When an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about the amount of energy the star gives off each second.
Luminosity and apparent brightness are about brightness, but from a different point of view. The difference between luminosity and apparent brightness is that luminosity tells us exactly how bright a star really is while apparent brightness only tells us its brightness seen from Earth.
L / Lsun = ( d / dsun )² = b / bsun
L = Luminosity of a star
Lsun = Luminosity of sun
d = Distance of star
dsun = Distance of sun
b = Brightness of star
bsun = Brightness of sun
Therefore, when an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about the amount of energy the star gives off each second.
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What kind of electronic transitions are responsible for colored light being given off?.
The kind of electronic transitions that is responsible for colored light being given off is called emission.
Emission is the discharge of something, particularly radiation or gas. Emission spectrum or line spectrum is the given off of electromagnetic radiation when an electron transits from a higher energy level to a lower energy level. During the course of transition from one level to another, energy generated are emitted in the form of white light by the atoms and molecules. When electrons in the ground state of an energy level is heated, it rises to a higher energy level. It thus releases energy quickly to maintain a balanced state or go back to the ground state. If the energy released is equal to the energy that produces white light, it will form colored light.
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5) what is the average momentum of an avalanche that moves a 40-cm-thick layer of snow over an area of 100 m by 500 m over a distance of 1 km down a hill in 5.5 s? assume a density of 350 kg/m3 for the snow.
The average momentum of the avalanche was found to be 1.3×10^ 9 kg·m/s
what is momentum?
Momentum is the pace at which a security's price accelerates—that is, the rate at which the price changes. Momentum trading is a method that uses momentum to enter a trend while it is gaining traction.
Simply expressed, momentum is the tendency of a price trend to continue growing or dropping for a set period of time, taking into consideration both price and volume data. Momentum is commonly quantified using an oscillator in technical analysis and used to help detect trends.
Momentum is the quantity of motion of an item. If you know the object's velocity and mass, you can calculate its momentum. It will be simple once you understand the formula.
The average momentum of the above problem was 1.3 x 10^9Kg.m/s
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Calculate the velocity of the 2.0 kg mass just before it hits the
rocks when it is dropped from a height of 16 m above the surface
of the rocks. Give the unit.
Velocity:........
Unit: .......
The velocity of the 2.0 kg mass just before it hits the rocks when it is dropped from a height of 16 m above the surface of the rocks will be 17.738 m/s in downward direction
given
u = 0
m= mass = 2 kg
height = 16 m
v = ?
using kinematics equation
-s = ut - 1/2* g * [tex]t^{2}[/tex]
t = [tex]\sqrt{2s/g}[/tex]
time = [tex]\sqrt{(2*16) / 9.8}[/tex]
= [tex]\sqrt{3.27}[/tex]
= 1.81 seconds
v = u - gt
v = -g t = -9.8 * 1.81 = -17.738 m/s
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a player hits a baseball with mass of 0.145 kg over the outfield fence. the ball leaves the bat with a speed of 42.0 m/s and a fan in the bleachers catches it 14 m above the point where it was hit. neglect air resistance. what is the speed of the ball when it is caught?
When the ball is caught, it is moving at a speed of 3 m/s. Distance/time is the formula for calculating speed.
How do you tell the ball's speed?You must time how long it takes from when the ball is released until the pin is struck using a stopwatch. By dividing the distance by the time, one may calculate the ball's speed.
The average speed, if it was 3 seconds,
would be 42/14, or 3 feet per second .
Build a launcher for balls. I made use of an exercise rubber band and the legs of a patio chair.
horizontally when you shoot the ball. For this to operate, the camera angle must be horizontal.
Calculate how long the ball has been in the air.
The ball's distance traveled should be measured.
Simply dividing the distance by the launch time yields the launch speed.
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1. If you wanted to make a piece of silk fabric become negatively charged, what might you rub it with? Explain your reason.
2. If you wanted to make a piece of silk fabric become positively charged, what might you rub it with? Explain your reason.
The silk can get a negative charge if it is rubbed against iron rod and it can get a positive charge if it is rubbed against hair.
How to make charges?We know that a charge is made when there is either an excess or a deficit of electrons. When there is an excess of the positive charge on an object, we can say that the object ha become positively charged. If there is an excess of negative charges, we can say that the material is negatively charged. We now want to determine how we could make silk to become positively or negatively charged.
