Using the standard enthalpies of formations find the standard enthalpy of the reaction below. 2A1+ 3CuCl₂ → 2AICI, + 3Cu ​

The mass of copper sulfate obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid is 50.27 grams.

The balanced chemical equation for the reaction between copper oxide and sulfuric acid is:

[tex]CuO + H_2SO_4\ - > CuSO_4 + H_2O[/tex]

First, we need to calculate the number of moles of CuO:

n(CuO) = m/M = 25 g / 79.55 g/mol = 0.314 mol

Therefore, the number of moles  [tex]CuSO_4[/tex] produced is also 0.314 mol.

Finally, we can calculate mass  [tex]CuSO_4[/tex]  produced:

m([tex]CuSO_4[/tex]) = n([tex]CuSO_4[/tex]) x M([tex]CuSO_4[/tex]) = 0.314 mol x 159.61 g/mol = 50.27 g

Therefore, assuming the reaction proceeds to completion, the mass of copper sulfate obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid is 50.27 grams.

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--The complete question is, What mass of copper sulfate can be obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid, assuming the reaction proceeds to completion?--

Answer:Yes

Explanation:

Because Chinstrap penguins eat krills

The pH of the given aqueous solution with [H+] = 0.0055 M at 298 K is approximately 2.26.

The formula used to find the pH of the solution is given as,

pH = -log[H+]

Substituting [H+] = 0.0055 M into the above formula, we get,

pH = -log(0.0055) ≈ 2.26

Therefore, the pH of the given aqueous solution with [H+] = 0.0055 M at 298 K is around 2.26.

A solution's acidity or basicity is determined by its pH. It is described as the hydrogen ion concentration's negative logarithm, pH = -log(H+). It is commonly expressed as [H+] and measured in units of moles per litre (M).

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Taking into account the definition of molarity, you would recover 0.525 moles of iron (II) nitrite.

Molar concentration or molarity indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

molarity= number of moles÷ volume

Molarity is expressed in units moles/L.

In this case, you have:

Replacing in the definition of molarity:

3.5 M= number of moles÷ 0.150 L

Solving:

3.5 M× 0.150 L= number of moles

0.525 moles= number of moles

Finally, you would recover 0.525 moles​.

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Nuclear modifications are alterations that take place inside an atom's nucleus. The amount of protons and neutrons in the nucleus may change, and this is the most fundamental degree of change that can take place in a material.

The atom is considered to have experienced a nuclear transition and is now a distinct atom when the number of protons or neutrons changes. This is thus because the element is determined by the number of protons, and the element changes if the number of protons varies.

If an atom of uranium contains 92 protons, for instance, it is uranium; nevertheless, if it has 91 protons, it is protactinium. This nuclear shift produces a distinct atom with different properties.

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The right response is B. 103.5 g. The mole ratio of sodium to chloride is 1:1 according to the equation Na+ + Cl NaCl. Since 4.5 moles of chloride are provided, the equation requires 4.5 moles of sodium to be balanced. We must utilise the molar mass of sodium, which is 22.99 g/mol, to get the mass of sodium.

We obtain 103.5 g of sodium by multiplying 4.5 moles of sodium by 22.99 g/mol. The correct response is B. 103.5 g.

The equation requires 1 mole of sodium for every mole of chloride, giving 4.5 moles of sodium and 103.5 g.

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5.93 moles of lithium oxide i.e. the product will be produced in the reaction.

The balanced chemical equation for the synthesis of lithium oxide from lithium and oxygen gas is:

4 Li + O₂ → 2 Li₂O

We must first compute the required volume of oxygen gas in order to determine the moles of lithium oxide that are created. Going by the stoichiometry of the reaction, 2.7 moles of lithium will produce 2 moles of lithium oxide when reacted with 0.675 moles of oxygen gas.

Therefore, the amount of lithium oxide generated can be calculated as follows, The formula is 2 moles Li₂O/0.675 moles O₂*1 = 5.93 moles Li₂O.

