Which of these neutron stars must have had its angular momentum changed by a binary companion? (a) a pulsar that pulses 30 times per second (b) a pulsar that pulses 600 times per second (c) a neutron star that does not pulse at all.

Answers

Answer 1

The neutron star that pulses 600 times per second must have had its angular momentum changed by a binary companion.

Neutron stars that pulse are known as pulsars and their pulses are caused by their rotation. The rate of pulsation is directly related to the neutron star's angular momentum. A pulsar that pulses faster must have a smaller radius and higher angular velocity than a pulsar that pulses slower.

Therefore, a pulsar that pulses 600 times per second must have a very small radius and high angular velocity, which can only be achieved by a change in its angular momentum. The most likely cause of this change in angular momentum is a binary companion transferring angular momentum to the pulsar.

In conclusion, a neutron star that pulses 600 times per second is the one that must have had its angular momentum changed by a binary companion.

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Related Questions

the velocity in ft/sec of a particle moving along the x-axis is given by the function v(t)=e^t+te^t

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The velocity in ft/sec of a particle moving along the x-axis is given by the function v(t) = e^t + te^t. The function v(t) represents the instantaneous velocity of the particle at any given time t.

The first term e^t represents the initial velocity of the particle when t=0, and the second term te^t represents the additional velocity gained due to acceleration. As t increases, both terms increase, resulting in a continuously increasing velocity. The velocity function of a particle moving along the x-axis is v(t)=e^t+te^t.

The given function represents the rate of change of the particle's position with respect to time. It combines the exponential function (e^t) and a linear function multiplied by an exponential function (te^t). To find the position function, integrate the velocity function with respect to time. The position function will give you the actual position of the particle along the x-axis at a given time, which can help determine its behavior as time progresses.

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The magnetic field strength inside a current carrying coil will be greater if the coil encloses a(n): A. iron rod B. wooden rod C. glass rod. D. none of these E. vacuum.

Answers

The magnetic field strength inside a current carrying coil is directly proportional to the number of turns of wire in the coil and the magnitude of the current flowing through it. However, the presence of a magnetic material like iron inside the coil can significantly enhance the magnetic field strength.

This is because iron has high magnetic permeability, which means it can easily magnetize and demagnetize in response to an external magnetic field. Therefore, if the coil encloses an iron rod, the magnetic field strength inside the coil will be greater compared to the case when the coil encloses a wooden or glass rod.

A wooden or glass rod will not affect the magnetic field strength because they are not magnetic materials. The presence of a vacuum inside the coil will also not affect the magnetic field strength because a vacuum has no magnetic properties. Therefore, the correct answer to this question is option A, an iron rod.

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a nonadjustable pressure relief valve has a cracking pressure of 98 bar and a pressure override of 100 bar. the spring has a spring constant of 1,883 n/cm and the poppet has a surface area of 0.18 cm2 in contact with the fluid. how much is the spring compressed in cm when the valve is assembled?

Answers

The compression of the spring is 0.096 cm.

What is the compression of the spring?

The compression of the spring is calculated as follows;

F = kx

x = F/k

where;

x is the compression of the springk is the spring constant

The force acting on the spring is calculated as follows;

F = PA

where;

P is the pressureA is the area

P = 100 bar = 1 x 10⁷ Pa

A = 0.18 cm² = 1.8 x 10⁻⁵ m²

F = 1 x 10⁷ Pa x 1.8 x 10⁻⁵ m² = 180 N

The compression of the spring is calculated as;

x = F/k

x = 180 N / 1,883 N/cm

x = 0.096 cm

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a metal surface has a work function of 2.50 ev. what is the longest wavelength of light that will eject electrons from the surface of this metal? (1 ev

Answers

The longest wavelength of light that will eject electrons from the surface of the metal is approximately 496 nm (nanometers).

The energy of a photon is given by E = hc/λ, where E is the energy (in electron volts), h is Planck's constant (4.1357 x 10^-15 eV·s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength of light (in meters). To eject electrons from the metal surface, the energy of the photons must be equal to or greater than the work function of the metal (2.50 eV). Rearranging the equation, λ = hc/E, we can substitute the given values to find λ = (4.1357 x 10^-15 eV·s) * (2.998 x 10^8 m/s) / 2.50 eV, which gives us λ ≈ 496 nm.

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on a map, each township consists of 36 sections which have an approximate surface area of:

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On a map, each township consists of 36 sections which have an approximate surface area of 1 square mile each.

In the United States Public Land Survey System (PLSS), a township is a unit of land measurement that is 6 miles by 6 miles, or 36 square miles. Each township is further divided into 36 sections, each of which is 1 square mile or 640 acres. This system was developed in the early 19th century to facilitate the survey and sale of public lands in the western United States. Today, the PLSS is still used in many western states for land management and property boundaries, as well as for mapping and geographic information systems (GIS).