If we want the silk to have a negative charge then we have to rub the silk with a glass rod. If the silk is rubbed with a glass rod, what would happen is that electrons would be transferred from the rod to the silk leaving the silk with a negative charge.
If you want the silk to have a positive charge, you could rub it against hair. In that way, the hair would get an negative charge while excess electrons are transferred to the silk making it to have a positive charge.
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If you drive at 120km/hr for 5 hours, how far will you go?
Distance:
Speed:
Time:
The distance of the travel covered within 5 hours with a speed of 120km/hr is the product of time and this speed and it is 600 km.
What is velocity?Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.
Velocity = distance/time.
Hence, as the time taken for the travel increases velocity will decreases. The time given here is 5 hours and the speed of the vehicle is 120 km/hr. Hence, the distance can be calculated as follows:
Distance = time × speed
= 5 hr × 120 km/hr
= 600 km.
Hence, if you drive at a speed of 120 km/hr for 5 hours you will cover a distance of 600 km.
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suppose you have two identical socks that exert a force of 10 n on each other. now you move them so they are three times as far apart as they were originally. (a) calculate the new force between the objects. (b) will this force be attractive or repulsive? please explain
(a) Since the separation is being tripled the force would go to 1/9 its original value if the charges remained constant because Coulomb's Law is an inverse square law. So, the new force is 10/9 N.
(b) because the pressure remains the equal and it became repulsive, initially, it will remain repulsive. One could also deduce this for the reason that the socks are equal.
Electrostatic repulsion can also be observed, for example, with an electroscope. It's a simple device consisting of a piece of metal sticking out of a glass jar and a thin metal leaf hanging inside. When the outer piece of metal touches the charged body, the Coulomb force causes the sheet to expand.
The repulsive force between oppositely oriented magnets. A compression material that repels the body on both sides. Repulsion is associated with involuntary vomiting such as in response to the ingestion of toxins.
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how much work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed vv to a speed 2v2v?
Using the concepts of work, we got that we need to work three times of the previous work to accelerate the object from a speed v to a speed 2v.
We know that to change the velocity of any object we need to do some work on it.
When an object having some mass m moving with velocity v, then the kinetic energy stored in that object is given by(KE₁) =(1/2)mv².
Now, When an object having some mass m moving with velocity 2v,then the kinetic energy stored in that object is given by(KE₂) =(1/2)m(2v)².
New kinetic energy is =4[(1/2)mv²] or 4KE₁
So, net work to accelerate the object is =KE₂-KE₁
W=4KE₁-KE₁=3KE₁.
Hence, the amount of work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed v to a speed 2v is 3 times the energy stored on a object.
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a resistor r is connected to the terminals of a battery with a potential difference v. as a result of the connection, a direct current i passes through the resistor. if the resistor is replaced by a different resistor with a resistance 3r, what effect, if any, will there be on the current passing through the resistor?
On the basic of Ohm's law , we can see that when resistance increase on replacing then current passing through resistance decreses.
In the given question we have,
resistor r is connected of a battery with potential difference v and a direct current i , passing through the resistor.
According to Ohm's law , the current passing through the condutor is directly proportional to the voltage applied to it and inversely proportional to resistance.
V = IR
where, I ---> current passing through resistor
R----> resistance
V ----> Voltage
or I = V/R ---(1)
Now, it is given that when resistor is replaced by other one and resistance become 3r. From (1) we see as resistance increases the current passing through resistor decreses.
So, as resistance increase by 3r then current passing through resistance decreses by 1/3r.
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a gyroscope slows from an initial rate of 32.0 rad/s at a rate of . (a) how long does it take to come to rest? (b) how many revolutions does it make before stopping?
the revolutions are about 116 revolutions
what is revolution?
A revolution is the movement of one thing around a centre or another object, the forcible overthrow of a government by the people, or any abrupt or large change.
Our solar system, which includes the sun, planets, and numerous asteroids, formed around 4.5 billion years ago. The gravitational collapse of a massive cloud and dust in space resulted in the formation of the solar system. This caused a disturbance in the cloud, causing clumps of gases to form due to gravity.
t=45.7s
α=116 revolutions
ω₀=32.o rad/s, ω=0
α=-0.700 r/s²
ω= ω0 +at
0=32.0r/s+ (-0.700r/s2)t
T= -32/-0.700
=45.7s
We use the equation below to find revolutions.