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Answer:

A. 9.83g

B. 13.06

Explanation:

A) To calculate the mass of BaSO4 formed, you need to first write the balanced equation for the reaction:

Ba(OH)2 + H2SO4 -> BaSO4 + 2H2O

Then, you need to find the limiting reactant, which is the one that runs out first and determines how much product is formed. You can do this by converting the volumes and concentrations of the solutions to moles and comparing them with the stoichiometric coefficients.

50 mL of 1.00 M Ba(OH)2 = 0.050 L x 1.00 mol/L = 0.050 mol Ba(OH)2 88.7 mL of 0.475 M H2SO4 = 0.0887 L x 0.475 mol/L = 0.0421 mol H2SO4

According to the equation, 1 mol of Ba(OH)2 reacts with 1 mol of H2SO4, so Ba(OH)2 is in excess and H2SO4 is the limiting reactant.

Next, you need to use the mole ratio between the limiting reactant and the product to find how many moles of BaSO4 are formed:

0.0421 mol H2SO4 x (1 mol BaSO4 / 1 mol H2SO4) = 0.0421 mol BaSO4

Finally, you need to multiply the moles of BaSO4 by its molar mass to get its mass:

0.0421 mol BaSO4 x 233.39 g/mol = 9.83 g BaSO4

So, the mass of BaSO4 formed is 9.83 g.

B) To calculate the pH of the mixed solution, you need to first find the concentration of OH- ions that remain after the reaction. You can do this by subtracting the moles of OH- that reacted with H+ from the initial moles of OH- and dividing by the total volume of the solution.

The initial moles of OH- are equal to the moles of Ba(OH)2:

0.050 mol Ba(OH)2 x (2 mol OH- / 1 mol Ba(OH)2) = 0.100 mol OH-

The moles of OH- that reacted with H+ are equal to the moles of H2SO4:

0.0421 mol H2SO4 x (2 mol H+ / 1 mol H2SO4) = 0.0842 mol H+

The remaining moles of OH- are:

0.100 mol OH- - 0.0842 mol H+ = 0.0158 mol OH-

The total volume of the solution is:

50 mL + 88.7 mL = 138.7 mL = 0.1387 L

The concentration of OH- is:

0.0158 mol OH- / 0.1387 L = 0.114 M

Next, you need to use the relationship between pH and pOH to find the pH:

pOH = -log[OH-] = -log(0.114) = 0.94 pH + pOH = 14 pH = 14 - pOH = 14 - 0.94 = 13.06

So, the pH of the mixed solution is 13.06.

As we know that, Because improving an oven entails increasing the heat released by the oven while it is operating, it is related to the idea of endothermic and exothermic reactions in chemistry.

Exothermic reactions emit heat into their surroundings, whereas endothermic reactions absorb heat from them. After 30 minutes of operation, the oven's modifications would probably cause it to release more heat, which would change the interior temperature. By observing the flow of heat from the heating components to the interior of the oven, the performance of the improved oven can be evaluated using the laws of thermodynamics and heat transfer.

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--The complete Question is, How does the process of enhancing an oven relate to the concept of endothermic and exothermic reactions in chemistry? Would the changes make to the oven lead to an increase or decrease in the heat released by the oven during operation, and how would this affect the temperature inside the oven after 30 minutes of use? How can the principles of thermodynamics and heat transfer be applied to analyze the performance of the enhanced oven, and what chemical reactions might be involved in the heating process? --

The balanced chemical reaction for the production of the C₃H₈, the propane :

3C(s) + 4H₂(g) → C₃H₈(g)

The chemical equations are :

(a) C₂H₈(g)+5O₂(g) --> 3CO₂(g)+ 4H₂O(l)

(b) C(s) + O₂(g) --> CO₂(g)

(c) H₂(g) + 0.5O₂(g) --> H₂O(l)

On multiplying the reaction b by 3 we get :

3C(s) + 3O₂(g) → 3CO₂

On multiplying the reaction c by 4 we get :

4H₂(g) + 2O₂(g) → 4H₂O(l)

On adding the both the equation :

3C(s) + 4H₂(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

After subtracting the equation we get the balanced chemical equation and will produce the propane, C₃H₈(g), from the elements :