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T/F: a car traveling at 20 mph on a curved exit ramp has a constant velocity.

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False.

A car traveling at 20 mph on a curved exit ramp does not have a constant velocity. This is because the car is changing direction as it navigates the curved ramp, meaning its velocity is constantly changing. Constant velocity requires both a steady speed and a straight path of travel.
False: A car traveling at 20 mph on a curved exit ramp does not have a constant velocity. This is because velocity is a vector quantity, which means it has both magnitude (speed) and direction. While the car may maintain a constant speed of 20 mph, its direction is changing due to the curve of the exit ramp, resulting in a changing velocity.

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the focal point is the point at which parallel rays converge after passing through a converging lens. responses true true false

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The statement is true.

a 440 g , 8.5-cm-diameter can is filled with uniform, dense food. it rolls across the floor at 1.0 m/s . part a part complete what is the can's kinetic energy? express your answer with the appropriate units.

Answers

0.33J is the can's kinetic energy as it rolls across the floor at 1.0 m/s

Define kinetic energy

An object's kinetic energy is the type of energy it has as a result of motion. It is described as the effort required to move a mass-determined body from rest to the indicated velocity.

Kinetic energy is present in every particle and moving object. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.

Potential energy can be moved into motion by a variety of catalysts, including gravity and chemical reactions, to release kinetic energy. As a result, kinetic energy rises and potential energy falls. Mechanical energy is the sum of all kinetic and potential energy.

KE =1/2I w^2 + 1/2mv^{2}

KE = 1/2*1/2 mr^{2} (v/r)^2 + 1/2mv^{2}

K.E= 3/4 mv^{2}

K.E=  3/4 (0.44) (1)^{2}

K.E=0.33J

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λ (nm) 633
L (mm) 180mm
h0 (mm) 100mm
h1 (mm) 200mm
ϴ0 (°) 29.1°
ϴ1 (°) 48.01°
d (mm) ?
Calculated Line Density n (Lines/mm) ?
Help me solve for question marks.
Answer the questions using the data table as a reference
1. How similar is the CD’s groove number in Data Table 3 to the typical value of 625? What factors would affect any discrepancies?
2. How do the interference patterns produced by a CD and diffraction grating compare? Explain similarities, differences, and causes in your answer.

Answers

The line density of the CD is 3.71 lines/mm and the groove number is 266, and the interference patterns of a CD and diffraction grating both exhibit diffraction but have different characteristics due to the structure of the CD.

To solve for the question marks:

[tex]d = L \times tan(\theta_1) - h_1 + h_0\\\\ = 180mm \times tan(48.01) - 200mm + 100mm\\\\ = 85.7 mm[/tex]

n = 1/Λ = 1/633 nm = 1.58 Lines/mm

The calculated line density (n = 1.58 Lines/mm) is lower than the typical value of 625 Lines/mm for a CD. Factors that could affect this discrepancy include the manufacturing process of the CD, the accuracy of the measurements taken in the experiment, and any potential damage or wear on the CD.

Both a CD and a diffraction grating produce interference patterns due to the diffraction of light, but there are some differences between the two. A CD has a spiral pattern of pits that diffract light in different directions, producing a series of concentric rings of different colors. A diffraction grating, on the other hand, has a regular pattern of equally spaced parallel slits or grooves that diffract light in a specific direction, producing a series of evenly spaced bright spots on a screen. The causes of these differences lie in the different patterns of grooves or pits on the surfaces of the CD and diffraction grating.

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Most of the material that makes up Earth and all life on Earth, including humans, was formed
A. in the Big Bang.
B. inside the Sun.
C. inside stars that died before Earth formed.
D. in the atmospheres of nearby stars that are still shining and spraying material out into the galaxy.

Answers

C. inside stars that died before Earth formed.

Most of the material that makes up Earth and all life on Earth, including humans, was formed inside stars that died billions of years ago. As these stars exploded in supernovae, they released the elements and compounds that make up everything around us, including carbon, nitrogen, oxygen, and iron. These materials eventually coalesced into planets like Earth, which became home to living organisms. So, we owe our existence to the stars that came before us.

These stars underwent nuclear reactions, creating heavier elements that were later released into the universe during their death. This material eventually contributed to the formation of our solar system, including Earth and its inhabitants.

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which has a greater angular momentum: a solid sphere of mass m rotating at a constant angular frequency about the z-axis, or a solid cylinder of the same mass and rotation rate about the z-axis and why?

Answers

The solid cylinder has a greater angular momentum than the solid sphere rotating at the same constant angular frequency about the z-axis.

