what is metallic conductivity ?

The solutions having osmotic pressure less than those of body fluids are called as hypoosmotic , therefore option C is correct.

Osmotic pressure is defined as the pressure that would be required to stop water from diffusing through a barrier by osmosis.

It is essentially a colligative feature that completely depends on the solute particle concentration in the solution.

Higher concentrations and higher temperatures increase osmotic pressure.

Osmotic pressure can be calculated using the following equation:

Π = MRT

where,

Π=osmotic pressure

M=Molar concentration of solution

R=Real gas constant

T=Temperature in Kelvin

Solutions having osmotic pressure  less than those of body fluids are called as hypoosmotic solutions ,hence option C is correct.

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When comparing the titration curves for the titration of a strong acid with a strong base and the titration of a weak acid with a strong base, pH increases when we reach the equivalent point.

Initially the pH rises little by little. This is because the scale of the pH increases is logarithmic. Then it rises sharply near the equivalent point. At this point the remaining hydronium ions are low, and only a small amount of hydroxide ion is needed to raise the pH.

Weak acid has low pH but second point is firstly the pH rises faster but less quickly when approaching the equivalent point.

The pH produced by titration of weak acid with strong base rises faster at first but less quickly when approaching the equivalent point.

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Pyruvate substance is a product of glycolysis, a precursor of gluconeogenesis and a precursor of the citric acid cycle

A crucial node in the network of metabolic pathways is pyruvate. Pyruvate can be transformed into ethanol, the amino acid alanine, fatty acids or energy through acetyl-CoA, carbohydrates through gluconeogenesis, and fatty acids or energy. As a result, it combines numerous important metabolic activities.

Pyruvate's main job is to carry carbon atoms into the mitochondrion where they are fully oxidized into carbon dioxide.

The final byproduct of glycolysis, pyruvate, is crucial to cell metabolism. It is made in the cytosol and then oxidized in the mitochondria, where it activates oxidative phosphorylation and feeds the citric acid cycle.

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Yes, because magnets strongly deflect beta radiation, you wouldn't have been affected.

Guidelines for conduct in the science lab

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Answer:

(1/0)n

See attached explanation.

The pair of reactants which will undergo aldol condensation to produce methyl vinyl ketone is formaldehyde and acetone.

It occurs only with aldehydes but only those aldehydes which are having alpha hydrogen within them because when two different forms of aldehydes react the elimination of waters molecule occurs which needs one alpha hydrogen within it.

CH₂O + CH3COCH3 will give methyl vinyl ketone elimination of water molecule has to be done.

Therefore, the pair of reactants which will undergo aldol condensation

to produce methyl vinyl ketone are formaldehyde and acetone.

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4Na + O₂ → 2Na₂O is balanced equation.

Hence, Option (B) is correct answer.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now check all the options one by one:

Option (A): 2H₂ + O₂ → 4H₂O

Reactant Side               Product Side

H = 4                               H = 8

O = 2                               O = 4

Here number of atoms of H on the reactant side is 4 and number of atom on product side is 8. H atoms are not balanced in this equation. Hence the given equation is not balanced.

Option (B): 4Na + O₂ → 2Na₂O

Reactant Side               Product Side

Na = 4                            Na = 4

O = 2                              O = 2

Here all the atom on reactant side and product side are equal. Hence the given equation is balanced.

Option (C):  Fe₂O₃ + H₂ → 2Fe + 3H₂O

Reactant Side               Product Side

Fe = 2                              Fe = 2

O = 3                                O = 3

H = 2                                H = 6

Here number of atoms of H on the reactant side is 2 and number of atom on product side is 6. H atoms are not balanced in this equation. Hence the given equation is not balanced.

Option (D): CH₄ + O₂ → CO₂ + H₂O

Reactant Side               Product Side

C = 1                                C = 1

H = 4                               H = 2

O = 2                               O = 3

Here H atoms on the reactant and product side is not equal and O atoms are also not equal on the reactant side and product side. Hence, the given equation is not balanced.

Thus from the above conclusion we can say that The balanced equation from the given options is 4Na + O₂ → 2Na₂O

Hence, Option (B) is correct answer.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Which of the following equations is balanced?

