The products created during nuclear fusion are Energy and Helium Gas
Overall, two positrons, two neutrinos (which convert two of the protons into neutrons), and energy are released along with the fusion of four protons into one alpha particle.
What is Nuclear fission ?Nuclear fission is a nuclear reaction in which low energy neutrons are used to smash the nucleus of an atom into smaller nuclei. In this process, a large amount of energy is released. Nuclear fission reactions are employed in nuclear power reactors due to their simplicity and high energy output.
What is Nuclear fusion ?When two or more atoms come together to produce one heavier nucleus, the process is known as nuclear fusion. This process releases a tremendous quantity of energy, far more than the energy
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In a particular redox reaction, no−2no2− is oxidized to no−3no3− and fe3 fe3 is reduced to fe2 fe2. complete and balance the equation for this reaction in acidic solution. phases are optional
Balanced chemical equation is - 3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O
Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O
3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O
A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.
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Which is incorrect? multiple choice at equilibrium, ecell = 0. e > 0 for a spontaneous process. e = 0 for a spontaneous process. δg < 0 for a spontaneous process. δg = 0 at equilibrium.
The incorrect statement is e = 0 for a spontaneous reaction.
e cell = 0The cell potential is 0 at equilibrium.
e > 0 for a spontaneous reactionFor a spontaneous reaction the value cell potential E cell is positive i.e. >0
e = 0 for a spontaneous reactionThis statement is incorrect because the potential of a cell is positive if the reaction is spontaneous. Hence it cannot be zero.
δ g < 0 for a spontaneous reactionFor a spontaneous reaction gibbs free energy δ g value is negative i.e. < 0
δg = 0 at equilibrium.At equilibrium the value of gibbs free energy is zero i.e. δg = 0
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A 21.496 grams sample of magnesium is burned in air to form magnesium oxide and magnesium nitride. When the products are treated with water,2.813 grams of gaseous ammonia are generated. Calculate the amounts of magnesium nitride and magnesium oxide formed?
25.898 g is the amount of magnesium nitride and magnesium oxide formed.
Step1 2Mg(s)+ O2(g)-----> 2 MgO(s)
3Mg(s)+N2(g)------> Mg3N2(s)
Mg3N2(s)+ 6 H2O(l)---> 3Mg(OH)2 + 2 NH3(g)
Step2 Moles of NH3 = (2.813/17)
Moles of Mg3N2= (1/2) Moles of NH3 = (2.813/2x17)= 2.813/34
Mass of Mg3N2 = (2.813/34) x100 =8.274g (Molar mass of Mg3N2=100)
Step3 Mass of Mg in Mg3N2 =(72/100) x8.274 =5.957g
Mass of Mg converted in MgO= 21.496-5.957=15.539
Moles of MgO= Moles of Mg = 15.539/24
Mass of MgO = 15.539x40/24 =25.898 g.
Magnesium is a cofactor for over 300 enzymatic systems that regulate various biochemical reactions in the body, including protein synthesis, muscle and nerve function, glycemic control, and blood pressure regulation [1-3].
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550. ml of a 0. 40m solution of naoh is titrated with 0. 25 m hcl. calculate the ph of the solution after 650. ml of the hcl has been added
Titration is the determination of quantity by a known amount. The pH of the solution after the solution was added with 650 mL of hydrochloric acid is 13.4.
What is pH?pH is the calculation of the hydrogen ion concentration in the solution and can be used to determine the acidity or the basicity of the solution.
Given,
M₁ = 0.40 M
V₁ = 550 mL
M₂ = 0.25 M
V₂ =?
Volume at 0.25 M is calculated as,
M₁V₁ = M₂V₂
0.40 × 550.0 =0.25 × V2
V2 = 880 ml
880 mL of HCl is required for the neutralization reaction.
The final molar concentration of NaOH is,
550 × M₁ = 0.25 × 650
M₁ = 0.295 M
pH is calculated as:
pOH = -log [OH⁻]
= -log [0.295]
= 0.529
Solving further,
pH+ pOH = 14
pH = 14 - pOH
= 14 - 0.529
= 13.4
Therefore, 13.4 is the pH of the solution.
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What will be the ph of a buffer solution with an acid (pka6. 1) that is exactly half as concentrated as its conjugate base?
