Fusion of helium nuclei to form carbon and oxygen in the core of a star after the start of helium nuclear reactions in its core compared.
The positions of the stars in relation to one another are largely constant. Orion and Taurus are constantly converging. Draco is always near Ursa Minor. When we look at the sky, the stars are a never-ending backdrop painting that barely move in relation to one another.
There are some minute movements as we orbit the sun throughout the year. Stars closer to us move more left and right than stars farther away. It makes sense, even if it only has a small impact. If you keep your eyes fixed out into the distance as you walk down the street, you'll notice that objects farther away move less in relation to you than ones closer to you.
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in addition to friction and the pressure-gradient force, which other force is influential in the control of wind on earth?
In addition to friction and the pressure-gradient force, the other force which is influential in the control of wind on earth is Coriolis force.
What is Coriolis force?
The wind's direction is influenced by how the earth rotates on its axis. The Coriolis force is what is known as. It significantly affects the wind's direction of movement.
The pressure gradient force causes winds to cross isobars at right angles, however because of the rotation of the planet, winds are diverted from their intended course.The Coriolis effect, often known as the Coriolis force, is a deviation caused by the rotation of the earth.
As a result, according to Farrell's Law, winds in the northern hemisphere are diverted to the right of their route, whereas those in the southern hemisphere are diverted to the left. The air does not appear to have a deflection force until it is moved, and it grows with wind speed, air mass, and latitude.
In low-pressure locations, the wind blows around it because the Coriolis force and the pressure gradient force operate in opposition to one another. The pressure gradient force is perpendicular to an isobar (cyclonic conditions).
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the motor of an elevator puts out 1,104 w of power. what is the mass of the elevator in kg if it lifts 135 m in 65 s at a constant speed? assume g
The mass of the elevator in Kilograms is 54.24 Kg.
The power applied by the elevator on the mass is 1104 W.
The height to which the mass is taken is 135m in the time period of 65 seconds.
We know,
Power applied is equal to the work done per unit time,
So,
P = MgH/t
Where, P, M, g, H and t are Power, mass, acceleration due to gravity, height and time respectively.
Now, putting values,
1104 = M x 9.8 x 135 / 65
M = 54.24 Kg.
So, the mass of the elevator is 54.24 kg.
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Determine the moment of inertia of the assembly about an axis perpendicular to the page and passing through point O. The block has a mass of 3 kg. and the semicylinder has a mass of 5 kg.
The moment of inertia of the assembly about the axis perpendicular to the page and passing through point O is 0.285 kg/m².
The dimensions of the block are 300mm x 400mm, the radius of the semi cylinder is 200mm.
The mass of the block is 3 kg and the semi cylinder has a mass of 5 kg.
The Moment of inertia of the block around the axis passing through the point O and perpendicular to the plane of the paper is given by,
I = M/12(L²+B²)
I₁ = M/12((0.3)²+(0.4)²)
I₁ = M/12
I₁ = 0.06 kg/m²
Now, the moment inertia of the semi cylinder around the point O is,
I₂ = M/2(R)²
I₂ = 5/2(0.3)²
I₂ = 0.225 kg/m².
The moment of inertia of the whole assembly around the axis perpendicular to the page and passing through point O.
I = I₁ + I₂
I = 0.06+0.225
I = 0.285 kg/m².
The moment of inertia of the assembly is 0.285 kg/m².
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a 10 g bullet is fired at 400 m/s into a 10 kg wood block and becomes embedded. a. if the block sits on a frictionless surface, what is the velocity of bullet block? b. if instead the block sits on a wooden table with coefficient of friction
When a particle of mass m moves at speed v, its linear momentum is defined as... In a block of wood (m = 5.00 kg), a 10.0g bullet comes to a stop.
What is the speed of the bullet plus block right when it hits the ground?The projectile penetrates the block. Following the collision, the bullet and wood combination is moving at a speed of 0.600 m/s.
Does the bullet's change in momentum match that of the block of wood?The momentum of the block with the bullet after the hit will be equal to the momentum of the block with the bullet before the hit, per the law of conservation of linear momentum.
