Which of the following can be mixed in solution with H₂CO3 to make a buffer?
OA. Na₂CO3
OB. HF
O C. NaHCO3
OD. NH3
SUBMIT

36°C

The correct reading of the temperature in the pictured thermometer is 36°C.

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The two effects do impurities have on the melting point of an organic compound are given as ,

The impurities decreases the melting point of the substance of organic compounds . This is because there are unwanted  particles which weaken the lattice structure of the  solids crystal due to which it become less stable and melts before its original melting point.

Example : Let take a clay and add dirt hen it breaks easily from the points where there is dirt . This is essentially what happens with impurities

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There are  21.42 milliliters of a 10. 5 M HCl(aq) are needed to prepare 225. 0 ml of 1. 00  M HCl(aq)

Calculation,

The formula for the dilution of a solution is given as:

[tex]M_{1} V_{1} =M_{2} V_{2}[/tex]

Where M is molarity and V is the volume of the solution in liters ( L ).

Given data,

[tex]M_{1}[/tex] =   10. 5 M

[tex]V_{1}[/tex] = ?

[tex]M_{2}[/tex] = 1. 00 M

[tex]V_{2}[/tex] = 225. 0 ml

10. 5 M × [tex]V_{1}[/tex] = 1. 00 M×225. 0 ml  

[tex]V_{1}[/tex]  in milliliters = 1. 00 M×225. 0 ml / 10. 5 M = 21.42 ml

Volume in milliliters is  21.42 ml .

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Explanation:

According to orbital hybridization theory, in ethene the C atoms are using sp2 hybrid orbitals. This leaves one unhybridized p orbital available to form the second bond (Pi bond) in the C-C double bonds.

One sp2 hybrid orbital from each C atom overlap to form one sigma bond between the two carbon atoms. One p orbital from each C atom then overlap to form a pi bond that completes the C-C double bond. The H atoms are bonded via sigma bonds to the C atoms when the H s orbitals overlap with the remaining sp2 hybrid orbitals from each C.

Answer: Calcium Hydroxide

Explanation:

CaOH will as it is the only base, the rest is acid

the greatest amount of work is required if the process is adiabatic.The correct option is adiabatic.

The process in  which heat is constant is called adiabatic process.

The The process in  which temperature is constant is called isothermal process.

The process in  which pressure is constant is called isobaric process.

The P-V diagram for adiabatic , isothermal and isobaric process is given below.

Work done in process = area encloses by P-V diagram axis . Since area under the curve is maximum for adiabatic process which is shown in the above diagram. So, work done by the gas will be maximum for adiabatic process.

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A molecular orbital that decreases the electron density between two nuclei is said to be antibonding.

The bonding orbital, which would be more stable and encourages the bonding of the two H atoms into [tex]H_{2}[/tex], is the orbital that is located in a less energetic state than just the electron shells of the separate atoms. The antibonding orbital, which has higher energy but is less stable, resists bonding when it is occupied.

An asterisk (sigma*) is placed next to the corresponding kind of molecular orbital to indicate an antibonding orbital. The antibonding orbital known as * would be connected to sigma orbitals, as well as antibonding pi orbitals are known as [tex]\pi[/tex]* orbitals.

Therefore,  molecular orbital that decreases the electron density between two nuclei is said to be antibonding.

Hence, the correct answer will be option (b)

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45,849 calories are given off when 85 gram of steam condenses to liquid water.

Vaporization is always a highly endothermic (heat-absorbing) process because you must break all the intermolecular interactions present inside of the liquid phase.

So,

Q = mass × heat of vapourization

Q = m×ΔH[tex]_{vap}[/tex]

Q = 85 × 539.4

Q = 45,849 cal

Therefore, 45,849 calories are given off when 85 gram of steam condenses to liquid water.

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Then the new pressure of the sample of nitrogen is  1.28 atm

So, option D is correct one.