(A) 2H₂ + O₂ → 4H₂O

(B) 4Na + O₂ → 2Na₂O

(C) Fe₂O₃ + H₂ → 2Fe + 3H₂O

(D) CH₄ + O₂ → CO₂ + H₂O

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As filtrate moves down the loop of Henle, the surrounding interstitial fluid becomes more concentrated than the filtrate, so water leaves the filtrate.

The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

It is expressed as:

pH = pKa + log([A-]/[HA].

where,

[A-] is molar concentration of conjugate base and

[HA] is molar concentration of weak acid.

Given,

pH = 5.30

Substitute the value in the Henderson Hasselbalch equation

5.30 = 4.874 + log[A-]/ [HA]

log[A-]/[HA] = 5.30 - 4.874

[A-]/[HA] = 10^ 0.426

[A-]/[HA] = 2.7

Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

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Nuclear decay is a radioactive decay where energy is released by unstable nuclei. After thorium undergoes decay, actinium-228 will be the final product. Thus, option a is correct.

Alpha radioactive decay is the loss of two protons and neutrons from the element that results in a decrease of the atomic mass by 4 and atomic number of the element by two.

²³² Th₉₀ → ²²⁸Ra₈₈ + ⁴α₂

Beta radioactive decay is the increase of the atomic number but not the atomic mass of the element.

²²⁸Ra₈₈ → ²²⁸Ac⁸⁹ + β⁻

Therefore, option a. actinium-228 is the final product of the decay.

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Your question is incomplete, but most probably your full question was, In the initial sequence of thorium-232 decay, an alpha particle is emitted followed by a beta particle. What is the product of these two decay steps?

²³² Th → α particle + β particle + ?

Taking into account the definition of calorimetry, the specific heat of the metal is 0.14 [tex]\frac{J}{gC}[/tex].

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m.

c is specific heat substance.

ΔT is the temperature variation.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .).

The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.

Specific heat of the metal

In this case, you know:

Replacing in the expression to calculate heat exchanges:

175 J= c× 50× 25 C

Solving:

c=[tex]\frac{175 J}{50 gx25C}[/tex]

c=0.14 [tex]\frac{J}{gC}[/tex]

Finally, the specific heat of the metal is 0.14 [tex]\frac{J}{gC}[/tex].

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The role of each of the reactants are:

What is the Diels-Alder reaction?

The Diels–Alder reaction is known to be a kind of reaction that is said to exist between what we call a conjugated diene and that of an alkene (dienophile).

Note that the union of both leads to a unsaturated six-membered rings and because the reaction is one that entails the formation of a cyclic product through what we call a cyclic transition state, it is said to be known as a "cycloaddition".

Note that from the experiment, The role of each of the reactants are:

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A polar molecule is a water. As a result, polar solutes such as ionic compounds and polar molecular compounds will dissolve in them.

Types of dissolved substances that may be present in water​:

Ionic chemicals and polar molecular compounds, for example, will dissolve in water since it is a polar molecules.

When it comes to organic compounds, water will dissolve any that have a carbon to oxygen atom ratio of less than or equal to 5.

[tex]$\frac{C}{O} \leq 5$[/tex]

Because of this, vitamin A is not water-soluble. Vitamin C is soluble, though.

A polar molecule is a water. As a result, polar solutes such as ionic compounds and polar molecular compounds will dissolve in them.

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It is false that ' Each individual candy/isotope is the same and will take the same amount of time to decay ' .

It is impossible to predict when an individual radioactive atom will decay .

The formula of half life day does not describe the exact amount of time that is every single atom experience before became right. The nuclear  reaction follows first order kinetics and have rate constant which is independent of temperature.

The atoms of the same elements , having the same atomic number but different mass numbers is called isotopes .

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The reaction of 75.0 g p4 with excess chlorine gas produces 110 g pcl3 in lab. The percent yield for the reaction is 32.7%.

P4+ 6 Cl2 — 4PCl3

moles of P4 in 75 g

n=m/M

where n = moles; m= mass; M = molar mass

M(P4) = 4× 30.974 g/ mol

P = 123.896g/mol

n can be given as

n(P4) = (75) / 123.896

= 0.60535 mol

Total=

0.60535 mol P4 × 4 mol/1 mol P4

= 2.4214 mol PCl3

mass of PCl3

m= n×M

M = 30.974 g/mol P+(3× 35.45g/mol Cl)

= 137.32g/mol

m= 2.4212 mol× 137.32g/mol

=333 g

The yield of PCl3 is 333 g.