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The figure below shows a constant magnetic field in a circular region which is pointing out of the page and increasing in magnitude at a constant rate. The magnetic field vanishes outside of the circular region. Two closed loops appear in the figure, one entirely outside the circular region (but not encircling it), and another entirely inside the circular region. Which of the following statements concerning the two loops false? Neither of the two loops experiences a net force. Only the interior loop experiences forces which tend to crush it. Both of the loops have currents running clockwise around them. Both of the two loops experience induced electric fields.
The correct answer is c that is both of the loops have currents running clockwise around them.
Since loop inside the region has an increasing magnetic field so it has clockwise current but the loop outside the magnetic region doesnt have current.
Powering lamps or other electrical devices always involves creating a loop in which electrical current flows. A circuit is made up of various parts that are wired together.
The battery or another power source moves the circuit's current. In a current loop, a dc power source is used to supply the current signal, which then travels through the transmitter, controller, and back to the power supply in a series circuit.
It was decided at random that the current would pass from the positive terminal to the negative terminal. However, when electrons were later discovered, it was revealed that they had a negative charge attached to them. Consequently, the direction of electron flow is the opposite of the direction of flow of conventional current.
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when the temperature of an ideal gas is increased, which of the following also increases? select all that apply. the number of gas atoms the thermal energy of the gas the average potential energy of the gas atoms the mass of the gas atoms the average kinetic energy of the gas atoms
Gas particles travel more quickly and clash more frequently and more violently as temperature rises. When a container is hard, it cannot expand, increasing pressure.
The kinetic energy of a substance's molecules increases as its temperature is raised through heating.
As a result, pressure rises if temperature is raised while remaining constant.
Boyle's Law: The Relationship Between Pressure and Volume. Because the gas particles are compressed closer together as the pressure on a gas increases, the volume of the gas decreases. As a result of the gas particles' newfound freedom to move farther apart, the volume of the gas rises as the pressure on it falls.
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What type of wave is a light wave?.
Light wave is a type of Transverse wave
What kind of wave is light ?All electromagnetic waves, including light, are transverse waves because they vibrate energy perpendicular to the wave's direction of travel. In a gas or a liquid, transverse waves cannot travel because there is no mechanism for generating motion perpendicular to the wave's direction of propagation.
A medium is not needed for the propagation of a light wave. It is therefore a non-mechanical wave. A light wave's electric and magnetic fields oscillate in a direction opposite to the direction in which the wave is traveling. This makes it a transverse wave.
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A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diagonal, and stick. What is the turntable's angular speed, in rpm, just after this event?
The turntable's angular speed, in rpm, just after this event is 50rpm (using moment of inertia calculation).
It is defined as the tendency of an object to remain in a state of rest or of a constant rotational velocity. Greater the moment of inertia, more torque is required to change this state. Torque in rotational motion plays the same role as force in linear motion.
What is the turntable's angular speed (in rpm) just after this event?
Moment of inertia of the turntable is
I₁ = (M*R²) / 2
= ( 2kg) * (0.2m / 2)² / 2
= 0.01 kg.m²
W₁ = 100 rpm
Moment of inertia when two blocks stick,
I₂ = I₁ + 2m*r²
= 0.01 + 2*(0.5kg)*(0.1m)²
= 0.02
from conservation of angular momentum
L₁ = L₂
I₁ * W₁ = I₂ * W₂
0.01 * 100rpm = 0.02*W₂
W₂ = 50rpm
Therefore, the turntable's angular speed is 50rpm based from the calculation above.
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can hubbles law be used to determine the distance of a centauri star and other stars relatively near the sun
The right response is D because one can use Hubble's law to calculate how far a galaxy cluster is from its nearby neighbors.
What Hubble's law ?According to Hubble's law, the speed at which various galaxies are moving away from us is proportional to how far away they are from the Earth. This observation in physical cosmology. Edwin Hubble, an American astronomer, was the one who drafted the law.
He found that the distance between galaxies and our planet affects how quickly they move away from us. It is the first observable evidence of the universe's expansion and is frequently used as a partial justification for the Big Bang theory.
