Answer:
Approximately [tex]63.2^{\circ}[/tex].
Explanation:
The refractive index [tex]n[/tex] gives the ratio between the speed of light in vacuum and the speed of light in the given material. A larger refractive index means slower speed of light in the medium. In this question, the speed of light is slower in polycarbonate than in quartz.
When light travels from a material of low light speed to a material of higher light speed, the angle of refraction [tex]\theta_{r}[/tex] will exceed the angle of incidence [tex]\theta_{i}[/tex] (both with respect to the normal.)
The critical angle at this interface is the [tex]\theta_{i}[/tex] for which [tex]\theta_{r} = 90^{\circ}[/tex]. Note that since [tex]\theta_{i}\![/tex] cannot exceed [tex]90^{\circ}[/tex], [tex]\theta_{i} < \theta{r}[/tex] and light must be entering a faster medium from a slower medium. In this question, light would be entering quartz ([tex]n = 1.41[/tex], faster) from polycarbonate ([tex]n = 1.58[/tex], slower.)
By Snell's Law:
[tex]n_{i}\, \sin(\theta_{i}) = n_{r}\, \sin(\theta_{r})[/tex],
Where:
[tex]n_{i}[/tex] is the refractive index of the medium from which light enters, [tex]n_{r}[/tex] is the refractive index of the medium light enters into,[tex]\theta_{i}[/tex] is the angle of incidence at which light enters the interface (with respect to the normal), and[tex]\theta_{r}[/tex] is the angle of refraction at which light leaves the interface (also with respect to the normal.)Set [tex]n_{i} = 1.58[/tex] (polycarbonate), [tex]n_{r} = 1.41[/tex] (quartz), and [tex]\theta_{r} = 90^{\circ}[/tex]. Rearrange the equation and solve for [tex]\theta_{i}[/tex]:
[tex]\begin{aligned}\sin(\theta_{i}) &= \frac{n_{r}\, \sin(\theta_{r})}{n_{i}} \end{aligned}[/tex].
[tex]\begin{aligned}\theta_{i} &= \arcsin\left (\frac{n_{r}\, \sin(\theta_{r})}{n_{i}} \right) \\ &= \arcsin \left(\frac{1.41\, \sin(90^{\circ})}{1.58}\right) \\ &\approx 63.2^{\circ}\end{aligned}[/tex].
Two objects, one with a mass of 75.0kg and the other with a mass of 60.0kg experience a gravitational force of attraction of 8.50x10-9N. How far apart are their
centers of mass?
Answer:
Approximately [tex]5.94\; {\rm N}[/tex].
Explanation:
The gravitational force between two objects of uniform mass is:
[tex]\displaystyle F = \frac{k\, M\, m}{r^{2}}[/tex],
Where:
[tex]k \approx 6.67 \times 10^{-11}\; {\rm m^{3}\, kg^{-1}\, s^{-2} }[/tex] is the gravitational constant,[tex]M[/tex] and [tex]m[/tex] are the mass of the two objects, and[tex]r[/tex] is the distance between the center of mass of the two objects.Rearrange this equation to find [tex]r[/tex]:
[tex]\begin{aligned} r &= \sqrt{\frac{k\, M\, m}{F}} \\ &= \sqrt{\frac{(6.67 \times 10^{-11})\, (75.0)\, (60.0)}{8.50 \times 10^{-9}}}\; {\rm kg} \\ &\approx 5.94\; {\rm kg}\end{aligned}[/tex].
What is the acceleration of a 650 kg racing camel that has a Ford net force of 897N
The acceleration of the racing camel is 1.38 m/s².
What is the acceleration of the racing camel?From Newton's second law, force is expressed as;
F = m × a
Where is mass of object and a is the acceleration
Given that:
Mass of the camel m = 650 kg Net force f = 897NAcceleration of the camel a = ?To determine the acceleration of the camel, pug the given values into the abovr formula and solve for a.
F = m × a
897N = 650 kg × a
Note that: Newton N is the same as kg·m/s²
Hence;
897kg·m/s² = 650 kg × a
Divide both sides by 650 kg
a = (897kg·m/s²) / (650 kg)
a = 1.38 m/s²
Therefore, the acceleration is 1.38 meters per second sqaure.
