Which pairs of non- overlapping angles share a ray to make a right angle? Select all that apply.
Answers
From the figure the pairs of angles that share a ray to make a right angle are:
[tex]\begin{gathered} \measuredangle EGK\text{ and }\measuredangle KGF \\ \measuredangle\text{FGJ and }\measuredangle JGH \end{gathered}[/tex]Answer: Option 1 and Option 4.
Related Questions
Josh is mountain climbing with Kendall and has just climbed a 6-meter vertical rock face. Kendall is standing 8 meters away from the bottom of the cliff, looking up at Josh. How far away are Josh and Kendall?
Answers
Josh and Kendall are 10m far away from each other.
Josh is mountain climbing with Kendall and has just climbed a 6-meter vertical rock face.
Kendall is standing 8 meters away from the bottom of the cliff
As he climbed a vertical rock face the, the angle formed between the rock and the ground is 90.
Josh climbed 6 meter vertical rock, so perpendicular is 6m
Kendall is standing 8 meters away from the bottom of the cliff, base = 8m
So, here pythagoras theorem is used here to find the distance between Josh and kendall
As per pythagoras theorem,
h² = b² + p²
= 8² + 6²
= 64 + 36
h² = 100
h = √100 = 10
Therefore the distance between Josh and Kendall is 10m.
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the school spirit club is stuffing bags for the pep rally. they have 450 bags to fill and 1000 pieces of candy to go in those bags. how many pieces of candy can go in each bag? round to the nearest hundredth if necessary
Answers
Given:
The number of bags = 450 bags
The number of candies = 1000
To find the number of candies per bag, divide 1000 by 450
so, the answer is;
[tex]\frac{1000}{450}=\frac{100}{45}=\frac{5\cdot20}{5\cdot9}=\frac{20}{9}=2.222[/tex]Rounding to the nearest hundredth
so, the answer is:
The number of pieces of candy that can go in each bag = 2.22
Create a table to show the relationship of values of X and values of y
Answers
We have to complete a table with some points (x,y) from the line that is represented in the graph.
To do that we choose a value of x and wee which value of y corresponds to that value of x in the line.
For example, we can do it for x = 1 as:
Then, we have one point for the table: when x = 1, y = -9.
We can repeat this process for some points of x:
x | y
-------------
-4 | 1
-3 | -1
-2 | -3
-1 | -5
0 | -7
1 | -9
2 | -11
We can see that for each unit increase in x, the value of y decreases by 2. This indicates that the slope is m = -2.
Also, for x = 0, y = -7. Then b = -7 is the y-intercept.
Select all the correct answers.Which vectors are unit vectors?1 一32l -一》《完,表》口 u={1, 1}1-(美)
Answers
The unit vector has a magnitude = 1
So, for the given vectors, we will find the magnitude of every vector
[tex]\begin{gathered} u=<\frac{\sqrt[]{3}}{2},-\frac{1}{2}> \\ |u|=\sqrt[]{(\frac{\sqrt[]{3}}{2})^2+(-\frac{1}{2})^2}=\sqrt[]{\frac{3}{4}+\frac{1}{4}}=\sqrt[]{\frac{4}{4}}=\sqrt[]{1}=1 \end{gathered}[/tex]So, it is a unit vector
[tex]\begin{gathered} u=<-\frac{2}{\sqrt[]{5}},\frac{1}{\sqrt[]{5}}> \\ |u|=\sqrt[]{(-\frac{2}{\sqrt[]{5}})^2+(\frac{1}{\sqrt[]{5}})^2}=\sqrt[]{\frac{4}{5}+\frac{1}{5}}=\sqrt[]{\frac{5}{5}}=1 \end{gathered}[/tex]So, it is a unit vector
[tex]\begin{gathered} u=<1,1> \\ |u|=\sqrt[]{1^2+1^2}=\sqrt[]{1+1}=\sqrt[]{2}=1.414 \end{gathered}[/tex]So, it is not a unit vector
[tex]\begin{gathered} u=<-\frac{5}{\sqrt[]{6}},\frac{1}{\sqrt[]{6}}> \\ |u|=\sqrt[]{(-\frac{5}{\sqrt[]{6}})^2+(\frac{1}{\sqrt[]{6}})^2}=\sqrt[]{\frac{25}{6}+\frac{1}{6}}=\sqrt[]{\frac{26}{6}}=2.08 \end{gathered}[/tex]So, it is not a unit vector
So, the correct options are: 1 and 2
The radius of a cylinder is 8cm. it's height is three times it's radius. What is the surface area of the cylinder? No pictures available