The angular momentum of an object depends on its moment of inertia and its angular velocity. The moment of inertia of a solid sphere is given by 2/5 * m * r^2, where m is the mass of the sphere and r is its radius. The moment of inertia of a solid cylinder is given by 1/2 * m * r^2, where m is the mass of the cylinder and r is its radius. Since the moment of inertia of the cylinder is less than that of the sphere, but they both have the same angular velocity, the cylinder has a greater angular momentum than the sphere. This can be seen mathematically by using the equation for angular momentum, L = I * omega, where L is the angular momentum, I is the moment of inertia, and omega is the angular velocity. Therefore, a solid cylinder of the same mass and rotation rate about the z-axis has a greater angular momentum than a solid sphere.

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Which of the following sensors would be most useful for helping a drone remain level as it flies? -Accelerometer -Magnetometer -Gyro sensor -Aero

Answers

The sensor that would be most useful for helping a drone remain level as it flies is the Gyro sensor.



A Gyro sensor, also known as a gyroscope, measures the angular velocity or rate of rotation around an axis. This is particularly useful for drones as it can detect any changes in orientation and help the drone maintain its level flight. By measuring the rate of rotation around each of its axes, a Gyro sensor can detect any changes in the drone's orientation and provide feedback to the flight controller to adjust the drone's motors accordingly.

Accelerometers can also be used in drones to detect changes in acceleration and tilt, but they are not as effective as gyroscopes in detecting changes in orientation. Magnetometers are used for detecting magnetic fields and can be used for navigation purposes, but they are not as useful for maintaining level flight. Aero sensors are not commonly used in drones and are more useful for measuring atmospheric conditions.

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A diverging lens with f = -37.5 cm is placed 15.0 cm behind a converging lens with f = 21.0 cm .Where will an object at infinity be focused? Determine the image distance from the second lens. Follow the sign conventions.

Answers

This means that the final image is generated 26.25 cm in front of the converging lens on the object's opposite side.

The image produced by the diverging lens acts as the object for the converging lens. Using the thin lens formula, we can find the location of the image from the diverging lens:

1/f = 1/di - 1/do

where f is the focal length of the diverging lens, di is the image distance from the diverging lens, and do is the object distance from the diverging lens (which is infinity in this case).

1/-37.5 = 1/di - 0

Solving for di, we get:

di = -37.5 cm

This means that the image from the diverging lens is formed 37.5 cm behind the lens on the same side as the object.

This image acts as the object for the converging lens. Using the thin lens formula again, we can find the location of the final image:

1/f = 1/di - 1/do

where f is the focal length of the converging lens, di is the distance of the image from the diverging lens (which we just found to be -37.5 cm), and do is the distance of the object from the converging lens (which is the distance of the image from the diverging lens, or -37.5 cm).

1/21.0 = 1/-37.5 - 1/-37.5

Solving for do, we get:

do = -26.25 cm

This means that the final image is formed 26.25 cm in front of the converging lens on the opposite side of the object. The negative sign indicates that the image is virtual (i.e. it cannot be projected onto a screen).

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a laser (λ = 293 nm) produces a light beam with an average power of 79 mw and a diameter of 4 mm. calculate how many photons per second, in the unit of 1016/s, are emitted by this laser.

Answers

The laser emits about 3.69 x 10¹⁷ photons per second, or 36.9 x 10¹⁶ photons per second in the unit of 10¹⁶ photons/s.

To calculate the number of photons emitted by the laser per second, we can use the following formula:

N = P / E

where N is the number of photons per second, P is the average power of the laser in watts, and E is the energy of each photon in joules.

The energy of each photon can be calculated using the formula:

E = hc / λ

where h is Planck's constant (6.626 x 10^⁻³⁴ J s), c is the speed of light (3.00 x 10⁸ m/s), and λ is the wavelength of the laser in meters.

Substituting the given values, we get:

E = (6.626 x 10⁻³⁴J s) x (3.00 x 10⁸m/s) / (293 x 10⁻⁹m)

E = 2.14 x 10⁻¹⁹ J

Now we can calculate the number of photons emitted per second:

N = (79 x 10⁻³ W) / (2.14 x 10⁻¹⁹J)

N = 3.69 x 10¹⁷ photons/s

Finally, we can express the result in the unit of 10¹⁶photons/s as follows:

N = 36.9 x 10¹⁶photons/s

N = 3.69 x 10¹⁷ photons/s

Therefore, the laser emits about 3.69 x 10¹⁷photons per second, or 36.9 x 10¹⁶photons per second in the unit of 10¹⁶ photons/s.

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Particles q₁ = -20.5 μC, q2 = -9.30 μC, and 93 = -31.6.0 μC are in a line. Particles q₁ and q₂ are separated by 0.980 m and particles q2 and q3 are separated by 0.750 m. What is the net force on particle q2₂? Remember: Negative forces (-F) will point Left Positive forces (+F) will point Right ​

Answers

On q₂, there is a net force of around 1.65 × 10⁻⁴ N, pointing left.

How to determine net force?