Calculation,

Formula used : [tex]P_{1} V_{1} /T_{1} =P_{2} V_{2}/T_{2}[/tex]             (i)

Where , P is pressure and V is the volume

Given data,

[tex]P_{1}[/tex] = 3. 65 atm

[tex]V_{1}[/tex] = 21. 2 L

[tex]P_{2}[/tex] =

[tex]V_{2}[/tex] = 62. 6 L

[tex]T_{1}[/tex] = 22°C = 22+273 = 295 K

[tex]T_{2}[/tex] = 34°C = 34 +273 = 307 K

Putting the value of all data given in equation (i) we get,

3. 65 atm ×  21. 2 L/295 K = [tex]P_{2}[/tex] ×  62. 6 L / 307 K

[tex]P_{2}[/tex] = 3. 65 atm × 21. 2 L × 307 K/295 K × 62. 6 L = 1.28 atm

Then the new pressure the sample of nitrogen is  1.28 atm

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Potential advantages of using water as a solvent in organic chemistry are:

Disadvantages of using water as a solvent in organic chemistry

Water is the most common liquefaction solvent. Not only is water an environmentally friendly solvent that is inexpensive and does not pollute the environment, but it also facilitates the recovery and recycling of inorganic matter contained in biomass in ionic form for eventual use as fertilizers.

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The sensory neurons within the olfactory organ are stimulated by Chemicals in the air.

Sensory neurons are the neurons that take up the signal from the receptors to the Central Nervous system (CNS)

Olfactory organ is the organ which is capable to sense smell i.e. Olfaction.

The Chemicals present in the air stimulates the sensory neurons present withing the olfactory organ consisting of olfactory epithelium. The cilia present in the epithelium recognizes the chemical present.

The neurons form connections of neuron to the olfactory bulb.

It is a mass of tissue that is round in shape that comprises of several kinds of cells of neurons that are capable to sense smell. It is necessary to sense smell properly.

Odorants are the compound that consist of an odor which get detected by the sensory neurons to carry out olfaction. They activate olfactory receptors and send signals to olfactory bulb.

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The correct answer is Carbon Dioxide.

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13 liters is the correct answer

13 liters is the final volume of the gas when the temperature and pressure remain constant.

v1/n1 = v2/n2

where,

v1 = initial volume = 8.5 liter

n1= initial mole of gas = 1.2 mole

n2= final mole of gas = 1.2+0.65= 1.85 mole

v2= final volume = ?

8.5 L/1.2 mol = v2/1.85 mol

7 L x 1.85 mol = v2/1.85 mol x 1.85 mol

13 L = v2

v2= 13 liter

22.4 L

At STP (Standard Temperature and Pressure = 0 °C, 1 atm), an ideal gas has a volume of 22.41 L/mol.

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The molecular mass of a 10g compound that has 30.066 × 10²³ atoms is 2.00g/mol.

The molecular mass of a substance can be calculated by dividing the mass of the substance by the number of moles.

molecular mass = mass ÷ no of moles

However, the number of moles of the substance must first be calculated by dividing the number of atoms by Avogadro's number.

no of moles = 30.066 × 10²³ ÷ 6.02 × 10²³

no of moles = 4.99moles

molecular mass = 10g ÷ 4.99 moles = 2.00 g/mol

Therefore, the molecular mass of a 10g compound that has 30.066 × 10²³ atoms is 2.00g/mol.

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Answer:

15.94 g

Explanation:

80 mins is 4 half lives ( 20 min each)

255 * 1/2 * 1/2 * 1/2 * 1/2   = 255 * 1/2^4 = 15.94 g

There are four unpaired electrons present in the complex ion  [tex][CoBr_6]^3^-[/tex]  

A complex ion  [tex][CoBr_6]^3^-[/tex]  is an octahedral complex. Co is the central atom to which 6 Br atoms are attached. Br is a weak field ligand and forms a high spin complex.

Electronic configuration of Co -  [tex][Ar] 3d^7 4s^2[/tex]

Electronic configuration of [tex]Co^3^+ \rightarrow [Ar] 3d^6[/tex]

Electronic configuration of [tex][CoBr_6]^3^-\\[/tex] - [tex]t_2_g^4 e_g^2[/tex]

Hence, there are 4 unpaired electrons present in the complex ion  [tex][CoBr_6]^3^-[/tex] .

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England topped what torturous temp for the first time of 40°C

For the first time ever, Britain experienced temperatures on Tuesday of over 40 degrees Celsius, or 104 degrees Fahrenheit, as a fierce heat wave moved northwest, causing raging wildfires, fatalities, and forced home evacuations throughout a Europe that was terrifyingly unprepared to deal with the new reality of extreme weather.

A heat wave is a period of very hot weather that may also be accompanied by significant humidity, especially in nations with maritime climates. While there are several definitions, a heat wave is typically assessed in relation to the local climate and the average temperatures for the time of year.