The theoretical yield of PCl3 is 110 g.

percent yield can be given as

(percent yield/ theoretical yield) × 100

%yield = (333/110) ×100

Thus, the percent yield of PCl3 is 32.7%.

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Answer:

4.70 L

Explanation:

Use the basic relationship:

P1V1/T1 = P2V2/T2

Re-arrange to:

P1V1 T2 / (T1P2) = V2   To find the new volume

Sub in the values:

880 * .5 * 327 / ( 300*102) = 4.70 L

Photosynthesis: water + carbon dioxide + sunlight → oxygen + glucose

Respiration: glucose + oxygen → carbon dioxide + water + energy

Combustion: methane + oxygen → water + carbon dioxide + heat

The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis.

water + carbon dioxide + sunlight → oxygen + glucose

The sugars created during photosynthesis are combined with oxygen during the process of respiration in plants to create energy for plant development.

glucose + oxygen → carbon dioxide + water + energy

Combustion is a chemical process between substances that often involves oxygen and produces heat and light in the form of flame.

methane + oxygen → water + carbon dioxide + heat

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Photosynthesis: water + carbon dioxide + sunlight → oxygen + glucose

Respiration: glucose + oxygen → carbon dioxide + water + energy

Combustion: methane + oxygen → water + carbon dioxide + heat

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The six p atomic orbitals combine to form 6 molecular orbitals. The correct option is A.

Molecular orbitals are the functions that tell the position of an electron in the orbital and the wave like property of the electron. This function is used to find the chemical and physical property of the element.

The six p atomic electrons will combine to constitute 6 molecular pi electrons. Because in benzene there are 6 pi orbitals. As benzene is planar, hexagonal and have sp2 hybridization. The remaining cyclic orbitals overlap to create 6 pi molecular orbitals.

Thus, the correct option is A. 6.

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The question is incomplete. Your complete question is given below:

A. 6

B. 5

C. 4

D. 3

E. 2

The molar mass of a protein if a 0. 30 l of solution containing 0. 45 g of the protein has an osmotic pressure of 0. 80 torr at 25∘c is 0.348 g/mol

Here we can apply the formula ∏ = iMRT, where ∏ = osmotic pressure = 0.80 - ( given ). This is only one part of the information we are given / can conclude in this case ....

i = van’t Hoff factor = 1 for a protein molecule,

R = gas constant = 62.36 L torr / K-mol,

T ( temperature in Kelvin ) = 25 + 273 - conversion factor C° + 273 = 298K

( Known initially ) ∏ = osmotic pressure = 0.80 torr

besides the part " M " in the formula, which we have no information on whatsoever, as we have to determine it's value.

_____

Substitute derived / known values to solve for M ( moles / liter ) -

∏ = iMRT

⇒ 0.80 = ( 1 )( M )( 62.36 )( 298 )

⇒ 0.80 = M( 18583.28 )

⇒ M = 0.80 / 18583.28 ≈ 4.3049 ....

_____

We know that M = moles / liter, so we can use this to solve for moles, and hence calculate the molar mass by the formula molar mass = g / mol -

M = mol / l

⇒ 4.3049 = 0.045 / 25 mL ( 0.030 L ),

0.045 / 0.030 = 1.5 g / L

⇒ 1.5 g = 4.3049 moles,

molar mass = 1.5 g = 4.3049 moles = 0.348 g / mol

Thus the concluded that the molar mass of protein is 0.348 g / mol.

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The energy diagrams of the synthesis, single replacement, and double replacement reactions are found in the attached image.

Energy profile diagrams are diagrams which illustrate the potential energy changes that occur when reactant molecule combine to form products.

The energy diagrams shows the potential energy of the reaction, the energy of the transition state of the reaction, the activation energy of the reaction, as well as the potential energy of the products.

From energy diagrams, the enthalpy change of a reaction can be determined. Also, it can also be established whether the reaction is exothermic or endothermic.

For exothermic reactions, the enthalpy change is negative since the potential energy of the reactants is greater than the potential energy of the products.

For endothermic reactions, the enthalpy change is positive since the potential energy of the reactants is less than the potential energy of the products.