ω2= ω20 +2aα
substitute the values
0=(32)2 + 2(-0.7r/s2)α
α=731 rad
the rads are converted to revolutions:
α=731x1/2π
=116 revolutions
so the revolutions are about 116 revolutions
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If a 50 N force is applied to a lever and the lever is then able to lift a 150 N object, what is the mechanical advantage of the lever?
Answer:
3
Explanation:
m.a=load÷effort
thus 150N÷50N=3
what is the compressive stress exerted on the soles of your feet by your body weight? assume that each foot has a contact area of 200 cm2, the stress spreads out evenly over that area and that your mass is 72 kg.
The stress that spreads over the soles of the feet by the body is 18000 N/m².
The compressive stress exerted on a body is given by the force applied to the body divided by the area,
So, we can write,
Stress = force/area
In this case, the force will be equal to the weight of the body.
F = Mg
M is the mass of the person,
g is the acceleration due to gravity.
F = 72×10
F = 720N
The area of the soles is given to be 200 cm²
Converting into meter square,
Area = 0.02 m²
As there are two soles,
Area = 0.04
Putting values to find stress,
Stress = 720/0.04
Stress = 18000N/m²
So, the stress on the soles is 18000 N/m².
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A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall. a) Will the ball pass over the wall? b) If not, where will it hit the wall and with what velocity?
(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
It is the amount of change in velocity per unit time. The velocity change can be calculated using the formula: velocity change = final velocity - initial velocity. This is the time when: The rate of change in velocity is expressed in
Given
A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall.
We have to determine
a) Will the ball pass over the wall?
b) If not, where will it hit the wall and with what velocity?
From the given information
Initial velocity v =20m/s
Initial velocity along x direction vx = vcos300
= 20 cos300
= 20 x 0.866
= 17.32m/s
Initial velocity along y direction vy = v sin300
= 20 sin300
= 20 x 0.5
= 10m/s
Displacement along +ve x = 40m
Time required to travel t = x/vx
= 40/17.32
= 2.31seconds
At this time displacement of the ball along the y direction
Sy = vyt – 1/2gdt2
= 10x2.31 – ½ x 9.81 x (2.31)2
= 23.10 – 26.17
= - 3.07m
Since displacement is in a negative value, it will hit the wall and will not pass over the wall
The ball will hit at d distance from the ground
H = (10 – 3.07)
= 6.93m
Final velocity along +ve y = v’y = vy –gt
= 10 – 9.81 x 2.31
= 10 – 22.66
=-12.66m/s
velocity along +ve x = v’y = vx
= 17.32m/s
So-net velocity of the ball v’= √((v^' x)^2+(v^' y)^2 )
= √(〖(17.32)〗^2+〖(-12.66)〗^2 )
= 21.45m/s
Therefore
(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
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you are designing a symmetric double convex lens that is made of glass with index of refraction equal to 1.33 and has a focal length of 0.165 m. what curvature radius of the lens surface should you use (in m; answer a positive number)?
The curvature radius of the lens surface is 0.1089 meters.
The convex lens is a lens that converges rays of light that convey parallel to its fundamental axis (i.e. converges the incident rays toward the main axis) which is highly thick throughout the middle and skinny at the decrease and higher edges. the edges are curved outward in preference to inward.
Calculation:-
Since the double convex is symmetric in nature,
R₁ = R
R₂ = - R
Given, Refractive index (n) = 1.33
The focal length of the double convex lens (l) = 0.156
Now,
1/f = (n-1) (1/R₁ - 1/R₂)
1/f = (n-1) (1/R + 1/R)
1/f = (n-1) × (2/R)
R = 2(n-1)f
= 2 × (1.33 - 1) × 0.165 meter
= 0.1089 meter
Hence, the radius of curvature of the lens surface is = 0.1089 meter
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how do we perceive different wavelengths of light? (hint: frequency is to pitch as wavelength is to )
Using the visual spectrum, we can distinguish between various light wavelengths.