The pH of a buffer solution with acid that (PKA 6. 1) is exactly half as concentrated as its conjugate base is 6.4.
What is a buffer solution?A buffer solution is a solution that has a maintained pH, not basic or not acidic. Its pH changes when acid or base is added to the solution.
We had to figure out the acid's concentration, which is exactly half that of its potential base.
We know that pH = pH_log
We have less than 6.1 pH so this is a conjugated base.
This will equal to 6.1 + log2 = 6.4
Thus, the pH of a buffer solution with acid is 6.4.
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How many milliliters of 0. 0140 m na2s2o3 solution are needed to dissolve 0. 590 g of agbr? agbr(s) 2na2s2o3(aq)→na3ag(s2o3)2(aq) nabr(aq)
The molarity of the solution can be used to give the moles and the volume of the solution. The 0.0140 M sodium thiosulfate needs 225 ml of volume.
What is molarity?Molarity is the property of the solution that is given by the ratio of the moles of the solute to the volume of the solution in liters.
Given,
Molarity of Sodium thiosulfate = 0.0140 M
Mass of solute (AgBr) = 0.590 gm
Molar mass of AgBr = 187.77 g/mol
First moles from the mass can be calculated as,
Moles = mass ÷ molar mass
n = 0.590 g ÷ 187.77 g/mol
= 0.00314 moles
Now, the volume of the solution from molarity is calculated as,
Volume = moles ÷ molarity
= 0.00314 moles ÷ 0.0140
= 0.225 L
Therefore, 225 mL is the volume required.
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What is the molality of phosphoric acid, h3po4, in a solution prepared from 376 g of phosphoric acid and 1. 70×103 g of ethylene glycol, c2h4(oh)2?
The molality of phosphoric acid, h3po4, in a solution prepared from 376 g of phosphoric acid and 1. 70×103 g of ethylene glycol, c2h4(oh)2 is 2.25m.
Ethylene Glycol is known as C2H4 (OH)2.
It is used to prepare Antifreeze solution by adding water in it.
Given,
Mass of phosphoric acid = 376g
Mass of ethylene acid = 1.7 × 10 3g
Since ethylene glycol is in excess. So it is acts as a solvent and phosphoric acid acts as solute
As we know that,
Molar mass of phosphoric acid = 98g
Moles of phosphoric acid
= Given mass / Molar mass
=376 / 98
= 3.83
Molality is defined as the ratio of moles of solute to the mass of solvent.
Molality = Moles of solute / Mass of solvent
= 3.83 / 1.7 kg
= 2.25m.
Thus, we found that the molality of phosphoric acid is 2.25m.
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Enough of a monoprotic acid is dissolved in water to produce a 1. 50 m solution. the ph of the resulting solution is 2. 83. calculate the ka for the acid
1.4406 × 10⁻⁶ is the Ka(dissociation constant) for the acid.
The equilibrium constant for the reaction of an acid with water is the acid dissociation constant, where the acid, HA separates into H⁺ and A⁻ ions.
The acid dissociation constant is represented by (Ka).
So let's first imagine that the given monoprotic acid is HA.
HA will dissociate into H⁺ and A⁻ ions.
HA ⇒ H⁺ and A⁻
The formula used for Ka is
Ka = [H⁺] [A⁻] / [HA]
Given
pH = 2.83
[HA] = 1.50 M
From the given pH, we can calculate [H⁺] and [A⁻]
[H⁺] = [A⁻] = 1 × [tex]10^{-2.83}[/tex] = 1.47 × 10⁻³ M
Ka = 1.47 × 10⁻³ × 1.47 × 10⁻³ / 1.50
Ka = 1.4406 × 10⁻⁶
Hence, 1.4406 × 10⁻⁶ is the Ka for the acid.
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) a student makes up a 0. 6 m solution of acetic acid. (note: the pka of acetic acid is 4. 74) a) what is the poh of this solution?
A student makes up a 0. 6 M solution of acetic acid then its pOH of this solution is 13.77
Calculation ,
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
We have to find pH of the acetic acid .
