What would happen if N₂ were added to N₂(g) + O₂(g) = 2NO(g) at
equilibrium?
O A. More O2 and NO would form.
OB. More NO would form.
C. More N₂ and O2 would form.
O D. Keq would decrease.

Chiari type ii malformation associated with myelomeningocele can lead to severe morbidity and mortality if it is not identified and treated promptly.

People diagnosed with myelomeningocele have abnormalities of the brain and spine, including spinal cord defects and symptoms related to the area in which the spinal column and the brain meet, known as Chiari malformation. Chiari Type II or Arnold-Chiari malformation is a worse form in which the cerebellar vermis and some portion of the brain stem descend into the cervical chine.

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Ethylene glycol has a specific heat of 0. 578 cal/(g°c). If 23.2 g of ethylene glycol absorbs 75.6 cal of heat energy. The temperature increase be 5.64°C.

The amount of heat needed to raise the temperature of 1 kg of substance.

It is expressed as

Q = mcΔT

where,

Q = Heat energy

m = Mass

c = Specific heat capacity

ΔT = Change in temperature.

Here,

Q = 75.6 cal

m = 23.3 g

c = 578  cal/(g°c)

Now put the values in above formula we get

Q = mcΔT

75.6 cal = 23.2 g ×  578  cal/(g°c) × ΔT

ΔT = 5.64°C

Thus from the above conclusion we can say that Ethylene glycol has a specific heat of 0. 578 cal/(g°c). If 23.2 g of ethylene glycol absorbs 75.6 cal of heat energy. The temperature increase be 5.64°C.

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The preparation of lead (ii) sulphate from lead (ii) carbonate occurs in two steps:

Lead (ii) carbonate and  lead (ii) sulphate are both insoluble salts of lead.

In order to prepare lead (ii) sulphate, a two step process is performed.

In the first step, Lead (ii) carbonate is reacted with dilute trioxonitrate (v) acid to produce lead (ii) nitrate.

In the second step, dilute sulfuric acid is reacted with the lead (ii) nitrate to produce insoluble lead (ii) sulphate which is filtered and dried.

In conclusion, lead (ii) sulphate is prepared in two steps.

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1.35 Litres of water need to be added to 750 ml of a 2.8 m hcl solution to make a 1.0 m solution.

Use the following relation:

M1V1=M2V2

Where M is molarity, V is volume and 1 is initial and 2 is the final conditions. Solving for V(2)

M1=2.8 M,V1=750 mL;M2=1.0 M

(2.8 M)×(750 mL)=(1.0 M)×V2

V2=(2.8 M)×(750 mL)(1.0 M) = 2100 mL = 2.1 L

Therefore, Volume of water to be added =2.1 L−0.75 L=1.35 L

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The pressure in atm is 6.8.

Calculation,

According to ideal gas law,

PV = nRT           ..(i)

Putting the value of all given data in equation (i) we get,

P×5.43 L =  1.82 moles ×247.50 K × 0.082 atm L/K mol

P =  1.82 moles ×247.50 K × 0.082 atm L/K mol /5.43 L = 6.8 atm

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NaHCO3 is can be mixed in solution with H₂CO3 to make a buffer.

Sodium bicarbonate (IUPAC name: sodium bicarbonate, commonly known as baking soda or sodium bicarbonate) is a compound with the chemical formula NaHCO3. It is a salt composed of a sodium cation (Na+) and bicarbonate anion (HCO3-). Sodium bicarbonate is a crystalline white solid that often looks like a fine powder. It has a slightly salty, alkaline taste similar to soda carbonate (sodium carbonate). The natural mineral form is Narcolite. It is a component of sodium bicarbonate and is dissolved in many mineral springs.

Sodium bicarbonate is an antacid used to relieve heartburn and acid indigestion. Doctors may also prescribe sodium bicarbonate to reduce the acidity of blood and urine under certain conditions.

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3.01× 1024 particles are the number of  particles are there in 5 grams of sodium carbonate.

There are 6.022 × 1023 particles in one gram of a substance according to Avogadro's number. So when we find out for 5 grams, then we multiply 5 with 6.022 × 1023, we get 3.01 × 1024 particles. For one gram atomic weight of hydrogen, one mole of hydrogen contains 6.022 × 1023 hydrogen atoms.

So we can conclude that 3.01× 1024 particles are the number of  particles are there in 5 grams of sodium carbonate.

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Soil particles, soot, lead (pb), asbestos, sea salt, and sulfuric acid droplets are all types of particulate matter.

