On research on animals they must given proper care and housing. And the purpose of the research must have a scientific reason. Thus option B is correct.
What is animal research?Animal research includes various scientific investigation on animals such as testing various doses of some drugs, effect of various chemicals, level of toxicity of some compounds etc.
According to the research ethics, no animals can be used to conduct any unscientific works. There must be a scientific purpose which is very important to conduct any animal research.
If any animals irrespective of its nature,it must be provided proper care, food and housing. No harmful things must be there which make them more suffering. Hence, option B is correct.
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A sample ends up 7 miles to the west of appear what statement is true about the situation
The statement that the sailboat ends up seven miles to the west is true because that it depicts displacement, a vector quantity.
Describe displacement.The vector quantity known as displacement stands for distance with a directional component. As a result, displacement is defined as a distance and a direction.
Contrarily, distance is the amount of space between two locations, typically those that are geographical, and is typically (though not always) measured along a straight line. It has no direction because it is a scalar quantity.
The primary distinction between the two terms is as follows: A scalar quantity known as distance measures "how much ground an object has traversed" while moving.
The answer to this query places a sailboat 7 miles west of a pier. This indicates displacement because the magnitude is 7 and the direction is west of the pier.
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What is the critical angle for light traveling from ice (n=1.309) into air?
a. 39.8⁰
c. 59.8⁰
b. 49.8⁰
d.
69.8°
Answer:
b. 49.8
Explanation:
θc = sin^-1(1/1.309) = 49.81
aball is through horizontal From The top at buiding the ball lands I00m for building and It takes 4 Second For It to hit The ground Find: A, The Inital horizontal componet OF Velocity
A ball is through horizontal From The top at building the ball lands I00m for building and It takes 4 Second For It to hit The ground . The Initial horizontal component of Velocity will be 25 m/s
using kinematic equation
s = u t + 1/2 a [tex]t^{2}[/tex]
since , there is no acceleration in horizontal direction
s = u(x) t + 0
100 = u (x) * 4
u(x) = 100 / 4
= 25 m/s
The Initial horizontal component of Velocity will be 25 m/s
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A rod slides along a metal frame. The earth’s magnetic field is 3.5 × 10−5 T at right angles to the plane of the frame. The rod is of length 0.23 m inside the frame and moves at 0.68 m/s. What is the motional EMF produced by the rod? Answer in units of V.
The motional EMF produced by the rod is 5.474 × 10⁻⁶ V.
What is electromotive force?When no current is flowing, electromotive force (EMF) equals the terminal potential difference.
Despite the fact that both EMF and terminal potential difference (V) are expressed in volts, they are not the same thing. EMF is the quantity of energy (E) that the battery supplies to each coulomb of charge (Q) that passes through.
Given parameters:
The earth’s magnetic field; B= 3.5 × 10⁻⁵ T
The length of the rod; l = 0.23 m.
Speed of the rod; v = 0.68 m/s.
So, the motional EMF produced by the rod = Blv
= 3.5 × 10⁻⁵ × 0.23 × 0.68
= 5.474 × 10⁻⁶ V.
Hence, motional EMF produced by the rod is 5.474 × 10⁻⁶ V.
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If 600 J of energy of chemical energy is contained inside the gasoline in a gas tank, how much work can the engine perform on the car? What kinetic energy can be achieved?
Kinetic energy will be 600J. According to law of conservation energy: All the energy in a system will simply change the state, and no more nor less energy will be created or lost during the operation of the system. In this case, then all 600J of energy will be transformed during the operation of car.
This chemical energy, what is it?kinetic energy, Chemical compounds' bonds contain energy. Chemical reactions have the potential to release chemical energy, frequently in the form of heat; these kinds of reactions are referred to as exothermic. Some of the energy from reactions that need heat input to continue may be stored as chemical energy in newly formed bonds.
