Answer:
well, it is not a solid path and thats a teeny tiny fact
What was the major problem with the hubble space telescope when it was first launched into orbit?
Answer:
Apparently, a measuring rod had been used incorrectly and the telescope was not focusing properly - changes were later made to the telescope to correct this problem.
What is the noon solar zenith angle if you are in san diego (32° north latitude) during the winter solstice (solar declination = 23.5° south latitude)?
The noon solar zenith angle is 55.5°.
How do you calculate the solar zenith angle ?Zenith Angle = latitude where you are at ± subsolar point
If the subsolar point and your latitude are in the same hemisphere, subtract.
If the subsolar point and your latitude are in different hemispheres, add.
In this case you are in north latitude and the winter solstice in south latitude. So according to the formula,
Zenith Angle = latitude where you are at + subsolar point
⇒Zenith Angle = 32°+23.5°
⇒Zenith Angle =55.5°
Hence, the noon solar zenith angle for this case is 55.5°.
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Give one example of a thermodynamic cycle that does not account for the carnot efficiency.
Thermo-Electrochemical converter (UTEC) is a thermodynamic cycle that does not account for the Carnot Efficiency.
What is the Carnot cycle in thermodynamics?
An ideal closed thermodynamic cycle that is reversible and consists of the four steps of isothermal expansion to a desired point, adiabatic expansion to a desired point, isothermal compression, and adiabatic compression back to the starting state.
What is the purpose of Carnot cycle?
The Carnot cycle, first proposed by the French engineer Sadi Carnot in the early 19th century, is the optimum cyclical sequence of changes in pressure and temperature of a fluid, such as a gas utilized in an engine. It serves as a benchmark for all heat engines operating in the range of high and low temperatures.Learn more about Carnot Efficiency.
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If the signal light changes from green to yellow as you enter the intersection, you should:_______
When the light turns from green to yellow while you are already in the intersection, proceed through the intersection at a safe speed.
To find the answer, we have to study more about the importance of traffic signals.
What are the importance of yellow signal light in traffic?Recognize that you have the right-of-way when a yellow light is flashing. Reduce your speed as you get close to a flashing yellow light and keep an eye out for other cars that might not be paying attention to or respecting your right-of-way. You should safely stop your car at any intersection where there is a constant yellow light. When the light turns from green to yellow while you are already in the intersection, proceed through the intersection at a safe speed.Thus, we can conclude that, When the light turns from green to yellow while you are already in the intersection, proceed through the intersection at a safe speed.
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The aeroplane then continues at a CONSTANT VELOCITY for a further 800 m before leaving the runway. The length of the runway is 2 000 m. 8 m-s-1 1 .2 1.3 → Define the term vector. Convert 67 m-s¹ to km.h¹. 67 m-s¹ Calculate the: .3.1 3.2 1.3.3 3.4 30 s 800 m Acceleration of the aeroplane during the first 30 seconds Distance travelled by the aeroplane during the first 30 seconds Time taken by the aeroplane to travel the 800 m Length of the runway NOT USED when the aeroplane leaves the runway (2) (1 (4 (4 (3
800 = 0 + [tex]\frac{1}{2}[/tex]a(30)[tex]^{2}[/tex]
800 = 450a
a = 1.77m[tex]s^{-2}[/tex]
Distance = s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]s = 0+ [tex]\frac{1}{2}[/tex]1.77[tex]t^{2}[/tex]
s = [tex]\frac{1}{2}[/tex]1.77(30)[tex]^{2}[/tex]
s = 796.5m
Time taken = distance / velocityt = 800/8
t = 100 sec
Length of the runway not used = total length of runway-total length covered before leaving runway2000 -800
length = 1200m
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3. [-/2 Points]
A race car traveling northward on a straight, level track at a constant speed travels 0.760 km in 21.0 s. The return trip over the
same track is made in 26.0 s.