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A solution of ethanol is pumped to a vessel 25 m above a reference level through a 25-mm-inside-diameter steel pipe at a rate of 10 m3 /h. The length of pipe is 30 m and contains two elbows with friction equivalent to 20 diameters each. Compute the power requirements of the pump. Solution properties include density of 975 kg/m3 and viscosity of 4 3 1024 Pa s
The mass of a density bottle is 20g when empty 70g when full of water and 695g when full of another liquid. Calculate the density of the other liquid (take density of water as 1g/cm³ (2mk) Mass of 20cm³ of the liquid ()
Answer:
The answer is 13.5g/cm³
Explanation:
m1=20g
m3=70g
m2=695g
v=20cm³
m2-m1/m3-m1
R.d=695-20/70-20
R.d=675/50
R.d=13.5
R.d=density of liquid/density of water
density of liquid =R.d×density of water
D=13.5×1
D=13.5g/cm³
The boy biked 600 m at a speed of 10 m/s, how long did it take him to bike the total distance?
Answer:60 seconds
Explanation: Since we have the boy's initial location si (0m), final location sf (600m) and his velocity v, we can have our position equation like so:
sf = si + vt
600 = 0 + 10t
Solve for t by dividing 600 by 10 and your time t = 60s
Which of the following statements regarding VDGS
Systems are true? (Select ALL that are true.)
You can guess what type of aircraft is being parked.
If the system stops the aircraft, you can just manually continue to park it.
You do not need to investigate the reason for the stop.
Anyone can give the "Stop" signal if a threat to the safety of the aircraft is
observed.
You must power on and check the system before arrival.
A qualified agent must man the Emergency stop.
The true statements regarding VDGS Systems are you must power on and check the system before arrival and a qualified agent must man the Emergency stop.
What is VDGS?VDGS stands for Visual Docking Guidance System. It is a technology used in airports to assist pilots in parking their aircraft at the gate by providing visual cues and guidance through the use of lights and/or displays.
The following statements regarding VDGS Systems are true:
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What is the force of gravity between two 70.0kg masses that are separated by 2.50m?
Answer:
F = 5.2324 x 10⁻⁸ N
Explanation:
F = G(m₁ · m₂) / r²
where F is the gravitational force, G is the gravitational constant (6.674 x 10⁻¹¹ N·m²/kg²), m1 and m2 are the masses of the two objects, and r is the distance between them.
Plugging in the given values m1 = m2 = 70.0 kg, r = 2.5 m:
F = (6.674 x 10⁻¹¹)(70.0 kg)² / (2.50 m)²
F = 5.2324 x 10⁻⁸ N
Therefore, the gravitational force between the two 70.0 kg masses separated by 2.50 m is approximately 5.2324 x 10⁻⁸ N.
Identify how each machine changes the way work is done so as to be useful.
The machine changes how work is done, by making the process easier and increasing output with less effort.
What is a machine?Any device that uses energy to carry out a task is a machine. Machines can be simple, like a lever or pulley, or complex, like a computer or a car engine. The purpose of a machine is to make work easier, faster, or more efficient than it would be without the machine. Different types of energy, including human power, electricity, and fuel, can be used to power machines.
Bicycle: A bicycle is a human-powered machine that allows people to move faster and with less effort than walking or running. A person can travel farther distances faster and with less physical effort by turning the wheels and shifting gears with their pedaling motion.
Ax blade: An ax blade is a cutting tool used for chopping wood. It facilitates the process of splitting wood by utilizing a sharp metal blade to cut through the wood fibers, rather than depending exclusively on physical power to break the wood apart.
Car jack: A car jack is a mechanical device used to lift a car off the ground. A person can raise the car to access the underside for repairs or maintenance by pulling a lever and applying hydraulic pressure. Compared to attempting to lift the car manually, this makes maintenance and repairs easier and safer.
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A woman weighs 100 kg and wants to know the force that the heels of her different shoes put on the new carpet by standing on one foot. The different shoes, A, B, C, D have heels of area 1cm, 4cm, 8cm and 64cm.
Which heel applies greater force to the carpet?
Answer: ALL EQUAL
^^^^^^^^^^^^^^^^^^^^^^^
^^^^^^^^^^^^^^^^^^^^^^^
Answer: ALL EQUAL
The heel of shoe D applies the greatest force to the carpet because it has the largest surface area in contact with it, and thus the largest force is distributed over that larger area.
