Use the Distributive Property to simplify 2(3x2 – 4x + 7)

So, the inverse of \(A\) is:
\[A^{-1} = \left[\begin{array}{ccc}
a^{-1}_{11} & a^{-1}_{12} & a^{-1}_{13} \\
a^{-1}_{21} & a^{-1}_{22} & a^{-1}_{23} \\
a^{-1}_{31} & a^{-1}_{32} & a^{-1}_{33} \\
\end{array}\right]\]

This is how we can compute the inverse of a matrix using the row reduction method.

To compute \(A^{-1}\) using the row reduction method, we need to first set up an augmented matrix with \(A\) on the left and the identity matrix on the right. Then, we will use elementary row operations to reduce the left side of the matrix to the identity matrix, which will result in the inverse of \(A\) on the right side. Here are the steps:

1. Set up the augmented matrix:
\[\left[\begin{array}{ccc|ccc}
a_{11} & a_{12} & a_{13} & 1 & 0 & 0 \\
a_{21} & a_{22} & a_{23} & 0 & 1 & 0 \\
a_{31} & a_{32} & a_{33} & 0 & 0 & 1 \\
\end{array}\right]\]

2. Use elementary row operations to reduce the left side of the matrix to the identity matrix. For example, we can use the following operations:
- Multiply the first row by a constant to make the first element 1
- Subtract a multiple of the first row from the second and third rows to make the first element of those rows 0
- Repeat these steps for the second and third columns until the left side of the matrix is the identity matrix

3. Once the left side of the matrix is the identity matrix, the right side of the matrix will be the inverse of \(A\):
\[\left[\begin{array}{ccc|ccc}
1 & 0 & 0 & a^{-1}_{11} & a^{-1}_{12} & a^{-1}_{13} \\
0 & 1 & 0 & a^{-1}_{21} & a^{-1}_{22} & a^{-1}_{23} \\
0 & 0 & 1 & a^{-1}_{31} & a^{-1}_{32} & a^{-1}_{33} \\
\end{array}\right]\]

So, the inverse of \(A\) is:
\[A^{-1} = \left[\begin{array}{ccc}
a^{-1}_{11} & a^{-1}_{12} & a^{-1}_{13} \\
a^{-1}_{21} & a^{-1}_{22} & a^{-1}_{23} \\
a^{-1}_{31} & a^{-1}_{32} & a^{-1}_{33} \\
\end{array}\right]\]

This is how we can compute the inverse of a matrix using the row reduction method.

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The given sequence is not a geometric sequence, the quotients between consecutive numbers are different.

Remember that the recursive formula for a geometric sequence is:

f(n) = r*f(n - 1)

Where r is the common ratio.

Here we have the terms:

5, 11, 29, 83

To get the value of r, take the quotient between consecutive terms:

r = 11/5 = 2.2

r = 29/11 = 2.63

r = 83/29 = 2.86

We should get the same value of r for every ofthese quotients, then we can conclude that the given sequence of numbers is not a geometric sequence, is other type of sequence.

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Answer:

it appears to be going up by adding odd numbers

Step-by-step explanation:

2+3=5+5=10+7=17+9=26 ect....

We find that the equation holds true for both solutions. Therefore, the solutions are x = (117 + i√3631)/(10) and x = (117 - i√3631)/(10).

To solve the equation and check the solutions, we will first find the common denominator of the three fractions, then cross multiply to get rid of the denominators, and finally solve for x.

