What is the answer of the fractions 9 and 1/6 multiplied by 1 and 1/11? Then, that answer simplified into simplest form?

Answers

Answer 1

The simplest form is 10.

We can find simplest as form:

Given, fractions are [tex]9\frac{1}{6}[/tex] and [tex]1\frac{1}{11}[/tex]

[tex]9\frac{1}{6}\times 1\frac{1}{11}[/tex]

[tex]\frac{55}{6}\times \frac{12}{11}[/tex]

[tex]=\frac{55\times 12}{6\times 11}[/tex]

=10

Hence, simplest form of given fraction is 10.

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Related Questions

#6 pls quick answer!!!







Answers

Answer:

ANSWER:  mix 120 ml of 35% acid solution with 60 ml of 65% acid                      solution to obtain 180 ml 0f 45% acid solution

Step-by-step explanation:

If x = number of ml of 35% acid solution and 60 = number of ml of 65% acid solution, then x + 60 = number of ml of the mixture.

Acid content of first ingredient + acid content of second ingredient = acid content of the mixture

So, 0.35x + 0.65(60) = 0.45(x + 60)

    0.35x + 39 = 0.45x + 27

                12 = 0.10x

               120 = x

Find the slope of the line grapef below

Answers

Answer:

x = 1

Step-by-step explanation:

No matter what y is, x will always be 1.

(1,-4)

(1,-3)

(1,-2)

(1,0)

(1,1)

(1,2) and so on and so on.

Veronica's trail-mix package says there are 7 peanuts for every 3 cashews. Casey's trail-
mix package says there are 63 peanuts and 27 cashews. Are these ratios proportional?
If not, how many peanuts should there have been to make it proportional?

Answers

Answer:

Yes, they are proportional.

Step-by-step explanation:

The ratio for Veronica's trail mix is 3:7

The ratio for Casey's trail mix is 27:63 <--- Simplify this number

27:63 simplified is 3:7, which means these ratios are proportional.

hope this helps :)

Select the correct answer. the diameter of a sphere measures 10.4 inches. what is the surface area of the sphere? a. b. c. d.

Answers

The surface area of the sphere is 108.16π in². So, option b is correct.

What is the surface area of a sphere?

The surface area of the sphere is calculated by the formula,

A = 4πr²

In terms of diameter - d;

A = 4π × (d/2)²

  = 4π × d²/4

  = πd² sq. inches

Calculation:

The given sphere has a diameter d = 10.4 inches

So, the surface area of the sphere is calculated by

A = πd²

  = π × (10.4)²

  = 108.16 π sq. inches

So, option b is correct.

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Disclaimer: The given question on the portal is incomplete. Here is the complete question.

Question: Select the correct answer. the diameter of a sphere measures 10.4 inches. What is the surface area of the sphere?

a. 432.64π in²

b. 108.16π in²

c. 54.08π in²

d. 216.32π in²

Answer:

Step-by-step explanation:

The surface area of the sphere is 108.16π in². So, option b is correct.

What is the surface area of a sphere?

The surface area of the sphere is calculated by the formula,

A = 4πr²

In terms of diameter - d;

A = 4π × (d/2)²

 = 4π × d²/4

 = πd² sq. inches

Calculation:

The given sphere has a diameter d = 10.4 inches

So, the surface area of the sphere is calculated by

A = πd²

 = π × (10.4)²

 = 108.16 π sq. inches

So, option b is correct.

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Disclaimer: The given question on the portal is incomplete. Here is the complete question.

Question: Select the correct answer. the diameter of a sphere measures 10.4 inches. What is the surface area of the sphere?

a. 432.64π in²

b. 108.16π in²

c. 54.08π in²

d. 216.32π in²

If BD = 16 yd and the area of rhombus ABCD is 72 yd^2, what is AC?