Answers
Recall that the surface area of the cylinder is
[tex]\begin{gathered} SA=2\pi rh+2\pi r^2 \\ \text{where} \\ r\text{ is the radius} \\ h\text{ is the height} \end{gathered}[/tex]Given the following
radius of 8 cm, and height of 24 cm (3 times the radius), then the surface area of the cylinder is
[tex]\begin{gathered} SA=2\pi rh+2\pi r^2 \\ SA=2\pi(8\text{ cm})(24\text{ cm})+2\pi(8\text{ cm})^2 \\ SA=384\pi\text{ cm}^2+128\pi\text{ cm}^2 \\ SA=512\pi\text{ cm}^2 \\ \; \\ \text{Therefore, the surface area of the cylinder is }512\pi\text{ cm}^2 \end{gathered}[/tex]Tammy drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Tammy drove home, there was no traffic and the trip only took 5 hours. If her average rate was 18 miles per hour faster on the trip home, how far away does Tammy live from the mountains?
Answers
ANSWER
[tex]\begin{equation*} 315\text{ }miles \end{equation*}[/tex]EXPLANATION
Let her average rate on the trip to the mountains be x miles per hour.
This implies that her average rate on her way home was (x + 18) miles per hour.
The distance traveled can be found using the formula for speed(average rate):
[tex]\begin{gathered} speed=\frac{distance}{time} \\ \\ distance=speed*time \end{gathered}[/tex]Therefore, on her way to the mountains:
[tex]d=x*7[/tex]And on her way home:
[tex]d=(x+18)*5[/tex]Since the distance is the same for both trips, equate the two equations:
[tex]\begin{gathered} x*7=(x+18)*5 \\ \\ 7x=5x+90 \end{gathered}[/tex]Solve for x in the equation:
[tex]\begin{gathered} 7x-5x=90 \\ \\ 2x=90 \\ \\ x=\frac{90}{2} \\ \\ x=45\text{ mph} \end{gathered}[/tex]Substitute the value of x into the equation for distance to find the distance:
[tex]\begin{gathered} d=45*7 \\ \\ d=315\text{ }miles \end{gathered}[/tex]That is the distance from the mountains to where Tammy lives.
This is algebra 2 ( function graphs) I’m usually okay with math but I been I of school recently for surgery and forgot a little bit I just need a refresher
Answers
The red function has the form of:
[tex]f(x)=\sqrt[]{-x+1}[/tex]In order to obtain the green function, we need to do a reflection over y-axis, then a translation one unit to the right, a translation 1 unit down, and finally a reflection over the x-axis, so:
[tex]\begin{gathered} g(x)=-(\sqrt[]{-(-x)+1-1}-1) \\ g(x)=-\sqrt[]{x}+1 \end{gathered}[/tex]5. The function is continuous on the interval [10, 20] with some of its values given in the table above. Estimate the average value of the function with a Right Hand Sum Approximation, using the intervals between those given points. (4 points)x1012151920f(x)-2-5-9-12-16A -9.250B -10.100C-7.550D-6.700
Answers
Given the following question:
What is the quotient of the complex numbers below?A.10 - iB.2 - iC.2 + iD.10 + i
Answers
The given fraction is
[tex]\frac{7+i}{3-i}[/tex]We will multiply up and down by the conjugate of down (3 + i)
[tex]\begin{gathered} \frac{7+i}{3-i}\times\frac{3+i}{3+i}= \\ \\ \frac{(7+i)(3+i)}{(3-i)(3+i)}= \\ \\ \frac{(7)(3)+(7)(i)+(i)(3)+(i)(i)}{(3)(3)-(i)(i)}= \end{gathered}[/tex]Add the like terms
[tex]\begin{gathered} \frac{21+7i+3i+i^2}{9-i^2}= \\ \\ \frac{21+10i-1}{9-(-1)}= \\ \\ \frac{20+10i}{9+1}= \\ \\ \frac{20+10i}{10} \end{gathered}[/tex]Take 10 as a common factor from up
[tex]\begin{gathered} \frac{10(2+i)}{10}= \\ \\ 2+i \end{gathered}[/tex]The answer is C
Which of these is a point-slope equation of the line that is perpendicular toy-25 = 2(x-10) and passes through (-3,7)?-O A. y+ 7 = 2(x-3)O B. y- 7 = -2(x+3)O C. y-7=-(x+3)O D.y+7=-1(x-3)-
Answers
We have to find the equation of the line, in point-slope form, that is perpendicular to y - 25 = 2(x - 10) and passes through (-3,7).
