The type of noise pollution that escalated rapidly in the late 1990s was electronic noise pollution.
The late 1990s saw an alarming increase in electronic noise pollution, which is any unwanted or undesired sound caused by electronic devices and appliances. This type of noise pollution can range from the humming of air conditioning units to the buzzing of computer servers, and is one of the leading causes of environmental degradation.
As such, it is important for individuals, businesses, and government organizations to take proactive steps to reduce this type of noise pollution. By investing in sound-proofing measures and noise-canceling technology, we can ensure that our environment remains free of unwanted electronic noise pollution.
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If 30 J are added by heat to water at 12°c, what is the change in entropy? a. 0.05J/K b. 6.0.1 J/K. c. 0.15 J/K d.0.2 J/K
If 30 J are added by heat to water at 12 °c, the change in entropy is calculated to be 0.105 J/K.
Entropy is the measure of disorder in a system, it tells about how much energy is not available to do work.
Mathematically, entropy is Δs = Q/T
where,
Q is heat transferred
T is temperature in kelvin
Δs is change in entropy
Heat energy Q is given as 30 J.
Temperature T = 12 + 273 = 285 K
Δs = Q/T = 30/285 = 0.105 J/K
Thus, if 30 J are added by heat to water at 12 °c, the change in entropy is calculated to be 0.105 J/K.
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what is the vertical distance, in meters, from where the projectile was launched to where it hits the target?
Without gravity, a projectile would climb vertically by a factor equal to time times the vertical component of its starting velocity (viy• t). It will fall 0.5 g t2 distance in the presence of gravity.
How can I calculate a projectile's vertical range?h = v 0 y 2 2 g . The maximum height a projectile can reach above its launch site is defined by this equation, which only depends on the vertical component of the starting velocity.
A vertically propelled projectile is what?In a vertical launch, an object is sent up or down vertically from a height H without taking into account any air resistance or other obstacles. It is a uniformly accelerated rectilinear motion (u.a.r.m.) where gravity serves as the acceleration.
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a cannon ball leaves a cannon traveling at 35 m/s at an angle of 45 degrees above the horizontal. determine the speed of the ball when it reaches 50 meters above the ground
The vertical speed of the ball will be 0.029 m/s, when it reaches 50 meters above the ground.
The projectile speed of the ball, v = 35 m/s
Angle of projectile motion, θ = 45°
Vertical component of velocity, u = 35sin45 = 24.75 m/s
Height of the ball, h = 50 m
Let the time taken to reach the ball is t sec, then by the second equation of motion,
h = ut - 0.5gt²
50 = 24.75×t - 0.5×9.81×t²
4.905t² - 24.75t + 50 = 0
On solving t = 2.52 & 4.905
Ignoring the t = 4.905 as it is during the freefall motion, so taking t = 2.52 sec.
Now by the first equation of motion,
v = u + at
v = u - gt
v = 24.75 - 9.81 × 2.52
v = 0.029 m/s
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Which preconnected hose load has hose folds that are laid into the hose bed in an S-shape?
Select one:
a.Minuteman load
b.Preconnected combination load
c.Triple layer load
d.Preconnected flat load
The preconnected hose load with hose folds laid into the hose bed in an S-shape is known as a "Minuteman Load."
A Minuteman load is a type of fire hose that is pre-connected and stored on a fire truck in a compact, organized manner. The hose is folded in an S-shape pattern and stored on the hose bed, which makes it easy for firefighters to access and deploy quickly in case of an emergency. The S-shape pattern helps prevent kinks and twists in the hose, which can slow down the flow of water and reduce the effectiveness of the firefighting effort. The compact storage also saves space on the fire truck and reduces the amount of time needed to deploy the hose. In addition, Minuteman loads are often made with high-quality materials that are resistant to abrasion, heat, and bchemicals, making them durable and long-lasting. Overall, the Minuteman load is a convenient and efficient way for firefighters to store and deploy fire hoses in the field.
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2. A boulder is shoved by a bulldozer at 2.3m/s and falls from a
72m high cliff. How far from the base of the cliff will the
boulder land?
The boulder will land approximately 81.3 meters from the base of the cliff.
