We write numbers using only the digits 1,3,6 and 9 and arrange them in order. Our list begins 1,3,6,11,13,16,19,31,33 and so on. How many numbers do we write which are smaller than 2022?

There is no line parallel to the line x + 2 · y + 8 = 0, as point (x, y) = (- 2, - 3) lies on the original line.

In this problem we need to determine the equation of line based on its slope relationship respect to another line and a given point. Two lines are parallel if and only if they have the same slope (m) and two distinct intercepts (b). First, transform the given equation of the line into slope-intercept form:

x + 2 · y + 8 = 0

2 · y = - x - 8

y = - (1 / 2) · x - 4

Then, the resulting line has a slope of - 1 / 2.

Second, determine the intercept of the resulting line:

y = m · x + b

b = y - m · x

b = - 3 - (- 1 / 2) · (- 2)

b = - 3 - 1

b = - 4

The intercept of the resulting line is - 4.

Third, transform the equation of the resulting line into standard form:

y = - (1 / 2) · x - 4

- 2 · y = x + 8

x + 2 · y + 8 = 0

There is no parallel line for the point (x, y) = (- 2, 3).

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The dimensions of the box that minimize total cost are height h =3.17m, width, w and length, l=9.52m  are equal to  .

Let h is the height of the box.

Given Volume of the box is 216 m³  with no top.

And the cost of the bottom is 40USD/m².

For the sides, it is 30USD/m².

The bottom of the box is square, so l = w.

So Volume

[tex]V=hl^{2}[/tex]

[tex]216=hl^{2}[/tex]

[tex]h=\frac{216}{l^{2} }[/tex]

Now Surface Area of the box without a top is

S = 4hl + l²

So,

cost = 4 × 30hl +40l²

cost = 120 hl + 40 l²

Putting h ,

cost = 120 × [tex](\frac{216}{l^{2} })l + 40l^{2}[/tex]

cost = [tex]\frac{25960}{l^{2} }+40l^{2}[/tex]

To find minimum cost, derivate the  by using the calculator at

[tex]l=3\sqrt[3]{4}[/tex]

l=4.762203 m

[tex]h=\frac{216}{4.762203^{2} }[/tex]

h = 9.5244069354 m

Hence the dimensions of the box are

l=w

 =9.52 m

and height ,h=3.17 m  

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Answer:

The answer is B. y = -x + 7.5.

Step-by-step explanation:

The slope is -1 and the y-intercept is 7.5.

The required expression which is equivalent to -51 -(-60) is -51 + 60.

Given that,
Which expression is equivalent to -51 - (-60) is to be determined.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Given expression =  -51 - (-60)
Simplify by applying the property of distribution under the parenthesis,
= -51 + 60

Thus, The required expression which is equivalent to -51 -(-60) is -51 + 60.

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The equation of the line in fully simplified slope - intercept form is 5x + 4y = 12 .

In the question ,

a graph of the line is given , we need to find the equation of the given line in the simplified slope - intercept form .

to find the equation , we need minimum two points ,

So , from the given graph ,

we can find that

when x [tex]=[/tex] 0 , the value of y [tex]=[/tex] 3 ,

the first point is (0 [tex],[/tex] 3) .

when x [tex]=[/tex] 4 , the value of y [tex]=[/tex] -2 ,

the second point is (4 [tex],[/tex] -2) .

the slope can be calculated by

slope = (-2-3)/(4-0)

= -5/4

So , the equation of the line passing through point (4,-2) with slope -5/4 ,  in the slope intercept form is

(y -(-2)) = (-5/4)(x-4)

y + 2 = (-5/4)x + 5

y = (-5/4)x + 5 - 2

y = (-5/4)x + 3

Simplifying further , we get

4y = -5x + 12

5x + 4y = 12

Therefore , The equation  line in fully simplified slope - intercept form is 5x + 4y = 12 .