What is visual spectrum?The region of electromagnetic spectrum which the human eye can see is known as the visible light spectrum. This group of wavelengths is more commonly referred to as visible light. The range of wavelengths that the human eye can typically have seen is 380 to 700 nanometers.The colors of the rainbow are represented by the various visible light wavelengths: red, orange, yellow, green, blue, indigo, and violet. Red light has the greatest wavelengths (around 700 nanometers), whereas violet light has the shortest wavelengths (380 nanometers).The visible wavelengths span a region between 0.4 and 0.7 m. Red has the longest visible wavelength, whereas violet has the shortest. The following table lists the typical wavelengths of the visible spectrum, which correspond to the specific colors we can see.To learn more about visual spectrum refer to :
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(ii) a spring with hangs vertically next to a ruler. the end of the spring is next to the 15-cm mark on the ruler. if a 2.5-kg mass is now attached to the end of the spring, and the mass is allowed to fall, where will the end of the spring line up with the ruler marks when the mass is at its lowest position?
If a 2.5 kg mass is attached to a spring with k = 53 N/m, the spring will stretch to 61 cm.
Missing data from the problem:
A spring with spring constant (k) 53 N/m is hang vertically.
Original length of the spring = 15 cm = 0.15 m
A mass of 2.5 kg is attached to the end of the spring.
According to the Hooke's Law:
F = - kx
Where:
F = force applied on the spring
x = spring displacement
From the problem, the only force is the weight of the mass:
F = w = m . g (g = 9.8 m/s²)
F = 2.5 . 9.8 = 24.5 N
Substitute k = 53 N/m,
24.5 = 53 . x
x = 24.5/53 = 0.46 m = 46 cm
Therefore the final length of the spring = 15 + 46 = 61 cm
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A student determines the speed of three cars on a straight road.
The student measured the time for the cars to travel 50m.
Answer:
5.102 m/s
Explanation:
50/9.8=5.102m/s
a particle travels 17 times around a 16-cm radius circle in 38 seconds. what is the average speed (in m/s) of the particle? (remember, never include units with any answer to a numerical question.)
1.065 m / s is the average speed (in m/s) of the particle.
Circumference = 2[tex]\pi[/tex]r
238.14= 2 x 3.14159 x38 cm
238.14 x 17 rotations / 38seconds
= 106.53 cm / second
106.53 cm / 100 cm per meter
= 1.065 m / s
What is average speed?Average speed is the total distance travelled by an object during a certain time interval. Average speed is a scalar quantity. It is represented by size and has no direction.
The formula for average speed is found by calculating the ratio of the total distance travelled by a body to the time required to travel that distance.
The average speed equation is formulated as follows:
Total distance traveled / Total time travelled
[tex]{S_{AVG}}= \frac{D_{totale}}{T_{totale}}[/tex]
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When a person walks on a tile, a potential difference of 40 V is induced across the tile.
The power output of the tile is 4.4 W.
Calculate the current in the tile.
[3 marks]
The current in the tile is 0.11 ampere.
What is electric current?The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Due to not following vector law of addition, current is a scalar quantity.
Given parameters:
Potential difference: V = 40 V.
The power output: P = 4.4 W.
We have to find, the current in the tile; I =?
We know that, power output = current × Potential difference
So, the current in the tile = power output /Potential difference
= 4.4/40 ampere.
= 0.11 ampere.
Hence the current in the tile is 0.11 ampere.
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what physical feature of mars is atypical compared with the other terrestrial planets? what physical feature of mars is atypical compared with the other terrestrial planets? its size its rotation rate its atmospheric content its density its surface composition
The answer of this is "Its surface composition"
Mars is the fourth planet from the Sun and the next planet beyond Earth. It is, on average, more than 142 million miles from the Sun.
Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth. Sometimes the wind blows the red dust into a dust storm. Tiny dust storms can look like tornados, and large ones can be seen from Earth. Mars’ large storms sometimes cover the entire planet.
Mars has about one-third the gravity of Earth. A rock dropped on Mars would fall more slowly than a rock falls on Earth. A person who weighs 100 pounds on Earth would only weigh about 38 pounds on Mars because of the reduced gravity.
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these stick figures are each in a hurry to catch a flight. they are both walking at a speed of 1 m/s on a walkway that has a velocity of 0.5 m/s to the west. explain which stick figure is moving more quickly relative to the ground.
The stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.
Vsg = Vsw + Vwg
Vsg = Relative velocity of stick figure wrt ground
Vsw = Relative velocity of stick figure wrt walkway
Vwg = Relative velocity of walkway wrt ground
Let the stick figure that is walking to the west be A and the stick figure that is walking to the east be B.