How far from the base of the cliff will the boulder land?The distance from the base of the cliff that the boulder will land can be calculated using the equation d=ut+1/2at^2, where d is the distance, u is the initial velocity, t is the time, and a is the acceleration due to gravity (9.8m/s^2).Using the given values, the equation becomes d=2.3t+1/2(9.8t^2). By solving for t, and inserting the value into the equation, the distance from the base of the cliff is calculated to be 577.4m.This type of calculation is called projectile motion. Projectile motion is the motion of an object traveling in a curved path, such as a ball or a boulder, due to the combined forces of gravity and inertia.In this particular example, the only force acting on the boulder is gravity, so it follows a parabolic path, reaching its highest point at the top of the cliff before falling back down to the base.The equation used to calculate the distance of the boulder is based on the principles of kinematics, which is the study of motion and the forces that cause it.To learn more about projectile motion refer to:
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what is the electron's speed after traveling 1.4 cm ? express your answer with the appropriate units.
The electron's speed after traveling 1.4 cm without knowing its original speed.
What is electron's speed?The speed of an electron is the speed of light in a vacuum, which is approximately 299,792,458 meters per second. Electrons are fundamental particles, and they travel at the speed of light due to the fact that they possess no mass. They are affected by electromagnetic fields, which can cause them to accelerate or decelerate, but they will always move at the speed of light when in a vacuum.
The electron's speed after traveling 1.4 cm cannot be determined without knowing its original speed. The electron's speed is a measure of its velocity, which is the rate of change of its position. Therefore, it is not possible to calculate the electron's speed after traveling 1.4 cm without knowing its original speed.
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correct answer is aaa
?
Answer:
it is in the direction of flow of elections
a wooden box is sitting on a table. the normal force on the box from the table is 75 n. a second identical box is placed on top of the first box. the normal force on the first box by the table will
The normal force on the first box from the table will stay at 75 N even after a second box is placed on top of it.
The normal force is a contact force that is determined by the weight of the object, as well as the interaction between the two surfaces in contact. The regular force that the table normally applies to the first box will stay unchanged because the weight of the box has not changed.
The normal force, which is equivalent in strength to gravity's force and acts in the opposite direction, is a force that is perpendicular to the surface of contact. The box is prevented from dropping through the table's surface by this reactionary force.
In other words, the normal force is equivalent to the object's weight, which in this instance is 75 N.
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Both copper and ilver are good conductor of electricity but only copper i ued for making electric wire and not ilver why?
Both copper and silver are good conductor of electricity but only copper is used for making electrics wire and not silver because silver is expensive material when compared to copper.
Despite the fact that silver is an excellent heat conductor, it is not used in the production of electrical wire because of its high cost. Silver is a valuable metal that is used to make jewelry, high-value coins, and electroplating. Because of this, silver is not used to make electric wires. When it is exposed to air, silver quickly oxidizes and becomes tarnished.
Copper is nearly always utilized because of its low cost and the fact that it is an adequate conductor for the majority of uses. In comparison to copper, silver has a resistivity that is just marginally lower; yet, due to its higher density, the two elements are almost comparable in terms of their ratio of resistivity to mass.
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which material is excellent for use as seals and diaphragm for water lubricated bearings? a. Rubber b.Titanium alloy c. Silicon d. Uranium
For seals and diaphragms in water lubricated bearings, rubber is an excellent material to use.
For seals and diaphragms in water lubricated bearings, rubber is an excellent material to use due to its properties of elasticity, flexibility, and durability. Rubber is able to withstand the pressure and wear caused by water movement, and its elasticity allows it to maintain a tight seal against the bearing surfaces.
Titanium alloys are known for their strength and corrosion resistance, but they may not have the necessary elasticity and flexibility for use as seals and diaphragms in water lubricated bearings. Silicon is commonly used in the electronics industry, but it may not have the necessary properties for use in these types of bearings. Uranium is a highly radioactive material and is not appropriate for use in seals or diaphragms in any type of machinery. Therefore, the answer is (a) rubber.
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letter “a” id point to slope of the graph, what letter in physics is used to represent the relationship between the force and spring stretch?
Letter “b” is pointing to the stretch variable in the graph, what letter in physics is used to represent the stretch of the spring. (This is a form of distance)
The letter "x" is used to represent the stretch of a spring in physics.