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A pyranose with the hydroxyl group on the anomeric carbon pointing up in the haworth structure is designated by alpha .

When aldohexoses undergo cyclization, anomers are formed. Anomers differ in the spatial position of the -OH group at [tex]C_{1}[/tex] . When the  -OH group is positioned along the direction of [tex]-CH_{2} OH[/tex] , alpha anomer exists but when the  -OH group is positioned opposite to the direction of the[tex]-CH_{2} OH[/tex] , then we have the beta anomer. Consider the alpha and beta anomers of galactopyranose and a pyranose with the hydroxyl group on the anomeric carbon pointing up in the haworth structure is given as ,

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Steps that are required for the correct use of an automatic micropipettor -

1. ensure that the pipette is adjusted to discharge the proper V

2. depress the knob until you reach the point of first resistance.

3. dip the tip of the pipette into the solution

4. gradually depress the plunger to suck solution into the tip

5. Remove the tip from the solution and put it on the inside wall of the container into which the solution to be dispersed.

6. again depress the knob to the first point of resistance

7. After a brief pause, depress the knob as far as it will go.

Pipettes that are automated can eliminate the need for manual work and provide a variety of benefits. The most obvious benefit is increased throughput, since automation frees up time and effort for other activities. Another advantage is increased repeatability.

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When an allergen binds with IgE antibodies on mast cells, resulting in release of chemical mediators, this reaction is called Type I reactions.

The Type I reactions is also known as immediate hypersensitivity reaction.

This reaction involve immunoglobulin E ( IgE ) - mediated release of histamine and other mediators from mast cells and basophils .

Examples : anaphylaxis and allergic rhinoconjunctivitis.

The IgE molecules bind to high - affinity receptors on the surface of mast cells and basophils and the subsequently cross-linking of these molecules with the allergen releases performed and newly synthesized mediators.

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The pH of the solution is 9.14

To calculate the amount of hydrogen gas collected, we use the equation given by ideal gas which follows:

PV = nRT

P= Pressure of the gas = 735 torr

V= volume of the gas = 7.70 l

T= Temperature of the gas= 22°C (22+273K) = 295K

R= Gas constant= 62.364 L torr/mol/K

n = number of moles of ammonia = ?

By substituting the values in the above equation, we get:

735×7.70 = n × 62.364 × 295

5659.5 = n × 18397.38

n= 5659.5/18397.38

n= 0.3076

To calculate the number of moles for given molarity, we use the equation:

Molarity of the solution = [tex]\frac{moles of solute}{volume of solution}[/tex]

Molarity of hydrochloric acid = 0.400 M

Volume of solution = 0.250 L

Putting values in above equation, we get:

0.400= moles of solute/0.250

moles of hydrochloric acid = 0.1 mol

The chemical reaction for ethylamine and HCl follows the equation:

NH3+HCl---> NH4Cl

Initial:         0.316             0.18

Final:          0.136     -            0.18

volume of the solution = 0.250 l

To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

pOH = pKb + log([tex]\frac{salt}{base}[/tex])

pOH = pKb + log([tex]\frac{NH4Cl}{NH3}[/tex])

it is given:

pKb =  negative logarithm of base dissociation constant of ammonia =

-log(1.8 × [tex]10^{-5}[/tex]) = 4.74

[NH4Cl] = 0.18/0.450

[NH3] = 0.136/0.450

On substituting the values we get,

pOH= 4.74 + log ([tex]\frac{0.18/0.250}{0.136/0.250}[/tex])

pOH = 4.74 + 0.12

pOH= 4.86

pH + pOH= 14

pH= 14-pOH

    = 14-4.86

pH = 9.14

pH of the solution = 9.14

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Answer:

The longest continuous chain

Explanation:

The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.

Calculation,

Given data,

Mass of the ice = 10 g

Temperature of ice =  0. 0°C

Heat required at this stage = mas of the ice ×latent heat of fusion of ice

Heat required at this stage = 10 g×80 = 800 cal  

Heat required for this = mass of the ice×rise in temperature×specific heat of water

Heat required for this  = 10 g×100× 1 = 1000 cal

Heat required for this = Mass of water× latent heat

Heat required for this  = 10g ×536 =5360 cal

Total energy or heat required = sum of all heat = 800 +1000+ 5360  = 7160 cal

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Answer:

[tex]K_{c} =\frac{[O_{2} ] [SO_{2} ]^{2} }{[SO_{3} ]^{2} }[/tex]

Explanation:

To construct the equilibrium constant, you need the balanced equation:

2 SO₃(g) -----> O₂(g) + 2 SO₂(g)

The equilibrium constant compares the concentrations of the products and the reactants.