Answers

[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]

Given:

[tex] \sf{Area\text{ ABCD=}\frac{1}{2}\times AC\times BD}[/tex]

[tex] \sf{Area = 72 yd^2}[/tex]

[tex] \sf{BD = 6yd}[/tex]

[tex]\leadsto[/tex] Substitute the values:

[tex]\longrightarrow \sf{72 = \dfrac{1}{2} \times AC \times 16}[/tex]

[tex]\leadsto[/tex] Solve for AC:

[tex]\longrightarrow \sf{72=8\times AC}[/tex]

[tex]\longrightarrow \sf{ \dfrac{72}{8}=\dfrac{8\times AC}{8}}[/tex]

[tex]\longrightarrow \sf{AC=9}[/tex]

[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]

[tex]\large \bm{AC= \: 9 yd}[/tex]

Solution:

BD = 16 yd

Area of ABCD = 72 yd²

AC = ?

Area of rhombus, using diagonal:

[tex] \frac{1}{2} \times d1 \times d2[/tex]

Therefore:

[tex] \frac{1}{2} \times 16 \times ac = 72[/tex]

Then:

[tex] \frac{16ac}{2} = 72[/tex]

Cross multiply the above into:

[tex]16ac \times 1 = 72 \times 2 = 144 \\ 16ac = 144[/tex]

Divide by the coefficient of AC:

[tex] \frac{16ac}{16} = \frac{144}{16} [/tex]

Final answer is 9 yd

Given the data cleanup problem of removing 0 values from a data set, the ____ algorithm scans a list from left to right and copies every legitimate value into a new list that it creates.

Answers

The copy over algorithm algorithm scans a list from left to right and copies every legitimate value into a new list that it creates.

According to the statement

We have given that the there is a algorithm which is used to data cleanup problem of removing 0 values from a data set, and scans a list from left to right and copies every legitimate value into a new list.

and we have to explain about that algorithm.

So,

Here we given that the algorithm copies and paste the values in the new files then

the algorithm is called the copy over algorithm.

So, The copy over algorithm is a a single specimen of something that occurs in a multiple edition, such as a book, article, etc. a matter to be reproduced in print or an imitation or reproduction of an original.

So, The copy over algorithm algorithm scans a list from left to right and copies every legitimate value into a new list that it creates.

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It costs $0.50 to mail a postcard to Canada and $0.60 to mail a one ounce letter to Canada. Ahmad wrote to 21 friends and spent $12.00 for postage. How many letters and how many postcards did he write?

Answers

It costs $0.50 to mail a postcard to Canada, cost of mailing a one ounce letter to Canada is $0.60 and Ahmad wrote to 21 friends and spent $12.00 for postage. This means that he wrote 15 letters and 6 postcards.

Given Information:

Cost of mailing a postcard = $0.50

Cost of mailing a letter = $0.60

Total number of friends Ahmad wrote to = 21

Total cost of postage = $12.00

Let the number of postcards written by Ahmad be x and that of letters be y.

Then, x + y = 21 ............... (1)

0.50x + 0.60y = 12 ................ (2)

Multiplying equation (1) by 0.50, we get,

0.50x + 0.50y = 10.5 ................. (3)

Subtracting equation (3) from (2), we get,

0.1y = 1.5

⇒ y = 15

From equation (1), x = 21 - y

x = 21 - 15

x = 6

Thus, Ahmad wrote 6 postcards at a mailing cost of $0.50 each and 15 letters at a mailing cost of $0.60 each.

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As people exited a movie theater, they were informally surveyed about whether they enjoyed the movie or not.

What are the values of a and b in the relative frequency table for the survey results? Round answers to the nearest percent.

Answers

A=41% B=3% hope this helps

HELP! A city pays a manufacturing company to produce more stop signs for the city due to an increase in traffic incidents at intersections. After doing some research, the company manager reads that a standard stop sign is a regular octagon that is 30 inches wide and 30 inches tall.

Answers

The apothem is 15 inches, the perimeter is calculated to be 99.41 while the area is given as 745.59

How to solve for the octagon

The side of the octagon is given by x inches

the interior side of the angles can be gotten by:

8-2 * 180 / 8 sides

= 135

We have to find the value of the angles

<abc = 180 - 135 = 45 degree

<acb = 180 - 135 = 45 degrees

x² = 2AB²

AB = x/√2

30 =  x/√2 + x +  x/√2

x = 30 / 1 + √2

The apothem = 30 / 2

= 15

perimeter = 8x

= 8(30 / 1 + √2)

= 99.4 inches

area = 0.5 x 15 x 99.4

= 745.59

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QUICK!!!HELP!!!!!!!!!!!!!!!!!!