What letter in physics is used to represent the relationship between the force and spring stretch?The letter used to represent the stretch of a spring in physics is "x".This is a form of distance that is used to represent the displacement of a spring by the force applied to it. In the graph, the variable "x" is used to represent the amount of stretch that is occurring in the spring due to the force (represented by the line).The relationship between the force and the spring stretch is known as Hooke's Law and states that the force applied to a spring is directly proportional to the amount of stretch that occurs.This means that as the force increases, the amount of stretch will also increase.By understanding this relationship, engineers and scientists can accurately predict the amount of force that needs to be applied to achieve a specific amount of stretch.To learn more about the stretch of a spring in physics refer to:
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a 1.15 kg ball (m1) moving at 5.00 m/s to the right hits a 2.15 kg ball (m2) head-on that is traveling at 3.50 m/s to the left. if this is an elastic collision, what is the velocity of each ball after the collision?
The speed of the ball having mass 1.15 kg and this 2.15 kg is 3.48m/s and 1.06m/s respectively after collision.
The ball having a mass of 1.15 kg is moving at a speed of 5m/s to the right and it hits A ball of mass 2.15 kg head on travelling with a speed of 3.5m/s to the left if the collision is elastic collision, then the speed of the balls after collision will be given by the formula,
v = 2mu/(M+m)
V = (M-m)U/(M+m)
Here,
m = 1.15 kg,
M = 2.15 kg,
u = 5m/s,
U = 3.5m/s.
v is speed of ball moving to right after collision and V is the speed of ball having mass 2.15 kg moving left after collision.
Putting values,
v = 3.48m/s and,
V = 1.06m/s.
So, the speed of the ball having a mass 1.15 kg after collision is 3.48m/s and the speed of the ball having mass 2.15 kg of the collision is 1.06m/s.
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19.78 g of copper is heated from 15 °c to 48 °c. how much heat was needed in joules?
To calculate the amount of heat required to raise the temperature of 19.78 g of copper from 15 °C to 48 °C, you need to use the equation for heat transfer:
q = mcΔT
where q is the heat transfer, m is the mass of the copper, c is the specific heat capacity of copper, and ΔT is the change in temperature.
The specific heat capacity of copper is approximately 385 J/kg°C. Therefore, the heat transfer can be calculated as follows:
q = (19.78 g) * (385 J/kg°C) * (48 °C - 15 °C)
where the mass is first converted to kilograms and the temperature change is calculated in Celsius.
The heat transfer required to raise the temperature of 19.78 g of copper from 15 °C to 48 °C is approximately 31,739 J.
It is important to note that this calculation assumes that no heat is lost to the surroundings and that all the heat energy is absorbed by the copper. In reality, some heat energy may be lost to the surroundings, so the actual heat energy required may be slightly higher.
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A ring of radius R has total charge Q.
A) At what distance along the
z-axis is the electric field strength a maximum?
Express your answer in terms of R.
B)What is the electric field strength at this point?
Express your answer in terms of the variables Q, R, and ?0
A) E = k * Q / R^2, electric field strength is maximum at R. B) Electric field strength at this point is E is k * Q / R^2 = k * Q / R^2,
What is electric field strength?A quantitative expression of the intensity of electric field at a particular location is called electric field strength.
A) Electric field strength is maximum at a distance of R from the ring, along the z-axis and the expression for the electric field strength can be given as: E = k * Q / R^2
k is Coulomb's constant and R is distance from the center of ring to the point where electric field is being calculated. Hence, the electric field strength is maximum at R.
B) Electric field strength at a distance of R from the center of the ring along the z-axis can be expressed as: E = k * Q / R^2
k is Coulomb's constant and R is radius of ring. Hence, the expression for the electric field strength at the point where it is maximum is:
E is k * Q / R^2 = k * Q / R^2,
k, Q, and R are variables and value of k is constant, equal to 8.99 * 10^9 N * m^2 / C^2. Variables Q and R are total charge on the ring and the radius of the ring respectively.
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A particle moves in such a way that its position z, in meters,is given as a function of t, in seconds, by the equations z=c1t^2-c2t^3
C1=2.12m/s/s C2=3.29m/s/s/s
The particle is at 0 twice. What is the time of the second occurrence of z=0 in seconds?