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lift can be described as the difference in elevation between the surface of the static water supply and the:
The static lift, which only exists when the pump is not in use, is the vertical distance between the pump's Centre line and the elevation of the water source. the pump's elevation is lower than the water elevation,
There is a positive static lift. The static lift is negative if the pump is situated below the water's surface level. The term "vertical position," "vertical location," or "level" refers to a position along a vertical axis that is above or below a specific vertical datum (reference level).
The vertical distance between pressures is constant, and this is the static lift. However, certain systems could have a variable operating pressure that depends on the height of the system and the pump's Centre line.
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what is the magnitude of the average force of air resistance? express your answer with the appropriate units tennis
Calculating air resistance involves adding up the drag coefficient, area, and air density, then multiplying by velocity squared.
What factors determine the strength of the air resistance?The object's shape, area, and speed as it travels through the air all affect air resistance. The resistance of the air is affected by altitude, temperature, and humidity changes in air density. The resistance increases with increasing speed and area.
How much force does friction typically exert?Perpendicular to the slope, the net force component must be zero. The perpendicular gravitational force must be cancelled by the normal force. As a result, n = mg cos, where mg is the normal force.
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select the income elasticity that corresponds to a normal good. income elasticity is positive and less than 1. income elasticity is -1. income elasticity is negative and less than -1. income elasticity is zero.
A normal good has an Income Elasticity > 0
What is Income Elasticity ?A measure of the economic responsiveness of the quantity of an item or service demanded to a change in income is called income elasticity of demand. The percentage change in quantity demanded divided by the percentage change in income is the formula for determining the income elasticity of demand.
The income elasticity of demand is categorised into three groups based on numerical value as follows:
Demand elasticity of income that is favorable
demand elasticity of income that is negative
There is no demand elasticity of income.
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The income elasticity of demand measures how sensitive the quantity demanded of a good is to changes in income. It helps us understand whether a good is a normal good, inferior good, or luxury good.
To calculate the income elasticity of demand, we can use the following formula:
Income Elasticity of Demand = (Percentage change in quantity demanded) / (Percentage change in income)
In this case, the percentage change in income is given as 23 percent, and the percentage change in consumption of farm goods is 0.4 percent.
Using the formula, we can calculate the income elasticity of demand for farm goods:
Income Elasticity of Demand = (0.4 percent) / (23 percent)
Simplifying this expression, we have:
Income Elasticity of Demand = 0.4 / 23
This yields a value of approximately 0.017, or 0.017%.
Since the income elasticity of demand is a positive but small value (less than 1), we can conclude that farm goods are a necessity or a normal good. This means that as consumers' incomes increase, the quantity demanded of farm goods increases, but at a relatively smaller rate compared to the income change.
It's important to note that the income elasticity of demand can also be negative. A negative value would indicate that the good is an inferior good, meaning that as consumers' incomes increase, the quantity demanded of the good decreases. However, in this case, the income elasticity of demand is positive, indicating that farm goods are a normal good.
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you change the distance to a sound source from 1 m to 10 m. by how much does the intensity level change in decibel (db)?
If you change the distance to a sound source from 1 m to 10 m the intensity level change in decibel (db) is 20 dB.
What is sound attenuation and how do you calculate it?
The intensity of sound decreases with distance when it passes through a medium. Two fundamental factors, scattering and absorption, are responsible for this wave's energy depletion. Attenuation refers to the outcome of both scattering and absorption combined.The decibel scale is used to gauge the strength of attenuation. An intensity of 1*10-12 W/m2 is equivalent to a sound level of 0 decibels (abbreviated as 0 dB), which is the threshold of hearing.The formula to calculate sound attenuation over distance for a point source is:
L(r2) = L(r1) - 20·Log10(r2/r1)
Where:
L(r1) = Known sound pressure level at the first location (typically measured data or equipment vendor data)
L(r2) = Unknown sound pressure level at the second location Location
r1 = Distance from the noise source to location of known sound pressure level
r2 = Distance from noise source to the second location
According to the given informations,
the initial distance,r1 = 1m
the final distance, r2 = 10m
Putting the values in the above equations, we have,
L2 = L1 −10log (r2/ r1)^2
L1 - L2 = 10log (r2/ r1)^2
= 10log (10/1)^2
= 10log 10^2
= 2 x 10log10
= 20 dB
Hence, the intensity level change in decibel (db) is 20 dB.