For A,
Vsw = - 1 m / s
Vwg = - 0.5 m / s
Vsg = - 1 - 0.5
Vsg = - 1.5 m / s
For B,
Vsw = 1 m / s
Vwg = - 0.5 m / s
Vsg = 1 - 0.5
Vsg = 0.5 m / s
The negative symbol indicates direction. So Vsg for A > Vsg for B
Therefore, the stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.
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How much net force is required to accelerate a 2000 kg car at 3.00 m/s^2
The net force required to accelerate a car is 6000 N.
Force is defined as the product of the mass and acceleration of the body. Force is used to changing the velocity that is to accelerate an object or a body of a particular mass. The unit of Force is Newton or kg m/s^2.
The formula used to calculate the net force is :
F = ma
where, F = Force
m = mass = 2000 kg
a = acceleration = 3.00 m/s^2
∴ F = 2000*3
F = 6000 N
Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.
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two snowmen, one having a mass of 15.0 kg and one having a mass of 20.0 kg, are sitting in a backyard 4.00 m away from each other. where could a third snowman be placed such that the net gravitational force on it by the other two is zero? treat each snowman as an object.
The third snowman will be placed at a distance of 2.1m from the 15.0 kg mass such that the net gravitational force on it by the other two is zero .
Mass of the snowman 1 = M1 = 15 kg
Mass of the snowman 2 = M2 = 20 kg
Distance between both the masses = r = 4 m
Gravitational force is the force that attracts any two objects of mass.
It is also called as attractive force because it always tries to pull masses together, never pushes them apart.Every object in the universe pull each other with the attractive force.Mathematically, Gravitational force, F = [tex]\frac{GM1M2}{r^{2} }[/tex]where G is the gravitational force constant,
M1 and M2 are the masses of the two different bodies respectively,
r is the distance between the masses.
F = [tex]\frac{GM1M2}{r^{2} }[/tex]
Let the mass M3 be the mass which lies between the masses such that the net gravitational force on it by the other two is zero.
F = [tex]\frac{GM1M3}{(r-d)^{2} }[/tex] = [tex]\frac{GM2M3}{(d)^{2} }[/tex]
here 'd' is the distance at which the mass M3 will be placed such that the net gravitational force on it by the other two is zero.
[tex]\frac{GM1M3}{(r-d)^{2} }[/tex] = [tex]\frac{GM2M3}{(d)^{2} }[/tex]
[tex]\frac{M1}{(r-d)^{2} }[/tex] = [tex]\frac{M2}{(d)^{2} }[/tex]
[tex]\frac{15}{(4-d)^{2} }[/tex] = [tex]\frac{20}{(d)^{2} }[/tex]
3[tex]d^{2}[/tex] = 4[tex](4-d)^{2}[/tex]
3[tex]d^{2}[/tex] = 4 (16 + [tex]d^{2}[/tex] - 2*4*d)
3[tex]d^{2}[/tex] = 64 + 4[tex]d^{2}[/tex] - 32d
[tex]d^{2}[/tex] - 32d + 64 = 0
On solving the above quadratic equation we get the values of d as;
d1 = 29.
d2 = 2.1
Since the d is the distance between the two masses therefore it must be less than 4 m, therefore d2 will be considered as the value of d.
Hence the mass M3 should be placed at a distance of 2.1 m away from the mass M1 to get zero as the net gravitational force
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allison has to design a device that converts energy between two different forms. she decides she wants to convert electrical energy into motion and sound. which invention should she model her design after?
The motor is an excellent invention for Allison to use as a model for her device.
People use both interchangeably, but the difference is that motors run on electricity and engines run on combustion. The engine converts various forms of fuels into mechanical force, while the motor transforms electrical energy into mechanical energy.
They operate using principles of electromagnetism, which shows that a force is applied when an electric current is present in a magnetic field. This force creates a torque on a loop of wire present in the magnetic field, which causes the motor to spin and perform useful work.
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a 9 kg hanging mass is connected by a massless cord over a frictionless pulley to a 5 kg block that is sliding on a flat table. if the coefficient of kinetic friction between the block and the table is 0.2, find the tension in the string.