What is the displacement(m) of the particle between 2sec and 5 sec?
What is the velocity of the particle at t=0.657s?
The velocity is also at 0 twice. What is the time of the second occurence?
(1) The time of the second occurrence is 2.92 s (2) displacement is 29.24 m (3) velocity of the particle is 4.86 m/s (4) the time of second occurence is 2.94 s.
Given z = c1t^2 - c2t^3 and c1 = 2.12 m/s^2 and c2 = 3.29 m/s^3.
1) The particle is at z = 0 twice. To find the second occurrence, we set z = 0 and solve for t:
0 = 2.12t^2 - 3.29t^3
This is a cubic equation and can be solved using numerical methods or by using a computer algebra system.
The second solution is approximately t = 2.92 s.
2) The displacement of the particle between 2 s and 5 s can be found by finding the final position minus the initial position:
Δz = z(5s) - z(2s) = (2.12 × 5^2 - 3.29 × 5^3) - (2.12 × 2^2 - 3.29 × 2^3)
Δz = 29.24 m
3) The velocity of the particle is given by the derivative of the position function, so we can find the velocity at t = 0.657 s as:
v = dz/dt = 2c1t - 3c2t^2 = 2 × 2.12 × 0.657 - 3 × 3.29 × 0.657^2
v = 4.86 m/s
4) The velocity is at 0 twice. To find the second occurrence, we set v = 0 and solve for t:
0 = 2 × 2.12t - 3 × 3.29t^2
This is a quadratic equation and can be solved using the quadratic formula or by using a computer algebra system.
The second solution is approximately t = 2.94 s.
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Question - A particle moves in such a way that its position z, in meters, is given as a function of t, in seconds, by the equations z=c1t^2-c2t^3
1) The particle is at 0 twice. What is the time of the second occurrence of z=0 in seconds?
2) What is the displacement(m) of the particle between 2sec and 5 sec?
3) What is the velocity of the particle at t=0.657s? The velocity is also at 0 twice.
4) What is the time of the second occurence?
An object is released from rest at top at Plane at an the top of a rough plane at an angle of 30° to the horizontal. and 4.0m high. It the coettiment of friction is 0.3, calculate- take the time the body takes to reach the bottom of the plane Take [g=10m/s]
Answer:
It takes the object 2.581 seconds to reach the bottom of the plane.
Explanation:
We will need to use Newton's Second Law to answer this question.
According to Newton's Second Law, acceleration is directly proportional to the net force and inversely proportional to the object's mass. Therefore the acceleration of an object depends on the mass of the object and the amount of force applied.
[tex]F_{net}=ma[/tex]
Lets identify all the forces affecting the motion of the object.
The force due to gravity has two components; the horizontal (parallel) and vertical (perpendicular).
The force parallel to the plane trying to accelerate the block down the plane is
[tex]mg\sin \theta[/tex]
The perpendicular force balances out with the normal force. The normal force is equal to the force of the object perpendicular to the plane.
[tex]mg\cos\theta[/tex]
We also have a force opposing the motion of the object; the force due to friction. The formula for the force due to friction is
[tex]F_F=F_N\mu[/tex]
[tex]F_F=\mu mg\cos \theta[/tex]
We can say the net force of the object is
[tex]ma=mg\sin \theta -\mu mg\cos \theta[/tex]
We can simplify this by cancelling the common factor of [tex]m[/tex].
[tex]a=g\sin \theta - \mu g\cos \theta[/tex]
We are given
[tex]\theta=30 \textdegree\\\mu=0.3\\h=4\\g=10[/tex]
Substituting our values into the equation gives us
[tex]a=10*\sin 30- 0.3* 10*\cos 30[/tex]
Acceleration
Lets simplify.
[tex]a=10*\frac{1}{2} - 0.3* 10*\cos 30[/tex]
[tex]a=10*\frac{1}{2} - 0.3* 10*\frac{\sqrt{3} }{2}[/tex]
[tex]a=5- 0.3* 10*\frac{\sqrt{3} }{2}[/tex]
[tex]a=5-3*\frac{\sqrt{3} }{2}[/tex]
[tex]a=5-\frac{3\sqrt{3} }{2}[/tex]
[tex]a=2.402[/tex]
Plane Length
We are given the angle and the side opposite to the angle.
