which of the following best describe lineation? multiple select question. it may be due to elongated mineral crystals that grow in linear orientation. it is the same thing as cleavage. it is the same as gneissic foliation. it can form under ductile shearing. stretched-out mineral crystals may show lineation.

The initial kinetic energy is zero because the girl was at rest. The final kinetic energy is thus, 3100 J. Therefore, the change in kinetic energy is 3100 J

Kinetic energy of an object is generated by virtue of its motion. It is related to the mass and velocity of the object as follows:

Ke = 1/2 mv²

Given that, mass of girl = 50 kg

mass of bicycle = 12 kg.

total mass = 62 kg.

velocity = 10 m/s.

Then initial kinetic energy  = 0 since v = 0.

Then, ΔKe = 1/2 62 kg × (10 m/s)² - 0 = 3100 J

Therefore, the change in kinetic energy of the girl is 3100 J.

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For those interested in mineral or petroleum extraction, "Who owns the land under a body of water" are especially important in the united states.

Hence, option (a) is the correct choice.

An easement appurtenant has to meet each of the requirements below: Benefit the owner of a dominating estate rather than a person unrelated to real estate. Benefit the owner of a dominating estate in terms of how the property is used physically. Include a dominating and subservient tenement or estate.

A quitclaim deed typically contains the legal description of the property, the grantor and grantee's names, the date, and both parties' notarized signatures. It may also include the name of the grantor and grantee.

An entity can utilise the property for right-of-way, fishing, grazing, and burial if they are granted an easement in gross over it.

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The missing option may be:

(a) Who owns the land under a body of water.

(b) Who owns the land above a body of water.

(c) Any of the above

255.7 KJ of heat is needed to decompose water and produce 17g of oxygen.

Balance chemical reaction is given by,

H₂O → H₂ + 1/2 O₂ .

Atomic mass of H = 1 u ,

Atomic mass of O = 16 u ,

Molar mass of H₂O = 2 × 1 + 1 × 16 = 18 g/mol ,

Molar mass of O₂ = 2 × 16 = 32 g/mol ,

Moles = mass/molar mass ,

Moles of H₂O = 100/18 = 5.555 mol ,

Moles of O₂ = 17/32 = 0.5312 mol ,

From balanced chemical reaction :

1 mol H₂O --------> 0.5 mol O₂

x --------> 0.5312 mol O₂ .

x = 0.5312/0.5 = 1.0625 mol H₂O

Moles of H₂O = 1.0625 mol  ,

Hence ,

5.555 mol H₂O ----------> 1337 KJ

1.0625 mol H₂O ----------> x

x = 1.0625 mol H2O × 1337 KJ/5.555 mol H₂O

x = 255.7 KJ .

Heat = 255.7 KJ .

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The liquid rise in the capillary tube when the boiling substance cools below the boiling point due to decrease in vapor pressure.

As the liquid cools down, its vapor pressure will decrease and when the vapor pressure drops just below atmospheric pressure, the liquid will be automatically drawn into the capillary tube (forced there by the higher atmospheric pressure).

The energy that is required for the liquid molecules to expand to the gas phase increases as the pressure applied to the liquid surface increases, requiring a greater temperature to transform the liquid to gas phase. As a result of this when pressure rises, the boiling point of a liquid rises.

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To determine how many Faradays are needed to deposit 10.5 g of copper onto the surface of an electrode from a solution of Cu2+, we can use the relationship between the amount of electric charge (Q) required for a redox reaction and the number of moles of a substance involved in the reaction (n).

One Faraday (F) of electric charge is defined as the amount of charge required to react with one mole of electrons. In this case, the reaction involves the reduction of Cu2+ ions to Cu atoms at the electrode surface, so we need to determine the number of moles of Cu2+ ions that are required to produce 10.5 g of copper.The molar mass of copper is 63.55 g/mol, so 10.5 g of copper corresponds to 10.5 g / 63.55 g/mol = 0.165 moles of copper. Since the reaction involves a 1:1 stoichiometry between Cu2+ ions and Cu atoms, we also have 0.165 moles of Cu2+ ions.

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The gross profit percentage for 20X3 was 69.7% (Option C).

