decimal is .49)   Divide both sides  by .49

x = 400

Kenya wants to open a savings account at a bank. The bank offers a savings account that pays
out 8% annual interest. If Kenya wants at least $7,000 in his account after 15 years, how much does
Kenya need to put in the account initially?

Answers

Kenya needs to initially put in the amount of $2,208.2in the account to have at least $7,000 after 15 years.

We can use the formula for compound interest:

A = P(1 + r/n)ⁿ

where A is the amount of money in the account after t years, P is the initial principal, r is the annual interest rate (as a decimal), and n is the number of times per year the interest is compounded.

Here, we want to find P, so we can rearrange the formula as:

P = A / (1 + r/n)ⁿ

We are given that r = 0.08 (8% interest) and n = 1 (interest is compounded annually).

We also know that A = $7,000 and t = 15 years.

So we can plug in these values and solve for P:

P = 7000 / (1 + 0.08/1)¹⁵

P = 7000 / (1.08)¹⁵

P ≈ $2,208.2

Therefore, Kenya needs to initially put in approximately $2,208.2in the account to have at least $7,000 after 15 years.

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Part A: Jan INCORRECTLY
finds the surface area of the
cone using the following
work. Explain Jan's error
and find the
correct volume AND
surface area of the cone.

Answers

The volume of the cone is 2786.2 cubic meters and the surface area of the cone is 1229.51 square meters.

Given the height (h) of a cone as 22 m and the diameter (d) of its circular base as 22 m, we can find the radius (r) of the circular base using the formula:

r = d/2 = 22/2 = 11 m

Here, Jan made a mistake in the work of the surface area of the cone because she used the wrong value of slant height (l=22) in the calculation.

The volume (V) of a cone is given by the formula:

V = (1/3)πr²h

Substituting the values of r and h, we get:

V = (1/3)π(11)²(22)

V = 2786.2 cubic meters

The surface area (A) of a cone is given by the formula:

A = πr(r + l)

here l is the slant height of the cone, which can be found using the Pythagorean theorem:

l = √(r² + h²)

l = √(11² + 22²)

l = √(605)

l = 24.6

Substituting the values of r and l, we get:

A = π(11)(11 + 24.6)

A ≈ 1229.51 square meters

Therefore, the volume of the cone is 2786.2 cubic meters and the surface area of the cone is 1229.51 square meters.

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Can I have answers for 2 a b c and d

Answers

Using the centimeter ruler:

a.  1 ÷ 1/10 and 4 ÷ 1/10 are 10 and 40b. multiplying by reciprocalc. 18 ÷ 1/10 is 180d. 4 ÷ 2/10  and 4 ÷ 8/10 are 20 and 5.

For the quotients:

a. 50b. 16²/₃c. 5⁵/₉

How to determine measurement?

2.a. To find 1 ÷ 1/10, divide 1 by the fraction 1/10. Dividing by a fraction is the same as multiplying by its reciprocal, rewrite the problem as 1 × 10/1, which simplifies to 10. Therefore, 1 ÷ 1/10 = 10.

To find 4 ÷ 1/10, divide 4 by the fraction 1/10. Again, rewrite the problem as 4 × 10/1, which simplifies to 40. Therefore, 4 ÷ 1/10 = 40.

b. To find each quotient, we used the fact that dividing by a fraction is the same as multiplying by its reciprocal.

c. Following the same pattern, find 18 ÷ 1/10 by dividing 18 by 1/10. This is the same as multiplying 18 by the reciprocal of 1/10, which is 10/1. Therefore, 18 ÷ 1/10 = 180.

d. To find 4 ÷ 2/10, divide 4 by 2/10. Rewrite the problem as 4 × 10/2, which simplifies to 20. Therefore, 4 ÷ 2/10 = 20.

To find 4 ÷ 8/10, divide 4 by 8/10. Rewrite the problem as 4 × 10/8, which simplifies to 5. Therefore, 4 ÷ 8/10 = 5.

3. a. To divide 5 by 1/10, Rewrite the problem as 5 × 10/1, which simplifies to 50. Therefore, 5 ÷ 1/10 = 50.

b. To divide 5 by 3/10, Rewrite the problem as 5 × 10/3, which simplifies to 16 2/3. Therefore, 5 ÷ 3/10 = 16²/₃.

c. To divide 5 by 9/10, Rewrite the problem as 5 × 10/9, which simplifies to 5 5/9. Therefore, 5 ÷ 9/10 = 5⁵/₉.