Two cars are moving with velocities 70 km/hr and west direction respectively.Find their relative velocity.
Answer:
Explanation:
To find the relative velocity of two cars moving in different directions, we need to subtract their velocities. In this case, one car is moving with a velocity of 70 km/hr and the other car is moving with a velocity in the west direction.
Let's assume that the velocity of the second car is also 70 km/hr. Since the car is moving in the west direction, we can represent its velocity as -70 km/hr (negative sign indicates motion in the opposite direction).
Now, we can find the relative velocity of the second car with respect to the first car by subtracting the velocity of the first car from the velocity of the second car:
Relative velocity = Velocity of the second car - Velocity of the first car
= (-70 km/hr) - (70 km/hr)
= -140 km/hr
Therefore, the relative velocity of the second car with respect to the first car is -140 km/hr, which means that the two cars are moving away from each other at a speed of 140 km/hr.
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2.
How did Robert Boyle demonstrate that sound needs a medium through which to travel?
He found that an alarm watch in a vacuum did not make a
sound.
He found that the speed of sound varied under different
conditions.
MacBook Air
He found that an alarm watch under water did not make a
sound.
He recorded the time that distant pistol fire was heard.
In the 1600s, a scientist by the name of Robert Boyle made the first known demonstration of the fact that a sound cannot pass through void space. Boyle placed the clock in a glass jar with a tight lid.
How can an experiment demonstrate that sound travels through a medium?Pump out the air from the sealed bell jar while putting an electrical bell inside. Set the electric bell to ringing. We cannot hear the sound that the bell makes with our ears. This indicates that sound waves require a material environment for propagation because they cannot move through a vacuum.
What justifies the notion that sound travels via a medium?Since sound waves are carried from one location to another by the molecules of solids, liquids, and gases, sound requires a physical medium for propagation, such as a solid, liquid, or gas. Since there are no molecules in the vacuum that can vibrate and convey sound waves, sound cannot travel through it.
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define boiling point
Answer: boiling point is when the object of a liquid is hot enough to start to boil and create bubbles, and even start to evaporate into gas.
Explanation:
3.
What is sonography?
using infrasonic waves to communicate long distances
through the ground
using ultrasonic waves to communicate and hunt for prey
MacBook Air
using infrasonic waves to create images of submerged
objects
using ultrasonic waves to create images of objects found
inside other objects
The correct answer is using ultrasonic waves to create images of objects found inside other objects.
What do the terms "infrasonic" and "ultrasonic" mean?Infrasonic Wave: An infrasonic wave is a longitudinal elastic wave whose frequency is lower than that of sound, or 20Hz. For instance: It typically occurs during an earthquake. Ultrasonic Wave: An ultrasonic wave is a longitudinal wave with a frequency greater than the threshold of human hearing, or 20 kHz.
What do ultrasonic and infrasonic waves consist of?The audible range of frequencies below 20 Hz is known as infrasonic. Volcanoes, earthquakes, and thunder all emit sound in the infrasonic range. Human ears cannot hear this sound, but elephants and whales can. Ultrasonic frequencies are those that are above 20,000 Hz.
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6.
Sonography uses infrasonic waves to create images of objects found inside other objects.
True
False
Sonography uses infrasonic waves to create images of objects found inside other objects.-False
Sonography, commonly known as ultrasound imaging, creates pictures of structures and organs inside the body using high-frequency sound waves (rather than infrared rays). These sound waves are emitted by a transducer, a portable device put on the skin and deliver sound waves through the body. The waves reverberate off internal organs and structures and are picked up by the transducer, which generates a visual representation on a computer screen. Ultrasonic imaging is widely used in obstetrics to monitor fetal development and in other medical specialties to diagnose and treat various disorders.
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You decide to go skiing but fall over. As you are attempting to get back up, you see a child start to head down the hill straight for you. If the coefficient of friction between the child and the snow is assumed to be 0, and the child appears to be 20 m above you when they start down the mountain, and the incline of the mountain is 31 degrees, how long do you have to get up and out of the way before you and the child collide?
The time taken to get up and out of the way before you and the child collide is 2.82 s.