Gross profit is the amount by which revenue from sales exceeds the cost of goods sold. It is calculated as follows:

Gross profit = Net sales revenue - Cost of goods sold

To calculate the gross profit percentage, we divide the gross profit by the net sales revenue and multiply by 100 to express the answer as a percentage:

Gross profit percentage = (Gross profit / Net sales revenue) x 100

Using the information given in the question, we can calculate the gross profit and gross profit percentage for 20X3 as follows:

Gross profit = 198 billion - Cost of goods sold

Gross profit = 198 billion - (198 billion - Gross profit)

Gross profit = 198 billion - 198 billion + Gross profit

Gross profit = Gross profit

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Answer:

tetrahedral is the molecular geometry of the oxygen atoms in epinephrine.

The terminal alkyne type of compound is most consistent with the IR spectrum.

Normally alcohol/phenol group's O-H stretching peak arises around 3550-3200 cm-1 and the carboxylic acid O-H stretching peak arises around 3000-2500 cm-1. O-H peak will appear as a broad peak due to hydrogen bonding. So the given spectra are not applicable for alcohol and carboxylic acid.

In the given spectra a strong sharp peak around 3300 cm-1 indicates terminal alkyne C-H stretch. Usually, the C-H stretch of terminal alkyne appears as a strong sharp peak around 3250-3330 cm-1

The carbonyl stretching peak is a strong peak at 1780-1630. This region peak is not present in the given spectra. Therefore, the given spectra do not match a ketone, ester, carboxylic acid, or aldehyde.

The structured peak at 2950 and 2870 cm-1 is due to-C-H stretch

The medium peak at 2150 cm-1 is due to carbon triple bond carbon

The peak around 610-700 cm-1 is because of -C-H bonding

Therefore the given IR spectra are for a terminal alkyne.

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What type of compound is most consistent with the IR spectrum shown below?

Diagram attached at end of solution

alcohol

carboxylic acid

terminal alkyne

ketone

ester

None of the choices are correct.

aldehyde

To prepare 240 mL of two-thirds strength hydrogen peroxide solution for a wound irrigation using normal saline as the diluent, you need to mix 160 mL of full-strength hydrogen peroxide with 80 mL of normal saline.

This creates a total volume of 240 mL, with two-thirds of it being hydrogen peroxide and one-third being normal saline.

When using a hydrogen peroxide solution for wound irrigation, it is important to ensure that the concentration of the solution is appropriate for the type of wound being treated. Generally, hydrogen peroxide solutions of 2-3% concentration are used for wound irrigation. Higher concentrations can cause tissue damage and skin irritation.

Additionally, it is important to ensure that the diluent used is appropriate for the type of wound being treated. For example, normal saline is most commonly used for wound irrigation, but other diluents such as sterile water may be used for different types of wounds.

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C.  1s22s22p33s1. The 1s22s22p33s1 is the electron configuration of an excited state of an oxygen atom.

When an electron is stimulated and leaps into a higher orbital, the atom's excited-state configuration differs from its normal configuration. Oxygen has the excited-state electron configuration 1s22s22p33s1.

An atom's excited state is one in which it has more energy than its ground state. In this case, one or more electrons are not at their lowest energy state. Electrons have advanced to a higher energy level by using external energy.

Energized-state absorption is the process of a system (such as an atom or molecule) being excited from one excited state to a higher-energy excited state by absorbing a photon (ESA). Only when an electron has already been excited from the ground state to a lower excited state is excited-state absorption conceivable.

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At greater pressures, the concentration of one kcl(s) in the gas phase increases, as does the concentration of dissolved gas molecules, o2(g) in the solution at equilibrium.

Henry's law is useful in many situations. CO2 bubbles develop when a carbonated beverage is opened, for example, because the drink was bottled under CO2 at a pressure greater than 1 atm. When the container is opened, the pressure of CO2 above the solution rapidly lowers, allowing some of the dissolved gas to escape as bubbles.

At some cases, if scuba divers are breathing compressed air, Henry's law explains why they must carefully rise to the surface after a dive. More N2 from the air dissolves in the diver's internal fluids when pressures rise beneath water.

