Which linear system has this matrix of constants? `[[12],[11],[4]]` a, b, c or d
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Which Linear System Has This Matrix Of Constants? `[[12],[11],[4]]` A, B, C Or D IMAGE ATTACHED

Answers

Answer 1

The following linear system has [[12], [11], [4]] matrix of constants,

x + y + z = 12

x - y = 11

x - y + z = 4  

(Option D)

Verification of the Choice:

The given linear system is,

x + y + z = 12

x - y = 11

x - y + z = 4  

This can be written in the form of matrix as follows,

[tex]\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right][/tex] [tex]\left[\begin{array}{}x&y&z\end{array}\right][/tex] = [tex]\left[\begin{array}{}12&11&4\end{array}\right][/tex]

Hence, option D is the correct linear system as it contains the desired matrix.

About the Other Options:

The RHS matrix in option A would be,

[tex]\left[\begin{array}{}26&17&23\end{array}\right][/tex] which is not the desired matrix.

Similarly, the linear systems in the options B and C contain the matrix [tex]\left[\begin{array}{}23&17&26\end{array}\right][/tex] and the matrix  [tex]\left[\begin{array}{}4&11&12\end{array}\right][/tex] on the RHS of the equality, which are not desired.

Thus, option D is correct.

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Related Questions

The table shows the cost of birdseed at the Feed n Seed store. What is the constant of proportionality between the cost and the number of pounds?

A table titled Feed n Seed Bird Seed. The table has 2 columns, Pounds and Cost. Row 1 says 5, 2 dollars and ninety-five cents. Row 2 says ten, five dollars and ninety cents. Row 3 says fifteen, 8 dollars and eighty-five cents.
A
0.59

B
0.60



C
1.18

D
2.95

Answers

The constant of proportionality between the cost and the number of pounds is: A. 0.59.

What is Constant of Proportionality?

The constant of proportionality of a relationship between two variables X and Y can be defined as the ratio between of X and Y at a constant value. This means that the ratio or product of X and Y will give us a constant if both are in a proportional relationship.

Thus, the constant of proportionality for the  relationship between two variables X and Y would be calculated as:

Constant of proportionality (k) = Y/X. [this is the proportional between the two quantities, X and Y].

Given the table of values, using a pair of points on the table, say, (5, 2.95), we can calculate the constant of proportionality as:

X = 5

Y = 2.95

Constant of proportionality (k) = Y/X = 2.95/5

Constant of proportionality (k) = 0.59 pounds per dollar.

Therefore, the constant of proportionality between the cost and the number of pounds is: A. 0.59.

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Solve for t.......
[tex]4 (t + \cfrac{1}{4} \: ) = 3[/tex]​

Answers

Answer:

[tex]t = \cfrac{1}{2}[/tex]

Step-by-step explanation:

Given equation:

[tex]4(t+\cfrac{1}{4})=3[/tex]

Divide both sides by 4:

[tex]t+\cfrac{1}{4}=\cfrac{3}{4}[/tex]

Subtract 1/4 from both sides:

[tex]t = \cfrac{3}{4}- \cfrac{1}{4}[/tex]

[tex]t = \cfrac{2}{4}[/tex]

Simplify:

[tex]t = \cfrac{1}{2}[/tex]

Answer:

[tex]t = \frac{1}{2} [/tex]

Step-by-step explanation:

[tex]4(t + \frac{1}{4} ) = 3[/tex]

Divid the whole equation by 4.

[tex] \frac{4(t + \frac{1}{4} )}{4} = \frac{3}{4} [/tex]

[tex](t + \frac{1}{4} ) = \frac{3}{4} [/tex]

[tex]t + \frac{1}{4} = \frac{3}{4} [/tex]

Take 1/4 to right side.

[tex]t = \frac{ 3}{4} - \frac{1}{4} [/tex]

[tex]t= \frac{2}{4} [/tex]

To simplify the answer more divide the numerator and denominator by 2.

[tex]t = \frac{1}{2} [/tex]

Helpppppp What’s the prime factorization of 36 and 22

Answers

To do this question I recommend dividing each number by the lowest prime number you can each time.