[ [tex]H^{+}[/tex] ] = 0. 6
pH = -㏒[ [tex]H^{+}[/tex] ]
pH = -㏒ [ 0. 6 ]
pH = 0.22
pH + pOH = 14
pOH = 14 - pOH = 14 - 0.22 = 13.77
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Enter your answer in the provided box. calculate the ph of a 0. 39 m ch3cooli solution. (ka for acetic acid = 1. 8 × 10−5. )
The pH of the solution is the negative logarithm of a proton or the hydrogen ion concentration. The pH of 0.39 M acetic acid solution (CH₃COONa) is 2.58.
What is pH?The pH has been said to be the hydrogen ion concentration that can also be given by the pOH.
Given,
The acid dissociation constant Ka = 1.8 × 10⁻⁵
Concentration of acetic acid (C) = 0.39 M
The hydrogen ion concentration from Ka and molar concentration are calculated as:
H⁺ = √ Ka × C
= √1.8 × 10⁻⁵ × 0.39
= √0.00000702
= 0.0026
Now, pH from hydrogen ion is calculated as,
pH = - log [H⁺]
= - log [0.0026]
= 2.58
Therefore, the pH of acetic acid is 2.58.
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Help me, place the element symbol in its location on the chart.
The elements that suits each given property for each of the empty boxes is as described below.
How to interpret the properties of Periodic Tables?For the first box, the property is that it is a conductor and that it has 2 energy levels. The only possible options here will be Lithium (Li) and Beryllium because they are both conductors and have 2 energy levels. However, among the given elements, only Li is given and as such we will select that.
For the second box, the property is that it is a conductor, it has 3 energy levels and has 2 valence electrons. The only element that falls into this category is Magnesium (Mg).
For the third box, the property is that it is a conductor, it has 3 energy levels and has 1 valence electron. The only element that falls into this category is Sodium (Na).
For the fourth box, the property is that it is not a conductor and has 3 energy levels. The only elements that falls into this category are Silicon(Si), Phosphorus(P), Sulphur(S), Argon(Ar). The only given option is Sulphur(S) and we will pick that.
For the fifth box, the property is that it is not a conductor and has 4 energy levels and 7 valence electrons. The only element that falls into this category is Bromine(Br).
For the sixth box, the property is that it is not a conductor and has 4 energy levels and 5 valence electrons. The only element that falls into this category is Arsenic (As).
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What type of bond will typically form between boron and hydrogen based on their electronegativity?
The type of bond will typically form between boron and hydrogen based is boron-hydrogen-boron bridge bond also known as 3 centered two electron bond on the basis of their electronegativity.
What is electronegativity?Electronegativity is a tendency or chances of an element to accepts the single electron from any atom not only the lone pair of electrons.
Fluorine is smallest and the highly electronegative element of the periodic table after that oxygen is also an electronegative element after that nitrogen.
Therefore, it is known as 3 centered two electron bond on the basis of their electronegativity.
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1. There are 42 grams of sugar (C12H22O11) in a can of pop (342mL). Use this information (where necessary) to answer the following questions:
a) How many moles of sugar are there in the pop (3 marks)?
b) If a mole of sugar costs 90 cents, what is the value of the sugar in a can of pop (3 marks)?
c) How many particles of sugar are there in the pop (3 marks)?
d) What is the concentration (mol/L) of the sugar in the pop (3 marks)?
1. The mole of sugar in the pop is 0.123 mole
2. The value of the sugar in the pop is 11.07 cents
3. The number of particles of the sugar in the pop is 0.74×10²³ particles
4. The concentration of the sugar in the pop is 0.36 mol/L
1. How to determine the mole of the sugarMass of sugar (C₁₂H₂₂O₁₁) = 42 gMolar mass of sugar (C₁₂H₂₂O₁₁) = 342 g/molMole of sugar (C₁₂H₂₂O₁₁) =?Mole = mass / molar mass
Mole of sugar (C₁₂H₂₂O₁₁) = 42 / 342
Mole of sugar (C₁₂H₂₂O₁₁) = 0.123 mole
2. How to determine the value of the sugarCost per mole = 90 centsCost of 0.123 mole of sugar =?1 mole of sugar = 90 cents
Therefore,
0.123 mole of sugar = 0.123 × 90
0.123 mole of sugar = 11.07 cents
3. How to determine the number of particles of the sugarFrom Avogadro's hypothesis,
1 mole of sugar = 6.02×10²³ particles
Therefore,
0.123 mole of sugar = 0.123 × 6.02×10²³
0.123 mole of sugar = 0.74×10²³ particles
4. How to determine the concentration of the sugarMole of sugar (C₁₂H₂₂O₁₁) = 0.123 moleVolume = 342 mL = 342 / 1000 = 0.342 L Concentration of sugar =?Concentration = mole / Volume
Concentration of sugar = 0.123 / 0.342
Concentration of sugar = 0.36 mol/L
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What is the molar solubility of a saturated solution of magnesium hydroxide, mg(oh)2, in water? the ksp of mg(oh)2 is 1. 2×10^–11
The molar solubility of saturated solution of magnesium hydroxide in water will be 1.4 × [tex]10^{-4}[/tex].