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Two friends, Burt and Ernie, are standing at opposite ends of a uniform log that is floating in a lake. The log is 4.0 m long and has mass 210 kg. Burt has mass 40.5 kg and Ernie has mass 25.5 kg. Initially the log and the two friends are at rest relative to the shore. Burt then offers Ernie a cookie, and Ernie walks to Burt's end of the log to get it.
Relative to the shore, what distance has the log moved by the time Ernie reaches Burt? Neglect any horizontal force that the water exerts on the log and assume that neither Burt nor Ernie falls off the log.
The distance that the log has moved till it got to where Ernie reached Burt would be 0.37m
How to solve for distanceWe have the following details that would be used to get the solution to this problem
length of log = 4. 0 m
The mass of the log is 210 kg
The weight pof Burt = 40 . 5 kg
The weight of ernie would be 25.5 kg
The formula to be used would be in the form of
x(mass of log) + x(mass of Burt) + mass of ernie (x - length of wood)
such that we would have
210x + 40.5x + 25.5(x - 4) = 0
210x + 40.5x + 25.5x - 102 = 0
276x - 102 = 0
cross sign to the other side
276x = 102
To get the distance we would have to divide through by 276 and this value that we would get is going to be the x value
276x / 276 = 102 / 276
x = 0.369
~ 0.37m
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A magnetic field points out of the page with B = 0.75 T . The wire shown carries a current of 69 A and has a length of 30 cm . What is the force exerted on the wire?
The force that acts on the conductor is obtained from the calculation as 15.5 N.
What is the force carried by the wire?We know that a magnetic field has to do with the region in space where the influence of a magnet can be felt. In this case, we have been told that;
The magnetic field of the conductor (B)= 0.75 T
The current (I) = 69 A
Length of the wire = 30 cm or 0.3 m
Let us recall the formula that says;
F = BIL
F = force on the conductor
B = magnetic field
L = length of the conductor
Thus if we substitute values;
F = 0.75 * 69 * 0.3
F = 15.5 N
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A circuit that has only one branch for electrons to follow is a(n) ____.
Question 1 options:
circuit diagram
electron circuit
parallel circuit
series circuit
Answer: series circuit
Explanation:
First 2 answers are garbage. In Parallel circuits electrons have 2 or more paths to follow. In Series circuits, there is only one path.
2. The total mass of a boy and his bike is 45 kg. The boy rides his bike at a velocity of -5.0 m/s. What is
the boy's momentum?
The correct answer is momentum of boy = 225 Kg. m /s
What is momentum?
Momentum is the product of the units of mass and velocity is the unit of Momentum.
To get the value the momentum, formula: P=mv, where P is the momentum.
Given, total mass and boy = 45 Kg., Velocity = -5 m/s
Momentum = Mass x Velocity = 45 Kg. x 5 m/s = 225 Kg. m / s
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A cannon fires a cannon ball vertically into the air. Find the initial velocity if the cannon ball reached the height of 4.75 meters
The initial velocity of the cannon ball when it reached a height of 4.75 m is 9.65 m/s.
Velocity- The rate of change of displacement is the definition of velocity.
The formula below is used to determine the cannon ball's initial velocity.
Formula:
v² = u²+2gH......... Equation 1
Where:
v = Final velocity
u = Initial velocity
H = Height
g = Acceleration due to gravity.
From the question,
Given:
v = 0 m/s (At the maximum height)
H = 4.75 m
g = 9.8 m/s
Substitute these values into equation 1
0² = u²+2×9.8×4.75
u² = 93.1
u = √(93.1)
u = 9.65 m/s
Hence, the initial velocity of the cannonball is 9.65 m/s.
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Explain how friction affects the mechanical energy of a system
Calculate the radius of
a Circular orbit for which
the period is 1 day
The radius of the circular orbit is equal to V/2π where V is the velocity of the orbiting object.
What is an orbital period?The orbital period can be described as the amount of time a given astronomical body occurs to complete one orbit around another object. It applies to planets orbiting the Sun, moons orbiting planets, etc.