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Find g(0), g(-1), g(2), and g(2/3)
for g(x) =x/ square root 1-x^2

Answers

Given statement solution is :- Outputs and values g(2/3) = 2/3.

To summarize:

g(0) = 0

g(-1) = undefined

g(2) = undefined

g(2/3) = 2/3

To find the values of g(x) for the given inputs, we substitute each input into the function g(x) = x / √([tex]1 - x^2[/tex]). Let's calculate the values:

g(0):

Substitute x = 0 into the function:

g(0) = 0 / √([tex]1 - 0^2[/tex])

= 0 / √(1 - 0)

= 0 / √1

= 0

Therefore, g(0) = 0.

g(-1):

Substitute x = -1 into the function:

g(-1) = (-1) / √(1 - [tex](-1)^2[/tex])

= (-1) / √(1 - 1)

= (-1) / √0

Since the square root of 0 is undefined, g(-1) is undefined.

g(2):

Substitute x = 2 into the function:

g(2) = 2 / √([tex]1 - 2^2[/tex])

= 2 / √(1 - 4)

= 2 / √(-3)

Since the square root of a negative number is undefined in the real number system, g(2) is undefined.

g(2/3):

Substitute x = 2/3 into the function:

g(2/3) = (2/3) / √(1 - [tex](2/3)^2[/tex])

= (2/3) / √(1 - 4/9)

= (2/3) / √(5/9)

= (2/3) / (√5/√9)

= (2/3) / (√5/3)

= (2/3) * (3/√5)

= 2√5 / 3√5

= 2/3

Therefore, outputs and values g(2/3) = 2/3.

To summarize:

g(0) = 0

g(-1) = undefined

g(2) = undefined

g(2/3) = 2/3

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what is the probability of spinning a blue, then green

Answers

The probability of getting Blue then Green while spinning the wheel is

3 / 32

Probability is a branch of mathematics that helps us to understand the likelihood of an event occurring. It is represented by a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain. Probability can be used to make predictions and informed decisions in real-world situations.

From the given figure we can find out the following information

The probability of getting Blue While spinning the wheel = 3/8

The probability of getting Green While spinning the Wheel = 2 / 8

The probability of getting Blue then Green while spinning the wheel

= 3/8 * 2/8

= 6/64

= 3/32

Therefore, probability of getting Blue then Green while spinning the wheel is 3 / 32

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The sum of Jerry's and Carrie's ages is 52. Jerry is 4 years older than Carrie. What is Jerry's age?

Answers

X = Jerry’s age
4 + x = 52
X = 52-4 = 48
I hope it helps :)

Answer:

28

Step-by-step explanation:

let's assumed that

x = Jerry's age

y = Carrie's age

if Jerry 4 years older that Carrie

x = y + 4

x + y = 52

(y + 4) + y = 52

2y + 4 = 52

2y = 48

y = 24

x = y + 4

x = 24 + 4

x = 28

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The cosine of θ is −0.95. What is sin(θ)?

Answers

The value of sin(θ) is 0.31 and it lies in the third and fourth quadrants. if the value of the cosine of θ is −0.95.

cos(θ) = -0.95

To calculate the value of sin(θ), we can use the Pythagorean theorem:

[tex]sin^{2}[/tex] (θ) +[tex]cos^{2}[/tex] (θ) = 1

We can rearrange the Pythagorean identity to solve for sin(θ):

[tex]sin^{2}[/tex] (θ)= 1 - [tex]cos^{2}[/tex]

sin(θ) = ±[tex]\sqrt{1-cos^{2}}[/tex] *(θ)---------  (equation 1)

Substitute the value of the cosine of θ = −0.95 in Equation 1

sin(θ) = ±[tex]\sqrt{1-cos^{2}}[/tex] *(θ)

sin(θ) = ±[tex]\sqrt{(1 - 0.9025)}[/tex]

sin(θ) = ±[tex]\sqrt{0.0975}[/tex]

The positive value determines that the value is in the first and second quadrants, Negative shows the third and fourth quadrants.

sin(θ) = [tex]\sqrt{ 0.0975}[/tex]

sin(θ) = 0.312

Therefore, we can conclude that the value of sin(θ) is 0.312.

