XZ.P Point P(-7, 2) is mapped onto P¹ (3, -11) by the reflection y=mx+c. find the values of the constants m and c.​

Answer:

  y = -10·sin(πt/5) +12

Step-by-step explanation:

You want the equation of the height of a rider of a Ferris wheel that has a radius of 10 and is 2 off the ground, with a period of 10 seconds, moving downward, starting from even with the center.

The general form of the equation will be ...

  y = A·sin(2πt/T) + B

where A is a scale factor that is based on the radius and initial direction, and B is the height of the center of the wheel above the ground.

We assume that 2 [units] off the ground means the low point of the travel is at that height. Then the middle of the wheel is those 2 [units] plus the radius of the wheel:

  B = 2 + 10 = 12

The scale factor A will be the radius of the wheel, made negative because the initial direction is downward from the initial height. That is, ...

  A = 10

The period (T) is given as 10 seconds.

Putting these parameters together gives ...

  y = -10·sin(2πt/10) +12

  y = -10·sin(πt/5) +12

__

Additional comment

We wonder if this wheel is really only 20 inches (20 in) in diameter, as that dimension seems suitable only for a model. We suspect it is probably 20 meters (20 m) in diameter.

Sometimes "m" is confused with "in" when it is written in Roman font and reproduced with poor resolution.

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Answer:

The answer is 8

Step-by-step explanation:

/x/ // /8/

x=8

The probability of a student being female given that they got a 'B' is 87/315.

We can use Bayes' theorem to find the probability of a student being female given that they got a 'B'. Let's first find the total number of students who got a 'B':

Total number of students who got a 'B'

= 7 + 9 + 6 + 13 + 16 + 12

= 63

Out of these 63 students, the number of females who got a 'B' is:

Number of females who got a 'B' = 13 + 16 = 29

So, the probability of a student being female given that they got a 'B' is:

P(Female | B) = P(B | Female) x P(Female) / P(B)

From the given data, we can calculate these probabilities as follows:

P(B | Female) = 29/25

P(Female) = 25/63

P(B) = 63/175

Plugging in these values, we get:

P(Female | B)

= (29/25) x (25/63) / (63/175)

= 87/315

Therefore, the probability of a student being female given that they got a 'B' is 87/315.

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The Second Linearly Independent solution of the differential equation is:

y = c₁x⁷ + c₂(Ax¹⁰ + Bx⁻¹¹)

When solving a second-order linear differential equation of the form

x²y'' - 42y = 0, it is important to find two linearly independent solutions to fully describe the general solution. The first solution is given as y₁=x⁷.

To find the second linearly independent solution, we can use the method of reduction of order.

Let y₂ = u(x)y₁(x), where u(x) is a function to be determined.

Then we have y₂' = u(x)y₁'(x) + u'(x)y₁(x) and y₂'' = u(x)y₁''(x) + 2u'(x)y₁'(x) + u''(x)y₁(x).

Substituting y₂ and its derivatives into the original differential equation, we have:

x²(u(x)y₁''(x) + 2u'(x)y₁'(x) + u''(x)y₁(x)) - 42u(x)y₁(x) = 0

Dividing by x²y₁(x), we get:

u''(x)/u(x) + 2/x[u'(x)/u(x)] - 42/x² = 0

Let v(x) = u'(x)/u(x), then v'(x) = u''(x)/u(x) - (u'(x))²/(u(x))². Substituting v(x) into the above equation, we have:

v'(x) + 2/xv(x) - 42/x² = 0

This is now a first-order linear differential equation that can be solved using an integrating factor. Letting mu(x) = x², we have:

(x²v(x))' = 42

Solving for v(x), we get:

v(x) = 21/x + C/x²

where C is an arbitrary constant. Substituting back to u(x), we get:

u(x) = Ax³ + Bx⁻⁻¹⁸

where A and B are constants. Therefore, the second linearly independent solution is

y₂ = (Ax³ + Bx⁻¹⁸)x⁷ = Ax¹⁰ + Bx⁻¹¹

Hence, the general solution of the differential equation is:

y = c₁x⁷ + c₂(Ax¹⁰ + Bx⁻¹¹)

where c₁ and c₂ are arbitrary constants

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Answer:

