What is the probality of rolling a 6-sided die on a getting a 1 or a prime number?

Answer:

The question is very not detailed but I assume that because the path will finish does not mean that the whole thing/project will finish.

Step-by-step explanation:

Answer:

(in image attached)

Step-by-step explanation:

A.

Left: 6×-3

Right: -3×-2

Bottom: 6×-2

B.

48÷6 = 8

-42÷6 = -7

-56÷8 = -7

-56÷-7= 8

Rewrite the fractions as decimals by dividing:

7/8 = 0.7777

3/4 = 0.75

1/2 = 0.5

2/3 = 0.666

0.777 is the largest number so 7/9 is the largest fraction.

Answer: 7/9

Answer:

2/3

Step-by-step explanation:

L.C.M:36

7/9:28/36

3/4:27/36

1/2:1836

2/3:36/36

Answer:

CDHG

Step-by-step explanation:

Because you can go in that order and be able to get to the next letter. In the other option you cannot

Answer:

d

Step-by-step explanation:

Answer: ∠1 = 48°, ∠2 = 42°

Step-by-step explanation:

∠M = 90° = ∠1 + (3x)° = (2x + 20)° + (3x)°

2x + 20 + 3x = 90

2x + 3x = 90 - 20

5x = 70

x = 14

∠1 = 2x + 20 = 2(14) + 20 = 28 + 20 = 48°

∠2 = 3x = 3(14) = 42°

(I hope this is right :\)

Answer:

hi.

Step-by-step explanation:

download photo math

The cue ball needs to be hit at a point that is 21.66 inches from the top bumper and 13 inches from the right bumper.

The first step is to calculate the angle at which the cue ball will hit the top bumper. We know that the angle of incidence is equal to the complement of the angle of reflection, so the angle of incidence is equal to 90 - 13/50 = 77 degrees.

The next step is to calculate the distance that the cue ball will travel along the top bumper before it strikes the other ball. We know that the angle of incidence is equal to the angle of reflection, so the angle of reflection is also 77 degrees. We also know that the distance between the cue ball and the other ball is 50 inches.

Using the law of sines, we can write the following equation:

sin(77) = (50 / d) * sin(180 - 77)

where d is the distance that the cue ball will travel along the top bumper before it strikes the other ball.

Solving for d, we get:

d = 50 * sin(77) / sin(103)

≈ 21.66 inches

Therefore, the cue ball needs to be hit at a point that is 21.66 inches from the top bumper and 13 inches from the right bumper.

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Answer:

Step-by-step explanation:

Answer:

h(n) = - 5.3 [tex](-11)^{n-1}[/tex]

Step-by-step explanation:

This is a geometric sequence with explicit formula

h(n) = h(1) [tex](r)^{n-1}[/tex]

where h(1) is the first term and r the common ratio

Here h(1) = - 5.3 and r = - 11 , then

h(n) = - 5.3 [tex](-11)^{n-1}[/tex]

Answer:

-1

Step-by-step explanation:

1. Sets the exponents equal

3b-1 = b-3

2. collect like terms and calculate it

3b-b=1-3

2b= -2

(divide both side by 2)

b=-1

No options are given for the question :

Answer:

t + 10 = 15

Step-by-step explanation:

Given that :

Length of pole = 15 feet

Height below the ground = t

Height above the ground = 10

Tge linear equation which represents the scenario can be modeled as :

Entire length of pole = 15 feets

Length above ground = 10

Length below ground = t

Length below + length above = total length

t + 10 = 15

Answer:

the answer is 35% probability

your welcome

(9-3)+18÷9

= 6+18÷9

= 6+2

= 8

Answer:

8

Step-by-step explanation:

Well, we need to use order of operations. Since there are parenthesis, we solve what is inside that first. So, 9-3=6. We have solved one part of the equation. There are no exponents so division comes next. 18/9=2. Now we are left with 6+2. 6+2=8. Therefore, your final answer is 8.