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Find (if possible) a. AB and b. BA.
A=
-
2
-
8
B=
||||
6
S
3
2

Answers

The products of the matrices A and B are [tex]AB = \left[\begin{array}{cc}-50 &7\\44 &-10\end{array}\right][/tex] and [tex]BA = \left[\begin{array}{cc}-12&-24 \\-16&-48\end{array}\right][/tex]

Finding the products of the matrices A and B

From the question, we have the following parameters that can be used in our computation:

Matrix A = [tex]\left[\begin{array}{cc}-3&-8\\2&8\end{array}\right][/tex]

Matrix B = [tex]\left[\begin{array}{cc}6&3\\4&-2\end{array}\right][/tex]

Using the above as a guide, we have the following:

[tex]AB = \left[\begin{array}{cc}-3 * 6 + -8 * 4 &-3 * 3 -8 * -2\\2 * 6 + 8 * 4 &2 * 3 + 8 * -2\end{array}\right][/tex]

Evaluate

[tex]AB = \left[\begin{array}{cc}-50 &7\\44 &-10\end{array}\right][/tex]

Next, we have

[tex]BA = \left[\begin{array}{cc}6 * -3 + 3 * 2&6 * -8 + 3 * 8 \\4 * -3 + -2 * 2&4 * -8 + -2 * 8\end{array}\right][/tex]

Evaluate

[tex]BA = \left[\begin{array}{cc}-12&-24 \\-16&-48\end{array}\right][/tex]

Hence, the values are [tex]AB = \left[\begin{array}{cc}-50 &7\\44 &-10\end{array}\right][/tex] and [tex]BA = \left[\begin{array}{cc}-12&-24 \\-16&-48\end{array}\right][/tex]

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find the center and radius by completing the square x2+6x+y2-4y=3​

Answers

Answer:

Center: (-3, 2)

Radius: 4

Step-by-step explanation:

x2 + 6x + y2 - 4y = 3​

x² + 6x + 9 + y² - 4y + 4 = 3 + 9 + 4

(x + 3)² + (y - 2)² = 16

(x + 3)² + (y - 2)² = 4²

Center: (-3, 2)

Radius: 4

Please help me understand this problem!

Answers

The requried solution of the given derivative has been given below.

If F(t) is an antiderivative of t⁵, then we have:

F'(t) = d/dt(F(t)) = t⁵

According to the Second Fundamental Theorem of Calculus, we have:

[tex]\int_1^x t^5 dt = F(x) - F(1)[/tex]

Using this formula, we can find [tex]d/dx(\int_1^x t^5 dt)[/tex] as follows:

[tex]d/dx(\int_1^x t^5 dt) = d/dx(F(x) - F(1)) = F'(x) - 0 = t^5[/tex]

Therefore, [tex]d/dx(\int_1^x t^5 dt) = t^5.[/tex]

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What is the total cost of 20 books at R25 each?

Answers

Answer:

R500

Step-by-step explanation:

20 books x R25 each = R500.

A rectangular prism measures 8 inches in width, 12 inches in length, and 4 inches in height. What is the surface area of the prism?

Answers

Step-by-step explanation:

It has

two sides 8x12

two sides 12x4

two sides 4x8           total 352 in^2

Darlene purchases $20,000 worth of stock on her brokers advice and pays her broker a 1.5% broker fee

Answers

Darlene's net proceeds from the investment into shares would be $ 8, 279 .

How to find the net proceeds ?

First, find the initial broker fee:

=  Initial investment × Broker fee rate

= 20, 000 x 1. 5 %

= 20, 000 x 0. 15

= $ 300

The total fees incurred to buy and sell are:

= 300 initial broker + 21 later broker

= $ 321

The net proceeds would then be:

= Final value of stock - Initial investment - Total fees

= 28, 600 - 20, 000 - 321

= 8, 600 - 321

= $ 8, 279

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Full question is:

Darlene purchases $20,000 worth of stock on her brokers advice and pays her broker a 1.5% broker fee. She sells her stock when it increases to $ 28,600  two years later, and uses a discount broker who charges $21 per trade. Compute Darlene's net proceeds after the broker fees are taken out.