3C(s) + 4H₂(g) → C₃H₈(g)

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174.72 liters of hydrogen, measured at STP, would be needed to produce 88.5 grams of ammonia

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of ammonia = 88.5g

Moles of ammonia = mass / molar mass

= 88.5 / 17

= 5.20 moles

From the reaction,

3 moles of hydrogen are needed to produce 2 moles of ammonia

Thus, 1 mole of ammonia is produced by 3/2 moles of hydrogen

So, 5.20 moles of ammonia is produced by (3 × 5.2) ÷ 2

= 7.8 moles of hydrogen

1 mole of a gas occupies 22.4 L of volume

7.8 moles occupy = 7.8 × 22.4 = 174.72 L

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Answer:

1.44 STABLE

Explanation:

The amount of NH₃ that would be produced from H₂ is less than the amount that would be produced from N₂, H₂ is the limiting reagent. Then, the theoretical yield of NH₃ is 6.98 g.

The balanced chemical equation for the reaction between H₂ and N₂ to form NH₃ is;

N₂ + 3H₂ → 2NH₃

To calculate the theoretical yield of NH₃, we need to determine the limiting reagent in the reaction. We can do this by calculating the amount of NH₃ that would be produced from each reactant, assuming that the other reactant is in excess.

For H₂; 1 mole of H₂ (2.02 g) reacts with 0.5 moles of NH₃ (17.03 g)

Therefore, 1.40 g of H₂ would produce: (0.5 mol NH₃ / 1 mol H₂) x (17.03 g NH₃ / 1 mol NH₃) x (1.40 g H₂ / 2.02 g H₂)

= 6.98 g NH₃

For N₂ 1 mole of N₂ (28.02 g) reacts with 2 moles of NH₃ (34.06 g)

Therefore, 9.66 g of N₂ would produce; (2 mol NH₃ / 1 mol N₂) x (34.06 g NH₃ / 1 mol NH₃) x (9.66 g N₂ / 28.02 g N₂) = 23.5 g NH₃

Therefore, the theoretical yield of NH₃ is 6.98 g.

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Answer:a=10.3 b=250.7c c= gass d= liquid

Explanation:

The correct answer is (C) CO2 and H2O.

When C4H8 (butene) is burned, it reacts with oxygen (O2) from the air to form carbon dioxide (CO2) and water (H2O) as products. The balanced chemical equation for this reaction is:

C4H8 + 6O2 → 4CO2 + 4H2O

Therefore, the products formed when C4H8 is burned are carbon dioxide and water.

The heat absorbed by the engine block when its temperature is raised from 20°C to 90°C is 665,640 J.

To calculate the heat absorbed by the engine block, we can use the equation:

Q = mcΔT

where Q is the heat absorbed, m is the mass of the engine block, c is the specific heat capacity of steel, and ΔT is the change in temperature.

First, we need to calculate the specific heat capacity of steel. The specific heat capacity of steel is typically around 0.45 J/g°C.

Using this value and the given values of mass and temperature change, we can calculate the heat absorbed by the engine block as follows:

Q = (21080 g) x (0.45 J/g°C) x (90°C - 20°C)

Q = 21080 g x 0.45 J/g°C x 70°C

Q = 665,640 J

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The experiment looks into how temperature impacts how quickly magnesium metal reacts with hydrochloric acid. The creation of hydrogen gas over time is used to determine the dependent variable, which is the reaction rate.

The experiment can be run at various temperatures to change the experiment's independent variable, which is the reaction mixture's temperature. Higher temperatures cause molecules to move more quickly, increasing the likelihood of reactant collisions and kinetic energy. By enabling more successful collisions between magnesium atoms and hydrochloric acid, can quicken the reaction and increase the amount of hydrogen gas produced. In contrast, it is anticipated that the reaction rate will be slower at lower temperatures since there will be less molecular mobility and fewer successful collisions.

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--The complete Question is, What is the effect of temperature on the rate of reaction between hydrochloric acid and magnesium metal?