12

Step-by-step explanation:

The figure is a right triangle with hypotenuse = QS

The  base from the graph = 4 units
(or you can just subtract the x-coordinates 2 - (-2) = 4)

The height from the graph is 3 units
(Or you can subtract the y-coordinates: 1 - (-2) = 3)

Since this is a right triangle the square of the hypotenuse = sum of squares of the other two sides

QS² = 3² + 4² = 9 + 16 = 25

QS, the hypotenuse = √25 = 5

The perimeter = sum of the sides = 3 + 4 + 5 = 12 units

According to the information, there are thousands of different lunch options in this restaurant.

To calculate the number of different lunches in the restaurant we must carry out the following mathematical procedure. We must multiply the different options as shown below:

4 green options x 5 protein options x 8 vegetable options x 4 extra options x 6 topping options = 4 x 5 x 8 x 4 x 6 = 4,800 different lunch options.

Based on the above, we can infer that 4,800 different lunch options can be created with the available ingredients.

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The expression that is equivalent to [tex]\\\\\frac{60m^-2n^6\\}{5m^-4 n^-2}[/tex] for all values of m and n where the 5m-4n-2 expression is defined is [tex]12m^{2} n^{8}[/tex]

In mathematics, an expression or mathematical expression  can be described as the finite combination of symbols which is been analyzed and  well-formed according by following some set of rules which could be varies base on the kind of the symbol as ll as the operation  that are involved in the expression and it s been done  depending on the context so that another expression can be gotten.

This is given as   [tex]\\\\\frac{60m^-2n^6\\}{5m^-4 n^-2}[/tex]

Then we have it defined by;  [tex]12m^{2} n^{8}[/tex]

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Answer:

The answer is 33°

Yes you are correct

Step-by-step explanation:

angles on a straight line equal 180°

57+90+x=180

x+147=180

x=180-147

x=33°

Hi, I can't tell if there's a little square drawn in red to indicate that there's a right angle in the middle. There's some squiggly lines and so it's kind of hard to tell.

I am going to assume that there is. Let me know if there isn't.

The sum of these 3 angles would be 180 degrees.

As an equation, 57 + 90 + x = 180

Solve for x.

147 + x = 180

x = 33 degrees.

So this would be correct ASSUMING that there's a little red square drawn indicating that there's a right angle.

The volume of the rectangular pyramid is 144.48 cubic feet.

A pyramid with a rectangular base is known as a rectangle pyramid. When viewed from the bottom, this pyramid seems to be a rectangle. As a result, the base has two equal parallel sides.

The apex, which is located at the summit of the pyramid's base, serves as its crown. Right or oblique pyramids can be seen in rectangular shapes. If it is a right rectangular pyramid, the peak will be directly over the base's center; if it is an oblique rectangular pyramid, the apex will be angled away from the base's center.

The volume of a rectangular pyramid is given as:

[tex]\sf V = \dfrac{(l)(b)(h) }{3}[/tex]

[tex]\sf V = \dfrac{(8.4)(8.6)(6) }{3}[/tex]

[tex]\sf V = \dfrac{433.44 }{3}[/tex]

[tex]\sf V = 144.48 \ cubic \ feet[/tex].

Hence, the volume of the rectangular pyramid is 144.48 cubic feet.

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Answer:

the percentage of red marbles in the bag is 30%.

Step-by-step explanation:

To find the percentage of red marbles in the bag, we need to divide the number of red marbles by the total number of marbles and then multiply by 100:

Percentage of red marbles = (Number of red marbles / Total number of marbles) x 100

Number of red marbles = 12

Total number of marbles = 40

Percentage of red marbles = (12/40) x 100

= 0.3 x 100

= 30%

Therefore, the percentage of red marbles in the bag is 30%.