We can use the SIN function to evaluate the length of the plane.
[tex]O[/tex] is the opposite side (height)
[tex]H[/tex] is the hypotenuse (plane length)
[tex]\sin \theta=\frac{O}{H}[/tex]
Solving for [tex]H[/tex] gives us
[tex]H=\frac{O}{\sin \theta}[/tex]
Given
[tex]O=4\\\theta=30[/tex]
[tex]H=\frac{4}{\sin 30}[/tex]
[tex]H=\frac{4}{\frac{1}{2} }[/tex]
[tex]H=4*2[/tex]
[tex]H=8[/tex]
The length of the plane is 8 meters.
Time
We can evaluate the time using this motion equation.
[tex]\Delta x=v_ot+\frac{1}{2} at^2[/tex]
We are given
[tex]\Delta x=8\\v_o=0\\a=2.402[/tex]
Substituting our values into the equation gives us
[tex]8=0*t+\frac{1}{2} *2.402*t^2[/tex]
Lets simplify and evaluate [tex]t[/tex].
[tex]8=\frac{1}{2} *2.402*t^2[/tex]
[tex]8=1.201*t^2[/tex]
[tex]\frac{8}{1.201}=t^2[/tex]
[tex]6.66=t^2[/tex]
[tex]\sqrt{6.66}=t[/tex]
[tex]2.581=t[/tex]
can the temperature of a system remain constant even though heat flows into or out of it? if so, give examples.
can the temperature of a system remain constant even though heat flows into or out of it? if so, give examples.
It is possible for a system's temperature to stay constant despite heat flow. It's called an isothermal process.
The average thermal energy of a system's component particles is gauged by the temperature of the system. The heat transfer that occurs between the system and its surroundings may be described using this state variable, which is what it is called. Heat flow can have an impact on a system's temperature, but under some circumstances, it won't change the temperature of the system.
Some instances are:
1. Containers with internal heat sources or sinks that are thermally insulated.
2. In an insulated piston-cylinder arrangement, adiabatic expansion or compression of ideal gases.
3. The gas expands isothermally as it travels through a porous stopper due to the Joule-Thomson effect.
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A converging lens with a diameter of 49.8 cm
forms an image of a satellite passing overhead.
The satellite has two green lights (wavelength
508 nm) spaced 1.1 m apart.
If the lights can just be resolved according
to the Rayleigh criterion, what is the altitude
of the satellite?
Answer in units of km.
The altitude of the satellite is 883.89 km
What is the altitude?Generally, The Rayleigh criterion for resolution states that the minimum angle, θ, between two point sources that can be resolved is given by:
θ = 1.22 * λ / D
where
λ is the wavelength of light and
D is the diameter of the lens.
The minimum distance, d, between two point sources that can be resolved is given by:
d = θ * L
where
L is the distance from the lens to the image.
Given the green lights have a wavelength of 508 nm, we can convert it to meters:
λ = 508 * 10^-9 m
Given the diameter of the lens is 49.8 cm, we can convert it to meters:
D = 49.8 cm * (1 m / 100 cm)
= 0.498 m
Using the Rayleigh criterion, we can find the minimum resolvable angle:
θ = 1.22 * λ / D
= 1.22 * 508 * 10^-9 / 0.498
= 1.24449799*10^{-6} radians
We know the lights on the satellite are spaced 1.1 m apart, so:
d = 1.1 m
Solving for the distance from the lens to the image, L:
L = d / θ
= 1.1 m / 1.24449799*10^{-6} radians
=883890.53 m
Finally, converting the distance to kilometers:
L = 883890.53 m * (1 km / 1000 m)
= 883.89 km
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a physician orders a diagnostic mammogram for a 42-year-old woman. which of these most likely happened before this decision was made?
A 42-year-old lady is prescribed a diagnostic mammography by a doctor. On a routine screening mammography, abnormal tissue was discovered. Values for the CBC, blood markers, or blood chemistry were abnormal.
An x-ray of a breast for diagnostic purposes is called mammogram.
As cancer cells are less specialised than healthy cells, they create abnormal proteins.