The dependent variable in this experiment is the rate of reaction, which can be measured by monitoring the production of hydrogen gas over time. The independent variable is the temperature of the reaction mixture, which can be controlled and varied by conducting the experiment at different temperatures.--

The experiment looks into how temperature impacts how quickly magnesium metal reacts with hydrochloric acid. The creation of hydrogen gas over time is used to determine the dependent variable, which is the reaction rate.

The experiment can be run at various temperatures to change the experiment's independent variable, which is the reaction mixture's temperature. Higher temperatures cause molecules to move more quickly, increasing the likelihood of reactant collisions and kinetic energy. By enabling more successful collisions between magnesium atoms and hydrochloric acid, can quicken the reaction and increase the amount of hydrogen gas produced. In contrast, it is anticipated that the reaction rate will be slower at lower temperatures since there will be less molecular mobility and fewer successful collisions.

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--The complete Question is, What is the effect of temperature on the rate of reaction between hydrochloric acid and magnesium metal?

The dependent variable in this experiment is the rate of reaction, which can be measured by monitoring the production of hydrogen gas over time. The independent variable is the temperature of the reaction mixture, which can be controlled and varied by conducting the experiment at different temperatures.--

Fluorine (F-) is the element with the fewest valence electrons. Seven electrons make up the outermost shell of fluorine, and one of them is unpaired. As a result, fluorine possesses seven valence electrons altogether.

Eight valence electrons are present in magnesium (Mg2+), nine are present in gallium (Ga+), eight are present in argon (Ar+), four are present in carbon (C+), six are present in sulphur (S2-), and seven are present in fluorine (F-).

Fluorine has a lower number of valence electrons than the other elements because it has a greater effective nuclear charge. This indicates that the fluorine atom will take electrons away from its outermost shell since it is more attracted to electrons than the other elements.

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The mass of NaCl produced by the reaction of 54.2 g of chloride ions with an excess of sodium is 89.51 grams.

Stoichiometry is the concentration of a substance in solution, expressed as the number of moles of solute per litre of solution.

According to this question, 1 mole of sodium reacts with 1 mole chloride ion to produce 1 mole of sodium chloride.

54.2 grams of chlorine is equivalent to 1.53 moles. Hence, 1.53 moles of sodium chloride will be produced.

1.53 moles of sodium chloride is equivalent to 89.51 grams.

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Answer:

radius = 16 in ; height = 27 in

The Sun rotates at different rates at different latitudes on the Sun

The sun revolves around its axis like a ball in motion. One cycle of the sun takes approximately 27 days. But the sun rotates at various rates in various parts. The sun's equator rotates more quickly than its poles. Differential rotation is the name given to this phenomena.

The depth of the sun also affects how quickly it rotates, with the core regions rotating more slowly than the outer regions.

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Missing parts;

Which statement about the Sun's rotation is TRUE?

The Sun rotates only at the equator, where the sunspots are found; the rest of the Sun does not rotate

Only the atmosphere of the Sun rotates, not the main body of the Sun

The Sun rotates at different rates at different latitudes on the Sun

The Sun rotates once a day

The Sun does not rotate; only planets rotate

Answer:

3. d

4. c

5. i

6. h

7. a

8. g

9. j

10. b

11. e

12. f

Explanation:

Answer:

The mass of oxygen needed to completely burn 80 grams of methane is 320 grams.

Explanation:

The balanced chemical equation for the combustion of methane with oxygen is:

CH4 + 2O2 -> CO2 + 2H2O

From the equation, we can see that 1 mole of methane reacts with 2 moles of oxygen to form 1 mole of carbon dioxide and 2 moles of water. We can use this information, along with the molar masses of the compounds, to calculate the mass of oxygen needed to burn 80 grams of methane.