36/2=18
18/2=9
9/3=3
Since 3 is prime we stop there. The prime factors of 36 are therefore 2,2,3, and 3. I would write this as 36=2^2x3^2

22 is simpler as it is just 2x11

Show Work Please Thank You

Answers

The angles in degrees to radian is as follows:

-54 degrees = -3π / 10 radian

How to convert from degree to radian?

The measurement is in degrees. Let's convert it to radian with respect to π.

Therefore,

180 degrees = π radian

-54 degrees = ?

cross multiply

Hence,

angle in radian = -54 × π / 180

angle in radian = - 54π / 180

angle in radian = - 6π / 20

angle in radian = -3π / 10 radian

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Which expression could represent the length of a rectangle that has an area equal to 4x2+12x?

Answers

there are two expressions that can represent the length of the rectangle, these two expressions are:

L = x

or

L = (4x + 12)

Which expression could represent the length of the rectangle?

Remember that for a rectangle of length L and width W, the area is given by:

A = L*W

In this case, we know that the area is:

[tex]A = 4x^2 + 12x[/tex]

We can factorize that expression into:

[tex]A = x*(4x + 12)[/tex]

So there are two expressions that can represent the length of the rectangle, these two expressions are:

L = x

or

L = (4x + 12)

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y=3x-4 and y= -x+2 to find the system of equations

Answers

Answer:

x=3/2 y=1/2

Step-by-step explanation:

If the measure of WZX is 262 what is the measure of XWY?

Answers

Answer:

49°

Step-by-step explanation:

The circumference of a circle measures 360 degrees, so arc XW is 98°.

So, angle XWY is 49°.

Please i need help for this calculus

Answers

Step-by-step explanation:

First thing first, let find the x value of where P and Q both meet y=5, we know that y=5, and y=2x^2+7x-4, so using transitive law,

[tex]5 = 2 {x}^{2} + 7x - 4[/tex]

[tex]2 {x}^{2} + 7x - 9[/tex]

[tex]2 {x}^{2} - 2x + 9x - 9[/tex]

[tex]2x(x - 1) + 9(x - 1)[/tex]

[tex](2x + 9)(x - 1) = 0[/tex]

[tex]x = 1[/tex]

[tex]2x + 9 = 0[/tex]

[tex]x = - \frac{9}{2} [/tex]

Now, to find the gradient of the curve let take the derivative of both sides

[tex]5 = 2 {x}^{2} + 7x - 4[/tex]

[tex]0 = 4x + 7[/tex]

[tex]4x + 7[/tex]

Plug in -9/2, let call that point P

[tex]4( \frac{ - 9}{2} ) + 7 = - 11[/tex]

Plug in 1, let call that point Q

[tex]4(1) + 7 = 11[/tex]

So the gradient of the curve at point P (-9/2,5) is -11

The gradient of the curve at point Q (1,5) is 11.

4(6)^x 864 for x answer for x

Answers

Answer:

  x = 3

Step-by-step explanation:

Maybe you want the value of x such that ...

  4(6^x) = 864

Solution

Dividing by 4 gives ...

  6^x = 216

You may know that 216 = 6^3. Using that, we can equate exponents:

  6^x = 6^3

  x = 3

Alternatively, we can use logarithms to find x. Taking logs gives ...

  x·log(6) = log(216)

  x = log(216)/log(6) = 3

A lender requires PMI that is 0.8% of the loan amount of $470,000. How much (in dollars) will this add to the borrower's monthly payments? (Round your answer to the nearest cent.)
$

Answers

The amount add to the borrower's monthly payment is $313.33.

Given that lender requires PMI that is 0.8% of the loan amount of $470,000.

A loan's PMI, or personal mortgage insurance, is a type of mortgage insurance used by lenders when making traditional loans such as home loans. A PMI helps cover the loss to the lender (bank) if the borrower stops making monthly mortgage payments on their home loan. Therefore, the PMI can be described as a kind of risk mitigation tool for the bank when the borrower defaults on their EMIs (monthly mortgage payments). So, PMI for a borrower is an additional cost or payment for the borrower on top of his monthly payments i.e. EMI.