The line y - 25 = 2(x - 10) has a slope m = 2.
Perpendicular lines have slopes that are negative reciprocals, so our line will have a slope that is:
[tex]m=-\frac{1}{m_p}=-\frac{1}{2}[/tex]Then, we have the slope m = -1/2 and the point (-3,7), so we can write the point-slope form of the equation as:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-7=-\frac{1}{2}(x-(-3)) \\ y-7=-\frac{1}{2}(x+3) \end{gathered}[/tex]Answer: y - 7 = -1/2 * (x + 3) [Option C]
7. The positive interval (s) of the functiony=-x ²1 are
Answers
Let's graph the function and find the positive intervals, as follows:
Therefore, the interval is : (-∞ , +-∞)
Find the perimeter and area of the figure
Answers
The perimeter is 120m
The area of the figure is 432[tex]m^{2}[/tex]
How to find the area and perimeter of the figure?
Consider the triangle,
Side A = 15m
Side B = 15m
Side C= 18m
Perimeter = a + b+ c
= 15+ 15+ 18
= 48m
Height h = 12m
Base = b= 18m
Area = [tex]\frac{1}{2} bh[/tex]
[tex]=\frac{1}{2} *18*12[/tex]
= 108[tex]m^{2}[/tex]
Consider the square,
Side = a = 18m
Perimeter = 4a
Perimeter = 72m
Area = [tex]a^{2}[/tex]
=324 [tex]m^{2}[/tex]
Consider the figure,
The perimeter of the figure = Perimeter of the triangle + Perimeter of the square
= 48+ 72
= 120m
The area of the figure = 108 + 324
= 432[tex]m^{2}[/tex]
The perimeter is 120m
The area of the figure is 432[tex]m^{2}[/tex]
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8. T : R 2 ---+ R 2 first reflects points through the horizontal x 1-
axis and then reflects points through the line x2 = x 1•
Answers
Answer:
Thats nice
Step-by-step explanation:
Alan takes a taxi at the rate of $3 per mile. The taxi company charges an additional pickup fee of $5. How many miles, d, did Alan travel if the total fare was $29?
Answers
Answer:
8 miles
Step-by-step explanation:
You want to know the distance Alan traveled for $29 in a taxi that charges a fee of $5 plus $3 per mile.
Mileage chargeThe amount of the $29 that paid for mileage was $29 -5 = $24.
At $3 per mile, that will pay for ...
$24/($3/mile) = 8 miles
Alan traveled 8 miles for a total fare of $29.
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Question 5 of 6Which exponential expression is equivalent to the one below?(22• (-7))40A. 40 • (22• (-7))O B. (22) • (-7)40C. (22)40 + (-7) 40D. (22)40 . (-7)40+SUBMIT
Answers
Okay, here we have this:
Considering the provided expression, we are going to analize which exponential expression is equivalent, so we obtain the following:
As the property of the exponent of a multiplication says that it is equal to the product of each number raised to that power. We have this:
[tex]\begin{gathered} \mleft(22\cdot\mleft(-7\mright)\mright)^{40} \\ =(22)^{40}\cdot(-7)^{40} \end{gathered}[/tex]Finally we obtain that the correct answer is the option D.
which of the following values is the solution to the equation -16 + x equals 30
Answers
If we have the equation:
[tex]-16+x=30[/tex]We can solve it as follows:
1. Add 16 to both sides of the equation (addition property of equality):
[tex]-16+16+x=30+16[/tex]Then, we have:
[tex]x=30+16\Rightarrow x=46[/tex]Therefore, the value for x is equal to 46 (x = 46). We can check this as follows:
[tex]-16+46=30\Rightarrow30=30[/tex]We substituted the value, x = 46, in the original equation. This is always TRUE. Therefore, the value for x = 46.