If cancer has been indicated by a suspicious lump or abnormal blood tests, then the type of body imaging which is next step is called diagnostic mammogram.
Chemotherapy functions to combat cancer because it targets characteristics of fast growing cancer cells. This means they target specific points of the cell cycle to stop cell division.
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"they changed the name from global warming to climate change because global warming stopped happening" what type of scientific misconception would you classify this as?
Answer:
This statement is a common misconception and would be classified as misinformation. The term "global warming" is often used to refer to the overall increase in the Earth's average surface temperature, which is primarily caused by human activity, such as the burning of fossil fuels and deforestation. The term "climate change" is used to describe the broader range of changes that are occurring in the Earth's climate, including not only warming but also changes in precipitation, sea level, and other factors. While there have been periods of slower warming, the Earth's average surface temperature has continued to rise overall, and is projected to continue to do so in the future.
if a galaxy is at z =1.0, what does this mean? how is this typically measured?
The value "z = 1.0" is given to a galaxy redshift, which is a measurement of how much the galaxy's light's wavelength has been distorted as it travels through the expanding cosmos.
Redshift is expressed as a fractional value "z", where z = (λ observed - λ emitted) / λ emitted. In this case, "z = 1.0" means that the observed wavelength of light from the galaxy has been stretched by a factor of 1 (i.e., the wavelength has doubled). Redshift is typically measured using spectroscopy, which involves splitting the light from the galaxy into its individual spectral lines and comparing the observed wavelengths to the wavelengths of the same spectral lines in a laboratory or a theoretical reference spectrum. By measuring the redshift of a galaxy, astronomers can determine its distance from us and its motion relative to us. The interpretation of a redshift as a measure of distance is based on the idea that the universe is expanding, and that the farther away a galaxy is from us, the faster it will be moving away from us due to the expansion of the universe. This leads to an increase in the observed wavelength of its light (i.e., redshift), which can be used to estimate the galaxy's distance.
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how long does it take from the moment when the motorcycle starts to accelerate until it catches up with the car? in other words, find
The equations of motion are used to find the motion characteristics of an object with time.The time it takes the motorcycle to reach the car is approximately 5.39 seconds
Find the solution ?A) The time it takes the motorcycle to reach the car is approximately 5.39 seconds
B) The distance the motorcycle travel from the moment it starts to accelerate to the moment it catches up with the car is approximately 155 meters
The reason the above values are correct is as follows:
The given parameters are;
The initial speed of the car and the motorcycle, v₁ = 18.0 m/s
The initial distance between the motorcycle following the car = 58.0 m
The time after which the motorcycle starts to accelerate, t₁ = 5.00 secs
The acceleration of the motorcycle = 4.00 m/s²
The time at which the motorcycle catches up with the car = t₂
Required:
A) The time it takes the motorcycle to accelerate before it catches up with the car, which is to find t₂ - t₁
Method:
The distance moved by motorcycle to reach the car = The distance moved by the car in the same time + 58.0 meters
The appropriate equation of motion to use are s = u \cdot t + \dfrac{1}{2} \cdot a\cdot t^2 and d = u\cdot t
Where;
s = The distance between the motorcycle and the car = 58.0 m
u = The initial velocity of the motorcycle = 18.0 m/s
t = Δt = t₂ - t₁ = The time the motorcycle accelerates
a = The acceleration of the motorcycle = 4.00 m/s²
d = The distance moved by the car
By the method, we have;
s = d + 58.0
u \cdot t + \dfrac{1}{2} \cdot a\cdot t^2 = u \cdot t
Plugging in the values into the equation gives;
(18.0 \times t) + \dfrac{1}{2} \times 4 \times t^2 = (18.0 \times t) + 58.0
Cancelling the like term, (18.0 × t), on both sides of the equation gives;
\dfrac{1}{2} \times 4 \times t^2 = 58.0
2\cdot t^2 = 58.0
t = \Delta t = \sqrt{\dfrac{58.0}{2} } = \sqrt{29} \approx 5.39
The time it takes the motorcycle to reach the car, t ≈ 5.39 second
The time it takes the motorcycle to reach the car is approximately 5.39 seconds
B) Required:
The distance the motorcycle travels from the moment it starts to accelerate, t₁ to the time it catches up with the car, t₂
Method:
The distance travelled during the time interval t₂ - t₁ should be calculated
The distance, s, travelled during the time interval t_2 - t_1 = \Delta t = t is given as follows;
s = u \cdot t + \dfrac{1}{2} \cdot a \cdot t^2
From part (A), u = 18.0 m/s t = \sqrt{29} s, and a = 4.00 m/s², therefore;
s = 18.0 \times \sqrt{29} + \dfrac{1}{2} \times 4.00 \times (\sqrt{29} )^2 \approx 154.933
Rounded to three significant figures, the distance the motorcycle travel, s = 155 meters
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find the capacitance of a parallel-plate capacitor made of two 4.0 cm x 4.0 cm metal plates if the plates are separated by 5.0 mm.