Thus, the additional amount of dollars that the borrower has to pay for the PMI on his loan along with his monthly mortgage payments

= Principal Loan amount × (PMI/12)

= $470,000 × (0.8%/12)

= $470,000 × (0.008/12)

= $470,000 × 0.0006666667

=$313.333349

Hence, the additional monthly payment for PMI where lender requires PMI that is 0.8% of the loan amount of $470,000 is $313.33.

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Solve rs + t = u for the variable s

Answers

Answer:

[tex]s=\frac{u}{r} -\frac{t}{r}[/tex]

Step-by-step explanation:

You have to move the variables (r and t) with u to isolate s.

[tex]rs+t=u[/tex]

   [tex]-t[/tex]       [tex]-t[/tex]

------------------------

[tex]rs=u-t[/tex]

÷ [tex]r[/tex]       ÷ [tex]r[/tex]

------------------------

[tex]s=\frac{u}{r} -\frac{t}{r}[/tex]

Which sequence has a common difference of -8?

{63, 71, 79, 87, 95, …}

{800, 8, 12.5, 1.5625, …}

{536, 528, 520, 512, 504, …}

{1, -8, 64, -512, 4,096, …}

Answers

Answer is the last choice (1,-8,64,-512,4096).

These numbers are all multiplied by -8 to get the next number in the sequence.

8 ABC please trig assignment

Answers

Using equivalent angles, the solutions are given as follows:

a) [tex]x = \frac{15\pi}{23}[/tex].

b) [tex]x = \frac{9\pi}{62}, x = \frac{53\pi}{62}[/tex].

c) [tex]x = \frac{3\pi}{8}, \frac{11\pi}{8}[/tex]

What are equivalent angles?

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

For item a, we have to find the equivalent angle on the 2nd quadrant, where the sine is also positive.

Hence:

[tex]\pi - \frac{8\pi}{23} = \frac{23\pi}{23} - \frac{8\pi}{23} = \frac{15\pi}{23}[/tex]

Hence [tex]x = \frac{15\pi}{23}[/tex].

For item b, if two angles are complementary, the sine of one is the cosine of the other.

Complementary angles add to 90º = 0.5pi, hence:

[tex]x + \frac{11\pi}{31} = \frac{\pi}{2}[/tex]

[tex]x = \frac{31\pi}{62} - \frac{22\pi}{62}[/tex]

[tex]x = \frac{9\pi}{62}[/tex]

The equivalent angle on the second quadrant is:

[tex]\pi - \frac{9\pi}{62} = \frac{62\pi}{62} - \frac{9\pi}{62} = \frac{53\pi}{62}[/tex]

Hence the solutions are:

[tex]x = \frac{9\pi}{62}, x = \frac{53\pi}{62}[/tex]

For item c, the angles are also complementary, hence:

[tex]x + \frac{\pi}{8} = \frac{\pi}{2}[/tex]

[tex]x = \frac{4\pi}{8} - \frac{\pi}{8}[/tex]

[tex]x = \frac{3\pi}{8}[/tex]

The tangent is also positive on the third quadrant, hence the equivalent angle is:

[tex]x = \pi + \frac{3\pi}{8} = \frac{8\pi}{8} + \frac{3\pi}{8} = \frac{11\pi}{8}[/tex]

Hence the solutions are:

[tex]x = \frac{3\pi}{8}, \frac{11\pi}{8}[/tex]

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How many solutions does the system have?
Y= 4x8
4y = 4x - 8

Answers

The number of solutions to the system is 1

What is a linear equation?

A linear equation is a equation that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

How to determine the number of solution to the system?

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

y = 4x + 8

4y = 4x - 8

Substitute y = 4x + 8 in 4y = 4x - 8

4(4x + 8) = 4x - 8

Expand the equation

16x + 32 = 4x - 8

Evaluate the like terms

12x = - 40

Divide by 12

x = -10/3

The above means that the number of solutions to the system is 1

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B) Using the two point above find the slope using the formula m =
y/₁y₁
x₂-1
C) Plug in your slope and one of the two points above into point-slope formy - y₁ = m(x-x₁)
D) Change above equation into slope-intercept form y = mx + b. (See page 5 in lesson 5.06).
16+20