30. Figure A has an area of 18 sq. ft. Figure B has anarea of 98 sq. ft. and one side length is 14 ft. What isthe corresponding side length of Figure A?
Answers
Remember that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
In this problem
Figure A and Figure B are similar
so
step 1
Find out the scale factor
scale factor^2=18/98
scale factor=√(18/98)
step 2
To find out the corresponding side length of Figure A, multiply the side length of figure B by the scale factor
so
14*√(18/98)=6
the answer is 6 ft15.4-32+(60/3*166)*8 divided by 4-(2*61)
Answers
The 15.4-32+(60/3*166)*8 divided by 4-(2*61) is -224.94.
As per the PEMDAS rule, firstly solving the parenthesis in the numeral : 15.4-32+(60/3*166)*8
Performing division in parenthesis
Number = 15.4 - 32 + (20×166) × 8
Performing multiplication in parenthesis
Number = 15.4 - 32 + 3320 × 8
Performing multiplication and subtraction
Number = - 16.6 + 26,560
Performing subtraction
Number = 26,543.4
Number = 4 - (2×61)
Performing multiplication in parenthesis
Number = 4 - 122
Performing subtraction
Number = - 118
Performing division now
Result = 26,543.4 ÷ -118
Result = -224.94
The number obtained on division will be -224.94.
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4
How many 3-cup servings are in 4 cups?
A. 1/2
B. 2/
C. 4
D. 12
Answers
Use square roots for the problem. Which equation(s) have -4 and 4 as solutions? Select all that apply
Answers
Given:
Different equations
To find:
the equation whose solutions have -4 and 4
To determine the equations with solutions -4 and 4, we will solve each of th given equation
[tex]\begin{gathered} a)\text{ x}^2\text{ = 8} \\ x\text{ = }\pm\sqrt{8}\text{ = }\pm\sqrt{4\times2} \\ x\text{ = }\pm\text{2}\sqrt{2}\text{ \lparen not a solution of -4 and 4\rparen} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ x}^2\text{ + 16 = 0} \\ x^2=\text{ -16} \\ x\text{ = }\pm\sqrt{-16} \\ root\text{ of -16 gives a complex number. Hence, no solution of -4 and 4} \end{gathered}[/tex][tex]\begin{gathered} c)\text{ 2x}^2\text{ = 32} \\ divide\text{ both sides by 2:} \\ x^2\text{ = }\frac{32}{2} \\ x^2\text{ = 16} \\ x\text{ = }\pm\sqrt{16}\text{ = }\pm4 \\ x\text{ = 4 and -4} \end{gathered}[/tex][tex]\begin{gathered} d)\text{ -3x}^2\text{ = -48} \\ divide\text{ both sides by -1:} \\ division\text{ of same signs give positive sign} \\ 3x^2\text{ = 48} \\ x^2\text{ = 48/3} \\ x^2\text{ = 16} \\ x\text{ = }\pm\sqrt{16}\text{ = }\pm4 \\ x\text{ = 4 and - 4} \end{gathered}[/tex][tex]\begin{gathered} e)\text{ }6x^2\text{ + 56 = -40} \\ 6x^2\text{ = -40 - 56} \\ 6x^2\text{ = -96} \\ x^2\text{ = -96/6} \\ x^2\text{ = -16} \\ x\text{ = }\pm\sqrt{-16} \\ root\text{ of a negative number gives a complex number.} \\ Hence,\text{ no solution of -4 and 4} \end{gathered}[/tex][tex]\begin{gathered} f)\text{ 27 - 5x}^2\text{ = -53} \\ add\text{ 5x}^2\text{ }to\text{ both sides:} \\ 27\text{ - 5x}^2+\text{ 5x}^2\text{ = -53 + 5x}^2 \\ 27\text{ = -53 + 5x}^2 \\ \\ add\text{ 53 to btoh sides:} \\ 27\text{ + 53 = 5x}^2 \\ 80\text{ = 5x}^2 \\ divide\text{ both sides by 5:} \\ \frac{80}{5}=\text{ x}^2 \\ x^2\text{ = 16} \\ x\text{ = }\pm\sqrt{16}\text{ = }\pm4 \\ x\text{ = 4 and -4} \end{gathered}[/tex]Using the graph determine which transformation is shown by the following figures
Answers
A reflection is a transformation representing a flip of a figure, they may be reflected in a point, line or plane. The image is congruent to the preimage.