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You are standing on an airless celestial body, one that is large enough to be approximately spherical. You have a cannon that you can adjust to launch a cannon ball at any speed you specify. Which of the following statements are true? Hint: There are 2 correct statements.
If you give it enough speed and aim it parallel to the ground the ball will go into a circular orbit. (Watch out, it may hit you in the back.)
If you launch the ball at low speed, it will move along an eccentric ellipse with the center of the body at one focus and most of the orbit underground.
If you give it enough speed and aim it parallel to the ground the ball will go into a circular orbit and provides angular acceleration is correct statement.
Angular acceleration is the rate of change of angular velocity over time. Radians per second is a frequently used measuring unit. Angular acceleration, also referred to as rotational acceleration, occurs when a body rotates. One can use a quantitative vector to express the change in angular velocity per unit of time.
An acceleration that is at an angle is a pseudo scalar. Positive angular acceleration is a rise in clockwise angular speed, whereas negative angular acceleration is a rise in counterclockwise angular speed. The acceleration vector is parallel to the plane of rotation since it is perpendicular to it. By increasing angular velocity clockwise, one can produce acceleration velocity that points away from the observer.
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How was radiogenic heat generated?.
The radioactive decay of elements within the Earth's mantle and crust outcomes in the production of daughter isotopes and the launch of geoneutrinos and warmth power, or radiogenic heat.
Sure elements, referred to as radioactive factors along with potassium, uranium, and thorium, damage down via a process known as radioactive decay, and release energy. This radioactive decay in Earth's crust and mantle constantly adds heat and slows the cooling of the Earth.
Radiogenic heating The thermal electricity released due to spontaneous nuclear disintegrations. in the Earth, the major isotopes concerned these days are of the factors uranium, thorium, and potassium, but diverse short-lived isotopes might also have been essential at some point in the early formation of the Earth.
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A following interval of _____ seconds provides time to steer out of problem areas on dry surfaces at speeds under 70 mph.
A interval of 7 seconds provides time to steer out of problem areas on dry surfaces at speeds under 70 mph.
In the SEEiT system helps to reduce driving risks. When the driver searches for new areas, he should look for open, curved and changing areas. The driver needs to adjust according to the new changes by measuring the intervals of seconds as steering around the risk can be done is lesser time than braking and the distance of steering < distance of stopping.
Thus, according to this system, a two second interval provides time to steer out of problem areas on dry surface at speeds under 35 mph, three second interval provides time to steer out of problem areas on dry surface at speeds under 45 mph and so on.
7 second interval provides time to steer out of problem areas on dry surface at speeds under 65-70 mph.
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a nozzle with an area of 0.3 cm2 is attached to a garden hose with an area of 1.8 cm2. the flow rate through the nozzle is 0.18 l/s.
A nozzle with an area of 0.3 cm² is attached to a garden hose with an area of 1.8 cm². The flow rate through the nozzle is 0.18 l/s and the flow rate through the garden hose is 0.108* 10⁻³m³/s.
We know that the equation of continuity as Q = A*v
From the above equation, the relation between flow rate and area can be written as Q₁A₂ = Q₂A₁
Given that, flow rate of the nozzle Q₁ = 0.18 l/s = 0.18*10⁻³ m³/s
flow rate of the garden hose Q₂ = ?
area of the nozzle A₁ = 0.3 cm² = 0.3*10⁻⁴ m²
area of the garden hose A₂ = 1.8 cm² = 1.8* 10⁻⁴ m²
Substitute the values in the above equation,
0.18* 10⁻⁴* 0.18*10⁻³ = 0.3*10⁻⁴* Q₂
0.18* 0.18* 10⁻³ = 0.3*Q₂
Q₂ = 0.108* 10⁻³m³/s
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Two weights are connected by a massless wire and pulled upward with a constant speed of 1.50 m/s by a vertical pull P. The tension in the wire is T.