The given expression follows this structure:

aA(g) ----> bB(g) + cC(g)

In this equation, the uppercase letters symbolize the molecules and the lowercase letters symbolize their corresponding coefficients in the balanced equation.

The general equilibrium expression looks like this:

[tex]K_{c} =\frac{[B]^{b} [C]^{c} }{[A]^{a} }[/tex]

To be clear, the concentrations in the numerator represent the gaseous products and the concentrations in the denominator represent the gaseous reactants.

Therefore, the equilibrium expression for this equation is:

[tex]K_{c} =\frac{[O_{2} ] [SO_{2} ]^{2} }{[SO_{3} ]^{2} }[/tex]

2mol of Hydrogen peroxide releases 196.6KJ heat

1mol releases

5mol releases

Answer: 491.5

Explanation:

Hope this helps :)

From the calculation, the volume of the gas is 12.6 L

We can define the pressure of a gas as the force that the gas exerts per unit area of the container. Now we knw that we can be able to obtain the volume  of the gas by the use of the ideal gas equation.

Now;

Number of moles =  40g/58 g/mol = 0.69 moles

1 mole of butane occupies 22.4 L

0.69 moles of butane occupies  0.69 moles  *  22.4 L/ 1mole

= 15.5 L

Now;

P1 =760 Torr

V1 =  15.5 L

T1 = 273 K

P2 =  1000 Torr

V2 = ?

T2 =  18°C + 273 = 291 K

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 760 Torr * 15.5 L * 291 K/1000 Torr * 273 K

V2 =12.6 L

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A sparingly soluble metal fluoride with formula MF₂, where m is an unknown metal, has a Ksp = 6.65 x 10⁻⁶. The concentration of F⁻ in solution 2.36 x 10⁻³M

Ksp  is called the Molar solubility product and S is the Molar solubility of an ion in a solution.

According to given formula, the dissociation of metal fluoride MF₂ occurs as follows in aqueous solution:

MF₂  ------> M⁺² + 2F⁻

                  S       2S

Ksp = [S] [2S]²

Ksp = 4S³

Given, Ksp = 6.65 x 10⁻⁶

On substituting,

6.65 x 10⁻⁶ = 4S³

S³ = 1.66 x 10⁻⁶

S = 1.18 x 10⁻³

So, Solubility of F⁻ ion = 2S

      Solubility of F⁻ ion = 2(1.18 x 10⁻³)

        Solubility of F⁻ ion = 2.36 x 10⁻³

Since Molarity of the ions is equal to the solubility of the ion in aqueous solution.

Hence, the concentration of F⁻ ion is 2.36 x 10⁻³M.

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When Americium–241 decays into neptunium–237, an unstable nucleus decays into a more stable nucleus.

What is Radioactive decay?

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cesium chloride is another chloride that could be used instead of the calcium chloride dihydrate to produce a solid precipitate with aqueous sodium carbonate

A mineral salt called cesium chloride (CsCl) is occasionally ingested or administered intravenously to cancer patients seeking alternative therapies. However, the FDA has not yet approved any cesium chloride products to treat cancer or other disorders.

In isopycnic centrifugation, cesium chloride is a common medical compound used to separate different forms of DNA. It is a reagent used in analytical chemistry to distinguish ions based on the hue and shape of the precipitate.

Cesium chloride is not proven to be effective in treating cancer. As an alternative to chemotherapy for cancer, cesium chloride is pushed. Supporters assert that cesium prevents tumor cells from proliferating by neutralizing the poisons they release.

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When an electron in a hydrogen atom jumps from an orbital farther from the nucleus to an orbital closer to the nucleus, the energy is emitted.

The energy of electron decreases. When it goes, the electron release a photon of electromagnetic energy.

When an electron jumps from higher energy orbital to lower energy orbital, the difference in the energies of these two orbitals is radiated as quantum.

E = hc/wavelength

The photon is emitted with the electron moving from higher energy level to lower energy level.

The wavelength of emitted radiation would be (27/32) × wavelength.

Thus we concluded that the energy of photon is exact energy that is lost by the electron moving to its lower energy level.

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