The atmosphere is dusty .The solid and liquid particles suspended in the atmosphere .

Examples : Soil particles, soot, lead (pb), asbestos, sea salt, and sulfuric acid droplets are all types of particulate matter

There are different categories of particulate matter. Such as mold spores , bacteria , dust , smoke and airborne viral paricles. The major sources of particulates matter are wildfires , dust storms , sea spray , volcanic eruption , and industrial process.

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Developing enduring relationships and sensing love - Taking care of others fosters empathy and the capacity to connect with others, especially through trying circumstances. Additionally, 77% of caregivers who are also employed claim that their relationship with their parents and/or in-laws has improved as a result of their caregiving.

Family supports us during both the best and worst of times, which makes these ties crucial. Family is crucial because they can provide unwavering love, support, and stability; they constantly strive to bring out the best in you even when you are unable to perceive it for yourself.

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The  [H3O+] in step 1 is 0.0034 M while the  [H3O+] in step 2 is 0.00039 M

Let us set up the ICE table in each case, for K1;

         H2A(aq) + H2O(l)-------->   H3O^+(aq) + HA^-(aq)

I        0.12                                     0                    0

C       -x                                        +x                   +x

E      0.12 - x                                x                     x

Ka1= [H3O^+] [HA^-]/[ H2A]

Ka1= x^2/  0.12 - x  

1.0×10^−4 = x^2/  0.12 - x  

1.0×10^−4(0.12 - x ) = x^2

1.2 * 10^-5 - 1.0×10^−4x =  x^2

x^2 +  1.0×10^−4x - 1.2 * 10^-5  = 0

x =0.0034 M

[H3O+] = 0.0034 M

Again;  [H3O+] = [HA^-] = 0.0034 M

          HA^-(aq) + H20(l)    -------> A^-(aq)   + H3O^+

I       0.0034                                  0               0

C       -x                                          + x            +x

E    0.0034 - x                               x                x

Ka2= [A^-] [H3O^+]/[HA^-]

5.0×10^−5 = x^2/ 0.0034 - x  

5.0×10^−5 (0.0034 - x ) = x^2

1.7 * 10^-7 - 5.0×10^−5x =  x^2

x^2 + 5.0×10^−5x - 1.7 * 10^-7 = 0

x=0.00039 M

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This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.

The ethane, propane, butane, belong to alkanes family.The alkanes are also considers as saturated hudrocarbons. Ethane is found in gaseous stae Ethane is the second alkane followed by propane followed by butane.

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Explanation:

secondary amine bro go leaen

The equilibrium expression is:

H2S (aq) + H2O (l) ⇋ H3O (aq) + HS (aq)

In order to calculate the pH of equation having aqueous solution of weak acid H2S, let’s assume that molar concentration of the products H3O and HS total released is ‘a’. Now as per given information concentration of weak acid H2S is 2.3 M. Thereby,

Ka = [H3O+] [HS] / [H2S]

1.19 x 10-7 = [a] * [a] / [2.3]

a2 = 1.19 x 10-7 x 2.3

a = 5.24 x 10-4

As per the calculation, the total concentration of the products released (HS) and (H3O) will be 5.24 x 10-4, on that basis, the pH of the weak acid (H2S) can be calculated as follows:

-log (0.000522494) = 3.28

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Ammonium salt of acetic acid is the reaction product of acetic acid and ethylamine at room temperature.

The acetic acid and ethylene amine form salts and this result is expected same as form in the reaction of oxalic acid and ethylene diamine at ambient temperature.

The reaction of acetic acid with ammonium forms ammonium salt of carboxylic acid which on heating undergoes elimination to form amide as acetamine. The salt is form due to deprotonation of acid by the base. The amide is form on heating of the ammonium carboxylate salt. Such type of reaction is called aminooacide reaction.

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Answer:

  3.0×10⁻¹³ M

Explanation:

The solubility product Ksp is the product of the concentrations of the ions involved. This relation can be used to find the solubility of interest.

The power of each concentration in the equation for Ksp is the coefficient of the species in the balanced equation.

  Ksp = [Al₃⁺³]×[OH⁻]³

The initial concentration [OH⁻] is that in water, 10⁻⁷ M. The reaction equation tells us there are 3 OH ions for each Al₃ ion. If x is the concentration [Al₃⁺³], then the reaction increases the concentration [OH⁻] by 3x.

This means the solubility product equation is ...