In Above:
T = P
P = T + 25 N
P = T + 100 N
T > P
P + T = 125 N
P is closest to:
245 N
125 N
1225 N
25 N
187.5 N
T is closest to:
980 N
100 N
125 N
150 N
75 N
If two weights are connected by a massless wire and pulled upward with a constant speed of 1.50 m/s by a vertical pull P and a tension in the wire is given by P = T + 25 N
For an object moving with constant speed,
a = 0
For 25 N object,
F = P - T - W
F = Net force
P = Pulling force
T = Tension force
W = Weight
W = 25 N
F = P - T - W
m a = P - T - 25 N
0 + 25 = P - T
P = T + 25 N
For 100 N object,
W = 100 N
F = T - W
0 = T - 100
T = 100 N
P = T + 25 N
P = 100 + 25
P = 125 N
Therefore,
P = T + 25 NP is closest to 125 NT is closest to 100 NThe given question is incomplete. The complete question is:
Two weights are connected by a massless wire and pulled upward with a constant speed of 1.50 m/s by a vertical pull P. The tension in the wire is T. The weights are shown in the image attached.
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How does dark matter affect the development of structures in the early universe?.
The development of structures in the early universe seeded the development of galaxies.
The growth of primordial fluctuations of hot and cold dark matter gives rise to two distinct distributions of cosmic structure. In a model of hot dark matter, the heaviest structures form first and then split into smaller structures.
Dark matter is thought to have played a role in the formation of galaxies. The galaxy's mass provided most of the gravitational pull necessary to form clouds and larger structures in protogalaxies. The energy of the Big Bang caused the initial expansion of the universe. Since then, gravity and dark energy have played a cosmic tug of war. Gravity pulls galaxies together. Dark energy pulls them apart.
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The time to assemble a certain type of a computer board from a certain assembly line, has a normal distribution. The assembly times for a random sample of 20 boards are measured. The sample mean and sample standard deviation of observed times are: X &=35 minutes and s=2.2 minutes. a. Find a 90% confidence interval for the true average assembly time for a board. b. Find a 90% confidence interval for the true variance of assembly time F2. c. Find a 90% confidence interval for the true standard deviation of assembly time F.
The 90% confidence interval for the true average assembly time for a board is (34.19 minutes, 35.81 minutes).
What is average?
The ratio of a sum of the values in a given set to all the values in the set is the mean value, which is the definition of the average. The average formula has numerous practical uses. If we were asked to determine the average male height throughout India or the average age of the men and women in a group, we would add up all the data and divide it by the total number of data points. In mathematics, the central value of the a set of data is expressed as the average of a list of data.
A) The 90% confidence interval for the true average assembly time for a board is (34.19 minutes, 35.81 minutes).
B) The 90% confidence interval for the true variance of assembly time is (3.42 minutes, 7.06 minutes).
C) The 90% confidence interval for the true standard deviation of assembly time is (1.84 minutes, 2.65 minutes).
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A heavy dart and a light dart are launched vertically by identical ideal springs. Both springs were initially compressed by the same amount. There is no significant air resistance. Which of the following statements about these darts are correct? (There could be more than one correct choice.)
the light dart goes higher than the heavy dart
at maximum height, both darts have the same gravitational potential energy
The correct statement is that the light dart goes higher than the heavy dart when both are thrown vertically by identical ideal springs initially compressed by the same amount.
ReasoningWhen the same force is applied to bodies with different masses, different accelerations are achieved.
The force is directly proportional to the acceleration experienced by the body, and the constant of proportionality of the body used corresponds to its mass.
According to the formulaF = m. a
In a situation where there is no significant air resistance when a given force is applied to a body of mass m, the force is directly proportional to the acceleration experienced by the body, and the body's constant of proportionality used corresponds to its mass.