Answers

The linear equations are y - 25 = 0.89(x - 20) and y  = 0.89x + 7.2

The slope of the line

The complete question is added as an attachment

The two points from the graph are (20, 25) and (38, 41)

The slope of the line is calculated using

m = (y2 - y1)/(x2 - x1)

Substitute the known values in the above equation

m = (41 - 25)/(38 - 20)

Evaluate

m =0.89

The linear equation in point slope form

This is calculated as:

y - y1 = m(x - x1)

Substitute the known values in the above equation

y - 25 = 0.89 * (x - 20)

Evaluate

y - 25 = 0.89(x - 20)

The linear equation in slope-intercept form

We have:

y - 25 = 0.89(x - 20)

Expand

y - 25 = 0.89x - 17.8

Add 25 to both sides

y  = 0.89x + 7.2

Hence, the linear equations are y - 25 = 0.89(x - 20) and y  = 0.89x + 7.2

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Leila bought 3 gallons of milk in one-gallon containers. She paid $9.75. QUESTION: What is the unit rate?

Answers

Hello and Good morning/afternoon:

Let's take this problem step-by-step:

What does the problem want:

 ⇒ unit rate ⇒ price per gallon

What does the problem give us:

  ⇒ price of all three milk

  ⇒ number of gallons of milk bought

Therefore

   [tex]\hookrightarrow \text {unit rate} = \text{total amount of money spent} / \text {total amount of milk bought}\\\\\hookrightarrow\text{unit rate} = 9.75 / 3 = 3.25 _. \text {dollar per gallon}[/tex]

Answer: 3.25 dollars per gallon

Hope that helps!

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03* For which one of the following functions is (-1,-1) a relative minimum?
f(x,y)=xy + 1/x + 1/y
f(x,y)=x^2 +2x
f(x,y)=xy-y^2
f(x,y)=xy-1/x-1/y​

Answers

If (-1, -1) is an extremum of [tex]f[/tex], then both partial derivatives vanish at this point.

Compute the gradients and evaluate them at the given point.

[tex]f(x,y)=xy+\frac1x +\frac1y[/tex]

[tex]\nabla f = \left\langle y - \dfrac1{x^2}, x - \dfrac1{y^2}\right\rangle \implies \nabla f (-1,-1) = \langle-2,-2\rangle \neq \langle0,0,\rangle[/tex]

[tex]f(x,y) = x^2+2x[/tex]

[tex]\nabla f = \langle 2x+2,0\rangle \implies \nabla f(-1,-1) = \langle0,0\rangle[/tex]

[tex]f(x,y)=xy-y^2[/tex]

[tex]\nabla f = \langle y, x-2y\rangle \implies \nabla f(-1,1) = \langle-1,1\rangle \neq\langle0,0\rangle[/tex]

[tex]f(x,y) = xy-\frac1x-\frac1y[/tex]

[tex]\nabla f = \left\langle y + \frac1{x^2}, x + \frac1{y^2}\right\rangle \implies \nabla f(-1,1) = \langle0,0\rangle[/tex]

The first and third functions drop out.

The second function depends only on [tex]x[/tex]. Compute the second derivative and evaluate it at the critical point [tex]x=-1[/tex].

[tex]f(x,y) = x^2+2x \implies f'(x) = 2x + 2 \implies f''(x) = 2 > 0[/tex]

This indicates a minimum when [tex]x=-1[/tex]. In fact, since this function is independent of [tex]y[/tex], every point with this [tex]x[/tex] coordinate is a minimum. However,

[tex]x^2 + 2x = (x + 1)^2 - 1 \ge -1[/tex]

for all [tex]x[/tex], so (-1, 1) and all the other points [tex](-1,y)[/tex] are actually global minima.

For the fourth function, check the sign of the Hessian determinant at (-1, 1).

[tex]H(x,y) = \begin{bmatrix} f_{xx} & f_{xy} \\ f_{yx} & f_{yy} \end{bmatrix} = \begin{bmatrix} -2/x^3 & 1 \\ 1 & -2/y^3 \end{bmatrix} \implies \det H(-1,-1) = 3 > 0[/tex]

The second derivative with respect to [tex]x[/tex] is -2/(-1) = 2 > 0, so (-1, -1) is indeed a local minimum.