Use Coulomb's law to find the forces between each pair of charges, and then use the principle of superposition to find the net force on q₂.

The force on q₂ due to q₁ is:

F₁₂ = k × |q₁| × |q₂| / d₁₂²

where k = Coulomb's constant, d₁₂ = distance between q₁ and q₂, and the absolute values of the charges are used because they are both negative.

Substituting the given values:

F₁₂ = (9 × 10⁹ N·m²/C²) x (20.5 × 10⁻⁶ C) x (9.30 × 10⁻⁶ C) / (0.980 m)²

F₁₂ ≈ -4.15 × 10⁻⁴ N (pointing left)

Similarly, the force on q₂ due to q₃ is:

F₂₃ = k × |q₂| × |q₃| / d₂₃²

Substituting the given values:

F₂₃ = (9 × 10⁹ N·m²/C²) x (9.30 × 10⁻⁶ C) x (31.6 × 10⁻⁶ C) / (0.750 m)²

F₂₃ ≈ 2.50 × 10⁻⁴ N (pointing right)

To find the net force on q₂, add the forces vectorially:

F_net = F₁₂ + F₂₃

F_net ≈ -4.15 × 10⁻⁴ N + 2.50 × 10⁻⁴ N

F_net ≈ -1.65 × 10⁻⁴ N (pointing left)

Therefore, the net force on q₂ is approximately 1.65 × 10⁻⁴ N, pointing left.

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(2)
What is the quantity used to measure an object's resistance to changes in rotation?
a) torque
b)moment of inertia
c)mass
d)angular velocity

Answers

The quantity used to measure an object's resistance to changes in rotation is called moment of inertia. Moment of inertia is a measure of an object's rotational inertia, which is the resistance of an object to changes in its rotation.

The moment of inertia depends on the mass and distribution of the object's mass around its axis of rotation. The greater the moment of inertia, the more difficult it is to change the object's rotation.

Therefore, moment of inertia is an important physical quantity used in many fields, including physics and engineering, to analyze and design systems involving rotational motion.

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(a) a grinding wheel 0.35 m in diameter rotates at 2500 rpm. calculate its angular velocity in rad/s. (b) what are the linear speed and acceleration of a point on the edge of the grinding wheel?

Answers

(a) The angular velocity of the grinding wheel can be calculated by converting the rotational speed from rpm to rad/s. Angular velocity (ω) is given by:

[tex]ω = (2π * N) / 60[/tex]

Where N is the rotational speed in rpm. Plugging in the values, we have:

[tex]ω = (2π * 2500) / 60 ≈ 261.8 rad/s.[/tex]

(b) The linear speed (v) of a point on the edge of the grinding wheel can be calculated using the formula:

[tex]v = r * ω[/tex]

Where r is the radius of the grinding wheel. Given that the diameter is 0.35 m, the radius (r) is 0.175 m. Plugging in the values, we have:

[tex]v = 0.175 * 261.8 ≈ 45.9 m/s.[/tex]

The acceleration (a) of a point on the edge of the grinding wheel can be calculated using the formula:

[tex]a = r * α[/tex]

Where α is the angular acceleration. Since the grinding wheel is rotating at a constant speed, α is 0, and thus the acceleration at the edge of the wheel is 0.

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reduction is the removal of hydrogen (electrons) from a molecule or atom. (True or False)

Answers

False. Reduction is actually the gain of electrons, usually accompanied by the addition of hydrogen to a molecule or atom. This process is commonly used in organic chemistry to create new molecules with specific properties. During reduction, a molecule or atom gains electrons, and since electrons have a negative charge, the overall charge of the molecule or atom decreases. This is why the process is called reduction.

In organic chemistry, reduction reactions typically involve the use of reducing agents, which are compounds that are capable of donating electrons to other molecules or atoms. Some common reducing agents include lithium aluminum hydride, sodium borohydride, and hydrogen gas. These agents are often used in conjunction with other reagents and solvents to achieve the desired chemical reaction.

Overall, reduction is an important process in chemistry that is used to create new molecules with specific properties. By gaining electrons and hydrogen, molecules and atoms can become more stable and less reactive, making them useful for a wide range of applications. Whether you are studying organic chemistry or simply interested in the basic principles of chemistry, understanding reduction is an essential part of your knowledge base.
False. The statement provided is incorrect. Reduction is actually the process of gaining electrons or adding hydrogen to a molecule or atom, not removing hydrogen or electrons.

In a reduction reaction, a substance undergoes a change in its oxidation state, typically by gaining electrons or hydrogen atoms. This process often occurs in tandem with oxidation, where another substance loses electrons or hydrogen atoms, and the two reactions together are known as a redox (reduction-oxidation) reaction.

In summary, reduction is the process of gaining electrons or adding hydrogen to a molecule or atom, while oxidation involves the loss of electrons or hydrogen atoms.

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