What is the time taken to get up?The time taken to get up and out of the way before you and the child collide is calculated as follows;
s = v + ¹/₂at²
s = v + ¹/₂(g sin (31)t²
where;
v is the initial velocitys is the displacementt is the time of motionThe time taken to get up is calculated as;
20 = 0 + ¹/₂(9.8 sin (31)t²
20 = 2.524t²
t² = 20/2.524
t² = 7.925
t = 2.82 s
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What force produces an extension of 2.5 cm?
HELP ASAP
The specific heat capacity of solid copper metal is 0.385 J/g-K. How many joules of heat are needed to raise the temperature of a 1.55-kg block of copper from 33.0 °C to 99.9 °C?
3.71 × 10^−6J
39.9 J
3.99 × 10^4J
0.00371 J
2.69 × 10^5 J
IT IS A CHEMISTRY QUESTION BUT WAS PUT WITH PHYSICS BY MISTAKE SORRY
Answer: 3.99•10⁴ J
Explanation:
The Heat Formula is: Q = m • C • ΔT
Your given C, m, T₀, and T
C = 0.385 J/g•K
m = 1.55 kg or 1,550 g
T₀ = 33.0 °C
T = 99.9 °C
(ΔT = T - T₀)
Your only remaining variable is Q, heat, so you can now plug in your values to solve.
Q = (1550)(0.385)(99.9 - 33.0)
(ΔT(°C) = ΔT(K) because the conversion is linear)
Q = 39,922.575 J
or
3.99•10⁴ J
The graph shows how the speed of a car travelling in a straight line changes with time. Which section shows the largest acceleration? speed A B C D time
The section that shows the largest acceleration on the graph would be section B, as it has the steepest slope.
This indicates that the car is increasing in speed at a faster rate during this section compared to the other sections.
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complete question not found in search engine.
The graph shows the decay of two different radioactive nuclei, Source A and Source B.
How long does it take Source B to complete two half-lives?
a. 10 s
b. 5 s
c. 40 s
d. 20 s
It takes source B 40 s to complete two half lives.
What is the half life?The half-life of a chemical is the amount of time it takes for half of the atoms in a sample to decay. This concept is widely used to describe how quickly a substance decays radioactively in nuclear physics and radiochemistry. Each radioactive substance has a unique half-life due to the properties of each atomic nucleus.
Looking at the graph, we can see that the half life of the source B is 20s .
Hence the time taken to complete two half lives = 2(20 s) = 40 s.
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What is the S-P difference (sec)?
What is the amplitude (mm)?
What is the distance (km)?
What is the magnitude (M)?
(a) The S-P difference (sec) is 40 sec.
(b) The amplitude (mm) is 10 mm
(c) The distance (km) is 380 km
(d) The magnitude (M) is 4.5
What is the S-P wave difference (sec)?The S-P wave difference (sec) is a measure used in seismology to determine the distance between a seismic station and an earthquake source.
From the graph, the S-P difference, that is between S and P = 40 s - 0 s
= 40 s
The distance (km) corresponding to 40 sec is 380 km.
The amplitude of the wave is the maximum displacement of the wave and it is equal to 10 mm.
The corresponding magnitude of the wave is 4.5.
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1.
A megaphone amplifies sound by
all the above
increasing the range of frequencies that can be produced.
focusing sound energy into one specific direction.
spreading out the sound waves over a large area.
The correct statement explaining how a megaphone amplifies sound is: "A megaphone amplifies sound by focusing sound energy into one specific direction."
How does a loudhailer increase sound volume?By increasing the acoustic impedance perceived by the vocal chords and bringing them into closer proximity to the air, the loudhailer amplifies the sound and increases the amount of sound power that is emitted.
What kind of sound does a loudhailer produce?Many people are familiar with the distinctively distorted sound of a human voice amplified by a loudhailer thanks to its use in train and bus stations and sporting venues. It produces the sound of a vintage acoustic phonograph record player when used with music.
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1.5 Find the center of gravity of a 100 mm x 150 mm x 30 mm T-section. H 150 mm -100 mm- G D BI 30 mm E -30 mm Figure 1.5 1.