DETAILS SHIPPS13 2.E.010. MY NOTES
ASK YOUR TEACHER
(a) What is the average velocity of the car in m/s for the first leg of the run?
m/s
(b) What is the average velocity (in m/s) for the total trip?
m/s
PRACTICE ANOTHER
(a) The average velocity of the car in m/s for the first leg of the run is 36.2 m/s.
(b) The average velocity (in m/s) for the total trip is 0.
Average velocity
The average velocity of the car in m/s for the first leg of the run is calculated as follows;
Average velocity = total displacement/total time
Average velocity = (760) / (21) = 36.2 M/S
Average velocity for total tripThe average velocity (in m/s) for the total trip is calculated as follows;
v = total displacement/total time
v = 0/(26 + 21)
v = 0
Thus, the average velocity of the car in m/s for the first leg of the run is 36.2 m/s.
The average velocity (in m/s) for the total trip is 0.
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An fm radio station broadcasts at 98. 6 mhz. What is the wavelength of the radiowaves?.
The wavelength of radiowaves is 3.042 m.
What is radiowaves?The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below.
Frequency given, f = 98.6 MHz = 98.6 x [tex]10^{6}[/tex] cycles/second
Electromagnetic waves including radiowaves also travel at the speed of light.
Therefore, c = 3.0 x [tex]10^{8}[/tex] m/sec
Wavelength = speed/frequency
wavelength of 98.6 MHz = 3.0 x [tex]10^{8}[/tex]/98.6 x [tex]10^{6}[/tex] meters
=3.042 meters
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On a frictionless, horizontal air track. the glider has a head-on collision with a 0. 300-kg glider that is moving to the left with a speed of 2. 20 m>s. Find the final velocity?
The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s
Given data,
Mass of glider A (M[tex]_{1}[/tex]) = 0.15 kg
Mass of glider B (M[tex]_{2}[/tex]) = 0.3 kg
Initial velocity of A (u[tex]_{1}[/tex]) = 0.80ms-1
Initial velocity of B ( u[tex]_{2}[/tex]) = -2.2m/s
Momentum and kinetic energy are conserved in elastic collision . So,
M[tex]_{1}[/tex]u[tex]_{1}[/tex]+M[tex]_{2}[/tex]u[tex]_{2}[/tex] = M[tex]_{1}[/tex]v[tex]_{1}[/tex]+M[tex]_{2}[/tex]v[tex]_{2}[/tex]
0.15×0.8+0.3x(-2.2) = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]
-0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex]
Again if,
u[tex]_{1}[/tex]+v[tex]_{1}[/tex] =u[tex]_{2}[/tex]+v[tex]_{2}[/tex]
0.8 +v[tex]_{1}[/tex] =-2.2+v[tex]_{2}[/tex]
v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3
Solving for -0.54 = 0.15v[tex]_{1}[/tex]+0.3v[tex]_{2}[/tex] and v[tex]_{1}[/tex]-v[tex]_{2}[/tex] = -3 , we get
v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s
Therefore,The final velocity is v[tex]_{2}[/tex] =-0.2m/s , v[tex]_{1}[/tex] = -3.2 m/s
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A spring with a constant k=400n/m shoots a 1. 00kg ball up a frictionless incline after being compressed 0. 150m. what is the maximum height reached by the ball?
The maximum height reached by the ball is 0.46m.
To find the answer, we have to know about the potential energy of a spring mass system.
How to find the maximum height reached by the ball?It is given that,[tex]k=400N/m\\m=1kg\\x=0.150m\\h=?\\[/tex]
We have to find the maximum height reached by the ball.Thus, we have the expression for potential energy of a spring mass system and that of gravitational field as,[tex]U=\frac{1}{2}kx^2 \\U=mgh[/tex]
Combining both, we get,[tex]h=\frac{kx^2}{2mg} =\frac{400*(0.15)^2}{2*1*9.8} =0.46m[/tex]
Thus, we can conclude that, the maximum height reached by the ball is 0.46m.
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how is that velocity got like this? pls explain
Answer:
if a car is increasing it's acceleration uniformly in a unit time, the graph will be moving away from it's origin. that's how you get this kind of graph.