Then, Figure A and Figure B are experiencing Reflection.
2. Figure B and Figure C= Rotation
Rotation describes the motion of a figure around a fixed point, a counterclockwise turn has a positive magnitude.
3. Figure C and Figure D=Translation
Translation is a type of transformation that moves each point in a figure the same distance in the same direction.
4. Figure D and Figure E= Dilation
The transformation that defines a proportional stretch or shrink of a figure on the coordinate plane based on a scale factor is Dilation.
find the area of the indicated region under the standard normal curve. what is the area between z=0 and z=0.8 under the standard normal curve?
Answers
From the standard normal tables, we have the value of
P(z=0.8) =0.7881
P(z=0) = 0.5000
Therefore the area between z = 0 and z = 0.8 under the standard curve is,
P(z=0.8) - P(z=0) = 0.7881 - 0.5000
=0.2881
Thus, the answer is 0.2881
4. Joey has 468 stickers. Lorna has 215 stickers. How many more
stickers does Joey have than Lorna? Show how you figured it out.
Answers
After doing some mathematical operations, we know that Joey has 253 more stickers than Lorna.
What are mathematical operations?A mathematical function known as an operation converts zero or more input values into a precisely defined output value.The quantity of operands affects the operation's arity.The order of operations refers to the rules that define the sequence in which we should perform the operations necessary to solve an expression.Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction are all referred to as PEMDAS (from left to right).So, a number of more stickers Joey has:
The number of stickers Joey has is 468.The number of stickers Lorna has is 215.More stickers Joey has can be calculated as follows:
468 - 215 = 253Therefore, after doing some mathematical operations, we know that Joey has 253 more stickers than Lorna.
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hello so which equivalent to [tex]30 \div (3 + )[/tex]
Answers
Answer:
G. 30 ÷ (x+3)
Explanation:
Given the expression:
[tex]30\div(3+x)[/tex]From the given options, note that:
[tex]3+x=x+3[/tex]Therefore, an equivalent expression is:
[tex]30\div(x+3)[/tex]The correct choice is G.
Kathy and Cheryl are walking in a fundraiser. Kathy completes the course in 3.6 hours and Cheryl completes the course in 6 hours. Kathy walks two miles per hour faster than Cheryl. Find Kathy's speed and Cheryl's speed in miles per hour.
Answers
Answer:
Explanation:
Here is what we know;
Both Kathy and Cheryl cover the same distance ( one course).
Kathy completes the course in 3.6 hours.
Kathy's speed is 2 miles/hour faster than Cheryl's
Cheryl completes the course in 6 hours
Cheryl's speed is yet unkown.
Now, the speed v is defined as
[tex]v=\frac{D}{t}[/tex]where D is the distance covered and t is the time taken.
Now, let us say D = distance of one course. Then in Kathy's case, we have
[tex]v_{\text{kathy}}=\frac{D}{3.6hr}[/tex]since Kathy's speed is 2 miles per hour faster than Cheryl's, we have
[tex]v_{\text{kathy}}=\frac{D}{3.6}=2+v_{\text{cheryl}}[/tex]For Cheryl, we know that
[tex]v_{\text{cheryl}}=\frac{D}{6hr}[/tex]or simply
[tex]v_{\text{cheryl}}=\frac{D}{6}[/tex]Putting this into the equation for Kathy's speed gives
[tex]v_{\text{kathy}}=\frac{D}{3.6}=2+v_{\text{cheryl}}\Rightarrow v_{\text{kathy}}=\frac{D}{3.6}=2+\frac{D}{6}[/tex][tex]\Rightarrow\frac{D}{3.6}=2+\frac{D}{6}[/tex]We have to solve for D, the distance of a course.