2
Select the correct answer from the drop-down menu.
Which equation satisfies all three pairs of a and b values listed in the table?
a b
0-10
1 -7
2-4
The equation is

Answers

An equation that satisfies all three pairs of a and b values listed in the table include the following: C. 3a - b = 10.

How to determine an equation that satisfies all three pairs of a and b values listed in the table?

In order to determine an equation that satisfies all three pairs of a and b values listed in the table, we would substitute each of the numerical values corresponding to each variable into the given equations and then evaluate as follows;

a - 3b = 10

0 - 3(-10) = 30 (False).

3a + b = 10

3(0) - 10 = -10 (False).

3a - b = 10

3(0) - (-10)

0 + 10 = 10 (True).

3a - b = 10

3(1) - (-7)

3 + 7 = 10 (True).

3a - b = 10

3(2) - (-4)

6 + 4 = 10 (True)

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Complete Question:

Which equation satisfies all three pairs of a and b values listed in the table?

a b

0 -10

1 -7

2 -4

The equation is?

A.) a-3b=10

B.) 3a+b=10

C.) 3a-b=10

D.) a+3b=10

Given that A={1,2,3,4,5} list the elements of the following sets. i.{x2:x€A} ii.{ :x€A} iii.{2x :x€A} iv.{4x+1:x€A}

Answers

I honestly have no idea what it is but a:3452+6x+5

Answer:no idea

Step-by-step explanation:

every year 5 rows and 5columns are increased . derive the formula for the number of students in each row

Answers

The number of students in each row after any number of years, as long as the increase in rows and columns is uniform every year.

Assuming that the increase in rows and columns is uniform every year, we can derive the formula for the number of students in each row as follows:

Let's start with the initial number of rows and columns, which we'll call R0 and C0, respectively, and the number of students in each row, which we'll call S.

After one year, the number of rows and columns will increase by 5, so we'll have R1 = R0 + 5 and C1 = C0 + 5. The total number of students will be R1 x S. We can also express this in terms of the initial number of rows and columns as:

R1 x S = (R0 + 5) x S

Expanding the brackets, we get:

R1 x S = R0 x S + 5 x S

Subtracting R0 x S from both sides, we get:

(R1 - R0) x S = 5 x S

Dividing both sides by 5 x (R1 - R0), we get:

S = 5 / (R1 - R0)

We can use this formula to calculate the number of students in each row after any number of years, as long as the increase in rows and columns is uniform every year.

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Multiply using the Vertical Method: (x+4)(2x^2−3x+5).

Answers

Using vertical method, the multiplication of (2x² −3x+5). by x + 4 is determined as 10x² - 15x + 25.

What is vertical multiplication?

In vertical multiplication, the numbers to be multiplied are placed vertically over one another with their least significant digits aligned.

The top number is named the multiplicand and the lower number is the multiplier. The result of the multiplication is the product.

The given expressions;

(x+4)(2x² −3x+5).

We will multiply as follows;

      2x² - 3x + 5

   ×    x + 4

_________________

     2x² - 3x + 5    (Multiply by x)

+   8x² - 12x + 20  (Multiply by 4)

_________________

    10x² - 15x + 25

Thus, using vertical method, the multiplication of (2x² −3x+5). by x + 4 is determined as 10x² - 15x + 25.

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2. Convert the following into a single log statement from the many log statements to 1.
2 Log w+ log 7-3 log x-8 log y
NOTE: You must show this in at least two steps.
1st line should be to convert the 2 the 3 and the 8 only.
2nd line can be the final answer.

Answers

A single log statement from the many log statements to 1 is: [tex]log(7wy^{(-8)}/x^3)[/tex]

The exponent that indicates the power to which a base number is raised to produce a given number are called logarithm.

Use the logarithmic identity:

log[tex](a^n)[/tex] = n*log(a)

to convert the coefficients 2, 3, and 8:

log w + log 7 - 3log x - 8log y

= log w + log 7 - log [tex]x^3[/tex] - log [tex]y^8[/tex]

Combine the terms on the right-hand side using the logarithmic identity:

log(a) + log(b) = log(ab)

log w + log 7 - log[tex]x^3[/tex] - log [tex]y^8[/tex]

= log([tex]7wy^{-8}/x^3[/tex])

Therefore, the single log statement is from the many log statements to 1 is: log[tex](7wy^{-8}/x^3)[/tex]

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please answer all 3 and show work