Calculate the wavelength of an electron (m = 9. 11 × 10^-28 g) moving at 3. 66 × 10^6 m/s
The wavelength of an electron (m = 9. 11 × 10^-28 g) moving at 3. 66 × 10^6 m/s will be 0.197 * [tex]10^{-12}[/tex] m
De Broglie wavelength is an important concept while studying quantum mechanics. The wavelength (λ) that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength. A particle's de Broglie wavelength is usually inversely proportional to its force.
momentum (p) = mv
DE Broglie wavelength = lambda = h / p
where
h = plank's constant
m = mass of electron
v = velocity of electron
lambda = h / mv
= 6.633 * [tex]10^{-34}[/tex] / 9. 11 × [tex]10^{-28}[/tex] * 3. 66 × [tex]10^{6}[/tex]
= 0.197 * [tex]10^{-12}[/tex] m
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Please help, I don't understand lol
The resulting velocity of marble B after the collision is 2.4 m/s.
The object with the faster velocity, and thus larger momentum, will impart more energy to the slower object during the collision than vice versa. Following the collision, the object with the lower beginning velocity will travel away from the other object with a higher speed and momentum.
Marble A's mass, marble B's mass, marble B's initial velocity, marble A's final velocity, marble B's final velocity, and marbles A and B's combined mass and initial velocity
Applying the mass-conservation principle
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v
0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v
0.12 kg m/s = (0.05 kg) v
v = 2.4 m/s
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I need help with these 2 physics questions ASAP thanks (Note, ignore problem 6 as I have solved it)
The final velocity of the ball is 20.8 m/s. Option C
What is the final speed?Now we have the equation;
v^2 = u^2 + 2gh
v = final velocity
u = initial velocity
a = acceleration
s = distance
v^2 = (11.4)^2 + (2 * 10 * 15.5)
v^2 = 129.96 + 310
v = √ 129.96 + 310
v = 20.8 m/s
b)
Given that;
R = u^2sin2θ/g
Where;
g = acceleration due to gravity
θ = acute angle
u = velocity
R = (60)^2 sin2(30)/10
R = 310 m
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An electron moving perpendicular to a magnetic field of 3. 2 × 10-2 t moves in a circle of radius 0. 40 cm. how fast is this electron moving?
An electron moving perpendicular to a magnetic field of 3. 2 × 10-2 t moves in a circle of radius 0. 40 cm. this electron is moving with 2.25 x 10⁷ m/s
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is traveling through a magnetic field.
A magnetic field is defined as a location in space close to a magnet or an electric current where a physical field is formed by a moving electric charge acting as a force on another moving electric charge. The magnetic field of the Earth is an illustration of a magnetic field. The region around a magnet where the effects of magnetism are felt is known as the magnetic field.
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A(n) ________ is one in which energy moves freely in and out, but no matter enters or leaves the system.
A(n) closed system is one in which energy moves freely in and out, but no matter enters or leaves the system.
You can have an open or closed system: A system that is totally cut off from its surroundings is referred to as a closed system. We have opted to adopt this definition because it is one that is frequently used in the system literature.
A closed system is one that only permits the transfer of energy within or outside the system but not the transport of matter. For instance, a beaker of evaporating water with a closed top permits the flow of energy to the environment but prevents the evaporation of (matter) water.
closed systems are also referred to as systems that don't allow anything other than energy to enter or exit. A closed water bottle functions as a closed system in this instance.
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What is the work generated by a healthy adult who circulates 9 l of blood through the brachial artery in 10 min?
120kJ work is generated by a healthy adult who circulates 9L of blood through the brachial artery in 10 min.
What is mean by work?Work is defined as the energy that is applied to or removed from an object by applying force along a displacement. It is frequently described in its most basic form as the result of force and displacement.Calculation of Work generatedA flow rate of 900 mL per minute is equal to a flow of 9 L in 10 minutes.
Additionally, you have 200W of total power generated.
9L Equals 9000 mL
900mL/min x 9,000mL/10min
By multiplying the power (watt) by the time, we can derive the work performed by the adult.