The capacitance of a parallel-plate capacitor made of two 4.0 cm x 4.0 cm metal plates if the plates are separated by 5.0 mm is 0.073 F (or 73 nF).
The capacitance of a parallel-plate capacitor can be calculated using the formula:
C = ε_0 × A / d
where:
C is the capacitance in Farads
ε_0 is the vacuum permittivity constant (8.854 x 10⁻¹² F/m)
A is the area of each plate in square meters
d is the distance between the plates in meters
So, for the given parallel-plate capacitor:
A = 4.0 cm x 4.0 cm = 0.04 m x 0.04 m = 0.0016 m²
d = 5.0 mm = 5.0 x 10⁻³ m
C = ε_0 × A / d
C = 8.854 x 10⁻¹² F/m * 0.0016 m² / 5.0 x 10⁻³ m
C = 0.073 F (or 73 nF)
Therefore, the capacitance is 0.073 F (or 73 nF)
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A cart with a mass of 120 kg collides with a stationary dumpster with a mass of 300 kg. Both the cart and the dumpster are free to roll in any direction. The cart and the dumpster stick together after the collision and move at 0.5 m/s. What other information is needed to determine the final momentum of the dumpster?
Other information needed to determine the final momentum of the dumpster is : the initial velocity of the cart.
What is collision?In physics, collision is any event in which two or more bodies exert force on each other in relatively short time. Although, most common use of the word collision refers to incidents in which two or more objects collide with great force, scientific use of the term implies nothing about the magnitude of force.
Collision is a short-duration interaction between two bodies or more than two bodies simultaneously causing change in the motion of bodies involved due to the internal forces acted between them during this.
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the ability to keep an object in the center of your field of view when moving from one objective to another is called:
The ability to keep an object in the center of your field of view when moving from one objective to another is called parfocality.
Parfocality is an important feature of compound microscopes, as it allows you to quickly switch between objective lenses while maintaining the same field of view.
This allows you to maintain the same field of view when changing objectives and quickly switch between different magnification powers. Parfocality also prevents the image from becoming blurred when switching objectives, as the object remains in the center of the field of view.
Additionally, parfocality ensures that the object is always in the same position in the field of view, regardless of the objective used. This makes it easier to observe and compare objects at different magnifications.
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our sun's blackbody temperature is about 6000 k and its peak radiation occurs at a wavelength of about 0.5 micrometers. some stars are bluer than our sun with temperatures of 10,000 k. at what wavelength does their radiation peak?
The peak radiation of a star with a temperature of 10,000 K will occur at a wavelength of approximately 0.3 micrometers.
What is peak radiation?Generally, The peak wavelength of a blackbody's radiation is inversely proportional to its temperature.
This means that as the temperature of the blackbody increases, the wavelength of its peak radiation decreases.
In this case, the temperature of the star is higher than our sun, so its peak radiation will occur at a shorter wavelength.
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is it possible to have a description of motion without a frame of reference? group of answer choices no, because motion is relative. no, because motion is absolute. yes, because motion is absolute. yes, because motion is relative.
No, because motion is relative.
Without a frame of reference, it is impossible to characterise the motion of the body. Motion is always described in relation to a chosen frame of reference since it is relative.
The frames of reference on this page are all classical (i.e., Special Relativity's effects are disregarded), and inertial (meaning the frames are not accelerating relative to one another). In all inertial frames, the laws of physics are the same (this is known as Galilean invariance). To put it another way, you cannot conduct an experiment to establish which reference frame you are in (Einstein used this hypothesis to devise the theory of Special Relativity). This implies that we can approach problems and provide a comparable answer in any reference frame.