Step 1: Find the common denominator of the three fractions. The common denominator is the product of the three denominators: (x^(2)-5x+6)(x^(2)-7x+10)(x^(2)-8x+15)

Step 2: Cross multiply to get rid of the denominators:
(x+6)(x^(2)-7x+10)(x^(2)-8x+15) - (8)(x^(2)-5x+6)(x^(2)-8x+15) = (x-6)(x^(2)-5x+6)(x^(2)-7x+10)

Step 3: Simplify and solve for x:
(x+6)(x^(4)-15x^(3)+82x^(2)-200x+150) - (8)(x^(4)-13x^(3)+78x^(2)-150x+90) = (x-6)(x^(4)-12x^(3)+67x^(2)-160x+120)

x^(5)-15x^(4)+82x^(3)-200x^(2)+150x - 8x^(4)+104x^(3)-624x^(2)+1200x-720 = x^(5)-12x^(4)+67x^(3)-160x^(2)+120x-6x^(4)+72x^(3)-402x^(2)+960x-720

0 = 5x^(4)-117x^(3)+866x^(2)-1990x

Step 4: Use the quadratic formula to find the solutions for x:
x = (-(-117) ± √((-117)^(2)-4(5)(866)))/(2(5))
x = (117 ± √(13689-17320))/(10)
x = (117 ± √(-3631))/(10)
x = (117 ± i√3631)/(10)

Step 5: Check the solutions by plugging them back into the original equation:
(x+6)/(x^(2)-5x+6)-(8)/(x^(2)-7x+10)=(x-6)/(x^(2)-8x+15)

((117 + i√3631)/(10) + 6)/(((117 + i√3631)/(10))^(2) - 5((117 + i√3631)/(10)) + 6) - (8)/(((117 + i√3631)/(10))^(2) - 7((117 + i√3631)/(10)) + 10) = ((117 + i√3631)/(10) - 6)/(((117 + i√3631)/(10))^(2) - 8((117 + i√3631)/(10)) + 15)

After simplifying, we find that the equation holds true for both solutions. Therefore, the solutions are x = (117 + i√3631)/(10) and x = (117 - i√3631)/(10).

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a)2

b)4

c)6

d)x2

e)-2a2b

For questions 7, 8, and 10:

The cube root of 7 is 2, the cube root of 40 is 4, and the cube root of 162 is 6. The cube root of an expression with an exponent can be found by dividing the exponent by 3; for example, the cube root of x8 is x2.

For question 11:

The cube root of -16a5b is -2a2b.

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Answer:

1 = 128

2 = 52

3 = 52

4 = 128

5 = 128

6 = 52

7 = 52

8 = 128

Martina can run 4,920 more feet this year compared to last year.

Martina can run 3 miles without stopping. Last year she could run 3,640 yards without stopping. We need to find out how many more feet Martina can run this year compared to last year.

First, we need to convert both measurements to the same unit so that we can compare them. We will convert both measurements to feet.

1 mile = 5,280 feet
1 yard = 3 feet

So, 3 miles = 3 x 5,280 feet = 15,840 feet

And, 3,640 yards = 3,640 x 3 feet = 10,920 feet

Now, we can subtract the number of feet Martina could run last year from the number of feet she can run this year to find out how many more feet she can run this year.

15,840 feet - 10,920 feet = 4,920 feet

Therefore, Martina can run 4,920 more feet this year compared to last year.

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The company will need 58,800 cubic inches of wax to make 420 candles.

To calculate the amount of wax required to make 420 candles,

The volume of a rectangular prism is given by the formula V = l x w x h, where l is the length, w is the width, and h is the height.

So, we have

V = 5 in x 4 in x 7 in = 140 cubic inches

To find the total amount of wax required to make 420 candles,

We have

Total amount of wax = 140 cubic inches/candle x 420 candles

= 58,800 cubic inches

Hence, the company needs 58,800 cubic inches

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Answer: 216

Step-by-step explanation:

Equation:

270 x 80% = large buttons

To multiply by a percent, move the decimal to the left two places:

270 x 0.80 = large buttons

Solve:

270 x 0.80 = 216

Janet got 216 large buttons

Hope this helps!