Based on this therefore, the energy diagrams of the given reactions have been constructed and are found in the attached image.

In conclusion, energy diagrams are used to show energy changes occurring in a reaction.

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At the most basic level, in order to produce oxygen and a carbohydrate (comprised of carbon, hydrogen, and oxygen), carbon dioxide must react with water as a source of hydrogen.

In order to construct carbohydrate molecules (often glucose) and release oxygen into the atmosphere, photosynthesis utilises carbon dioxide and water. Photosynthesis occurs in organelles called chloroplasts found in eukaryotic autotrophs like plants and algae.

Commonly used notation for photosynthesis is:

6CO[tex]_{2}[/tex] + 6H[tex]_{2}[/tex]O C[tex]_{6}[/tex]H[tex]_{12}[/tex]O[tex]_{6}[/tex] + 6O[tex]_{2}[/tex]

This indicates that the reactants, six carbon dioxide molecules and six water molecules, are transformed into a sugar molecule and six oxygen molecules, the products, by light energy being absorbed by chlorophyll.

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The amount of nitrogen-13 sample that remained after 40 minutes has been 8 mg.

Half-life can be defined as the time required by the substance to reduce half of its initial concentration.

The half-life of Nitrogen-13 has been 10 minutes. In 10 minutes, the sample will be reduced to

of its concentration,

The total time has been 40 minutes.

The number of half-life experienced by the sample has:

Number of half-life = {Total-time}/{Half-life}

Number of half life cycles = {40}/{10}

The number of half-life cycles = 4

The sample has been reduced to 50% in the first half-life cycle,reduced to 25% in the 2nd half-life cycle, then 12.5% in 3rd half cycle and finally 6.25% by the end of 4th half cycle.

The sample remained = 6.25% of the initial concentration.

The sample remained = (6.25/100)

×128mg

The sample remained = 8 mg

Thus from above we concluded that the amount of nitrogen-13 sample that remained after 40 minutes has been 8 mg.

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The number of moles of the gas is 0.0396 moles.

The ideal gas equation is used to determine the relationship between the variables; temperature, pressure, volume and the number of moles of a gas. We know that the gas laws are used to understudy the parameters that has to do with gases.

Thus;

Volume = 1000.0 cm 3 or 1 L

Gas constant = 0.082 atmLK-1Mol-1

Temperature = 32 o C + 273 K = 305 K

Pressure =  752 mm Hg  or 0.99 atm

Thus;

PV = nRT

n = PV/RT

n =  0.99 atm *  1 L/0.082 atmLK-1Mol-1 * 305 K

n = 0.0396 moles

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One isomer is formed

1,1- Dichloroethane is the isomer.

If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, it would result in one isomer.

These are the three different categories of structural isomers.

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Answer:

B.) No, because the coefficients could be reduced to 2,1, and 3.

Explanation:

The equation is not in its lowest molar ratio form. In this case, all of the coefficients can be divided by 2 and still result in whole numbers.

As such, the correct balanced equation is:

2 NH₃ ----> N₂ + 3 H₂

True

The bare minimum required standard

The minimal necessary standard restricts uses, disclosures, and requests for PHI to the bare minimum amount required to fulfil the use's or disclosure's intended purposes.

Under the Privacy Rule's Minimum Necessary Standard, covered entities are required to take all necessary precautions to ensure that protected health information (PHI) is only accessed as much as is required to carry out the duties at hand.

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Taking into account the reaction stoichiometry and the definition of STP, 72.8 L of CO₂ gas is produced once the gas cools to STP.

In first place, the balanced reaction is:

CaCO₃  → CaO + CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CaCO₃ form 1 mole of CO₂, 3.25 moles of CaCO₃ form how many moles of CO₂?

[tex]moles of CO_{2} =\frac{3.25 moles of CaCO_{3}x 1 mole of CO_{2}}{1 moleof CaCO_{3}}[/tex]

moles of CO₂= 3.25 moles

Then, 3.25 moles of CO₂ are formed when 3.25 moles of CaCO₃ decomposes.

Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of CO₂ occupies a volume of 22.4 liters, 3.25 moles occupies how much volume?

[tex]volume= \frac{3.25 molesx22.4 L}{1 mole}[/tex]

volume= 72.8 L

Finally, 72.8 L of CO₂ gas is produced once the gas cools to STP.

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