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what unit would you use to measure thge distance to australia
The measurement unit we would use to measure the distance of Australia is Kilometer.
There are various units of measurement of length and distance. But they are used on the basis of the scale of measurement or on the basis of the accuracy required to measure anything. Like meter is used to measure the dimension of a field, a ground, cricket pitch, similarly inches, or cm are used to measure the length of the cloths, size of our shoes, etc. Whereas long distance like the distance between two cities, or countries are measure by kilometer or miles. 1 kilometer is equal to 1000 meters and one mile is equal to 1061 meters.
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A 45 kg firefighter is working on a ladder 20 m above the ground. What will be the firefighter's gravitational potential energy decrease by when the firefighter descends to a height of 5 m above ground?
Height above Earth affects the gravitational potential energy of an item. We know the height of the ball lowers since it is rolling down a hill.
How do you calculate decrease in gravitational potential energy?Moving downward over a distance h results in an equal increase in kinetic energy and a loss of gravitational potential energy. This can be expressed mathematically as -PEg = KE.The potential energy of an object diminishes while its kinetic energy rises. The increase in kinetic energy perfectly offsets the reduction in potential energy.A doubling of the height will result in a doubling of the gravitational potential energy since the gravitational potential energy of an object is precisely proportional to its height above the zero point. The gravitational potential energy will triple for every threefold increase in height.The gravitational potential energy of the ball then reduces as a result of the height decreasing.To learn more about energy refer to:
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21.5 °c; volume of gas in syringe:
The values for the molar volume obtained from the two reactions are very close, and we can conclude that the molar volume of the gas produced in the reactions is approximately 5.3 × 104 L/mol at 21.5°C.
The molar volume of a gas can be calculated by dividing the volume of the gas by the number of moles of gas produced. To compare the values for the molar volume obtained from the two reactions, we need to determine the number of moles of gas produced in each reaction.
For experiment 1, the mass of zinc added was 0.100 g, and the molar mass of zinc is 65.38 g/mol, so the number of moles of zinc added is 0.100 g / 65.38 g/mol = 0.00153 mol. The volume of gas produced in the reaction is given by the volume in the gas syringe, which is 36.81 ml. At 21.5°C and 1 atm, 1 ml of a gas has a volume of 22.4 liters, so the volume of gas produced in the reaction is 36.81 ml * 22.4 L/ml = 817.24 L. Therefore, the molar volume of the gas produced in experiment 1 is 817.24 L / 0.00153 mol = 5.30 × 104 L/mol.
For experiment 2, the mass of zinc added was 0.200 g, and the molar mass of zinc is 65.38 g/mol, so the number of moles of zinc added is 0.200 g / 65.38 g/mol = 0.00306 mol. The volume of gas produced in the reaction is given by the volume in the gas syringe, which is 73.64 ml. At 21.5°C and 1 atm, 1 ml of a gas has a volume of 22.4 liters, so the volume of gas produced in the reaction is 73.64 ml * 22.4 L/ml = 1634.48 L. Therefore, the molar volume of the gas produced in experiment 2 is 1634.48 L / 0.00306 mol = 5.31 × 104 L/mol.
As we can see, the values for the molar volume obtained from the two reactions are very close, and we can conclude that the molar volume of the gas produced in the reactions is approximately 5.3 × 104 L/mol at 21.5°C.
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The complete question is:
Calculate and compare the value for the molar volume at 21.5 °C obtained based on the data for the first reaction with the value for the molar volume at 21.5 °C obtained using the second reaction. The molar mass of Zn is 65.38 g/mol. experiment 1 HCL: 45 ml Zn: 0.100 g pressure before zinc was added to HCL: 1.000 atm pressure after: 1.138 atm temp before: 21.5 C temp after: 22.3 C volume in gas syringe: 36.81 ml experiment 2 HCL: 45 ml Zn: 0.200 g pressure before zinc was added to HCL: 1.000 atm pressure after: 1.277 atm temp before: 21.5 C temp after: 23.0 C volume in gas syringe: 73.64 ml.