Answers

The equation of the Damari's investment is B(x) = 30000 * 1.03ˣ

Sky's family should take the offer of $5000 for the boatThe rule of the function is f(x) = 8 * 0.6ˣ

Calculating the equations of the functions

Damari's investment

Given that

Initial value, a = 30000

B(3) = 32306.72

The function is calculated as

B(x) = a * bˣ

Using B(3), we have

30000 * b³ = 32306.72

So, we have

b³ = 1.077

Take the cube root of both sides

b = 1.03

So, we have

B(x) = 30000 * 1.03ˣ

So, the function is B(x) = 30000 * 1.03ˣ

The boat of Sky's family

Here, we have

Initial value = 6000

Rate of depreciation = 6%

So, the function is

f(x) = 6000 * (1 - 6%)ˣ

So, we have

f(x) = 6000 * (0.94)ˣ

In 2024, we have

x = 2024 - 2021

x = 3

So, we have

f(3) = 6000 * (0.94)³

Evaluate

f(3) = 4983.50

This value is less than the offered value of $5000

This means that Sky's family should take the offer

The rule of the function

Here, we have the graph

From the graph, we have

Initial value, a = 8

Rate, b = 4.8/8

So, we have

Rate, b = 0.6

So, the function is

f(x) = 8 * 0.6ˣ

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What is the mode of the data represented in this line plot?
Enter your answer in the box.

5 - xx
6 - xxxx
7 - xxx
8 - xxxxxx
9 - xx
10 - xxxx
11 - xx

Answers

The mode of the data represented in this line plot will be 8.

Simply counting how several times each number looks in the data set can help you identify the mode, which is the integer that repeats the most frequently in the collected data. The figure with the largest total is the mode.

The value that appears the most frequently in data collection is its mode. By examining the line plot, we can observe that the number 8 and the six Xs above it are the most commonly occurring values. Consequently, 8 represents the data set's mode.

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You roll a 6-sided number cube and toss a coin. Let event A = Toss a heads.

What outcomes are in event A?

What outcomes are in event AC?

Answers

1. Event A includes the outcomes of H and T,

2. while event AC includes all the possible outcomes of rolling a number cube, which are 1, 2, 3, 4, 5, and 6.

1. Event A is defined as tossing a heads on a coin, regardless of the outcome of rolling a number cube. Therefore, the outcomes in event A are H (heads) and T (tails), since either of these outcomes could occur when rolling a number cube and tossing a coin.

2. Event AC is the complement of event A, i.e., it is the set of outcomes that are not in event A. Since event A contains H and T, the outcomes in event AC are the remaining outcomes that are not in event A, which are all the possible outcomes when rolling a number cube: 1, 2, 3, 4, 5, and 6.

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4. Approximate the solution to this system of equations.
y = -2x+6
y = 4x - 1

Answers

The solution of the system of linear equations, is (1.167, 3.667).

Given that the system of linear equations, y = -2x+6 and y = 4x - 1, we need to find the solution for the same,

y = -2x+6............(i)

y = 4x - 1.......(ii)

Equating the equations since the LHS is same,

-2x+6 = 4x-1

6x = 7

x = 1.167

Put x = 1.16 to find the value of y,

y = 4(1.16)-1

y = 4.66-1

y = 3.667

Therefore, the solution of the system of linear equations, is (1.167, 3.667).

You can also find the solution using the graphical method,

Plot the equations in the graph, the point of the intersection of both the lines will be the solution of the system of linear equations, [attached]

Hence, the solution of the system of linear equations, is (1.167, 3.667).

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There are 135 people in a sport centre.
77 people use the gym.
62 people use the swimming pool.
65 people use the track.
27 people use the gym and the pool.
23 people use the pool and the track.
31 people use the gym and the track.
4 people use all three facilities.
How many people didn't use any facilities?

Answers

8 people didn't use any of the gym pool or track facilities.

The number of people use any facilities need to subtract the total number of people who used at least one facility from the total number of people in the sport centre.

The total number of people who used at least one facility by adding the number of people who used each facility and subtracting the number of people who used two facilities and three facilities:

Total = Gym + Pool + Track - (Gym and Pool) - (Pool and Track) - (Gym and Track) + (Gym and Pool and Track)

Total = 77 + 62 + 65 - 27 - 23 - 31 + 4

Total = 127

The number of people who didn't use any facilities is:

135 - 127 = 8

8 people didn't use any of the gym, pool or track facilities.