10 min = 600s
200W x 600s = 120 kJ
Hence, the work generated is 120kJ.
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what are the importance of wedge?
A wedge is a machine and it is used for separating bodies.
The Wedge as a MachineThe wedge is a combination of two inclined planes. When the wedge is driven into a body by an effort force, a much larger force will be exerted to each side by the wedge surfaces.
What are the importance of wedge?
A wedge is used to separate bodies which are held together by large forces example of this scenario is splitting of timber. A wedge is a machine and the example of wedge - type of machine are;
AxesChiselKnivesCutting toolsNote that a thin wedge has a higher mechanical advantage than a short thick one.
Therefore, a wedge is a machine and it is used for separating bodies.
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Which method of measurement would be accurate but lack precision?
A. Measuring a volume of water by estimating the size of the
container
B. Measuring a volume of water using a graduated cylinder that can
be read to nearest mL
C. Measuring air temperature with a thermometer that has just been
taken out of hot water
D. Measuring air temperature with a thermometer that can be read to
the nearest degree and is calibrated to the correct temperature
Answer:
B
Explanation:
reading the volume of water in a graduated cylinder which can be read to the nearest mL is accurate, it lacks precision due to the bottom meniscus formed.
the bottom meniscus may cause a wrong reading due to refraction of light
What is the total mass of the earth's atmosphere? (the radius of the earth is 6.4 ´ 106 m, and atmospheric pressure at the surface is 105 n/m2.)
The total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.
How do you calculate the total mass of the earth's atmosphere ?To calculate the total mass of the earth's atmosphere we use the expression
[tex]P=\frac{F}{A}[/tex]
or, [tex]F=P\times A[/tex]
or,[tex]M\times g=P\times A[/tex]
or,[tex]M=\frac{P\times 4\times \pi\times r^{2} }{g}[/tex]
Here, P= Atmospheric pressure at the surface = [tex]10^{5}[/tex] N/m2
F= Force at the earth surface.
A= Area of the earth.
r= Radius of the earth=6.4 × [tex]10^{6}[/tex] m
g= Acceleration due to gravity. = 9.8 m/s2 ≈ 10 m/s2
Let, M be the total mass of the earth's atmosphere.
Now, [tex]M=\frac{10^{5}\times4\times\pi\times(6.4\times10^{6} )^{2} }{10}[/tex]
M= 5×[tex]10^{8}[/tex] kg.
Thus from the above calculation we can show that, the total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.
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The colors of a soap bubble or oil slick are due to __________. two-slit interference thin-film interference huygens' principle diffraction
Answer:
Thin film interference
When energy is transferred between earth's system, some energy is lost to the surroundings in the form of _____________________. (select all that apply)
When energy is transferred between earth's system, some energy is lost to the surroundings in the form of
-light
-movement
-heat
-vibration
What is energy in earth's system?Only a few factors account for the majority of the energy in the Earth system: solar energy, gravity, radioactive decay, and the rotation of the Earth. Many surface processes, including winds, currents, the hydrologic cycle, and the entire climate system, are powered by solar energy. Rivers and other materials flow downhill due to gravity, which also causes tides (due to the Moon's gravitational pull). The Earth's interior is heated by radioactive decay, while air and water currents are influenced by the forces of rotation.
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Two point charges of 20. 0 μc and -8. 00 μc are separated by a distance of 20. 0 cm. what is the intensity of electric field e midway between these two charges? group of answer choices
The intensity of electric field E midway between these two charges is 2.52*10^7N/C.
To find the answer, we have to know more about the electric field.
How to find the electric field?We have the expression for net electric field as,[tex]E=\frac{kQ}{r^2}[/tex]
where, k is the constant equal to 8.99*10^9.