Answer:

A. Similar - AA

Step-by-step explanation:

The given parameters of ΔPQR and ΔXYZ are;

In ΔPQR, we have; PQ = 3, PR = 5, and ∠PQR = 80°

In ΔXYZ, we have; XY = 6, XZ = 10, and ∠XYZ = 80°

In ΔPQR, by sine rule, we have;

3/(sin(∠PRQ)) = 5/(sin(80°))

sin(∠PRQ) = (3/5) × sin(80°)

∴ ∠PRQ = arc sin((3/5) × sin(80°))

In ΔXYZ, by sine rule, we have;

6/(sin(∠XZY)) = 10/(sin(80°))

sin(∠XZY) = (6/10) × sin(80°) = (3/5) × sin(80°)

∴ ∠XZY = arc sin((3/5) × sin(80°))

∠PRQ = ∠XZY by transitive property of equality

Therefore in ΔPQR and ΔXYZ, we have;

∠PRQ = ∠XZY and ∠PQR = ∠XYZ

Therefore, ΔPQR is similar to ΔXYZ by Angle Angle, AA, similarity postulate.

Answer:

D

Step-by-step explanation:

The percentage of discount on the sweater will be 40%. The correct option is D.

The percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

Given that a sweater is on sale for $45.00, down from $75.00. The percentage discount will be calculated as:-

Percentage discount = (75 - 45) / 75

Percentage discount = ( 30 / 75 )

Percentage discount = 0.4 x 100 = 40%

Therefore, the percentage of discount on the sweater will be 40%. The correct option is D.

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Answer:

. JUST LOAD

Step-by-step explanation:

Answer:

4c+10t

Step-by-step explanation:

c= car

t= time/ hour

Answer:

This triangle is an isosceles triangle because it has two congruent sides. Therefore, the two bottom angles are also congruent. And, the sum of the interior angles of a triangle is 180 degrees.

180 = 104 + (9x - 25) + (9x - 25)

180 = 104 + 18x - 50

180 = 54 + 18x

126 = 18x

x = 7

Hope this helps!

Answer:

honestly this is a very poorly worded question...

it can be interpreted in several different ways....

the cost of the house (for them to purchase it) was

$129,625 + $18,375 = $148,000

The total amount that they paid for the house (money spent)

was  

$129,625 + $18,375 + $273,116 = $421,116

all being said I think that the $148,000 is the answer that the question

is trying for you to figure out

Step-by-step explanation:

Answer:

8 - 4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Given: [tex]\frac{26}{4 + \sqrt{3} }[/tex]

To express the given question in the form a + b[tex]\sqrt{3}[/tex], we first have to rationalize the denominator of the expression.

Rationalizing the denominator, we have;

[tex]\frac{26}{4 + \sqrt{3} }[/tex] * [tex]\frac{4 - \sqrt{3} }{4 - \sqrt{3} }[/tex]  = [tex]\frac{104 -26\sqrt{3} }{16 -4\sqrt{3} + 4\sqrt{3}- 3 }[/tex]

= [tex]\frac{104 - 26\sqrt{3} }{16 - 3}[/tex]

 = [tex]\frac{26(4 - \sqrt{3} }{13}[/tex]

= 2(4 - [tex]\sqrt{3}[/tex])

= 8 - 4[tex]\sqrt{3}[/tex]

The required form of the given question is therefore 8 - 4[tex]\sqrt{3}[/tex]

2^5 = 32

Hope this helps! :)

Answer:

32

Step-by-step explanation:

[tex]2^{5}[/tex]

= 2 × 2 × 2 × 2 × 2

= 4 × 4 × 2

= 16 × 2

= 32

Given:

[tex]\dfrac{3}{4}[/tex] of a number is added to [tex]\dfrac{5}{4}[/tex] it gives the same result as taking [tex]\dfrac{7}{8}[/tex] of the number from [tex]20\dfrac{1}{3}[/tex].