Answers

Using the normal distribution, the probability that a worker selected at random makes between $500 and $550 is: 2.15%.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean mu and standard deviation sigma is given by:

Z = (X - mu)/sigma

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given as follows:

mu = 400, sigma = 50

The probability is the p-value of Z when X = 550 subtracted by the p-value of Z when X = 500, hence:

X = 550:

Z = (X - mu)/sigma

Z = (550 - 400)/50

Z = 3

Z = 3 has a p-value of 0.9987.

X = 500:

Z = (X - mu)/sigma

Z = (500 - 400)/50

Z = 2

Z = 2 has a p-value of 0.9772.

0.9987 - 0.9772 = 0.0215 = 2.15% probability.

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Match the key features of functions terms to their corresponding definitions.

Answers

The key features of the above given functions are correctly matched to their corresponding definition.

Definition of terms

Negative sections of the graph: They are the parts where the graph is below the x-axis. That is option C.

End behaviour: This is what happens to the graph on the far left or far right. That is option E.

Positive sections of the graph: This is the parts where the graph is above the x-axis. That is option D.

Intercepts: This is the points where the graph crosses an axis. That is option B

Relative extrema: This is the points of relative minimum or maximum in a graph. That is option A.

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Select the correct answer what are the solutions to this quadratic equation 4x^2-10=10-20x

Answers

Answer:

x1 = 5-3squareroot 5/2 x2= -5+3 squareroot 5 / 2

Step-by-step explanation:

Please give me a correct answer and the step by step explanation.

Answers

keeping in mind that the points are A(-8 , 6) and C(2 , 5), so

[tex]\textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-8}~,~\stackrel{y_1}{6})\qquad C(\stackrel{x_2}{2}~,~\stackrel{y_2}{5})~\hspace{8em} \frac{2}{5}\textit{ of the way from A to C} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{2}-\stackrel{x_1}{(-8)}~~,~~ \stackrel{y_2}{5}-\stackrel{y_1}{6})\qquad \implies \qquad \stackrel{\stackrel{\textit{component form of}}{\textit{segment AC}}}{\left( 10 ~~,~~ -1 \right)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\left( \stackrel{x_1}{-8}~~+~~\frac{2}{5}(10)~~,~~\stackrel{y_1}{6}~~+~~\frac{2}{5}(-1) \right)\implies \left(-8+4~~,~~6-\frac{2}{5} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill B\left(-4~~,~~5\frac{3}{5} \right)~\hfill[/tex]

A standard deck of cards contains 52 cards. There are four suits (spades, clubs, hearts, and diamonds) and thirteen of each suit (2-10, jack, queen, king, ace). One card is selected at random from the deck. What is the probability the card selected is an Ace or a heart?

Answers

The probability of selecting an ace or a heart when one card is drawn from 52 cards is 1/52.

Given that there are 52 cards in which there are 13 cards each for spades,clubs,hearts and diamonds.

We are required to find the probability of getting an ace or a heart when one card is drawn from 52 cards.

Probability is basically the chance of happening an event among all the events possible. It lies between 0 and 1. It cannot be negative. The probability can be calculated through following formula:

Probability=Number of items/total number of items.

Number of hearts=13

Number of ace=4

Probability of getting an ace or a heart when one card is drawn=P(X=heart)*P(X=ace)

=13/52 * 4/52

=52/(52*52)

=1/52

Hence the probability of getting an ace or heart when one card is drawn from standard deck of cards is 1/52.

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Which values represent solutions to cosine (startfraction pi over 4 endfraction minus x) = startfraction startroot 2 endroot over 2 endfraction sine x, where x is an element of [0, 2pi)?

Answers

The given trigonometric function consists of trigonometric values of common angles.

The values that represent the solution to [tex]cos(\frac{\pi }{4} -x)=\frac{\sqrt{2} }{2} .sinx[/tex], x ∈ [0, 2·π) are; [tex]x=({\frac{\pi }{2} or \frac{3.\pi }{2} )[/tex].

What are trigonometric functions?Trigonometric functions are real functions in mathematics that connect an angle of a right-angled triangle to ratios of two side lengths. They are widely utilized in all geosciences, including navigation, solid mechanics, celestial mechanics, geodesy, and many more.