The function g(x) in the form a(x-h)^2 + k is: [tex]g(x) = (x + 2)^2 - 4[/tex]

Starting with[tex]f(x) = x^2[/tex], the translation 2 units left and 4 units down would result in the following transformation:

g(x) = f(x + 2) - 4

Substituting[tex]f(x) = x^2:[/tex]

[tex]g(x) = (x + 2)^2 - 4[/tex]

Expanding the square:

[tex]g(x) = x^2 + 4x + 4 - 4[/tex]

Simplifying:

[tex]g(x) = x^2 + 4x[/tex]

Now we need to rewrite this expression in the form [tex]a(x-h)^2 + k.[/tex] To do this, we will complete the square:

[tex]g(x) = x^2 + 4x\\g(x) = (x^2 + 4x + 4) - 4\\g(x) = (x + 2)^2 - 4[/tex]

Therefore, the function g(x) in the form a(x-h)^2 + k is:

[tex]g(x) = (x + 2)^2 - 4[/tex]

Where a = 1, h = -2, and k = -4.

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Answer:

-----------------------

Quadratic equation has the form of:

Analyze the given equations and see which has the same form:

The slope field for the differential equation would be D . Graph D .

A slope field provides a pictorial representation of differential equations that displays the magnitude and direction of the derivative or slope for solution curves at various points in the plane .

The length of line segments represents the magnitude, while the direction indicates the sign of the slope.

The equation given is y = 2 y + x which means that the slope is positive. This is why we can tell that Graph D has the correct slope field as it goes up for positive.

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The surface areas of the solids are listed below:

Case I: A = 216 ft²

Case O: A = 204 mm²

Case H: A = 216 ft²

Case L: A = 284.6 cm²

Case E: A = 25.657 yd

Case N: A = 356 yd²

Case S: A = 361.88 ft²

Case T: A = 150 cm²

In this problem we find eight solids, whose surface areas, that is, the sum of the areas of all faces of the solid, must be found. Each face can be represented by the following area formula:

Rectangle

A = w · h

Triangle

A = 0.5 · w · h

Where:

Now we proceed to determine the surface areas:

Case I:

A = 6 · (6 ft)²

A = 216 ft²

Case O:

A = 4 · 0.5 · (6 mm) · (14 mm) + (6 mm)²

A = 204 mm²

Case H:

A = 2 · (8 ft) · (6 ft) + (8 ft) · (5 ft) + (6 ft) · (5 ft) + (10 ft) · (5 ft)

A = 216 ft²

Case L:

A = 2 · 0.5 · (7 cm) · (5 cm) + 2 · (6.1 cm) · (13 cm) + (7 cm) · (13 cm)

A = 284.6 cm²

Case E:

A = 2 · 0.5 · (2 yd)² + 2 · (2 yd) · (4 yd) + (√2 yd) · (4 yd)

A = 25.657 yd

Case N:

A = 2 · (3 yd) · (8 yd) + 2 · (8 yd) · (14 yd) + 2 · (14 yd) · (3 yd)

A = 356 yd²

Case S:

A = 2 · 0.5 · (8 ft) · (6 ft) + 2 · (14 ft) · (7.21 ft) + (14 ft) · (8 ft)

A = 361.88 ft²

Case T:

A = 6 · (5 cm)²

A = 150 cm²

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Answer:

3)  A = 35.2°, B = 38.6°, C = 106.2°

4)  B = 70.4°, C = 31.6°, a = 18.7

Step-by-step explanation:

To solve for the remaining angles of the triangle ABC given its side lengths, use the Law of Cosines for finding angles.