The concentration of such ions in a suitable solvent that will be in equilibrium with both the solid substance is known as the solubility product, or Ksp, of such an ionic compound.
When a chemical substance in the solid form would be in chemical equilibrium with such a solution of that molecule, a solubility equilibrium would be a sort of dynamic equilibrium that develops.
The molar solubility of magnesium hydroxide can be expressed as:
[tex]K_{sp} = [Mg^{2+} ][OH^{-} ]^{2}[/tex]
Let the molal solubility will be S.
[tex]K_{sp} = S(S^{2} )\\1.2 * 10^{-11} = 4S^{3} \\(S)^{3} = 0.3 *10^{-11} \\S = 1.4 *10^{-4}[/tex]
Therefore, the molar solubility of saturated solution of magnesium hydroxide in water will be 1.4 × [tex]10^{-4}[/tex].
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The Enthalpy profile of chemical reaction is shown at the river. On the graph, indicate the magnitude of:
Energy was given out in the process as such the reaction must be exothermic given the loss of energy.
What is a reaction profile?The reaction profile shows the the interaction between substances. Now the vertical axes shows the energy while the horizontal axes shows the course of the reaction. The hump at the top of the profile shows the activation energy. The activation energy is the maximum energy that is required for reactants to cross the barrier and become products.
Now we know that the endothermic reaction is one in which energy is taken in while an exothermic reaction is one in which energy is given out.
As such we can see from the graph that the energy of the reactants is greater than that of the products. This implies that energy was given out in the process as such the reaction must be exothermic given the loss of energy.
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Gallium exists naturally as a mixture of two isotopes, Gallium - 69 & Gallium - 71. The atomic mass number of gallium is 31.
Relative Atomic Mass of Gallium is 69.8 . Calculate % composition of each isotope
Considering the definition of atomic mass, isotopes and atomic mass of an element, the % composition of each isotope is:
Gallium - 69: 60% Gallium - 71: 40%Definition of atomic massFirst of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.
Definition of isotopeThe same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.
Definition of atomic massOn the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.
% composition of each isotopeIn this case, the first isotope Gallium - 69 has an atomic mass of 69 and a percent natural abundance of X%. The second isotope Gallium - 71 has an atomic mass of 71 and a percent natural abundance of (100-X)%.
On the other hand, the Relative Atomic Mass of Gallium is 69.8 .
Then, the value of X can be calculated as:
69× X+ 71× (1-X)= 69.8
Solving
69× X+ 71× 1- 71× X= 69.8
69× X+ 71- 71× X= 69.8
69× X- 71× X= 69.8 - 71
- 2× X= -1.2
X= (-1.2)÷ (-2)
X=0.6 which expressed as a percentage is X%= 60%.
So, the % compositon of Gallium - 71 is calculated as (100-X)%=(100 -60)%= 40%
Finally, the % composition of each isotope is:
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A label on an empty sample container reads 12. 00 g. you add in a sample of a compound and mass the sample container obtaining 15. 5465 g. what should the mass of the sample be reported as?
The mass of the substance is the quantitative measure of the physical object. The mass of the sample must be reported as 3.5465 g. Thus, option e is correct.
What is mass?The mass of the substance is the quantity of matter that the sample weighs and is reflected in grams or kilograms.
Given,
Mass of empty sample container = 12.00 g
Mass of sample + empty container = 15.5465 g
The mass of the sample will be given as,
mass of sample = (Mass of sample + empty container) - ( Mass of empty container)
= (15.5465 g - 12.00g)
=3.5465 g
Therefore, 3.5465 gm is the mass of the sample, and the correct option is e.