The number of individuals who did not utilise any facilities must be subtracted from the total number of individuals who utilised at least one facility.

The total number of individuals who utilised at least one facility is calculated by adding the individuals who utilised each facility and deducting the individuals who utilised two and three facilities:

Total = Fitness Centre + Pool + Track - Fitness Centre and Pool - Fitness Centre and Track - Fitness Centre and Pool and Track

Total = 77 + 62 + 65 - 27 - 23 - 31 + 4

Total = 134-127

= 8

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A sequence can be generated by using an= 3an-1, where a1 = 10 and n is a whole number greater than 1.
What are the first 3 terms in the sequence?
A. 3, 13, 23
B. 10, 30, 90
C. 10, 13, 16
D. 3, 30, 300

Answers

Answer:

B

Step-by-step explanation:

using the recursive rule [tex]a_{n}[/tex] = 3[tex]a_{n-1}[/tex] and a₁ = 10, then

a₁ = 10

a₂ = 3a₁ = 3 × 10 = 30

a₃ = 3a₂ = 3 × 30 = 90

the first 3 terms are 10 , 30 , 90

what is the resultant displacement of 6m north 8m east and 10m north west?​

Answers

The resultant displacement is approximately 13.071m north and 8m east.

To find the resultant displacement, we need to combine the given displacements in a vector-like manner.

Let's break down the displacements into their components and then add them up.

The first displacement is 6m north.

Since it is purely in the north direction, its components would be 6m in the north direction (along the y-axis) and 0m in the east direction (along the x-axis).

The second displacement is 8m east.

As it is purely in the east direction, its components would be 0m in the north direction and 8m in the east direction.

The third displacement is 10m northwest.

To find its components, we can split it into two perpendicular directions: north and west.

The northwest direction can be thought of as the combination of north and west, each with a magnitude of 10m.

Since they are perpendicular, we can use the Pythagorean theorem to find the components.

The north component would be 10m multiplied by the cosine of 45 degrees (45 degrees because northwest is halfway between north and west).

Similarly, the west component would be 10m multiplied by the sine of 45 degrees.

Calculating the components:

North component = 10m [tex]\times[/tex] cos(45°) = 10m [tex]\times[/tex] 0.7071 ≈ 7.071m

West component = 10m [tex]\times[/tex] sin(45°) = 10m [tex]\times[/tex] 0.7071 ≈ 7.071m

Now, let's add up the components:

North component: 6m (from the first displacement) + 7.071m (from the third displacement) = 13.071m north

East component: 8m (from the second displacement).

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There are 1000 students at a college. In January, æ of these students had passed
their driving test.
Between January and April, the number of students who had passed their driving
test increased by 20%, and the number of students who had not passed
decreased by 5%. No one left or joined the college during this time.
a) Explain why the number of students who had not passed their driving test yet
was 0.95(1000 - x) in April.
b) Hence explain why 1.2x +0.95(1000-x) = 1000.
c) How many students had passed their driving test in January?

Answers

a) In April, the number of students who had not passed their driving test decreased by 5%.

b) The equation is 1.2x + 0.95(1000 - x) = 1000.

c) 200 students passed their driving test in January.

a) At the beginning, of January, x students had passed their driving test, then the remaining number of students who had not passed their driving test was (1000 - x).

In April, the number of students who had not passed their driving test decreased by 5%, which means the remaining number of students who had not passed their driving test is 0.95 times the original number (1000 - x).

b)

The number of students who had passed their driving test increased by 20%, which means the new number of students who passed their driving test is 1.2 times the original number (x).

The number of students who had not passed their driving test decreased by 5%, which means the new number of students who had not passed their driving test is 0.95 times the original number (1000 - x).

Therefore, we can write the equation 1.2x + 0.95(1000 - x) = 1000.

c) We can solve for x in the equation 1.2x + 0.95(1000 - x) = 1000.

Expanding the equation, we get:

1.2x + 950 - 0.95x = 1000

0.25x = 50

x = 200

Therefore, 200 students passed their driving test in January.

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How do I divide this somebody please help

Answers

Answer:

3

Step-by-step explanation:

factorize whats common in the question

division turns to multiplication by Inverwing the fraction

at the end of the day you will be left with 3

I hope you understand

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