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Answer:

Step-by-step explanation:

A. Both triangles have two pairs of corresponding sides and a pair of included angles, therefore, ΔABC ≌ ΔABD by SAS.

B. ∠CBA ≌ ∠DBA by CPCTC.

The SAS congruence theorem state that if we have two triangles that we can show that they posses two pairs of corresponding sides that are equal and a pair of included angles that are also equal, then we can state that the two triangles are congruent to each other

When two triangles are proven to be congruent to each other, every corresponding parts of both triangles will be equal to each other based on CPCTC.

Part A:

We are given that AC ≌ AD, and ∠CAB ≌ ∠DAB.

Also, AB ≌ AB based on the reflexive property.

Therefore, both triangles are congruent to each other based on SAS.

ΔABC ≌ ΔABD

Part B:

Since both triangles are congruent, therefore ∠CBA ≌ ∠DBA by CPCTC.

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The probabilities will be 0.1081 , 0.676, 0.863, 0.605 respectively.

let us consider, the chances of getting stem be a success(S) and not getting it be a failure(F) , and the total probability be 1 .

as per the statement 26% students are major in stem

total students selected randomly are 36.

∴ P(S) = 0.26

P( F)  = 1 - 0.26 = 0.74

Now the binomial probability of success is given by

[tex]P(x) = C^{n} _{x} S^{x} F^{n-x}[/tex]

where C is for the combination formula

S is changes of success

F is chances of failure

x = no. of times success

n = total times the experiment done

From the provided information we can solve each case as follows :

A) exactly 7 of them major in stem

P(7) = [tex]C^{36} _{7} (0.26)^{7} (0.74)^{29}[/tex]

   = 0.1081

B)at most 10 of them major in stem

it means P(0,1,2...10)

∴ P = P(0) + P(1) +......+P(10)

P = 0.676

C) at least 7 of them major in stem.

it means P(7,8,9...36)

∴ P = P(7) + P(8) + ...+ P(36)

P = 0.863

D) between 9 and 15 (including 9 and 15) of them major in stem.

In this case we subtract P(0,1,2...8) from P(0,1,2,...15)

and get P(9,10,11,...15)

∴ P(9,10,11,...15) =  P(0,1,2,...15)  -   P(0,1,2...8)

                        =  0.987  -  0.382

                        = 0.605

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The y-intercept of f(x) = (1.6)x is (a) less than the y-intercept of the function in the graph

The equation of the function is given as

f(x) = (1.6)x

To determine the y-intercept, we set x = 0

So, we have

f(0) = 1.6 * 0

Evaluate

f(0) = 0

For the graph, we have

When x = 0, the function has a value of 1

This means that

y-intercept is 1

0 is less than 1

Hence, the y-intercept of f(x) = (1.6)x is (a) less

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Line a and line b are parallel to each other, and c is neither parallel nor perpendicular.

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

If a line passes through two points, then the slope of the line is

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Line a passes through (2, 10) and (4, 13).  So, the slope of this line is

[tex]m_{a}=\frac{13-10}{4-2}=\frac{3}{2}[/tex]

Line b passes through (4, 9) and (6, 12).  So, the slope of this line is

[tex]m_{b}=\frac{12-9}{6-4}=\frac{3}{2}[/tex]

Line c passes through (2, 10) and (4,9).  So, the slope of this line is

[tex]m_{c}=\frac{9-10}{4-2}=\frac{1}{2}[/tex]

The product of slopes of perpendicular lines is -1.

and if the slope of 2 lines is equal then those lines are parallel

so, line a and line b are parallel to each other, and c is neither parallel nor perpendicular.

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If they are competing for 1st, 2nd, and 3rd place ribbons. The number of different ways can the winners be chosen is:  B. 60.

Given data:

Number of people =5

Number of places = 1st, 2nd, and 3rd

Hence,

Different combinations =5 ×4×3

Different combinations = 60 ways

Therefore the winners will be chosen by  60 different possible ways ,

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The number of ways voters could rank their first 5 choices out of 10 is 30240.