[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Law of Cosines (for finding angles)} \\\\$\cos(C)=\dfrac{a^2+b^2-c^2}{2ab}$\\\\\\where:\\ \phantom{ww}$\bullet$ $C$ is the angle. \\ \phantom{ww}$\bullet$ $a$ and $b$ are the sides adjacent the angle. \\ \phantom{ww}$\bullet$ $c$ is the side opposite the angle.\\\end{minipage}}[/tex]

Given sides of triangle ABC:

Substitute the values of a, b and c into the Law of Cosines formula and solve for angle C:

[tex]\implies \cos(C)=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

[tex]\implies \cos(C)=\dfrac{12^2+13^2-20^2}{2(12)(13)}[/tex]

[tex]\implies \cos(C)=\dfrac{-87}{312}[/tex]

[tex]\implies \cos(C)=-\dfrac{29}{104}[/tex]

[tex]\implies C=\cos^{-1}\left(-\dfrac{29}{104}\right)[/tex]

[tex]\implies C=106.191351...^{\circ}[/tex]

To find the measure of angle B, swap b and c in the formula, and change C for B:

[tex]\implies \cos(B)=\dfrac{a^2+c^2-b^2}{2ac}[/tex]

[tex]\implies \cos(B)=\dfrac{12^2+20^2-13^2}{2(12)(20)}[/tex]

[tex]\implies \cos(B)=\dfrac{375}{480}[/tex]

[tex]\implies B=\cos^{-1}\left(\dfrac{375}{480}\right)[/tex]

[tex]\implies B=38.6248438...^{\circ}[/tex]

To find the measure of angle A, swap a and c in the formula, and change C for A:

[tex]\implies \cos(A)=\dfrac{c^2+b^2-a^2}{2cb}[/tex]

[tex]\implies \cos(A)=\dfrac{20^2+13^2-12^2}{2(20)(13)}[/tex]

[tex]\implies \cos(A)=\dfrac{425}{520}[/tex]

[tex]\implies A=\cos^{-1}\left(\dfrac{425}{520}\right)[/tex]

[tex]\implies A=35.1838154...^{\circ}[/tex]

Therefore, the measures of the angles of triangle ABC with sides a = 12, b = 13 and c = 20 are:

[tex]\hrulefill[/tex]

Given values of triangle ABC:

First, find the measure of side a using the Law of Cosines for finding sides.

[tex]\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines (for finding sides)} \\\\$c^2=a^2+b^2-2ab \cos (C)$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}[/tex]

As the given angle is A, change C for A in the formula and swap a and c:

[tex]\implies a^2=c^2+b^2-2cb \cos (A)[/tex]

Substitute the given values and solve for a:

[tex]\implies a^2=10^2+18^2-2(10)(18) \cos (78^{\circ})[/tex]

[tex]\implies a^2=424-360\cos (78^{\circ})[/tex]

[tex]\implies a=\sqrt{424-360\cos (78^{\circ})}[/tex]

[tex]\implies a=18.6856038...[/tex]

Now we have the measures of all three sides of the triangle, we can use the Law of Cosines for finding angles to find the measures of angles B and C.

To find the measure of angle C, substitute the values of a, b and c into the formula:

[tex]\implies \cos(C)=\dfrac{a^2+b^2-c^2}{2ab}[/tex]

[tex]\implies \cos(C)=\dfrac{(18.6856038...)^2+18^2-10^2}{2(18.6856038...)(18)}[/tex]

[tex]\implies \cos(C)=0.852040063...[/tex]

[tex]\implies C=31.565743...^{\circ}[/tex]

To find the measure of angle B, swap b and c in the formula, and change C for B:

[tex]\implies \cos(B)=\dfrac{a^2+c^2-b^2}{2ac}[/tex]

[tex]\implies \cos(B)=\dfrac{(18.6856038...)^2+10^2-18^2}{2(18.6856038...)(10)}[/tex]

[tex]\implies \cos{B}=0.334888270...[/tex]

[tex]\implies B=\cos^{-1}(0.334888270...)[/tex]

[tex]\implies B=70.434256...^{\circ}[/tex]

Therefore, the remaining side and angles for triangle ABC are:

It would cost [tex]$8,100[/tex] to rent the safety deposit box for 15 years at a rate of [tex]$45[/tex] per month.

The total cost of renting a safety deposit box for 15 years, we need to first determine the total number of months in 15 years.