Thus, we can write the electric field created by 20micro coulomb charge at the midway between two charges is,[tex]E_1=\frac{8.99*10^9*20*10^{-6}}{10*10^{-2}} =1.79*10^7N/C[/tex]
We can write the electric field created by -8micro coulomb charge at the midway between two charges is,[tex]E_2=\frac{8.99*10^9*8*10^{-6}}{(10*10^{-2})^2} =7.19*10^6N/C[/tex]
Thus, the net field at the midway due to two charges will be,[tex]E=1.79*10^7+7.19*10^6=2.52*10^7N/C[/tex]
Thus, we can conclude that, the intensity of electric field e midway between these two charges is 2.52*10^7N/C.
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Aluminium has a work function of 4. 08 ev. (a) find the cutoff wavelength and cutoff frequency for the photoelectric effect?
Aluminium has a work function of 4. 08 eV. The cutoff wavelength and cutoff frequency for the photoelectric effect is 303.9nm and 911.7× 10¹⁷ s⁻¹ respectively.
Work Function is the minimum energy required to eject an electron from a photoelectric material.
Cutoff Wavelength is the maximum wavelength below which electron will be ejected
Cutoff Frequency is the minimum frequency required to eject electron.
Let the work function of Aluminium be Φ
Given, work function Φ = 4.08eV
We know that hc/λ = Φ
where, h is Planck constant
c is speed of light
λ is wavelength of light used
Hence, on subsitution
1240 / λ = 4.08 eV (hc = 1240)
⇒ λ = 303.9 nm
Hence, cutoff wavelength used is 303.9 nm
We know that ν = c/λ
ν = 3 × 10⁸ / 303.9
⇒ ν = 911.7 × 10¹⁷ s⁻¹
Hence, cutoff frequency used is 911.7 × 10¹⁷ s⁻¹
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The cost of operating an electrical appliance is based upon its
Aage.
Bease of use.
Cwattage and time used.
D original purchase price.
Answer:
wattage and time used
Explanation:
Look
If a electrical appliance has more power or wattage it will use more energy and cost more
If a electrical appliance is used for more time the cost is more
Hence Option C is correct
Use the same line to answer the questions
Q1. Use the number line above to calculate the distances and displacements for the paths listed. Don't forget to include the units.
Distance Displacement
From A to B to M to N
From C to A to G to D
From J to I to E to H
From F to B to K to F
Q2. For each of the paths from Q1, calculate the average speed and the average velocity if the path is traveled in 5.0 seconds. Don't forget to include the units. Use this Formula Reference Sheet (click this highlighted link for information) to remember the formulas you need.
Average velocity Average speed
From A to B to M to N
From C to A to G to D
From J to I to E to H
From F to B to K to F
(a) The distance From A to B to M to N is 22 m, the displacement is 22 m, the speed is 4.4 m/s and the average velocity is 4.4 m/s.
(b) The distance From C to A to G to D is 24 m, the displacement is 2 m, the speed is 4.8 m/s and the average velocity is 0.4 m/s.
(c) The distance From J to I to E to H is 16 m, the displacement is -2 m, the speed is 3.2 m/s and the average velocity is -0.4 m/s.
(d) The distance From F to B to K to F is 32 m, the displacement is 0 m, the speed is 6.4 m/s and the average velocity is 0 m/s.
Distance traveled by the objectThe distance traveled by the object is calculated as follows;
Distance From A to B to M to N
From A to B to M to N = 3 + 18 + 1 = 22
Distance From C to A to G to D
= 5 + 13 + 6
= 24
Distance From J to I to E to H
= 1 + 8 + 7
= 16
Distance from F to B to K to F
= 8 + 16 + 8
= 32
Displacement of the objectThe displacement of the object is calculated as follows;
displacement = final position - initial position
Displacement From A to B to M to N
= 11 - (-11)
= 22
Displacement from C to A to G to D
= D - C
= - 4 - (-6)
= 2
Displacement from J to I to E to H
= H - J
= 5 - 7
= - 2
Displacement From F to B to K to F
= F - F
= 0
Speed of the objectThe speed of the object is calculated as follows;
speed = total distance/total time
Speed of the object from A to B to M to N
= 22/5 = 4.4 m/s
Speed of the object from C to A to G to D
= 24/5
= 4.8 m/s
Speed of the object from J to I to E to H
= 16/5
= 3.2 m/s
Speed of the object from F to B to K to F
= 32/5
= 6.4 m/s
Average velocity of the objectThe average velocity of the object is calculated as follows;
Average velocity from A to B to M to N
= 22/5
= 4.4 m/s
Average velocity of the object from C to A to G to D
= 2/5
= 0.4 m/s
Average velocity of the object from J to I to E to H
= -2/5
= -0.4 m/s
Average velocity of the object from F to B to K to F
= 0
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As a gaseous element condenses, the atoms become ________ and they have ________ attraction for one another.