Given,

Number of students sought the nomination for president of the student body = 10 students

We have to find the number of ways voters could rank their first 5 choices.

Permutation;

An arrangement of items in a specific order is referred to as a permutation. Here, the components of sets are arranged in a linear or sequential order.

Here we have to use permutation formula;-

ⁿPr = n! /  (n - r)!

Here,

n is the number of students = 10

r is the choices = 5

Then,

ⁿPr = n! /  (n - r)!

¹⁰P₅ = 10! / (10 - 5)!

¹⁰P₅ = 10! / 5!

¹⁰P₅ = 10 x 9 x 8 x 7 x 6

¹⁰P₅ = 30240

That is,

The number of ways voters could rank their first 5 choices out of 10 is 30240.

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Answer:

4.73

Step-by-step explanation:

10% is 10

so, you have to multiple 3×.10=.30

3-.30=2.70

2.70×.75 because 7.5% is .75

that is 2.0250 and then you have to add 2.0250 with 2.70 that is 4.7250 and if you round it. It is 4.73

Hope that works

Answer:

x=22

Step-by-step explanation:

Let the unknown number be x

:- the power of x = x³

From the question

x³-15=7 and x²

x³=7+15

x³ * x²= 22

x= 22

Answer:

x = -1

Step-by-step explanation:

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Answer:

-1

Step-by-step explanation:

Replace the variable x with 1 in the expression .

f(1)= 2(1) - 3

Remove the parenthasis

2(1) - 3

Multiply 2 by 1

2 - 3

subtract 2 from 3

-1

m ∠5 and m ∠7 is  72 ° . All straight angles are 180 degrees, according to the straight angle theorem. A straight angle is formed when the angle's legs point precisely in the opposite directions. The symbol for a straight angle is 180 degrees, or  π (in radians).

An angle is a shape created by two rays that share a terminus and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are in the plane where the rays are located. The meeting of two planes also creates angles. We refer to these as dihedral angles.

The names of basic angles are Acute angle, Obtuse angle, Right angle, Straight angle, reflex angle and full rotation. An angle is geometrical shape formed by joining two rays at their end-points. An angle is usually measured in degrees.

m ∠4 = 108°

m ∠5 = m ∠1

m ∠1 is in same line of m ∠4

So

m ∠1 = 180 - m ∠4

m ∠1 = 180 - 108

m ∠1 = 72 °

So m ∠5 = 72 °

m ∠7 is opposite to m ∠5 , opposite angles will be equal

Therefor m ∠7 = 72 °

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Answer: Stacy is 12 years old

Step-by-step explanation:

36/4 = 12

The absolute equation in the graph is f(x) = |x - 3| + 5

From the question, we can see that the lines on the graph has a sharp v-shape

Graphs that have this form are absolute value graphs

The general form of an absolute value equation is expressed as

y = |x - h| + k

From the above form, we have

Vertex = (h, k)

By definition, the vertex of a function is either the maximum point or the minimum point

On the given graph, the minimum point is (3, 5)

So, we have the following representation

(h, k) = (3, 5)

Substitute (h, k) = (3, 5) in the above equation

So, we have:

y = |x - 3| + 5

Hence, the function represented by the graph has an equation of f(x) = |x - 3| + 5

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Answer:

9/16

Step-by-step explanation:

The number of batches of muffins Ms. Kirkland can bake with 7 ½ pounds of flour is 5 batches.

Given that, Ms. Kirkland is baking muffins. Each batch of muffins uses 1 ½ pounds of flour.

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Here, [tex]1\frac{1}{2} = \frac{3}{2}[/tex] and [tex]7\frac{1}{2} = \frac{15}{2}[/tex]

The number of batches of muffins can she bake

= 15/2 ÷ 3/2

= 15/2 × 2/3

= 5 batches

Hence, the number of batches of muffins Ms. Kirkland can bake with 7 ½ pounds of flour is 5 batches.