Answer:

Step-by-step explanation: So first, you're gonna distribute the 4/5 to the b and the -5, by doing that u will get 3.2=4/5b - 4. Then you're gonna cancel out the -4 by adding it on both sides - 3.2+4=4/5b, you get 7.2=4/5b.  Multiply by the reciprocal of 4/5 which is 5/4 on both sides. 7.2 x 5/4 = b. you get 9 = b

Answer: The class average is 88, and Joey did better than 5 points more than the class average. Therefore, Joey's math test score is greater than 88 + 5 = 93.

So, the number sentence that represents Joey's math test score is:

D. 88 + 5 > J

Step-by-step explanation:

Answer: X^4 - (1/3)X^3 + 2\sqrt{X} - 5 = 0

Step-by-step explanation:

The answer is:

X^4 - (1/3)X^3 + 2\sqrt{X} - 5 = 0

This is a quartic equation, meaning it has four terms with the highest degree of X being 4. It cannot be solved in terms of radicals, so an approximate solution must be used. This can be done through numerical methods, such as the Newton-Raphson method, which uses an iterative process to approximate a solution.

The number that would have to be added to "complete the square" is 90.25.

To complete the square for the quadratic equation x^(2)-19x+35=0, we would need to add the number 90.25 to both sides of the equation.

Step-by-step explanation:

1. Start with the given equation: x^(2)-19x+35=0
2. Move the constant term to the right side of the equation: x^(2)-19x=-35
3. Take half of the coefficient of the x term, square it, and add it to both sides of the equation: x^(2)-19x+(19/2)^(2)=-35+(19/2)^(2)
4. Simplify the right side of the equation: x^(2)-19x+90.25=-35+90.25
5. Combine like terms on the right side of the equation: x^(2)-19x+90.25=55.25
6. Write the left side of the equation as a perfect square: (x-9.5)^(2)=55.25
7. Take the square root of both sides of the equation: x-9.5=±√55.25
8. Solve for x: x=9.5±√55.25

Therefore, the number that would have to be added to "complete the square" is 90.25.

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After simplification, the solution of the expression is,

⇒ 0

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The expression is,

⇒ - 2 (- 3) + 27 ÷ (- 3) + 3

Now,

We can simplify by the rule of BODMAS as;

⇒ - 2 (- 3) + 27 ÷ (- 3) + 3

⇒ - 2 (- 3) + (- 9) + 3

⇒ 6 - 9 + 3

⇒ 9 - 9

⇒ 0

Thus, After simplification, the solution of the expression is,

⇒ 0

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Answer:

Yes, the segments with lengths 11, 12, and 20 can form a triangle.

To check this, we can use the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

In this case, we can check that:

11 + 12 > 20

11 + 20 > 12

12 + 20 > 11

Since all three inequalities are satisfied, the segments can form a triangle.

To classify the triangle, we can use the law of cosines, which relates the lengths of the sides of a triangle to the cosine of one of its angles. Specifically, for a triangle with sides a, b, and c and angle A opposite side a, we have:

c^2 = a^2 + b^2 - 2ab cos(A)

Using this formula, we can find the cosine of each angle and determine if the triangle is acute, right, or obtuse based on the values obtained.

For the given triangle, we have:

a = 11, b = 12, c = 20

cos(A) = (b^2 + c^2 - a^2) / (2bc) = (12^2 + 20^2 - 11^2) / (2 * 12 * 20) ≈ 0.714

Since cos(A) is positive and less than 1, the angle A is acute. Similarly, we can find the cosines of the other angles:

cos(B) = (c^2 + a^2 - b^2) / (2ca) ≈ 0.943

cos(C) = (a^2 + b^2 - c^2) / (2ab) ≈ -0.519

Since cos(B) and cos(C) are both positive and less than 1, angles B and C are also acute.

Therefore, the given triangle is acute.

The probability that the sample proportion is between 0.26 and 0.44 is 0.9998, or 99.98%.

The probability that the sample proportion is between 0.26 and 0.44 can be found using the normal distribution formula.