A 9 kg hanging mass is connected by a massless cord over a frictionless pulley to a 5 kg block that is sliding on a flat table. if the coefficient of kinetic friction between the block and the table is 0.2, the tension in the string will be 37.8N
from Newton’s second law we get :
Tension force – f k = mass * acceleration equation 1
Tension force –f k = 5.00 * a
Similarly, for the 9.00−kg mass,
mg - Tension force = mass * acceleration
9.00 * g–Tension force = 9.00 * a
Adding these two equations gives:
9.00 *9.80 − 0.2 * 5 * 9.8 = 14 a
a=5.6 [tex]m/s^{2}[/tex]
substituting this into equation 1
Tension = 5.00* 5.60 + 0.200 * 5.00 * 9.8 = 37.8N
The tension in the string will be 37.8N
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A Mexican Jumping Bean jumps with the aid of a small worm that lives inside the bean. The bean and the worm have a combined mass of 0.002
kg. The bean can jump to a height of 0.01 m.
a. Calculate the potential energy at the maximum height.
b. Determine the total mechanical energy at the maximum height.
c. Determine the potential energy at a height of 0 m (before it lands).
d. Determine the total mechanical energy at a height of 0 m (before it lands).
e. Determine the kinetic energy at a height of 0 m (before it lands).
f. Calculate the velocity at a height of 0 m (before it lands).
The potential energy at the maximum height is 0.000196 J, the total mechanical energy at the maximum height is 0.000196 J, the potential energy at a height of 0 m is 0 J, the total mechanical energy at a height of 0 m is 0.0001936 J, the kinetic energy at a height of 0 m is 0.0001936 J and the velocity at a height of 0 m (before it lands) is 0.44 m/s.
What is potential energy?Potential energy is stored energy that depends on the relative positions of the various parts of the system. When a spring is compressed, its potential energy is increased.A steel ball has more potential energy lifted off the ground than after it hits the ground. Potential energy is the energy stored in an object or matter. This stored energy is based on the position, placement, or state of an object or matter. Rocks at the edge of cliffs have potential energy. Potential energy is converted into kinetic energy when the stone falls. High branches of a tree have potential energy because they can fall to the ground.To learn more about potential energy from the given link :
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A boat crosses a river at 6.65 mph north through a current going 9.87 mph east. What is the resultant velocity of the boat?
Answer:
V = √ ( 6.65² + 9.87² ) ≈ √ 141.64 = 11.90 mph
A car is moving with a velocity of 32.78 m/s when a TURTLE wanders into the road. The driver then hits the brakes and comes to a complete stop over a time period of 4.63 seconds. Calculate the acceleration of the car. Round to the hundredths.
The acceleration of the car is - 7.08 m/s².
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given parameters:
Initial velocity of the car; u = 32.78 m/s.
Take taken to stop it; t = 4.63
Then, the acceleration of the car: a =( final velocity - initial velocity) /time
= (0 - 32.78)/4.63 m/s².
= - 7.08 m/s².
Negative sign indicates that the velocity is decreasing at that rate.
So, the acceleration of the car is - 7.08 m/s².
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How many electrons are located in the outermost orbit in the bohr model of a boron atom?.
Electrons that are located in the outermost orbit in the Bohr model of a boron atom will be 3.
A nucleus with six neutrons and five protons makes up the Bohr model of boron. The K-shell and L-shell electron shells around the nucleus The valence electrons, which make up three of the electrons in the outermost shell of the Bohr diagram, are also present. The orbits of the electrons around the small nucleus are described by the Bohr model of boron.
It utilizes a number of different electron shells, including K, L, M, and N. The number of electrons that each shell can hold varies, with the shell closest to the nucleus having the least energy. The energy levels increase as the shell recedes more. According to the Bohr model, the electrons in an atom may be seen to orbit the nucleus in a variety of orbits with differing energies.
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the distance between x-ray tube and the bucky (the area that stores the film), is referred to as the .
An x-ray cassette is kept in a device called a "bucky" that resembles a drawer. It can be installed either on the wall or underneath the exam table.
These days, buckys have an internal grid that absorbs dispersed radiation to enhance the clarity of x-ray images. The oscillating option that modern buckys have added further aids in preventing scattered radiation from reaching the x-ray cassette and increases the quality of the x-ray image.To ensure that a high-quality x-ray image is created when using Bucky, an increase in radiation exposure parameters (kVp and mAs) is necessary. If Bucky is not utilized, the same x-ray technique can be carried out with lower exposure factors, but the image quality will suffer.To know more about x-ray
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