  Ksp = x(10⁻⁷ +3x)³

For the given Ksp = 3×10⁻³⁴, we can estimate the value of x will be less than 10⁻⁸. This means the sum will be dominated by the 10⁻⁷ term, and we can figure x from ...

  3.0×10⁻³⁴ = x(10⁻⁷)³

Then x = [Al₃⁺³] will be ...

  [tex][\text{Al}_3^{\,+3}]=\dfrac{3.0\times10^{-34}}{10^{-21}}\approx \boxed{3.0\times10^{-13}\qquad\text{moles per liter}}[/tex]

We note this value is significantly less than 10⁻⁷, so our assumption that it could be neglected in the original Ksp equation is substantiated.

__

Additional comment

The attachment shows the solution of the 4th-degree Ksp equation in x. The only positive real root (on the bottom line) rounds to 3.0×10^-13.

Equilibrium constant for the reaction is

[tex]\sf K_{sp}=[Al^{3+}][OH^-]^3[/tex]

So

[tex]\\ \rm\Rrightarrow s=\dfrac{3.0\times 10^{-34}}{(10^{-7})^3}[/tex[

[tex]\\ \rm\Rrightarrow s=\dfrac{3.0\times 10^{-34}}{10^{-21}}[/tex]

[tex]\\ \rm\Rrightarrow s=3.0\times 10^{-13}M[/tex]

Answer:

0.481 M

Explanation:

The molarity ratio looks like this:

Molarity = moles / volume (L)

Since you have been given both the mass and volume, you can plug them into the equation to find the molarity.

Molarity = moles / volume

Molarity = 0.650 moles / 1.35 L

Molarity = 0.481 M

The rules scientists will have to follow to give an element a symbol is by verifying it and naming it with a one-, or two-letter symbol which is usually derived from the name of the element.

This is referred to as substance which can't be broken down into simpler units by any form of chemical means.

When an element is discovered by an individual, it is best for it to be verified before it is named by the discoverer. The possible name for the element Jofrofrinium is Jo which is a two letter symbol or it could be J which is referred to as a one letter symbol.

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There is a total of three atoms present in the water (H₂O) molecule.

An atom is the smallest particle of an element that may or may not be capable of independent existence.

A molecule is the smallest particle of an element or compound that can exist freely.

Subscripts are the numbers that come below after a symbol. They tell you the number of atoms of an element. If there is no subscript then it is understood that the subscript is 1.

For calculating the number of atoms in a molecule, add the subscripts of that molecule, and you will get the total atoms of it.

For example, in molecule C₂H₅O, there are 2 carbon atoms, 5 hydrogen atoms, and 1 oxygen atom.

Add the subscripts

2 + 5 + 1 = 8

Hence, there is a total of 8 atoms in C₂H₅O.

For the H₂O molecule,

2 + 1 = 3

Hence, there is a total of 3 atoms present in one water molecule.

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The volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.

If 400 ml of CO2 is produced at 30°C at 740 torr, then number of moles can be calculated as:

By using ideal gas equation:

P1V1 = N1R1T1

P1 = pressure = 740torr

V1 = 400 ml = volume of CO2

R = Gas constant = 8.314

T = 273+30 = 303 k

740×400 = N1×8.314×303

N1 = (740×400) /(8.314×303) =117.5.

Chemical equation

C2H6 ---- 2CO2 + 3H2O.

As we noticed from the equation that

2 moles of CO2 = 3 moles of H2O

1 moles of CO2 × 1 moles of H2O

Then N2 = 117.5 moles of CO2 = 3/2 × 117.5 moles of H2O

By using ideal gas equation:

P2V2 = N2RT2

V2 = 3/2 × 117.5 × 8.314 × 292/ 780

= 548.5ml.

Thus, we found that the volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.

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Answer: 75.3%

Explanation:

Mg molar mass = 24

MgCl2 molar mass = 94

—> 94 x 10 / 24

29.5/1 x 24/94 x 10

= 29.5 x 24 / 94 x 10

since we are looking for percentage yield we multiply by 100

= 29.5 x 24 x 100 / 94 x 10 = 75.3%

The molecular weight of this gas will be 45 g/mol .

The state equilibrium equation for a fictitious perfect gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has significant drawbacks, it represents a decent approximation of the activity of many gases under various conditions.

Ideal gas law can be expressed as:

PV =nRT

Calculation of molecular weight by using ideal as law.