Answer:
Explanation:
que ricos puntitos
An electric golf cart develops 1.25 kW of power while moving at a constant speed: (a) Express its power in horsepower: (b) If the cart travels 200 m in 35.0 %, what force is exerted by the cart?
a) The power of the electric golf cart is approximately 1.674 horsepower.
b) The force exerted by the electric golf cart is approximately 2182.5 Newtons.
Power and force in the Electric golf cart(a) To convert 1.25 kW to horsepower, we can use the conversion factor:
1 horsepower = 0.746 kW
So, 1.25 kW = (1.25/0.746) horsepower = 1.674 horsepower (approximately)
Therefore, the power of the electric golf cart is approximately 1.674 horsepower.
(b) To calculate the force exerted by the cart, we can use the following formula:
force = power / velocity
where power is in watts, velocity is in meters per second, and force is in Newtons.
First, we need to convert the power of the cart from 1.25 kW to watts:
1 kW = 1000 watts
So, 1.25 kW = 1250 watts
Now, we need to convert the distance traveled by the cart from meters to kilometers, and the time taken from seconds to hours:
200 m = 0.2 km
35.0% = 0.35 hours
Using the formula, we can calculate the force exerted by the cart as:
force = power / velocity
force = 1250 / (0.2/0.35)
force = 1250 / 0.5714
force = 2182.5 N (approximately)
Therefore, the force exerted by the electric golf cart is approximately 2182.5 Newtons.
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what is scientific learning
Answer:
the learning which is gained through observation and experimentation
Review the ray tracing provided.
A thin lens is located centered over a 14 cm ruler at the 7 cm mark. A black dot is located at 5.5 cm on the left side of the lens and at 8.5 cm on the right side of the lens. An arrow is located at the 6 cm mark. Rays appear to go from the head of the arrow towards the lens, and then extend backwards to the tip of an arrow located at 4 cm.
Which of the following best describes the image?
Inverted, smaller, and real
Upright, smaller, and virtual
Upright, larger, and real
Upright, larger, and virtual
The best description of the image is (B) upright, smaller, and virtual is correct option.
To determine the characteristics of the image, we can use the thin lens equation:
1/f = 1/do + 1/di
where f is the focal length of the lens, do is the object distance (distance of the object from the lens), and di is the image distance (distance of the image from the lens).
We can also use the magnification equation:
m = -di/do
where m is the magnification.
First, we need to determine the focal length of the lens. We can use the fact that the lens is centered over the 14 cm ruler at the 7 cm mark, which means the lens is 7 cm from both the left and right sides of the ruler. Since the ruler has a total length of 14 cm, the lens must be in the middle, and the distance from the lens to the ruler is 7 cm. Therefore, the lens has a focal length of 7 cm.
Next, we can use the thin lens equation to find the image distance for the arrow located at the 6 cm mark:
1/7 = 1/(6 - 7) + 1/di
di = -7 cm
The negative sign indicates that the image is inverted.
We can also use the magnification equation to find the magnification of the image:
m = -di/do = -(-7)/(-6) = 7/6
The positive magnification indicates that the image is upright.
Finally, we can use the image distance and magnification to determine the characteristics of the image. Since the image distance is negative, the image is virtual. Since the magnification is less than 1, the image is smaller.
Therefore, the best description of the image is upright, smaller, and virtual.
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Answer:
upright, smaller virtual
Explanation:
The pressure difference between two locations is 0.005 Torr .Which one of the following barometers is preferred to measure the small pressures accurately? (knowing that: Density of mercury = 13600 kg/m³, density water = 1000 kg/m³, density of oil = 800 kg/m³
A-Mercuric barometer
B-Oil-water barometer
C-Water barometer
D-Oil barometer
Due to its high density, the mercury barometer is the greatest option for precisely measuring minor changes in pressure. The correct option is A.
A barometer is an instrument used to measure atmospheric pressure. It typically consists of a long glass tube filled with a liquid, usually mercury, and inverted in a container of the same liquid.
The preferred barometer to measure small pressures accurately would be the mercury barometer (option A), because it has a higher density compared to the other options and hence it can detect smaller changes in pressure.
To see why the other options are not as good for measuring small pressures accurately, we can compare their densities:
Oil-water barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Water barometer: The density of water is much lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Oil barometer: The density of oil is lower than the density of mercury, so it would not be as accurate for measuring small changes in pressure.