Meanwhile, if a diver ascends too rapidly, the abrupt pressure shift causes tiny bubbles of N2 to develop throughout the body, resulting in "the bends." These bubbles can obstruct blood flow through small blood arteries, causing severe discomfort and, in rare cases, death.

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If it required 192g of oxygen. The formula for the hydrocarbon can be observed as C₆H₁₂.

It is required to examine the chemical equation that is balanced for the combustion of the hydrocarbon in order to find the value of 'n' in the hydrocarbon formula CₙH₂ₙ.

The equation for the combustion process of a hydrocarbon is:

CₙHₙ  + (n + 1/2)O₂ → nCO₂ + nH₂O

In the equation, it is observed that 'n' moles of  CₙH₂ₙ react with 'n + 1/2' moles of O₂ to produce 'n' moles of CO₂ and 'n' moles of H₂O.

According to the question, 192g of oxygen is needed, so find the moles of oxygen used:

Moles of O₂ = mass of O₂ / molar mass of O₂

= 192g / 32g/mol

= 6 moles

The stoichiometric ratio between O₂ and  CₙH₂ₙ is 1:1, the number of moles of  CₙH₂ₙ is also 6 moles.

Now, find the value of 'n' through the relationship between moles of C and moles of H in the hydrocarbon.

Each mole of CₙH₂ₙ contains 'n' moles of carbon and 2n moles of hydrogen.

To consider the balanced equation, it is observed that 6 moles of carbon are produced.

Thus, the number of moles of carbon is equal to 6. Hence, each mole of CₙH₂ₙ contains 'n' moles of carbon, the formula for the hydrocarbon can be observed as C₆H₁₂.

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The given question is incomplete,  so the most probable complete question is,

1 mole of a hydrocarbon of formula CnH2n was burned completely in oxygen producing carbon dioxide and water vapour only. It required 192g of oxygen. Work out the formula of the hydrocarbon.

The mass of [tex]Ag_2CrO_4[/tex] that would be formed will be 2.69 grams.

Mole of 2.5 grams silver nitrate = 2.5/143.32 = 0.017 mol

Mole of 18.0 mL, 0.450 M sodium chromate = 18/1000 x 0.450 = 0.0081

From the balanced equation of the reaction, the mole ratio of silver nitrate to sodium chromate is 2:1. In other words, the sodium chromate is a bit limiting.

The mole ratio of sodium chromate and  [tex]Ag_2CrO_4[/tex] is 1:1. Hence, the equivalent mole of [tex]Ag_2CrO_4[/tex] formed would also be 0.0081 mol.

Mass of 0.0081 mol [tex]Ag_2CrO_4[/tex] = 0.0081 x 331.73

                                                 = 2.69 grams

In other words, the mass of [tex]Ag_2CrO_4[/tex] formed from the reaction would be 2.68 grams.

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The use of tap water instead of boiled, distilled water for preparing the saturated Ca(OH)2 solution would affect the value of ksp for Ca(OH)2.

Tap water often contains dissolved minerals, salts, and other impurities, which can change the concentration of ions in the solution and the affect the value of ksp. If these impurities alter the ion concentration in the solution, the value of ksp may differ from what it would be if the solution were the prepared using distilled water. Thus, it is important to use distilled water when preparing a solution to accurately determine its ksp value. The use of  the tap water instead of boiled, distilled water for preparing the saturated Ca(OH)2 solution would affect the value of ksp for Ca(OH)2.

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The ratio of ingredients used to make broth when using water as the main liquid can vary depending on the recipe, but a common ratio is 1:10, meaning 1 part of solid ingredients to 10 parts of water.

When making broth, the ratio of ingredients is important as it affects the taste, texture, and nutritional value of the final product. The 1:10 ratio of ingredients is a starting point that can be adjusted based on personal preference.

For example, using a 1:10 ratio of ingredients means that for every 1 part of solid ingredients, such as chopped vegetables, meat, or bones, 10 parts of water are added. This can result in a light, flavorful broth. If a stronger flavor is desired, the ratio of solid ingredients can be increased, while a weaker flavor can be achieved by reducing the amount of solid ingredients.