The correct choice is the fourth function.

WILL GIVE BRAINLIEST




Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.

1) 50 mph

2) 70 mph

3) x mph

4) (x+10)mph

5) (x-5)mph

Answers

The length of the trip at a distance of 300 miles and the given times are

6 hours30/7 hours300/x hours300/x + 10 hours300/x - 5 hoursHow to determine the length of the trip?

The distance is given as:

d = 300

The formula is represented as:

d = r * t

Make t the subject

t = d/r

Substitute 300 for d

t = 300/r

When r = 50 mph,

t = 300/50

Evaluate

t = 60

When r= 70 mph, we have

t = 300/70

Evaluate

t = 30/7

When r = x, we have

t = 300/x

When r = x + 10, we have

t = 300/x + 10

When r = x - 5, we have

t = 300/x - 5

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Complete question

A train traveled 300 miles. How long did the trip take if the train was traveling at a rate of:

Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.

Please help, will mark brainliest.

Answers

Divide the interval [3, 5] into [tex]n[/tex] subintervals of equal length [tex]\Delta x=\frac{5-3}n = \frac2n[/tex].

[tex][3,5] = \left[3+\dfrac0n,3+\dfrac2n\right] \cup \left[3+\dfrac2n,3+\dfrac4n\right]\cup\left[3+\dfrac4n,3+\dfrac6n\right]\cup\cdots\cup\left[3+\dfrac{2(n-1)}n, 3+\dfrac{2n}n\right][/tex]

The right endpoint of the [tex]i[/tex]-th subinterval is

[tex]r_i = 3 + \dfrac{2i}n[/tex]

where [tex]1\le i\le n[/tex].

Then the definite integral is given by the Riemann sum

[tex]\displaystyle \int_3^5 \sqrt{8+x^2} \, dx = \lim_{n\to\infty} \sum_{i=1}^n \sqrt{8+{r_i}^2} \Delta x = \boxed{\lim_{n\to\infty} \frac2n \sum_{i=1}^n \sqrt{17 + \frac{12i}n + \frac{4i^2}{n^2}}}[/tex]

Which statement is true?

1-31 = 3 and -1-4| = -4
1-31 = 3 and 1-4| = -4
-131 = 3 and 14| = 4
1-31 = 3 and -14| = 4

Answers

Answer:

  |-3| = 3 and -|-4| = -4

Step-by-step explanation:

The absolute value function changes the sign to positive, if it isn't already. The usual rules of arithmetic and logic apply to these statements.

|-3| = 3 (true) and -|-4| = -4 (true)   ⇒ this statement is true

|-3| = 3 (true) and |-4| = -4 (false)   ⇒ this statement is false

-|3| = 3 (false) and |4| = 4 (true)   ⇒ this statement is false

|-3| = 3 (true) and -|4| = 4 (false)   ⇒ this statement is false

__

Additional comment

A compound "and" statement is only true if all of the parts of it are true.

If s(x) = x - 7 and f(x) = 4x²-x + 3, which expression is equivalent to (t*s) (x)?

Answers

Answer: [tex]4x^3 -29x^2 +10x-21[/tex]

Step-by-step explanation:

[tex](4x^2 -x+3)(x-7)\\\\=4x^3 -28x^2 -x^2 +7x+3x-21\\\\=4x^3 -29x^2 +10x-21[/tex]

Let f(x)=x^2 and g(x)=(x+3)^2. Describe the transformation from f(x) to g(x).


Select one:

Shift right 3
Shift up 3
Shift down 3
Shift left 3

Answers

Answer:

shift left 3

Step-by-step explanation:

(x+3)²

x = -3

therefore translation by (-3,0)

The negative number shows it move to the left

I need help with this question

Answers

The cost of goods sold using LIFO is $99.

Cost of goods  sold using LIFO

Using this formula

Cost of goods sold=(March 3 Purchased units × March 3 Purchase price)+ [(March 3 Purchased units -March 9 sold units)×March 1 Beginning inventory cost]

Let plug in the formula

Cost of goods sold=(15 units×$3.90)+[(22 units-15 units)×$5.80]

Cost of goods sold=$58.5+(7 units×$5.80)

Cost of goods sold=$58.5+$40.6

Cost of goods sold=$99.1

Cost of goods sold=$99 (Approximately)

Therefore the cost of goods sold using LIFO is $99.