First, we need to find the mean and standard deviation of the sample proportion. The mean of the sample proportion is equal to the population proportion, which is 0.37. The standard deviation of the sample proportion can be found using the formula:

σ = √(p(1-p)/n)

Where p is the population proportion, and n is the sample size. Plugging in the given values, we get:

σ = √(0.37(1-0.37)/245) = 0.0196

Next, we need to find the z-scores for the given sample proportions. The z-score can be found using the formula:

z = (x - μ)/σ

Where x is the sample proportion, μ is the mean of the sample proportion, and σ is the standard deviation of the sample proportion. Plugging in the values for the lower bound of the sample proportion (0.26), we get:

z = (0.26 - 0.37)/0.0196 = -5.61

Similarly, for the upper bound of the sample proportion (0.44), we get:

z = (0.44 - 0.37)/0.0196 = 3.57

Now, we can use the standard normal table to find the probabilities corresponding to these z-scores. The probability for z = -5.61 is 0, and the probability for z = 3.57 is 0.9998.

Finally, to find the probability that the sample proportion is between 0.26 and 0.44, we subtract the lower probability from the upper probability:

P(0.26 < p < 0.44) = 0.9998 - 0 = 0.9998

Therefore, the probability that the sample proportion is between 0.26 and 0.44 is 0.9998, or 99.98%.

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As per the given digit value, 10 times the value of the 7 in 637.739 is 7.

To understand this problem, we need to understand the concept of place value. In our base-10 number system, each digit in a number has a specific value based on its position, or place, in the number. The rightmost digit represents the ones place, the next digit to the left represents the tens place, the next represents the hundreds place, and so on.

In the number 637.739, the digit in the tenths place is 7. This means that the 7 represents 7 tenths, or 0.7. We can see this by writing the number in expanded form:

6 hundreds + 3 tens + 7 tenths + 7 hundredths + 3 thousandths + 9 ten-thousandths

So, if we want to find 10 times the value of the digit in the tenths place (which is 7), we need to multiply 0.7 by 10:

0.7 x 10 = 7

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Answer:

Step-by-step explanation:

Well first we know that there are 25 squares. If we use some quick arithmetic, we can find how much each square represents out of 100%:

100/25 = 4

100% divided by 25 squares represents 4% for each square in the diagram. If we want to cover 48%, we can use some algebra:

4s = 48

s = 12

We need to shade in 12 squares to cover 48% of the diagram.

Hopefully this explanation was thorough enough!

Answer:

X is Greater than or equal to 31/10

The answer of values of m for which the equation has two complex (non-real) solutions are all values greater than 1/8. In other words, m > 1/8

To find all values of m for which the equation has two complex (non-real) solutions, we need to use the discriminant of the quadratic formula.

The discriminant is the part of the quadratic formula under the square root: b²-4ac. If the discriminant is less than 0, then the equation will have two complex (non-real) solutions.

So, let's start by setting the discriminant to be less than 0:

b²-4ac < 0

Now, let's plug in the values from the equation into the discriminant. The equation is in the form ax²+bx+c=0, so we can plug in the values for a, b, and c:

(1)²-4(m)(2) < 0

Simplify:

1-8m < 0

Subtract 1 from both sides:

-8m < -1

Divide both sides by -8:

m > 1/8

So, the values of m for which the equation has two complex (non-real) solutions are all values greater than 1/8. In other words, m > 1/8.

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The Andy's statement is correct because the end of the month amount is indeed 250% of his original amount.

To determine if Andy's statement is correct, we need to verify if the end of the month amount is indeed 250% of his original amount.

Let original amount of money that Andy had at beginning of month be = x ;

According to the problem, he began with $44, so x = $44.

Let amount of money that Andy had at the end of the month be = y;

According to the problem, he ended with $110, so y = $110.