The given function is:  [tex]cos(\frac{\pi }{4} -x)=\frac{\sqrt{2} }{2} .sinx[/tex]

Where; x ∈ [0, 2·π).

We have; cos(A - B) = cos(A)·cos(B) - sin(A)·sin(B).

[tex]cos(\frac{\pi }{4} )=\frac{\sqrt{2} }{2}, sin(\frac{\pi }{4} )=\frac{\sqrt{2} }{2}[/tex]

Which gives:

[tex]cos(\frac{\pi }{4}-x )=\frac{\sqrt{2} }{2}. cosx+\frac{\sqrt{2} }{2}.sinx[/tex]

So, we obtain:
[tex]\frac{\sqrt{2} }{2} .cosx=\frac{\sqrt{2} }{2}.sinx-\frac{\sqrt{2} }{2} .sinx=0\\cosx=0\\cos\frac{\pi }{2} =0[/tex]

Therefore, the possible solutions (x-values) to cos x = 0 are:

[tex]0[/tex] ≤ [tex]\frac{n.\pi }{2}[/tex] ≤ [tex]2.\pi[/tex]

Where, n = 1, 3, 5, .., x ∈ [0, 2·π)

We get:  [tex]x=({\frac{\pi }{2} or \frac{3.\pi }{2} )[/tex].

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bell canada came by my house that I just bought and installed a new wire support for one of the telphone poles on my property. the electrical code says that the support must hit the ground at a 55 degree angle..If the telephone pole is 25 feet tall. how long is the wire spport that bell just installed?

Answers

Answer:

The cable length will have to be at least 30.51936ft

Step-by-step explanation:

[tex]c= \frac{25}{ \sin( 55 ) } = 30.51936[/tex]

C = Cable

The cable is going to have to be 40 ft long to be installed

Given: the equation of a parabola is x2 = 8y. step 4: where does the focus for the given parabola lie?

Answers

The vertex of the given parabola [tex]$x^{2}=8 \mathrm{y}$[/tex] exists (0, 0).

What is the vertex of a parabola?

The vertex of a parabola exists as the point at the intersection of the parabola and its line of symmetry. The vertex of the parabola exists as the minimum point on the graph for a positive right-handed parabola.

Given the equation of parabola exists [tex]$x^{2}=8 y$[/tex].

[tex]$\mathrm{y}=x^{2} / 8[/tex]

General vertex form for any given parabola exists [tex]$\mathrm{y}=\mathrm{a}(x-a)^{2}+\mathrm{b}$[/tex]

where (a, b) exists the coordinates of the vertex.

For this function it exists [tex]$\mathrm{y}=1 / 8(x-0)^{2}+0$[/tex]

The vertex of the given parabola exists at (0, 0).

Therefore, the vertex of the given parabola [tex]$x^{2}=8 \mathrm{y}$[/tex] exists (0, 0).

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Louise Tammy Dolores and Cheryl score 78 points in the tennis matches they play. A score consecutive number of points from smallest to greatest in respect to the order of the name is mentioned. How many points does Lewis score? Options:
A. 19 p
B. 20 p
C. 21 p
D. 18 p

Answers

Based on the fact that the number of points scored are consecutive numbers, the number of points scored by Lewis is D. 18 points.

How many points did Lewis score?

Lewis is the player who scored the least amount of points as they are first in the order.

To find the total number of points scored in the game therefore, you need to assume Lewis's points based on the options, and then sum up the three numbers above it to see if they add up to 78 points.

If Lewis scored 19 points as the lowest then the total points would be:

= 19 + 20 + 21 + 22

= 82 points

If Lewis scored 20 points, the total points would be:

= 20 + 21 + 22 + 23

= 86 points

Lewis therefore scored less than 19 points.

If Lewis scored 18 points, the total is:

= 18 + 19 + 20 + 21

= 78 points

Lewis therefore scored 18 points.

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PLS HELP ITS MATH PLS

Answers

Answer:

y = 2x + 7

Step-by-step explanation:

When a line is parallel to another line, then the slopes of the lines are equal. If line A has an equation y = 3x + 5, then line B, parallel to line A, must also have a slope of 3. Therefore, we know that m (slope) is 2 in this case.