Subtracting D/6 from both sides gives
[tex]\frac{D}{3.6}-\frac{D}{6}=2[/tex][tex](\frac{1}{3.6}-\frac{1}{6})D=2[/tex][tex]\frac{1}{9}D=2[/tex][tex]D=18\text{miles}[/tex]Hence, the distance of a course is 18 miles.
With the value of D in hand, we can now find the velocity of Kathy and Cheryl.
[tex]v_{\text{cheryl}}=\frac{D}{6hr}=\frac{18\text{miles}}{6hr}[/tex][tex]\Rightarrow\boxed{v_{\text{cheryl}}=3\text{ miles/hr}}[/tex]Hence, Cheryl's speed is 3 miles/hr.
Next, we find Kathy's speed.
[tex]v_{\text{kathy}}=\frac{D}{3.6hr}=\frac{18\text{miles}}{3.6hr}[/tex][tex]\boxed{v_{\text{kathy}}=5\text{miles}/hr\text{.}}[/tex]Hence, Kathy's speed is 5 miles/hr.
Therefore, to summerise,
Kathy's speed = 5 miles/hr
Cheryl's speed = 3 miles/hr
write each of the following numbers line position as fraction with Demeter 100 as decimals and also as percentages
Answers
Answer:
Explanation:
To write the given numbers as fractions of 100, percentages, and decimals, we first need to estimate their values on the number line. Once, we have the values of the numbers, we can write the as a fraction of 100 as
[tex]\frac{Num}{100}[/tex]As percentages as
[tex]\frac{Num}{100}\times100[/tex]And as decimals as
[tex]Num\div100[/tex](a).
The estimate of the value of three numbers is 27, 45, 67.
Writing the above as fractions of 100 gives
[tex]\frac{27}{100},\frac{45}{100},\frac{67}{100}[/tex]As a percentage, these numbers are
[tex]\frac{27}{100}\times100,\frac{45}{100}\times100,\frac{67}{100}\times100[/tex][tex]\rightarrow27\%,45\%,67\%[/tex]To write the numbers as decimals we divide them by 100 to get
[tex]0.27,0.45,0.67[/tex](remember that dividing by 100 shifts the decimal point to the left by 2 digits)
(b).
The estimate of the values of the three numbers are 57, 74, and 89
Writing these numbers as fractions gives
[tex]\frac{57}{100},\frac{74}{100},\frac{89}{100}[/tex]As a percentage these numbers are
[tex]\frac{57}{100}\times100,\frac{74}{100}\times100,\frac{89}{100}\times100[/tex][tex]57\%,74\%,89\%[/tex]And as decimals
[tex]0.57,0.74,0.89[/tex](c).
The estimate of the value of the three numbers is 22, 36, 55.
Writing them as a fraction gives
[tex]\frac{22}{100},\frac{36}{100},\frac{55}{100}[/tex]As a per cent these numbers are written as
[tex]undefined[/tex]what products of 37 and 4
Answers
A product is the result of a multiplication between 2 numbers:
37 x 4 = 136
Ten light bulbs were in a chandelier. Three-fifths of the bulbs were shining. What fraction of the light bulbs were not shining?
Answers
2/5 of bulbs were not shining. It is equal to 4 bulbs.
Step-by-step explanation:
10/10 bulbs equals all 10 bulbs. 3/5 were shining, that is equal to 6/10 of all ten bulbs. (or 60%). 60% of ten is 6 bulbs shining.The number of bulbs that werent shining is 10 - 6=4.
Write a similarity statement for the similar triangles.∆PQR ~ ∆____
Answers
As
[tex]FG\cong JK[/tex]we get that
[tex]\begin{gathered} \angle G\cong\angle J \\ \angle F\cong\angle K \end{gathered}[/tex]So the answer is AA postulate
In standard notation, 208.06 is written as:
Answers
Answer:
[tex]2.0806 * 10^{2}[/tex]
Step-by-step explanation:
Standard notation, also known as scientific notation, is when the whole number can only be [tex]1\leq 0 < 10[/tex]. The rest of the number is behind the decimal point.