It is also important to consider the type of ingredients used. For example, if a lot of salty ingredients are used, such as ham hocks or cured meats, the amount of water can be increased to balance out the saltiness. On the other hand, if a lot of herbs and spices are used, the water ratio can be adjusted to suit the desired taste.

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We should heavy cream be chilled before whipping because that is cream  too warm is little hard to whip and it will curdles easily.

The whipping cream will be stored in the refrigerator for some times because if the whipping cream is too warm so, it will be little hard and it will curdles easily. The first sign that the cream is becoming overwhipped is the  grainy appearance to the cream. When the cream is overwhipped it will separates into the butter and the whey.

Thus , because of the reason that is cream  too warm is little hard to whip and it will curdles easily.

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15 protons ,16 neutrons, 15 electrons are in this ion.

What is the chemical symbol for phosphorus?

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This is a chemical change. When sodium thiosulfate (Na₂S₂O₃) is mixed with potassium iodide (KI), a chemical reaction will occurs, which producing iodine (I₂) as well as other products.

Evidence of a chemical change which includes the formation of a new substances with different properties, such as different color, odor, as well as chemical behavior. The dissolving of the sodium thiosulfate into the solution is also an indication of a chemical change, as the properties of the solid have changed into a new substance in solution form, with different properties than to the solid.

2Na₂S₂O₃ + I₂ → 2NaI + Na₂S₄O₆

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The Van' Hoff factor I is the ratio of the number of particles generated by solute dissociation to the total number of solute molecules in solution. To get the Van' Hoff factor of formic acid.

and Cm is the molality of the solution. The Van' Hoff factor I is the ratio of the number of particles generated by solute dissociation to the total number of solute molecules in solution. To get the Van' Hoff factor of formic acid. constant (-1.86°C/m for water), I is the Van' Hoff factor, and Cm is the molality of the solution. The Van' Hoff factor I is the ratio of the number of particles generated by solute dissociation to the total number of solute molecules in solution. To get the Van' Hoff factor of formic acid.

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Answer:

Neon is one of six elements, found in the rightmost column of the Periodic Table, that is inert.

Explanation:

Neon is one of six elements, found in the rightmost column of the Periodic Table, that is inert. Noble gases react very unwillingly, because the outermost shell of electrons orbiting the nucleus is full, giving these gases no incentive to swap electrons with other elements.

A real-world example of chemistry where nucleophilic substitution is involved is the industrial reaction between sodium cyanide and acetic acid to produce sodium acetate and hydrogen cyanide.

This reaction is a nucleophilic substitution reaction because the cyanide ion acts as a nucleophile and attacks the carbonyl carbon of the acetic acid molecule, replacing the leaving group (hydrogen).

In the reaction between sodium cyanide and acetic acid, the cyanide ion acts as a nucleophile and attacks the carbonyl carbon of the acetic acid molecule. This leads to the formation of a new bond between the cyanide ion and the carbonyl carbon, and the displacement of the hydrogen ion. The resulting product is sodium acetate and hydrogen cyanide.

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Explanation:

=> The simplest form of

56

:

98

56:98 is

4

:

7.

4:7.

Step-by-step explanation:

Given ratio -

56

:

98

56:98

We have to reduce it to its simplest form,

For that, we have to find the GCD of the numerator as well as the denominator:

So, the GCD for

56

56 and

98

98 is

14.

14.

Now, divide both the numerator and denominator by the GCD:

=

>

56

÷

14

98

÷

14

=>

98÷14

56÷14

=

>

4

7

=>

7

4

Hence, the simplest form is

4

:

7.

4:7.

Compound formula                 Major species

CH₃OH                                            CH₃OH

MgSO₄                                        Mg²⁺, SO₄²⁻, H₃O⁺                    

C₃H₆(OH)₂                                      C₃H₆(OH)₂

1) CH₃OH   , it is called as methanol. It is nonelectrolyte. It is neither a base nor the acid and it can not dissociates into the water.

The major species is  CH₃OH  .

2) MgSO₄  , magnesium sulfate will dissociates into the ions when dissolve in the water.

MgSO₄   +  H₂O   -->  Mg²⁺   +  SO₄²⁻  +   H₃O⁺      

3)  C₃H₆(OH)₂ , propylene gylcol and  it will not dissociate but it will remain as the molecule. The  molecules is the species that solvated by the water molecule.