In general, the sidereal period is referred to by the orbital period, calculated by a 360° revolution of one body around its primary.
Given, the orbital period = 1 day
The total distance covered will be equal to the circumference of the circular orbit.
Distance = 2πr where r is the radius of the orbit.
We know that distance = Velocity ×time
2πr = V × 1
r = V/2π
Where V is the velocity of the orbiting object.
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Please help, it's a question on Elasticity!
A wire can support a load W without breaking. It is cut in to two equal parts. The maximum load that each part can support is
(1) W/4
(2)W/2
(3) W
(4) 2W
(5) 4W
A wire is capable of carrying a load W without snapping. It is divided in half, equally. Each component's maximum load capacity is W.
The maximum load supported by the cable is directly proportional to the breaking stress.
Since,
Breaking stress=F/A
where F is the force and A is the cross-sectional area
As we see that the breaking stress is independent of the length of the cable. So, if the cable is cut in two equal parts, the maximum load that can be supported by either part of the cable remains the same as before.
So, the answer would be W.
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Scientists determine the masses of planets by observing the effect of the gravitational field of those planets on nearby objects - mainly upon their moons. By measuring the orbital period and orbital radius of a moon about a planet, Newton's laws of motion can be used to determine the mass of the planet. Phobos, a moon of the planet Mars, was discovered in 1877. It's orbital radius is 9380 km and its orbital period is 0.319 days (2.77 x 104 seconds). Determine the mass of Mars based on this data.
equal to 9380 into 10. To the power three m. T is equal to 2.77 into 10 to the power of four seconds. So the expression for finding the mass of mars as the Squire divided by r cube as equal to four Pi Square divided by G into em. So M will be equal to for by Squire. Our cue divided by G. The Squire. So now we can substitute the values That does four by Squire. indu 9380 into 10. to the power three all cube divided by Value of GS 6.67, 3 into 10 to the Power -11. Indu 2.77 into 10 to the power of four all Squire. By solving this, we will get the mosque as six point 363 into 10. to the power 23 kilogram
Why is there an upper limit to the mass that can be supported by electron degeneracy pressure?
Electron degeneracy pressure is a specific manifestation of the more general occurrence of quantum degeneracy pressure.
What is mass electron degeneracy pressure?Electron degeneracy pressure will halt the gravitational slump of a star if its mass is below the Chandrasekhar limit (1.44 solar masses). This is the pressure that averts a white dwarf star from collapsing. Electron degeneracy pressure occurs when electrons are squeezed into a very small volume. Since their positions are well-known, they gain a large momentum in obedience to Heisenberg's uncertainty principle. This momentum generates a pressure that is temperature-independent and can result in helium flash. in stars. Electron degeneracy occurs at a solidity of about 106 kg/m3.
So we can conclude that The electron degeneracy pressure is taken by (n.v.p) where n is the number density, and v is the mean speed of the degenerate electrons.
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Which of the following is an example of Newton's third law of motion?
A) Izzie's bicycle hits a curb and she falls forward onto the grass.
B) A tissue and a rock are dropped from a ladder. The rock exerts a greater force when it hits the ground.
C) Kyle sits at the base of a water slide, another person on the slide pushes him forward into the pool.
D) Tires from a bike push against the road, and the road pushes back.
Answer:
D
Explanation:
bike and road show equal and oppisite reaction
A 5 -kg ball hangs at one end of a string that is attached to a support on a railroad boxcar. When the boxcar
accelerates to the right, the string makes an angle of 30° with the vertical. The acceleration of gravity is 9.8 m/s
and air resistance is negligible. Find the acceleration of the boxcar
The acceleration of the boxcar is 5.586m/s².
Explain what an acceleration is.We refer to any process where the velocity changes as acceleration. You can only accelerate by changing your speed, direction, or both since velocity is a function of both speed and direction.
Positive acceleration is a property of objects that are accelerating and moving in the right direction. In the first illustration, positive acceleration was demonstrated by the moving car. The acceleration is occurring in the same direction that the vehicle is moving forward and accelerating.