To find:

The unknown number.

Solution:

Let x be the unknown number.

[tex]\dfrac{3}{4}[/tex] of a number is added to [tex]\dfrac{5}{4}[/tex] it gives the same result as taking [tex]\dfrac{7}{8}[/tex] of the number from [tex]20\dfrac{1}{3}[/tex].

[tex]\dfrac{5}{4}+\dfrac{3}{4}x=20\dfrac{1}{3}-\dfrac{7}{8}x[/tex]

[tex]\dfrac{5+3x}{4}=\dfrac{61}{3}-\dfrac{7}{8}x[/tex]

[tex]\dfrac{5+3x}{4}=\dfrac{488-21x}{24}[/tex]

Multiply both sides by 24.

[tex]6(5+3x)=488-21x[/tex]

[tex]30+18x=488-21x[/tex]

[tex]18x+21x=488-30[/tex]

[tex]39x=458[/tex]

Divide both sides by 39.

[tex]x=\dfrac{458}{39}[/tex]

Therefore, the required number is [tex]\dfrac{458}{39}[/tex].

Answer:

1.25% and 16 times

Step-by-step explanation:

Since the interest is compounded quarterly it will be compounded 4 times a year. So 4 x 4 is 16, so it will be compounded 16 times.

Then you have to divide the 5% by four to get how much will be compounded each quarter. So, (0.05 / 4) = 0.0125, which is 1.25%.

Answer:

1.25% and 16 times

Step-by-step explanation:

Answer:

option b is correct

tag me as brilliaiest

Answer:

Option A

Step-by-step explanation:

If the speed of a car in miles per hour (m) is proportional to the speed in kilometers per hour (k),

m ∝ k

m = ck

Here, c = Proportionality constant

Therefore, c = [tex]\frac{m}{k}[/tex] should be constant for each value given in the table.

For m = 11 and k = 17.699,

c = [tex]\frac{11}{17.699}[/tex]

c = 0.6215

For m = 26 and k = 41.834,

c = [tex]\frac{26}{41.834}[/tex]

c = 0.6215

For m = 34 and k = 54.706,

c = [tex]\frac{34}{54.706}[/tex]

c = 0.6215

Therefore, c is constant for each value of m and k.

Option A will be the correct option.

Answer:

(g ￮ f )(- 5) = - 6

Step-by-step explanation:

Evaluate f(- 5), then substitute the value obtained into g(x)

f(- 5) = - 2(- 5) - 7 = 10 - 7 = 3 , then

g(3) = - 4(3) + 6 = - 12 + 6 = - 6

Answer:

[tex](gof)(-5)=-6[/tex]

Step-by-step explanation:

One is given the following information;

[tex]f(x)=-2x-7\\g(x)=-4x+6[/tex]

One is asked to find the following,

[tex](g o f)(-5)[/tex]

The expression ([tex]gof[/tex]) is another way to denote ([tex]g(f(x))[/tex]), in essence, substitute function (f) into function (g) in place of parameter (x). The simplify to find the resulting function;

[tex]g(f(x))\\=-4(-2x-7)+6\\=(-4)(-2x)+(-4)(-7)+6\\=8x+28+6\\=8x+34[/tex]

One is asked to evaluate the function ([tex]gof[/tex]) for (-5). Substitute (-5) into the function and simplify to evaluate;

[tex](gof)(-5)=8x+34\\=8(-5)+34\\=-40+34\\=-6[/tex]

Answer:

On distributing the - sign outside the parenthesis we get,

-2h - 9.6k + 1

Answer:

[tex]( { {x}^{2} })^{2} + 16 {x}^{2} + {8}^{2} \\ ( {x}^{2} + 8) ^{2} \\ ( { {x}^{2} })^{2} - 16 {x}^{2} + {8}^{2} \\ ( {x}^{2} - 8) ^{2} [/tex]