Your question is incomplete, but most probably your full question was, A label on an empty sample container reads 12.00 g. you add in a sample of a compound and the mass of the sample container obtaining 15.5465 g. what should the mass of the sample be reported as?
3.546 g3.54 g4 g4.0 g3.5465 gLearn more about mass here:
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what is the pH value of Potassium hydroxide
Answer:
from 10-14
Explanation:
the pH of potassium hydroxide is extremely high and is a strong base although the exact value depends on the concentration of the base in water.
HELP PLS important plsssssssssssssssss
Answer: All have something wrong with them!!!
Explanation: #1: He is using chemicals without using any goggles or protection
#2: She is unsupervised while around fire as well as no protection
#3:
#4: There are many flammable things around the fire especially since its paper it could start a major fire
#5: Again has no protection (goggles. gloves, e.t.c.) and putting chemicals close to your face is just a Don't in science
#6: They are "horseplaying" and also someone else is doing all the work
In a kitchen, during preparation of food or tea, salt and sugar are
mixed. What methods for separation of this mixture would you
suggest to your mother?
Answer:
A mixture of salt and sugar can be separated by the process of filtration.
Which of the following statements statements expresses the following chemical equation with words?
2 K(s) + Cl₂(g) →> 2 KCI(S)
->
Select one:
O a. Four atoms of krypton react with two molecules of Cl₂
O b. Two atoms of potassium react with one molecule of chlorine to produce two molecules of potassium chloride.
O c. One atom of chromium reacts with 1 molecule of calcium to produce 1 molecule of chromium calcide.
O d. Two atoms of potassium react with potassium chloride to produce chlorine gas.
Answer:
option b is the answer of given statementtwo atoms of potassium react with one molecule of chlorine to produce two molecules of potassium chloride
In a titration experiment, 31. 4 ml of 1. 120 m hcooh is neutralized by 16. 3 ml of ba(oh)2. what is the concentration of the ba(oh)2 solution?
In a titration experiment, 31. 4 ml of 1. 120 M HCOOH is neutralized by 16. 3 ml of [tex]Ba(OH)_{2}[/tex]. So, the concentration of the [tex]Ba(OH)_{2}[/tex] solution is 23.16 M
Calculation,
The formula for the dilution of a solution is given as:
[tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex]
Where M is molarity and V is the volume of the solution in liters ( L ).
Given data,
[tex]M_{1}[/tex] = 120 M
[tex]V_{1}[/tex] =31. 4 ml
[tex]M_{2}[/tex] = ?
[tex]V_{2}[/tex] = 16. 3 ml
120 M ×31. 4 ml = [tex]M_{2}[/tex] × 16. 3 ml
[tex]M_{2}[/tex] = 120 M ×31. 4 ml / 16. 3 ml =23.16 M
In a titration experiment, the concentration of the [tex]Ba(OH)_{2}[/tex] solution is 23.16 M
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Which compound contains a chiral carbon atom? 3-chloropentane 2-bromopropane 3-bromopentane 2-bromopentane
The compound 2-bromopentane contains a chiral carbon atom.
So , option D is correct one.
The carbon which is bonded with four different substituent or four valency of carbon is satisfy by the four different substituent is called chiral carbon and the molecule contain such chiral carbon is called chiral molecule. The molecule contain chiral carbon rotates plane polarized light.
Example: The compound 2-bromopentane contains chiral carbon at second carbon and four different substituent at second carbon is methyl , bromine , propyl and hydrogen.
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1. Fill in the blanks.
a. Breathing is a combined form of______and_______.
b. Oxygen is absorbed by diffusion from______of the lungs.
c. Plants take______gas for respiration. d. Plants have______and______for respiration.
e. Plants have_______and_______for transportation.
Respiration deals with the gaseous exchange that occur between the individuals and the environment.
What is respiration?The term respiration deals with the gaseous exchange that occur between the individuals and the environment. The individuals take in a gas from the environment and pass out a gas to the environment. This is the way in which the balance of the universe is maintained.
Now, plants take in carbon dioxide and give out oxygen whereas animals take in oxygen and give out carbon dioxide. By so doing, the delicate carbon - oxygen balance in nature is maintained unless it is upturned by anthropogenic activities.