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determine by direct integration the moment of inertia of the shaded area with respective to the y axis. (20 points)
The moment of inertia of the shaded area respective to the y-axis is [tex]\frac{a^{3}b }{6}[/tex]
We need to calculate n the moment of inertia of the shaded area respective to the y-axis, that is, [tex]I_{y}[/tex]
The equations of the given curves,
[tex]y = kx^{3}[/tex] equation(1)
and [tex]b = ax^{3}[/tex]
So, we have,
[tex]b = ax^{3}[/tex]
[tex]k =\frac{b}{a^{3} }[/tex]
Putting this in equation (1), we get :
[tex]dI_{y} =x^{2} dA\\\\dI_{y} =x^{2} (ydx)\\\\I_{y} =\int\ {}\, dI_{y}[/tex]
[tex]I_{y} = \frac{b}{a^{3} }\int\limits^a_0 {x^{2}x^{3} } \, dx \\\\I_{y} = \frac{b}{a^{3} }\int\limits^a_0 {x^{5} } \, dx \\\\I_{y} = \frac{a^{3} b}{6}[/tex]
Thus, the moment of inertia of the shaded area respective to the y-axis is [tex]\frac{a^{3}b }{6}[/tex]
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the solid rod is subjected to the loading shown. determine the state of stress at point a, and show the results on a differential volume element located at this point.
A body's intrinsic ability to fend off the consequences of an external load is known as stress.
Find the stress levels at points B and C, and then display the findings on a differential volume element?A body's intrinsic ability to fend off the consequences of an external load is known as stress.The ratio of the applied force to the cross-sectional area is used to compute the normal stress, which acts perpendicular to the body's cross-sectional area.Rz=20kN is the standard reaction in the z-direction.Equation R x = describes the typical reaction in the x-direction.The formula for calculating normal stress is as follows:σ = F/AAxial and tangential stress are the two different forms. The only dimension (the radius, not the length) that is provided indicates that axial stress may be present. The area is therefore A = r2 =. (0.75 in) ² = 1.767 in².The result is that = F/A = 500 lb/1.767 in2 = 282.94 psi.
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the first law of thermodynamics for a closed system can be characterized in words as a. (change in energy in a system)
first law of thermodynamics for a closed system can be characterized in words as a change in energy in a system zero.
what is first law of thermodynamics?The first law of thermodynamics, also known as the law of conservation of energy, states that energy can neither be created nor destroyed, but it can be changed from one form to another. According to this law, some heat given to the system is used to change the internal energy while the rest is used in doing work by the system.
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system , plus the net work done on the system .
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A particle of mass 4m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with speed v each in mutually perpendicular directions. The total energy released in the process of the explosion is-(A) 23mv2(B) 32mv2(C) 43mv2(D) 34mv2
The correct answer is option B.
Total Energy is the total final energy consumption at a specific variable. Total energy is distinguishable from Final Energy Intensity by the fact that energy data is entered directly.
The total energy of a system is the sum of kinetic and gravitational potential energy.
This total energy is conserved in orbital motion.
We are given that the mass of the big particle is 4m and velocity of two fragments are mutually perpendicular to each other.
If p₁ and p₂ are the momentum of the fragments
Then momentum of third fragment is p₃=
p₃ = √[(p₁²+p₂²)] = √[(mv)²+(mv)²] = √2mv
Velocity of third fragment = v /√2
Total energy released in the explosion
= 1/2 mv² +1/2 mv² + 1/2*2m(v/√2)²
= 3/2 mv²
Therefore, the total energy released by particle having mass 4m is 3/2 mv².
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Compared to their values on Earth, on another planet your
mass would be the same but your weight would be different.
Compared to their values on Earth, on another planet your mass would be the same but your weight would be different due to the force of gravity.
W = m g
W = Weight
m = Mass
g = Acceleration due to gravity
Mass is the quantity of amount of substance present in a body. It does not depend on any outside factors. So its value is not altered by any external factors.
W ∝ g
As you can see that weight changes based on the value of g acting on the body. Weight can also be called as force of gravity. The value of g in earth is different than the value of g in other planets.
Therefore, compared to their values on Earth, on another planet your mass would be the same but your weight would be different due to the force of gravity.
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The acceleration of an object is ____________ related to the mass of the object.
Answer:
Inversely
Explanation:
According to Newton's Second Law, force is equal to mass times acceleration (F=ma). Rewriting this equation as an expression for acceleration, we have a=F([tex]\frac{1}{m}[/tex]). This shows a∝[tex]\frac{1}{m}[/tex], or acceleration is proportional to the inverse of mass.
a 12v battery output is divided down to obtain two output voltages. three 3.3k resistors are used to provide the two taps. determine the output voltages. if a 10k load is connected to the higher of the two outputs
The output voltages are V₁ = 8 voltages and V₂ = 4 voltages. If a 10k load is connected to the higher of the two outputs then the loaded value is 6.55 voltages.