Since there are 12 months in a year, the total number of months in 15 years is:

15 years x 12 months/year = 180 months

So, if the safety deposit box costs [tex]$45[/tex] per month to rent, then the total cost of renting the box for 15 years would be:

180 months x [tex]$45[/tex]/month = [tex]$8,100[/tex]

We must first ascertain the entire number of months in 15 years in order to compute the total cost of renting a safety deposit box for 15 years.

Since there are 12 months in a year, there are a total of 180 months in 15 years: 15 years multiplied by 12 months per year.

In this case, if the monthly rental fee for the safety deposit box is [tex]$45[/tex] and the rental period is 15 years, the total cost would be calculated

180 months x [tex]$45[/tex]/month = [tex]$8,100[/tex]

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Segment BF is 36 will be the accurate statement.

A triangle known to be similar if the ratio of similar sides of the triangle is equal to a constant.

From the given triangle, the following expression is true:

EC/FC = AC/BF+FC

Substitute the given parameters into the formula to have:

20/30 = 24+20/BF+30

20/30 = 44/BF+30

2/3 = 44/BF + 30

2(BF+30) = 132

2BF + 60 = 132

2BF = 132 - 60

2BF = 72

BF = 36

Hence the correct statement will be that segment BF is 36

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Answer:

[tex]C. -5.15\cdot10^{13}[/tex]

Step-by-step explanation:

[tex]Common\ ratio\ (r)=\frac{a_{n+1}}{a_n}=(-3)\\\\Sum\ (S_n)=\frac{a(r^n-1)}{r-1}\ \ (r\neq1)\\\\\implies S_n=\frac{1\ (\ (-3)^{30}-1\ )}{-4}\\\\\implies S_n=\frac{205891132094649-1}{-4}\\\\\approx\frac{206\cdot10^{12}}{-4}\\\\\approx-5.15\cdot10^{13}[/tex]

Answer:

im an expert

Step-by-step explanation:

Diego is correct as the number of groups result to 6/5 or 1 1/5.

We have to find the number of groups of 5/6 in 1.

So, we need to perform the division as

= 1/ (5/6)

= 1 x 6/5

= 6/5

= 1 1/5

Thus, Diego is correct as the number of groups result to 6/5 or 1 1/5.

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If the size of matrix "M" is 9×10, and a scalar "c" is multiplied by matrix, then the size of "cM"  will be 9×10.

We know that when a scalar is multiplied to a matrix, each element of the matrix gets multiplied by that scalar.

In this case, the scalar "c" is multiplied with the Matrix "M";

So if a scalar "c" is multiplied by a matrix "M" of size 9×10, then the resulting matrix "cM" will also have the same number of rows and columns as the original matrix "M".

Therefore, the size of "cM" will also be 9×10.

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The circle equation x² + 8x + y² -10y - 32 = 0​ can be graphed using (x + 4)² + (y - 5)² = 73

From the question, we have the following parameters that can be used in our computation:

x² + 8x + y² -10y - 32 = 0​

Add 32 to both sides of the equation

This gives

x² + 8x + y² -10y = 32

Group the terms in two's

So, we have

(x² + 8x) + (y² -10y) = 32

When we complete the square on each group, we have

(x + 4)² + (y - 5)² = 16 + 25 + 32

Evaluate the like terms

(x + 4)² + (y - 5)² = 73

Hence, the circle equation can be graphed using (x + 4)² + (y - 5)² = 73

See attachment for the graph

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Answer:

In a geometric sequence, each term is found by multiplying the previous term by a constant value called the common ratio (r).

In this case, the first term (a₁) is 2, and the common ratio (r) can be found by dividing any term by its preceding term. Let's calculate it:

r = 6 / 2 = 3

Now, to find the 15th term (a₅₊₁₋₅), we can use the formula:

aₙ = a₁ * r^(n-1)

Substituting the values, we have:

a₁ = 2

r = 3

n = 15

a₁₅ = 2 * 3^(15-1)

Calculating the exponent first:

3^(15-1) = 3^14 = 4782969

Now, substituting this value back into the formula:

a₁₅ = 2 * 4782969

a₁₅ = 9565938

Therefore, the 15th term of the geometric sequence 2, 6, 18, ... is 9565938.