The following fill in the blanks as requested in the question;
a) Inhalation and exhalation'
b) trachea
c) carbon dioxide
d) leaves and stomata
e) xylem and phloem
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Answer:
a) inhalation and exhalation
b) trachea
c) carbon dioxide
d) leaves and stomata
e) xylem and phloem
How does the mass per nucleon of an element change as the atomic number increases?
Answer:
Explanation: So, the atomic number is the number of protons present in an atom. For example, Helium's atomic number is 2, meaning it only has 2 protons. In most cases, the number of nuetrons and protons are equal, so Helium (usually) has 2 protons and 2 nuetrons - this is the nucleus. The atomic mass, or mass per nucleon is the proton and nuetron added together, so the atomic mass of Helium is about 4. Therefore, on the periodic table, as the atomic number increases by 1, the atomic mass increases by about 2 (the atomic mass is an average so it's not exact).
Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a strong acid; ka for hso4− = 1. 3 × 10−2. ) [hso4−] = m [so42−] = m [h ] = m
At equilibrium the concentrations of:
[HSO₄⁻] = 0.10 M;
[SO₄²⁻] = 0.037 M;
[H⁺] = 0.037 M;
There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.
HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid. HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.
R [tex]HSO_4^-[/tex] ⇄ [tex]H^+ + SO_4^2^-[/tex]
I [tex]0.14[/tex]
C [tex]- x[/tex] [tex]+x[/tex] [tex]+x[/tex]
E [tex]0.14-x[/tex] [tex]x[/tex] [tex]x[/tex]
[tex]K_a = 1.3[/tex] × [tex]10^-^2[/tex] for [tex]HSO^-_4[/tex] . As a result,
[tex]\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a[/tex]
[tex]K_a[/tex] is large. It is no longer valid to approximate that [tex][HSO^-_4][/tex] at equilibrium is the same as its initial value.
[tex]\frac{x^2}{0.14-y} = 1.3 * 10^-^2[/tex]
[tex]x^2+1.3*10^-^2x - 0.14[/tex] × [tex]1.3[/tex] × [tex]10^-^2= 0[/tex]
Solving the quadratic equation for [tex]x , x \geq 0[/tex] since [tex]x[/tex] represents a concentration;
[tex]x=0.0366538[/tex]
Then, round the results to 2 significant figure;
[tex][SO_4^2^-] = x = 0.037 mol. L ^-^1[/tex][tex][H^+] = x = 0.037 mol. L ^-^1[/tex][tex][HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1[/tex]Learn more about concentration here:
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A solution of acetic acid, hc2h3o2, on a laboratory shelfwas of undetermined concentration. if the ph of the solution wasfound to be 2. 68, what was the concentration of the acetic acid?
A solution of acetic acid , on a laboratory shelf was of undetermined concentration. if the pH of the solution was found to be 2. 68 , then its the concentration of the acetic acid was 2×[tex]10^{-3}[/tex]
Calculation ,
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
We have to find concentration of the acetic acid .
pH = 2. 68
pH = -㏒[ [tex]H^{+}[/tex] ]
2. 68 = -㏒[ [tex]H^{+}[/tex] ]
[ [tex]H^{+}[/tex] ] = [tex]10^{-2.68}[/tex]
[ [tex]H^{+}[/tex] ] = 2×[tex]10^{-3}[/tex]
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[?] describes how small molecules can be selectively removed from a colloidal suspension while retaining large molecules.
A) Dialysis
B) The Tyndall effect
Answer:
using a centrifuge
Explanation:
Centrifugation will make the large molecules to settle at the bottom.
The Most suitable answer is tyndall effect
another student collected boiling point data of 10 different substances. Should he display his results in a line graph or a bar chart.
Answer:
Bar chartExplanation:
Because if he displays his or her result in a line graph the Boling data of 10 different substances will be incorrect.Hope it helps you
When you created hypotheses to guess whether each chemical was an acid or base, what specifically did you look for in the chemical formulas?
While assigning a term for a chemical to be an acid or base we have to look for the [tex]H^{+}[/tex] ions that can be donated by a chemical formulas or [tex]OH^{-}[/tex] ions for the basic , When you created hypotheses to guess whether each chemical was an acid or base,
To determine whether a substance is an acid or base , count the hydrogen on each substance before and after the reaction . If the number of hydrogens has decreased the substance is the acid ( donates hydrogen ions ) . If the number of hydrogens has increased that substance is the base ( accepts hydrogen ion )
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