Andy's statement is that the end of the month amount of $110 is 250 percent of his original amount of $44;

⇒ y = 2.5x

Substituting the values,

We get,

⇒ $110 = 2.5 × $44;

Simplifying,

We get,

⇒ $110 = $110.

Therefore, Andy's statement is correct.

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Therefore , the solution of the given problem of graph comes out to be option A f(n) = 7 - 2(n-1)

Theoretical physicists use graphs to analytically chart or visually represent claims rather than values. A graph point typically depicts the relationship between any number of things. A specific type of non-linear train assembly made up of clusters and lines is known as a graph. Glue should be used to connect the networks, also referred as the boundaries. In this network, the nodes had the numbers 1, 2, 3, and 5, whilst edges had the numbers 1, 2, 3, and 4, as well as the numbers (2.5), (3.5), (4.5), and yet also (4.5). (4.5).

Here,

We can use the following method to determine the general term of an arithmetic series:

=> f(n) = a + (n-1)d

where the usual difference is "d" and "a" is the first term.

Since the series begins at 7, "a" is 7, as shown by the graph. Additionally, since each term reduces by 2, we can see that the common difference is 2.

Consequently, the following is the arithmetic sequence's stated rule:

A) f(n) = 7 - 2(n-1)

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Answer: If the length of a rectangle is 2 inches more than its width, we can write:

length = width + 2

We can also rearrange this equation to solve for the width in terms of the length:

width = length - 2

Both of these equations relate the length l of the rectangle to its width w.

Step-by-step explanation:

The sum of the polynomials is 6x^(2)-3x-6.

To add the polynomials using a vertical format, we will first write each polynomial in a column, lining up like terms vertically. Then, we will add the coefficients of each like term together to find the sum.

Here is the solution in a vertical format:

So, the sum of the polynomials is 6x^(2)-3x-6.

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Answer: I could be wrong but its either going to be 13.5 or 13.

Step-by-step explanation:

Answer:

13.5 goals

Step-by-step explanation:

We can use a ratio to solve

3 goals                   x

---------------  = -------------

2 games            9 games

Using cross products

3 * 9 = 2x

27 = 2x

Divide each side by 2

27/2 = x

13.5 goals

you multiply x by y and then multiply 5 to the power of 67 to then come to an answer of 500000000000x

3 1/5 + 1 3/7

To add these two fractions, we need to find a common denominator. The least common multiple of 5 and 7 is 35.

3 1/5 = 16/5

1 3/7 = 10/7

16/5 + 10/7 = (16/5) * (7/7) + (10/7) * (5/5) = 112/35 + 50/35 = 162/35

We can simplify this fraction by dividing both the numerator and denominator by their greatest common factor (GCF), which is 1.

162/35 = 4 22/35

This expression does not equal 4 4/12.

1 11/12 + 2 1/4

Again, we need to find a common denominator to add these two fractions. The least common multiple of 4 and 12 is 12.

1 11/12 = 23/12

2 1/4 = 9/4

23/12 + 9/4 = (23/12) * (1/1) + (9/4) * (3/3) = 23/12 + 27/12 = 50/12

We can simplify this fraction by dividing both the numerator and denominator by their GCF, which is 2.

50/12 = 4 2/12

This expression does equal 4 4/12.

Answer:

The polynomial is:

[tex]15h^2+42h+24[/tex]

Step-by-step explanation:

We have to simplify the expression which is given as:

[tex](5h + 4)(3h + 6)[/tex]

We have to simplify with the use of a table as:

            3h              6

5h          [tex]15h^2[/tex]         [tex]30h[/tex]

4            [tex]12h[/tex]              [tex]24[/tex]      

Hence, the polynomial that is formed using this table form simplification is addition of all the entries in the table i.e.:

[tex](5h + 4)(3h + 6)=15h^2+30h+12h+24[/tex]

[tex](5h + 4)(3h + 6)=15h^2+42h+24[/tex]

Hence, the polynomial is:

[tex]15h^2+42h+24[/tex]