The major species is  C₃H₆(OH)₂ .

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Answer:

0.73 moles

Explanation:

The membrane potential of this neuron if it were only permeable to potassium and you reduced the [K+]outside is -89 mV.

The difference in electric potential between the interior and exterior of a biological cell is known as membrane potential (also transmembrane potential or membrane voltage). That is, there is a difference in the energy necessary for electric charges to flow from the internal to the external cellular surroundings and vice versa, as long as no kinetic energy is acquired or radiation is produced.

This energy need is determined directly by the charge concentration gradients. Typical membrane potential values for the cell's exterior, generally reported in millivolts and indicated as mV, vary from -80 mV to -40 mV. A membrane made of a lipid bilayer with proteins incorporated in it surrounds all animal cells.

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The element Iridium (Ir) has an atomic number of 77, meaning that there are 77 protons in an atom of Iridium.

Iridium is a chemical element with the symbol Ir and atomic number 77. It is a dense, malleable, ductile, highly unreactive, precious, silverish-white transition metal. Iridium is the second-densest element (after osmium) and is the most corrosion-resistant metal, even at temperatures as high as 2000 °C.

It has a very low electrical conductivity and is the only metal to maintain good electrical conductivity in air at temperatures of up to 1600 °C. Iridium is the most stable of the noble metals and its monatomic form is the most common state of the element in nature.

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Explanation:

The weight of an object is the force exerted on it due to gravity, and its magnitude is measured in newtons (N).

We can calculate the weight of the sodium ion using the formula:

weight = mass x acceleration due to gravity

The mass of the sodium ion is given as 23 u (atomic mass units). One atomic mass unit is defined as one twelfth of the mass of a carbon-12 atom, which is approximately 1.66 x 10^-27 kg.

The acceleration due to gravity on the Earth's surface is approximately 9.8 m/s^2.

So, we can calculate the weight of the sodium ion as:

(23 x 1.66 x 10^-27 kg) x 9.8 m/s^2 = 3.6 x 10^-25 N

Therefore, the magnitude of the weight of the sodium ion is 3.6 x 10^-25 N. Keep in mind that this is a very small value, and the weight of the sodium ion is difficult to measure or detect.

To make 200 ml of 0.05 M NaCl solution, you would need:

0.05 M * 200 ml = 0.01 moles of NaCl

So, the amount of NaCl needed would be 0.01 moles * 56.44 g/mol = 0.56 g

Process:

The solution is now ready to use.

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To prepare 22 mL of a 0.8 M solution of sodium ions from a 4.8 M solution of sodium sulfate, you must extract 33.6 mL of the 4.8 M solution.

This can be calculated using the formula M1V1 = M2V2, where M1 is the molarity of the initial solution (4.8 M), V1 is the volume of the initial solution (33.6 mL), M2 is the desired molarity of the final solution (0.8 M), and V2 is the volume of the final solution (22 mL).

It is important to note that when preparing solutions, it is essential to use accurate measuring equipment and to make sure that the solutions are mixed thoroughly. Additionally, when preparing solutions of acids or bases, it is important to add the solute to the solvent rather than the other way around, as this will help to prevent any splashing or accidental contact with the concentrated solutions.

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In a redox reaction, the species that is oxidized (loses electrons) is assigned a higher oxidation number after the reaction, while the species that is reduced (gains electrons) is assigned a lower oxidation number after the reaction.

The element and its oxidation number before and after oxidation or reduction can be determined by examining the reaction equation and noting changes in oxidation numbers for each species.

Example: In the reaction, Fe + Cu^2+ -> Fe^2+ + Cu, the Fe goes from an oxidation number of 0 to +2, which indicates that it has been oxidized. The Cu^2+ goes from an oxidation number of +2 to 0, indicating that it has been reduced.

So, the species oxidized is Fe (0 to +2) and the species reduced is Cu^2+ (+2 to 0).

Electrons are subatomic particles that have a negative charge and are commonly written as e-. The electron has no known basic components or substructures, so it is believed to be an elementary particle. Electrons have a mass of about 1/1836 the mass of a proton.

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