Next, let’s substitute the x and y coordinates and the slope value into y - y1 = m(x - x1). In this case, -4 is x1, and -1 is y1.

y - y1 = m(x - x1)

y + 1 = 2(x + 4)


Finally, simplify the equation and transform it into the slope intercept form, y = mx + b.

y + 1 = 2(x + 4)
y + 1 = 2x + 8

y = 2x + 7

n January 1989, the temperature in Nome, Alaska dropped to −49° F. Would the gas in the driver's truck have remained in liquid form so he could have driven on this day? Why or why not?

Answers

Answer: The gas would not have remained liquid

Step-by-step explanation:

Since the freezing point of gasoline starts at -40°F, and the temperature that day was -49°F, we can conclude that the gasoline would not have remained liquid

Can someone please help me with this?

Answers

Answer:

-2

Step-by-step explanation:

See attachment

Oscar corporation is planning to construct an elliptical gate at its headquarters. the width of the ellipse will be 5 feet across and its maximum height along the center will be 3 feet. the company wants to place two bright spots at the foci of the ellipse. how far from the center of the ellipse will the spots be located?

Answers

The distance from the center of the ellipse to where the spots are located will be 2 feet.

What is Distance?

Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.

The distance from the center of the ellipse to where the spots are located will be -

= 5 - 3

= 2 feet.

Therefore, the distance from the center of the ellipse is 2 feet.

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Which term is not possible in the domain of a sequence?

Answers

The term that is not possible in the domain of a sequence is:

-5

What is the domain of a function?

The domain of a function is the set that contains all possible input values for the function. For a sequence, the domain is the set that contains all the indexed of the terms, starting at 0 and going until the nth term.

For example, suppose we have the following sequence: 3, 5, 7, ...

The term with index 0 is 3.The term with index 1 is 5.The term with index 2 is 7.

From what was explained above, which also can be visualized with the example, an index term of a sequence cannot be negative, hence the term that is not possible in the domain of a sequence is:

-5.

Which is the only negative number of the options.

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Choose the expression that represents a cubic expression. 2x 11 −3x2 − 2x 11 4x3 − 3x2 − 2x 11 5x4 4x3 − 3x2 − 2x 11

Answers

(C) [tex]8x^{3} -7x^{2} -6x+5[/tex] represents a cubic expression.

What is a cubic expression?A cubic polynomial has the generic form [tex]p(x): ax^{3} +bx^{2} +cx+d[/tex], a 0, where a, b, and c are coefficients and d is the constant, all of which are real integers. A cubic equation is one that involves a cubic polynomial.

To determine which expression represents a cubic expression:

[tex]8x^{3} -7x^{2} -6x+5[/tex]  is a cubic expression.The variable is x. [tex]8x^{3} -7x^{2} -6x+5[/tex] : The variable x has the highest power as 3. [tex]8x^{3} -7x^{2} -6x+5[/tex]  is a polynomial.[tex]-7x+4[/tex] is a linear expression because the highest power of the variable x is 1.[tex]7x^{2} -5x+6[/tex] is a quadratic expression because the highest power of the variable x is 2.[tex]9x^{4} +8x^{3} -6x^{2} -2x+11[/tex] is a polynomial with the highest power of the variable being 4.

Therefore, (C) [tex]8x^{3} -7x^{2} -6x+5[/tex] represents a cubic expression.

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The complete question is given below:

Choose the expression that represents a cubic expression.

(A) −7x + 14

(B) 7x2 − 5x + 6

(C) 8x3 − 7x2 − 6x + 5

(D) 9x4 + 8x3 − 6x2 − 2x + 11

PLEASE ASAP - Drag each tile to the correct box. Arrange the figures from least to greatest according to their volumes. Assume the variable h has the same value for each figure.

Answers

Assuming that the variable h is the same for each figure, the figures from the least to the greatest is:

Cone with radius of 3 units Cylinder with radius of 3 units Cone with radius of 6 units Cylinder with radius of 6 units

What are the volumes of these shapes?

The value of h is the same for all the shape so assume the value of h is 2 units.