θ = ma/mg
tanθ = a/g
a = tanθ g
a = tan 30×9.8
a = 0.57×9.8
a = 5.586m/s².
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particle that is not considered part of an element’s atomic mass?
Answer:
Electrons.
Explanation:
Neutrons are neutral particles found in the nucleus. The atomic mass is calculated using the protons and neutrons but not the electrons, as their mass is negligible. In an example, the element oxygen has an atomic number of 8 and an atomic mass of 16.
Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from mars to the sun, then calculate it
The average distance from mars to the sun if Mars had an orbital period of 1.88 years is 2.27 * [tex]10^{8}[/tex] km
P² = a³
P = Orbital period
a = Average distance
P = 1.88 years
a³ = 1.88²
a³ = 3.53
a = 1.52 AU
a = 1.52 * 1.496 * [tex]10^{8}[/tex] km
a = 2.27 * [tex]10^{8}[/tex] km
The formula used to solve the given problem is derived from Kepler's third law of planetary motion. AU is the abbreviated from of Astronomical unit. 1 AU = 1.496 * [tex]10^{8}[/tex] km
Therefore, the average distance from mars to the sun is 2.27 * [tex]10^{8}[/tex] km
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URGENTTTTT HELP ME
Referring to the graph in the section header, what was his displacement between 100 and 300 seconds?
Question 2 options:
Question 3 (2 points)
Referring to the graph in the section header, what was the runner's velocity during segment D?
Answer:
V = (S2 - S1) / t = (750 - 500) m / (300 - 100) s = 1.25 m/s
Likewise during segment (D)
V = (0 - 750) m / (500 - 300) s = -3.75 m/s
A 60km is suspended from two cables which makes 30° and 45° angle with the vertical. Determine the tension in each string.
The tension in each string if a 60 kg is suspended from two cables which makes 30° and 45° angle with the vertical is 429.2 N to the left and 302.25 N to the right.
m = 60 kg
Resolving the tension force of 30° string into its horizontal and vertical components
Tx = T1 sin θ
Tx = T1 sin 30°
Tx = 0.5 T1
Ty = T1 cos θ
Ty = T1 cos 30°
Ty = 0.87 T1
Resolving the tension force of 45° string into its horizontal and vertical components
Tx = T2 sin θ
Tx = T2 sin 45°
Tx = 0.71 T2
Ty = T2 cos θ
Ty = T2 cos 45°
Ty = 0.71 T2
∑Fx = 0
- 0.5 T1 + 0.71 T2 = 0 → ( 1 )
∑Fy = 0
0.87 T1 + 0.71 T2 - m g = 0
0.87 T1 + 0.71 T2 - ( 60 * 9.8 ) = 0
0.87 T1 + 0.71 T2 - 588 = 0 → ( 2 )
( 2 ) - ( 1 ),
1.37 T1 - 588 = 0
T1 = 588 / 1.37
T1 = 429.2 N
Sub T1 in ( 1 ),
( - 0.5 * 429.2 ) + 0.71 T2 = 0
- 214.6 + 0.71 T2 = 0
T2 = 214.6 / 0.71
T2 = 302.25 N
Therefore, the tension in each string is 429.2 N to the left and 302.25 N to the right.
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A weightless spring of force constant 2.50 N/cm is 15.0 cm long when nothing is attached to it. It is now used to pull horizontally on a 12.5 kg box on a smooth horizontal floor. You observe that the box starts from rest and moves 96.0 cm during the first 1.60 s of its motion. How long is the spring during this motion?
The length of the spring during the motion is 16.875 cm
How do I determine the length of the spring?We'll begin by obtaining the velocity during the first 1.60 s. This is illustrated as follow:
Distance = 96 cm = 96 / 100 = 0.96 mTime = 1.60 sVelocity =?Velocity = distance / time
Velocity = 0.96 / 1.6
Velocity = 0.6 m/s
Next, we shall determine the acceleration.