Therefore, option A, the mercury barometer, is the best choice for measuring small changes in pressure accurately due to its high density.
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What is the acceleration of a 650 kg racing camel that has a forward net force of 897N
Answer:
a = 0.724 m/s2
Explanation:
Known:
m = 650 kg
F = 897 N
a = ?
Use this formula:
F = ma
a = F/m
a = 650/897
a = 0.724 m/s2
what is screw guage how does it work
Answer:
A screw gauge, also known as a micrometer screw gauge, is a precision measuring instrument used to measure small distances with high accuracy. It consists of a calibrated screw and a calibrated thimble with a spindle and an anvil face. The spindle is attached to the screw, and the anvil face is fixed to the body of the instrument.
To use a screw gauge, the object being measured is placed between the spindle and the anvil face, and the screw is turned until the spindle makes contact with the object. The thimble is then turned, which moves the spindle and the screw, until the spindle is firmly in contact with the object. The reading on the scale of the thimble is then taken, which gives the distance between the spindle and the anvil face, with a high degree of precision.
Screw gauges are commonly used in a variety of fields, including engineering, machining, and scientific research, where accurate measurements are required.
Screw gauge measures diameter with high accuracy using a screw and nut mechanism. It has a pitch and graduated thimble.
A screw check is an estimating instrument used to gauge the width of items, particularly wires and chambers, with high exactness. It deals with the rule of a screw and nut component.The screw measure comprises of a U-molded outline with a screw toward one side and a thimble at the other.
The screw has a pitch, which is the distance gone by the screw in one complete turn. The pitch is as a rule of the request for 0.5 mm. The thimble is graduated into 50 or 100 equivalent parts. The roundabout scale on the thimble must be changed to such an extent that the zero of the scale matches with the zero of the pitch scale.
To utilize the screw check, the item whose width is to be estimated is set between the iron block and the shaft. The screw is turned until the shaft simply contacts the item. The pitch scale perusing is noted.
The thimble is then turned until the zero of the thimble scale concurs with the middle line of the pitch scale. The thimble scale perusing is then noted. The breadth of the item is then determined by adding the pitch scale perusing and the thimble scale perusing.
Along these lines, a screw check can gauge widths to an exactness of 0.01 mm or better. It is broadly utilized in designing, fabricating, and logical applications.
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A rifle with a weight of 30 N fires a 5.0-g bullet with a speed of 300 m/s. (a) Find
the recoil speed of the rifle. (b) If a 700-N man holds the rifle firmly against his
shoulder, find the recoil speed of man and rifle.
The recoil speed of the rifle is 0.5 m/s.
Weight of the rifle, W = 30 N
Mass of the rifle, M = W/g = 30/10 = 3 kg
Mass of the bullet, m = 5 g = 5 x 10⁻³kg
Speed of the bullet, v = 300 m/s
a) The expression for the recoil speed of the rifle is given by,
v(r) = mv/M
v(r) = 5 x 10⁻³ x 300/3
v(r) = 0.5 m/s
b) Weight of the man, W' = 700 N
Mass of the man, M' = W'/g = 700/10 = 70 kg
So, the combined mass of the man and the rifle,
M₁ = M + M'
M₁ = 3 + 70
M₁ = 73 kg
Therefore, the recoil speed of man and rifle,
v(r)' = mv/M₁
v(r)' = 5 x 10⁻³ x 300/73
v(r)' = 0.0205 m/s
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You are an astronomer and are making observations about a
visible but faraway galaxy. In 2-3 sentences, describe what evidence you could gather to gain more information about (1) the galaxy's elemental
composition and (2) its motion relative to the Milky Way Galaxy.
To determine the elemental composition of the faraway galaxy, would use spectroscopy to analyze the light that is emitted or absorbed by the galaxy. This technique enables me to determine the types of atoms and molecules that are present in the galaxy, providing insights into its elemental composition.
To determine the galaxy's motion relative to the Milky Way, would use the Doppler effect to measure the galaxy's redshift or blueshift. This would enable me to determine whether the galaxy is moving away from or towards us, and at what speed, providing information about its motion relative to our galaxy.
It could also look for any gravitational lensing effects, which could indicate the presence of massive objects that are influencing the galaxy's motion.
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