Answer:
blank 1: close together
blank 2: more
(Repost) I need help with this physics question. Thanks in advance! Answer ASAP.
(a) The gravitational force received by each 1 kg mass is 8.66 N.
(b) The magnitude of gravitational acceleration is 8.66 m/s².
(c) The orbital speed of the ISS is 7,663.6 m/s.
(d) The time take for the ISS to orbit round the Earth is 5,558.75 seconds which is equal to 1.54 hours.
Gravitational force received by each 1 kg massThe gravitational force received by each 1 kg mass is calculated as follows;
F = Gm₁m₂/r²
where;
m₁ is mass of Earthm₂ is mass of ISSr is the distance between the ISS and center of EarthF = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 1) / (6780,000)²
F = 8.66 N
Magnitude of gravitational accelerationmg = GMm/r²
g = GM/r²
where;
M is mass of Earthg = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ ) / (6780,000)²
g = 8.66 m/s²
Orbital Speed of the ISSv = √GM/r
v = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ / 6780,000)
v = 7,663.6 m/s
Time of motion of the ISS round the EarthT = 2πr/v
T = (2π x 6780,000) / (7663.6)
T = 5,558.75 seconds
1 hour = 3600 seconds
= 5,558.75/3600
= 1.54 hours
Thus, the gravitational force received by each 1 kg mass is 8.66 N.
The magnitude of gravitational acceleration is 8.66 m/s².
The orbital speed of the ISS is 7,663.6 m/s.
The time take for the ISS to orbit round the Earth is 5,558.75 s = 1.54 hours.
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A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg
initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final momentum of the blue train?
A. 90 kgm/s
B. 200 kgm/s
C. 110 kgm/s
D. 20 kgm/s
Answer:
C
Explanation:
Use conservation of momentum
Momentum before collision = mv = 50 (4) = 200 kg-m/s
AFTER collision
30 * 3 + Blue momentum = 200
blue momentum = 110 kg-m/s
On which of saturn’s moons did the cassini-huygens probe land in 2004, providing our first view of the varied and active surface?
On Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.
To find the answer, we have to know more about the Cassini-Huygens Mission.
What is Cassini-Huygens mission?Before arriving at its final destination of Saturn in 2004 and beginning a series of flybys of Saturn's moons, the spacecraft contributed to studies of Jupiter for six months in 2000. In the same year, it launched the Huygens probe to explore Titan's atmosphere and surface makeup on Saturn's moon. During its second extended mission, Cassini sailed between the rings, entered the planet's atmosphere, and obtained the first measurements of a whole seasonal period for Saturn and its moons.Thus, we can conclude that, on Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.
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What is the maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee?
The maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee 119.28N.
Given,
m=76kg, μ=0.16, g=9.81 m/[tex]s^{2}[/tex]
frictional force = mμg= 76*0.16*9.81= 119.28 N
Frictional forceAn opposing force to the relative motion of two bodies in contact is known as frictional force. Always acting in the opposite direction from the direction of motion, frictional force is applied to a moving body. Because it resists motion, it aids in lowering the moving object's speed. The force is one of touch. Four broad categories can be made for the force of friction depending on the sort of motion that occurs between the two objects. Static friction is the force of friction between an object and the surface it is put on.
What is the maximum frictional force in the knee joint of a person who supports 76. 0 kg of her mass on that knee?
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