What is Kirchoff's Current Law?Kirchoff's Current Law or KCL states that the algebraic sum of all currents entering and leaving a node must be equal to zero. This law is used to explain how a charge travels to and from a wire junction or node.
Let the two output voltages be V₁ and V₂ respectively.
By applying Kirchoff's Current Law (KCL) at V₁ node,
(Assuming all currents flowing in the outward direction from node)
Here, V = Volts
[tex]\frac{ V_{1} - 12}{3.3K}[/tex] [tex]+ \frac{V_{1} }{6.6K} = 0[/tex]
[tex]\frac{V_{1} }{3.3K} - \frac{12}{3.3K} + \frac{V_{1} }{6.6K} = 0[/tex]
[tex]\frac{V_{1} }{3.3K} + \frac{V_{1} }{6.6K} = \frac{12}{3.3K}[/tex]
[tex]\frac{V_{1} }{K} (\frac{1}{3.3} + \frac{1}{6.6} )= \frac{12}{3.3K}[/tex]
[tex]V_{1} (\frac{3}{6.6} )= \frac{12}{3.3}[/tex]
[tex]V_{1}= \frac{12*6.6}{3.3*3} = 8[/tex]
By applying KCL at V₂ node,
[tex]\frac{ V_{2} - 12}{6.6K}+ \frac{V_{2} }{3.3K} = 0[/tex]
[tex]\frac{V_{2} }{6.6K} - \frac{12}{6.6K} + \frac{V_{2} }{3.3K} = 0[/tex]
[tex]\frac{V_{2} }{6.6K} + \frac{V_{2} }{3.3K} = \frac{12}{6.6K}[/tex]
[tex]\frac{V_{2} }{K} (\frac{1}{6.6} + \frac{1}{3.3} )= \frac{12}{6.6K}[/tex]
[tex]V_{2}= \frac{12*6.6}{3*6.6} = 4[/tex]
By applying KCL at V node,
[tex]\frac{V-12}{3.3K} + \frac{V}{6.6K} + \frac{V }{10K} = 0[/tex]
[tex]\frac{V}{3.3K}-\frac{12}{3.3K} + \frac{V}{6.6K} + \frac{V }{10K} = 0[/tex]
[tex]\frac{V}{3.3K}+ \frac{V}{6.6K} + \frac{V }{10K} = \frac{12}{3.3K}[/tex]
[tex]\frac{V}{K}( \frac{1}{3.3}+ \frac{1}{6.6} + \frac{1}{10}) = \frac{12}{3.3K}[/tex]
[tex]V (\frac{18.3}{33} )= \frac{12}{3.3}[/tex]
[tex]V=\frac{12*33}{18.3*3.3} = 6.55[/tex]
Hence, the loaded value is 6.55 V.
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a cylinder measuring 4.7 cm wide and 5.7 cm high is filled with gas. the piston is pushed down with a steady force measured to be .
When a piston is depressed, the steady force is 15 N.
How does balancing force work?Forces that are equal in size and opposing in direction are said to be balanced forces. Equilibrium is regarded as a state of balanced forces. There is no change in direction when the forces are in balance. Balanced combined forces are always equal to zero.
Unbalanced force: What is it?Unbalanced forces are those in which the force acting in one direction is greater than the force acting in the other. A change in speed and/or direction occurs when an object is being affected by unbalanced forces.
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What are 4 types of waves?.
The various types of electromagnetic waves are as follows: Radio waves, X-rays, microwaves, and ultraviolet rays.
A wave is a dynamic disturbance that propagates and causes one or more quantities to depart from equilibrium. Quantities may oscillate regularly around an equilibrium (resting) value at certain frequency if a wave is periodic.
A travelling wave is one in which the entire waveform moves in one direction; in contrast, a standing wave is one in which two periodic waves are overlaid and move in the opposing directions. In a standing wave, there are some points where the wave amplitude seems reduced or even zero, and these positions have null vibration amplitudes.
A wave equation (standing wave field comprising two opposing waves) or a one-way wave equation (for single wave propagation in a certain direction) is frequently used to describe waves.
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