Step-by-step explanation:

Answer:

Consider the following claim: Group behavior can increase the chances for an individual and a species to survive and reproduce.

Consider the following claim: Group behavior can increase the chances for an individual and a species to survive and reproduce.

Consider the following claim: Group behavior can increase the chances for an individual and a species to survive and reproduce.

Consider the following claim: Group behavior can increase the chances for an individual and a species to survive and reproduce.

Consider the following claim: Group behavior can increase the chances for an individual and a species to survive and reproduce.

Consider the following claim: Group behavior can increase the chances for an individual and a species to survive and reproduce.

Step-by-step explanation:

1. Area of the smaller circle is 100πcm²

2. Area of the bigger circle 800πcm²

The formula for the circumference of a circle is expressed as;

Circumference = 2πr

Substitute the values, we get;

20π = 2πr

Divide by the coefficient of r, we get;

r = 10cm

Now, area of a circle is expressed as;

Area = πr²

Substitute the value of the radius

Area = π × 10²

Find the square

Area = 100πcm²

Area of the big circle = 8(area of the small circle)

substitute the values

Area of the big circle = 8(100π)

expand the bracket

Area of the big circle = 800 πcm²

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The sum of the expressions 12√23x¹³ + 14√23x¹³ is in its simplest form if x > 0 is 26x⁶√23x

From the question, we have the following parameters that can be used in our computation:

12\sqrt{23x^{13}}+14\sqrt{23x^{13}}

Express the summation expression, properly

So, we have

12√23x¹³ + 14√23x¹³

Next, we add the terms of teh expression

Using the above as a guide, we have the following:

12√23x¹³ + 14√23x¹³ = 26√23x¹³

Take the square root of x¹³

12√23x¹³ + 14√23x¹³ = 26x⁶√23x

The above expression is in its simplest form if x > 0.

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Answer:

a) r(t) = (10, 5, -5) + (5, 5, 0)*t

b) (0, -5, -5)

Step-by-step explanation:

a) 2x + 4 -2y -5 = -3z -6

2x - 2y +3z +5 =0

(10, 5, -5)

(15, 10, -5)

(5, 5, 0)

r = (10, 5, -5) + (5, 5, 0)*t

b) The yz plane is given by the equation x = 0.

x = 0  in the vector equation of a straight line if and only if  t = -2, than r ( - 2) = (0, -5, -5) is the desired intersection point.

163. The distance between A(-5, 6) and B(5, -5) is: AB ≈ 14.9 units

164. Applying the Pythagorean theorem, we have: Diagonal ≈ 21.2 ft.

165. Marissa's final answer is wrong. It should be, c = √676 = 26 units.

166. Missing side = 29 ft.

The Pythagorean theorem states that c² = a² + b², given that a and b are shorter legs and c is the hypotenuse or longest leg of the right triangle.

163. The distance between A(-5, 6) and B(5, -5):

AB = √[(5−(−5))² + (−5−6)²]

AB = √221

AB ≈ 14.9 units

164. Apply the Pythagorean theorem to find the diagonal:

Diagonal = √(15² + 15²) ≈ 21.2 ft.

165. The answer Marissa got is wrong. The final answer which is the square root of 676 is:

c = √676 = 26 units.

166. Missing side = √(20² + 21²) = 29 ft.

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k bro i gochu

the answer is 84 man,

do good on ur hw

also can i get a pizza

The distance that the plane traveled from point A to point B is given as follows:

10,750 ft.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

The altitude of 5375 feet is the opposite angle, hence the position A is obtained as follows:

tan(15º) = 5375/A

A = 5375/tangent of 15 degrees

A = 20060 ft.

The position B is obtained as follows:

B = 5375/tangent of 30 degrees

B = 9310 ft.

Hence the distance is of:

20060 - 9310 = 10,750 ft.

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