Given data:

P = 3 atm

T = 127 °c

Density =  4. 20 grams per liter

PV =nRT

where p is pressure , T is temperature and R is gas constant.

PV = gram / molecular weight RT

Molecular weight = (g/v)( 1/P) RT

Putting the given data in above equation.

Molecular weight =4.20 × 1/ 3× 400 × 0.0831

Molecular weight = 45 g/mol.

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The reaction  [tex]Na_{3} PO_{4} ( aq) +3AgNO_{3} (aq)[/tex] → [tex]Ag_{3} PO_{4} ( aq) +3NaNO_{3} (aq)[/tex] is best classified as double displacement reaction.

Those reaction in which two compounds react by exchanges of ions to form two new compounds is called  double displacement reaction. The easiest way to identify double displacement reactions is to check to see whether the cations exchanged anions with each other  or not . Always balanced chemical equation is used to determine.

There are three types of double displacement reaction which is given as,

The real world example of double displacement reaction is combining vinegar and baking soda to create homemade volcano.

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A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 m, BaF₂ will precipitate.

Let's consider the solution of BaF₂.

BaF₂(s) ⇄ Ba²⁺(aq) + 2 F⁻(aq)

We can use the solubility product constant (Ksp) to find the equilibrium concentration of F⁻ when [Ba²⁺] is 0.0144 M.

When [F⁻] exceeds 0.011 M, BaF₂ will precipitate.

A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 M, BaF₂ will precipitate.

What is BaF₂.?

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Volume of hydrogen (in l) is produced is 35.20 L

Given:

moles of hcl = 3.143 mol

To Find:

volume of hydrogen

Solution:

2HCl → H2 + Cl2

STP 2*22.4L 22.4L 22.4L

2 mol 1 mol 1 mol

73 gm 2gm 35.5gm

here we can see that 2 mol hcl is producing 22.4 litres of hydrogen

So, 3.143 mol hcl will produce hydrogen = 22.4/2*3.143 = 35.20 litres

Volume of hydrogen (in l) is produced is 35.20 L

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Low pressure region is formed as air masses move horizontally

Basically, an air mass is a volume of air that is doing something. A high pressure region and a low pressure area on a weather chart are examples of air masses. It may be the cloud burst that you were recently trapped in. Essentially a description of a zone that behaves consistently.

The horizontal motion of air is known as wind. When there are variations in air pressure, winds begin to blow. A force is created when air pressure is higher in one location than another. High pressure pushes the force in the direction of lower pressure.

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A 20. 0 l cylinder of oxygen gas is at a temperature of 27. 0°c and a pressure of 5. 00 atm. The density of the oxygen gas in the cylinder is 1.24 atm

The physical force applied to an object is referred to as pressure. Per unit area, a perpendicular force is delivered to the surface of the objects. F/A is the fundamental formula for pressure (Force per unit area). Pascals are a unit of pressure (Pa). Absolute, atmospheric, differential, and gauge pressures are different types of pressure.

By pressing a knife on some fruit, one can get a straightforward illustration of pressure. The surface won't be cut if you press the flat section of the knife against the fruit. The force is dispersed over a wide area (low pressure).

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Ammonium chloride is a white solid that breaks down when heated and produces ammonia and hydrogen chloride.

A reversible reaction is a reaction in which the conversion of reactants to products and products to reactants occur at the same time. In the above example, the chemical shows a reversible reaction because it moves both forward and backward direction. In reversible reaction, equal amount of reactant is converted into product and product into reactant.

So we can conclude that Ammonium chloride is a chemical that represents a reversible reaction.

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Answer:

It's too short. Write at least 20 characters to explain it well.

Explanation:

It's too short. Write at least 20 characters to explain it well.

When an atom of the element lithium (Li) transfers an electron to an atom of the element fluorine (F), then the bond results between the atoms is ionic bond.

A chemical bond is defined as the bond which holds atoms together in molecules.

Bonds arise due to the electrostatic forces present between positively charged atomic nuclei and negatively charged electrons.

Ionic bond is defined as the transfer of electron from one atom to another atom.

Since, electron transfer from lithium to fluroine. Thus lithium get positive charge and fluorine occupy negative charge.

Thus, the bond form between lithium atom and fluorine atom is ionic bond.

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Answer:

Alkanes

Explanation:

Alkanes are hydrocarbons containing only single bonds between the parent chain carbons.

Alkenes are hydrocarbons containing at least one double bond between the parent chain carbons.

Alkynes are hydrocarbons containing at least one triple bond between the parent chain carbons.