Initial velocity (u) = 0 m/sFinal velocity (v) = 0.6 m/sTime (t) = 1.6 sAcceleration (a) =?a = (v – u) / t
a = (0.6 – 0) / 1.6
a = 0.6 / 1.6
a = 0.375 m/s²
Next, we shall determine the force.
Mass (m) = 12.5 kg
Acceleration (a) = 0.375 m/s²
Force (F) =?
Force = mass × acceleration
Force = 12.5 × 0.375
F = 4.6875 N
Next, we shall determine the extension of the spring.
Force (F) = 4.6875 NSpring constant (K) = 2.50 N/cmExtension (e) =?F = Ke
Divide both sides by K
e = F / K
e = 4.6875 / 2.5
e = 1.875 cm
Finally, we shall dtermin the length of the spring. This can be obtained as follow:
Original length = 15 cmExtended length = 1.875 cmLength of spring =?Length of spring = 15 + 1.875
Length of spring = 16.875 cm
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The figure shows an overhead view of a 1.40 kg plastic rod of length 1.20 m on a table. One end of the rod is attached to the table, and the rod is free to pivot about this point without friction. A disk of mass 38.0 g slides toward the opposite end of the rod with an initial velocity of 35.5 m/s. The disk strikes the rod and sticks to it. After the collision, the rod rotates about the pivot point.
A thin vertical rod has a point labeled pivot at its bottom, and a disk moving horizontally along an arrow labeled vector v that will reach the rod perpendicularly at the top.
(a) What is the angular velocity, in rad/s, of the two after the collision?
The angular velocity, in rad/s, of the two after the collision is 28.7 rad/s.
What is the angular velocity after collision?
The angular velocity, in rad/s, of the two after the collision is determined by applying principle of conservation of angular momentum as follows;
I₁ω₁ = I₂ω₂
where;
I₁ is the initial moment of inertia of the rodI₂ is the final moment of inertia of the rodω₁ is the initial angular speed of the diskω₂ is the final angular velocity of the system after the collisionInitial moment of inertia of the rod is calculated as follows;
I₁ = ¹/₃ML²
where;
M is mass of the rodL is length of the rodI₁ = ¹/₃ x 1.4 x (1.2²)
I₁ = 0.67 kgm²
Final moment of inertia of the rod is calculated as;
I₂ = ¹/₃ x (1.4 + 0.038) x (1.2²)
I₂ = 0.69 kgm²
I₁ω₁ = I₂ω₂
0.67(0 + 35.5/1.2) = 0.69ω₂
19.82 = 0.69ω₂
ω₂ = 19.82/0.69
ω₂ = 28.7 rad/s
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7. Daniel is fishing the canals and hooks a 2 kg peacock bass. Daniel exerts a 50 N
force on the fish to the left and the fish exerts an unknown amount of force in the
opposite direction. If the fish accelerates 2 m/s² towards Daniel, what is the
amount of force the fish is exerting?
Ans:
explain the impact covid had had on the rate of cardiovascular disease
The inner walls of veins and arteries can be affected by coronavirus infection, which can result in blood vessel inflammation, harm to extremely small vessels, and blood clots leading to the risks of cardiovascular diseases.
How covid had an impact on the rate of cardiovascular diseases?The mechanisms by which the COVID-19 pandemic might change trends in cardiovascular health have been the subject of numerous ideas. People with COVID-19 have a worse prognosis when they have established CVD and atherosclerosis cardiovascular disease risk factors.
Like other viral illnesses, such as some flu strains, the coronavirus may directly infect and harm the heart's muscular tissue. The body's immune system's response could also indirectly harm and inflame the heart.Less oxygen can enter the circulation as the virus induces inflammation plus fluid to clog the air sacs of the lungs. Blood pumping through the body requires more effort from the heart, which can be problematic for those who already have heart disease.Therefore, covid had a great impact on cardiovascular diseases and increased the overall disease rate.