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Answer: The answer is 5

Step-by-step explanation: I have my ways ;>

The value of function is positive so the function have maximum value 30 at x=3.

In the given question we have to find the maximum or the minimum value of a function.

The given function is

f(x) = -3x^2+18x+3

To find the maximum or minimum value we firstly find the value of f'(x).

f'(x) = -6x+18

Now put f'(x)=0

-6x+18=0

Subtract 18 on both side we get

-6x=-18

Divide by -6 on both side we get

x = 3

Now finding the value of function at x=3

f(3)= -3*(3)^2+18*3+3

f(3)= -3*9+54+3

f(3)= -27+54+3

f(3)= 30

Since the value of function is positive so the function have maximum value 30 at x=3.

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The type of bias that can be present in stratified sampling is that the students cannot be selected to accurately reflect the population.

Samples may be classified according to the five options as follows:

In this problem, an equal amount of students from each class was surveyed, hence a stratified sample was used.

The type of bias present in stratified sampling is that the students cannot be selected to accurately reflect the population.

The problem asks for which type of bias is present in this sample.

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The probability that the sum of the numbers rolled on the dice is even =1/2.

For the given question,

A fair dice is rolled twice.

Six different results are available with a single roll of the dice (1,2,3,4,5,6)

Therefore, if two dice are rolled, there are a total of 36 possible results, or 6².

Sample space for the sum of even = [(1,1), (1,3), (1,5), (2,2), (2, 4),(2,6), (3, 1), (3,3),(3,5),(4,2),(4,4),(4,6), (5, 1), (5,3),(5,5),(6,2),(6,4),(6,6)]

Total sample space for sum of even = 18

For the probability that the sum of the numbers rolled is even is -

probability (sum is even) = 18 / 36 = 1/2

Thus, the probability that the sum of the numbers rolled is even is 1/2.

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Option A: Multiply the top equation by 3, multiply the bottom equation by -2, then add the equations will eliminate the variables.

Rewriting the equation -

2x + 8y = -3 : Equation 1

3x + 6y = -4 : Equation 2

Multiplying equation 1 with and equation 2 with -2.

6x + 24y = -9 : Equation 3

-6x - 12y = 24 : Equation 4

Adding the equation 3 and equation 4. This will eliminate the variable x.

12y = 15

y = 5/4

So, option 1 will eliminate the variable x on solving we get the value of y as 5/4.

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If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

acc to our question-,

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Answer:

A base

Step-by-step explanation:

its not an acid bc a ph level of 14 means is has a strong base.

Answer:

324 ft

Step-by-step explanation:

[tex]v=\sqrt{2gh}[/tex]

[tex]v^2=(\sqrt{2gh})^2[/tex]

[tex]v^2=2gh[/tex]

[tex]\frac{v^2}{2g}=\frac{2gh}{2g}[/tex]

[tex]\frac{v^2}{2g}=h[/tex]

[tex]\frac{144^2}{2(32)}=h[/tex]

[tex]\frac{20736}{64}=h[/tex]

[tex]324=h[/tex]

8.77 ft/sec  is the tip of her shadow moving with a speed of 6 ft/sec .

What is speed, for instance?

Let H = the height of the pole.

h = the height of the woman.

x = the length of the woman's shadow.

s = the distance from the pole to the woman.

By similar triangles,  H/h = (s + x)/x  or  Hx = h(s + x).

Differentiating, H dx/dt = h(ds/dt + dx/dt)

19 dx/dt = 6(6 + dx/dt) = 36 + 6 dx/dt

13 dx/dt = 36

dx/dt = 36/13 ft/sec = 2.77 ft/sec for how fast her shadow is lengthening.

The speed of the tip of her shadow would be this speed added to her traveling speed: 2.77 + 6 = 8.77 ft/sec.

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