The volume of a cylinder is:

= πr²h

First cylinder area:

= 22/7 x 3 x 2

= 56.54867 units

The second cylinder area:

= 22/7 x 6 x 2

= 226.19467 units

The volume of a cone is:

= πr²h/3

First cone volume:

= 22/7 x 3 x 2/3

= 18.84956 units

Second cone volume:

= 22/7 x 6 x 2/3

= 75.39822 units

The order is therefore:

Cone with radius of 3 units < Cylinder with radius of 3 units < Cone with radius of 6 units < Cylinder with radius of 6 units

In conclusion, the shapes with the larger radius of 6 units will have more volume.

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Which linear inequality will not have a shared solution set with the graphed linear inequality? y < five-thirdsx – 2 y < negative five-thirdsx 1 y > five-thirdsx 2 y > negative five-thirdsx 2

Answers

The inequality will not have a shared solution set with the graphed linear inequality is y > five-thirds x + 2.

Linear inequalities are inequalities that involves at least one linear algebraic expression, that is, a polynomial of degree 1.Linear inequalities are the expressions where any two values are compared by the inequality symbols such as, '<', '>', '≤' or '≥'. These values could be numerical or algebraic or a combination of both.

y < five-thirds x – 2. The inequality will have a shared solution set with the graphed linear inequality. y < negative five-thirds x - 1. The inequality will have a shared solution set with the graphed linear inequality.y > five-thirds x + 2. The inequality will not have a shared solution set with the graphed linear inequality. y >  negative five-thirds x + 2. The inequality will have a shared solution set with the graphed linear inequality

Hence, the inequality will not have a shared solution set with the graphed linear inequality is y > five-thirds x + 2.

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Answer:

C

Step-by-step explanation:

answer is C

The triathletes were offered water as they rode by the volunteer station. The volunteers handed them cones with the dimensions shown. If each triathlete sloshed 1/3 of the water out before they drank it, how many cubic cm of water did they slosh out? Round to the nearest tenth. (PLEASE ANSWER)

Answers

Answer:

 29.9 cm³

Step-by-step explanation:

You want to know the volume represented by 1/3 of a cone that is 7 cm high and has a radius of 3.5 cm.

Cone

The volume of a cone is given by ...

  V = 1/3πr²h

The volume of the cone of interest is ...

  V = 1/3π(3.5 cm)²(7 cm) ≈ 89.797 cm³

Slosh

1/3 of the volume is the amount of water that sloshed out of the cone. That volume is ...

  1/3(89.797 cm³) ≈ 29.9 cm³

They sloshed out about 29.9 cm³ before they drank the water.

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When calculating a nation’s digital power, what term is used to refer to the demonstrated capabilities of a nation-state in cyber offense or defense?

Answers

When calculating a nation’s digital power, the term that is used to refer to the demonstrated capabilities of a nation-state in cyber offense or defense is Cyberwarfare.

What is Cyberwarfare?

Cyberwarfare  can be regarded as the use of cyber attacks against a nation-state so as to produce significant harm.

It should be noted that Cyber Warfare is set of actions  which is been carried out by  nation or organization so as to be able to launch an attack on institutions' computer network systems.

The interests or reasons for cyberwarfares based on the Cybersecurity as well as Infrastructure Security Agency are;

To weaken the system of another country.To disrupt or destroy the sytem of another nation.

In order to achieve the goals behind the cyberwarfare programs, it is usually designed to focus on spectrum of objectives which will bring harm to national interests.

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Solve the system of equations

ax+y=2a
x+ay=1+a^2

Answers

Answer:

x = 1; y = a

Step-by-step explanation:

ax+y=2a

x+ay=1+a^2

-a²x-ay=-2a²

x+ay=1+a^2

(1 - a²)x = 1 - a²

x = (1 - a²)/(1 - a²)

x = 1

a + y = 2a

1 + ay = 1 + a²

a = y

x = 1; y = a

Given f(x) = 3 and g(x) = cos(x). what is limit of left-bracket f (x) minus g (x) right-bracket as x approaches negative pi? 2 3 4 dne

Answers

Answer:

3

Step-by-step explanation:

f(x)-g(x)=3-cos(x)

when u limit it

u have

3-cos180

which is 3-0

3

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