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ANSWER ASAP I NEED THIS NOW PLEASE
The specific heat of lead is 128 J/kgoC. Suppose that 300 grams of lead shot at 100oC is mixed with 200 grams of water at 0oC in an insulated container. What is the final temperature of the mixture?
2.1oC
5.9C
3.2C
12.0C
4.4C
The final temperature of the mixture or the equilibrium temperature of the mixture is 4.4⁰C.
option E is the correct answer.
What is final temperature of the mixture?The final temperature of the mixture or the equilibrium temperature of the mixture is determined by applying the principle of conservation of energy.
Heat lost by the lead = Heat gained by the water
m₁c₁(T₁ - T) = m₂c₂(T - T₂)
where;
m₁ is mass lead = 300 g = 0.3 kgm₂ is mass of water = 200 g = 0.2 kgc₁ is specific heat capacity of lead = 128 J/kgCc₂ is specific heat capacity of water = 4200 J/kgCT is the equilibrium or final temperature of the mixtureT₁ is initial temperature of the lead = 100 ⁰CT₂ is initial temperature of water = 0⁰ C0.3 x 128 x (100 - T) = 0.2 x 4200 x (T - 0)
3840 - 38.4T = 840T
3840 = 878.4T
T = 3840/878.4
T = 4.4⁰C
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4. A 0.7 kg object has a momentum of 15 kg m/s. What is the object's speed?
Answer:
21.4 m/s
Explanation:
Momentum = m * v
15 kg m/s = .7 * v
v = 15/.7 = 21.4 m/s
You are holding a small helium balloon. Your friend says that the buoyant force from the atmosphere is greater on her car than your balloon. Is she correct? Explain your answer.
Buoyant force from the atmosphere is greater on her car than the balloon is a correct statement
buoyant force = - rho * g * V
where
rho = fluid density or in our case air density
g = acceleration due to gravity
V = volume of displaced liquid or volume of displaced air
volume of displaced air is more in the case of car as compared to balloon because car has larger volume then balloon .
and volume displaced is directly proportional to the buoyant force , hence buoyant force from the atmosphere is greater on her car than the balloon is a correct statement .
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Ametal cube of side 6cm at 20 degree Celsius on
heating to 600 degree Celsius increases by 0.3cm
calculating the coefficient of linear expansion
coefficient of superficial expression
coefficient of cubical expansion
We have the following from the question;
The coefficient of linear expansion is 8.6 * 10^-5
The coefficient of superficial expression is 1.72 * 8.6 * 10^-4
The coefficient of cubical expansion is 2.5 * 10^-4
What is the linear expansivity?Let us recall that the term linear expansivity has to do with the increase in length, per unit length, per degree Kelvin rise in temperature. Now we know that we have the following information from the question;
Initial length = 6cm
Increase in length = 0.3cm
Initial temperature = 20 degree Celsius
Final temperature = 600 degree Celsius
We then have;
coefficient of linear expansion = e/[tex]l_{1}[/tex]([tex]T_{2}[/tex] - [tex]T_{1}[/tex])
e = extension
[tex]l_{1}[/tex] = initial length
[tex]T_{2}[/tex] = Final temperature
[tex]T_{1}[/tex] = initial temperature
coefficient of linear expansion = 0.3/6(600 - 20)
= 8.6 * 10^-5
coefficient of superficial expression = 2( 8.6 * 10^-5)
= 1.72 * 8.6 * 10^-4
coefficient of cubical expansion = 3(8.6 * 10^-5)
= 2.5 * 10^-4
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A truck has a speed of 14 m/s. How far will the truck go in 3 minutes? O a 18,650 meters 42 meters 4.7 meters 1640 meters 2520 meters
Answer:2,520
Explanation: The truck goes 14 meters per second
Since it is traveling for 3 minutes which is 180 seconds, all you need to do is times the 180 seconds with the 14 meters. :)