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Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places.
P(X ≥ 5), n=6, p=0.3

Answers

The probability of obtaining a success is 0.010935.

Given that the probability of obtaining success is P(X>=5),n=6,p=0.3.

We are required to find the probability of obtaining a success if the probability is P(X>=5).

Probability is basically likeliness of happening an event among all the events possible.

Binomial distribution is basically the discrete probability distribution of the number of successes in a sequence of n independent experiments.

[tex](a+b)^{n} =nC_{0}p^{0} (1-p)^{n-0}+-----------nC_{n} p^{n} (1-p)^{0}[/tex]

We have to just put n=6 anr r=6 and 5 one by one to get the probability.

P(X>=5)=[tex]6C_{5}(0.3)^{5} (0.7)^{1} +6C_{6}(0.3)^{6} (0.7)^{0}[/tex]

=6!/5!1!8*0.00243*0.7+0.000729

=6*0.00243*0.7+0.000729

=0.010206+0.000729

=0.010935

Hence the probability of obtaining a success if the probability is P(X>=5) is 0.010935.

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Help me with this question please. ASAP!

Answers

Answer:

Step-by-step explanation:

I am going to be honest here. I know the answer is 22 but I cant really explain it you kinda just have to trust I'm right.

FIND THE INDICATED PROBABILITY FOR THE FOLLOWING:
IF P(A OR B) = 0.9, P(A) = 0.5, AND P(B) = 0.6, FIND P(A AND B)

Answers

The value of the probability P(A and B) is 0.20

How to determine the probability?

The given parameters about the probability are

P(A or B) = 0.9

P(A) = 0.5

P(B) = 0.6

To calculate the probability P(A and B), we use the following formula

P(A and B) = P(A) + P(B) - P(A or B)

Substitute the known values in the above equation

P(A and B) = 0.5 + 0.6 - 0.9

Evaluate the expression

P(A and B) = 0.2

Hence, the value of the probability P(A and B) is 0.20

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ASAP help me with this question PLEAZE

Answers

Answer:

38°

Step-by-step explanation:

EFGH is an isosceles trapezoid (a trapezoid with two congruent legs is isosceles)

∠HGF=70° (base angles of an isosceles trapezoid are congruent)

∠EGH=32° (angles in a triangle add to 180°)

∠FGE=38° (angle subtraction postulate)

Can someone please help meee<3

Answers

Answer:

36

Step-by-step explanation:

[tex]\sqrt{24a}=12\sqrt{6} \\ \\ 24a=864 \\ \\ a=36[/tex]

The Bureau of Alcohol, Tobacco, and Firearms (BATF) has been concerned about lead levels in California wines. In a previous testing of wine specimens, lead levels ranging from 47 to 660 parts per billion were recorded. How many wine specimens should be tested if the BATF wishes to estimate the true mean lead level for California wines to within 10 parts per billion with 95% confidence? (Round your answer up to the nearest whole number.)

Answers

The number of specimens should be tested is 1352.

According to the statement

we have to given that the in testing of wine specimens, lead levels ranging from 47 to 660 parts per billion were recorded. and we have to find the number specimen should be tested.

so,

Using the uniform and the z-distribution, it is found that 1353 specimens should be tested.

For an uniform distribution of bounds a and b, the standard deviation is given by:

σ = [tex]\sqrt{\frac{(b-a^{2})}{12} }[/tex]

and put the values a= 50 and b= 700 then the

standard deviation is 187.64

And here the critical value become 1.6 then

We want the sample for a margin of error of 10, thus, we have to solve for n with the help of value of m is 100.

Then n is 1352.

So,  The number of specimens should be tested is 1352.

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6. Dacă a + 2b = 18 şi b+3c=17, calculaţi 3a+8b+6c.

Answers

Answer:

Răspuns: 88=>rezultatul

Explicație pas cu pas:

a+2b =18/×3

b+3c=17/×2

3a+6b =54 ^

2b+6c=34 | +

3a+(6b+2b)+6c=54+34

3a+8b+6c=88

Step-by-step explanation:

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