First, we need to convert the given mqss of methane to moles. The molar mass of methane is 16.04 g/mol, so:

Moles of CH4 = Mass of CH4 / Molar mass of CH4

Moles of CH4 = 80 g / 16.04 g/mol

Moles of CH4 = 4.98 mol

Next, we can use the mole ratio from the balanced equation to calculate the moles of oxygen needed:

Moles of O2 = Moles of CH4 x (2 Moles of O2 / 1 Mole of CH4)

Moles of O2 = 4.98 mol x 2

Moles of O2 = 9.96 mol

Finally, we can convert the moles of oxygen to grqms using its molar mass of 32.00 g/mol:

Mass of O2 = Moles of O2 x Molar mass of O2

Mass of O2 = 9.96 mol x 32.00 g/mol

Mass of O2 = 319.68 g

Therefore, the mass of oxygen needed to completely burn 80 grams of methane is 319.68 grams, which we can round up to 320 grams.

There are 3.33 moles of [tex]C_{2}H_{4}[/tex] in the mixture.

The balanced chemical equation for the combustion of methane and ethene is:

[tex]CH_{4} + 2O_{2} = CO_{2} + 2H_{2}O\\C_{2}H_{4} + 3O_{2} = 2CO_{2} + 2H_{2}O[/tex]

From the equation, we can see that for every mole of [tex]C_{2}H_{4}[/tex], 3 moles of O2 are needed. Therefore, to burn 10 moles of O2, we need:

10 moles [tex]O_{2}[/tex]x (1 mole [tex]C_{2}H_{4}[/tex]/3 moles [tex]O_{2}[/tex]) = 3.33 moles [tex]C_{2}H_{4}[/tex]

So, there are 3.33 moles of [tex]C_{2}H_{4}[/tex] in the mixture.

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The total moles of [tex]O_2[/tex] needed is 10

To find the moles of [tex]C2H_4[/tex] in the mixture, first, write the balanced equations for combustion:

[tex]CH_4 + 2O_2[/tex] → [tex]CO_2 + 2H_2O[/tex]

Expanding, this becomes:

[tex]C_2H_4 + 3O_2[/tex] → [tex]2CO_2 + 2H_2O[/tex]

Let x = moles of [tex]CH_4[/tex] and y = moles of [tex]C2H_4.[/tex]

The total moles of [tex]O_2[/tex] needed is 10: 2x + 3y = 10

Therefore, it can be seen that in order to burn the mixture of methane [tex]CH_4[/tex] and ethane [tex]C2H_4[/tex], there are 10 moles of CH4 that are needed in the solution.

With this in mind, the total moles of [tex]O_2[/tex] needed is 10:

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We need to add approximately 0.3375 moles of HCl to the 1-liter buffer solution to achieve a pH of 4.02.

To adjust the pH of a 1-liter buffer solution (1.3M acetic acid, 0.8M sodium acetate) to 4.02, use the Henderson-Hasselbalch equation: pH = pKa + log ([A-] / [HA]).

Acetic acid's pKa is 4.74.

Solving for the ratio (0.8 / 1.3) gives ≈ 0.215. After adding HCl, new concentrations are: [HA]new = 1.3 + x, [A-]new = 0.8 - x.

The new ratio (0.8 - x) / (1.3 + x) = 0.215.

Solving for x yields ≈ 0.3375 moles.

Add 0.3375 moles of HCl to achieve a pH of 4.02.

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Answer:

The structural formula for diethylamine is C4H11N

Explanation:

44.4 g is the mass of Aluminum Oxide is required for the given chemical reaction 3 BaSO[tex]_4[/tex] + Al[tex]_2[/tex]O[tex]_3[/tex]—> 3 BaO + Al[tex]_2[/tex](SO[tex]_4[/tex])[tex]_3[/tex].

It is the most fundamental characteristic of matter as well as one of the essential quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the international standard of mass. A body's bulk remains constant at all times. only in rare instances where an enormous quantity of energy is supplied to or taken away from a body.

3 BaSO[tex]_4[/tex] + Al[tex]_2[/tex]O[tex]_3[/tex]—> 3 BaO + Al[tex]_2[/tex](SO[tex]_4[/tex])[tex]_3[/tex]

moles of BaO =202/ 153.3

                        =1.32

moles of Al[tex]_2[/tex]O[tex]_3[/tex] = 1/3×1.32=0.44

mass of Al[tex]_2[/tex]O[tex]_3[/tex] = 0.44×101.9=44.4 g

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